QT-I (Probability Dist II)
QT-I (Probability Dist II)
QT-I (Probability Dist II)
Perhaps the most widely known of all discrete distributions is the binomial
distribution. The assumptions underlie the distribution is
(I) The experiment involves n identical trials.
(ii) Each trial has only two possible outcomes denoted as success or as failure.
(iii) Each trial is independent of the previous trials.
(iv) The terms p and q remain constant throughout the experiment, where the
term p is the probability of getting a success on any one trial and the term q=1-p is
the probability of getting a failure on any one trial.
The probability of r successes in n trials with probability p for a success in each trial
is given by
n! r nr
P(r, n, p)= r!(n r )! p q where p+ q=1
Some example of the Binomial Distribution:
1. Suppose a machine producing computer chips has a 6%
defective rate. If a company purchases 30 of these chips, what is
the probability that none is defective?
2. Suppose that the brand X car battery has a 35% market share. If
70 cars are selected at random, what is the probability that at
least 30 cars have a brand X battery.
Examples: At Kerr pharmacy, where employees are often late. Five workers are in
the pharmacy. The owner has studied the situation over a period of time and has
determined that there is a 0.4 chance of any one employee being late and that they
arrive independently of one another. How would we draw a binomial probability
distribution illustrating the probabilities of 0,1,2,3,4,or 5 workers being late
simultaneously?
Exercise 5.10
The Wall Street Journal reported some interesting statistics on the job market. One
statistic is that 40% of all workers say they would change the job for slightly
higher pay. In addition, 88% of companies say that there is a shortage of qualified
job candidates. Suppose 16 workers are randomly selected and asked if they would
change job for slightly higher pay. What is the probability that 9 or more say yes?
What is the probability that three, four, five or six say yes? If 13 companies are
contacted, what is the probability that exactly 10 say there is a shortage of
qualified job candidates? What is the probability that all of the companies say there
is a shortage of qualified job candidates? What is the expected number of
companies that would say there is a shortage of qualified job candidates?
Mean and Standard deviation of a Binomial Distribution
Mean of a Binomial Distribution= np
Where n=number of trials
p= probability of success
Standard Deviation of a Binomial Distribution= npq
The Poissons Distribution
The Poissons distribution focuses on the number of discrete occurrences
oversomeintervalorcontinuum.
2. The Poissons distribution describes the occurrence of rare events. In fact,
thePoissonsformulahasbeenreferredtoasthelawofimprobableevents.
3. Poisson distribution often is used to describe the number of random
arrivals per some time interval. If the number of arrivals per interval is too
frequent, the time interval can be reduced enough so that the rare number of
occurrences is expected.
ThePoissondistributionhasthefollowingcharacteristics
Itisadiscretedistribution.
Itdescribesrareevents.
Eachoccurrenceisindependentoftheotheroccurrences.
Theoccurrencesineachintervalcanrangefromzerotoinfinity.
The expected number of occurrences must hold constant throughout the
experiment
Example:
1. Number of telephone calls per minute at a small business
2. Number of cases of rare blood disease per 100,000 people.
3. Number of arrivals at a turnpike tool booth per minute between 3 a.m. and 4
a.m. in January on the Kansas Turnpike.
4. Number of sewing flaws per pair of Jeans during production.
5. Number of times a tire blows on a commercial airplane per week.
6. Number of flaws per bolt of cloth.
Let X is the discrete rv which can take the values 0,1,2,3,4, and so on. Then the
probability of exactly x occurrences over an interval is calculated with the formula
x e
P(x)=
x!
Where =Long run average.
e=2.71828
Note: The value must hold constant throughout a Poisson
experiment.
You should be specific in describing the interval for which is being
used.
Applications.
Suppose bank customers arrive randomly on weekday afternoons at an
average of 3.2 customers every 4 minutes. What is the probability of
exactly five customers arriving in a four minutes interval on a
weekday afternoon? The lambda for this problem is 3.2 customers per
four minutes. The value of x is five customers per four minutes. The
probability of five customers randomly arriving during 4-minutes
interval when the long run average has been 3.2 customers per 4
minute interval is
Exercise 5.18. On Monday mornings, the First National Bank only has one teller
window open for deposits and withdrawals. Experience has shown that the
average number of arriving customers in a 4-minute interval on Monday mornings
is 2.8, and each teller can serve more than that number efficiently. These random
arrivals at this bank on Monday mornings are Poissons Distributed.
a. What is the probability that on a Monday morning exactly six customers will
arrive in a 4- minute interval?
b. What is the probability that no one will arrive at the bank to make a deposit
on withdrawals during a 4 minute interval?
c. Suppose that the teller can serve no more than 4 customers in any 4-minute
interval at this window on a Monday morning. What is the probability that, during
any given 4 minute interval, the teller will be unable to meet the demand? What is
the probability that the teller will be able to meet the demand? When demand
cannot be met during any given interval, a second window is opened. What
percentage of the time will a second window have to be opened?
d. What is the probability that exactly three people will arrive at the bank during
a 2- minute period on Monday mornings to make a deposit or a withdrawal? What
is the probability that five or more customers will arrive during an 8- minute
period?
Mean and Standard Deviation of a Poisson distribution
The mean or expected value of a Poissons Distribution is .
It is the long run average of occurrences for an interval if many random samples
are taken. This gives the actual occurrences that are likely to happen.
The variance of a Poisson distribution is also . The standard deviation
is .
What is the probability that more than 10 people will have the rare
blood disorder?
Suppose that the researcher gets more than 10 people who have the
rare blood disorder in the sample of 100,000 but the sample was
taken form a particular geographic region. What might the
researcher conclude from the results?
5.21. The average number of annual trips per family to amusement
parks in the United States is Poisson Distributed, with a mean of
0.6 trips per year. What is the probability of randomly selecting
an American family and finding the following:
a. The family did not make a trip to an amusement park last year?
b. The family took exactly one trip to an amusement park last year?
c. The family took two or more trips to amusement parks last year?
d. The family took three or fewer trips to amusement parks over a
three year period?
e. The family took exactly four trips to amusement parks during a
six year period?