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    Binding Energy

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    RaghuRam
    1) The document calculates the binding energy of Bismuth-83 by determining the mass defect when 83 protons and 126 neutrons fuse to form Bismuth-209. 2) The mass defect is found to be 1.760891 atomic mass units, and multiplying this by the speed of light squared gives a binding energy of 1640.2699665 MeV. 3) Dividing the total binding energy by the total nucleons gives an average binding energy of about 8.0 MeV per nucleon.

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    Binding Energy

    Uploaded by

    RaghuRam
    11 views1 page
    1) The document calculates the binding energy of Bismuth-83 by determining the mass defect when 83 protons and 126 neutrons fuse to form Bismuth-209. 2) The mass defect is found to be 1.760891 atomic mass units, and multiplying this by the speed of light squared gives a binding energy of 1640.2699665 MeV. 3) Dividing the total binding energy by the total nucleons gives an average binding energy of about 8.0 MeV per nucleon.

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    binding energy calculation

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    1) The document calculates the binding energy of Bismuth-83 by determining the mass defect when 83 protons and 126 neutrons fuse to form Bismuth-209. 2) The mass defect is found to be 1.760891 atomic mass units, and multiplying this by the speed of light squared gives a binding energy of 1640.2699665 MeV. 3) Dividing the total binding energy by the total nucleons gives an average binding energy of about 8.0 MeV per nucleon.

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    © All Rights Reserved
    Download as DOC, PDF, TXT or read online from Scribd
    Download as doc, pdf, or txt
    11 views1 page

    Binding Energy

    Uploaded by

    RaghuRam
    1) The document calculates the binding energy of Bismuth-83 by determining the mass defect when 83 protons and 126 neutrons fuse to form Bismuth-209. 2) The mass defect is found to be 1.760891 atomic mass units, and multiplying this by the speed of light squared gives a binding energy of 1640.2699665 MeV. 3) Dividing the total binding energy by the total nucleons gives an average binding energy of about 8.0 MeV per nucleon.

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    © All Rights Reserved
    Download as DOC, PDF, TXT or read online from Scribd
    Download as doc, pdf, or txt
    of 1

    Calculation of Binding energy of Bismuth 83Bi ( 209

    ):
    mass defect:
    Dm = �
    � ( �� )
    m 83 ( 1 H ) �+ �
    m ( ( 209 - 83) ( n ) )
    1 �- �
    ��
    m 83Bi �(
    209

    � )
    =� ( 1.007825 ) u + 126 ( 1.008665) u �
    83 �
    � � �- ( 208.980374 ) u �
    �
    = 1.760891u
    Energy released during the fusion reaction is,
    BE = ( mass defect ) c 2
    = 1.760891uc 2
    �931.5 MeV �
    = 1.760891uc 2 � 2 �
    � uc �
    =1640.2699665 MeV
    �1640 MeV
    Average binding energy is,
    BE 1640.269 MeV
    =
    A 209
    = 7.85 / nucleon
    �8.0 / nucleon

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