7 Polymers
7 Polymers
7 Polymers
GIST
1.
Polymer:
It is a very large molecule having molecular mass 103 - 107 g mol-1. They are
formed by joining together repeating structural units.
2.
(a)
Classification of Polymers:
Based On Source:
(i)
(ii)
PVC, polystyrene.
(b)
(i)
Based On Structure:
(ii)
Branched Polymers: This contain linear chains having some branches e.g.
amylopectin, glycogen etc.
(iii)
between various linear polymer chains. E.g. Bakelite, urea- formaldehyde polymer,
melamine, formaldehyde polymer etc.
(c) Based On Mode Of Polymerization:
(i)
(ii)
(i)
(ii)
Fibers: Strong hydrogen bonds are present between the polymer chains.
They have high tensile strength e.g., nylon.polyster, silk, wool, orlon, rayon etc.
(iii)
(iv)
(i)
(ii)
POLYMERS
POLYMER
Polythene
Teflon
(Poly
tetrfluoroethene
)
Poly acrylonitrile
Buna S
Buna N
Natural Rubber
Synthetic
Rubber(Neoprene)
Polypropene
Acrylonitrile CH2=CH-CN
Buta-1,3-diene
+ Styrene
CH2=CH-CH=CH2
C6H5CH=CH2
Buta-1,3-diene
+
Acrylonitrile
CH2=CH-CH=CH2
CH2=CH-CN
2-Methylbuta-1,3-diene (Isoprene)
2-Chlorobuta-1,3-diene (Chloroprene)
Propene
CH3-CH=CH2
Polystyrene
Styrene
C6H5CH=CH2
Polyvinyl chloride
(PVC)
Terylene(Dacron)
Nylon 6
Bakelite
Phenol + Methanal
Melamine
PHBV (biodegradable)
Melamine + Methanal
3-Hydroxybutanoic acid +
3Hydroxypentanoic acid
Glycine
+ Amino caproic acid
H2N-CH2-COOH
H2N (CH2)5-COOH
Nylon 2 Nylon 6
(biodegradable)
Nylon 66
Urea-formaldehyde resin
VSA
Urea + Formaldehyde
Ethane1,2-diol + Benzene-1,2-dicarboxylic
acid
(1 marks)
(2 marks)
SAII
(3 marks)
(ii)
chloroprene.
use of
polymerisation
B Give the products A& B.
A=Aminocaproic acid
B=nylon6
5.(i) Give an example of a synthetic rubber.
Polymers
Very Short Answer Type Questions (1 marks)
Q.1 Classify the following as addition and condensation polymers.
Terylene, Bakelite , polyvinyl chloride (PVC),polythene.
Sol. Addition polymers
Polyvinyl chloride and polythene
Condensation polymers
Treylene and Bakelite
Q2. Arrange the following in increasing order of their intermolecular forces.
(i)
Nylon-6,6, Buna-S , polythene
(ii)
Nylon-6 , neoprene , polyvinyl chloride
Sol.
Q3. Is a
homopolymer or a copolymer?
Sol. The process in which small molecules constitute the repeating units in a
polymer are called monomer units and are linked to each other by covalent
bond and this process of formation of polymers from respective monomers
is known as polymerisation.
Q5. In which classes, the polymers are classified on the basis of molecular
forces?
Sol.
i. Elastomers
ii. Fibres
iii. Thermoplastics
iv. Thermosetting polymers.
Q6. Write the name and structure of one of the common initiators used in
free radical addition polymerisation.
Sol. Benzoyl peroxide
(ii)Monomers
Terylene ;Teflon
Q17. What are the monomeric repeating units of nylon-6 and nylon-6,6?
Sol. Nylon-6
Q18. Write the monomers used for getting the following polymers
(i)Polyvinyl chloride
(ii)Teflon
(iii)Bakelite.
Sol.
Sol.
COOCH3
|
(ii)Methyl methacrylate, CH2=CCH3.
Q24. Give one example of a condensation polymer.
Sol. Nylon-6,6 is an example of condensation polymer because it is the result of
condensation reaction between adipic acid and hexamethlyendiamine.
Q25. Define plasticizers.
Sol. These organic compounds which added to plastics make them soft and
workable are known as plasticizers e.g., tricresyl phosphate , di-n-octylphthalate.
Q28. Give an example of a polymer which is used to make cups for hotdrinks?
Sol. Urea-formaldehyde resin.
Que.1:- (1) How does vulcanisation change the character of natural rubber?
(2) Why are the number, 6,6and6 put in the names of nylon-6,6 and nylon6?
Sol.:- (1) Valcanisation of natural rubber makes it hard and even more elastic. It
possess more wear and tear properties. It is used in automobile tyres.
(2) Nylon-6,6 and nylon-6 are the polymer of adipic acid, hexamitheylenediamini
and caprolactam respectively. Each of them has 6 carbon atom. Therefore
number 6,6 and 6 put in the names refer to the number of carbon atoms in the
monomers involved.
Que.2:- Explain the term coplymerisation and give two examples.
Sol.:- Coplymerisation is the process in which two or more diffrent monomers
polmerise together to form copolymer. e.g., Buna-S and Bina-N
Que.3:- What are the natural and synthetic polymers ? Give two example of
each type.
Sol.:- (1) Natural Polymers. These are found in plants and animals. e.g.,
cellulose, starch(polymer of glucose),
Protein .
(2) Synthetic Polymers These are man-made polymers that are used in day to
day life and in industries. e.g., Synthetic fibers, synthetic rubber
Que.4:- What are polymers?
Sol.:- The word 'ploymer' is coined from two Greek words 'poly' means 'many'
and 'mer' means 'unit/part'.
Ploymers can be defined as compound of high molecules formed by combination
of large numbe of small molecules. The small molecules which constitute the
reparing unit in polymer are called monomer unit and are linked to each other
by covalebt bond and this process of formation of polymers from respective
monomers is known as polymerisation.
e.g.-
Sol.:Melamine and formaldehyde are the staring material for this intermediate. Its
polymerisation leads to the formation of melamine polymers.
Styrene
(ii)
Teflon
Monomer Tetrafluoroethene
Structure
F
F
C == C
F
F
Q3- How are polymers classified on the basis of structure?
Ans- (i) Linear Polymers- These consist of long and straight chains. They have
high densities, high melting points and high tensile strength. Thus, these are well
packed structures e.g., high density polythene, polyvinyl chloride etc. These are
represented as
(iii) Branched Chain Polymers- These contain linear chains having some
branches. Due to their irregularly packed structure they have low tensile
strength, low densities and lower melting point as compared to linear
polymer e.g. low density polythene, glycogen etc. These are depicted as
C6H5CH==CH2
Styrene
CH2==CHCN
1, 3- butadiene
(iii) Dacron
Acrylonitrile
HOCH2CH2OH;
HOOC(C6H4)COOH
Ethyl glycol
Terephthalic acid
(iv) Neoprene
Cl
CH2==CCH==CH2
Chloroprene
Q8- How does the presence of double bonds in rubber molecules influence
their structure and reactivity?
Ans- Natural rubber is cis-polyisoprene and it is obtained by 1, 4-polymerisation
of isoprene units.
H3C
H
H 3C
H
C==C
CH2
CH2
C==C
~~~ H2C
CH2
C==C
CH2
CH2--~~~
H3C
H
Natural
rubber
The cis-configuration at double bonds does not allow the polymer chains to come
closer for effective interactions and hence intermolecular forces are quite weak.
As a result, natural rubber, cis-polyisoprene has a randomly coiled structure and
hence shows elasticity.
Q9- Differentiate thermoplastics and thermosetting polymers with two
examples of each.
AnsS.No. Thermoplastic Polymer
1
These are linear or slightly
branched long chain molecules.
2
These are capable of repeatedly
softening on heating and
hardening on cooling.
3
Intermolecular forces are
intermediate of elastomer and
fibres.
4
These can be reused e.g.
polythene, polyvinyl chloride
(PVC)
Thermosetting Polymer
These are cross-linked or heavily
branched molecules
On heating, these undergo
extensive cross-linking and
become infusible.
Intermolecular forces are
strongest.
These cannot be reused e.g.
bakelite, urea- formaldehyde
resin.
Q10- Write the free radical mechanism for the polymerization of ethane?
Ans- Alkenes/dienes and their derivatives are polymerized in the presence of a
free radical generating initiator (catalyst) like acetyl peroxide, benzoyl peroxide,
etc e.g. polymerization of ethene to polythene.
It consist of heating or exposing to light a mixture of ethene with a small amount
of benzoyl peroxide (as an initiator).
This process is completed in three steps given below
Step I- Chain Initiating Step
Firstly, the phenyl radical is formed by benzoyl peroxide. Then phenyl radical
added to the double bond of ethene molecule (monomer) to form a new and a
large free radical through homolysis.
O
C6H5COOCC6H5
Benzoyl peroxide
O
2C6H5C--O
2C6H5
Phenyl radical
C6H5 + CH2 == CH2
C6H5CH2CH2
Ethene (Monomer)
Big free radical
Step II- Chain Propagation Step
The new big free radical thus formed in the chain initiating step reacts with
another molecule of etheneto form another bigger sized radical. Thus, the
repetition of this sequence with new and bigger radicals tends to carry the
reaction forward.
C6H5 -- CH2 -- CH2 + CH2 == CH2
C6H5 -- CH2 -- CH2 -- CH2 -- CH2
C6H5 (CH2 -- CH2)n-- CH2 -- CH2
Step III- Chain Termination Step
Ultimately, the growing free radical chain may get terminated by reactions which
consume these free radicals by combination of free radicals in different ways to
form polythene.
C6H5 (CH2 -- CH2)n-- CH2 -- CH2 +
C6H5(CH2-- CH2)n-- CH2-- CH2
C6H5(CH2-- CH2)n -- CH2 CH2
CH2(CH2 -- CH2)n -- C6H5
Polythene
CHOOH
420 460 K
Terephthalic acid
O
--OCH2CH2OC
O
C
+ (2n 1) H2O
Polymerisation
CH2CH3
3-hydroxypentanoic acid
--OCHCH2COCHCH2C
CH3
CH2CH3
polyethylene
--OCH2CH2OC
C
n
Dacron
(iii) Copolymers
--CH2CH==CHCH2CHCH2--
Buna-S