Math 38 Mathematical Analysis III: I. F. Evidente
Math 38 Mathematical Analysis III: I. F. Evidente
Math 38 Mathematical Analysis III: I. F. Evidente
Unit 3
Outline
Outline
Recall
R R = R2 = {(x, y) | x R and y R}
Geometrically, R2 is associated with two-dimensional Euclidean space
(Euclidean 2-space)
Definition
A function of two variables f (x, y) is a rule that assigns a unique real
number to each point (x, y) in some subset D of 2 .
Examples
Example
1
2
3
f (x, y) = 6 3x 2y
f (x, y) = 4x 2 + y 2
p
f (x, y) = 9 x 2 y 2
Evaluation
Example
1
f (x, y) = 6 3x 2y .
1 Find f (0, 2)
2 Find f (x + x, y + y)
f (x, y) = 4x 2 + y 2 .
p
1 Find f ( 2, 1).
2 Find f (x + x, y)
Remark
The set D is called the domain of f , which we denote by dom f .
Remark
The set D is called the domain of f , which we denote by dom f .
If no set D is specified, then D is the natural domain of f :
Remark
The set D is called the domain of f , which we denote by dom f .
If no set D is specified, then D is the natural domain of f : the
largest subset of 2 containing all points (x, y) for which f (x, y) is
defined.
Remark
The set D is called the domain of f , which we denote by dom f .
If no set D is specified, then D is the natural domain of f : the
largest subset of 2 containing all points (x, y) for which f (x, y) is
defined.
The set of all possible values of f (x, y) is called the range of f and is
denoted by ran f .
Examples
Example
Find and sketch the domain of the following:
1
2
3
f (x, y) =
x
2x + y
f (x, y) = 4x 2 + y 2
p
f (x, y) = 9 x 2 y 2
Remark
The graph of f (x, y) is the surface in
the equation z = f (x, y).
Example
Determine the graph of the following:
1
2
3
f (x, y) = 6 3x 2y
f (x, y) = 4x 2 + y 2
p
f (x, y) = 9 x 2 y 2
Example
f (x, y) = 6 3x 2y
Example
f (x, y) = 4x 2 + y 2
Example
f (x, y) =
p
9 x2 y 2
Remark
Example
1
p
9 x 2 y 2 on the
Remark
Example
Remark
Suppose is the graph of f . Geometrically:
The domain of f is Projx y ()
Remark
Suppose is the graph of f . Geometrically:
The domain of f is Projx y ()
The range of f is the "projection" of onto the z -axis.
Example
f (x, y) = 4x 2 + y 2
p
f (x, y) = 9 x 2 y 2
Example
f (x, y) = 4x 2 + y 2
Example
f (x, y) =
p
9 x2 y 2
Contour Maps
Let f (x, y) be a function of two variables with graph given by z = f (x, y).
Contour Maps
Let f (x, y) be a function of two variables with graph given by z = f (x, y).
Let C k be the trace of the graph of f (x, y) on the plane z = k
Contour Maps
Let f (x, y) be a function of two variables with graph given by z = f (x, y).
Let C k be the trace of the graph of f (x, y) on the plane z = k
The level curve of height k is Projx y (C k )
Contour Maps
Let f (x, y) be a function of two variables with graph given by z = f (x, y).
Let C k be the trace of the graph of f (x, y) on the plane z = k
The level curve of height k is Projx y (C k )
A set of level curves for various values of k is called a contour map
of f
Contour Maps
Let f (x, y) be a function of two variables with graph given by z = f (x, y).
Let C k be the trace of the graph of f (x, y) on the plane z = k
The level curve of height k is Projx y (C k )
A set of level curves for various values of k is called a contour map
of f
We get an idea about the graph of f from its contour map.
Raise the level curve of height k to z = k .
The "steepness" of the graph can be gleaned from the contour map.
Example
f (x, y) = 4x 2 + y 2
p
f (x, y) = 9 x 2 y 2
f (x, y) = 4x 2 + y 2
f (x, y) =
p
9 x2 y 2
Remark
All the above notions can be extended to functions of 3 or more variables.
In particular, we are also interested in functions of 3 variables.
Outline
(x,y)(x 0 ,y 0 )
(x,y)(x 0 ,y 0 )
(x,y)(x 0 ,y 0 )
Examples
Example
1
Find
x2
along the path y = 0, x = 0 and y = x .
(x,y)(0,0) x 2 + y 2
Find
x9 y
along the path y = x and y = x 2 .
(x,y)(0,0) (x 6 + y 2 )2
lim
lim
Recall
For functions of one variable:
Recall
For functions of one variable:
There two ways of approaching x 0 : from the left and from the right
Recall
For functions of one variable:
There two ways of approaching x 0 : from the left and from the right
Concept of one-sided limits: only two types
Recall
For functions of one variable:
There two ways of approaching x 0 : from the left and from the right
Concept of one-sided limits: only two types
Since the limit is the unique value that the y -values approach as the
x -values approach x 0 from both sides, lim f (x) exists if and only if
xa
xa
xa
Theorem
1
lim
(x,y)(x 0 ,y 0 )
2
c =c
lim
(x,y)(x 0 ,y 0 )
f (x, y) = f (x 0 , y 0 )
Examples
lim
(x,y)(1,2)
2x 3y =
Examples
lim
(x,y)(1,2)
2x 3y = 2 1 3 2 =
Examples
lim
(x,y)(1,2)
2x 3y = 2 1 3 2 = 2
Examples
lim
2x 3y = 2 1 3 2 = 2
lim
1000 =
(x,y)(1,2)
2
(x,y)(0,0)
Examples
lim
2x 3y = 2 1 3 2 = 2
lim
1000 = 1000
(x,y)(1,2)
2
(x,y)(0,0)
lim
(x,y)(x 0 ,y 0 )
1
f (x, y) = L and
lim
(x,y)(x 0 ,y 0 )
2
If c
R, then (x,y)(x
lim
c f (x, y) = c L .
,y )
lim
(x,y)(x 0 ,y 0 )
4
g (x, y) = M , then
f (x, y) g (x, y) = L M
0
lim
(x,y)(x 0 ,y 0 )
f (x, y) g (x, y) = L M .
If M 6= 0, then
lim
(x,y)(x 0 ,y 0 )
f (x, y)
L
= .
g (x, y) M
Remark
As a consequence of the last two theorems, if h(x, y) =
function where f and g are polynomial functions,
lim
(x,y)(x 0 ,y 0 )
provided that g (x 0 , y 0 ) 6= 0.
h(x, y) =
f (x 0 , y 0 )
g (x 0 , y 0 )
f (x, y)
is a rational
g (x, y)
Examples
x 2 2y + 2
=
(x,y)(0,0) x y + 1
lim
Examples
x 2 2y + 2 2
= =2
(x,y)(0,0) x y + 1
1
x2
=
(x,y)(0,0) x 2 + y 2
lim
lim
Examples
x 2 2y + 2 2
= =2
(x,y)(0,0) x y + 1
1
x2
=theorem does not apply!!!
(x,y)(0,0) x 2 + y 2
lim
lim
Announcements
Midterm Exam: February 3, Monday, 7-9 AM, MBLH, conflict need to
sign up with respective recit teachers
Scope of Midterm: until todays lesson
Announcements
Midterm Exam: February 3, Monday, 7-9 AM, MBLH, conflict need to
sign up with respective recit teachers
Scope of Midterm: until todays lesson
No recitation class tomorrow
Announcements
Midterm Exam: February 3, Monday, 7-9 AM, MBLH, conflict need to
sign up with respective recit teachers
Scope of Midterm: until todays lesson
No recitation class tomorrow
Math, Physics (Materials Science) and Chem Majors are invited to the
IMSP Research Colloquium
Tilings, Quasicrystals and Pinwheels
Speaker: Dr. Dirk Frettleoh from Bielefeld University, Germany
To celebrate the International Year of Crystallography
Announcements
Midterm Exam: February 3, Monday, 7-9 AM, MBLH, conflict need to
sign up with respective recit teachers
Scope of Midterm: until todays lesson
No recitation class tomorrow
Math, Physics (Materials Science) and Chem Majors are invited to the
IMSP Research Colloquium
Tilings, Quasicrystals and Pinwheels
Speaker: Dr. Dirk Frettleoh from Bielefeld University, Germany
To celebrate the International Year of Crystallography