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A Level Chemistry Core Practical Sample Teacher Worksheet Acc

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EDEXCEL

Chemistry

Core practical 1 Teacher sheet


Measure the molar volume of a gas

Teacher Resource Pack 1

Core practical 1: Measure the molar volume of a gas


Objective

To find the volume of one mole of carbon dioxide gas

Safety

Specification links

Wear eye protection.

Core practical 1

Ensure the delivery tube does not become blocked.

Practical techniques 1; 4; 11

Ethanoic acid will sting if it gets into cuts in the skin.

CPAC statements 1a; 2a; 2b; 3a;


3b; 4a

Procedure

Notes on procedure
3

1.

Place 30cm of 1 mol dm ethanoic acid in the


boiling tube.

2.

Set the apparatus up as shown in the diagram.

3.

Place approximately 0.05g of calcium carbonate in


a test tube.

4.

Weigh the test tube and its contents accurately.

5.

Remove the bung from the boiling tube and tip the
calcium carbonate into the boiling tube. Quickly
replace the bung in the boiling tube.

6.

Once the reaction is over, measure the volume of


gas collected in the measuring cylinder.

7.

Reweigh the test tube that had contained the


calcium carbonate.

8.

Repeat the experiment six more times, increasing


the mass of calcium carbonate by about 0.05g each
time. Do not exceed 0.40g of calcium carbonate.

Use of over 0.40g of calcium


carbonate will result in the volume
of gas produced exceeding the
capacity of the measuring cylinder.
If larger masses of calcium
carbonate are to be used (such as if
only a 1 d.p. mass balance is
available) then a larger measuring
cylinder will be required.

Use of a stronger acid will result in a


faster reaction and so a greater loss
of gas when the calcium carbonate
is added to the acid.

Answers to questions
1.

CaCO3 + 2CH3COOH Ca(CH3COO)2 + CO2 + H2O

2.

Allows for the mass of any calcium carbonate that remains in the test tube after tipping it out.

3.

Gas loss before replacing the bung.

4.

Use tube containing the acid inside the vessel containing the calcium carbonate tip to mix the
reagent.

5.

When 0.40g of calcium carbonate is used:


moles CaCO3 = 0.4 / 100.1 = 0.003996 moles ethanoic acid = c v = 1 30/1000 = 0.03
moles acid > 2 moles calcium carbonate hence ethanoic acid in excess.

All users will need to review the risk assessment information and may
need to adapt it to local circumstances.

Pearson Education Ltd 2015


This document may have been altered from the original

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