Nothing Special   »   [go: up one dir, main page]

Energy Balance: Hydrogen Production

Download as docx, pdf, or txt
Download as docx, pdf, or txt
You are on page 1of 7

Hydrogen production

ENERGY BALANCE
PRIMARY REFORMER:
Reactions taking place in primary reformer are:
(1) CH
4
+ H
2
O CO + 3H
2
H
298
= +206 kJ/mol
(2) CO + H
2
O CO
2
+ H
2
H
298
= - 41 kJ/mol
Inlet temperature : 500C
Outlet temperature : 860C
H
1133
= H
298
+
}


1073
298
Cpi xi dT
(H
1133
)
1
= 20600+ {(3*14.71*2 + 1*1.12*28) - (1*3.44*16 + 1*2.102*18)}*(1133-298)
= 226726.6 kJ/kmol
(H
1133
)
2
= - 41000 + {(1.05*44 + 2*14.71) - (1.12*28 + 2.102*18)}(1133-298)
= - 36021.4kJ/kmol
Thus ,
Heat required by first reaction : Flow rate of methane (H
1133
)
1

1493.12*226726.6 kJ/hr

= 33.85 10
7
kJ/hr
Heat liberated by second reaction : Flow rate of carbon monoxide (H
1133
)
2

2415.46*36021.4 kJ/hr
= 8.7 10
7
kJ/hr
Enthalpy content of outlet stream :
E (F .x .Cp.1133) =
(224*44*1.265)+(2415.46*28*1.208)+(2446.85*2*15.2)+
(31.26*16*4.71)+(29.02*28*1.192)+(1167.16*18*2.375)
= 179045.28 kJ/hr
Enthalpy content of inlet stream :
E (F .x .Cp.773) =
(1493.12*3.84*16)+(29.06*1.116*28)+(4031.42*3444.3)
= 1.398 10
7
kJ/hr
Hydrogen production

Thus,
Additional heat required,
33.85 10
7
+ 179045.28 - 8.7 10
7
- 1.398 10
7
kJ/hr
= 23.7710
7
kJ/hr
Rest of heating is done in radiation zone of primary reformer using natural gas,
Calorific value = 43000 kJ/m
3

Natural gas required =



=5527.9 m
3
/hr
= 246.8 kmol/hr

Radiation section of reformer:
CH
4
+ 2O
2
CO
2
+ 2H
2
O
Oxygen required = 2242.74= 484.2 kmol/hr
Air required =


=2305.4 kmol/hr

Energy to preheat air from 30C to 500C = m C
p
T
= 3.35610
7
kJ/hr
Natural gas required to preheat the air = 3.35610
7
kJ/hr/43000kJ/m
3

=780 m
3
/hr

HEAT RECOVERY BETWEEN SMR REACTOR & HTSC:
Effluent from secondary reformer is cooled to 673 K before being fed to HTSC. This heat is
utilized for producing HP steam at 250C and 41 bar.
Steam produced:
s T Cp
H
+ A
A

H = heat recovered = 179045*(860-400)
= 8.23610
7
kJ/hr
Hydrogen production

o
= 4.187-80 + 1703 = 4.067 10
7
J/kmol
Steam produced = 8.23610
7
kJ/hr 4.067 10
7
J/kmol
= 2245.16 kmol/hr

HIGH TEMPERATURE SHIFT CONVERTOR:
Inlet temperature: 693 K
CO + H
2
O CO
2
+ H
2
H = -41000 kJ/mol
Additional steam required for reaction = 3507.3 kmol/hr
Enthalpy of inlet steam = [(224.4*1.135*44) + (2415.4*1.112*28) + (2446.85*14.63*2) +
(31.26*3.556*16) + (29.02*1.1*28) + (3507.3*2.071*18)] (673-298)
=8.514 10
7
kJ/hr
Let outlet temperature of HTSC = T
Enthalpy of outlet steam = [(2085.8*1.135*44) + (553.7*1.112*28) + (4309*14.63*2) +
(31.26*3.556*16) + (29.02*1.1*28) + (1645.53*2.071*18)] (T-298)
=31142(T 298) kJ/hr
Heat released by the reaction, H
rxn
= -41000kJ/kmol*2415.46kmol/hr
= 9.9 10
7
kJ/hr
Applying balance: 8.514 10
7
kJ/hr + 9.9 10
7
kJ/hr = 31142(T 298) kJ/hr
T = 889 K
Outlet temperature of HTSC = 889 K
To maintain the temperature of reactor to 425

C , water cooling is required


Heat to be removed= 311482(889-698) = 5.94*10
7

Cooling water available at 30 C and leaves at 70 C
Water required= 5.94*10
7
/ (4.187* 40)*18
= 19673.6 kmol/hr

HEAT RECOVERY BETWEEN HTSC & LTSC:
Inlet temperature = 698 K
Outlet temperature = 573 K
Hydrogen production

Heat removed = 311482(698-523)
=5.451 10
7
kJ/hr
This heat is utilized for producing steam at 373 K and 1 atm.
Amount of steam produced :
s T Cp
H
+ A
A
=

*1/18
=1486 kmol/hr

LOW TEMPERATURE SHIFT CONVERTOR:
Inlet temperature : 523 K
CO + H
2
O CO
2
+ H
2
H = -41000kJ/hr
Inlet enthalpy = (2085.8*0.986*44) + (553.7*1.113*28) + (4308*14.51*2) +
(31.26*2.889*16) + (29.02*1.056*28) + (1645.53*1.954*18)
=292972.64 kJ/hr.K
Outlet enthalpy = (2520*0.986*44 ) + (119.08*1.113*28) + (4743*14.51*2) +
(31.26*2.889*16) + (29.02*1.056*28) + (1210.93*1.954*18)
= 257272.6 kJ/hr.K
H = -41000*553.7 kJ/hr
=2.27 10
7
kJ/hr
Applying balance: 292972.64(523-298) + 2.27 10
7
= 257272.6(T-298)
T = 642 K
Reactor has to be maintained at 250 C to prevent catalyst from over heating and steam from
condensation.
Cooling water available at 30 C will heat to 70 C
Thus required water is
T Cp
H
A
A
= 257272.6(642-523)/ 4.187*40*18
= 10124 kmol/hr

Hydrogen production

CONDENSER:
Exit stream from LTSC contains steam which is an unwanted load on absorber. In condenser,
steam is condensed at 513 K. Further no sub-cooling of products takes place.
Exit gases ( other than steam) are also cooled from 523K to 513K through a heat exchanger
AH = E (F .x .Cp.(523-513)) + F
H2O
* = 3.76 10
7
kJ/hr
Cooling Water at 30 C is heated to 70 C and required amount is =
3.76 10
7
kJ/hr / 4.187*40*18kJ/kmol
=12433.86 kmol/hr
HEAT EXCHANGER BEFORE ABSORBER
Finally remaining gaseous products are cooled from 250

C to 40

C
Heat duty = {(2520*0.986*44 ) + (119.08*1.113*28) + (4743*14.51*2) + (31.26*2.889*16)
+ (29.02*1.056*28)}(250 - 40)
= 4.51*10
7
kJ/hr
Cooling water required =

()

kmol/hr
= 14954.74 kmol/hr

FEED PREHEATER
Feed at 50 C is heated to 210 C by saturated steam available at 600 psig.
Inlet feed temp. = 50C
Outlet feed temp. = 210C
Feed flow rate = 1522.18 kmol/hr
Methane flow rate = 1493.12 kmol/hr
Nitrogen flow rate = 29.02 kmol/hr
Cp (CH
4
) = 41.8 kJ/kmol.K
Cp(N
2
) = 30.43 kJ/kmol.K
Cp (mix) = 0.981*41.8 + 0.019*30.43
= 41.59 kJ/kmol.K
Heat received by feed = mCpT
Hydrogen production

= 1522.18*41.59*(210-50)
= 1.01*10
7
kJ/hr
Steam required = m kg/hr
m = 1.01*10
7
kJ/hr
m = 1.01*10
7
/2233.5
= 4535.12 kg/hr = 251.95 kmol/hr

FEED SUPERHEATER 1 and SUPERHEATER 2
In superheater1 Feed is heated from 210 C to 380 C before fed to the desulfurizer.
saturated steam available at 600 psig.
Cp (CH
4
) = 46.24 kJ/kmol.K
Cp(N
2
) = 30.43 kJ/kmol.K
Cp (mix) = 0.981*46.24 + 0.019*30.43
= 45.94 kJ/kmol.K

Heat received by feed = mCpT
= 1522.18*45.94*(380-210)
= 1.189*10
7
kJ/hr
Steam required = m kg/hr
m = 1.189*10
7
kJ/hr
m = 1.189*10
7
/2233.5
= 5322.5 kg/hr = 295.7 kmol/hr

In superheater2 Feed is heated from 380 C to 500 C before fed to the SMR reactor..
saturated steam available at 600 psig.
Cp (CH
4
) = 56.9 kJ/kmol.K
Cp(N
2
) = 30.8 kJ/kmol.K
Cp (mix) = 0.981*56.9 + 0.019*30.8
Hydrogen production

= 56.4 kJ/kmol.K

Heat received by feed = mCpT
= 1522.18*56.4*(500-380)
= 1.03*10
7
kJ/hr
Steam required = m kg/hr
m = 1.03*10
7
kJ/hr
m = 1.03*10
7
/2233.5
= 4612.9 kg/hr = 256.3 kmol/hr

You might also like