International Journal of Mathematics and Statistics Invention (IJMSI)
International Journal of Mathematics and Statistics Invention (IJMSI)
International Journal of Mathematics and Statistics Invention (IJMSI)
=
) z ( f
) z ( f
A
2
1
and
(
=
) z ( g
) z ( g
B
2
1
be two meromorphic matrix valued functions. If f
k
and g
k
(k=1, 2) satisfy
2
2
2
1
2
2
2
1
) z ( g ) z ( g ) z ( f ) z ( f + = + (1)
on a complex domain D, the n
B A
= , where
A
and
B
are the orders of A and B respectively.
A Short Note on The Order of a Meromorphic Matrix Valued Function
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We use the following lemmas to prove our result.
Lemma 1[3] [ The Nevanlinna Polya theorem]
Let n be an arbitrary fixed positive integer and for each k (k = 1, 2, n) let f
k
and g
k
be analytic
functions of a complex variable z on a non empty domain D.
If f
k
and g
k
(k = 1,2,n) satisfy
2
k
n
1 k
2
k
n
1 k
) z ( g ) z ( f
= =
=
on D and if f
1
,f
2
,f
n
are linearly independent on D, then there exists an n n unitary matrix C, where each of
the entries of C is a complex constant such that
(
(
(
(
(
=
(
(
(
(
(
) z ( f
.
) z ( f
) z ( f
C
) z ( g
) z ( g
) z ( g
n
2
1
n
2
1
holds on D.
Lemma 2 Let f
k
and g
k
be as defined in our theorem (k = 1,2). Then there exists a 2 2 unitary matrix C where
each of the entries of C is a complex constant such that B = CA
(2)
where A and B are as defined in the theorem.
Proof of Lemma 2
We consider the following two cases.
Case A: If f
1
, f
2
are linearly independent on D, then the proof follows from the Nevanlinna Polya theorem.
Case B: If f
1
and f
2
are linearly dependent on D, then there exists two complex constants c
1
, c
2
, not both zero
such that
c
1
f
1
(z) + c
2
f
2
(z) = 0 (3)
We discuss two subcases
Case B
1
: If c
2
= 0, then by (3) we get ) z ( f
c
c
) z ( f
1
2
1
2
= (4)
holds on D.
If we set b = ,
c
c
2
1
\
|
+
'
|
|
.
|
\
|
(8)
Since
2 2
(z) P 4 P(z) ' = A , [14] where P is an analytic function of z, by (8), we get
0
) z ( f
) z ( g
, 0
) z ( f
) z ( g
1
2
1
1
=
'
|
|
.
|
\
|
=
'
|
|
.
|
\
|
Hence, g
1
(z) = c f
1
(z) and g
2
(z) = d f
1
(z) (9)
where c, d are complex constants.
Substituting (9) in (7), we get
2 2 2
b 1 d c + = + (10)
Let us define
(
(
(
(
(
(
(
+ +
+
+
=
b 1
1
b 1
b
b 1
b
b 1
1
: U
2 2
2 2
(11)
and
(
(
(
(
(
(
(
+ +
+
+
=
b 1
c
b 1
d
b 1
d
b 1
c
: V
2 2
2 2
(12)
Then, it is easy to prove that
(
=
(
(
+
b
1
0
b 1
U
2
(13)
and
(
=
(
(
+
d
c
0
b 1
V
2
(14)
Set C = V U
-1
(15)
Since all 2 2 unitarly matrices form a group under the standard multiplication of matrices, by (15), C is a 2 2
unitary matrix.
A Short Note on The Order of a Meromorphic Matrix Valued Function
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Now, by (13), we have
(
(
+
=
|
|
.
|
\
|
0
b 1
b
1
U
2
1
(16)
Thus, we have on D,
b
1
C ) z ( f
) z ( f
) z ( f
C
1
2
1
|
|
.
|
\
|
=
(
, by (5)
|
|
.
|
\
|
|
|
.
|
\
|
=
b
1
U V ) z ( f
1 -
1
, by (15)
|
|
.
|
\
|
+
=
0
b 1
V ) z ( f
2
1
, by (16)
|
|
.
|
\
|
=
d
c
) z ( f
1
, by (14)
(
=
) z ( g
) z ( g
2
1
, by (9)
Hence, the result.
Case B
2
. Let c
2
= 0 and c
1
= 0.
Then by (3), we get f
1
= 0.
Hence, by (1),
2
2
2
1
2
2
(z) g (z) g (z) f + = (17)
holds on D.
By (17) and by a similar argument as in case B
1
, we get the result.
Proof of the theorem
By Lemma 2, we have B = CA where A and B are as defined in the theorem.
Therefore, T(r, B) = T(r, CA)
using the basics of Nevanlinna theory[2], we can show that,
T(r, B) s T(r, A) as T(r,C)=o{T(r,f}
On further simpler simplifications, we get
A B
s
.
(18)
By inter changing f
k
and g
k
(k=1, 2) in Lemma 2,
we get A =CB , which implies
T(r, A) s T(r, B) and hence
B A
s (19)
By (18) and (19), we have
B A
=
Hence the result.
A Short Note on The Order of a Meromorphic Matrix Valued Function
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REFERRENCES
[1.] C. L. PRATHER and A.C.M. RAN (1987) : Factorization of a class of mermorphic matrix valued functions, Jl. of Math.
Analysis, 127, 413-422.
[2.] HAYMAN W. K. (1964) : Meromorphic functions, Oxford Univ. Press, London.
[3.] HIROSHI HARUKI (1996) : A remark on the Nevanlinna-polya theorem in alanytic function theory, Jl. of Math. Ana. and Appl.
200, 382-387.