Mechanical Vibrations-1 PDF
Mechanical Vibrations-1 PDF
Mechanical Vibrations-1 PDF
D
School of Mechanical Engineering
Recommended reading :
... : !"#, Pearson Education
Indochina 2545
Singiresu S.Rao : Mechanical Vibration (Fourth Edition) ,Prentice Hall
2004. SI Edition
Leonard Meirovitch : Fundamentals of Vibrations , Mc-Graw Hill 2001.
Kelly S. Graham : Fundamentals of Mechanical Vibrations,
Mc-Graw Hill 2000.
Vibration Characteristics of a
Spring
Structural Vibration
10
!"#$%&')*+,!)-.&'%&')/0.$1'2*))
11
!"" #$% &'()*+#+
,)-..""" .
/"
.)01#*/2 "% #$""
12
13
14
15
16
17
18
19
$""
*#
*"""*# +/
+*//
2. $'#/2.
2/'
()%/+(*.3+'"""*
+
""")-'#// #$'#/
4#$2 .""
20
XBBSGTGOEFGYTF"
(Undamped Vibration)
#+*(*1*+
#"./
"" (+
).*+/ #$.$/
$""
$*.""(*#'#
""#
$**2**
*(*#""/2(/2
.""(*#.
.""*""*+
*5, (Natural Frequency)
21
22
23
""&)"/+
) .
# *
!)
*+.)
.'()+,"
+#$4 /*,
."",, #
'.#
(Principle of Superposition)
24
""&)"/+
) .
# *
!)
*+.)
.'()+()-,
"+#$4 /*,
25
CDFHEY!"FFG
(Vibration Analysis Procedure)
26
27
.""'
6 (Mathematical Modeling)
#
$* (Derivation of Governing Equations)
#8
9
+
$* (Solution of Governing Equations)
#68
*(/ (Interpretation of the Results)
28
P"XBBL#"!"E[
(Mathematical Modeling)
YGHE#`!O
(Derivation of Governing Equations)
:"$2""*/ %/+.**
/+.""'
+3 ,
..#
+6 .""""/+)(spring )
.*'#/1*+
/+#(damped)
.*)-.#
6 /+
(mass) , 9$+
. 56
)
*+)
)
& (Laplace)s transform)
5*,
(Numerical method)
29
30
FHEYb#!OSP
(Interpretation of the Results)
Yb#Hc#QGHE#`!O
(Solution of Governing Equations)
.
$* """.""'
*
2&(/#
+5* ,
;
$*
;
6
*
*
*
31
5"+.
)8
56*(/
/.*'
+
$(#
4,
32
Mathematical Model of
Motorcycle
."'
*+*/
33
Mathematical Model of
Motorcycle
34
Mathematical Model of
Motorcycle
35
36
Mathematical Model of
Motorcycle
37
38
Spring Elements
Stiffness (N/m)
Youngs modulus (N/m)
Density (kg/m)
Shear modulus G(N/m)
Springs in series
Springs in parallel
F = kx
39
U=
1 2
kx
2
40
Springs in Parallel
Springs in Series
1. Static of the system ( st )
Equilibrium equation
W = k1 st + k 2 st
st = 1 + 2
W = keq st
W = k2 2
where keq = k1 + k 2
W = keq st
k11 = k 2 2 = keq st
or
keq = k1 + k 2 + k3 + + k n
1
1 1 1
1
= + + ++
keq k1 k 2 k3
kn
1 =
that is,
keq st
k1
, 2 =
keq st
k2
1
1 1
= +
keq k1 k 2
41
42
Damping Elements
The stiffness of helical spring is given by
d 4G (0.02 ) 80 109
=
40,000 N m
k=
3
8D 3n
8(0.2 ) 5
4
44
Viscous Damping
Damping
Damper (c)
x
f c = cv(t ) = cx (t )
fc
45
46
Viscous Damping
1 1 1
1
= + +
ceq c1 c2
cn
Damper
Damping coefficient
Critical damping coefficient
Damping ratio
47
48
Underdamped Motion
Overdamped Motion
Critically Damped Motion
49
50
Fsi = ki x ; i = 1,2,3,4
Fdi = ci x ; i = 1,2,3,4
Fd = ceq x
Fs = Fs1 + Fs 2 + Fs 3 + Fs 4
Fd = Fd1 + Fd 2 + Fd 3 + Fd 4
where
keq = k1 + k2 + k3 + k4
ceq = c1 + c2 + c3 + c4
G center of mass , Fsi forces acting on the springs , Fdi forces acting on the dampers
Fs forces acting on all the springs , Fd forces acting on all the dampers
51
52
53