Lifting Lug
Lifting Lug
Lifting Lug
200140X
Page 42
DESIGN CALCULATION
FOR C-2432 C2C SUCTION DRUM 2ND STAGE
APPROVED
WITH COMMENT
REVIEWED
RESUBMIT
CHECKED
APPD (PRJ.)
SIGN
DATE
SAMSUNG ENGINEERING CO., LTD.
7/18/2013
FOR APPROVAL
REV.
ISSUE DATE
DESCRIPTION
PROJECT NAME
SECL JOB NO.
REQUISITION NO.
LETTER OF INTENT NO.
:
:
:
:
WINSON LIM
KS LAW
TC MOK
OWNER :
PURCHASER :
PLANT LOCATION :
KERTEH, MALAYSIA
TABLE OF CONTENT
1.
2.
3.
M.A.W.P. case
13
4.
19
5.
25
1 .1
:
:
GEOMETRIC DATA
Basic design wind speed, V
As per ASCE 7, the wind pressure shall be determined as follows : Qw
= Qz.Gh.Cf N/m
where
Qz = Velocity pressure
( N/m )
Gh = Gust response factor ( dimensionless )
Cf = Force coefficient
( dimensionless )
Calculate : Qz
= 0.613.Kz.(I.V)
where
I
= Importance factor ( table 5 )
V
= Basic design wind speed
1 .2
ASCE 7 - 95
C
=
=
145.08 km/hr
40.30 m/s
=
=
1
40.30 m/s
=
=
274320 mm
7
case 4572mm z zg
Kz
= 2.58 ( z / zg )(2/a)
zg
a
Gh
where
= 0.65 + 3.65.Tz
Tz
Do
Cf
0.005
overall diameter
h/D
D*(Qz)^(1/2)
3000.4 mm
3.6161845
95.856227
>
=
=
=
=
=
0.7436031
2.5
10850 mm
1020.66 N/m
1.242
0.74
942.55 N/m
Vessel diameter, ID
Vessel thickness, ts
Vessel diameter, OD
Insulation thickness (if applicable)
Vessel OD + insulation, Do'
:
:
:
:
:
2000
14
2028
140
2308
mm
mm
mm
mm
mm
=
=
Do'
Do'
3000
+
x
600
1.3
=
=
2908 mm
3000 mm
mm
=
=
3000
30.00 %
2308
2308
over diameter
100 %
WEIGHT CALCULATION
Equipment no:
Equipment name:
Equipment size:
09-F004
NH3 SEPARATOR
ID 1500
T/T 2000
Description
Ellip Head (top)
Ellip Head (bottom)
Shell plate
Jacket head
Jacket shell
Lifting lugs
Reinforcement Plate
Nozzle, N1
Nozzle, N2
Nozzle, N3
Nozzle, N4
Nozzle, N5
Nozzle, N6A
Nozzle, N6B
Nozzle, N7
Nozzle, N8
Nozzle, N9A
Nozzle, N9B
Nozzle, N10
Nozzle, N11
Line pipe
Demister
Elbow N6B
Elbow N9B
Skirt & base ring
Name plate
Miscellaneous
Total
Weight (kg)
286.74
560.21
1799.53
385.25
393.46
36
63
31
31
4
2.9
5.3
5.3
5.3
7.3
138.5
5.3
5.3
4.5
2.9
26
85
2.5
2.5
645.7
2
113.51
4650
Fabrication weight
Empty weight
Content weight
Operating weight
Water weight
Hydrotest weight
Full of water weight
4650
5580
2823
8403
4420
10230
10230
kg
kg
kg
kg
kg
kg
kg
3825 mm
X=
4225 mm
R=
1005 mm
175048
N)
DEG.
--------0
5
10
15
20
25
30
35
40
45
50
55
60
65
70
75
80
85
90
---------
LL
LV
LH
TL
TV
TH
PV
PH
------------------ --------------------- -------------------- --------------------------- ----------------- ------------------ -------------------------- ------------83175
83175
0
91873
91873
0
0
0
84168
83847
7336
90880
90534
7921
3668
##
85154
83860
14787
89894
88528
15610
7393
##
86149
83213
22297
88899
85870
23009
11148
##
87168
81911
29813
87880
82580
30057
14907
##
88229
79963
37287
86819
78684
36691
18644
##
89352
77381
44676
85696
74215
42848
22338
##
90561
74183
51943
84487
69208
48460
25972
##
91887
70389
59064
83161
63705
53455
29532
##
93372
66024
66024
81676
57754
57754
33012
##
95074
61112
72831
79974
51406
61264
36415
##
97077
55681
79521
77971
44722
63870
39760
##
99509
49755
86177
75539
37769
65418
43089
##
102577
43351
92967
72470
30627
65680
46483
##
106639
36473
100208
68408
23397
64283
50104
##
112376
29085
108546
62672
16221
60537
54273
##
121259
21056
119417
53789
9340
52972
59708
##
137193
11957
136671
37855
3299
37711
68335
##
175048
0
175048
0
0
0
87524
##
---------------------------------------------------------------------------------------------------------
FORCE
--------ANGLE
---------
LL
175048
-------------90
--------------
LV
83860
---------------5
----------------
LH
175048
---------------90
----------------
TL
91873
--------------0
---------------
TV
91873
-------------0
--------------
TH
65680
--------------65
---------------
PV
87524
-----------------90
------------------
PH
##
---90
----
1.5 x 17650g
175047.8
SA 537 CL1
SA 240 304
334.8
118.9
22.0
14.0
MM
MM b =
MM d =
MM f =
MM h =
MM B =
MM tr =
MM t2 =
mm
leg (
110.0
38.0
81.0
0.0
264.0
0.0
14.0
15
MPa
MPa
MM
MM
MM
MM
MM
MM
MM
MM
MM
mm)
PK
262
182
444
Note : t1 and t2 are throat length
WT
P=
87858 N
2 x COS 5
2. STRENGTH OF LIFTING LUG
1) SHEAR STRESS
P
Ss =
2 ( t x f + 2tr x h )
=
t=
=
24.7 MPa
< Sa = 0.4Sy =
Shear Stress, Ss x 2
49.30316 Mpa
133.9 MPa
<< OK >>
Please note that P is not
vertical load. P is the max
load during lifting.
2) BENDING STRESS
Pxg
Sb = M / Z =
t x a / 6
0.5WT
=
65.9 Mpa
< Sa = 0.66Sy =
220.9 MPa
0.5WT/cos(5 )
<< OK >>
301.275 Mpa
OK
At Y-Y section
COMBINE STRESSES
s1/2
= (sx + sy/2
= (Sb + Ss/2
=
=
=
65.89
+
24.65
2
45.27
66.94
112.21 OR -21.66326
SQRT [ (
65.89 +
24.65
301.275 Mpa
OK
220.94 Mpa
) /4 + t ]
OK
OK
36.7 MM
a + 2b + 2c
POLAR MOMENT OF INERTIA (J)
(a - d)
J = (2.b [(b/12) + r1] + (a-d)[
n]
12
d
+ 2.c [(c/12) + r2] + d [
+ (c - n)]).t1
12
=
bb
WHERE,
r1 = (
-n)+(
2
r2 = (
c
-n)+
2
4
74063936 MM
a
)=
2
d
)=
2
10334 MM
438 MM
94.7 MPa
76.0 MPa
56.5 MPa
(b - n)
WHERE, = atan ( ----------) =
a/2
3) DIRECT SHEAR STRESS
S2 = P / (2*b*t1 + a*t1)
=
4) MAX. SHEAR STRESS
S = @SQRT ( (S2 + Sv) + Sh )
=
102.5 MPa < Sa = 0.55 x 0.6Sy =
36.6
9.5 MPa
110.5 MPa
<< OK >>
110.5 MPa
<< OK >>
SA 537 CL1
334.8 MPa
91872.92 N
104.0 MM
60.0 MM
22.0 MM
60 MM
208.0 MM
416.0 MM
133.9 MPa
<< OK >>
220.9 MPa
<< OK >>
2) BENDING STRESS
PxB
Sb = M / Z = --------------t x H / 6
=
2. STRENGTH OF WELDMENT
1) REQUIRED WELDMENT BY SHEAR
P
P
Aw = ------- = ------------- =
Sa
0.55x0.4 Sy
1248 MM
2) LEG LENGTH
Aw
l = ---------------- =
Lw
USE LEG LENGTH
3.0 MM
16 MM
<< OK >>
C-2432
A=
=
P x K2
(a x T) + ( 2 x c x t)
95.94
MPa
WHERE , a =
d=
b=
a/d =
T=
c=
t=
74
60
208
1.2333333
22
0
0
<
220.935 MPa
===>
K2 =
O.K!
1.7
l1 =
l2 =
l3 =
:
:
:
:
:
:
:
A 283 GR C
206.8
103.4
91872.92
70.8
41.0
857.5
100.0 MM,L1 =
84.0 MM,L2 =
125.6 MM,L3 =
MPa
MPa
N
MM
MM
MM
200.0 MM,t1 =
320.8 MM,t2 =
112.0 MM,t3 =
1. CALCULATION OF N.A
(L1xt1xl1) + (L2xt2xl2) + (L3xt3xl3)
Y = = ---------------------------------------------------(L1xt1) + (L2xt2) + (L3xt3)
15.9 MM,A1 =
8.0 MM,A2 =
15.9 MM,A3 =
3180.0 MM
2566.4 MM
1780.8 MM
100.6 MM
2. MOMENT OF INERTIA
1.4E+07 MM^4
3. SECTION MODULUS
I
Z = ------- =
Y
142111 MM^3
1.9E+07 N-MM
136.5 MPa
P
5. SHEAR STRESS
==>
Po
P = w Rm
w = P / Rm
Mo
34.10 N/MM
Wo = 0.5 w Rm
14622.03 N
w
6. COMBINED STRESSES
Wo / A2 Sb
138.19008
155.1 MPa
NOT REQUIRED.
BY RAYMOND J.ROARK.
P(TV)
A 106 GR B
206.844 MPa
6236 MM
W 6" X 6" X 20 LB/FT
10389.52 MM
91872.92 N
TENSILE STRESS
ST = P / A
RADIUS OF GYRATION
COMPRESSION STRESS
Pxw
Sc = ----- =
A
WHERE; w =
(i) :
LAMDA
20
30
40
50
60
70
80
90
100
110
0
1
1.03
1.07
1.12
1.19
1.28
1.39
1.53
1.7
2.03
124.1064 MPa
O.K
67.39328 MM
124.1 MPa
L
LAMDA =------ =
n^0.5xi
n=
46.3
1
1
1.03
1.07
1.13
1.20
1.29
1.40
1.54
1.73
2.08
2
1
1.04
1.08
1.13
1.20
1.30
1.41
1.56
1.76
2.13
3
1
1.04
1.08
1.14
1.21
1.31
1.43
1.58
1.79
2.14
4
1
1.05
1.09
1.15
1.22
1.32
1.44
1.59
1.81
2.20
5
1
1.05
1.09
1.16
1.23
1.33
1.46
1.61
1.87
2.40
6
1.01
1.05
1.10
1.17
1.24
1.34
1.47
1.63
1.90
2.47
7
1
##
##
##
##
##
##
##
##
##
AISC
C-2432
L1
L2
D1
D2
e
JOINT EFFICIENCY, n
THROAT = 0.7 t1 = C1
=
=
=
=
=
=
=
41930.05
110
110
197
38
577
0.49
22
N
y
AW1 = 2xC1x(C1+L1)+C1xD1+2xC1xL2
14982
= ((D1/2+C1)+f2)
144.2666
f1
f2 = C1 + L1 - f1
79.32599
Ix = 2x{(C1+L1)xC1^3/12 + (C1+L1)xC1x((C1+D1)/2)}
+2x{C1x((D1-D2)/2)^3/12 + C1x(D1-D2)/2x(D2/2+(D1-D2)/4)}
+2x{L2xC1^3/12+L2xC1x((D2-C1)/2)} + C1xD2^3/12
69873628 +
13915919 +
605572
84395119
Iy = 2x{C1x(C1+L1)^3/12 + C1x(C1+L1)x((C1+L1)/2-f1)}
+2x{((D1-D2)/2xC1^3)/12 + (D1-D2)/2xC1x(f1-C1/2)}
+2x{C1xL2^3/12+C1xL2x(L2/2-f1)}
+{D2xC1^3/12 + D2xC1x(L2+C1/2-f1)}
9464612
6216143
4906519
3936535
24523810
Ip = Ix + Iy
1.09E+08
+
+
+
74.389
MPa <0.6*0.7*Sy =
140.595 MPa
< OK >
5.712
MPa
<
140.595 MPa
< OK >
80.101
MPa
<
140.595 MPa
< OK >
SHEAR STRESS
S2 = LV / (AW1xn)
COMBINED SHEARING STRESS
Ss = S1 + S2
87858.23
SHEAR STRESS
SV1 = P / (AW1xn)
11.968
<
140.595
< OK >
MPA
0.816
<
234.325
< OK >
MPA (0.7*Sy)
TENSILE STRESS
SV2 = R1 / (AW1*n)
R = P TAN 15 * (L7+L8)/L7
29532.691 N
R1 = R - PTAN 15
5991.1491 N
COMPRESSIVE STRESS
Sc = R / AW2
AW2 = a * t / 1.414
13.25
2229.14
MM2
144.7908 MPa
<OK>