Chemistry Project 2
Chemistry Project 2
Chemistry Project 2
Certificate
Acknowledgement
Aim
Introduction
Materials and Equipment
Theory
ExperimentalProcedure
*Experiment 1
*Experiment 2
*Experiment 3
Result
Precautions
Bibliography
AIM
The aim of this project is to
determine the amount of
Acetic Acid in different
types of vinegar using
titration with a coloured pH
indicator to determine the
endpoint
INTRODUCTION
Vinegar is a solution made from the fermentation
of ethanol (CH3CH2OH), which in turn was
previously fermented from sugar. The
fermentation of ethanol results in the production
of acetic acid (CH3COOH). There are many
different types of vinegar, each starting from a
different original sugar source (e.g., rice, wine,
malt, etc.). The amount of acetic acid in vinegar
can vary, typically between 4 to 6% for table
vinegar, but up to three times higher (18%) for
pickling vinegar. In this project, we will determine
the amount of acid in different vinegars using
titration, a common technique in chemistry.
Titration is a way to measure the unknown
amount of a chemical in a solution (the titrant) by
adding a measured amount of a chemical with a
known concentration (the titrating solution). The
titrating solution reacts with the titrant, and the
endpoint of the reaction is monitored in some
way. The concentration of the titrant can now be
calculated from the amount of titrating solution .
added, and the ratio of the two chemicals in the
chemical equation for the reaction. To measure the
acidity of a vinegar solution, we can add enough
hydroxyl ions to balance out the added hydrogen
ions from the acid. The hydroxyl ions will react with
the hydrogen ions to produce water.
In order for a titration to work, we need three things:
1. A titration solution (contains hydroxyl ions with a
precisely known concentration),
2. A method for delivering a precisely measured
volume of the Titrating solution,
3. A means of indicating when the endpoint has
been reached.
For the titrating solution, we'll use a dilute solution
of sodium hydroxide (NaOH). Sodium hydroxide is a
strong base, which means that it dissociates almost
completely in water. So for every NaOH molecule
that we add to the solution, we can expect to
produce a hydroxyl ion. To dispense an accurately
measured volume of the titrating solution, we will
use a burette. A burette is a long tube with a valve at
the Bottom and graduated markings on the outside
to measure the volume Contained in the burette.
The burette is mounted on a ring stand, directly
above the titrant solution (as shown in the picture).
. Solutions in the burette tend to creep up the sides
of the glass at the surface of the liquid. This is due to
the surface tension of water. The surface of the
liquid thus forms a curve, called a meniscus. To
measure the volume of the liquid in the burette,
always read from the bottom of the meniscus. In
this experiment, we will use an indicator solution
called Phenolphthalein.
Molarmass of NaOH=40g/mol
=0.5 x 40 x 500
1000
= 10 g
CH3COOH(aq) + NaOH(aq)--->CH3COONa(aq)+H20
(acid) + (base) ---> (salt) + (water)
Indicator: - Phenolphthalein
End Point: - Colourless to pink
EXPERIMENTAL PROCEDURE
Performing the Titration
OBSERVATION
Burette Reading
Volum
Volume of
Sl.no e of
NaOH
vineg
ar
Initial{ml} Final{ml}
3 1.5 ml 0 23 ml 30.4 ml
CALCULATION
50-14.3=35.7 ml
50-19.6=30.4 ml
50-23=27 ml
Volume of NaOH Used
=> 35.7+30.4+27
3
=> 93.1
3
=>31.03 ml
Molarity of NaOH=0.02M
Average volume of NaOH=31.03
=0.03103
Vinegar solution=1.5 ml
=0.0015 ml
M=0.02 M x 0.03103
0.0015 l
= 0.4137 M/l
OBSEVATION
Burette reading
Volume of Volume of
Serial.
vinegar NaOH
No
Initial{ml}
Final{ml}
=> 32.4+35.2+31.1
3
=> 98.7
3
=>32.9 ml
Molarity of NaOH=0.02M
Average volume of NaOH=32.9
=0.0329
Vinegar solution=1.5 ml
=0.0015 ml
M=0.02 M x 0.0329
0.0015 l
= 0.4139 M/l
OBSEVATION
Burette reading
Volume of Volume of
Serial.
vinegar NaOH
No
Initial{ml}
Final{ml}
1 1.5 ml 0 13 ml 37 ml
2 1.5 ml 0 9 ml 41 ml
=> 37+41+39.7
3
=> 114.7
3
=>38.2 ml
Molarity of NaOH=0.02M
Average volume of NaOH=38.2
=0.0382
Vinegar solution=1.5 ml
=0.0015 ml
M=0.02 M x 0.0382
0.0015 l
= 0.509 M/l
Red Wine Vinegar < White Wine Vinegar < Synthetic Vinegar
PRECAUTION
Transference of measured vinegar into a measuring flask
should be done very carefully.
Measuring must be performed carefully.
Look at the meniscus of solution at eye level to avoid
parallax.
Look at the lower meniscus in the light coloured solution
and upper meniscus in the dark coloured solution because
of visibility.
Do not forget to add distilled water to the vinegar.
BIBLIOGRAPHY