PARKING SHADE Report
PARKING SHADE Report
PARKING SHADE Report
Design Method:
Loading Code: SBC 301 - CR & ASCE-07-16.
Steel design code: AISC 360 -16 – LRFD
European Design Guide for Tensile Structure.
Materials:
- Fabric: HDPE 430 g/m2
- Steel sections: ASTM A53GR B
- Steel Plate: Grade A36
- Bolts, Nuts: Gr. 8.8
Loads:
Dead load / self-weight.
Self-weight steel are automatically
added by the software.
Wind load:
• In X – Direction
• In Y – Direction
LOADS
❖ Wind load: (WL)
Location → RIYADH
Ultimate wind speeds for Risk Category I Buildings and other Structures.
Assign wind load:
Wind Load X direction:
Material
Steel A53GrB, A36
Concrete 4000 psi
Name Material
1 - css A53GrB
Anchors
N Vy Vz Mx My Mz
Name Member
[kN] [kN] [kN] [kNm] [kNm] [kNm]
UDSTL1(1) 23F -3.5 0.0 -0.1 0.0 -6.0 0.0
UDSTL4(2) 23F -2.2 0.0 2.9 0.0 -10.5 0.0
UDSTL2(4) 23F -2.9 0.0 2.9 -0.1 -11.8 0.0
UDSTL5(5) 23F -2.3 0.0 -3.1 0.0 2.7 0.0
UDSTL3(3) 23F -3.0 0.0 -3.1 0.0 1.4 0.0
Foundation block
Check
Summary
Plates
Design data
fy εlim
Material
[MPa] [%]
A53GrB 241.4 5.0
A36 248.2 5.0
Symbol explanation
Anchors
V ϕNcb ϕVcb
Nf ϕVcp Utt Uts Utts Statu
Shape Item Loads [kN g g
[kN] [kN] [%] [%] [%] s
] [kN] [kN]
250. 18.
A1 UDSTL5(5) 9.4 0.8 101.8 - 1.2 6.1 OK
8 5
42. 250. 84. 75.
A2 UDSTL2(4) 0.9 101.8 - 1.2 OK
9 8 3 3
250. 18.
A3 UDSTL5(5) 9.4 0.8 101.8 - 1.2 6.1 OK
8 5
42. 250. 84. 75.
A4 UDSTL2(4) 0.8 101.8 - 1.2 OK
9 8 3 3
Design data
ϕNsa ϕVsa
Grade
[kN] [kN]
27 A325M - 1 266.7 148.6
Symbol explanation
Nf Tension force
V Resultant of shear forces Vy, Vz in bolt
ϕNcbg Concrete breakout strength in tension – ACI 318-14 – 17.4.2
ϕVcbg Concrete breakout strength in shear – ACI 318-14 – 17.5.2
ϕVcp Concrete pryout strength in shear – ACI 318-14 – 17.5.3
Utt Utilization in tension
Uts Utilization in shear
Utts Utilization in tension and shear
ϕNsa Steel strength of anchor in tension - ACI 318-14 – 17.4.1
ϕVsa Steel strength of anchor in shear - ACI 318-14 – 17.5.1
Weld sections
Th Ls L Lc Fn ϕRn Ut
Item Edge Xu Loads Status
[mm] [mm] [mm] [mm] [kN] [kN] [%]
BP1 23F E70xx ◢4.0 ◢5.7 383 6 UDSTL2(4) 5.9 7.8 76.2 OK
Symbol explanation
Concrete block
A1 A2 σ Ut
Item Loads Status
[mm2] [mm2] [MPa] [%]
CB 1 UDSTL2(4) 33196 392274 2.8 9.0 OK
Symbol explanation
A1 Loaded area
A2 Supporting area
σ Average stress in concrete
Ut Utilization
Buckling
Code settings
Item Value Unit Reference
Friction coefficient - concrete 0.40 - ACI 349 – B.6.1.4
Friction coefficient in slip-
0.30 - AISC 360-16 J3.8
resistance
Limit plastic strain 0.05 -
Plastic
Weld stress evaluation
redistribution
Detailing No
Distance between bolts [d] 2.66 - AISC 360-16 – J3.3
Distance between bolts and edge
1.25 - AISC 360-16 – J.3.4
[d]
Concrete breakout resistance
Both
check
Base metal capacity check at
No AISC 360-16: J2-2
weld fusion face
Cracked concrete Yes ACI 318-14 – Chapter 17
Local deformation check No
Local deformation limit 0.03 - CIDECT DG 1, 3 - 1.1
Analysis with large deformations for
Geometrical nonlinearity (GMNA) Yes
hollow section joints
BASE
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
Loading Data
Unfactored loads
Column LF LF P Hx Hy Mx My
Load Case: Number ULS ULS (kN) (kN) (kN) (kNm) (kNm)
ovt
Sketch of Base
BS8110 - 1997 Y
C1
X
B
A
Y
Mx
P
Hx
X
Z
Y
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
0.20 0.20
X X
0.80
0.80
1.80 1.80
Y Y
Mx Mx
P P
Hx Hx
0.30
0.30
0.30 0.30
0.60 0.60
f st
est =
Es
391.3
=
200000
= 0.0020
d
xb =
est
1 +
ec
550
=
.00196
1 +
.0035
= 352.564 mm
%redis
bb = 1 -
100
0
=1 -
100
= 1.0000
min d
x= , (bb - 0.4 ). d
est
1 +
ec
min 550
= , (.9 - 0.4 )×550
.00196
1 +
.0035
= 275.000
a = b. x
= .9 ×275
= 247.500 mm
a . . . . .
Mu = a . d - b a f f cu 1×10-6
2
247.5
= 247.5 × 550 - ×1000 ×.66667 ×.66667 ×35 ×1×10-6
2
= 1 641.079 kNm
M
z = d . 0.5 + 0.25 -
2 a f b . d 2 . f cu
. . .
2817×103
= 550 × 0.5 + 0.25 -
2 ×.66667 ×.66667 ×1000 ×550 2 ×35
= 549.835 mm
z = min(z , 0.95 . d )
= min( , 0.95 ×550 )
= 0.0000×100
M
Ast =
f st . z
2817×103
=
391.3 ×522.5
= 13.778 mm2
2 . (d - z )
NA =
b
2 ×(550 - 522.5 )
=
.9
= 61.111 mm
f st
est =
Es
391.3
=
200000
= 0.0020
d
xb =
est
1 +
ec
550
=
.00196
1 +
.0035
= 352.564 mm
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
%redis
bb = 1 -
100
0
=1 -
100
= 1.0000
min d
x= , (bb - 0.4 ). d
est
1 +
ec
min 550
= , (.9 - 0.4 )×550
.00196
1 +
.0035
= 275.000
a = b. x
= .9 ×275
= 247.500 mm
a . . . . .
Mu = a . d - b a f f cu 1×10-6
2
247.5
= 247.5 × 550 - ×1000 ×.66667 ×.66667 ×35 ×1×10-6
2
= 1 641.079 kNm
M
z = d . 0.5 + 0.25 -
2 a f b . d 2 . f cu
. . .
1536×103
= 550 × 0.5 + 0.25 -
2 ×.66667 ×.66667 ×1000 ×550 2 ×35
= 549.910 mm
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
z = min(z , 0.95 . d )
= min( , 0.95 ×550 )
= 0.0000×100
M
Ast =
f st . z
1536×103
=
391.3 ×522.5
= 7.513 mm2
2 . (d - z )
NA =
b
2 ×(550 - 522.5 )
=
.9
= 61.111 mm
f st
est =
Es
391.3
=
200000
= 0.0020
d
xb =
est
1 +
ec
540
=
.00196
1 +
.0035
= 346.154 mm
%redis
bb = 1 -
100
0
=1 -
100
= 1.0000
min d
x= , (bb - 0.4 ). d
est
1 +
ec
min 540
= , (.9 - 0.4 )×540
.00196
1 +
.0035
= 270.000
a = b. x
= .9 ×270
= 243.000 mm
a . . . . .
Mu = a . d - b a f f cu 1×10-6
2
243
= 243 × 540 - ×1000 ×.66667 ×.66667 ×35 ×1×10-6
2
= 1 581.946 kNm
M
z = d . 0.5 + 0.25 -
2 . a . f . b . d 2 . f cu
90297
= 540 × 0.5 + 0.25 -
2 ×.66667 ×.66667 ×1000 ×540 2 ×35
= 539.995 mm
z = min(z , 0.95 . d )
= min( , 0.95 ×540 )
= 0.0000×100
M
Ast =
f st . z
90297
=
391.3 ×513
= 0.4498 mm2
2 . (d - z )
NA =
b
2 ×(540 - 513 )
=
.9
= 60.000 mm
Column number:1
Shear Calculations:
Area used for shear calculations:
3.4.5.4-6
Ast
F1 =
Ash
.44982
=
540000
= 833.00×10-9
3.4.5.4-6
f 1 = f 1i . 100
= 0 ×100
= 0.0000×100
F1 = min(F1, 3 )
= min( , 3 )
= 0.0000×100
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
F1 = max(F1, 0.15 )
= max( , 0.15 )
= 0.1500
3.4.5.4-6
f2 = 1
3.4.5.4-6
f cu 0.33333
F3 =
25
35 0.33333
=
25
= 1.119
v c = v c1. F3
= .3358 ×1.1187
= 0.3757 MPa
3.4.5.4-6
v cu = 0.8 . f cu
= 0.8 × 35
= 4.733 MPa
3.4.5.4-6
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
v cu = min(v cu, 5 )
= min( , 5 )
= 0.0000×100
V . 1×103
v=
Ash
0 ×1×103
=
540000
= 0.0000×100 MPa
0.40 . b
Asv/svn =
0.95 . f yv
0.40 ×1000
=
0.95 ×450
= 0.9357
Job Number Sheet
Job Title
Client
Your details here
Calcs by Checked by Date
4Y16-A-250 (B1)
col1
8Y16-D-250 ABR (T2)
8Y16-B-250 (B2)
PLAN
B B B B B B B B
SECTION