Convection
Convection
Convection
Abdulraof Habibullah
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heat transfer
Heat Transfer By Eng. Abdulraof Habibullah
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Introduction
It is well known that a hot plate of metal will cool faster when placed in front of a fan than when
exposed to still air. We say that the heat is convected away, and we call the process convection
heat transfer. The term convection provides the reader with an intuitive motion concerning the
heat-transfer process; however, this intuitive motion must be expanded to enable one to arrive at
anything like an adequate analytical treatment of the problem. For example, we know that the
velocity at which the air blows over the hot plate obviously influences the heat-transfer rate. But
does it influence the cooling in a linear way; i.e., if the velocity is doubled, will the heat-transfer
rate doubled? We should suspect that the heat transfer rate might be different if we cooled the
plate with water instead of air, but, again, how much difference would there be? These questions
may be answered with the aid of some rather basic analyses presented in later chapters.
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CONVECTION
Convection: The mode of energy transfer between a solid surface and the adjacent liquid or gas
that is in motion, and it involves the combined effects of conduction and fluid motion.
The faster the fluid motion, the greater the convection heat transfer.
In the absence of any bulk fluid motion, heat transfer between a solid surface and the adjacent fluid
is by pure conduction.
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CONVECTION
Forced convection: If the fluid is forced to flow over the surface by external means such as a
fan, pump, or the wind.
Natural (or free) convection: If the fluid motion is caused by buoyancy forces that are induced
by density differences due to the variation of temperature in the fluid.
Heat transfer processes that involve change of phase of a fluid are also considered to be
convection because of the fluid motion induced during the process, such as the rise of the
vapor bubbles during boiling or the fall of the liquid droplets during condensation.
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Newton s law of cooling
Regardless of the reason for the motion in the fluid, whether forced or natural, we call this
mechanism convective heat transfer
Note that this equation only serves to define this heat transfer coefficient h, and we must have
some way of knowing its value to use the equation for the heat flux. Later, we ll learn about
correlations that are used to calculate h values of in a variety of flow situations.
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Convective Heat Transfer Coefficient
For the present h may be considered as a constant in a given problem. From Newton's Law
of Cooling, we see that the thermal resistance between the fluid and the wall is
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Consider the plane wall shown in the Figure exposed to a hot fluid A on one side and a cooler
fluid B on the other side. The heat transfer is expressed by
Example 1
A house wall may be approximated as two 1.2 cm layers of fiber insulating board (k = 0.038
W/mK), an 8.0 cm layer of loosely packed asbestos (k = 0.16 W/mK), and a 10 cm layer of
common brick (k = 0.72 W/mK). Assuming convection heat-transfer coefficients of 12W/m2
oC on both sides of the wall, calculate the overall heat-transfer coefficient for this
arrangement.
Heat Transfer By Eng. Abdulraof Habibullah
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Class work
An insulation system is to be selected for a furnace wall at 1000 oC using first a layer of mineral
wool blocks (km=0.09 W/m oC) followed by fiberglass boards (kf=0.042 W/m oC) . The outside of
the insulation is exposed to an environment with h=15 W/m2 oC and T =40 oC. calculate the
thickness of each insulating material such that the interface temperature is not greater than 400 oC
and the outside temperature is not greater than 55 oC. What is the heat loss in this wall in watts
per square meter? [q/A= 225 W/m2, xm=0.24 m, xf=0.0644 m]
[Li= 0.195 m]
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Homework # 2
The rear window of an automobile is defogged by passing warm air at 40 C over its inner
surface, and the associated convection coefficient is 30 W/m2 K. Under conditions for which the
outside ambient air temperature is -10 C and the associated convection coefficient is 65 W/m2 K,
what are the inner and outer surface temperatures of the window? The window glass is 4 mm
thick and the thermal conductivity of it k= 1.4 W/m K [Ti=7.73 oC, To= 4.89 oC]
The rear window of an automobile is defogged by attaching a thin, transparent, film-type heating
element to its inner surface. By electrically heating this element, a uniform heat flux may be
established at the inner surface. What is the electrical power that must be provided per unit
window area to maintain an inner surface temperature of 15 C when the interior air temperature
and convection coefficient are 25 C and 10 W/m2 K and the exterior (ambient) air temperature
and convection coefficient are -10 C and 65 W/m2 K? The window glass is 4 mm thick and the
thermal conductivity of it k= 1.4 W/m K.
Heat Transfer By Eng. Abdulraof Habibullah
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ro
k ri
TFi , hi TFo , ho
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For steady conditions, this must be the same as the heat transfer rate through the pipe wall and
the heat transfer rate to the surrounding fluid. Thus, with
ro
ri
k
TFi , hi TFo , ho
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ro
ri
k
TFi , hi TFo , ho
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Consider the plane wall shown in the Figure exposed to a hot fluid A on one side and a cooler
fluid B on the other side. The heat transfer is expressed by
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The heat-transfer process may be represented by the resistance network in the Figure, and the
overall heat transfer is calculated as the ratio of the overall temperature difference to the sum of
the thermal resistances
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The overall heat transfer by combined conduction and convection is frequently expressed in
terms of an overall heat-transfer coefficient U, defined by the relation
Example 1
Water flows at 50 oC inside a 2.5-cm-inside-diameter tube such that hi =3500 W/m2 oC. The tube
has a wall thickness of 0.8 mm with a thermal conductivity of 16 W/m oC. The outside of the
tube loses heat by free convection with ho =7.6 W/m2 oC. Calculate the overall heat-transfer
coefficient and heat loss per unit length to surrounding air at 20 oC.
ro
ri
k
TFi , hi TFo , ho
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Class work
A 5 cm diameter steel pipe is covered with a 1 cm layer of insulating material having k = 0.22 W/m oC
followed by a 3 cm thick layer of another insulating material having k = 0.06 W/m oC . The entire
assembly is exposed to a convection surrounding condition of h = 60 W/m2 oC and T =15 oC. The
outside surface temperature of the steel pipe is 400 oC. Calculate the heat lost by the pipe-insulation
assembly for a pipe length of 20 m. Express in Watts.
A domestic hot water pipe is made of copper and has an internal diameter of 25 mm and a thickness of
2 mm. The pipe is exposed to atmospheric air at 10 oC and the hot water flowing inside the pipe is at 60
oC. The thermal conductivity of copper is k = 385 W/m K. The convective heat transfer coefficient h
has values of 3500 W/m2 K and 6.5 W/m 2K at the internal and external tube surfaces, respectively.
Calculate the overall thermal resistance between the hot water and the atmosphere for a unit length of
tube, based on the internal surface of the tube calculate the rate at which heat is lost to the atmosphere
per unit length of the tube.
[R = 1.693 K/W] [Ui = 0.591 W/K] [ = 29.5 W/m]
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HW# 2 Q2
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where dAs is the surface area of the differential element. Substituting the foregoing rate
equations into the energy balance
To simplify the form of this equation, we transform the dependent variable by defining an
excess temperature as
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O
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Fin Performance
Recall that fins are used to increase the heat transfer from a surface by increasing the
effective surface area. However, the fin itself represents a conduction resistance to heat
transfer from the original surface. For this reason, there is no assurance that the heat transfer
rate will be increased through the use of fins. An assessment of this matter may be made by
evaluating the fin effectiveness f. It is defined as the ratio of the fin heat transfer rate to the
heat transfer rate that would exist without the fin. Therefore
Hence the fin effectiveness may be interpreted as a ratio of thermal resistances, and to
increase f it is necessary to reduce the conduction/convection resistance of the fin. If the fin
is to enhance heat transfer, its resistance must not exceed that of the exposed base.
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Fin Performance
Another measure of fin thermal performance is provided by the fin efficiency f. The maximum
driving potential for convection is the temperature difference between the base (x=0) and the
fluid, ( b =Tb T ) Hence the maximum rate at which a fin could dissipate energy is the rate
that would exist if the entire fin surface were at the base temperature. However, since any fin is
characterized by a finite conduction resistance, a temperature gradient must exist along the fin
and the preceding condition is an idealization. A logical definition of fin efficiency is therefore
s
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Fin Performance
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ix s
I
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L O
eaggooeta
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Example 1
A very long rod 5 mm in diameter has one end maintained at 100 C. The surface of the rod is
exposed to ambient air at 25 with a convection heat transfer coefficient of 100 W/m2 .
Determine the temperature distributions along rods constructed from pure copper k= 398 W/m
O 2
Gt
Example 2
A circumferential fin of rectangular profile has a thickness of 0.7mm and is installed on a tube
having a diameter of 3 cm that is maintained at a temperature of 200 C. The length of the fin is
2 cm and the fin material is copper. Calculate the heat lost by the fin to a surrounding
convection environment at 100 C with a convection heat-transfer coefficient of 524 W/m2 C.
0
r1= 0.015m f= 0.55
r2= r1+L = 0.015+ 0.02=0.035 m I
r2c= r2+t/2 = 0.035+ 0.00035 = 0.03535 m Qf = f hA b