Yr 12 Extension 1 Exam Term 3 2021
Yr 12 Extension 1 Exam Term 3 2021
Yr 12 Extension 1 Exam Term 3 2021
Mathematics Extension 1
1
Section I - 5 marks
Use the multiple choice answer sheet for questions 1-5
1. 1
Which of the following functions is a primitive of ?
4 − 9x 2
1 −1 2 x
A) sin
3 3
1 −1 3 x
B) sin
9 2
1 −1 2 x
C) sin
9 3
1 −1 3 x
D) sin
3 2
2. A cricket ball is hit from the origin so that its position vector at time t is given by
r (t ) = 15ti + (20t − 5t 2 ) j for t ≥ 0, where i is the unit vector in the forward direction and j is a unit
vector vertically up.
When the cricket ball reaches its maximum height, what is its position vector?
r 30 i + 20 j
A) =
r 15i + 20 j
B) =
C) r = 60 i
r 30 i + 10 j
D) =
3. If sin(α
= + β ) a and sin(α
= cos β ?
− β ) b then sin α=
A) a 2 + b2
B) ab
C) a 2 − b2
a+b
D)
2
2
4. The direction (slope) field for a first order differential equation is shown.
5. ax d 2 y dy
The equation y = e satisfies the differential equation + − 6y =
0. What are the possible values
dx 2 dx
of 𝑎𝑎?
A) a = 3or a = −2
B) a = −6 or a =−1
C) a = 1or a = −6
D) a = 2 or a = −3
End of Section I
3
Section II
47 marks
Attempt Questions 6-9
Allow about 1 hour and 23 minutes for this section
Answer each question on the appropriate page of your answer booklet. Extra paper is available. Your
responses should include relevant calculations and/or mathematical reasoning.
ii. y = e x ( cos −1 x ) 2
dy 2 x
= = where y (0) 1
dx 3 y 2
k
dx π
∫ 9+ x
0
2
=
9
?
e) Evaluate 2
π
4
4
Question 7 (9 marks)
a) 1 for −π ≤ x ≤ π .
Consider the equation cos x − 2sin x =
t 2 + 2t =
0, where x 1
i. Show that the equation can be written as t = tan .
2
ii. Hence, solve the equation cos x − 2sin x =
1 for −π ≤ x ≤ π , giving solution to two 2
decimal places where necessary.
b) Solve=
sin 2θ cos θ for 0 ≤ θ ≤ 2π . 2
5
Question 8 (14 marks) Marks
a) 2 3 sin θ − 2cos θ in the form π 2
i. Express R sin(θ − α ) where R > 0 and 0 < α < .
2
ii. =
Find the values of 𝑥𝑥 for which f ( x) 2 3 sin x − 2cos x attains its maximum 2
b) x
The diagram below shows the graph of y = 2 cos −1 .
3
The area under the curve for 0 ≤ x ≤ 3 is shaded.
6
c)
3
The shaded region is bounded by the curve y = 1 + 2 x , the y − axis and the horizontal
Calculate the exact volume of the solid of revolution formed when the shaded region is
d) i. Show that 2
π 1 + 3 tan θ
tan θ + = .
6 3 − tan θ
2
ii. Hence, or otherwise, solve for 0 ≤ θ ≤ 2π
1 + 3 tan θ =
( 3 − tan θ ) tan(π − θ ).
7
Question 9 (11 marks)
a) A projectile is fired from O at an angle θ to the horizontal with initial velocity V ms−1 to
strike a target R metres right of O on the level ground. Assume the displacement of the
gt 2
r (t )= (Vt cos θ ) i + Vt sin θ − j. Do not prove it.
2
2V 2
tan 2 θ − tan θ + 1 =0
gR
ii. Show that the target will be hit from two angles of projection, say 𝜃𝜃1 and θ 2 , if
2
V2
R< .
g
iii. Let the respective times of flight for each path be t1 and t2 . By considering the roots 2
of the equation in part (i) or otherwise, find the difference in the two times in terms
of V , g and R.
8
b) A colony of bacteria occupied the area A cm 2 . The colony has its growth modelled by the
dA 1
logistic equation = A(50 − A) where t ≥ 0 and t is measured in days. At time
dt 25
1
𝑡𝑡 = 0, the area occupied by the bacteria colony is cm 2 .
2
1 1 1 1 1
i) Show that = + .
A(50 − A) 50 A 50 − A
3
ii) Using the above result, solve the logistic equation and hence show that
50
A= .
1 + 99e −2t
1
iii) According to this model, what is the limiting area of the bacteria colony?
End of Exam