UPtplj SIi A57 SHG 7 P4 AO
UPtplj SIi A57 SHG 7 P4 AO
UPtplj SIi A57 SHG 7 P4 AO
SYLLABUS :
CHEMISTRY
Chemical Bond, Octet Rule, Ionic Bond, Covalent Bond, Fajan's Rule ( 0 6]
Max. Marks : 120 Time : 60 min.
GENERAL INSTRUCTIONS
•
The Daily Practice Problem Sheet contains 30 MCQ's. For each question only one option is correct. Darken the correct drcle/
bubble in the Response Grid provided on each page.
•
You have to evaluate your Response Grids yourself with the help of solution booklet.
Each correct answer will get you 4 marks and 1 mark shall be deduced for each incorrect answer. No mark will be given/ deducted
if no bubble is filled. Keep a timer in front of you and stop immediately at the end of 60 min.
•
• The sheet follows a particular syllabus. Do not attempt the sheet before you have completed your preparation for that syllabus.
Refer syllabus sheet in the starting of the book for the syllabus of all the DPP sheets.
• After completing the sheet check your answers with the solution booklet and complete the Result Grid. Finally spend time to
l
ana yse your performance and revise the areas which emerge out as weak in your evaluation.
DIRECTIONS (Q.l-Q.21) : There are 21 multiple choice Q.3 W11ich ofthe following is most covalent ?
questions. Each question has 4 choices (a), (b), (c) and (d), (a) AlF3 (b) AlCl3 (c) AJBr3 (d) All3
out of which ONLY ONE choice is correct. Q.4 Among LiCl, BeCl2, BCl3 and CC14, the covalent bond
Q.l Which follows octet rule ? character follows the order -
(a) SF6 (b) PCI5 (c) NH3 (a) LiCI < BeC I2 > BCI3 > CCI4
Q.2 The crystal lattice of an electrovalent compound is composed
of-
I
(b) LiC > BeCl2 < BCI3 < CCI4
(c) LiCI < BeC12 < BCI3 < CCI4
(a) atoms (d) LiCI > BeC12 > BC13 > CCI4
(b) molecules Q.S Wllich of the following bonds is most polar ?
(c) oppositely charged ions (a) 0 - H (b) P - H
ll o
(d) both mo ecu es and i n s (c) C - F (d) S - CI
(a) Statement-! is True, Statement-2 is True; Statement-2 is a Statement-2 : Energy is absorbed during the formation of
correct explanation for Statement-!. crystal lattice.
(b) Statement-! is True, Statement-2 is True; Statement-2 is Q.30 Statement-! : According to Fajan's rule, covalent character
NOT a correct explanatioll for Statement- ! . is favoured by small cation and small anion.
(c) Statement -1 is False, Statement-2 is True. Statement-2 : The magnitude of covalent character in the
(d) Statement -I is True, Statement-2 is False. ionic bond depends upon the extent of polarisation.
(5)
(c)
(c)
The covalent character increases according to charge
on cation.
Due to maximum electronegativity difference.
constant
(18) (b)
80 2 7 21 4.1
Polarisation in the molecule increases with increase
(6) (d) As the size of anion increases, polarity character of charge and decreases in size ofthe cation when the
increases. anion is same.
(7) (b)
_
Yo Ioruccharacter- x
(a) Observed dipolemoment
(8) Though all compounds have covalent bond but there 0 . . 100
(19) (b) Theoretical dipole moment
is coordination bond also between N and C in
C2H5 NC, C2H5 N � C
=e= 2.xd=(J. 6 x J 0-19C)x(J.41 x I0-10m)
Theoretical dipole moment ofa I 00% ionic character
256 w-29
(9) (d) The structure ofNp5 clears about it
x em
. 1 0 11. 5
O � N -0- N � O
II II
0 0 2 6 x 0-3
% ionic character = =
(10) (a) Structure ofH2S207 is as follows 2.256x 10-29
0
0 (20) (d) BF3 is planar while NF3 is pyramidal due to the
i i presence of lone pair ofelectron on nitrogen in NF3 .
H-0-S -0-S - 0 - H (21) (b) Agl has maximum covalent character [ ·: Cis a large
.1. ! anion], whileAgF has minimum covalent character,
0 0
therefore, it has more solubility.
(11) (b) (22) (a)
(12) (a) A cation with non-noble gas configuration is more (23) (a) Covalent bond is directional.
polarising than the cation with noble gas configuration
(24) (a) According to Fajan's rule, polarisation of anion is
and so these cation favours covalency.
1(1
influenced by charge and size of cati,on. More is the
(13) (a) Valency ofelement X is 2(2 electrons in the outermost
charge on cation, more is polarisation ofanion.
shell) while that ofelement Y is electron required
in the outermost shell to complete octet). So the
(25) (b) Using Fajan's rule, larger cation and smaller anion will
formula ofthe compound between X and Y is XY2. have maximum ionic character.
(26) (a) Because zn+2 has smallest size among the all.
(14) (b) In this case the valence electrons in the atom A is
three and hence its valency is generally 3. 1n the atom (27) (d) As the size of cation increases, polarizing power
B t11e number of valence electrons is six. Hence, its decreases hence ionic character increases.
valency is usually 2. Hence the formula ofthe molecule (28) (d) The size of alkali metal increases from Li to K. So,
formed from A and B could be A2B3. An example of statement-1 is true & statement-2 is false.
two such elements are AI and 0 and the fonnula of (29) (d) Energy is released during the formation ofthe crystal