Cambridge International Examinations

Cambridge International General Certificate of Secondary Education (9–1)

MATHEMATICS 0626/06
Paper 6 (Extended) For Examination from 2017
SPECIMEN MARK SCHEME
2 hours

MAXIMUM MARK: 96

This syllabus is regulated in England as a Cambridge International Level 1/Level 2 (9–1) Certificate.

This document consists of 9 printed pages and 1 blank page.

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Marking instructions

MARKING - GENERAL

1. Where a candidate has crossed out a complete part of a question, it should be marked provided
that it has not been replaced.

2. If two or more methods are offered, mark the method that leads to the answer on the answer line.

3. Method marks are for a full correct method but may be lost if subsequent incorrect method is
shown.

4. Unless a particular method has been specified in the question, full marks may be awarded for any
correct method. However, if a calculation is required then no marks will be awarded for a scale
drawing.

5. Where the answer in the answer space is incorrect because of a clear transcription error, then
marks may be awarded.

6. Occasionally a candidate will misread a number in a question and use that value consistently
throughout. Provided that number does not alter the difficulty or method required, award all marks
earned and penalise 1 mark. M marks are still awarded in any case. Record this by using the MR
annotation.

7. Unless specified in the question, answers may be given as fractions, decimals or in standard form.
Ignore superfluous zeros provided that the degree of accuracy is not affected.

8. Allow any sensible notation. Watch out for commas being used for decimal points and dots being
used for products. Brackets may be seen to represent inequalities.

9. Anything in the mark scheme which is in square brackets […] is not required for the mark to be
earned, but if present it must be correct.

10. FT – A correct answer will score or follow through after an error.

Strict FT – you must follow through from their error. These will be indicated in the mark scheme.

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ABBREVIATIONS IN MARK SCHEME

Abbreviation Meaning
M Method marks – for a correct method applied to appropriate numbers
A Accuracy marks – depend on M marks. Hence M0 A1 is not possible
B Independent of method marks – for a correct final answer or intermediate stage

SC Marks given in special cases only when indicated in mark scheme

FT Work can be followed through after an error
isw Ignore subsequent working (after correct answer obtained)
cao Correct answer only
nfww Not from wrong working
oe Or equivalent
soi Seen or implied
eeo Each error or omission
dep Dependent on the previous mark(s)

ACCURACY

1. If a question asks for a particular level of accuracy then the mark scheme will include specific
details.

2. In other cases, the following apply:

• More than 3 sf in the answer but correct (either rounded or truncated to 4 or more figure
accuracy) – allow full marks.
• Less than 3 sf in the answer but correct to 3 or more sf seen in the working – allow full marks
even if rounded incorrectly.
• 3 sf incorrect in the answer but 3 or more correct seen in the working – allow full marks.
• If the third sf is zero after the decimal point (e.g. 15.0) then allow marks for 2 sf answers
providing no wrong working is seen.

3. General principles are:

• 2 sf answers will not imply method in most cases.
• If the final answer on the answer line has clearly been spoiled from the 3 sf or more answer
seen in the working (more than just rounding errors) don’t allow the marks.
• Mark at most accurate which is usually where the answer is first seen.
• If the most accurate answer is incorrect then it scores zero, even if it has been correctly
rounded into a correct answer.
• If this answer is then used in another part of the question then any M marks are available.
• If an accuracy FT is also available in the new part, then give the FT mark for a correct follow
through from a value which has lost the accuracy mark in the first part.
• However, a correct value from the first part may have been given the accuracy mark but has
then been rounded incorrectly and this has been condoned. If the wrongly rounded value is
used in the new part and leads to an incorrect answer, even if correctly followed through, then
this should not receive the accuracy mark here and should not be treated as a FT case.

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4. Exact answers involving π and

• Exact answer 2.345 π Unless question is set in context (where some appreciation of
appropriate accuracy is required),
allow A1 for 2.345 π on the answer line,
allow A0 for 2.35 π.
Mark scheme will indicate in final column if marks to be allowed.
• Exact answer √23 Scores A1 if the question is not set in context and the √(prime
number) is given on the answer line.
Scores A0 if the question is set in context (where some appreciation
of appropriate accuracy is required).
Surd answers which simplify need not be implied e.g. √12 or 2√3
are acceptable but not irrational denominators – if simplified, mark
the simplified answer i.e. not isw.
Mark scheme will indicate in final column if marks to be allowed.

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 Qu. Answers Mark Part Marks Notes
1 (a) 50.27 6 B3 for 53.2[0] seen
or M2 for 2 × 6 (6 + 4 × 2) + 3 × (3.60 + 4 ×

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1.20)
or M1 for 6 + 4 × 2 and 3.60 + 4 × 1.20 or
better seen
M1 for their 53.2[0] × 1.05 oe [63.84]
and M1 for multiplying their costs at any stage
by 0.90
(b) 11 cao 4 B2 for 201 Accept 2.01 or 64π or 0.64π for
or M1 for 2 × π × 32 or 2 × π × 0.32 B2
M1FT for 2400 ÷ their 201 oe
If 0 scored SC3 for answer 11.9
or SC2 for figs 119 as answer
(c) 11.6 3 M2 for 40 × [0].29
or M1 for 360
9 × 29 soi by 1160
5

25
2 (a) (i) 798 or 798.4 to 798.41 2 M1 for 10712 ÷ 13 or 10712 ÷ 13.4...
60

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(ii) 1.82 × 105 4 B3 for 182 000 or 181 500 to 181 600 seen
or 1.815 × 105 to 1.816 × 105 or M2 for 10 712 000 ÷ 59 oe
or M1 for figs 10 712 ÷ figs 59 soi by figs 182
or figs 1815 to 1816
and B1FT for their number of litres correctly
converted to standard form rounded to 3sf or
better
(b) 8600 3 M2 for 10148 ÷ 1.18 oe
or M1 for 10148 associated with 118[%]
3 (a) (i) 640 × 1.026 oe M1 Must be seen
= 720.7… B1
(ii) 3.02 or 3.020 to 3.024… nfww 4 M3 for [x =] 4 721 ' 640 or better (implied by
answer of 1.03[02…] or r = 0.0302[4…]
or M2 for (their x)4 = 721 ÷ 640

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or M1 for 640 × (their x)4 = 721 oe
 Qu. Answers Mark Part Marks Notes
(b) 874.80 final answer 2 M1 1200 × (1 – 0.1)3 oe

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2 (s - ut)
4 (a) oe nfww 3 M1 for a correct rearrangement to isolate the a
t2 term
M1 for a correct multiplication by 2
M1 for a correct division by t2
16
(b) (i) or better [3.2] 1
5
1
(ii) 280 3 M2 for (25 + 10)16 oe
2
or M1 for correct attempt to find one relevant
area
24 x
5 (a) (i) (100 – 70) × 0.4 [= 12] or better 1 Accept × 39 oe Not enough for = 30 then
78 0.4
x = 12
Must arrive at 12 and not use it
6

– no reverse method

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(ii) 60.9 or 60.89... nfww 5 B1 for 3 or 4 correct extra frequencies 3, 6, 10, e.g. 30 × 0.1 for 3
8 soi Condone one error or omission
M1 for at least 4 of mid-interval values 15, 40, Including either boundary and
55, 65, 85 soi condone one further error or
M1 for Σfx where x is any value in each omission
interval allow their frequencies provided
integers and they must be shown
[3 × 15 + 6 × 40 + 10 × 55 + 8 × 65 + 12 × 85]
[2375]
M1 (dependent on second M1) for ÷ 39
or ÷ (3 + 6 + 10 + 8 + 12)
(b) 60.5 3 M2 for 20 × 70 – 19 × 70.5 oe
or M1 for either 20 × 70 or 19 × 70.5 M1 implied by 1400 or 1339.5
seen
 Qu. Answers Mark Part Marks Notes
6 (a) 45.[0] or 45.01 to 45.02 nfww 4 M2 for 552 + 702 – 2 × 55 × 70 cos 40
or M1 for correct implicit equation

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A1 for 2026.[...]
(b) 84.9 or 84.90 to 84.91 4 B1 for angle BDC = 40 soi
70 sin (their 40)
M2 for
sin 32
or M1 for correct implicit equation
1
(c) 4060 or 4063 to 4064 nfww 3 M2 for (55 × 70 sin 40)
2
1
+ (70 × their (b) sin (180 – their 40 – 32)) oe
2
or M1 for correct method for one of the triangle
areas
distance
(d) 35.4 or 35.35... nfww 2 M1 for sin 40 = or better
55
7

1
or for (55 × 70 sin 40) = (70 × distance) ÷ 2
2

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or better
7 (a) (0, 16) (4, –16) 6 M1 for 3x2 or 12x
A1 correct 3x2 – 12x
B1 setting their dy/dx = 0
M1 for factorising their dy/dx
A1 x = 0 and x = 4
A1 (0, 16) and (4, –16)
(b) (0, 16) maximum with correct reason 3 B2 for both correct with no/one reason
(4, –16) minimum with correct reason or B1 for one correct (with no reasons)
or M1 correct attempt to find e.g. second
derivative or gradients

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 Qu. Answers Mark Part Marks Notes
8 (a) (5, –3) 6 M2 for
(–3, 5) x2 + (2 – x)2 = 34

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or (y – 2)2 + y2 = 34
or M1 for y = 2 – x
or x = 2 – y

M1FT for 2x2 – 4x – 30 = 0 oe Rearranging their quadratic to

=0
M1FT for (x – 5)(x + 3) = 0

A1 for x = 5, x = –3 Factorising their quadratic

A1FT for y = –3, y = –5 equation

FT correctly substituting their x

into x + y = 2

(b) (their xA - their xB) 2 + (their y A - their yB) 2

8

M1

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(- 3 - 5) 2 + (5 - (- 3)) 2 A1
9 (a) (i) 90 ÷ (42/360 × π × 82) oe M3 M2 for 42/360 × π × 82 × h = 90
or M1 for 42/360 × π × 82
3.836 to 3.837 A1
(ii) 131 or 130.75 to 130.9 nfww 5 M2 for 42/360 × π × 2 × 8 × 3.84 oe [22.48 to
22.53]
or
M1 for 42/360 × π × 2 × 8 oe soi [5.86 to
5.87]
and M1 for 2 × (8 × 3.84) [61.37 to 61.44]
and M1 for 2 × (42/360 × π × 82) [46.88 to 47]
 Qu. Answers Mark Part Marks Notes
3 22.5
(b) 2.42 or 2.416 to 2.419... 3 M2 for 3.84 × oe or
90

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3 3.84 3 # 22.5
h=
90
3 22.5 3 90
or M1 for oe or oe seen
90 22.5
3.84 3 90
or = oe
h3 22.5
10 (a) 2n – 1 oe 2 B1 for 2k seen
1 3
(b) [a =] oe, [b =] oe 6 B1 for 12 or 30 seen but if 30 clearly only from
2 2
diagram 4 then B0.
M1 for any 1 of a + b + 1 = 3 oe, 8a + 4b + 2 =
12 oe, 27a + 9b + 3 = 30 oe
M1 for a 2nd of the above equations
M1 (indep) for correctly eliminating a or b
9

from pair of linear equations

A1 for one correct value

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