C Programming Language

1) How do you construct an increment statement or
decrement statement in C?
There are actually two ways you can do this. One is to use the increment
operator ++ and decrement operator –. For example, the statement “x++”
means to increment the value of x by 1. Likewise, the statement “x –”
means to decrement the value of x by 1. Another way of writing increment
statements is to use the conventional + plus sign or – minus sign. In the
case of “x++”, another way to write it is “x = x +1”.
2) What is the difference between Call by Value and Call by

Reference?
When using Call by Value, you are sending the value of a variable as
parameter to a function, whereas Call by Reference sends the address of
the variable. Also, under Call by Value, the value in the parameter is not
affected by whatever operation that takes place, while in the case of Call
by Reference, values can be affected by the process within the function.
3) Some coders debug their programs by placing comment

symbols on some codes instead of deleting it. How does
this aid in debugging?
Placing comment symbols /* */ around a code, also referred to as
“commenting out”, is a way of isolating some codes that you think maybe
causing errors in the program, without deleting the code. The idea is that if
the code is in fact correct, you simply remove the comment symbols and
continue on. It also saves you time and effort on having to retype the codes
if you have deleted it in the first place.
4) What is the equivalent code of the following statement

in WHILE LOOP format?
for (a=1; a<=100; a++)
printf ("%d\n", a * a);

Answer:
a=1;
while (a<=100) {
printf ("%d\n", a * a);
a++;
5) What is a stack?
A stack is one form of a data structure. Data is stored in stacks using the
FILO (First In Last Out) approach. At any particular instance, only the top of
the stack is accessible, which means that in order to retrieve data that is
stored inside the stack, those on the upper part should be extracted first.
Storing data in a stack is also referred to as a PUSH, while data retrieval is
referred to as a POP.
6) What is a sequential access file?

When writing programs that will store and retrieve data in a file, it is
possible to designate that file into different forms. A sequential access file
is such that data are saved in sequential order: one data is placed into the
file after another. To access a particular data within the sequential access
file, data has to be read one data at a time, until the right one is reached.
7) What is variable initialization and why is it important?

This refers to the process wherein a variable is assigned an initial value
before it is used in the program. Without initialization, a variable would
have an unknown value, which can lead to unpredictable outputs when
used in computations or other operations.
8 What is spaghetti programming?

Spaghetti programming refers to codes that tend to get tangled and
overlapped throughout the program. This unstructured approach to
coding is usually attributed to lack of experience on the part of the
programmer. Spaghetti programing makes a program complex and
analyzing the codes difficult, and so must be avoided as much as possible.
9) Differentiate Source Codes from Object Codes

Source codes are codes that were written by the programmer. It is made
up of the commands and other English-like keywords that are supposed to
instruct the computer what to do. However, computers would not be able
to understand source codes. Therefore, source codes are compiled using a
compiler. The resulting outputs are object codes, which are in a format
that can be understood by the computer processor. In C programming,
source codes are saved with the file extension .C, while object codes are
saved with the file extension .OBJ
10) In C programming, how do you insert quote characters

(‘ and “) into the output screen?
This is a common problem for beginners because quotes are normally part
of a printf statement. To insert the quote character as part of the output,
use the format specifiers \’ (for single quote), and \” (for double quote).
11) What is the use of a ‘\0’ character?

It is referred to as a terminating null character, and is used primarily to
show the end of a string value.
12) What is the difference between the = symbol and ==

symbol?
The = symbol is often used in mathematical operations. It is used to assign
a value to a given variable. On the other hand, the == symbol, also known
as “equal to” or “equivalent to”, is a relational operator that is used to
compare two values.
13) What is the modulus operator?
The modulus operator outputs the remainder of a division. It makes use of
the percentage (%) symbol. For example: 10 % 3 = 1, meaning when you
divide 10 by 3, the remainder is 1.
14) What is a nested loop?

A nested loop is a loop that runs within another loop. Put it in another
sense, you have an inner loop that is inside an outer loop. In this scenario,
the inner loop is performed a number of times as specified by the outer
loop. For each turn on the outer loop, the inner loop is first performed.
15) Which of the following operators is incorrect and why?

( >=, <=, <>, ==)
<> is incorrect. While this operator is correctly interpreted as “not equal to”
in writing conditional statements, it is not the proper operator to be used
in C programming. Instead, the operator != must be used to indicate “not
equal to” condition.
16) Compare and contrast compilers from interpreters.

Compilers and interpreters often deal with how program codes are
executed. Interpreters execute program codes one line at a time, while
compilers take the program as a whole and convert it into object code,
before executing it. The key difference here is that in the case of
interpreters, a program may encounter syntax errors in the middle of
execution, and will stop from there. On the other hand, compilers check
the syntax of the entire program and will only proceed to execution when
no syntax errors are found.
17) How do you declare a variable that will hold string

values?
The char keyword can only hold 1 character value at a time. By creating an
array of characters, you can store string values in it. Example: “char
MyName[50]; ” declares a string variable named MyName that can hold a
maximum of 50 characters.
18) Can the curly brackets { } be used to enclose a single

line of code?
While curly brackets are mainly used to group several lines of codes, it will
still work without error if you used it for a single line. Some programmers
prefer this method as a way of organizing codes to make it look clearer,
especially in conditional statements.
19) What are header files and what are its uses in C
programming?
Header files are also known as library files. They contain two essential
things: the definitions and prototypes of functions being used in a
program. Simply put, commands that you use in C programming are
actually functions that are defined from within each header files. Each
header file contains a set of functions. For example: stdio.h is a header file
that contains definition and prototypes of commands like printf and scanf.
20) What is syntax error?

Syntax errors are associated with mistakes in the use of a programming
language. It maybe a command that was misspelled or a command that
must was entered in lowercase mode but was instead entered with an
upper case character. A misplaced symbol, or lack of symbol, somewhere
within a line of code can also lead to syntax error.
21) What are variables and it what way is it different from

constants?
Variables and constants may at first look similar in a sense that both are
identifiers made up of one character or more characters (letters, numbers
and a few allowable symbols). Both will also hold a particular value. Values
held by a variable can be altered throughout the program, and can be used
in most operations and computations. Constants are given values at one
time only, placed at the beginning of a program. This value is not altered in
the program. For example, you can assigned a constant named PI and give
it a value 3.1415 . You can then use it as PI in the program, instead of
having to write 3.1415 each time you need it.
22) How do you access the values within an array?

Arrays contain a number of elements, depending on the size you gave it
during variable declaration. Each element is assigned a number from 0 to
number of elements-1. To assign or retrieve the value of a particular
element, refer to the element number. For example: if you have a
declaration that says “intscores[5];”, then you have 5 accessible elements,
namely: scores[0], scores[1], scores[2], scores[3] and scores[4].
23) Can I use “int” data type to store the value 32768?
Why?
No. “int” data type is capable of storing values from -32768 to 32767. To
store 32768, you can use “long int” instead. You can also use “unsigned
int”, assuming you don’t intend to store negative values.
24) Can two or more operators such as \n and \t be

combined in a single line of program code?
Yes, it’s perfectly valid to combine operators, especially if the need arises.
For example: you can have a code like printf (“Hello\n\n\’World\'”) to output
the text “Hello” on the first line and “World” enclosed in single quotes to
appear on the next two lines.
25) Why is it that not all header files are declared in every C
program?
The choice of declaring a header file at the top of each C program would
depend on what commands/functions you will be using in that program.
Since each header file contains different function definitions and
prototype, you would be using only those header files that would contain
the functions you will need. Declaring all header files in every program
would only increase the overall file size and load of the program, and is not
considered a good programming style.
26) When is the “void” keyword used in a function?

When declaring functions, you will decide whether that function would be
returning a value or not. If that function will not return a value, such as
when the purpose of a function is to display some outputs on the screen,
then “void” is to be placed at the leftmost part of the function header.
When a return value is expected after the function execution, the data type
of the return value is placed instead of “void”.
27) What are compound statements?

Compound statements are made up of two or more program statements
that are executed together. This usually occurs while handling conditions
wherein a series of statements are executed when a TRUE or FALSE is
evaluated. Compound statements can also be executed within a loop.
Curly brackets { } are placed before and after compound statements.
28) What is the significance of an algorithm to C

programming?
Before a program can be written, an algorithm has to be created first. An
algorithm provides a step by step procedure on how a solution can be
derived. It also acts as a blueprint on how a program will start and end,
including what process and computations are involved.
29) What is the advantage of an array over individual

variables?
When storing multiple related data, it is a good idea to use arrays. This is
because arrays are named using only 1 word followed by an element
number. For example: to store the 10 test results of 1 student, one can use
10 different variable names (grade1, grade2, grade3… grade10). With
arrays, only 1 name is used, the rest are accessible through the index name
(grade[0], grade[1], grade[2]… grade[9]).
30) Write a loop statement that will show the following

output:
1
12
123
1234
12345
Answer:
for (a=1; a<=5; i++) {
for (b=1; b<=a; b++)
printf("%d",b);
printf("\n");
}
31) What is wrong in this statement?
scanf(“%d”,whatnumber);
An ampersand & symbol must be placed before the variable name
whatnumber. Placing & means whatever integer value is entered by the
user is stored at the “address” of the variable name. This is a common
mistake for programmers, often leading to logical errors.
32) How do you generate random numbers in C?

Random numbers are generated in C using the rand() command. For
example: anyNum = rand() will generate any integer number beginning from 0,
assuming that anyNum is a variable of type integer.
33) What could possibly be the problem if a valid function

name such as tolower() is being reported by the C compiler
as undefined?
The most probable reason behind this error is that the header file for that
function was not indicated at the top of the program. Header files contain
the definition and prototype for functions and commands used in a C
program. In the case of “tolower()”, the code “#include <ctype.h>” must be
present at the beginning of the program.
34) What are comments and how do you insert it in a C

program?
Comments are a great way to put some remarks or description in a
program. It can serves as a reminder on what the program is all about, or a
description on why a certain code or function was placed there in the first
place. Comments begin with /* and ended by */ characters. Comments can
be a single line, or can even span several lines. It can be placed anywhere
in the program.
35) What is debugging?

Debugging is the process of identifying errors within a program. During
program compilation, errors that are found will stop the program from
executing completely. At this state, the programmer would look into the
possible portions where the error occurred. Debugging ensures the
removal of errors, and plays an important role in ensuring that the
expected program output is met.
36) What does the && operator do in a program code?

The && is also referred to as AND operator. When using this operator, all
conditions specified must be TRUE before the next action can be
performed. If you have 10 conditions and all but 1 fails to evaluate as
TRUE, the entire condition statement is already evaluated as FALSE
37) In C programming, what command or code can be used

to determine if a number of odd or even?
There is no single command or function in C that can check if a number is
odd or even. However, this can be accomplished by dividing that number
by 2, then checking the remainder. If the remainder is 0, then that number
is even, otherwise, it is odd. You can write it in code as:
if (num % 2 == 0)
printf("EVEN");
else
printf("ODD");
38) What does the format %10.2 mean when included in a
printf statement?
This format is used for two things: to set the number of spaces allotted for
the output number and to set the number of decimal places. The number
before the decimal point is for the allotted space, in this case it would allot
10 spaces for the output number. If the number of space occupied by the
output number is less than 10, addition space characters will be inserted
before the actual output number. The number after the decimal point sets
the number of decimal places, in this case, it’s 2 decimal spaces.
39) What are logical errors and how does it differ from
syntax errors?
Program that contains logical errors tend to pass the compilation process,
but the resulting output may not be the expected one. This happens when
a wrong formula was inserted into the code, or a wrong sequence of
commands was performed. Syntax errors, on the other hand, deal with
incorrect commands that are misspelled or not recognized by the
compiler.
40) What are the different types of control structures in

programming?
There are 3 main control structures in programming: Sequence, Selection
and Repetition. Sequential control follows a top to bottom flow in
executing a program, such that step 1 is first perform, followed by step 2,
all the way until the last step is performed. Selection deals with
conditional statements, which mean codes are executed depending on the
evaluation of conditions as being TRUE or FALSE. This also means that not
all codes may be executed, and there are alternative flows within.
Repetitions are also known as loop structures, and will repeat one or two
program statements set by a counter.
41) What is || operator and how does it function in a

program?
The || is also known as the OR operator in C programming. When using || to
evaluate logical conditions, any condition that evaluates to TRUE will
render the entire condition statement as TRUE.
42) Can the “if” function be used in comparing strings?

No. “if” command can only be used to compare numerical values and
single character values. For comparing string values, there is another
function called strcmp that deals specifically with strings.
43) What are preprocessor directives?

Preprocessor directives are placed at the beginning of every C program.
This is where library files are specified, which would depend on what
functions are to be used in the program. Another use of preprocessor
directives is the declaration of constants.Preprocessor directives begin
with the # symbol.
44) What will be the outcome of the following conditional
statement if the value of variable s is 10?
s >=10 && s < 25 && s!=12
The outcome will be TRUE. Since the value of s is 10, s >= 10 evaluates to
TRUE because s is not greater than 10 but is still equal to 10. s< 25 is also
TRUE since 10 is less then 25. Just the same, s!=12, which means s is not
equal to 12, evaluates to TRUE. The && is the AND operator, and follows
the rule that if all individual conditions are TRUE, the entire statement is
TRUE.
45) Describe the order of precedence with regards to

operators in C.
Order of precedence determines which operation must first take place in
an operation statement or conditional statement. On the top most level of
precedence are the unary operators !, +, – and &. It is followed by the
regular mathematical operators (*, / and modulus % first, followed by +
and -). Next in line are the relational operators <, <=, >= and >. This is then
followed by the two equality operators == and !=. The logical operators &&
and || are next evaluated. On the last level is the assignment operator =.
46) What is wrong with this statement? myName =

“Robin”;
You cannot use the = sign to assign values to a string variable. Instead, use
the strcpy function. The correct statement would be: strcpy(myName,
“Robin”);
47) How do you determine the length of a string value that

was stored in a variable?
To get the length of a string value, use the function strlen(). For example, if
you have a variable named FullName, you can get the length of the stored
string value by using this statement: I = strlen(FullName); the variable I will
now have the character length of the string value.
48) Is it possible to initialize a variable at the time it was

declared?
Yes, you don’t have to write a separate assignment statement after the
variable declaration, unless you plan to change it later on. For example:
char planet[15] = “Earth”; does two things: it declares a string variable
named planet, then initializes it with the value “Earth”.
49) Why is C language being considered a middle level

language?
This is because C language is rich in features that make it behave like a
high level language while at the same time can interact with hardware
using low level methods. The use of a well structured approach to
programming, coupled with English-like words used in functions, makes it
act as a high level language. On the other hand, C can directly access
memory structures similar to assembly language routines.
50) What are the different file extensions involved when

programming in C?
Source codes in C are saved with .C file extension. Header files or library
files have the .H file extension. Every time a program source code is
successfully compiled, it creates an .OBJ object file, and an
executable .EXE file.
51) What are reserved words?

Reserved words are words that are part of the standard C language library.
This means that reserved words have special meaning and therefore
cannot be used for purposes other than what it is originally intended for.
Examples of reserved words are int, void, and return.
52) What are linked list?
A linked list is composed of nodes that are connected with another. In C
programming, linked lists are created using pointers. Using linked lists is
one efficient way of utilizing memory for storage.
53) What is FIFO?

In C programming, there is a data structure known as queue. In this
structure, data is stored and accessed using FIFO format, or First-In-First-
Out. A queue represents a line wherein the first data that was stored will be
the first one that is accessible as well.
54) What are binary trees?

Binary trees are actually an extension of the concept of linked lists. A
binary tree has two pointers, a left one and a right one. Each side can
further branch to form additional nodes, which each node having two
pointers as well. Learn more about Binary Tree in Data Structure if you are
interested.
55) Not all reserved words are written in lowercase. TRUE

or FALSE?
FALSE. All reserved words must be written in lowercase; otherwise the C
compiler would interpret this as unidentified and invalid.
56) What is the difference between the expression “++a”

and “a++”?
In the first expression, the increment would happen first on variable a, and
the resulting value will be the one to be used. This is also known as a prefix
increment. In the second expression, the current value of variable a would
the one to be used in an operation, before the value of a itself is
incremented. This is also known as postfix increment.
57) What would happen to X in this expression: X += 15;
(assuming the value of X is 5)
X +=15 is a short method of writing X = X + 15, so if the initial value of X is 5,
then 5 + 15 = 20.
58) In C language, the variables NAME, name, and Name

are all the same. TRUE or FALSE?
FALSE. C language is a case sensitive language. Therefore, NAME, name
and Name are three uniquely different variables.
59) What is an endless loop?

An endless loop can mean two things. One is that it was designed to loop
continuously until the condition within the loop is met, after which a break
function would cause the program to step out of the loop. Another idea of
an endless loop is when an incorrect loop condition was written, causing
the loop to run erroneously forever. Endless loops are oftentimes referred
to as infinite loops.
60) What is a program flowchart and how does it help in

writing a program?
A flowchart provides a visual representation of the step by step procedure
towards solving a given problem. Flowcharts are made of symbols, with
each symbol in the form of different shapes. Each shape may represent a
particular entity within the entire program structure, such as a process, a
condition, or even an input/output phase.
61) What is wrong with this program statement? void = 10;

The word void is a reserved word in C language. You cannot use reserved
words as a user-defined variable.
62) Is this program statement valid? INT = 10.50;

Assuming that INT is a variable of type float, this statement is valid. One
may think that INT is a reserved word and must not be used for other
purposes. However, recall that reserved words are express in lowercase, so
the C compiler will not interpret this as a reserved word.
63) What are actual arguments?

When you create and use functions that need to perform an action on
some given values, you need to pass these given values to that function.
The values that are being passed into the called function are referred to as
actual arguments.
64) What is a newline escape sequence?

A newline escape sequence is represented by the \n character. This is used
to insert a new line when displaying data in the output screen. More spaces
can be added by inserting more \n characters. For example, \n\n would
insert two spaces. A newline escape sequence can be placed before the
actual output expression or after.
65) What is output redirection?

It is the process of transferring data to an alternative output source other
than the display screen. Output redirection allows a program to have its
output saved to a file. For example, if you have a program named
COMPUTE, typing this on the command line as COMPUTE >DATA can
accept input from the user, perform certain computations, then have the
output redirected to a file named DATA, instead of showing it on the screen
66) What are run-time errors?

These are errors that occur while the program is being executed. One
common instance wherein run-time errors can happen is when you are
trying to divide a number by zero. When run-time errors occur, program
execution will pause, showing which program line caused the error.
67) What is the difference between functions abs() and
fabs()?
These 2 functions basically perform the same action, which is to get the
absolute value of the given value. Abs() is used for integer values, while
fabs() is used for floating type numbers. Also, the prototype for abs() is
under <stdlib.h>, while fabs() is under <math.h>.
68) What are formal parameters?

In using functions in a C program, formal parameters contain the values
that were passed by the calling function. The values are substituted in
these formal parameters and used in whatever operations as indicated
within the main body of the called function.
69) What are control structures?

Control structures take charge at which instructions are to be performed in
a program. This means that program flow may not necessarily move from
one statement to the next one, but rather some alternative portions may
need to be pass into or bypassed from, depending on the outcome of the
conditional statements.
70) Write a simple code fragment that will check if a

number is positive or negative
If (num>=0)
printf("number is positive");
else
printf ("number is negative");

71) When is a “switch” statement preferable over an “if”
statement?
The switch statement is best used when dealing with selections based on a
single variable or expression. However, switch statements can only
evaluate integer and character data types.
72) What are global variables and how do you declare
them?
Global variables are variables that can be accessed and manipulated
anywhere in the program. To make a variable global, place the variable
declaration on the upper portion of the program, just after the
preprocessor directives section.
73) What are enumerated types?

Enumerated types allow the programmer to use more meaningful words
as values to a variable. Each item in the enumerated type variable is
actually associated with a numeric code. For example, one can create an
enumerated type variable named DAYS whose values are Monday,
Tuesday… Sunday.
74) What does the function toupper() do?

It is used to convert any letter to its upper case mode. Toupper() function
prototype is declared in <ctype.h>. Note that this function will only convert
a single character, and not an entire string.
75) Is it possible to have a function as a parameter in

another function?
Yes, that is allowed in C programming. You just need to include the entire
function prototype into the parameter field of the other function where it
is to be used.
76) What are multidimensional arrays?

Multidimensional arrays are capable of storing data in a two or more
dimensional structure. For example, you can use a 2 dimensional array to
store the current position of pieces in a chess game, or position of players
in a tic-tac-toe program.
77) Which function in C can be used to append a string to
another string?
The strcat function. It takes two parameters, the source string and the
string value to be appended to the source string.
78) What is the difference between functions getch() and

getche()?
Both functions will accept a character input value from the user. When
using getch(), the key that was pressed will not appear on the screen, and
is automatically captured and assigned to a variable. When using getche(),
the key that was pressed by the user will appear on the screen, while at the
same time being assigned to a variable.
79) Dothese two program statements perform the same

output? 1) scanf(“%c”, &letter); 2) letter=getchar()
Yes, they both do the exact same thing, which is to accept the next key
pressed by the user and assign it to variable named letter.
80) What are structure types in C?

Structure types are primarily used to store records. A record is made up of
related fields. This makes it easier to organize a group of related data.
81) What does the characters “r” and “w” mean when
writing programs that will make use of files?
“r” means “read” and will open a file as input wherein data is to be
retrieved. “w” means “write”, and will open a file for output. Previous data
that was stored on that file will be erased.
82) What is the difference between text files and binary
files?
Text files contain data that can easily be understood by humans. It
includes letters, numbers and other characters. On the other hand, binary
files contain 1s and 0s that only computers can interpret.
83) is it possible to create your own header files?

Yes, it is possible to create a customized header file. Just include in it the
function prototypes that you want to use in your program, and use the
#include directive followed by the name of your header file.
84) What is dynamic data structure?

Dynamic data structure provides a means for storing data more efficiently
into memory. Using Using dynamic memory allocation, your program will
access memory spaces as needed. This is in contrast to static data
structure, wherein the programmer has to indicate a fix number of
memory space to be used in the program.
85) What are the different data types in C?

The basic data types in C are int, char, and float. Int is used to declare
variables that will be storing integer values. Float is used to store real
numbers. Char can store individual character values.
86) What is the general form of a C program?

A C program begins with the preprocessor directives, in which the
programmer would specify which header file and what constants (if any) to
be used. This is followed by the main function heading. Within the main
function lies the variable declaration and program statement.
87) What is the advantage of a random access file?
If the amount of data stored in a file is fairly large, the use of random
access will allow you to search through it quicker. If it had been a
sequential access file, you would have to go through one record at a time
until you reach the target data. A random access file lets you jump directly
to the target address where data is located.
88) In a switch statement, what will happen if a break

statement is omitted?
If a break statement was not placed at the end of a particular case portion?
It will move on to the next case portion, possibly causing incorrect output.
89) Describe how arrays can be passed to a user defined

function
One thing to note is that you cannot pass the entire array to a function.
Instead, you pass to it a pointer that will point to the array first element in
memory. To do this, you indicate the name of the array without the
brackets.
90) What are pointers?

Pointers point to specific areas in the memory. Pointers contain the
address of a variable, which in turn may contain a value or even an address
to another memory.
91) Can you pass an entire structure to functions?

Yes, it is possible to pass an entire structure to a function in a call by
method style. However, some programmers prefer declaring the structure
globally, then pass a variable of that structure type to a function. This
method helps maintain consistency and uniformity in terms of argument
type.
92) What is gets() function?

The gets() function allows a full line data entry from the user. When the user
presses the enter key to end the input, the entire line of characters is
stored to a string variable. Note that the enter key is not included in the
variable, but instead a null terminator \0 is placed after the last character.
93) The % symbol has a special use in a printf statement.

How would you place this character as part of the output
on the screen?
You can do this by using %% in the printf statement. For example, you can
write printf(“10%%”) to have the output appear as 10% on the screen.
94) How do you search data in a data file using random

access method?
Use the fseek() function to perform random access input/ouput on a file.
After the file was opened by the fopen() function, the fseek would require
three parameters to work: a file pointer to the file, the number of bytes to
search, and the point of origin in the file.
95) Are comments included during the compilation stage

and placed in the EXE file as well?
No, comments that were encountered by the compiler are disregarded.
Comments are mostly for the guidance of the programmer only and do not
have any other significant use in the program functionality.
96) Is there a built-in function in C that can be used for
sorting data?
Yes, use the qsort() function. It is also possible to create user defined
functions for sorting, such as those based on the balloon sort and bubble
sort algorithm.
97) What are the advantages and disadvantages of a heap?

Storing data on the heap is slower than it would take when using the stack.
However, the main advantage of using the heap is its flexibility. That’s
because memory in this structure can be allocated and remove in any
particular order. Slowness in the heap can be compensated if an algorithm
was well designed and implemented.
98) How do you convert strings to numbers in C?

You can write you own functions to do string to number conversions, or
instead use C’s built in functions. You can use atof to convert to a floating
point value, atoi to convert to an integer value, and atol to convert to a
long integer value.
99) Create a simple code fragment that will swap the

values of two variables num1 and num2.
int temp;
temp = num1;
num1 = num2;
num2 = temp;
100) What is the use of a semicolon (;) at the end of every
program statement?
It has to do with the parsing process and compilation of the code. A
semicolon acts as a delimiter, so that the compiler knows where each
statement ends, and can proceed to divide the statement into smaller
elements for syntax checking.
These interview questions will also help in your viva(orals)
1. Write a C program to print your name, date of birth, and mobile

number.
Expected Output:
Name : Alexandra Abramov
DOB : July 14, 1975
Mobile : 99-9999999999
Write a C program to print your name, date of birth, and mobile

number.
#include <stdio.h>
int main()
{
// Print Name
printf("Name : Alexandra Abramov\n");
// Print Date of Birth

printf("DOB : July 14, 1975\n");
// Print Mobile Number

printf("Mobile : 99-9999999999\n");
// Indicate successful execution

return(0);
}
Explanation:
In the exercise above -

 #include <stdio.h>: This line includes the standard input-output
library, which contains functions for reading and writing data to
and from the console.
 int main(): This is the main function of the program, where

execution begins. It returns an integer value, typically 0, to
indicate successful execution.
 Inside the "main()" function, there are three printf statements.

The "printf()" function is used to print formatted text to the
console. Each printf statement prints a line of text with specific
information:
o printf("Name : Alexandra Abramov\n"); prints "Name :

Alexandra Abramov" followed by a newline character,
which moves the cursor to the next line.
o printf("DOB : July 14, 1975\n"); prints "DOB : July 14, 1975"

followed by a newline character.
o printf("Mobile : 99-9999999999\n"); prints "Mobile : 99-

9999999999" followed by a newline character.
 return(0);: This line indicates the end of the main function and
returns 0.
Sample Output:
Name : Alexandra Abramov
DOB : July 14, 1975
Mobile : 99-9999999999
2. Write a C program to get the C version you are using.

Expected Output:
We are using C18!
Write a C program to get the C version you are using.
#include <stdio.h>
int main(int argc, char** argv) {
// Check for C standard version
#if __STDC_VERSION__ >= 201710L
printf("We are using C18!\n");
#elif __STDC_VERSION__ >= 201112L
#elif __STDC_VERSION__ >= 199901L
#else
printf("We are using C89/C90!\n");
#endif
Explanation:
 #include : This line includes the standard input-output library,

which is necessary for using "printf".
 int main(int argc, char** argv): This is the main function with
command-line arguments argc and argv. However, in this code,
these arguments are not used.
 The code uses preprocessor directives (#if, #elif, #else, and

#endif) to conditionally compile different print statements based
on the version of the C standard detected by the compiler:
o #if __STDC_VERSION__ >= 201710L checks if the C standard

version is greater than or equal to C18 (2017). If true, it
prints "We are using C18!".
o #elif __STDC_VERSION__ >= 201112L checks if the C

standard version is greater than or equal to C11 (2011). If
true, it prints "We are using C11!".
o #elif __STDC_VERSION__ >= 199901L checks if the C

standard version is greater than or equal to C99 (1999). If
true, it prints "We are using C99!".
o #else is a fallback condition that triggers if none of the
above conditions are met. It prints "We are using C89/C90!".
 return 0;: This line indicates the end of the main function and
returns 0 to the operating system, indicating a successful
program execution.
Sample Output:
We are using C18!
3. Write a C program to print a block F using the hash (#), where

the F has a height of six characters and width of five and four
characters. And also print a very large 'C'.
Expected Output:
######
#
#
#####
#
#
#
######
## ##
#
#
#
#
#
## ##
######
Write a C program to print a block F using the hash (#), where the
F has a height of six characters and width of five and four
characters. And also print a very large 'C'.
Block of 'F':
C Code:
#include <stdio.h>
int main()
{
// Print a line of hashes
printf("######\n");
// Print a single hash

printf("#\n");

printf("#\n");
// Print a line of hashes

printf("#####\n");

printf("#\n");
4. Write a C program to print the following characters in reverse.

Test Characters: 'X', 'M', 'L'
Expected Output:
The reverse of XML is LMX
Write a C program to print the following characters in reverse.
Pictorial Presentation:
Test Characters : 'X', 'M', 'L'

C Code:
#include <stdio.h>
int main()
{
// Declare and initialize character variables
char char1 = 'X';
char char2 = 'M';
char char3 = 'L';
// Print the original and reversed characters

printf("The reverse of %c%c%c is %c%c%c\n",
char1, char2, char3,
char3, char2, char1);
return(0);
}Explanation:
#include <stdio.h> - This code includes the standard input/output

library <stdio.h>.
 In the "main()" function, it declares three character variables:

'char1', 'char2', and 'char3', and assigns them the values 'X', 'M',
and 'L' respectively.
 It uses the "printf()" function to display a formatted message.

The message contains placeholders specified by %c, which
represent characters.
 Inside the "printf()" function, it provides the values to substitute

for the placeholders. In this case, it provides 'char1', 'char2', and
'char3' followed by their reverse order: 'char3', 'char2', and
'char1'.
 The program will print: "The reverse of XML is LMX" because it

swaps characters in reverse order.
 Finally, the main function returns 0 to indicate successful

program execution.
Sample Output:
The reverse of XML is LMX
5. Write a C program to compute the perimeter and area of a

rectangle with a height of 7 inches and width of 5 inches.
Expected Output:
Perimeter of the rectangle = 24 inches
Area of the rectangle = 35 square inches
Write a C program to compute the perimeter and area of a

rectangle with a height of 7 inches and width of 5 inches.
C programming: Perimeter of a rectangle
A perimeter is a path that surrounds a two-dimensional shape.

The word comes from the Greek peri (around) and meter
(measure). The perimeter can be used to calculate the length of
fence required to surround a yard or garden. For rectangles or
kites which have only two different side lengths, say x and y, the
perimeter is equal to 2x + 2y
C programming: Area of a rectangle
The area of a two-dimensional figure describes the amount of

surface the shape covers. You measure area in square units of a
fixed size, square units of measure are square inches, square
centimeters, or square miles etc. The formula for the area of a
rectangle uses multiplication: length • width = area. A
rectangle with four sides of equal length is a square.
C Code:
#include <stdio.h>
/*
Variables to store the width and height of a rectangle in inches
*/
int width;
int height;
int area; /* Variable to store the area of the rectangle */

int perimeter; /* Variable to store the perimeter of the
rectangle */
int main() {
/* Assigning values to height and width */
height = 7;
width = 5;
/* Calculating the perimeter of the rectangle */

perimeter = 2*(height + width);
printf("Perimeter of the rectangle = %d inches\n", perimeter);
/* Calculating the area of the rectangle */

area = height * width;
printf("Area of the rectangle = %d square inches\n", area);
return(0);
}
Explanation:
 The program includes the standard input/output library <stdio.h>.
 It declares several integer variables:
o width: Represents the rectangle width in inches.
o height: Represents the height of the rectangle in inches.
o area: Will store the calculated rectangle area.
o perimeter: Will store the calculated rectangle perimeter.
 In the "main()" function:
o It assigns the values 7 to the 'height' variable and 5 to the

'width' variable, representing the rectangle's dimensions.
 The program then calculates the rectangle's perimeter and area:
o Perimeter: It uses the formula 2 * (height + width) to

calculate the perimeter of the rectangle and stores the
result in the 'perimeter' variable.
o Area: It calculates the area using the formula height * width

and stores the result in the 'area' variable.
 Finally, the program uses the "printf()" function to display the

calculated values:
o It prints the calculated perimeter with a message:

"Perimeter of the rectangle = [perimeter] inches."
o It prints the calculated area with a message: "Area of the

rectangle = [area] square inches."
 The program returns 0 to indicate successful execution.
Sample Output:
Perimeter of the rectangle = 24 inches
Area of the rectangle = 35 square inches
6. Write a C program to compute the perimeter and area of a

circle with a given radius.
Expected Output:
Perimeter of the Circle = 37.680000 inches
Area of the Circle = 113.040001 square inches
Write a C program to compute the perimeter and area of a circle

with a given radius.
C programming: Area and circumference of a circle
In geometry, the area enclosed by a circle of radius r is πr2. Here

the Greek letter π represents a constant, approximately equal to
3.14159, which is equal to the ratio of the circumference of any
circle to its diameter.
The circumference of a circle is the linear distance around

its edge.
C Code:
#include <stdio.h>
int main() {
int radius; /* Variable to store the radius of the circle */
float area, perimeter; /* Variables to store the area and
perimeter of the circle */
radius = 6; /* Assigning a value to the radius */
/* Calculating the perimeter of the circle */

perimeter = 2 * 3.14 * radius;
printf("Perimeter of the Circle = %f inches\n", perimeter);
/* Calculating the area of the circle */
area = 3.14 * radius * radius;
printf("Area of the Circle = %f square inches\n", area);
return(0);
}
Explanation:
 It declares several variables:
o int radius: Represents the circle radius.
o float area and float perimeter: Will store the calculated area
and perimeter of the circle.
 In the "main()" function:
o It assigns the value 6 to the 'radius' variable, representing

the circle radius.
 The program then calculates the circle's perimeter and area:
o Perimeter: It uses the formula 2*3.14* radius to calculate

the circle perimeter and stores the result in the 'perimeter'
variable. Here, 3.14 is an approximation of the
mathematical constant π (pi).
o Area: It calculates the area using the formula

3.14*radius*radius (π * r^2) and stores the result in the
'area' variable.
 Finally, the program uses the "printf()" function to display the

calculated values:
o It prints the calculated perimeter with a message:

"Perimeter of the Circle = [perimeter] inches."
o It prints the calculated area with a message: "Area of the

Circle = [area] square inches."
Sample Output:
Perimeter of the Circle = 37.680000 inches
Area of the Circle = 113.040001 square inches
7. Write a C program to display multiple variables.

Sample Variables :
a+ c, x + c,dx + x, ((int) dx) + ax, a + x, s + b, ax + b, s + c, ax + c,
ax + ux
Declaration :
int a = 125, b = 12345;
long ax = 1234567890;
short s = 4043;
float x = 2.13459;
double dx = 1.1415927;
char c = 'W';
unsigned long ux = 2541567890;
C Code:
#include <stdio.h>
int main()
int a = 125, b = 12345; /* Declare and initialize integer

variables */
long ax = 1234567890; /* Declare and initialize long

integer variable */
short s = 4043; /* Declare and initialize short

integer variable */
float x = 2.13459; /* Declare and initialize floating-

point variable */
double dx = 1.1415927; /* Declare and initialize double
precision variable */
char c = 'W'; /* Declare and initialize character

variable */
unsigned long ux = 2541567890; /* Declare and initialize unsigned

long integer variable */
/* Various arithmetic operations and type conversions */
printf("a + c = %d\n", a + c);
printf("x + c = %f\n", x + c);
printf("dx + x = %f\n", dx + x);
printf("((int) dx) + ax = %ld\n", ((int) dx) + ax);
printf("a + x = %f\n", a + x);
printf("s + b = %d\n", s + b);
printf("ax + b = %ld\n", ax + b);
printf("s + c = %hd\n", s + c);
printf("ax + c = %ld\n", ax + c);
printf("ax + ux = %lu\n", ax + ux);
return 0;
Copy
Sample Output:
a + c = 212
x + c = 89.134590
dx + x = 3.276183
((int) dx) + ax = 1234567891
a + x = 127.134590
s + b = 16388
ax + b = 1234580235
s + c = 4130
ax + c = 1234567977
ax + ux = 3776135780
8. Write a C program to convert specified days into years, weeks

and days.
Note: Ignore leap year.
Test Data :
Number of days : 1329
Expected Output :
Years: 3
Weeks: 33
Days: 3
Write a C program to convert specified days into years, weeks

and days.
Note: Ignore leap year.
Test Data :
Number of days : 1329
C Code:
#include <stdio.h>
int main()
int days, years, weeks;
days = 1329; // Total number of days
// Converts days to years, weeks and days
years = days/365; // Calculate years

weeks = (days % 365)/7; // Calculate weeks
days = days - ((years*365) + (weeks*7)); // Calculate remaining

days
// Print the results
printf("Years: %d\n", years);
printf("Weeks: %d\n", weeks);
printf("Days: %d \n", days);
return 0;
Explanation:
 It declares three integer variables:
o int days: This variable stores the total number of days to be

converted.
o int years: It stores the calculated number of years.
o int weeks: It stores the calculated number of weeks.
 The program initializes the 'days' variable with 1329.
 It then converts:
o years = days / 365: This division calculates the number of

years in the given number of days. Since there are
approximately 365 days in a year, this division gives an
estimate of the number of years.
o weeks = (days % 365) / 7: After calculating the years, the
program uses the modulo operator % to find the remaining
days that couldn't be represented in full years. It then
divides this remainder by 7 to calculate the number of
weeks.
o Finally, it subtracts the days accounted for by years and

weeks to get the remaining days.
 The program uses printf statements to display the calculated

values:
o It prints the number of years with the message: "Years:

[years]."
o It prints the number of weeks with the message: "Weeks:

[weeks]."
o It prints the remaining days with the message: "Days:

[days]."
Sample Output:
Years: 3
Weeks: 33
Days: 3
9. Write a C program that accepts two integers from the user

and calculates the sum of the two integers.
Test Data :
Input the first integer: 25
Input the second integer: 38
Expected Output:
Sum of the above two integers = 63
Write a C program that accepts two integers from the user and
calculates the sum of the two integers.
C Code:
#include <stdio.h>
int main()
int x, y, sum; // Declare variables for two integers and their sum
// Prompt user for input and store in 'x'
printf("\nInput the first integer: ");
scanf("%d", &x);
// Prompt user for input and store in 'y'
printf("\nInput the second integer: ");
scanf("%d", &y);
sum = x + y; // Calculate the sum of 'x' and 'y'
// Print the sum
printf("\nSum of the above two integers = %d\n", sum);
return 0; // Indicate successful execution
Copy
Sample Output:
Sum of the above two integers = 63
10. Write a C program that accepts two integers from the user
and calculates the product of the two integers.
Test Data :
Expected Output:
Product of the above two integers = 375
C Code:
#include <stdio.h>
int main()
int x, y, result; // Declare variables for two integers and their

product
// Prompt user for input and store in 'x'
scanf("%d", &x);
// Prompt user for input and store in 'y'
scanf("%d", &y);
result = x * y; // Calculate the product of 'x' and 'y'
// Print the product
printf("Product of the above two integers = %d\n", result);
Copy
Sample Output:

Product of the above two integers = 375
11. Write a C program that accepts two item's weight and
number of purchases (floating point values) and calculates their
average value.
Test Data :
Weight - Item1: 15
No. of item1: 5
Weight - Item2: 25
No. of item2: 4
Expected Output:
Average Value = 19.444444
C Code:
#include <stdio.h>
int main()
double wi1, ci1, wi2, ci2, result; // Declare variables for

weights and counts
// Prompt user for weight and count of item 1
printf("Weight - Item1: ");
scanf("%lf", &wi1);
// Prompt user for count of item 1
printf("No. of item1: ");
scanf("%lf", &ci1);
// Prompt user for weight and count of item 2
printf("Weight - Item2: ");
scanf("%lf", &wi2);
// Prompt user for count of item 2
printf("No. of item2: ");
scanf("%lf", &ci2);
// Calculate average value
result = ((wi1 * ci1) + (wi2 * ci2)) / (ci1 + ci2);
// Print the average value
printf("Average Value = %f\n", result);
return 0;
Sample Output:
Weight - Item1: 15
No. of item1: 5
Weight - Item2: 25
No. of item2: 4
Average Value = 19.444444
12. Write a C program that accepts an employee's ID, total
worked hours in a month and the amount he received per hour.
Print the ID and salary (with two decimal places) of the employee
for a particular month.
Test Data :
Input the Employees ID(Max. 10 chars): 0342
Input the working hrs: 8
Salary amount/hr: 15000
Expected Output:
Employees ID = 0342
Salary = U$ 120000.00
C Code:
#include <stdio.h>
int main() {
char id[10]; // Variable to store employee ID (up to 10

characters)
int hour; // Variable to store working hours
double value, salary; // Variables for hourly salary and total

salary
// Prompt user for employee ID
printf("Input the Employees ID(Max. 10 chars): ");
scanf("%s", &id);
// Prompt user for working hours
printf("\nInput the working hrs: ");
scanf("%d", &hour);
// Prompt user for hourly salary
printf("\nSalary amount/hr: ");
scanf("%lf", &value);
// Calculate total salary
salary = value * hour;
// Print employee ID and salary
printf("\nEmployees ID = %s\nSalary = U$ %.2lf\n", id, salary);
return 0;
Copy
Sample Output:
Input the Employees ID(Max. 10 chars): 0342
Input the working hrs: 8
Salary amount/hr: 15000
Employees ID = 0342
Salary = U$ 120000.00
13. Write a C program that accepts three integers and finds the
maximum of three.
Test Data :
Input the third integer: 15
Expected Output:
Maximum value of three integers: 35
C Code:
#include <stdio.h>
#include <stdlib.h>
int main()
int x, y, z, result, max; // Declare variables
// Prompt user for the first integer and store in 'x'
scanf("%d", &x);
// Prompt user for the second integer and store in 'y'
scanf("%d", &y);
// Prompt user for the third integer and store in 'z'
printf("\nInput the third integer: ");
scanf("%d", &z);
// Calculate the result
result = (x + y + abs(x - y)) / 2;
// Calculate the maximum value
max = (result + z + abs(result - z)) / 2;

// Print the maximum value
printf("\nMaximum value of three integers: %d", max);
printf("\n");
return 0;
Copy
Sample Output:
Maximum value of three integers: 35
14. Write a C program to calculate a bike’s average consumption

from the given total distance (integer value) travelled (in km) and
spent fuel (in litters, float number – 2 decimal points).
Test Data :
Input total distance in km: 350
Input total fuel spent in liters: 5
Expected Output:
Average consumption (km/lt) 70.000
C Code:
#include <stdio.h>
int main()
int x; // Variable to store total distance in km
float y; // Variable to store total fuel spent in liters

// Prompt user for total distance and store in 'x'
printf("Input total distance in km: ");
scanf("%d",&x);
// Prompt user for total fuel spent and store in 'y'
printf("Input total fuel spent in liters: ");
scanf("%f", &y);
// Calculate and print average consumption
printf("Average consumption (km/lt) %.3f ",x/y);
printf("\n");
return 0;
Copy
Sample Output:
Input total distance in km: 350
Input total fuel spent in liters: 5
Average consumption (km/lt) 70.000
15. Write a C program to calculate the distance between two

points.
Test Data :
Input x1: 25
Input y1: 15
Input x2: 35
Input y2: 10
Expected Output:
Distance between the said points: 11.1803
Write a C program to calculate the distance between two points.
Note: x1, y1, x2, y2 are all double values.
Formula:
C Code:
#include <stdio.h>
#include <math.h>
int main() {
float x1, y1, x2, y2, gdistance; // Declare variables for

coordinates and distance
// Prompt user for coordinates (x1, y1) and store them
printf("Input x1: ");
scanf("%f", &x1);
printf("Input y1: ");
scanf("%f", &y1);
// Prompt user for coordinates (x2, y2) and store them
printf("Input x2: ");
scanf("%f", &x2);
printf("Input y2: ");
scanf("%f", &y2);
// Calculate squared distance between points
gdistance = ((x2-x1)*(x2-x1))+((y2-y1)*(y2-y1));
// Calculate and print the distance between the points
printf("Distance between the said points: %.4f", sqrt(gdistance));
printf("\n");
return 0;
Copy
Explanation:
 First, the program includes two standard libraries: <stdio.h> for

input/output functions and <math.h> to use the sqrt() function for
calculating the square root.
 It declares the following variables:
o float x1, y1, x2, y2: These variables will store the
coordinates of two points in the form (x, y) where (x1, y1)
are the coordinates of the first point, and (x2, y2) are the
coordinates of the second point.
o float gdistance: This variable stores the squared distance

between the two points.
 The program prompts the user to input the coordinates of the

first point:
o It uses "printf()" function to display "Input x1:" to instruct

the user to input the x-coordinate of the first point.
o It uses "scanf()" function to read the user's input and store

it in the variable 'x1'.
o It repeats the same process for the y-coordinate of the first
point ('y1') and then for the coordinates of the second point
('x2' and 'y2').
 It calculates the squared distance between the two points using

the distance formula for two points (x1, y1) and (x2, y2):
o gdistance = ((x2 - x1)*(x2 - x1)) + ((y2 - y1)*(y2 - y1)): This

formula computes the square of the distance between the
points.
 The program uses the "printf()" function to display the result:
o It prints "Distance between the said points: " along with the
calculated square root of 'gdistance' using sqrt(gdistance).
o The %.4f format specifier displays the result with four

decimal places.
 Finally, the program returns 0 to indicate successful execution.
Sample Output:
Input x1: 25
Input y1: 15
Input x2: 35
Input y2: 10
Distance between the said points: 11.1803
16. Write a C program to read an amount (integer value) and

break the amount into the smallest possible number of bank
notes.
Test Data :
Input the amount: 375
Expected Output:
There are:
3 Note(s) of 100.00
1 Note(s) of 50.00
1 Note(s) of 20.00
0 Note(s) of 10.00
1 Note(s) of 5.00
0 Note(s) of 2.00
0 Note(s) of 1.00
C Code:
#include <stdio.h>
int main() {
int amt, total; // Declare variables for amount and total
// Prompt user for the amount and store it in 'amt'
printf("Input the amount: ");
scanf("%d",&amt);
// Calculate and print the number of each denomination
total = (int)amt/100;
printf("There are:\n");
printf("%d Note(s) of 100.00\n", total);
amt = amt-(total*100);
total = (int)amt/5;
total = (int)amt/2;
total = (int)amt/1;
return 0;
Copy
Explanation:
 First, the program includes the standard library for input/output

functions.
 It declares the following variables:
o int amt: This variable stores the input amount.

o int total: This variable will be used to calculate the number
of each denomination of currency notes.
 The program prompts the user to input the amount:
o It uses "printf()" function to display "Input the amount: " to

instruct the user to input the amount.
o It uses "scanf()" function to read the user's input and store

it in the variable amt.
 The program calculates the number of each denomination of

currency notes:
o Starting with the largest denomination and moving to the

smallest, it calculates the number of notes needed for each
denomination.
o For each denomination (e.g., 100, 50, 20, etc.), it calculates

the number of notes and updates the 'total' variable
accordingly.
o After calculating the number of notes for each

denomination, it subtracts the total value of those notes
from the remaining amount (amt) to continue with the next
denomination.
 The program uses "printf()" function to display the number of

notes for each denomination:
o It prints the number of notes for each denomination, using

the 'total' variable.
o The format is "X Note(s) of Y.YY" where X is the number of

notes, and Y.YY is the denomination.
 Finally, the program returns 0 to indicate successful execution.
Sample Output:
Input the amount: 375
There are:
3 Note(s) of 100.00
1 Note(s) of 50.00
1 Note(s) of 20.00
0 Note(s) of 10.00
1 Note(s) of 5.00
0 Note(s) of 2.00
0 Note(s) of 1.00
17. Write a C program to convert a given integer (in seconds) to

hours, minutes and seconds.
Test Data :
Input seconds: 25300
Expected Output:
There are:
H:M:S - 7:1:40
C Code:
#include <stdio.h>
int main() {
int sec, h, m, s; // Declare variables for seconds, hours,

minutes, and seconds
// Prompt user for input seconds and store in 'sec'
printf("Input seconds: ");
scanf("%d", &sec);
// Calculate hours, minutes, and remaining seconds
h = (sec/3600);
m = (sec -(3600*h))/60;
s = (sec -(3600*h)-(m*60));
// Print the time in format H:M:S
printf("H:M:S - %d:%d:%d\n",h,m,s);
return 0;
Copy
Sample Output:
Input seconds: 25300
H:M:S - 7:1:40
18. Write a C program to convert a given integer (in days) to

years, months and days, assuming that all months have 30 days
and all years have 365 days.
Test Data :
Input no. of days: 2535
Expected Output:
6 Year(s)
11 Month(s)
15 Day(s)
C Code:
#include <stdio.h>
int main() {
int ndays, y, m, d; // Declare variables for number of days,

years, months, and days
// Prompt user for input number of days and store in 'ndays'
printf("Input no. of days: ");
scanf("%d", &ndays);
// Calculate years, months, and remaining days
y = (int) ndays/365;
ndays = ndays-(365*y);
m = (int)ndays/30;
d = (int)ndays-(m*30);
// Print the result
printf(" %d Year(s) \n %d Month(s) \n %d Day(s)", y, m, d);
return 0;
Copy
Sample Output:
Input no. of days: 2535
6 Year(s)
11 Month(s)
15 Day(s)
19. Write a C program that accepts 4 integers p, q, r, s from the

user where q, r and s are positive and p is even. If q is greater
than r and s is greater than p and if the sum of r and s is greater
than the sum of p and q print "Correct values", otherwise print
"Wrong values".
Test Data :
Input the fourth integer: 46
Expected Output:
Wrong values
Test Data :
Expected Output:
Wrong values
C Code:
#include <stdio.h>
int main() {
int p, q, r, s; // Declare variables for four integers
// Prompt user for the first integer and store in 'p'
scanf("%d", &p);
// Prompt user for the second integer and store in 'q'
scanf("%d", &q);
// Prompt user for the third integer and store in 'r'
printf("\nInput the third integer: ");
scanf("%d", &r);
// Prompt user for the fourth integer and store in 's'
printf("\nInput the fourth integer: ");
scanf("%d", &s);
// Check conditions for correctness
if((q > r) && (s > p) && ((r+s) > (p+q)) && (r > 0) && (s > 0) &&
(p%2 == 0))
{
printf("\nCorrect values\n");
else {
printf("\nWrong values\n");
return 0;
Sample Output:
Wrong values
20. Write a C program to print the roots of Bhaskara’s formula

from the given three floating numbers. Display a message if it is
not possible to find the roots.
Test Data :
Input the first number(a): 25
Input the second number(b): 35
Input the third number(c): 12
Expected Output:
Root1 = -0.60000
Root2 = -0.80000
C Code:
#include <stdio.h>
#include <math.h>
// Include math.h header file for mathematical functions
int main() {
double a, b, c, pr1; // Declare variables for coefficients and

discriminant
// Prompt user for coefficients 'a', 'b', and 'c'
printf("\nInput the first number(a): ");
scanf("%lf", &a);
printf("\nInput the second number(b): ");
scanf("%lf", &b);
printf("\nInput the third number(c): ");
scanf("%lf", &c);
pr1 = (b*b) - (4*(a)*(c)); // Calculate discriminant
if(pr1 > 0 && a != 0) { // Check conditions for real roots
double x, y;
pr1 = sqrt(pr1); // Calculate square root of discriminant
x = (-b + pr1)/(2*a); // Calculate first root
y = (-b - pr1)/(2*a); // Calculate second root
printf("Root1 = %.5lf\n", x); // Print first root
printf("Root2 = %.5lf\n", y); // Print second root
}
else {
printf("\nImpossible to find the roots.\n"); // Print message

for no real roots
return 0;
Copy
Sample Output:
Input the first number(a): 25
Input the second number(b): 35
Input the third number(c): 12

Root1 = -0.60000
Root2 = -0.80000
21. Write a C program that reads an integer and checks the

specified range to which it belongs. Print an error message if the
number is negative and greater than 80.
Test Data :
Input an integer: 15
Expected Output:
Range [0, 20]
C Code:
#include <stdio.h>
int main() {
int x; // Declare variable to store an integer
// Prompt user for an integer and store in 'x'

printf("\nInput an integer: ");
scanf("%d", &x);
if(x >=0 && x <= 20) // Check if 'x' is in the range [0, 20]
printf("Range [0, 20]\n"); // Print message for the first

range
else if(x >=21 && x <= 40) // Check if 'x' is in the range (21,40]
printf("Range (21,40]\n"); // Print message for the second

range
else if(x >=41 && x <= 60) // Check if 'x' is in the range (41,60]
printf("Range (41,60]\n"); // Print message for the third

range
else if(x >61 && x <= 80) // Check if 'x' is in the range (61,80]
printf("Range (61,80]\n"); // Print message for the fourth

range
else
printf("Outside the range\n"); // Print message for values

outside of all ranges
}
return 0;
Copy
Sample Output:
Range [0, 20]
22. Write a C program that reads 5 numbers and sums all odd
values between them.
Test Data :
Input the first number: 11
Input the second number: 17
Input the third number: 13
Input the fourth number: 12
Input the fifth number: 5
Expected Output:
Sum of all odd values: 46
C Code:
#include <stdio.h>
int main() {
int j, numbers[5], total=0; // Declare variables for loop counter,

an array of numbers, and total
// Prompt user for five numbers and store them in the array
printf("\nInput the first number: ");
scanf("%d", &numbers[0]);
printf("\nInput the second number: ");
printf("\nInput the third number: ");
printf("\nInput the fourth number: ");
printf("\nInput the fifth number: ");
// Loop through the numbers to find and sum the odd ones
for(j = 0; j < 5; j++) {
if((numbers[j]%2) != 0)
total += numbers[j];
// Print the sum of odd values
printf("\nSum of all odd values: %d", total);
printf("\n");
return 0;
Copy
Sample Output:
23. Write a C program that reads three floating-point values and

checks if it is possible to make a triangle with them. Determine
the perimeter of the triangle if the given values are valid.
Test Data :
Expected Output:
Perimeter = 75.0
C Code:
#include <stdio.h>
int main() {
float x, y, z, P, A; // Declare variables for side lengths and

perimeter
// Prompt user for the side lengths and store in 'x', 'y', and 'z'
scanf("%f", &x);
scanf("%f", &y);

scanf("%f", &z);
if(x < (y+z) && y < (x+z) && z < (y+x)) // Check if the sides can
form a triangle
P = x+y+z; // Calculate perimeter
printf("\nPerimeter = %.1f\n", P); // Print perimeter
else
printf("Not possible to create a triangle..!"); // Print

message if it's not possible to form a triangle
return 0;
Copy
Sample Output:
Perimeter = 75.0
24. Write a C program that reads two integers and checks

whether they are multiplied or not.
Test Data :
Expected Output:
Multiplied!
C Code:
#include <stdio.h>
int main() {
int x, y; // Declare variables for two integers
// Prompt user for the first number and store in 'x'
scanf("%d", &x);
// Prompt user for the second number and store in 'y'
scanf("%d", &y);
if(x > y)
int temp;
temp = x; // Swap the values of 'x' and 'y'
x = y;
y = temp;
if((y % x)== 0) // Check if 'x' is a factor of 'y'
{
printf("\nMultiplied!\n"); // Print message if 'x' is a factor
of 'y'
else
printf("\nNot Multiplied!\n"); // Print message if 'x' is not

a factor of 'y'
return 0;
Copy
Sample Output:
Multiplied!
25. Write a C program that reads an integer between 1 and 12

and prints the month of the year in English.
Test Data :
Input a number between 1 to 12 to get the month name: 8
Expected Output:
August
C Code:
#include <stdio.h>
int main() {
int mno; // Declare variable for month number

// Prompt user for a number between 1 to 12
printf("\nInput a number between 1 to 12 to get the month name:

");
scanf("%d", &mno);
switch(mno) {
case 1 : printf("January\n"); break; // Print the name of the

month for each case
case 2 : printf("February\n"); break;
case 3 : printf("March\n"); break;
case 4 : printf("April\n"); break;
case 5 : printf("May\n"); break;
case 6 : printf("June\n"); break;
case 7 : printf("July\n"); break;
case 8 : printf("August\n"); break;
case 9 : printf("September\n"); break;
case 10 : printf("October\n"); break;
case 11 : printf("November\n"); break;
case 12 : printf("December\n"); break;
default : printf("Input a number between 1 to 12."); // Print

a message for an invalid input
return 0;
Copy
Sample Output:
Input a number between 1 to 12 to get the month name: 8
August
26. Write a C program that prints all even numbers between 1

and 50 (inclusive).
Test Data :
Even numbers between 1 to 50 (inclusive):
Expected Output:
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46
48 50
C Code:
#include <stdio.h>
int main() {
int i; // Declare variable for loop counter
printf("Even numbers between 1 to 50 (inclusive):\n");
for (i = 1; i <= 50; i++)
if(i%2 == 0) // Check if 'i' is even
printf("%d ", i); // Print 'i' if it's even
return 0;
}
Sample Output:
Even numbers between 1 to 50 (inclusive):
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46
48 50
27. Write a C program that reads 5 numbers and counts the

number of positive numbers and negative numbers.
Test Data :
Input the second number: -4
Input the fifth number: -1
Expected Output:
Number of positive numbers: 3
Number of negative numbers: 2
C Code:
#include <stdio.h>
int main() {
float numbers[5]; // Declare an array to store 5 numbers
int j, pctr=0, nctr=0; // Declare variables for loop counter,

positive count, and negative count
scanf("%f", &numbers[0]);

for(j = 0; j < 5; j++) {
if(numbers[j] > 0) // Check if the number is positive
pctr++; // Increment positive count
else if(numbers[j] < 0) // Check if the number is negative
nctr++; // Increment negative count
// Print the counts of positive and negative numbers
printf("\nNumber of positive numbers: %d", pctr);
printf("\nNumber of negative numbers: %d", nctr);
printf("\n");
return 0;
}
Copy
Sample Output:
Input the second number: -4
Input the fifth number: -1

Number of negative numbers: 2
28. Write a C program that reads 5 numbers, counts the number

of positive numbers, and prints out the average of all positive
values.
Test Data :
Input the fourth number: -5
Expected Output:
Average value of the said positive numbers: 12.00
C Code:
#include <stdio.h>
int main() {
float numbers[5], total=0, avg; // Declare an array to store 5

numbers, and variables for total and average
int j, pctr=0; // Declare variables for loop counter and positive

count
for(j = 0; j < 5; j++) {
if(numbers[j] > 0) // Check if the number is positive
pctr++; // Increment positive count
total += numbers[j]; // Add positive number to total
avg = total/pctr; // Calculate average of positive numbers
// Print the counts of positive numbers and the average
printf("\nNumber of positive numbers: %d", pctr);
printf("\nAverage value of the said positive numbers: %.2f", avg);

printf("\n");
return 0;
Copy
Sample Output:
Input the fourth number: -5

Average value of the said positive numbers: 12.00
29. Write a C program that read 5 numbers and sum of all odd
values between them.
Test Data :
Expected Output:
C Code:
#include <stdio.h>
int main() {
int j, numbers[5], total=0; // Declare array to store 5 numbers
and variable for total
for(j = 0; j < 5; j++) {
if((numbers[j]%2) != 0) // Check if the number is odd
total += numbers[j]; // Add odd number to total
printf("\nSum of all odd values: %d", total); // Print the sum of

odd numbers
return 0;
Copy
Sample Output:
30. Write a C program to find and print the square of all the even
values from 1 to a specified value.
Test Data :
List of square of each one of the even values from 1 to a 4 :
Expected Output:
2^2 = 4
4^2 = 16
C Code:
#include <stdio.h>
int main() {
int x, i; // Declare variables for user input and loop counter
printf("Input an integer: ");
scanf("%d", &x); // Prompt user for an integer
printf("List of square of each one of the even values from 1 to a

%d :\n", x);
for(i = 2; i <= x; i++) { // Loop through numbers from 2 to x
if((i%2) == 0) { // Check if the number is even

printf("%d^2 = %d\n", i, i*i); // Print the square of the
even number
return 0;
Copy
Sample Output:
List of square of each one of the even values from 1 to a 4 :
2^2 = 4
4^2 = 16
31. Write a C program to check whether a given integer is

positive even, negative even, positive odd or negative odd. Print
even if the number is 0.
Test Data :
Expected Output:
Positive Odd
C Code:
#include <stdio.h>
int main() {
int x; // Declare a variable to store user input
// Check different conditions based on the value of x
if(x == 0){
printf("Positive\n");
else if(x < 0 && (x%2) != 0) // Check if x is negative and odd
printf("Negative Odd\n");
else if(x < 0 && (x%2) == 0) // Check if x is negative and even
printf("Negative Even\n");
else if(x > 0 && (x%2) != 0) // Check if x is positive and odd
printf("Positive Odd\n");
else if(x > 0 && (x%2) == 0) // Check if x is positive and even
printf("Positive Even\n");
return 0;
Copy
Sample Output:
Positive Odd
32. Write a C program to print all numbers between 1 and 100
which are divided by a specified number and the remainder will
be 3.
Test Data :
Expected Output:
3
28
53
78
C Code:
#include <stdio.h>
int main() {
int x, i; // Declare variables for user input and loop counter
for(i = 1; i <= 100; i++) // Loop through numbers from 1 to 100
if((i%x) == 3) { // Check if the remainder of i divided by x

is 3
printf("%d\n", i); // Print i if the condition is met
return 0;
}
Copy
Input data: 25
Sample Output:
Input an integer: 3
28
53
78
33. Write a C program that accepts some integers from the user
and finds the highest value and the input position.
Test Data :
Input 5 integers:
5
7
15
23
45
Expected Output:
Highest value: 45
Position: 5
C Code:
#include <stdio.h>
#define MAX 5
int main()
int number[MAX], i, j, max=0, num_pos=0; // Declare an array to

store 5 numbers, and variables for loop counters and maximum value
printf("Input 5 integers: \n");
for(i = 0; i < MAX; i++) {
scanf(" %d", &number[i]); // Read 5 integers from the user

}
for(j = 0; j < MAX; j++)
if(number[j] > max) { // Check if current number is greater

than current maximum
max = number[j]; // Update maximum if needed
num_pos = j; // Record the position of maximum
printf("Highest value: %d\nPosition: %d\n", max, num_pos+1); //

Print the maximum value and its position
return 0;
Copy
Sample Output:
Input 5 integers:
5
7
15
23
45
Highest value: 45
Position: 5
34. Write a C program to compute the sum of consecutive odd

numbers from a given pair of integers.
Test Data :
Input a pair of numbers (for example 10,2):
Input first number of the pair: 10
Input second number of the pair: 2
Expected Output:
List of odd numbers: 3
5
7
9
Sum=24
C Code:
#include <stdio.h>
int main() {
int x, y, i, total = 0; // Declare variables for user input and

calculations
printf("\nInput a pair of numbers (for example 10,2):");
printf("\nInput first number of the pair: ");
scanf("%d", &x); // Read the first number
printf("\nInput second number of the pair: ");
scanf("%d", &y); // Read the second number
if (x < y) {
return 0; // If x is less than y, exit the program
printf("\nList of odd numbers: ");
for (i = y; i <= x; i++) {
if ((i % 2) != 0) {
printf("%d\n", i); // Print odd numbers within the range
total += i; // Add odd numbers to the total
}
}
printf("Sum=%d\n", total); // Print the total sum
return 0;
Copy
Sample Output:
Input a pair of numbers (for example 10,2):
List of odd numbers: 3

5
7
9
Sum=24
35. Write a C program to check if two numbers in a pair are in

ascending order or descending order.
Test Data :
Input a pair of numbers (for example 10,2 : 2,10):
Expected Output:
The pair is in descending order!
C Code:
#include <stdio.h>
int main() {
int x, y, i, total = 0; // Declare variables for user input and

calculations
printf("\nInput a pair of numbers (for example 10,2 : 2,10):");

printf("\nInput first number of the pair: ");
scanf("%d", &x); // Read the first number
printf("\nInput second number of the pair: ");
scanf("%d", &y); // Read the second number
if (x > y) {
printf("The pair is in descending order!"); // If x is greater

than y, print message for descending order
} else {
printf("The pair is in ascending order!"); // Otherwise, print

message for ascending order
printf("\n");
return 0;
Copy
Sample Output:
Input a pair of numbers (for example 10,2 : 2,10):

The pair is in descending order!
36. Write a C program to read a password until it is valid. For

wrong password print "Incorrect password" and for correct
password print, "Correct password" and quit the program. The
correct password is 1234.
Test Data :
Input the password: 1234
Expected Output:
Correct password
C Code:
#include <stdio.h>
int main() {
int pass, x = 10; // Initialize variables for password and loop

control
while (x != 0) {
printf("\nInput the password: ");
scanf("%d", &pass); // Read the password input
if (pass == 1234) {
printf("Correct password"); // If the password is correct,

print a success message
x = 0; // Set x to 0 to exit the loop
} else {
printf("Wrong password, try another"); // If the password

is incorrect, prompt for another attempt
printf("\n");
return 0;
}
Copy
Sample Output:
Input the password: 1234
Correct password
37. Write a C program to read the coordinates (x, y) (in the

Cartesian system) and find the quadrant to which it belongs
(Quadrant -I, Quadrant -II, Quadrant -III, Quadrant -IV).
Note: A Cartesian coordinate system is a coordinate system that
specifies each point uniquely in a plane by a pair of numerical
coordinates.
These are often numbered from 1st to 4th and denoted by Roman
numerals: I (where the signs of the (x,y) coordinates are I(+,+), II
(−,+), III (−,−), and IV (+,−).
Test Data :
Input the Coordinate(x,y):
x: 25
y: 15
Expected Output:
Quadrant-I(+,+)
Note: A Cartesian coordinate system is a coordinate system that

specifies each point uniquely in a plane by a pair of numerical
coordinates.
These are often numbered from 1st to 4th and denoted by Roman
numerals: I (where the signs of the (x,y) coordinates are I(+,+), II
(−,+), III (−,−), and IV (+,−).
Sample Solution:
C Code:
#include <stdio.h>
int main() {
int x, y;
// Prompt for user input
printf("Input the Coordinate(x,y): ");
printf("\nx: ");
scanf("%d", &x);
printf("y: ");
scanf("%d", &y);
// Check which quadrant the point lies in
if(x > 0 && y > 0) {
printf("Quadrant-I(+,+)\n");
else if(x > 0 && y < 0) {
printf("Quadrant-II(+,-)\n");
else if(x < 0 && y < 0) {
printf("Quadrant-III(-,-)\n");
else if(x < 0 && y > 0) {
printf("Quadrant-IV(-,+)\n");
return 0;
Copy
Sample Output:
Input the Coordinate(x,y):
x: 25
y: 15
Quadrant-I(+,+)
38. Write a program that reads two numbers and divides the first
number by the second number. If division is not possible print
"Division is not possible".
Test Data :
Input two numbers:
x: 25
y: 5
Expected Output: 5.0
C Code:
#include <stdio.h>
int main() {
int x, y;
float div_result;
printf("Input two numbers: ");
printf("\nx: ");
scanf("%d", &x);
printf("y: ");
scanf("%d", &y);
// Check if division is possible
if(y != 0) {
div_result = x/y;
printf("%.1f\n", div_result);
} else {
printf("Division not possible.\n");
return 0;
Copy
Sample Output:
Input two numbers:
x: 25
y: 5
5.0
39. Write a C program to calculate the sum of all numbers not

divisible by 17 between two given integer numbers.
Test Data :
Input the first integer: 50 Input the second integer: 99
Expected Output:
Sum: 3521
C Code:
#include <stdio.h>
int main() {
int x, y, temp, i, sum=0;
scanf("%d", &x);

scanf("%d", &y);
// Swap values if x is greater than y
if(x > y) {
temp = y;
y = x;
x = temp;
// Calculate the sum of numbers not divisible by 17
for(i = x; i <= y; i++) {
if((i % 17) != 0) {
sum += i;
// Display the sum
printf("\nSum: %d\n", sum);
return 0;
Copy
Sample Output:

Sum: 3521
40. Write a C program that finds all integer numbers that divide
by 7 and have a remainder of 2 or 3 between two given integers.
Test Data :
Expected Output:
30
31
37
38
44
C Code:
#include <stdio.h>
int main() {
int x, y, temp, i, sum=0;
scanf("%d", &x);
scanf("%d", &y);
// Swap values if x is greater than y
if(x > y) {
temp = y;
y = x;
x = temp;
}
// Iterate through numbers between x and y (exclusive)
for(i = x+1; i < y; i++) {
// Check if the number modulo 7 is 2 or 3
if((i%7) == 2 || (i%7) == 3) {
printf("%d\n", i);
return 0;
Copy
Sample Output:

30
31
37
38
44
41. Write a C program to print 3 numbers on a line, starting with

1 and printing n lines. Accept the number of lines (n, integer)
from the user.
Test Data :
Input number of lines: 5
Expected Output:
123
456
789
10 11 12
13 14 15
C Code:
#include <stdio.h>
int main() {
int a, i, j = 1, x = 0;
printf("Input number of lines: ");
scanf("%d", &a);
// Loop for each line
for(i = 1; i <= a; i++) {
// Loop to print numbers
while(x < 3) {
printf("%d ", j++);
x++;
x = 0; // Reset the counter
printf("\n");
return 0;
}
Copy
Sample Output:
1 2 3
4 5 6
7 8 9
10 11 12
13 14 15
42. Write a C program to print a number, its square and cube,

starting with 1 and printing n lines. Accept the number of lines (n,
integer) from the user.
Test Data :
Expected Output:
111
248
3 9 27
4 16 64
5 25 125
C Code:
#include <stdio.h>
int main() {
int a, i, j = 1, x = 0;
scanf("%d", &a);
// Loop for each line
for(i = 1; i <= a; i++) {

// Print i, i squared, and i cubed
printf("%d %d %d\n", i, i*i, i*i*i);
return 0;
Copy
Sample Output:
1 1 1
2 4 8
3 9 27
4 16 64
5 25 125
43. Write a C program that reads two integers p and q, prints p

number of lines in a sequence of 1 to b in a line.
Test Data :
Number of characters in a line: 6
Expected Output:
123456
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
25 26 27 28 29 30
C Code:
#include <stdio.h>
int main() {
int x, y, i, j, l;
scanf("%d", &x);
printf("Number of numbers in a line: ");
scanf("%d", &y);
// Loop to generate the pattern
for(i = 1, l=1; i <= x; i++) {
for(j = 1; j <= y; j++) {
printf("%d ", l);
l++;
printf("\n");
return 0;
Copy
Sample Output:
Number of numbers in a line: 6
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
25 26 27 28 29 30
44. Write a C program to calculate the average mathematics
marks of some students. Input 0 (excluding to calculate the
average) or a negative value to terminate the input process.
Test Data :
Input Mathematics marks (0 to terminate): 10
15
20
25
0
Expected Output:
Average marks in Mathematics: 17.50
C Code:
#include <stdio.h>
int main() {
int marks[99], m, i, a=0, total=0;
float f;
printf("Input Mathematics marks (0 to terminate): ");
// Loop to get input marks
for(i = 0; ; i++) {
scanf("%d", &marks[i]);
if(marks[i] <= 0) {
break;
a++;
total += marks[i];
}
// Calculate and print average
f = (float)total/(float)a;
printf("Average marks in Mathematics: %.2f\n", f);
return 0;
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Sample Output:
Input Mathematics marks (0 to terminate): 10
15
20
25
0
Average marks in Mathematics: 17.50
45. Write a C program to calculate the value of S where S = 1 +
1/2 + 1/3 + … + 1/50.
Expected Output:
Value of S: 4.50
C Code:
#include <stdio.h>
int main() {
float S = 0;
int i;
// Loop to calculate the sum
for(i=1; i<=50; i++) {
S += (float)1/i;
}
// Print the result
printf("Value of S: %.2f\n", S);
return 0;
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Sample Output:
Value of S: 4.50
46. Write a C program to calculate the value of S where S = 1 +

3/2 + 5/4 + 7/8.
Expected Output:
Value of series: 4.62
C Code:
#include <stdio.h>
int main() {
double s=0, j=1, d, i;
// Loop to calculate the series
for(i=1; i<=7; i+=2){
d = (i/j);
s += d;
j = j*2;
}
// Print the result
printf("Value of series: %.2lf\n", s);
return 0;
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Sample Output:
Value of series: 4.62
47. Write a C program that finds all the divisors of an integer.

Test Data:
Expected Output:
All the divisor of 45 are:
1
3
5
9
15
45
C Code:
#include <stdio.h>
int main() {
int x, i;
// Get an integer input from the user
printf("\nInput an integer: ");
scanf("%d", &x);
// Print all the divisors of x
printf("All the divisors of %d are: ", x);
for(i = 1; i <= x; i++) {
if((x%i) == 0){
printf("\n%d", i);
printf("\n");
return 0;
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Sample Output:
All the divisor of 45 are:
1
15
45
48. Write a C program that reads and prints the elements of an

array of length 7. Before printing, replace every negative number,
zero, with 100.
Test Data:
Input the 5 members of the array:
25
45
35
65
15
Expected Output:
Array values are:
n[0] = 25
n[1] = 45
n[2] = 35
n[3] = 65
n[4] = 15
C Code:
#include <stdio.h>
int main() {
int n[5], i, x;
// Input the 5 members of the array
printf("Input the 5 members of the array:\n");
for(i = 0; i < 5; i++) {
scanf("%d", &x);
if(x > 0) {
n[i] = x;
} else {
n[i] = 100;
// Print the array values

printf("Array values are: \n");
for(i = 0; i < 5; i++) {
printf("n[%d] = %d\n", i, n[i]);
return 0;
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Sample Output:
25
45
35
65
15
Array values are:
n[0] = 25
n[1] = 45
n[2] = 35
n[3] = 65
n[4] = 15
49. Write a C program to read and print the elements of an array

with length 7. Before printing, insert the triple of the previous
position, starting from the second position.
For example, if the first number is 2, the array numbers must be
2, 6, 18, 54 and 162
Test Data:
Input the first number of the array: 5
Expected Output:
n[0] = 5
n[1] = 15
n[2] = 45
n[3] = 135
n[4] = 405
C Code:
#include <stdio.h>
int main() {
int n[5], i, x;
// Input the first number of the array
printf("Input the first number of the array:\n");
scanf("%d", &x);
// Fill the array with values based on the input
for(i = 0; i < 5; i++) {
n[i] = x;
x = 3 * x;
// Print the array values
for(i = 0; i < 5; i++) {
printf("n[%d] = %d\n", i, n[i]);
return 0;
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Sample Output:
Input the first number of the array:
5
n[0] = 5
n[1] = 15
n[2] = 45
n[3] = 135
n[4] = 405
50. Write a C program to read an array of length 5 and print the

position and value of the array elements of value less than 5.
Test Data:
15
25
4
35
40
Expected Output:
A[2] = 4.0
C Code:
#include <stdio.h>
#define AL 5 // Define the size of the array as 5
#define MAX 5 // Define a maximum value for comparison
int main() {
float N[AL]; // Declare an array of size 5 to hold floating-point

numbers
int i;

// Read and store user input into the array
for(i = 0; i < AL; i++) {
scanf("%f", &N[i]);
// Iterate through the array and print elements less than MAX
for(i = 0; i < AL; i++) {
if(N[i] < MAX) {
printf("A[%d] = %.1f\n", i, N[i]);
return 0;
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Sample Output:
15
25
4
35
40
A[2] = 4.0
51. Write a C program to read an array of length 6, change the

first element by the last, the second element by the fifth and the
third element by the fourth. Print the elements of the modified
array.
Test Data:
15
20
25
30
35
Expected Output:
array_n[0] = 35
array_n[1] = 30
array_n[2] = 25
array_n[3] = 20
array_n[4] = 15
C Code:
#include <stdio.h>
#define AL 5
int main() {
// Define the size of the array
int array_n[AL], i, temp;
// Prompt user to input 5 elements of the array
for(i = 0; i < AL; i++) {
scanf("%d", &array_n[i]);
// Swap the first half of the array with the second half
for(i = 0; i < AL; i++) {
if(i < (AL/2)) {

temp = array_n[i];
array_n[i] = array_n[AL-(i+1)];
array_n[AL-(i+1)] = temp;
// Print the modified array
for(i = 0; i < AL; i++) {
printf("array_n[%d] = %d\n", i, array_n[i]);
return 0;
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Sample Output:
15
20
25
30
35
array_n[0] = 35
array_n[1] = 30
array_n[2] = 25
array_n[3] = 20
array_n[4] = 15
52. Write a C program to read an array of length 6 and find the
smallest element and its position.
Test Data:
Input the length of the array: 5 Input the array elements:
25
35
20
14
45
Expected Output:
Smallest Value: 14
Position of the element: 3
C Code:
#include <stdio.h>
int main() {
int e, i, sval, position;
// Prompt user to input the length of the array
printf("\nInput the length of the array: ");
scanf("%d", &e);
// Declare an array of length 'e'
int v[e];
// Prompt user to input the array elements
printf("\nInput the array elements:\n ");
for(i = 0; i < e; i++) {
scanf("%d", &v[i]);
// Initialize 'sval' and 'position' with the first element of the

array
sval = v[0];
position = 0;
// Find the smallest value and its position in the array
for(i = 0; i < e; i++) {
if(sval > v[i]) {
sval = v[i];
position = i;
// Print the smallest value and its position
printf("Smallest Value: %d\n", sval);
printf("Position of the element: %d\n", position);
return 0;
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Sample Output:
Input the length of the array: 5
Input the array elements:

25
35
20
14
45
Smallest Value: 14
Position of the element: 3
53. Write a C program that accepts the principle, rate of interest,
and time and calculates simple interest.
Test Data:
Input Data: p = 10000, r = 10% , t = 12 year
Expected Output:
Input principle, Rate of interest & time to find simple interest:
Simple interest = 12000
C Code:
#include<stdio.h>
int main() {
int p, r, t, int_amt;
// Prompt user to input principle, rate of interest, and time
printf("Input principle, Rate of interest & time to find simple

interest: \n");
scanf("%d%d%d", &p, &r, &t);
// Calculate simple interest
int_amt = (p * r * t) / 100;
// Display the calculated simple interest
printf("Simple interest = %d", int_amt);
return 0;
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Sample Output:
Input Data: p = 10000, r = 10% , t = 12 year
Input principle, Rate of interest & time to find simple interest:
Simple interest = 12000
54. Write a C program that accepts a distance in centimeters

and prints the corresponding value in inches.
Test Data:
Input Data: 500cms
Input the distance in cm:
Distance of 500.00 cms is = 196.85 inches
Note: 1 inch = 2.54 cm.

C Code:
#include <stdio.h>
// Define a constant for converting inches to centimeters
#define INCH_TO_CM 2.54
int main() {
double inch, cm;
// Prompt user to input the distance in centimeters
printf("Input the distance in cm:\n");
scanf("%lf", &cm);
// Convert centimeters to inches
inch = cm / INCH_TO_CM;
// Display the converted distance
printf("Distance of %0.2lf cms is = %0.2lf inches\n", cm, inch);

return 0;
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Sample Output:
Input Data: 500cms
Input the distance in cm:
Distance of 500.00 cms is = 196.85 inches
55. Write a C program that swaps two numbers without using a

third variable.
Input value for x & y:
Before swapping the value of x & y: 5 7
After swapping the value of x & y: 7 5
This problem requires writing a C program to swap the values of

two variables without using a third, temporary variable. The
program should demonstrate the swap operation using arithmetic
or bitwise XOR operations to achieve the swap directly between
the two variables. This approach avoids the need for additional
memory allocation, making the solution more efficient in terms of
space.
What is swapping in C language?
Swapping in the C language refers to the process of exchanging

the values of two variables. This operation involves assigning the
value of one variable to another and vice versa, so that each
variable holds the initial value of the other. Swapping is a
common operation in various algorithms and applications, such
as sorting algorithms, to rearrange data.
Applications of Swapping
Swapping is widely used in various programming scenarios,

including:
 Sorting Algorithms: Algorithms like bubble sort, quick sort, and
others frequently swap elements to arrange data in a particular
order.
 Permutations: Generating permutations of a set of values often

involves swapping elements.
 Data Manipulation: Various data manipulation tasks require

swapping values to achieve desired outcomes.
Sample Solution: Using arithmetic operations
C Code:
#include<stdio.h>
int main()
int x, y;
printf("Input value for x & y: \n");
scanf("%d%d",&x,&y);
printf("Before swapping the value of x & y: %d %d",x,y);
x=x+y;
y=x-y;
x=x-y;
printf("\nAfter swapping the value of x & y: %d %d",x,y);
return 0;
}
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Output:
Explanation:
 Include the Standard Input-Output Library: #include<stdio.h>

ensures that the functions for input and output operations are
available.
 Main Function Definition: int main() begins the execution of the

program.
 Variable Declaration: int x, y; declares two integer variables x

and y.
 User Input Prompt:
o printf("Input value for x & y: \n"); prompts the user to input

values for x and y.
o scanf("%d%d", &x, &y); reads the input values from the user
and stores them in x and y.
 Display Initial Values: printf("Before swapping the value of x & y:

%d %d", x, y); prints the values of x and y before swapping.
 Swap Values Using Arithmetic Operations:
o x = x + y; adds x and y and stores the result in x.
o y = x - y; subtracts the new value of y (which is the original

x + y) by y to get the original value of x and stores it in y.
o x = x - y; subtracts the new value of y (original x) from x to

get the original value of y and stores it in x.
 Display Swapped Values: printf("\nAfter swapping the value of x

& y: %d %d", x, y); prints the values of x and y after swapping.
 Return Statement: return 0; indicates that the program has

executed successfully.
Sample Solution: using bitwise XOR operations
Code:
#include <stdio.h>
int main() {
int x, y;
// Prompt user to input values for x and y
printf("Input value for x & y: \n");
scanf("%d%d", &x, &y);
// Display the values of x and y before swapping
printf("Before swapping the value of x & y: %d %d\n", x, y);
// Swap the values of x and y using bitwise XOR operations
x = x ^ y; // Step 1: x now holds the result of x XOR y
y = x ^ y; // Step 2: y now holds the original value of x
x = x ^ y; // Step 3: x now holds the original value of y
// Display the values of x and y after swapping
printf("After swapping the value of x & y: %d %d\n", x, y);
return 0;
}
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Output:
2 3
Explanation:
 Include the Standard Input-Output Library: #include <stdio.h>

ensures that the functions for input and output operations are
available.
 Main Function Definition: int main() begins the execution of the

program.
 Variable Declaration: int x, y; declares two integer variables x

and y.
 User Input Prompt:
o printf("Input value for x & y: \n"); prompts the user to input

values for x and y.
o scanf("%d%d", &x, &y); reads the input values from the user
and stores them in x and y.
 Display Initial Values: printf("Before swapping the value of x & y:

%d %d\n", x, y); prints the values of x and y before swapping.
 Swap Values Using Bitwise XOR Operations:
o x = x ^ y; stores the result of x XOR y in x.
o y = x ^ y; stores the original value of x in y by performing x

XOR y (since x now holds x XOR y, this operation effectively
isolates the original x).
o x = x ^ y; stores the original value of y in x by performing x

XOR y (since y now holds the original x).
 Display Swapped Values: printf("After swapping the value of x &

y: %d %d\n", x, y); prints the values of x and y after swapping.
 Return Statement: return 0; indicates that the program has
executed successfully.
56. Write a C program to shift given data by two bits to the left.
Input value : 2
Read the integer from keyboard-
Integer value = 2
The left shifted data is = 16
C Code:
#include<stdio.h>
int main() {
int a, b;
// Prompt user to input an integer
printf("Read the integer from keyboard-");
scanf("%d",&a);
// Display the original integer value
printf("\nInteger value = %d ",a);
// Left shift 'a' by 2 bits and assign it to 'b'
a <<= 2;
b = a;
// Display the left shifted data
printf("\nThe left shifted data is = %d ",b);

return 0;
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Sample Output:
Read the integer from keyboard-
Integer value = 2
The left shifted data is = 8
57. Write a C program to reverse and print a given number.

Input a number:
The original number = 234
The reverse of the said number = 432
C Code:
#include<stdio.h>
int main() {
int num, x, r_num = 0;
// Prompt user to input a number
printf("Input a number: ");
scanf("%d", &num);
// Display the original number
printf("\nThe original number = %d", num);
// Reverse the digits of the number
while (num >= 1) {
x = num % 10;
r_num = r_num * 10 + x;
num = num / 10;
// Display the reverse of the number
printf("\nThe reverse of the said number = %d", r_num);
return 0;
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Sample Output:
Input a number:
The original number = 234
The reverse of the said number = 432
58. Write a C program that accepts 4 real numbers from the

keyboard and prints out the difference between the maximum
and minimum values of these four numbers.
Input four numbers: 1.54 1.236 1.3625 1.002
Difference is 0.5380
Note: Use 4-decimal places.

Test data and expected output:
Input: 1.54 1.236 1.3625 1.002
Output: Difference is 0.5380
C Code:
#include <stdio.h>
int main() {
// Declare variables to store four numbers

double a1, a2, a3, a4;
double max, min;
// Prompt user to input four numbers
printf("Input four numbers: \n");
scanf("%lf%lf%lf%lf", &a1, &a2, &a3, &a4);
// Find the maximum among the four numbers
if (a1 >= a2 && a1 >= a3 && a1 >= a4)
max = a1;
else if (a2 >= a1 && a2 >= a3 && a2 >= a4)
max = a2;
else if (a3 >= a1 && a3 >= a2 && a3 >= a4)
max = a3;
else
max = a4;
// Find the minimum among the four numbers
if (a1 <= a2 && a1 <= a3 && a1 <= a4)
min = a1;
else if (a2 <= a1 && a2 <= a3 && a2 <= a4)
min = a2;
else if (a3 <= a1 && a3 <= a2 && a3 <= a4)
min = a3;
else
min = a4;
// Calculate and display the difference between max and min
printf("Difference is %0.4lf\n", max - min);
return 0;
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Sample Output:
Input four numbers: 1.54 1.236 1.3625 1.002
Difference is 0.5380
59. Write a C program to display the sum of series 1 + 1/2 + 1/3 +

………. + 1/n.
Input any number: 1 + 1/0
Sum = 1/0
C Code:
#include<stdio.h>
int main() {
int num, i, sum = 0;
// Prompt the user to input a number
printf("Input any number: ");
scanf("%d", &num);
// Display the initial part of the series
printf("1 + ");
// Print the series
for(i = 2; i <= num - 1; i++)
printf(" 1/%d +", i);
// Calculate the sum of the series
for(i = 1; i <= num; i++)
sum = sum + i;
// Display the last term of the series
printf(" 1/%d", num);
// Calculate and display the sum
printf("\nSum = 1/%d", sum + 1/num);
return 0;
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Sample Output:
Input any number: 1 + 1/0
Sum = 1/0
60. Write a C program to create enumerated data types for 7

days and display their values in integer constants.
Sun = 0
Mon = 1
Tue = 2
Wed = 3
Thu = 4
Fri = 5
Sat = 6
C Code:
#include <stdio.h>
int main() {
// Define an enumeration type 'week'
enum week {Sun, Mon, Tue, Wed, Thu, Fri, Sat};
// Print the values of the days using the enumeration constants
printf("Sun = %d", Sun);
printf("\nMon = %d", Mon);
printf("\nTue = %d", Tue);
printf("\nWed = %d", Wed);
printf("\nThu = %d", Thu);
printf("\nFri = %d", Fri);
printf("\nSat = %d", Sat);
return 0;
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Sample Output:
Sun = 0
Mon = 1
Tue = 2
Wed = 3
Thu = 4
Fri = 5
Sat = 6
61. Write a C program that accepts a real number x and prints

out the corresponding value of sin(1/x) using 4-decimal places.
Input value of x: .6235
Value of sin(1/x) is 0.9995
Note: Use 4-decimal places.

Input value of x:
C Code:
#include <stdio.h>
#include <math.h>
int main() {
double x, tval;
// Prompt user for input
printf("Input value of x: \n");
// Read the input value
scanf("%lf", &x);
if (x != 0.0) {
// Calculate sin(1/x) if x is not zero
tval = sin(1/x);
printf("Value of sin(1/x) is %0.4lf\n", tval);
} else {
// Display error message if x is zero
printf("Value of x should not be zero.");
return 0;
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Sample Output:
Input value of x:
62. Write a C program that accepts a positive integer less than

500 and prints out the sum of the digits of this number.
Input a positive number less than 500:
Sum of the digits of 347 is 14

C Code:
#include <stdio.h>
int main() {
int a, x = 0, y;
printf("Input a positive number less than 500: \n");

scanf("%d", &a);
y = a;
if (y < 1 || y > 999) {
// Display error message if the number is out of range
printf("The given number is out of range\n");
} else {
// Calculate the sum of the digits
x += y % 10;
y /= 10;
x += y % 10;
y /= 10;
x += y % 10;
// Display the result
printf("Sum of the digits of %d is %d\n", a, x);
return 0;
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Sample Output:
63. Write a C program that accepts a positive integer n less than
100 from the user. It prints out the sum of 14 + 24 + 44 + 74 +
114 + • • • + m4. In this case, m is less than or equal to n. Print an
appropriate message.
Input a positive number less than 100: 68
Sum of the series is 37361622
It prints out the sum of 14 + 24 + 44 + 74 + 114 + • • • + m4. In

this case, m is less than or equal to n. Print an appropriate
message.
Sample Solution:
C Code:
#include <stdio.h>
int main() {
int i, j, n, sum_int = 0;
printf("Input a positive number less than 100: \n");
scanf("%d", &n);
// Check if the input is valid
if (n < 1 || n >= 100) {
printf("Wrong input\n");
return 0;
j = 1;
for (i = 1; j <= n; i++) {
sum_int += j * j * j * j;
j += i;
// Display the result
printf("Sum of the series is %d\n", sum_int);
return 0;
Sample Output:
Input a positive number less than 100: 68
64. Write a C program that accepts integers from the user until a
zero or a negative number, displays the number of positive values,
the minimum value, the maximum value, and the average value.
Input a positive integer:
Input next positive integer: 15
Number of positive values entered is 4
Maximum value entered is 43
Minimum value entered is 15
Average value is 30.0000

5 2 5 8 9 12 0
C Code:
#include <stdio.h>
int main() {
int a, ctr = 0, min_num, max_num, s = 0;
double avg;
printf("Input a positive integer:\n");
// Read the first input value
scanf("%d", &a);
// Check if the input is positive
if (a <= 0) {
printf("No positive number entered\n");
return 0;
// Initialize min_num and max_num with the first input value
min_num = a;
max_num = a;
// Loop to process subsequent inputs
while (a > 0) {
s += a;
ctr++;
max_num = a > max_num ? a : max_num;
min_num = a < min_num ? a : min_num;
// Prompt for the next positive integer
printf("Input next positive integer:\n");
scanf("%d", &a);
avg = s / (double) ctr;
// Display the results
printf("Number of positive values entered is %d\n", ctr);
printf("Maximum value entered is %d\n", max_num);
printf("Minimum value entered is %d\n", min_num);
printf("Average value is %0.4lf\n", avg);
return 0;
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Sample Output:
Number of positive values entered is 4
Maximum value entered is 43
Minimum value entered is 15
Average value is 30.0000
65. Write a C program that prints out the prime numbers

between 1 and 200. The output should be such that each row
contains a maximum of 20 prime numbers.
Expected output:
The prime numbers between 1 and 199 are:
2 3 5 7 11 13 17 19 23 29
31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113
127 131 137 139 149 151 157 163 167 173
179 181 191 193 197
C Code:
#include <stdio.h>
int main() {
int i, j, flag, ip = 0;
// Print a message indicating the purpose of the program
printf("The prime numbers between 1 and 199 are:\n");
// Loop to check prime numbers from 2 to 198
for (i = 2; i < 199; i++) {
flag = 1;
// Loop to check if i is divisible by any number other than 1
and itself
for (j = 2; j <= i / 2 && flag == 1; j++) {
if (i % j == 0) {
flag = 0;
// If i is prime, print it
if (flag == 1) {
printf("%5d ", i);
ip++;
// Print a newline character after every 10 prime numbers
if (ip % 10 == 0) {
printf("\n");
printf("\n");
return 0;
Sample Output:
The prime numbers between 1 and 199 are:
2 3 5 7 11 13 17 19 23 29
31 37 41 43 47 53 59 61 67 71
73 79 83 89 97 101 103 107 109 113
127 131 137 139 149 151 157 163 167 173
179 181 191 193 197
66. Write a C program that generates 50 random numbers

between -0.5 and 0.5 and writes them to the file rand.dat. The
first line of ran.dat contains the number of random numbers,
while the next 50 lines contain 50 random numbers.
50
-0.4215
0.2620
0.3065
-0.0485
.... 0.3980
0.1750
0.4780
-0.2915
0.0715
0.3565
C Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 50
int main() {
int i;
char str;
FILE * fptr;
// Open a file for writing
fptr = fopen("rand.dat", "w");
if (fptr == NULL) {
printf("Error in creating output.dat\n");
return 0;
// Seed the random number generator
srand(time(NULL));
// Write the number of values to the file
fprintf(fptr, "%d\n", N);
// Generate and write random numbers to the file
for (i = 1; i <= N; i++) {
fprintf(fptr, "%0.4lf\n", (rand() % 2001 - 1000) / 2.e3);
// Close the file
fclose(fptr);
// Open the file for reading
fptr = fopen ("rand.dat", "r");
str = fgetc(fptr);
// Print the contents of the file
while (str != EOF)
printf ("%c", str);
str = fgetc(fptr);
// Close the file
fclose(fptr);
return 0;
Copy
Sample Output:
50
-0.4215
0.2620
0.3065
-0.0485
-0.2085
-0.2490
-0.2780
0.2905
-0.3120
0.1275
0.4010
0.3060
0.4680
-0.1135
0.0130
-0.0145
-0.1890
-0.3825
0.3790
-0.2370
0.0840
-0.1985
0.2065
0.4445
0.0785
-0.2370
-0.0705
0.3870
-0.4695
0.1525
0.2755
0.3880
-0.3075
-0.1400
-0.3825
-0.0155
-0.1105
-0.1605
-0.4470
0.0780
0.4675
0.2330
-0.3380
0.2135
0.3980
0.1750
0.4780
-0.2915
0.0715
0.3565
67. Write a C program to evaluate the equation y=xn when n is a

non-negative integer.
Input the values of x and n: 256
x=256.000000; n=0;
x to power n=1.000000
C Code:
#include <stdio.h>
int main(){
int count, n;
float x,y;
// Input the values of x and n
printf("Input the values of x and n:\n");
scanf("%f%d", &x,&n);
y=1.0;
count=1;
// Calculate x to the power n
while(count<=n)
y=y*x;
count++;
// Print the result
printf("x=%f; n=%d; \nx to power n=%f", x, n,y);
return 0;
Copy
Sample Output:
Input the values of x and n: 256
x=256.000000; n=0;
x to power n=1.000000
68. Write a C program that prints the powers of 2 table for the
powers 0 to 10, both positive and negative.
=======================================
n 2 to power n 2 to power -n
=======================================
0 1 1.000000000000
1 2 0.500000000000
2 4 0.250000000000
3 8 0.125000000000
4 16 0.062500000000
5 32 0.031250000000
6 64 0.015625000000
7 128 0.007812500000
8 256 0.003906250000
9 512 0.001953125000
10 1024 0.000976562500
C Code:
#include<stdio.h>
int main() {
long int p;
int n;
double q;
// Print table header
printf("\n=======================================");
printf("\n n 2 to power n 2 to power -n");
printf("\n=======================================");
p = 1;
// Generate table
for (n = 0; n < 11; ++n) {
if (n == 0)
p = 1;
else
p = p * 2;
q = 1.0 / (double) p;
printf("\n%2d %8d %20.12lf", n, p, q);
// Print table footer
printf("\n======================================");
return 0;
Copy
Sample Output:
=======================================
n 2 to power n 2 to power -n
=======================================
0 1 1.000000000000
1 2 0.500000000000
2 4 0.250000000000
3 8 0.125000000000
4 16 0.062500000000
5 32 0.031250000000
6 64 0.015625000000
7 128 0.007812500000
8 256 0.003906250000
9 512 0.001953125000
10 1024 0.000976562500
======================================
69. Write a C program to print a binomial coefficient table.
Mx 0 1 2 3 4 5 6 7 8 9 10
----------------------------------------------------------
01
111
2121
31331
414641
5 1 5 10 10 5 1
6 1 6 15 20 15 6 1
7 1 7 21 35 35 21 7 1
8 1 8 28 56 70 56 28 8 1
9 1 9 36 84 126 126 84 36 9 1
10 1 10 45 120 210 252 210 120 45 10 1
----------------------------------------------------------
C Code:
#include<stdio.h>
#define MAX 10
int main() {
int n, a, bi_nom;
// Print header
printf("Mx ");
for (n = 0; n <= 10; ++n)
printf("%d ", n);
printf("\
n----------------------------------------------------------\n");
n = 0;
do {
a = 0, bi_nom = 1;
printf("%2d", n);
while (a <= n) {
if (n == 0 || a == 0)
printf("%4d", bi_nom);
else {
bi_nom = bi_nom * (n - a + 1) / a;
printf("%4d", bi_nom);
a = a + 1;
printf("\n");
n = n + 1;
} while (n <= MAX);
// Print footer
printf("----------------------------------------------------------");
return 0;
}
Copy
Sample Output:
Mx 0 1 2 3 4 5 6 7 8 9 10
----------------------------------------------------------
0 1
1 1 1
2 1 2 1
3 1 3 3 1
4 1 4 6 4 1
5 1 5 10 10 5 1
6 1 6 15 20 15 6 1
7 1 7 21 35 35 21 7 1
8 1 8 28 56 70 56 28 8 1
9 1 9 36 84 126 126 84 36 9 1
10 1 10 45 120 210 252 210 120 45 10 1
----------------------------------------------------------
70. Write a C program to print the alphabet set in decimal and

character form.
[65-A] [66-B] [67-C] [68-D] [69-E] [70-F] [71-G] [72-H] [73-I] [74-J]
[75-K] [76-L] [77-M] [78-N] [79-O] [80-P] [81-Q] [82-R] [83-S] [84-T]
[85-U] [86-V] [87-W] [88-X] [89-Y]
[90-Z] [97-a] [98-b] [99-c] [100-d] [101-e] [102-f] [103-g] [104-h]
[105-i] [106-j] [107-k] [108-l] [109-m] [110-n] [111-o] [112-p] [113-q]
[114-r] [115-s] [116-t] [117-u] [118-v]
[119-w] [120-x] [121-y] [122-z]
C Code:
#include <stdio.h>
#define N 10
int main() {
char chr;
printf("\n");
// Loop through ASCII values from 65 ('A') to 122 ('z')
for (chr = 65; chr <= 122; chr = chr + 1) {
// Exclude characters between 'Z' and 'a'
if (chr > 90 && chr < 97)
continue;
printf("[%2d-%c] ", chr, chr);
return 0;
Copy
Sample Output:
[65-A] [66-B] [67-C] [68-D] [69-E] [70-F] [71-G] [72-H] [73-I]
[74-J] [75-K] [76-L] [77-M] [78-N] [79-O] [80-P] [81-Q] [82-R]
[83-S] [84-T] [85-U] [86-V] [87-W] [88-X] [89-Y] [90-Z] [97-a]
[98-b] [99-c] [100-d] [101-e] [102-f] [103-g] [104-h] [105-i]
[106-j] [107-k] [108-l] [109-m] [110-n] [111-o] [112-p] [113-q]
[114-r] [115-s] [116-t] [117-u] [118-v] [119-w] [120-x] [121-y]
[122-z]
71. Write a C program to copy a given string into another and

count the number of characters copied.
Input a string
Original string: w3resource
Number of characters = 10
C Code:
#include<stdio.h>
#define N 10
int main() {
char str1[80], str2[80];
int i;
printf("Input a string: ");
scanf("%s", str2);
// Copy characters from str2 to str1
for(i=0; str2[i]!='\0'; i++)
str1[i]=str2[i];
str1[i]='\0';
// Output results
printf("\n");
printf("Original string: %s", str1);
printf("\nNumber of characters = %d\n", i);
return 0;
Copy
Sample Output:
Input a string
Original string: w3resource
Number of characters = 10
72. Write a C program to remove any negative sign in front of a
number.
Input a value (negative):
Original value = -253
Absolute value = 253
C Code:
#include<stdio.h>
#define N 10
// Function prototype declaration
int abs_val(int);
int main() {
int x, result;
printf("Input a value (negative): \n");
scanf("%d", &x);
printf("Original value = %d", x);
// Call the abs_val function and store the result
result = abs_val(x);
// Output the result
printf("\nAbsolute value = %d", result);

return 0;
// Function to calculate the absolute value
int abs_val(int y) {
if(y < 0)
return(y * -1);
else
return(y);
Copy
Sample Output:
Input a value (negative):
Original value = -253
Absolute value = 253
73. Write a C program that reads two integers and checks

whether the first integer is a multiple of the second integer.
Sample Input: 9 3
Sample Output:
Input the first integer : Input the second integer:
9 is a multiple of 3.
C Code:
#include<stdio.h>
// Function to check if n1 is a multiple of n2
int is_Multiple(int n1, int n2)
return n1 % n2 == 0;
}
int main()
int n1, n2;
printf("Input the first integer : ");
scanf("%d", &n1);
printf("Input the second integer: ");
scanf("%d", &n2);
// Check if n1 is a multiple of n2 and print result
if(is_Multiple(n1, n2))
printf("\n%d is a multiple of %d.\n", n1, n2);
else
printf("\n%d is not a multiple of %d.\n", n1, n2);
return 0;
Copy
Sample Output:
Input the first integer : Input the second integer:
9 is a multiple of 3.
74. Write a C program to display the integer equivalents of
letters (a-z, A-Z).
Sample Output:
List of integer equivalents of letters (a-z, A-Z).
==================================================
97 98 99 100 101 102
103 104 105 106 107 108
109 110 111 112 113 114
115 116 117 118 119 120
121 122 32 65 66 67
68 69 70 71 72 73
74 75 76 77 78 79
80 81 82 83 84 85
86 87 88 89 90
C Code:
#include<stdio.h>
int main()
// Define a string containing lowercase and uppercase letters
char* letters = "abcdefghijklmnopqrstuvwxyz

ABCDEFGHIJKLMNOPQRSTUVWXYZ";
int n;
// Print header
printf("List of integer equivalents of letters (a-z, A-Z).\n");
printf("==================================================\n");
// Loop through each character and print its integer equivalent
for(n=0; n<53; n++) {

printf("%d\t", letters[n]);
// Add a newline every 6 characters for better formatting
if((n+1) % 6 == 0)
printf("\n");
return 0;
Copy
Sample Output:
List of integer equivalents of letters (a-z, A-Z).
==================================================
97 98 99 100 101 102
103 104 105 106 107 108
109 110 111 112 113 114
115 116 117 118 119 120
121 122 32 65 66 67
68 69 70 71 72 73
74 75 76 77 78 79
80 81 82 83 84 85
86 87 88 89 90
75. Write a C program that accepts a seven-digit number,

separates the number into its individual digits, and prints the
digits separated from one another by two spaces each.
Sample Input: 2345678
Input a seven digit number:
Output: 2 3 4 5 6 7 8
C Code:
#include<stdio.h>
int main()
int n;
// Prompt for input
printf( "Input a seven digit number: " );
// Read the input
scanf("%d", &n);
// Output header
printf( "\nOutput: " );
// Extract and print each digit
printf("%d ", (n/1000000));
n = n - ((n/1000000)*1000000);
printf("%d ", (n/100000));
n = n - ((n/100000)*100000);
printf("%d ", (n/10000));
n = n - ((n/10000)*10000);
printf("%d ", (n/1000));
n = n - ((n/1000)*1000);
printf("%d ", (n/100));
n = n - ((n/100)*100);
printf("%d ", (n/10));
n = n - ((n/10)*10);
printf("%d\n", (n%10));
return 0;
Copy
Sample Output:
Input a seven digit number:
Output: 2 3 4 5 6 7 8
76. Write a C program to calculate and print the squares and

cubes of the numbers from 0 to 20. It uses tabs to display them in
a table of values.
Sample Output:
Number Square Cube
=========================
000
111
248
3 9 27
.....
18 324 5832
19 361 6859
20 400 8000
C Code:
#include<stdio.h>
int main()
int x;
/* Print column names */
printf("Number\tSquare\tCube\n");
printf("=========================\n");
// Loop to calculate and print squares and cubes
for(x=0; x<=20; x++)
printf("%d\t%d\t%d\n", x, x*x, x*x*x);
return 0;
Copy
Sample Output:
Number Square Cube
=========================
0 0 0
1 1 1
2 4 8
3 9 27
4 16 64
5 25 125
6 36 216
7 49 343
8 64 512
9 81 729
10 100 1000
11 121 1331
12 144 1728
13 169 2197
14 196 2744
15 225 3375
16 256 4096
17 289 4913
18 324 5832
19 361 6859
20 400 8000
77. Write a C program that accepts principal amount, rate of

interest and days for a loan and calculates the simple interest for
the loan, using the following formula.
interest = principal * rate * days / 365.
Sample Input:
10000
.1
365
0
Sample Output:
Input loan amount (0 to quit): Input interest rate: Input term of
the loan in days: The interest amount is $1000.00
Input loan principal_amt (0 to quit):
Sample Input: 10000

.1
365
0
Sample Solution:
C Code:
#include<stdio.h>
int main()
{
// Declare variables
float principal_amt, rate_of_interest, days, interest;
const int yearInDays = 365; // Constant for converting interest

rate
// Prompt user for loan amount
printf( "Input loan amount (0 to quit): " );
scanf( "%f", &principal_amt );
// Main loop for processing loans
while( (int)principal_amt != 0)
// Prompt user for interest rate
printf( "Input interest rate: " );
scanf( "%f", &rate_of_interest );
// Prompt user for loan term in days
printf( "Input term of the loan in days: " );
scanf( "%f", &days );
// Calculate interest
interest = (principal_amt * rate_of_interest * days )/

yearInDays;
// Display interest amount
printf( "The interest amount is $%.2f\n", interest );

// Prompt user for next loan principal_amt
printf( "\n\nInput loan principal_amt (0 to quit): " );
scanf( "%f", &principal_amt );
return 0;
Copy
Sample Output:
Input loan amount (0 to quit): Input interest rate: Input term of
the loan in days: The interest amount is $1000.00
Input loan principal_amt (0 to quit):
78. Write a C program to demonstrate the difference between

predecrementing and postdecrementing using the decrement
operator --.
Sample Output:
Predecrementing:
x = 10
x-- = 10
x=9
C Code:
#include<stdio.h>
int main()
int x = 10; // Initialize variable x with value 10

// Predecrementing
printf("Predecrementing:\n");
printf("x = %d\n", x); // Print current value of x
printf("x-- = %d\n", x--); // Print x and then decrement it
printf("x = %d\n\n", x); // Print updated value of x
x = 10; // Reset x to 10
// Postdecrementing
printf("Postdecrementing:\n");
printf(" x = %d\n", x); // Print current value of x
printf("--x = %d\n", --x); // Decrement x and then print it
printf(" x = %d\n", x); // Print updated value of x
return 0;
Copy
Sample Output:
Predecrementing:
x = 10
x-- = 10
x = 9
79. Write a C program using looping to produce the following

table of values.
Sample Output:
x x+2 x+4 x+6
--------------------------------
1 3 5 7
4 6 8 10
7 9 11 13
10 12 14 16
13 15 17 19
C Code:
#include<stdio.h>
int main()
int x; // Declare variable x
// Print header for table
printf("x\tx+2\tx+4\tx+6\n\n");
printf("---------------------------\n");
// Loop to generate and print table values
for(x=1; x<=15; x+=3)
printf("%d\t%d\t%d\t%d\n", x, (x+2), (x+4), (x+6));
return 0; // Indicate successful program execution
Copy
Sample Output:
x x+2 x+4 x+6
---------------------------
1 3 5 7
4 6 8 10
7 9 11 13
10 12 14 16
13 15 17 19
80. Write a C program that reads the side (side sizes between 1
and 10 ) of a square and prints square using hash (#) character.
Sample Input: 10
Sample Output:
Input the size of the square:
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
Sample Input: 10
Sample Solution:
C Code:
#include<stdio.h>
int main()
int size, i, j; // Declare variables for size and loop counters
// Prompt user for the size of the square
printf( "Input the size of the square: \n" );
scanf( "%d", &size );
// Check if the size is within the valid range

if(size < 1 || size > 10) {
printf("Size should be in the range 1 to 10\n"); // Print

error message
return 0; // Exit the program
// Loop for rows
for(i=0; i<size; i++) {
// Loop for columns
for(j=0; j<size; j++) {
printf(" #"); // Print a space and a #
printf("\n"); // Move to the next line after completing a row
return 0; // Indicate successful program execution
Copy
Sample Output:
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
# # # # # # # # # #
81. Write a C program that reads the side (side sizes between 1
and 10 ) of a square and prints a hollow square using the hash (#)
character.
Sample Input: 10
Sample Output:
##########
# #
# #
# #
# #
# #
# #
# #
# #
##########
Sample Input: 10
Sample Solution:
C Code:
#include <stdio.h>
int main()
int size, i, j;
printf("Input the size of the square: ");

// Read the size from user
scanf("%d", &size);
// Check if size is within valid range
if (size < 1 || size > 10) {
printf("Size should be in the range 1 to 10\n");
return 0; // Exit program if size is invalid
// Loop for rows
for (i = 0; i< size; i++)
// Loop for columns
for (j = 0; j < size; j++)
// Check if it's a border or inside space
if (i == 0 || i == size - 1)
printf("#"); // Print border
else if (j == 0 || j == size - 1)
printf("#"); // Print border
else
printf(" "); // Print space for inside
printf("\n"); // Move to the next line after each row is printed
}
return 0; // Indicate successful execution of the program
Copy
Sample Output:
##########
# #
# #
# #
# #
# #
# #
# #
# #
##########
82. Write a C program that reads a five-digit integer and

determines whether or not it's a palindrome.
Sample Input: 33333
Sample Output:
Input a five-digit number: 33333 is a palindrome.
Sample Input: 33333
Sample Solution:
C Code:
#include <stdio.h>
// Function to check if a number is a palindrome
int is_Palindrome(int);
int main()
{
int n;
printf("Input a five-digit number: ");
// Read the number from user
scanf("%d", &n);
// Check if the number is a palindrome using the function

is_Palindrome
if (is_Palindrome(n))
printf("%d is a palindrome.", n);
else
printf("%d is not a palindrome.", n);
return 0;
// Function to check if a number is a palindrome
int is_Palindrome(int n) {
int x = n;
int reverse_num = 0;
// Extract the digits in reverse order and reconstruct the number
reverse_num += x / 10000;
x = x - ((x / 10000) * 10000);
reverse_num += ((x / 1000) * 10);
x = x - ((x / 1000) * 1000);
reverse_num += ((x / 100) * 100);
x = x - ((x / 100) * 100);
reverse_num += ((x / 10) * 1000);
x = x - ((x / 10) * 10);
reverse_num += ((x % 10) * 10000);
// Check if the original number is equal to the reversed number
return n == reverse_num;
Copy
Sample Output:
Input a five-digit number: 33333 is a palindrome.
83. Write a C program that reads an integer (7 digits or fewer)

and counts the number of 3s in the given number.
Sample Input: 538453
Sample Output:
Input a number: The number of threes in the said number is 2
C Code:
#include<stdio.h>
// Function to count the occurrences of digit '3' in a number
int count_three(int);
int main()
int num;
scanf("%d", &num);
// Call the function count_three and print the result
printf("The number of threes in the said number is %d\n",

count_three(num) );
return 0;
int count_three(int num)
int ctr = 0; // Initialize counter variable
int remainder; // Variable to store the remainder
// Loop until num is greater than 0
while(num> 0) {
remainder = num % 10; // Get the last digit

num /= 10; // Remove the last digit
if(remainder == 3) // Check if the last digit is 3
ctr++; // Increment counter if it is 3
return ctr; // Return the count of occurrences of 3
Copy
Sample Output:
Input a number: The number of threes in the said number is 2.
84. Write a C program to calculate and print the average of some

integers. Accept all the values preceding 888.
Sample Input:12
15
24
888
Sample Output:
Input each number on a separate line (888 to exit):
The average value of the said numbers is 17.000000
Sample Input: 12
15
24
888
Sample Solution:
C Code:
#include <stdio.h>
int main()
int ctr = 0, n; // Initialize counter and variable for input
int sum = 0; // Initialize sum variable
float avg_value = 0; // Initialize average variable
printf("Input each number on a separate line (888 to exit):\n");
// Read the first number
scanf("%d", &n);
// Loop until the user enters 888
while (n != 888) {
sum += n; // Add the number to the sum
ctr++; // Increment counter
scanf("%d", &n); // Read the next number
// Calculate the average if there were inputs
if (ctr)
avg_value = (float) sum / ctr;
// Print the average value

printf("\nThe average value of the said numbers is %f\n", avg_value);
Copy
Sample Output:
Input each number on a separate line (888 to exit):
The average value of the said numbers is 17.000000
85. Write a C program to print a table of all the Roman numeral

equivalents of decimal numbers in the range 1 to 50.
Sample Output:
Decimal Roman
number numeral
-------------------
1 I
2 II
3 III
4 IV
.....
98 LXXXXVIII
99 LXXXXIX
100 C
C Code:
#include <stdio.h>
int main()
int i, x;
// Print the header of the Roman numeral table

printf("Decimal Roman\n");
printf("number numeral\n");
printf("-------------------\n");
// Loop through numbers from 1 to 100
for(i = 1; i<= 100; i++)
x = i; // Store current value of i in x
printf("%d ", x); // Print the decimal number
// Convert decimal number to Roman numeral
if(x == 100) {
printf("C"); // Print Roman numeral for 100
x = 0; // Reset x to 0
if(x >= 50) {
printf("L"); // Print Roman numeral for 50
x -= 50; // Subtract 50 from x
while(x >= 10) {
printf("X"); // Print Roman numeral for 10
if(x >= 5) {
if(x % 10 == 9) {
printf("IX"); // Print Roman numeral for 9
else {
printf("V"); // Print Roman numeral for 5
while(x > 0)
if(x % 10 == 4) {
printf("IV"); // Print Roman numeral for 4
else {
printf("I"); // Print Roman numeral for 1
printf("\n"); // Move to the next line for the next number
return 0;
}
Copy
Sample Output:
Decimal Roman
numbers numerals
-------------------
1 I
2 II
3 III
4 IV
5 V
6 VI
7 VII
8 VIII
9 IX
10 X
11 XI
12 XII
13 XIII
14 XIV
15 XV
16 XVI
17 XVII
18 XVIII
19 XIX
20 XX
21 XXI
22 XXII
23 XXIII
24 XXIV
25 XXV
26 XXVI
27 XXVII
28 XXVIII
29 XXIX
30 XXX
31 XXXI
32 XXXII
33 XXXIII
34 XXXIV
35 XXXV
36 XXXVI
37 XXXVII
38 XXXVIII
39 XXXIX
40 XL
41 XLI
42 XLII
43 XLIII
44 XLIV
45 XLV
46 XLVI
47 XLVII
48 XLVIII
49 XLIX
50 L
51 LI
52 LII
53 LIII
54 LIV
55 LV
56 LVI
57 LVII
58 LVIII
59 LIX
60 LX
61 LXI
62 LXII
63 LXIII
64 LXIV
65 LXV
66 LXVI
67 LXVII
68 LXVIII
69 LXIX
70 LXX
71 LXXI
72 LXXII
73 LXXIII
74 LXXIV
75 LXXV
76 LXXVI
77 LXXVII
78 LXXVIII
79 LXXIX
80 LXXX
81 LXXXI
82 LXXXII
83 LXXXIII
84 LXXXIV
85 LXXXV
86 LXXXVI
87 LXXXVII
88 LXXXVIII
89 LXXXIX
90 XC
91 XCI
92 XCII
93 XCIII
94 XCIV
95 XCV
96 XCVI
97 XCVII
98 XCVIII
99 XCIX
100 C
86. Write a C program to display the sizes and ranges for each of
C's data types.
Sample Output:
Size of C data types:
Type Bytes
--------------------------------
char 1
int8_t 1
unsigned char 1
uint8_t 1
short 2
int16_t 2
uint16t 2
int 4
unsigned 4
long 8
unsigned long 8
int32_t 4
uint32_t 4
long long 8
int64_t 8
unsigned long long 8
uint64_t 8
float 4
double 8
long double 16
_Bool 1
C Code:
#include <stdio.h>
#include <stdint.h>
#include <stdbool.h>
#include <limits.h>
int main(void) {
// Display title
printf("Size and Range of C data types:\n\n");
// Display column headers
printf("%-20s %-20s %-20s\n", "Type", "Bytes", "Range");
// Display separator line
printf("------------------------------------------------------\
n");
// Print size and range of various data types
printf("%-20s %lu %-20d to %-20d\n", "char", sizeof(char),

CHAR_MIN, CHAR_MAX);
printf("%-20s %lu %-20d to %-20d\n", "int8_t", sizeof(int8_t),

INT8_MIN, INT8_MAX);
printf("%-20s %lu %-20d to %-20d\n", "unsigned char",

sizeof(unsigned char), 0, UCHAR_MAX);
printf("%-20s %lu %-20d to %-20d\n", "uint8_t", sizeof(uint8_t),

0, UINT8_MAX);
printf("%-20s %lu %-20d to %-20d\n", "short", sizeof(short),

SHRT_MIN, SHRT_MAX);


0, UINT16_MAX);
printf("%-20s %lu %-20d to %-20d\n", "int", sizeof(int), INT_MIN,
INT_MAX);
printf("%-20s %lu %-20u to %-20u\n", "unsigned", sizeof(unsigned),

0, UINT_MAX);
printf("%-20s %lu %-20ld to %-20ld\n", "long", sizeof(long),

LONG_MIN, LONG_MAX);
printf("%-20s %lu %-20lu to %-20lu\n", "unsigned long",

sizeof(unsigned long), 0, ULONG_MAX);

printf("%-20s %lu %-20u to %-20u\n", "uint32_t", sizeof(uint32_t),

0, UINT32_MAX);
printf("%-20s %lu %-20lld to %-20lld\n", "long long", sizeof(long

long), LLONG_MIN, LLONG_MAX);
printf("%-20s %lu %-20llu to %-20llu\n", "int64_t",

sizeof(int64_t), 0LL, ULLONG_MAX);
printf("%-20s %lu %-20lld to %-20lld\n", "int64_t",

sizeof(int64_t), LLONG_MIN, LLONG_MAX);
printf("%-20s %lu %-20llu to %-20llu\n", "uint64_t",

sizeof(uint64_t), 0ULL, ULLONG_MAX);
// Floating point types don't have well-defined "range" in the

same sense as integers
// Add a newline for better output formatting
printf("\n");
// Indicate successful execution of the program
return 0;
Copy
Sample Output:
Size and Range of C data types:
Type Bytes Range
------------------------------------------------------
char 1 -128 to 127
int8_t 1 -128 to 127
unsigned char 1 0 to 255
uint8_t 1 0 to 255
short 2 -32768 to 32767
int16_t 2 -32768 to 32767
uint16_t 2 0 to 65535
int 4 -2147483648 to 2147483647
unsigned 4 0 to 4294967295
long 4 -2147483648 to 2147483647
unsigned long 4 0 to 4294967295
int32_t 4 -2147483648 to 2147483647
uint32_t 4 0 to 4294967295
long long 8 -9223372036854775808 to
9223372036854775807
int64_t 8 0 to
18446744073709551615
int64_t 8 -9223372036854775808 to
9223372036854775807
uint64_t 8 0 to
18446744073709551615
86. Write a C program to display the sizes and ranges for each of
C's data types.
Sample Output:
Size of C data types:
Type Bytes
--------------------------------
char 1
int8_t 1
unsigned char 1
uint8_t 1
short 2
int16_t 2
uint16t 2
int 4
unsigned 4
long 8
unsigned long 8
int32_t 4
uint32_t 4
long long 8
int64_t 8
unsigned long long 8
uint64_t 8
float 4
double 8
long double 16
_Bool 1
C Code:
#include <stdio.h>
#include <stdint.h>
#include <limits.h>
int main(void) {
// Display title
printf("Size and Range of C data types:\n\n");
// Display column headers
printf("%-20s %-20s %-20s\n", "Type", "Bytes", "Range");
// Display separator line
printf("------------------------------------------------------\
n");
// Print size and range of various data types
printf("%-20s %lu %-20d to %-20d\n", "char", sizeof(char),

CHAR_MIN, CHAR_MAX);

printf("%-20s %lu %-20d to %-20d\n", "unsigned char",

sizeof(unsigned char), 0, UCHAR_MAX);

0, UINT8_MAX);
printf("%-20s %lu %-20d to %-20d\n", "short", sizeof(short),
SHRT_MIN, SHRT_MAX);


0, UINT16_MAX);
printf("%-20s %lu %-20d to %-20d\n", "int", sizeof(int), INT_MIN,

INT_MAX);
printf("%-20s %lu %-20u to %-20u\n", "unsigned", sizeof(unsigned),

0, UINT_MAX);
printf("%-20s %lu %-20ld to %-20ld\n", "long", sizeof(long),

LONG_MIN, LONG_MAX);
printf("%-20s %lu %-20lu to %-20lu\n", "unsigned long",

sizeof(unsigned long), 0, ULONG_MAX);

printf("%-20s %lu %-20u to %-20u\n", "uint32_t", sizeof(uint32_t),

0, UINT32_MAX);
printf("%-20s %lu %-20lld to %-20lld\n", "long long", sizeof(long

long), LLONG_MIN, LLONG_MAX);
printf("%-20s %lu %-20llu to %-20llu\n", "int64_t",

sizeof(int64_t), 0LL, ULLONG_MAX);
printf("%-20s %lu %-20lld to %-20lld\n", "int64_t",

sizeof(int64_t), LLONG_MIN, LLONG_MAX);
printf("%-20s %lu %-20llu to %-20llu\n", "uint64_t",

sizeof(uint64_t), 0ULL, ULLONG_MAX);
// Floating point types don't have well-defined "range" in the

same sense as integers
// Add a newline for better output formatting
printf("\n");
// Indicate successful execution of the program

return 0;
Copy
Sample Output:
Size and Range of C data types:
Type Bytes Range

------------------------------------------------------
char 1 -128 to 127
int8_t 1 -128 to 127
unsigned char 1 0 to 255
uint8_t 1 0 to 255
short 2 -32768 to 32767
int16_t 2 -32768 to 32767
uint16_t 2 0 to 65535
int 4 -2147483648 to 2147483647
unsigned 4 0 to 4294967295
long 4 -2147483648 to 2147483647
unsigned long 4 0 to 4294967295
int32_t 4 -2147483648 to 2147483647
uint32_t 4 0 to 4294967295
long long 8 -9223372036854775808 to
9223372036854775807
int64_t 8 0 to
18446744073709551615
int64_t 8 -9223372036854775808 to
9223372036854775807
uint64_t 8 0 to
18446744073709551615
87. Write a C program to display the minimum and maximum

values for each of C's data types.
Sample Output:
Ranges for integer data types in C
------------------------------------------------------------
int8_t -128 127
int16_t -32768 32767
int32_t -2147483648 2147483647
int64_t -9223372036854775808 9223372036854775807
uint8_t 0 255
uint16_t 0 65535
uint32_t 0 4294967295
uint64_t 0 18446744073709551615
============================================================
Ranges for real number data types in C
------------------------------------------------------------
float 1.175494e-38 3.402823e+38
double 2.225074e-308 1.797693e+308
long double 3.362103e-4932 1.189731e+4932
C Code:
#include <stdio.h>
#include <stdint.h>
#include <limits.h>
#include <float.h>
int main( void )
// Print header for integer data types
printf( "Ranges for integer data types in C\n\n" );
// Print separator line
printf(
"------------------------------------------------------------\n");
// Print range for int8_t
printf( "int8_t %20d %20d\n" , SCHAR_MIN , SCHAR_MAX );

printf( "int16_t %20d %20d\n" , SHRT_MIN , SHRT_MAX );
printf( "int32_t %20d %20d\n" , INT_MIN , INT_MAX );
printf( "int64_t %20lld %20lld\n" , LLONG_MIN , LLONG_MAX );
// Print range for uint8_t
printf( "uint8_t %20d %20d\n" , 0 , UCHAR_MAX );
printf( "uint16_t %20d %20d\n" , 0 , USHRT_MAX );
printf( "uint32_t %20d %20u\n" , 0 , UINT_MAX );
printf( "uint64_t %20d %20llu\n" , 0 , ULLONG_MAX );
printf( "\n" );

printf(
"============================================================\n\n");
// Print header for real number data types
printf( "Ranges for real number data types in C\n\n" );
printf(
"------------------------------------------------------------\n");
// Print range for float
printf( "float %14.7g %14.7g\n" , FLT_MIN , FLT_MAX );
// Print range for double
printf( "double %14.7g %14.7g\n" , DBL_MIN , DBL_MAX );
// Print range for long double
printf( "long double %14.7Lg %14.7Lg\n" , LDBL_MIN , LDBL_MAX );
printf( "\n" );
return 0;
Copy
Sample Output:
Ranges for integer data types in C
------------------------------------------------------------
int8_t -128 127
int16_t -32768 32767
int32_t -2147483648 2147483647
int64_t -9223372036854775808 9223372036854775807
uint8_t 0 255
uint16_t 0 65535
uint32_t 0 4294967295
uint64_t 0 18446744073709551615
============================================================
Ranges for real number data types in C
------------------------------------------------------------
float 1.175494e-38 3.402823e+38
double 2.225074e-308 1.797693e+308
long double 3.362103e-4932 1.189731e+4932
88. Write a C program to create an extended ASCII table. Print

the ASCII values 32 through 255.
Sample Output:
|----------------------------------------------------------------
-----------------------------------------|
|extended ASCII table - excluding control characters
|
| Ch Dec Hex | Ch Dec Hex | Ch Dec Hex | Ch Dec Hex |
Ch Dec Hex | Ch Dec Hex | Ch Dec Hex |
|----------------|----------------|-------------|--------------|-
-------------|-------------|-------------|
| har 32 0x20 | @har 64 0x40 | ` 96 0x60 | � 128 0x80 |
� 160 0xa0 | � 192 0xc0 | � 224 0xe0 |
| !har 33 0x21 | Ahar 65 0x41 | a 97 0x61 | � 129 0x81 |
� 161 0xa1 | � 193 0xc1 | � 225 0xe1 |
| "har 34 0x22 | Bhar 66 0x42 | b 98 0x62 | � 130 0x82 |
� 162 0xa2 | � 194 0xc2 | � 226 0xe2 |
| #har 35 0x23 | Char 67 0x43 | c 99 0x63 | � 131 0x83 |
� 163 0xa3 | � 195 0xc3 | � 227 0xe3 |
| $har 36 0x24 | Dhar 68 0x44 | d 100 0x64 | � 132 0x84 |
� 164 0xa4 | � 196 0xc4 | � 228 0xe4 |
| %har 37 0x25 | Ehar 69 0x45 | e 101 0x65 | � 133 0x85 |
� 165 0xa5 | � 197 0xc5 | � 229 0xe5 |
| &har 38 0x26 | Fhar 70 0x46 | f 102 0x66 | � 134 0x86 |
� 166 0xa6 | � 198 0xc6 | � 230 0xe6 |
| 'har 39 0x27 | Ghar 71 0x47 | g 103 0x67 | � 135 0x87 |
� 167 0xa7 | � 199 0xc7 | � 231 0xe7 |
| (har 40 0x28 | Hhar 72 0x48 | h 104 0x68 | � 136 0x88 |
� 168 0xa8 | � 200 0xc8 | � 232 0xe8 |
| )har 41 0x29 | Ihar 73 0x49 | i 105 0x69 | � 137 0x89 |
� 169 0xa9 | � 201 0xc9 | � 233 0xe9 |
| *har 42 0x2a | Jhar 74 0x4a | j 106 0x6a | � 138 0x8a |
� 170 0xaa | � 202 0xca | � 234 0xea |
| +har 43 0x2b | Khar 75 0x4b | k 107 0x6b | � 139 0x8b |
� 171 0xab | � 203 0xcb | � 235 0xeb |
| ,har 44 0x2c | Lhar 76 0x4c | l 108 0x6c | � 140 0x8c |
� 172 0xac | � 204 0xcc | � 236 0xec |
| -har 45 0x2d | Mhar 77 0x4d | m 109 0x6d | � 141 0x8d |
� 173 0xad | � 205 0xcd | � 237 0xed |
| .har 46 0x2e | Nhar 78 0x4e | n 110 0x6e | � 142 0x8e |
� 174 0xae | � 206 0xce | � 238 0xee |
| /har 47 0x2f | Ohar 79 0x4f | o 111 0x6f | � 143 0x8f |
� 175 0xaf | � 207 0xcf | � 239 0xef |
| 0har 48 0x30 | Phar 80 0x50 | p 112 0x70 | � 144 0x90 |
� 176 0xb0 | � 208 0xd0 | � 240 0xf0 |
| 1har 49 0x31 | Qhar 81 0x51 | q 113 0x71 | � 145 0x91 |
� 177 0xb1 | � 209 0xd1 | � 241 0xf1 |
| 2har 50 0x32 | Rhar 82 0x52 | r 114 0x72 | � 146 0x92 |
� 178 0xb2 | � 210 0xd2 | � 242 0xf2 |
| 3har 51 0x33 | Shar 83 0x53 | s 115 0x73 | � 147 0x93 |
� 179 0xb3 | � 211 0xd3 | � 243 0xf3 |
| 4har 52 0x34 | Thar 84 0x54 | t 116 0x74 | � 148 0x94 |
� 180 0xb4 | � 212 0xd4 | � 244 0xf4 |
| 5har 53 0x35 | Uhar 85 0x55 | u 117 0x75 | � 149 0x95 |
� 181 0xb5 | � 213 0xd5 | � 245 0xf5 |
| 6har 54 0x36 | Vhar 86 0x56 | v 118 0x76 | � 150 0x96 |
� 182 0xb6 | � 214 0xd6 | � 246 0xf6 |
| 7har 55 0x37 | Whar 87 0x57 | w 119 0x77 | � 151 0x97 |
� 183 0xb7 | � 215 0xd7 | � 247 0xf7 |
| 8har 56 0x38 | Xhar 88 0x58 | x 120 0x78 | � 152 0x98 |
� 184 0xb8 | � 216 0xd8 | � 248 0xf8 |
| 9har 57 0x39 | Yhar 89 0x59 | y 121 0x79 | � 153 0x99 |
� 185 0xb9 | � 217 0xd9 | � 249 0xf9 |
| :har 58 0x3a | Zhar 90 0x5a | z 122 0x7a | � 154 0x9a |
� 186 0xba | � 218 0xda | � 250 0xfa |
| ;har 59 0x3b | [har 91 0x5b | { 123 0x7b | � 155 0x9b |
� 187 0xbb | � 219 0xdb | � 251 0xfb |
| <har 60 0x3c | \har 92 0x5c | | 124 0x7c | � 156 0x9c |
� 188 0xbc | � 220 0xdc | � 252 0xfc |
| =har 61 0x3d | ]har 93 0x5d | } 125 0x7d | � 157 0x9d |
� 189 0xbd | � 221 0xdd | � 253 0xfd |
| >har 62 0x3e | ^har 94 0x5e | ~ 126 0x7e | � 158 0x9e |
� 190 0xbe | � 222 0xde | � 254 0xfe |
| ?har 63 0x3f | _har 95 0x5f |DEL 127 0x7f | � 159 0x9f |
� 191 0xbf | � 223 0xdf | � 255 0xff |
C Code:
#include <stdio.h>
int main( void )
unsigned char char1 , char2 , char3 , char4 , char5 , char6 , char7 ,

char8 ;
// Print table header
printf("|-------------------------------------------------------------
--------------------------------------------|\n" );
printf("|extended ASCII table - excluding control characters

|\n" );
printf("| Ch Dec Hex | Ch Dec Hex | Ch Dec Hex | Ch Dec Hex

| Ch Dec Hex | Ch Dec Hex | Ch Dec Hex |\n" );
printf("|----------------|----------------|-------------|-------------
-|--------------|-------------|-------------|\n" );
// Loop through characters

for(int i = 0 ; i< 32; i++)
// Calculate characters for different ranges
char1 = i;
char2 = i+32;
char3 = i+64;
char4 = i+96;
char5 = i+128; // extended ASCII characters
char6 = i+160;
char7 = i+192;
char8 = i+224;
// Print characters and their decimal and hexadecimal

representations
printf( "| %c %3d %#x " , char2 , char2 , char2 );
printf( "| %c %3d %#x " , char3 , char3 , char3 );
// Special case for DEL character
if( char4 == 127 ) {
printf("|%s %3d %#x |" , "DEL" , char4 , char4 );
} else {
printf("| %c %3d %#x |" , char4 , char4 , char4 );
// Print extended ASCII characters for current system.

printf(" %c %3d %#x | %c %3d %#x | %c %3d %#x | %c %3d %#x |\n" ,
char5 , char5 , char5 ,
char8 , char8 , char8 );
Copy
Sample Output:
|----------------------------------------------------------------
-----------------------------------------|
|extended ASCII table - excluding control characters
|
| Ch Dec Hex | Ch Dec Hex | Ch Dec Hex | Ch Dec Hex |
Ch Dec Hex | Ch Dec Hex | Ch Dec Hex |
|----------------|----------------|-------------|--------------|-
-------------|-------------|-------------|
| har 32 0x20 | @har 64 0x40 | ` 96 0x60 | � 128 0x80 |
� 160 0xa0 | � 192 0xc0 | � 224 0xe0 |
| !har 33 0x21 | Ahar 65 0x41 | a 97 0x61 | � 129 0x81 |
� 161 0xa1 | � 193 0xc1 | � 225 0xe1 |
| "har 34 0x22 | Bhar 66 0x42 | b 98 0x62 | � 130 0x82 |
� 162 0xa2 | � 194 0xc2 | � 226 0xe2 |
| #har 35 0x23 | Char 67 0x43 | c 99 0x63 | � 131 0x83 |
� 163 0xa3 | � 195 0xc3 | � 227 0xe3 |
| $har 36 0x24 | Dhar 68 0x44 | d 100 0x64 | � 132 0x84 |
� 164 0xa4 | � 196 0xc4 | � 228 0xe4 |
| %har 37 0x25 | Ehar 69 0x45 | e 101 0x65 | � 133 0x85 |
� 165 0xa5 | � 197 0xc5 | � 229 0xe5 |
| &har 38 0x26 | Fhar 70 0x46 | f 102 0x66 | � 134 0x86 |
� 166 0xa6 | � 198 0xc6 | � 230 0xe6 |
| 'har 39 0x27 | Ghar 71 0x47 | g 103 0x67 | � 135 0x87 |
� 167 0xa7 | � 199 0xc7 | � 231 0xe7 |
| (har 40 0x28 | Hhar 72 0x48 | h 104 0x68 | � 136 0x88 |
� 168 0xa8 | � 200 0xc8 | � 232 0xe8 |
| )har 41 0x29 | Ihar 73 0x49 | i 105 0x69 | � 137 0x89 |
� 169 0xa9 | � 201 0xc9 | � 233 0xe9 |
| *har 42 0x2a | Jhar 74 0x4a | j 106 0x6a | � 138 0x8a |
� 170 0xaa | � 202 0xca | � 234 0xea |
| +har 43 0x2b | Khar 75 0x4b | k 107 0x6b | � 139 0x8b |
� 171 0xab | � 203 0xcb | � 235 0xeb |
| ,har 44 0x2c | Lhar 76 0x4c | l 108 0x6c | � 140 0x8c |
� 172 0xac | � 204 0xcc | � 236 0xec |
| -har 45 0x2d | Mhar 77 0x4d | m 109 0x6d | � 141 0x8d |
� 173 0xad | � 205 0xcd | � 237 0xed |
| .har 46 0x2e | Nhar 78 0x4e | n 110 0x6e | � 142 0x8e |
� 174 0xae | � 206 0xce | � 238 0xee |
| /har 47 0x2f | Ohar 79 0x4f | o 111 0x6f | � 143 0x8f |
� 175 0xaf | � 207 0xcf | � 239 0xef |
| 0har 48 0x30 | Phar 80 0x50 | p 112 0x70 | � 144 0x90 |
� 176 0xb0 | � 208 0xd0 | � 240 0xf0 |
| 1har 49 0x31 | Qhar 81 0x51 | q 113 0x71 | � 145 0x91 |
� 177 0xb1 | � 209 0xd1 | � 241 0xf1 |
| 2har 50 0x32 | Rhar 82 0x52 | r 114 0x72 | � 146 0x92 |
� 178 0xb2 | � 210 0xd2 | � 242 0xf2 |
| 3har 51 0x33 | Shar 83 0x53 | s 115 0x73 | � 147 0x93 |
� 179 0xb3 | � 211 0xd3 | � 243 0xf3 |
| 4har 52 0x34 | Thar 84 0x54 | t 116 0x74 | � 148 0x94 |
� 180 0xb4 | � 212 0xd4 | � 244 0xf4 |
| 5har 53 0x35 | Uhar 85 0x55 | u 117 0x75 | � 149 0x95 |
� 181 0xb5 | � 213 0xd5 | � 245 0xf5 |
| 6har 54 0x36 | Vhar 86 0x56 | v 118 0x76 | � 150 0x96 |
� 182 0xb6 | � 214 0xd6 | � 246 0xf6 |
| 7har 55 0x37 | Whar 87 0x57 | w 119 0x77 | � 151 0x97 |
� 183 0xb7 | � 215 0xd7 | � 247 0xf7 |
| 8har 56 0x38 | Xhar 88 0x58 | x 120 0x78 | � 152 0x98 |
� 184 0xb8 | � 216 0xd8 | � 248 0xf8 |
| 9har 57 0x39 | Yhar 89 0x59 | y 121 0x79 | � 153 0x99 |
� 185 0xb9 | � 217 0xd9 | � 249 0xf9 |
| :har 58 0x3a | Zhar 90 0x5a | z 122 0x7a | � 154 0x9a |
� 186 0xba | � 218 0xda | � 250 0xfa |
| ;har 59 0x3b | [har 91 0x5b | { 123 0x7b | � 155 0x9b |
� 187 0xbb | � 219 0xdb | � 251 0xfb |
| <har 60 0x3c | \har 92 0x5c | | 124 0x7c | � 156 0x9c |
� 188 0xbc | � 220 0xdc | � 252 0xfc |
| =har 61 0x3d | ]har 93 0x5d | } 125 0x7d | � 157 0x9d |
� 189 0xbd | � 221 0xdd | � 253 0xfd |
| >har 62 0x3e | ^har 94 0x5e | ~ 126 0x7e | � 158 0x9e |
� 190 0xbe | � 222 0xde | � 254 0xfe |
| ?har 63 0x3f | _har 95 0x5f |DEL 127 0x7f | � 159 0x9f |
� 191 0xbf | � 223 0xdf | � 255 0xff |
89. Write a C programming to calculate (x + y + z) for each pair

of integers x, y and z where -2^31 <= x, y, z<= 2^31-1.
Sample Output:
Result: 140733606875472
C Code:
#include <stdio.h>
int main()
long long x, y, z;
// Prompt the user for input
printf("Input x, y, z:\n");
// Read input values
scanf("%lld %lld %lld", &x, &y, &z);

// Calculate and print the result
printf("Result: %lld\n", x + y + z);
Copy
Sample Output:
Input x,y,x:
Result: 140733606875472
90. Write a C program to find all prime palindromes in the range

of two given numbers x and y (5 <= x<y<= 1000,000,000).
A number is called a prime palindrome if the number is both a
prime number and a palindrome.
Sample Output:
Input two numbers (separated by a space):
List of prime palindromes:
0
1
C Code:
#include<stdio.h>
// Function to compute a palindrome number from a given number
int compute(int n){
if(n == 9) // Special case for n = 9
return 11; // Return 11
int res = 0, tmp, base = 1;
// Loop to reverse the digits of n

for(tmp = n / 10; tmp> 0; tmp = tmp / 10){
res = res * 10 + tmp % 10; // Build the reversed number
base *= 10;
return n * base + res; // Combine the original and reversed

numbers
// Function to check if a number is prime and print it if it is
int prime(int n){
int i;
int flag;
// Loop to check for factors of n
for(i = 2; i * i<= n; i++){
flag = 0;
if(n % i == 0){
flag = 1; // Set flag to indicate non-prime
break;
if(flag == 0){ // If flag remains 0, n is a prime number
printf("%d\n", n); // Print the prime number

}
int main(){
int x, y, temp = 0;
printf("Input two numbers (separated by a space):\n");
scanf("%d %d", &x, &y);
printf("List of prime palindromes:\n");
// Loop to generate and check palindrome numbers
for(; temp <= y; x++){
temp = compute(x);
prime(temp);
Copy
Sample Output:
Input two numbers (separated by a space):
List of prime palindromes:
0
1
91. Write a C program to find the angle between (12:00 to 11:59)

the hour hand and the minute hand of a clock. The hour hand and
the minute hand are always between 0 and 180 degrees.
For example, when it's 12 o'clock, the angle of the two hands is 0
while 3:00 is 45 degrees and 6:00 is 180 degrees.
Sample Output:
Input hour(h) and minute(m) (separated by a space):
3 0
At 3:00 the angle is 90.0 degrees.
6 15
The angle is 90.0 degrees at 6:15.
12 0
C Code:
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
int main()
int h, m; // Declare variables for hour and minute
double angle; // Declare variable for angle
const int num[13] = {0,30,60,90,120,150,180,210,240,270,300,330,0}; //

Define an array of angles
printf("Input hour(h) and minute(m) (separated by a space):\n"); //

Prompt user for input
scanf("%d %d",&h,&m); // Read input for hour and minute

angle = num[h] - m*5.5; // Calculate the angle based on the input
values
if (angle < 0) // Ensure angle is positive
angle = -angle;
if (angle > 180) // Ensure angle is within 180 degrees
angle = 360 - angle;
if ( m < 10 )
printf("At %d:0%d the angle is %.1f degrees.\n",h,m,angle); // Print

angle and time in format HH:MM
else
printf("The angle is %.1f degrees at %d:%d.\n",angle,h,m); // Print

angle and time in format HH:MM
Copy
Sample Output:
3 0
6 15
The angle is 90.0 degrees at 6:15.
12 0
92. Write a C program to find the last non-zero digit of the
factorial of a given positive integer.
For example for 5!, the output will be "2" because 5! = 120, and 2
is the last nonzero digit of 120
Sample Output:
Input a positive number:
The last non-zero digit of the said factorial:
0
C Code:
#include <stdio.h>
#include <string.h>
// Array representing the factorials of numbers 0 to 9
const char ftr[] = {1,1,2,6,4,4,4,8,4,6};
// Function to perform computation on an array of digits
void comp(char i[], int* len)
int j;
char c, tmp;
if(i[0] < 5)
c = i[0];
(*len)--;
// Iterate through the digits and perform computation

for(j = 0; j < *len; j++)
tmp = (c*10 + i[j+1]) % 5;
i[j] = (c*10 + i[j+1]) / 5;
c = tmp;
else
c = 0;
// Iterate through the digits and perform computation
for(j = 0; j < *len; j++)
tmp = (c*10 + i[j]) % 5;
i[j] = (c*10 + i[j]) / 5;
c = tmp;
// Recursive function to calculate factorial
char fact(char i[], int len)
char ans, c, d;
if(len == 1 &&i[0] < 5)
return ftr[(int)i[0]];
else
ans = ftr[(int)i[len-1]] * 6 % 10;
comp(i, &len);
d = (i[len-1] + ((len> 1) ? i[len-2] * 10 : 0)) & 0x03;
// Apply further calculations
for(c = 0; c < d; c++)
if(ans == 2 || ans == 6)
ans += 10;
ans /= 2;
return fact(i, len) * ans % 10;
int main()
char chr[1002];
int len, i;
char c;
printf("Input a positive number:\n");
scanf("%s", chr);
len = strlen(chr);
// Convert character digits to actual integers
for(i = 0; i<len; i++)
chr[i] -= '0';
// Calculate factorial and get the last non-zero digit
c = fact(chr, len);
printf("The last non-zero digit of the said factorial:\n");
putchar(c + '0');
putchar(10);
return 0;
Copy
Sample Output:
Input a positive number:
The last non-zero digit of the said factorial:
0
93. Write a C program to check if a given number is nearly prime

number or not.
Nearly prime numbers are a positive integer which is equal to the
product of two prime numbers.
Sample Output:
It is not a Nearly prime number.
C Code:
#include <stdio.h>
// Define the number of primes to generate
#define NUM_OF_PRIMES 3500
// Function to check if a number is prime
int is_prime(int num);
int main() {
int primes[NUM_OF_PRIMES], num_of_primes = 0;
// Initialize the list of primes with the first prime number
primes[num_of_primes++] = 2;
// Generate primes up to 1000000000
for(int num = 3; num * num<= 1000000000; num++) {
int flag = 1;
// Check if num is divisible by any previously generated

primes
for(int id = 0; id <num_of_primes; id++) {

if(num % primes[id] == 0) {
flag = 0;
break;
// If num is prime, add it to the list of primes
if(flag) primes[num_of_primes++] = num;
int N, num;
scanf("%d", &num);
int flag = 0;
// Check if num is a Nearly prime number
for(int j = 0; (j <num_of_primes) && (primes[j] * primes[j] <= num);

j++) {
if(num % primes[j] == 0) {
num /= primes[j];
flag = 1;
break;
// Check if the remaining number after division is also prime

if(flag &&is_prime(num))
printf("It is a Nearly prime number.\n");
else
printf("It is not a Nearly prime number.\n");
return 0;
// Function to check if a number is prime
int is_prime(int num) {
if(num != 2 &&num % 2 == 0)
return 0;
for(int factor = 3; factor * factor <= num ; factor += 2) {
if(num % factor == 0)
return 0;
return 1;
Copy
Sample Output:
It is not a Nearly prime number.
94. Write a C program to calculate body mass index and display
the grade.
Sample Output:
Input the weight: 65
Input the height: 5.6
BMI = 2.072704
Grade: Under
C Code:
#include <stdio.h>
// Function to calculate and display BMI
void BMI(int, float);
int main(void) {
int w; // Variable to store weight
float h; // Variable to store height
// Prompt user for weight and height
printf("Input the weight: ");
scanf("%d", &w);
printf("Input the height: ");
scanf("%f", &h);
// Call the BMI function with provided weight and height
BMI(w, h);
}
// Function to calculate and display BMI
void BMI(int weight, float height) {
// Calculate BMI using the provided formula
float temp = weight / (height * height);
// Display the calculated BMI
printf("BMI = %f\n", temp);
printf("\nGrade: ");
// Determine BMI grade and display it
temp< 18.5 ? printf("Under ") : temp < 25 ? printf("Normal ") : temp <
30 ? printf("Over ") : temp < 40 ? printf("Obese ") : printf("Error");
Copy
Sample Output:
Input the weight: 65
Input the height: 5.6
BMI = 2.072704
Grade: Under
95. Write a C program to print the corresponding Fahrenheit to

Celsius and Celsius to Fahrenheit.
Both cases initial tempratue = 00, maximum temperature =
1500 and step 100
Sample Output:
Celsius to Fahrenheit
---------------------
Celsius Fahrenheit
0.0 32.0
10.0 50.0
20.0 68.0
30.0 86.0
....
120.0 248.0
130.0 266.0
140.0 284.0
150.0 302.0
Fahrenheit to Celsius
---------------------
Fahrenheit Celsius
0.0 -17.8
10.0 -12.2
20.0 -6.7
30.0 -1.1
40.0 4.4
50.0 10.0
...
120.0 48.9
130.0 54.4
140.0 60.0
150.0 65.6
C Code:
#include <stdio.h>
int main() {
float f_temp, c_temp; // Variables to store Fahrenheit and Celsius

temperatures
float start_temp, end_temp; // Starting and ending temperatures for

the conversion
int STEP; // Step size for temperature increments

// Initialize temperature conversion settings
start_temp = 0;
end_temp = 150;
STEP = 10;
// Fahrenheit to Celsius conversion
printf("Fahrenheit to Celsius");
printf("\n---------------------\n");
printf("Fahrenheit Celsius\n");
// Loop through the range of Fahrenheit temperatures
while (start_temp<= end_temp) {
// Convert Fahrenheit to Celsius
f_temp = start_temp * 9 / 5 + 32;
// Print the conversion results
printf("%6.1f \t %8.1f\n", start_temp, f_temp);
// Increment the temperature by the specified step size
start_temp = start_temp + STEP;
// Reset temperature conversion settings for the second conversion
start_temp = 0;
end_temp = 150;
STEP = 10;
// Celsius to Fahrenheit conversion
printf("\n\nCelsius to Fahrenheit\n");
printf("---------------------\n");
printf("Celsius Fahrenheit\n");
// Loop through the range of Celsius temperatures
while (start_temp<= end_temp) {
// Convert Celsius to Fahrenheit
c_temp = (start_temp - 32) * 5 / 9;
// Print the conversion results
printf("%6.1f \t %8.1f\n", start_temp, c_temp);
// Increment the temperature by the specified step size
start_temp = start_temp + STEP;
Copy
Sample Output:
Celsius to Fahrenheit
---------------------
Celsius Fahrenheit
0.0 32.0
10.0 50.0
20.0 68.0
30.0 86.0
40.0 104.0
50.0 122.0
60.0 140.0
70.0 158.0
80.0 176.0
90.0 194.0
100.0 212.0
110.0 230.0
120.0 248.0
130.0 266.0
140.0 284.0
150.0 302.0
Fahrenheit to Celsius
---------------------
Fahrenheit Celsius
0.0 -17.8
10.0 -12.2
20.0 -6.7
30.0 -1.1
40.0 4.4
50.0 10.0
60.0 15.6
70.0 21.1
80.0 26.7
90.0 32.2
100.0 37.8
110.0 43.3
120.0 48.9
130.0 54.4
140.0 60.0
150.0 65.6
96. Write a C program to count blanks, tabs, and newlines in

input text.
Sample Output:
Number of blanks, tabs, and newlines:
Input few words/tab/newlines
The quick
brown fox jumps
over the lazy dog
^Z
blank=7,tab=2,newline=3
C Code:
#include <stdio.h>
int main() {
int blank_char, tab_char, new_line; // Variables to count blank

characters, tab characters, and newlines
blank_char = 0; // Initialize the count of blank characters
tab_char = 0; // Initialize the count of tab characters
new_line = 0; // Initialize the count of newlines
int c; // Variable to hold input characters
printf("Number of blanks, tabs, and newlines:\n");
printf("Input few words/tab/newlines\n");
// Loop to read characters until end-of-file (EOF) is encountered
for (; (c = getchar()) != EOF;) {
if (c == ' ') {
++blank_char; // Increment the count of blank characters
if (c == '\t') {
++tab_char; // Increment the count of tab characters
if (c == '\n') {
++new_line; // Increment the count of newlines
}
}
// Print the final counts of blanks, tabs, and newlines
printf("blank=%d,tab=%d,newline=%d\n", blank_char, tab_char,

new_line);
Copy
Sample Output:
Number of blanks, tabs, and newlines:
Input few words/tab/newlines
The quick
brown fox jumps
over the lazy dog
^Z
blank=7,tab=2,newline=3
97. Write a C program that accepts a string and counts the

number of characters, words and lines.
Sample Output:
Input a string and get number of charcters, words and lines:
The quick brown fox jumps over the lazy dog
^Z
Number of Characters = 44
Number of words = 9
Number of lines = 1
C Code:
#include <stdio.h>
int main() {
long ctr_char, ctr_word, ctr_line; // Variables to count characters,

words, and lines
int c; // Variable to hold input characters

int flag; // Flag to track word boundaries
ctr_char = 0; // Initialize the count of characters
flag = ctr_line = ctr_word = 0; // Initialize flag and counts for

words and lines
printf("Input a string and get number of characters, words and lines:\

n");
// Loop to read characters until end-of-file (EOF) is encountered
while ((c = getchar()) != EOF) {
++ctr_char; // Increment the count of characters
if (c == ' ' || c == '\t') {
flag = 0; // Reset the flag when a space or tab is encountered
} else if (c == '\n') {
++ctr_line; // Increment the count of lines
flag = 0; // Reset the flag on a newline
} else {
if (flag == 0) {
++ctr_word; // Increment the count of words when a new word

begins
flag = 1; // Set the flag to indicate a word is in progress
}
// Print the counts of characters, words, and lines
printf("\nNumber of Characters = %ld", ctr_char);
printf("\nNumber of words = %d", ctr_word);
printf("\nNumber of lines = %d", ctr_line);
Copy
Sample Output:
Input a string and get number of characters, words and lines:
^Z
Number of Characters = 44
Number of words = 9
Number of lines = 1
98. Write a C program that accepts some text from the user and
prints each word of that text on a separate line.
Sample Output:
Input some text:
The
quick
brown
fox
jumps
over
the
lazy
dog
C Code:
#include <stdio.h>
int main() {
long nc = 0; // Variable to count characters
int new_l = 0; // Variable to count newlines
int n_word = 0; // Variable to count words
int chr; // Variable to hold input characters
int flag = 0; // Flag to track word boundaries
int last = 0; // Flag to track the last character
printf("Input some text:\n");
while ((chr = getchar()) != EOF) {
++nc; // Increment the count of characters
if (chr == ' ' || chr == '\t') {
flag = 0; // Reset the flag when a space or tab is encountered
} else if (chr == '\n') {
++new_l; // Increment the count of newlines
flag = 0; // Reset the flag on a newline
} else {
if (flag == 0) {
++n_word; // Increment the count of words when a new word

begins
flag = 1; // Set the flag to indicate a word is in progress
}
if (flag == 0 && last == 0) {
printf("\n"); // Print a newline when a word ends and the last

character was not a space
last = 1; // Set last to 1 to indicate the last character was a

space
} else {
putchar(chr); // Print the character
last = 0; // Set last to 0 to indicate the last character was not

a space
Copy
Sample Output:
Input some text:
The
quick
brown
fox
jumps
over
the
lazy
dog
99. Write a C program that takes some integer values from the
user and prints a histogram.
Sample Output:
Input number of histogram bar (Maximum 10):
4
Input the values between 0 and 10 (separated by space):
9
7
4
3
Histogram:
#########
#######
####
###
C Code:
#include <stdio.h>
// Function to print a histogram
void print_Histogram ( int *hist, int n );
int main() {
int i, j;
int inputValue, hist_value=0;
// Prompt the user to input the number of histogram bars (Maximum

10)
printf("Input number of histogram bar (Maximum 10): \n");
scanf("%d", &inputValue);
int hist[inputValue];
if (inputValue<=10)
// Prompt the user to input values for the histogram bars
printf("Input the values between 0 and 10 (separated by space): \

n");
for (i = 0; i < inputValue; ++i) {

scanf("%d", &hist_value);
// Check if the input value is within the valid range (1 to 10)
if (hist_value>=1 && hist_value<=10)
hist[i] = hist_value;
hist_value=0;
int results[10] = {0};
// Count the occurrences of each value in the histogram
for(j = 0; j < inputValue; j++) {
if ( hist[j] == i){
results[i]++;
printf("\n");
// Print the histogram
print_Histogram(hist, inputValue);
return 0;
// Function to print the histogram
void print_Histogram(int *hist, int n) {
printf("\nHistogram:\n");
int i, j;
// Loop through the histogram bars and print '#' for each
occurrence
for (i = 0; i < n; i++) {
for ( j = 0; j < hist[i]; ++j) {
printf("#");
printf("\n");
Copy
Sample Output:
Input number of histogram bar (Maximum 10):
4
Input the values between 0 and 10 (separated by space):
9
7
4
3
Histogram:
#########
#######
####
###
100. Write a C program to convert a currency value (floating

point with two decimal places) to the number of coins and notes.
Sample Output:
Input the currency value (floating point with two decimal
places):
10357.75
Currency Notes:
100 number of Note(s): 103
Currency Coins:
.50 number of Coin(s): 1
C Code:
#include <stdio.h>
#include <math.h>
int main() {
double amt;
unsigned int int_amt, frac_amt;
// Prompt the user to input the currency value
printf("Input the currency value (floating point with two decimal

places):\n");
scanf("%lf", &amt);
// Separate the integer part and fractional part
int_amt = (int) amt;
amt -= int_amt;
frac_amt = round((amt * 100));

// Display currency notes
printf("\nCurrency Notes:");
// Calculate and display 100 rupee notes
printf("\n100 number of Note(s): %d", int_amt / 100);
// Update the integer amount after deducting 100 rupee notes
int_amt -= (int_amt / 100) * 100;
// Check and display 50 rupee note
if (int_amt > 50) {
printf("\n50 number of Note(s): 1");
int_amt -= 50;
// Check and display 20 rupee notes
if (int_amt/20 > 0)
int_amt -= (int_amt / 20) * 20;
if (int_amt/10 > 0)
int_amt -= (int_amt / 10) * 10;
if (int_amt/5 > 0)
int_amt -= (int_amt / 5) * 5;
if (int_amt > 0)
int_amt -= (int_amt / 2) * 2;
if (int_amt > 0)
printf("\n1 number of Note(s): %d", int_amt);
// Display currency coins
printf("\n\nCurrency Coins:");
// Check and display 50 paise coins
if (frac_amt > 50) {
printf("\n.50 number of Coin(s): 1");
frac_amt -= 50;
if (frac_amt/25 > 0)
printf("\n.25 number of Coin(s): %d", frac_amt / 25);
// Update the fractional amount after deducting 25 paise coins
frac_amt -= (frac_amt / 25) * 25;
if (frac_amt/10 > 0)
if (frac_amt/5 > 0)

if (frac_amt > 0)
printf("\n.01 number of Coin(s): %d", frac_amt);
return 0;
Copy
Sample Output:
Input the currency value (floating point with two decimal
places):
10387.75
Currency Notes:
Currency Coins:
101. There are three given ranges. Write a C program that reads
a floating-point number and finds the range where it belongs from
four given ranges.
Sample Output:
Input a number: 87
Range (80,100]
C Code:
#include <stdio.h>
int main ()
// Declare a variable "x" to hold the input number
float x = 0;
// Read the input number
scanf("%f", &x);
// Check the range of the input number and print the corresponding
message
if (x >= 0 && x <= 30)
printf("Range [0,30]\n");
else if (x > 30 && x <= 50)
printf("Range (30,50]\n");
else if (x > 50 && x <= 80)
else if (x > 80 && x <= 100)
else
printf("\nNot within range..!\n");

}
Copy
Sample Output:
Input a number: 87
Range (80,100]
102. Write a C program that reads three integers and sorts the
numbers in ascending order. Print the original numbers and the
sorted numbers.
Sample Output:
Input 3 integers: 17
-5
25
---------------------------
Original numbers: 17, -5, 25
Sorted numbers: -5, 17, 25
C Code:
#include <stdio.h>
#include <math.h>
int main (){
// Declare three integer variables
int x, y, z;
// Prompt the user to input three integers
printf("Input 3 integers: ");
// Read the input values for x, y, and z
scanf("%d %d %d", &x, &y, &z);

// Print a separator line for clarity
printf("\n---------------------------\n");
// Display the original input numbers
printf("Original numbers: %d, %d, %d", x, y, z);
// Display the sorted numbers
printf("\nSorted numbers: ");
// Nested if-else statements to sort and print the numbers
if (x <= y && y <= z){
printf("%d, %d, %d", x, y, z);
else{
if (x <= z && z <= y){
printf("%d, %d, %d", x, z, y);
else{
if (y <= x && x <= z){
printf("%d, %d, %d", y, x, z);
else{
if (y <= z && z <= x){
printf("%d, %d, %d", y, z, x);

}
else{
if (z <= x && x <= y){
printf("%d, %d, %d", z, x, y);
else{
if (x == y && y == z){
printf("%d, %d, %d", x, y, z);
else{
printf("%d, %d, %d", z, y, x);
Copy
Sample Output:
Input 3 integers: 17
-5
25
---------------------------
Original numbers: 17, -5, 25
Sorted numbers: -5, 17, 25
103. Write a C program that takes two integers and tests
whether they are multiplied or not.
In science, a multiple is the product of any quantity and an
integer. In other words, for the quantities a and b, we say that b
is a multiple of a if b = na for some integer n, which is called the
multiplier. If a is not zero, this is equivalent to saying that b/a is
an integer.
Sample Output:
Input two integers:
3
9
Multiplies
C Code:
#include <stdio.h>
int main () {
// Declare unsigned short integer variables x, y, and multi
unsigned short int x, y, multi;
// Prompt the user to input two integers
printf("Input two integers: \n");
// Read the input values for x and y
scanf("%hd %hd", &x, &y);
// Check if x is greater than y
if (x > y){
// Calculate the remainder when x is divided by y
multi = x % y;
// Check if the remainder is zero
if ( multi == 0){
printf("Multiplies\n");
else{
printf("Not Multiplies\n");
else{
// Calculate the remainder when y is divided by x
multi = y % x;
// Check if the remainder is zero
if (multi == 0){
printf("Multiplies\n");
else{
printf("Not Multiplies\n");
Copy
Sample Output:
Input two integers:
3
9
Multiplies
104. Write a C program that reads the item's price and creates a
revised price for the item, based on the item price table.
Sample Output:
Input the item price:525
New Item price: 582.75
Increased price: 57.75
Increase Percentage: 11%
C Code:
#include <stdio.h>
int main ()
// Declare variables for item price and increased price
float price, increased_price;
// Prompt the user to input the item price
printf("Input the item price:");
// Read the input value for item price
scanf("%f", &price);
// Check the range of the item price and calculate increased price
and percentage accordingly
if (price >= 100 && price <= 400){

// Calculate increased price and update item price
increased_price = price * 0.14;
price = price + increased_price;
// Print the new item price, increased price, and increase

percentage
printf("New Item price: %.2f\n", price);
printf("Increased price: %.2f\n", increased_price);
printf("Increase Percentage: 14%%\n");
else{
if (price > 400 && price <= 800){
else{
if (price > 800 && price <= 1200){

else{
if (price > 1200 && price <= 2000){
printf("Increased price: %.2f\n",

increased_price);
else{

printf("Increased price: %.2f\n",
increased_price);
Copy
Sample Output:
Input the item price:525
New Item price: 582.75
Increased price: 57.75
Increase Percentage: 11%
105. Write a C program that accepts seven floating point

numbers and counts the number of positive and negative
numbers. Print the average of all positive and negative values
with two digits after the decimal number.
Sample Output:
Input 7 numbers(int/float):
25
35.75
15
-3.5
40
35
16
6 Number of positive numbers: Average 27.79
1 Number of negative numbers: Average -3.50
C Code:
#include <stdio.h>
int main () {
float x, p_avg = 0, n_avg = 0, temp_p = 0, temp_n = 0;
int i, p_ctr = 0, n_ctr = 0;
// Prompt the user to input 7 numbers
printf("Input 7 numbers(int/float):\n");
// Loop through 7 times to read the numbers
for (i = 0; i < 7; i++){
// Read a number
scanf("%f", &x);
// Check if the number is positive
if (x > 0){
p_ctr++; // Increment positive counter
temp_p += x; // Sum positive numbers
// Check if the number is negative
if (x < 0){
n_ctr++; // Increment negative counter
temp_n += x; // Sum negative numbers
}
}
// Calculate the average of positive numbers
p_avg = temp_p/p_ctr;
// Calculate the average of negative numbers
n_avg = temp_n/n_ctr;
// Check if there were positive numbers
if (p_ctr > 0){
printf("\n%d Number of positive numbers: ", p_ctr);
printf("Average %.2f\n", p_avg);
// Check if there were negative numbers
if (n_ctr > 0){
printf("\n%d Number of negative numbers: ", n_ctr);
printf("Average %.2f\n", n_avg);
Copy
Sample Output:
Input 7 numbers(int/float):
25
35.75
15
-3.5
40
35
16
6 Number of positive numbers: Average 27.79
1 Number of negative numbers: Average -3.50
106. Write a C program that accepts 7 integer values and counts

the even, odd, positive and negative values.
Sample Output:
Input 7 integers:
10
12
15
-15
26
35
17
Number of even values: 3

Number of odd values: 4
Number of positive values: 6
Number of negative values: 1
C Code:
#include <stdio.h>
int main ()
// Declare variables for input, counters for even, odd, positive,

and negative numbers
int x, i, ctr_even = 0, ctr_odd = 0, ctr_positive = 0,

ctr_negative = 0;
// Prompt the user to input 7 integers

printf("\nInput 7 integers:\n");
// Loop through 7 times to read the numbers
for (i = 0; i < 7; i++){
// Read an integer
scanf("%d", &x);
// Check if the number is positive
if (x > 0){
ctr_positive++; // Increment positive counter
// Check if the number is negative
if (x < 0){
ctr_negative++; // Increment negative counter
// Check if the number is even
if (x % 2 == 0){
ctr_even++; // Increment even counter
// Check if the number is odd
if (x % 2 != 0){
ctr_odd++; // Increment odd counter
// Print the counts of even, odd, positive, and negative numbers
printf("\nNumber of even values: %d", ctr_even);
printf("\nNumber of odd values: %d", ctr_odd);
printf("\nNumber of positive values: %d", ctr_positive);
printf("\nNumber of negative values: %d", ctr_negative);
Copy
Sample Output:
Input 7 integers:
10
12
15
-15
26
35
17
Number of even values: 3

Number of odd values: 4
Number of positive values: 6
Number of negative values: 1
107. Write a C program that prints ten consecutive odd and even
numbers after accepting an integer.
Sample Output:
Input an integer number:
15
Next 10 consecutive odd numbers:

17, 19, 21, 23, 25, 27, 29, 31, 33, 35,
Next 10 consecutive even numbers:
26, 28, 30, 32, 34, 36, 38, 40, 42, 44,
C Code:
#include <stdio.h>
int main () {
int a, i, ctr = 0;
// Prompt the user to input an integer number
printf("Input an integer number:\n");
scanf("%d", &a);
// Print the next 10 consecutive odd numbers
printf("\nNext 10 consecutive odd numbers:\n");
for (i = a + 1; ctr < 10; i++){
if (i % 2 != 0){
printf("%d, ", i);
ctr++;
}
// Reset counter for even numbers
ctr = 0;
// Print the next 10 consecutive even numbers
printf("\n\nNext 10 consecutive even numbers:\n");
for (i = a + 1; ctr < 10; i++){
if (i % 2 == 0){
printf("%d, ", i);
ctr++;
Copy
Sample Output:
Input an integer number:
15
Next 10 consecutive odd numbers:

17, 19, 21, 23, 25, 27, 29, 31, 33, 35,
Next 10 consecutive even numbers:

26, 28, 30, 32, 34, 36, 38, 40, 42, 44,
108. Write a C program that reads two integer values and

calculates the sum of all odd numbers between them.
Sample Output:
Input the first integer number:
25
Input the second integer number (greater than first integer):
45
Sum of all odd values between 25 and 45:
385
Sum of all even values between 25 and 45:
350
C Code:
#include <stdio.h>
int main () {
// Declare variables for input, counters, and sum of odd and even
numbers
int a, b, i, ctr = 0, sum_odd = 0, sum_even = 0;
// Prompt the user to input the first integer number
printf("Input the first integer number:\n");
scanf("%d", &a);
// Prompt the user to input the second integer number (greater

than the first integer)
printf("Input the second integer number (greater than first

integer):\n");
scanf("%d", &b);
// Check if b is greater than a
if (b > a)
// Calculate the sum of all odd values between a and b

for (i = a; i <= b; i++){
if (i % 2 != 0){
sum_odd = sum_odd + i;
// Print the sum of all odd values
printf("Sum of all odd values between %d and %d:", a, b);
printf("\n%d", sum_odd);
// Reset counter
ctr = 0;
// Calculate the sum of all even values between a and b
for (i = a; i <= b; i++){
if (i % 2 == 0){
sum_even = sum_even + i;
// Print the sum of all even values
printf("\nSum of all even values between %d and %d:", a, b);
printf("\n%d", sum_even);
}
}
Copy
Sample Output:
Input the first integer number:
25
Input the second integer number (greater than first integer):
45
Sum of all odd values between 25 and 45:
385
Sum of all even values between 25 and 45:
350
109. Write a C program to find and print the square of each even
and odd value between 1 and a given number (4 < n < 101).
Sample Output:
Input a number(integer): 15
Square of each even between 1 and 15:

2^2 = 4
4^2 = 16
6^2 = 36
8^2 = 64
10^2 = 100
12^2 = 144
14^2 = 196
Square of each odd between 1 and 15:

1^2 = 1
3^2 = 9
5^2 = 25
7^2 = 49
9^2 = 81
11^2 = 121
13^2 = 169
15^2 = 225
C Code:
#include <stdio.h>
#include <math.h>
int main () {
int x, cont = 0, i;
printf("Input a number(integer): ");
scanf("%d", &x);
// Check if x is between 5 and 100
if (x >= 5 && x <= 100)
// Print the squares of even numbers between 1 and x
printf("\nSquare of each even between 1 and %d:\n",x);
for (i = 1; i <= x; i++){
if (i % 2 == 0){
cont = pow(i, 2);
printf("%d^2 = %d\n", i, cont);
// Print the squares of odd numbers between 1 and x
printf("\nSquare of each odd between 1 and %d:\n",x);
for (i = 1; i <= x; i++){
if (i % 2 != 0){
cont = pow(i, 2);
printf("%d^2 = %d\n", i, cont);
Copy
Sample Output:
Input a number(integer): 15
Square of each even between 1 and 15:

2^2 = 4
4^2 = 16
6^2 = 36
8^2 = 64
10^2 = 100
12^2 = 144
14^2 = 196
Square of each odd between 1 and 15:

1^2 = 1
3^2 = 9
5^2 = 25
7^2 = 49
9^2 = 81
11^2 = 121
13^2 = 169
15^2 = 225
110. Write a C program to find the odd, even, positive and

negative numbers from a given number (integer) and print a
message 'Number is positive odd' or 'Number is negative odd' or
'Number is positive even' or 'Number is negative even'. If the
number is 0 print "Zero".
Sample Output:
Input a number (integer):
12
Number is positive-even
C Code:
#include <stdio.h>
int main () {
int b;
// Prompt the user to input a number (integer)
printf("Input a number (integer):\n");
// Read the input number
scanf("%d", &b);
// Check if the number is positive and even
if ((b % 2 == 0) && b > 0){
printf("Number is positive-even\n");
else{
// Check if the number is negative and even
if ((b % 2 == 0) && b < 0){
printf("Number is negative-even'\n");
else{
// Check if the number is positive and odd
if ((b % 2 !=0) && b > 0){

printf("Number is positive-odd\n");
else{
// Check if the number is negative and odd
if ((b % 2 != 0) && b < 0){
printf("Number is negative-odd\n");
else{
// If none of the above conditions are met, it

must be zero
printf("Zero\n");
Copy
Sample Output:
12
Number is positive-even
111. Write a C program that accepts an integer from the user

and divides all numbers between 1 and 100. Print those numbers
where the remainder value is 3.
Sample Output:
65
Remainder value is 3 after divide all numbers between 1 and 100
by 65:
3
68
C Code:
#include <stdio.h>
int main () {
int x, i, y;
printf("Input a number (integer):\n");
// Read an integer from user and store it in 'x'
scanf("%d", &x);
// Print a message about the remainder condition
printf("\nRemainder value is 3 after divide all numbers between 1

and 100 by %d:\n", x);
// Loop to check for remainder condition
for (i = 1; i <= 100; i++){
if (i % x == 3){
printf("%d\n", i);
}
return 0; // End of program
Copy
Sample Output:
65
Remainder value is 3 after divide all numbers between 1 and 100

by 65:
3
68
112. Write a C program that reads seven integer values from the
user and finds the highest value and its position.
Sample Output:
Input 6 numbers (integer values):
15
20
25
17
-8
35
Maximum value: 35
Position: 6
C Code:
#include <stdio.h>
int main () {
int x, i, n = 0, temp_num = 0, position = 0;

printf("Input 6 numbers (integer values):\n");
// Loop to read and process 6 numbers
for (i = 1; i < 7; i++){
// Read an integer from user and store it in 'x'
scanf("%d", &x);
n = x; // Assign 'x' to 'n'
// Check if 'n' is greater than or equal to 'temp_num'
if (n >= temp_num){
temp_num = n; // Update 'temp_num' with the new maximum

value
position = i; // Update 'position' with the current

position
// Print the maximum value and its position
printf("\nMaximum value: %d\n", temp_num);
printf("Position: %d", position);
}
Copy
Sample Output:
Input 6 numbers (integer values):
15
20
25
17
-8
35
Maximum value: 35
Position: 6
113. Write a C program to create and print the sequence of the

following example.
Sample Output:
a=1 b=100
a=6 b=90
a=11 b=80
a=16 b=70
a=21 b=60
a=26 b=50
a=31 b=40
a=36 b=30
a=41 b=20
a=46 b=10
a=51 b=0
C Code:
#include <stdio.h>
int main ()
int a, b;
// Loop to execute statements with changing values of 'a' and 'b'
for (a = 1, b = 100; b >= 0; a += 5, b -= 10)

printf("a=%d \t b=%d\n", a, b);
Copy
Sample Output:
a=1 b=100
a=6 b=90
a=11 b=80
a=16 b=70
a=21 b=60
a=26 b=50
a=31 b=40
a=36 b=30
a=41 b=20
a=46 b=10
a=51 b=0
114. Write a C program that accepts two integer values and

calculates the sum of all even values between them.
Sample Output:
Input two numbers (integer values):
25
45
Sum of all even values between 25 and 45

350
Sample Output:
27
13

140
C Code:
#include <stdio.h>
int main () {
int y, i, z;
int l, m, n, ctr1 = 0, ctr2 = 0;
printf("Input two numbers (integer values):\n");
// Read two integer values from user and store them in 'm' and 'n'
scanf("%d %d", &m, &n);
ctr1 = 0; // Reset counter 1
printf("\nSum of all even values between %d and %d\n", m, n);
// Check if 'm' is greater than 'n'
if (m > n) {
// Loop to find and sum all even numbers between 'n' and 'm'
for (l = n + 1; l < m; l++){
if (l % 2 == 0){
ctr1 += l; // Accumulate even numbers in counter 1
printf("%d\n", ctr1); // Print the sum of even numbers
else {
// Loop to find and sum all even numbers between 'm' and 'n'
for (l = m + 1; l < n; l++){

if (l % 2 == 0){
ctr2 += l; // Accumulate even numbers in counter 2
printf("%d\n", ctr2); // Print the sum of even numbers
Copy
Sample Output:
25
45

350
Sample Output:
27
13

140
115. Write a C program that accepts a pair of numbers from the

user and prints the sequence from the lowest to the highest
number. Also, print the average value of the sequence.
Sample Output:
Input two pairs values (integer values):
14
25
Sequence from the lowest to highest number:
14 15 16 17 18 19 20 21 22 23 24 25
Average value of the said sequence
19.50
Sample Output:
35
13

13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34
35
24.00
C Code:
#include <stdio.h>
int main () {
int p, x = 1, y = 1, i = 0, temp = 0;
float sum_val = 0;
printf("Input two pairs values (integer values):\n");
// Read two integer values from user and store them in 'x' and 'y'
scanf("%d %d", &x, &y);
// Check if both 'x' and 'y' are positive
if (x > 0 && y > 0) {
// Swap 'x' and 'y' if 'y' is smaller than 'x'

if (y < x) {
temp = x;
x = y;
y = temp;
printf("\nSequence from the lowest to highest number:\n");
// Loop to print and accumulate values from 'x' to 'y'
for (p= 0, i = x; i <= y; i++) {
sum_val += i; // Accumulate the values for average

calculation
printf("%d ", i);
p++;
// Print the average value of the sequence
printf("\nAverage value of the said sequence\n%9.2f", sum_val

/ p);
Copy
Sample Output:
14
25
14 15 16 17 18 19 20 21 22 23 24 25
19.50
Sample Output:
35
13

13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34
35
24.00
116. Write a C program that accepts a pair of numbers from the

user and prints "Ascending order" if the two numbers are in
ascending order, otherwise prints, "Descending order".
Sample Output:
12
35
Ascending order
Sample Output:
65
25
Descending order
C Code:
#include <stdio.h>
int main () {
int a, b;
printf("Input two pairs values (integer values):\n");
// Read two integer values from user and store them in 'a' and 'b'
scanf("%d %d", &a, &b);
// Check if 'a' is not equal to 'b'
if (a != b) {
// Check if 'b' is greater than 'a'
if (b > a) {
printf("Ascending order\n"); // Print message for

ascending order
else {
printf("Descending order\n"); // Print message for

descending order
Copy
Sample Output:
12
35
Ascending order
Sample Output:
65
25
Descending order
117. Write a C program that reads two integers and divides the
first number by second, print the result of this division with two
digits after the decimal point and prints “Division not possible..!”
if the division is not possible.
Sample Output:
Input two integer values:
75
5
Result: 15.00
C Code:
#include <stdio.h>
int main () {
int n, x, y, i;
float result = 0;
printf("Input two integer values:\n");
// Read two integer values from user and store them in 'x' and 'y'
scanf("%d %d", &x, &y);

// Check if 'y' is zero (division by zero case)
if (y == 0) {
printf("Division not possible..!\n"); // Print an error

message
else {
// Calculate the result of division as a float value
result = (x * 1.0) / (y);
// Print the result with two decimal places
printf("Result: %.2f\n", result);
Copy
Sample Output:
75
5
Result: 15.00
118. Write a C program that reads five subject marks (0-100) of a

student and calculates the average of these marks.
Sample Output:
Input five subject marks(0-100):
75
84
56
98
68
Average marks = 76.20
C Code:
#include <stdio.h>
int main () {
float marks, tot_marks = 0;
int i = 0, subject = 0;
printf("Input five subject marks(0-100):\n");
// Loop to read marks for five subjects
while (subject != 5) {
// Read a float value 'marks' from user
scanf("%f", &marks);
// Check if 'marks' is within valid range (0-100)
if (marks < 0 || marks > 100) {
printf("Not a valid marks\n"); // Print an error message
else {
tot_marks += marks; // Accumulate valid marks
subject++; // Increment subject count

}
// Calculate and print the average marks
printf("Average marks = %.2f\n", tot_marks/5);
Copy
Sample Output:
Input five subject marks(0-100):
75
84
56
98
68
Average marks = 76.20
119. Write a C program to calculate the sum of all numbers

between two given numbers (inclusive) not divisible by 7.
Sample Output:
Input two numbers(integer):
25
5
Sum of all numbers between said numbers (inclusive) not divisible
by 7:
273
Sample Output:
6
36
by 7:
546
C Code:
#include <stdio.h>
int main () {
int a, b, sum_nums = 0, i, temp = 0;
printf("Input two numbers(integer):\n");
// Read two integer values from user and store them in 'a' and 'b'
scanf("%d %d", &a, &b);
// Swap 'a' and 'b' if 'b' is smaller than 'a'
if (b < a) {
temp = a;
a = b;
b = temp;
// Loop through the range from 'a' to 'b' (inclusive)
for (i = a; i <= b; i++) {
// Check if 'i' is not divisible by 7
if (i % 7 != 0) {
sum_nums += i; // Accumulate numbers not divisible by 7

}
// Print the sum of numbers not divisible by 7
printf("Sum of all numbers between said numbers (inclusive) not

divisible by 7:\n");
printf("%d\n", sum_nums);
Copy
Sample Output:
25
5
by 7:
273
Sample Output:
6
36
by 7:
546
120. Write a C program to print a sequence from 1 to a given

(integer) number, inserting a comma between these numbers.
There will be no comma after the last character.
Sample Output:
Input a number(integer):
25
Sequence:
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25
C Code:
#include <stdio.h>
int main () {
int n, i;
printf("\nInput a number(integer):\n");
// Read an integer value 'n' from user
scanf("%d", &n);
// Check if 'n' is positive
if (n > 0) {
printf("Sequence:\n");
// Loop to print numbers from 1 to 'n-1'
for (i = 1; i < n; i++) {
printf("%d,", i); // Print each number followed by a comma
printf("%d\n", i); // Print the last number without a comma

}
Copy
Sample Output:
Input a number(integer):
25
Sequence:
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25
121. Write a C program that reads an integer and finds all the
divisors of the said integer.
Sample Output:
Input a number (integer value):
35
All positive divisors of 35

1
5
7
35
C Code:
#include <stdio.h>
int main () {
int i, n;
printf("Input a number (integer value):\n");
// Read an integer value 'n' from user
scanf("%d", &n);
// Print a message indicating what the program will do
printf("\nAll positive divisors of %d \n",n);
// Loop through numbers from 1 to 'n'
for (i = 1; i <= n; i++) {
// Check if 'i' is a divisor of 'n'
if (n % i == 0) {
printf("%d\n", i); // Print 'i' if it is a divisor of 'n'
Copy
Sample Output:
Input a number (integer value):
35
All positive divisors of 35

1
5
7
35
122. Write a C program that reads two integers m, n and

computes the sum of n even numbers starting from m.
Sample Output:
Input two integes (m, n):
20
60
Sum of 60 even numbers starting from 20:

4740
C Code:
#include <stdio.h>
int main () {
int m, n, i, j, k, sum_even_nums = 0;
printf("\nInput two integers (m, n):\n");
// Read two integer values 'm' and 'n' from user
scanf("%d %d", &m, &n);
printf("\nSum of %d even numbers starting from %d: ",n,m);
// Loop to find and sum 'n' even numbers starting from 'm'
for (k = 0, j = m; k < n; j++) {
// Check if 'j' is even
if (j % 2 == 0) {
sum_even_nums += j; // Accumulate even numbers

k++; // Increment the count of even numbers found
// Print the sum of even numbers
printf("\n%d", sum_even_nums);
Copy
Sample Output:
20
60

4740
C Code:
#include <stdio.h>
int main () {
int m, n, i, j, k, sum_even_nums = 0;
printf("\nInput two integers (m, n):\n");
// Read two integer values 'm' and 'n' from user

scanf("%d %d", &m, &n);
printf("\nSum of %d even numbers starting from %d: ",n,m);
// Loop to find and sum 'n' even numbers starting from 'm'
for (k = 0, j = m; k < n; j++) {
// Check if 'j' is even
if (j % 2 == 0) {
sum_even_nums += j; // Accumulate even numbers
k++; // Increment the count of even numbers found
// Print the sum of even numbers
printf("\n%d", sum_even_nums);
Copy
Sample Output:
20
60

4740
123. Write a C program that reads two integers m, n and

computes the sum of n odd numbers starting from m.
Sample Output:
65
5
Sum of 5 odd numbers starting from 65:

345
124. Write a C program that reads an array of integers (length 7),

replaces every negative or null element with 1 and prints the
array elements.
Sample Output:
Input 7 array elements:
15
12
-7
25
0
27
53
Array elements:
array_nums[0] = 15
array_nums[1] = 12
array_nums[2] = 1
array_nums[3] = 25
array_nums[4] = 1
array_nums[5] = 27
array_nums[6] = 53
C Code:
#include <stdio.h>
int main () {
int array_nums[7], i, n;
printf("Input 7 array elements:\n");
// Loop to read 7 integer values from the user and store them in
the array
for (i = 0; i < 7; i++) {
scanf("%d", &n);
array_nums[i] = n;
// Print a message indicating the array elements will be displayed
printf("\nArray elements:\n");
// Loop to print each element of the array
for (i = 0; i < 7; i++) {
// Check if the element is less than or equal to 0
if (array_nums[i] <= 0) {
array_nums[i] = 1; // Set the element to 1 if it's less

than or equal to 0
// Print the array element and its value
printf("array_nums[%d] = %d\n", i, array_nums[i]);

}
Copy
Sample Output:
15
12
-7
25
0
27
53
Array elements:
array_nums[0] = 15
array_nums[1] = 12
array_nums[2] = 1
array_nums[3] = 25
array_nums[4] = 1
array_nums[5] = 27
array_nums[6] = 53
and replaces the first element of the array by a given number and
replaces each subsequent position of the array by the double
value of the previous.
Sample Output:
Input the first element of the array:
5
Array elements:
array_nums[0] = 5
array_nums[1] = 10
array_nums[2] = 20
array_nums[3] = 40
array_nums[4] = 80
array_nums[5] = 160
array_nums[6] = 320
C Code:
#include <stdio.h>
int main () {
int array_nums[7], i, x, k;
// Prompt user for the first element of the array
printf("Input the first element of the array:\n");
scanf("%d", &x);
// Loop to generate array elements by doubling 'x' in each

iteration
for (k = 0, i = x; k < 7; i *= 2, k++) {
array_nums[k] = i; // Assign the calculated value to the array
// Print a message indicating the array elements will be displayed
// Loop to print each element of the array
for (i = 0; i < 7; i++) {

}
Copy
Sample Output:
Input the first element of the array:
5
Array elements:
array_nums[0] = 5
array_nums[1] = 10
array_nums[2] = 20
array_nums[3] = 40
array_nums[4] = 80
array_nums[5] = 160
array_nums[6] = 320
126. Write a C program that reads an array (length 7) and prints

all array positions that store a value less than or equal to 0.
Sample Output:
15
23
37
65
20
-7
65
Array positions that store a value less or equal to 0:

array_nums[5] = -7.0
C Code:
#include <stdio.h>
int main () {
float n, array_nums[7];
int i;
// Loop to read 7 float values from the user and store them in the
array
for (i = 0; i < 7; i++) {
scanf("%f", &n);
array_nums[i] = n;
// Print a message indicating the positions with values less than

or equal to 0
printf("\nArray positions that store a value less or equal to 0:\

n");
// Loop to check and print positions with values less than or

equal to 0
for (i = 0; i < 7; i++) {
if (array_nums[i] <= 0) {
printf("array_nums[%d] = %.1f\n", i, array_nums[i]);
Sample Output:
15
23
37
65
20
-7
65
Array positions that store a value less or equal to 0:

array_nums[5] = -7.0

replaces the 1st element with the 8th, the 2nd with the 7th and so
on. Print the final array.
Sample Output:
25
35
17
-5
29
45
60
65
Modified array:
array_nums[0] = 65
array_nums[1] = 60
array_nums[2] = 45
array_nums[3] = 29
array_nums[4] = -5
array_nums[5] = 17
array_nums[6] = 35
array_nums[7] = 25
C Code:
#include <stdio.h>
int main () {
unsigned short i, j; // Declare variables for looping

short array_nums[8], n, temp1, temp2; // Declare array and
temporary variables
// Loop to read 8 short values from the user and store them in the
array
for (i = 0; i < 8; i++) {
scanf("%hd", &n);
array_nums[i] = n;
// Loop to swap elements from the first half of the array with the
second half
for (i = 0, j = 7; i <= 4 && j >= 4; i++, j--) {
temp1 = array_nums[i];
temp2 = array_nums[j];
array_nums[i] = temp2;
array_nums[j] = temp1;
// Print modified array
printf("\nModified array:\n");
for (i = 0; i < 8; i++)

Copy
Sample Output:
25
35
17
-5
29
45
60
65
Modified array:
array_nums[0] = 65
array_nums[1] = 60
array_nums[2] = 45
array_nums[3] = 29
array_nums[4] = -5
array_nums[5] = 17
array_nums[6] = 35
array_nums[7] = 25
128. Write a C program that reads an array of integers (length

10), fills it with numbers from o to a (given number) n – 1
repeatedly, where 2 ≤ n ≤ 10.
Sample Output:
Input an integer (2-10)
8
array_nums[0] = 0
array_nums[1] = 1
array_nums[2] = 2
array_nums[3] = 3
array_nums[4] = 4
array_nums[5] = 5
array_nums[6] = 6
array_nums[7] = 7
array_nums[8] = 0
array_nums[9] = 1
C Code:
#include <stdio.h>
int main ()
int n, i, array_nums[10], k;
printf("Input an integer (2-10)\n");
scanf("%d", &n);
if (n >= 2 && n <= 10)
k = 0;
// Loop to fill array with sequential numbers, starting from 0
for (i = 0; i < 10; i++)
array_nums[i] = k;
k++;
if (k == n)
k = 0;
}
}
// Loop to print array elements
for (i = 0; i < 10; i++)
Copy
Sample Output:
8
array_nums[0] = 0
array_nums[1] = 1
array_nums[2] = 2
array_nums[3] = 3
array_nums[4] = 4
array_nums[5] = 5
array_nums[6] = 6
array_nums[7] = 7
array_nums[8] = 0
array_nums[9] = 1
129. Write a C program that reads an array (length 10), and

replaces the first element of the array by a given number and
replaces each subsequent position of the array by one-third the
value of the previous.
Sample Output:
8
array_nums[0] = 0
array_nums[1] = 1
array_nums[2] = 2
array_nums[3] = 3
array_nums[4] = 4
array_nums[5] = 5
array_nums[6] = 6
array_nums[7] = 7
array_nums[8] = 0
array_nums[9] = 1
C Code:
#include <stdio.h>
int main ()
int i;
double array_nums[10];
double n;
printf("Input a number:\n");
scanf("%lf", &n);
// Initialize the first element of the array with the input value
array_nums[0] = n;
// Loop to generate and store subsequent array elements
for (i = 1; i < 10; i++)
n = n / 3; // Divide the current value by 3

array_nums[i] = n; // Store the result in the array
// Print the array elements
for (i = 0; i < 10; i++)
printf("array_nums[%d] = %.4lf\n", i, array_nums[i]);
Copy
Sample Output:
Input a number:
35
Array elements:
array_nums[0] = 35.0000
array_nums[1] = 11.6667
array_nums[2] = 3.8889
130. Write a C program to create an array of length n and fill the

array elements with integer values. Find the smallest value and
its position in the array.
Sample Output:
Input a number:
35
Array elements:
array_nums[0] = 35.0000
array_nums[1] = 11.6667
C Code:
#include <stdio.h>
int main ()
int array_size, i, x, z;
int min_val, position;
// Prompt the user for the array size
printf("Input the array size:\n");
scanf("%d", &array_size);
// Declare an array of integers with the specified size
int vetor[array_size];
// Prompt the user to input array elements
printf("\nInput array elements:\n");
for (i = 0; i < array_size; i++)

{
scanf("%d", &z);
vetor[i] = z; // Store the input value in the array
// Initialize min_val and position with the first element of the

array
min_val = vetor[0];
position = 0;
// Loop to find the smallest value and its position within the array
for (i = 1; i < array_size; i++)
if (vetor[i] < min_val)
min_val = vetor[i]; // Update the minimum value
position = i; // Update the position of the minimum value
// Print the smallest value and its position
printf("\nSmallest Value: %d\n", min_val);
printf("Position within array: %d\n", position);

}
Sample Output:
Input the array size:
5
Input array elements:

35
17
-5
45
36
Smallest Value: -5
Position within array: 2
131.Write a C program that accepts two strings and checks

whether the second string is present in the last part of the first
string.
Sample Output:
Input the first string:
abcdef
Input the second string:
ef
Is second string present in the last part of the first string?
Present!
C Code:
#include <stdio.h>
#include <string.h>
int main() {
short num1_len, num2_len;
char num1[50], num2[50];

// Prompt the user to input the first string
printf("Input the first string:\n");
scanf("%s", num1);
// Prompt the user to input the second string
printf("Input the second string:\n");
scanf("%s", num2);
// Get the lengths of the two strings
num1_len = strlen(num1);
num2_len = strlen(num2);
// Check if the second string is present in the last part of the

first string
printf("Is second string present in the last part of the first

string?\n");
if (num1_len == num2_len) // If the lengths are equal
if (strcmp(num1, num2) == 0) // If the strings are equal
printf("Present!\n");
else
printf("Not Present!\n");
else if (num1_len < num2_len) // If the first string is shorter than

the second
else if (strstr(&num1[num1_len - num2_len - 1], num2)) // If the

second string is found in the last part of the first string
printf("Present!\n");
else
Copy
Sample Output:
Input the first string:
abcdef
Input the second string:
ef
Is second string present in the last part of the first string?
Present!
132. Write a C program to find the heights of the top three

buildings in descending order from eight given buildings.
Input:
0 <= height of building (integer) <= 10,000
Sample Output:
Input heights(integer values) of the top eight buildings:
25
15
45
22
35
18
95
65
Heights of the top three building:

95
65
45
C Code:
#include<stdio.h>
int main(){
int heights[10], i, j, h, max_heights;
// Prompt the user to input heights of the top eight buildings
printf("Input heights (integer values) of the top eight buildings:\

n");
// Read the heights into the array
for(i = 0; i < 8; i++){
scanf("%d", &heights[i]);
// Sorting the heights in descending order
for(i = 0; i < 8; i++){
max_heights = i;
for(j = i; j < 8; j++){
if(heights[j] > heights[max_heights]){
max_heights = j;
h = heights[max_heights];
heights[max_heights] = heights[i];
heights[i] = h;
// Printing the heights of the top three buildings
printf("\nHeights of the top three buildings:\n");
printf("%d\n%d\n%d\n", heights[0], heights[1], heights[2]);
Copy
Sample Output:
Input heights(integer values) of the top eight buildings:
25
15
45
22
35
18
95
65
Heights of the top three building:

95
65
45
133. Write a C program to calculate the sum of two given

integers and count the number of digits in the sum value.
Sample Output:
68
75
Number of digits of the sum value of the said numbers:

3
C Code:
#include <stdio.h>
int main()
int x, y, sum_val, ctr;
printf("Input two integer values:\n");
scanf("%d %d", &x, &y);
ctr = 0; // Initialize a counter to keep track of digits
sum_val = x + y; // Calculate the sum of x and y
// Loop to count the number of digits in the sum value
while (sum_val != 0)
if (sum_val > 0)
sum_val = sum_val / 10; // Divide by 10 to remove the

rightmost digit
ctr++; // Increment the counter
// Print the number of digits in the sum value
printf("\nNumber of digits of the sum value of the said numbers:\

n");
printf("%d\n", ctr);
Copy
Sample Output:
68
75
Number of digits of the sum value of the said numbers:

3
134. Write a C program to check whether the three given lengths

(integers) of three sides of a triangle form a right triangle or not.
Print "Yes" if the given sides form a right triangle otherwise print
"No".
Input:
Integers separated by a single space.
1 <= length of the side <= 1,000
Sample Output:
Input the three sides of a trainagel:
12
11
13
It is not a right angle triangle!
Input:
Integers separated by a single space.
1 <= length of the side <= 1,000
Sample Solution:
C Code:
#include<stdio.h>
int main()
int x, y, z;
// Prompt the user to input the three sides of a triangle
printf("Input the three sides of a triangle:\n");
// Read the input values for x, y, and z
scanf("%d %d %d", &x, &y, &z);
// Check if the triangle is a right angle triangle
if ((x*x) + (y*y) == (z*z) || (x*x) + (z*z) == (y*y) || (y*y) +

(z*z) == (x*x))
// If the condition is true, print that it's a right angle

triangle
printf("It is a right angle triangle!\n");
else
// If the condition is false, print that it's not a right

angle triangle
printf("It is not a right angle triangle!\n");
}
return 0; // End of the program
Copy
Sample Output:
Input the three sides of a trainagel:
12
11
13
It is not a right angle triangle!
135. Write a C program that reads an integer n and finds the

number of combinations of a, b, c and d (0 ≤ a, b, c, d ≤ 9) where
(a + b + c + d) will be equal to n.
Input:
n (1 <= n <= 50)
Sample Output:
Input a number:
5
a + b + c + d = n
0, 0, 0, 5
0, 0, 1, 4
....
4, 0, 1, 0
4, 1, 0, 0
5, 0, 0, 0
Total number of combinations:

56
Input:
n (1 <= n <= 50)
Sample Solution:
C Code:
#include<stdio.h>
int main() {
int i, j, k, l, n;
scanf("%d", &n);
// Check if n is within the valid range (1 to 39)
if (n >= 1 && n <= 39) {
printf("\na + b + c + d = n");
// Initialize a counter to keep track of the valid combinations
int count = 0;
// Nested loops to iterate through all possible combinations of a,

b, c, and d
for (i = 0; i <= 9; i++) {
for (j = 0; j <= 9; j++) {
for (k = 0; k <= 9; k++) {
for (l = 0; l <= 9; l++) {
if (i + j + k + l == n) {
// Print the combination and increment the counter
printf("\n%d, %d, %d, %d", i, j, k, l);
count++;
}
}
// Print the total number of valid combinations
printf("\n\nTotal number of combinations: %d\n", count);
Copy
Sample Output:
Input a number:
5
a + b + c + d = n
0, 0, 0, 5
0, 0, 1, 4
0, 0, 2, 3
0, 0, 3, 2
0, 0, 4, 1
0, 0, 5, 0
0, 1, 0, 4
0, 1, 1, 3
0, 1, 2, 2
0, 1, 3, 1
0, 1, 4, 0
0, 2, 0, 3
0, 2, 1, 2
0, 2, 2, 1
0, 2, 3, 0
0, 3, 0, 2
0, 3, 1, 1
0, 3, 2, 0
0, 4, 0, 1
0, 4, 1, 0
0, 5, 0, 0
1, 0, 0, 4
1, 0, 1, 3
1, 0, 2, 2
1, 0, 3, 1
1, 0, 4, 0
1, 1, 0, 3
1, 1, 1, 2
1, 1, 2, 1
1, 1, 3, 0
1, 2, 0, 2
1, 2, 1, 1
1, 2, 2, 0
1, 3, 0, 1
1, 3, 1, 0
1, 4, 0, 0
2, 0, 0, 3
2, 0, 1, 2
2, 0, 2, 1
2, 0, 3, 0
2, 1, 0, 2
2, 1, 1, 1
2, 1, 2, 0
2, 2, 0, 1
2, 2, 1, 0
2, 3, 0, 0
3, 0, 0, 2
3, 0, 1, 1
3, 0, 2, 0
3, 1, 0, 1
3, 1, 1, 0
3, 2, 0, 0
4, 0, 0, 1
4, 0, 1, 0
4, 1, 0, 0
5, 0, 0, 0
Total number of combinations:

56
136. Write a C program to find prime numbers that are less than
or equal to a given integer.
Input:
n (1 <= n <= 999,999)
Sample Output:
Input a number:
123
Number of prime numbers which are less than or equal to 123
30
Input:
n (1 <= n <= 999,999)
Sample Solution:
C Code:
#include<stdio.h>
#define MAX_N 999999
int is_prime[MAX_N + 1];
int prime[MAX_N];
int main() {
int p = 0, i, j, n;
// Prompting the user to input a number
scanf("%d", &n);
// Initializing the is_prime array to all true (1)
for (i = 0; i <= n; i++)
is_prime[i] = 1;
is_prime[0] = is_prime[1] = 0; // 0 and 1 are not prime

// Finding prime numbers using the Sieve of Eratosthenes algorithm
for (i = 2; i <= n; i++) {
if (is_prime[i]) {
prime[p++] = i; // Storing prime numbers in the prime array
for (j = 2 * i; j <= n; j += i)
is_prime[j] = 0; // Marking multiples of a prime as not prime
// Printing the number of prime numbers and the count
printf("Number of prime numbers which are less than or equal to %d

", n);
printf("\n%d", p);
Copy
Sample Output:
Input a number:
123
Number of prime numbers which are less than or equal to 123
30
137. Write a C program to check if a point (x, y) is within a

triangle or not. Three points make up a triangle.
Input:
x1,y1,x2,y2,x3,y3,xp,yp separated by a single space
Sample Output:
Input three points to form a triangle:
x1 y1 z1
Input the point to check it is inside the triangle or not:

The point is outside the triangle!
Input:
x1,y1,x2,y2,x3,y3,xp,yp separated by a single space
Sample Solution:
C Code:
#include <stdio.h>
// Function to calculate the outer product of two vectors
double check_outer_product(double X1, double Y1, double X2, double Y2)

{
return X1 * Y2 - X2 * Y2;
int main() {
double x[3], y[3], xp, yp, cop1, cop2, cop3;
// Prompting the user to input three points to form a triangle
printf("Input three points to form a triangle:\n");
scanf("%lf %lf %lf %lf %lf %lf", &x[0], &y[0], &x[1], &y[1], &x[2],
&y[2]);
// Prompting the user to input a point to check if it's inside the

triangle
printf("\nInput the point to check if it is inside the triangle or

not:\n");
scanf("%lf %lf", &xp, &yp);
// Calculating the outer products using the function
cop1 = check_outer_product(x[1] - x[0], y[1] - y[0], xp - x[0], yp -

y[0]);

y[1]);

y[2]);
// Checking if the point is inside or outside the triangle based on

outer products
if (((cop1 > 0.0) && (cop2 > 0.0) && (cop3 > 0.0)) ||
((cop1 < 0.0) && (cop2 < 0.0) && (cop3 < 0.0))) {
printf("The point is inside the triangle!");
} else {
printf("The point is outside the triangle!");
Copy
Sample Output:
Input three points to form a triangle:
x1 y1 z1
Input the point to check it is inside the triangle or not:

The point is outside the triangle!
138.Write a C program to test whether two lines are parallel or
not. The four points are P(x1, y1), Q(x2, y2), R(x3, y3) and S(x4,
y4), check PQ and RS are parallel are not.
Input:
−100 <= x1, y1, x2, y2, x3, y3, x4, y4 <= 100
Each value is a real number with at most 5 digits after the
decimal point.
Sample Output:
Input P(x1,y1):
5
7
Input P(x2,y2):
3
6
Input P(x3,y3):
8
9
Input P(x4,y4):
5
6
PQ and RS are not parallel!
Input:
−100 <= x1, y1, x2, y2, x3, y3, x4, y4 <= 100
Each value is a real number with at most 5 digits after the
decimal point.
Sample Solution:
C Code:
#include <stdio.h>
main() {
// Variable declarations
double x1, x2, y1, y2, x3, y3, x4, y4;
int i, n;
// Getting user input for coordinates
printf("Input P(x1,y1):\n");
scanf("%lf %lf", &x1, &y1);
printf("\nInput P(x2,y2):\n");
// Checking if lines PQ and RS are parallel
if ((x1 == x2) && (x3 == x4))
printf("\nPQ and RS are parallel!\n");
else if ((x1 == x2) || (x3 == x4))
printf("\nPQ and RS are not parallel!\n");
else if (((y1 - y2) / (x1 - x2) - (y3 - y4) / (x3 - x4)) == 0.0)
printf("\nPQ and RS are parallel!\n");
else
printf("\nPQ and RS are not parallel!\n");
return (0); // End of the program

}
Copy
Sample Output:
Input P(x1,y1):
5
7
Input P(x2,y2):
3
6
Input P(x3,y3):
8
9
Input P(x4,y4):
5
6
PQ and RS are not parallel!
139. Write a C program to find the maximum sum of a contiguous

subsequence from a given sequence of numbers a1, a2, a3, ... an
( n = number of terms in the sequence).
Input:
You can assume that 1 <= n <= 500 and -10000 <= ai <= 10000.
Sample Output:
Input number of terms in the sequence:
5
Input the terms of the said sequence:

3
2
6
-7
8
Maximum sum of a contiguous subsequence:
12
Write a C program to find the maximum sum of a contiguous
subsequence from a given sequence of numbers a1, a2, a3, ... an
( n = number of terms in the sequence).
You can assume that 1 <= n <= 500 and -10000 <= ai <= 10000.
A contiguous subsequence of a list S is a subsequence made up
of consecutive elements of S.
For instance, if S is
5, 15, −30, 10, −5, 40, 10,
then 15, −30, 10 is a contiguous subsequence but 5, 15, 40 is not.
Give a linear-time algorithm for the following task:
• Input: A list of numbers a1, a2, . . . , an
• Output: The contiguous subsequence of maximum sum. (Note
that a subsequence of length zero has sum zero.)
For the preceding example, the answer would be 10, −5, 40, 10,
with a sum of 55
Ref: https://bit.ly/2IGGI3f
Sample Solution:
C Code:
#include <stdio.h>
int main() {
int n;
long a[5000];
long long max, tmp;
int i, j;
// Getting the number of terms in the sequence from the user
printf("Input number of terms in the sequence:\n");
scanf("%d", &n);
// Getting the terms of the sequence from the user
printf("\nInput the terms of the said sequence:\n");
for (i = 0; i < n; i++)
scanf("%ld", &(a[i]));
max = a[0];
tmp = 0;
// Finding the maximum sum of a contiguous subsequence
for (i = 0; i < n; i++) {
for (j = i; j < n; j++) {
tmp += a[j];
if (max < tmp)
max = tmp;
tmp = 0;
// Printing the maximum sum of a contiguous subsequence
printf("Maximum sum of a contiguous subsequence:\n");
printf("%lld\n", max);
}
Sample Output:
Input number of terms in the sequence:
5
Input the terms of the said sequence:

3
2
6
-7
8
Maximum sum of a contiguous subsequence:
12
140. Write a C program that reads a sequence of integers and

finds the element that occurs most frequently.
Sample Output:
Input the terms of the sequence:

5
2
4
6
8
10
^Z
Mode values of the said sequence in ascending order:
2
4
5
6
8
10
C Code:
#include <stdio.h>
#include<stdlib.h>
#include<math.h>
#include<string.h>
int main(void) {
int in;
int nums[101] = {0}; // Initialize an array to store frequency of

each number (from 1 to 100)
int i;
int max_val = 0; // Variable to keep track of the maximum frequency
printf("\nInput the terms of the sequence:\n");
while (scanf("%d", &in) != EOF) // Keep reading numbers until end of

input (EOF)
nums[in]++; // Increment the frequency count for the input number
// Find the maximum frequency
for (i = 1; i <= 100; i++) {
if (max_val < nums[i])
max_val = nums[i];
printf("Mode values of the said sequence in ascending order:\n");
// Print numbers that have the maximum frequency
for (i = 1; i <= 100; i++) {
if (max_val == nums[i])
printf("%d\n", i);
}
Copy
Sample Output:
Input the terms of the sequence:

5
2
4
6
8
10
^Z
Mode values of the said sequence in ascending order:
2
4
5
6
8
10
141. Write a C program that reads n digits (given) chosen from 0
to 9 and prints the number of combinations where the sum of the
digits equals another given number (s). Do not use the same
digits in a combination.
For example, the combinations where n = 3 and s = 6 are as
follows:
1+2+3=6
0+1+5=6
0+2+4=6
Sample Output:
Input the number:
3
Sum of the digits:

6
Number of combinations: 3
C Code:
#include<stdio.h>
// Recursive function to find combinations
int combination(int n, int s, int a) {
int i, result = 0;
// Base case: if n is 1, check if s is within valid range
if (n == 1) {
if (s >= a && s <= 9) {
return 1;
} else {
return 0;
// Iterate through possible values (a to 9)
for (i = a; i <= 9; i++) {
// Recursively call combination for (n-1) and adjust s and a

values
result += combination(n - 1, s - i, i + 1);
return result; // Return the total combinations

}
int main() {
int n, s;
printf("Input the number:\n");
scanf("%d", &n);
printf("\nSum of the digits:\n");
scanf("%d", &s);
if (n != 0 && s != 0) {
printf("Number of combinations: %d\n", combination(n, s, 0));
return 0;
Copy
Sample Output:
Input the number:
3
Sum of the digits:

6
Number of combinations: 3
142. Write a C program that reads the two adjoining sides and
the diagonal of a parallelogram and checks whether the
parallelogram is a rectangle or a rhombus.
Input:
Two adjoined sides and the diagonal.
1 <= ai, bi, ci <= 1000, ai + bi > ci
Sample Output:
Input two adjoined sides of the parallelogram:
3
4
Input the diagonal of the parallelogram:

5
This is a rectangle.
Sample Output:
5
5

7
This is a rhombus.
According to Wikipedia-
parallelograms: In Euclidean geometry, a parallelogram is a
simple (non-self-intersecting) quadrilateral with two pairs of
parallel sides. The opposite or facing sides of a parallelogram are
of equal length and the opposite angles of a parallelogram are of
equal measure.
rectangles: In Euclidean plane geometry, a rectangle is a
quadrilateral with four right angles. It can also be defined as an
equiangular quadrilateral, since equiangular means that all of its
angles are equal (360°/4 = 90°). It can also be defined as a
parallelogram containing a right angle.
rhombus: In plane Euclidean geometry, a rhombus (plural rhombi
or rhombuses) is a simple (non-self-intersecting) quadrilateral
whose four sides all have the same length. Another name is
equilateral quadrilateral, since equilateral means that all of its
sides are equal in length. The rhombus is often called a diamond,
after the diamonds suit in playing cards which resembles the
projection of an octahedral diamond, or a lozenge, though the
former sometimes refers specifically to a rhombus with a 60°
angle (see Polyiamond), and the latter sometimes refers
specifically to a rhombus with a 45° angle.
Input:
Two adjoined sides and the diagonal.
1 <= ai, bi, ci <= 1000, ai + bi > ci
Sample Solution:
C Code:
#include <stdio.h>
int main() {
int h1, h2, t;
int rect = 0;
int hisi = 0;
// Initialize variables
rect = 0;
hisi = 0;
// Input the adjoined sides of the parallelogram
printf("Input two adjoined sides of the parallelogram:\n");
scanf("%d", &h1);
scanf("%d", &h2);
// Input the diagonal of the parallelogram

printf("\nInput the diagonal of the parallelogram:\n");
scanf("%d", &t);
// Check if it's a rectangle
if (t * t == h1 * h1 + h2 * h2)
rect++;
// Check if it's a rhombus
if (h1 == h2)
hisi++;
// Output the results
if (rect > 0)
printf("\nThis is a rectangle.");
if (hisi > 0)
printf("\nThis is a rhombus.");
return 0;
Copy
Sample Output:
3
4

5
This is a rectangle.
Sample Output:
5
5

7
This is a rhombus.
143. Write a C program to find the difference between the

largest integer and the smallest integer, which are created by 8
numbers from 0 to 9. The number that can be rearranged shall
start with 0 as in 00135668.
Input:
Data is a sequence of 8 numbers (digits from 0 to 9).
Output:
The difference between the largest integer and the smallest
integer.
Sample Output:
Input an integer created by 8 numbers (0 to 9):
25346879

integer.
98765432 - 23456789 = 75308643
Input:
Data is a sequence of 8 numbers (digits from 0 to 9).
Output:
integer.
Sample Solution:
C Code:
#include<stdio.h>
int main() {
int max_val, min_val, k, d, t;
// Prompt user to input an integer created by 8 numbers (0 to 9)
printf("Input an integer created by 8 numbers (0 to 9):\n");
scanf("%d", &d);
int i, j, s[8] = {0};
// Extract individual digits and store them in array s
for (i = 0; d != 0; i++) {
s[i] = d % 10;
d /= 10;
// Sort the digits in descending order
for (i = 0; i < 8; i++) {
for (j = 1; j + i < 8; j++) {
if (s[j - 1] < s[j]) {
t = s[j - 1];
s[j - 1] = s[j];
s[j] = t;
}
}
max_val = 0;
// Construct the largest integer from sorted digits
for (i = 0; i < 8; i++) {
max_val *= 10;
max_val += s[i];
// Reverse the order of digits in array s
for (i = 0; i * 2 < 8; i++) {
t = s[i];
s[i] = s[7 - i];
s[7 - i] = t;
min_val = 0;
// Construct the smallest integer from reversed digits
for (i = 0; i < 8; i++) {
min_val *= 10;
min_val += s[i];
}
// Calculate and display the difference between the largest and
smallest integers
printf("\nThe difference between the largest integer and the

smallest integer.\n");
printf("%d - %d = %d\n", max_val, min_val, max_val - min_val);
return 0;
Copy
Sample Output:
Input an integer created by 8 numbers (0 to 9):
25346879

integer.
98765432 - 23456789 = 75308643
144. Write a C program to create the maximum number of

regions obtained by drawing n given straight lines.
Input:
(1 ≤ n ≤ 10,000).
Sample Output:
Input number of straight lines:
2
Maximum number of regions obtained by drawing 2 given straight
lines:
4
If you draw a straight line on a plane, the plane is divided into

two regions. For example, if you pull two straight lines in parallel,
you get three areas, and if you draw vertically one to the other,
you get four areas.
Input:
(1 ≤ n ≤ 10,000)
C Code:
#include <stdio.h>
int main() {
long n;
// Prompt user to input number of straight lines
printf("Input number of straight lines:\n");
scanf("%ld", &n);
// Calculate and display maximum number of regions obtained by

drawing 'n' given straight lines
printf("Maximum number of regions obtained by drawing %ld given

straight lines:\n", n);
printf("%ld\n", (n*n+n+2)/2);
return 0;
Copy
Sample Output:
Input number of straight lines:
2
Maximum number of regions obtained by drawing 2 given straight
lines:
4
145. Write a C program to sum all numerical values (positive

integers) embedded in a sentence.
Input:
Sentences with positive integers are given over multiple lines.
Each line is a character string containing one-byte alphanumeric
characters, symbols, spaces, or an empty line. However the input
is 80 characters or less per line and the sum is 10,000 or less.
Sample Output:
Input Sentences with positive integers:
5littleJackand2mouse.
Sum of all numerical values embedded in a sentence:

7
Input:
Sentences with positive integers are given over multiple lines.
Each line is a character string containing one-byte alphanumeric
characters, symbols, spaces, or an empty line. However the input
is 80 characters or less per line and the sum is 10,000 or less
Sample Solution:
C Code:
#include <stdio.h>
#include <stdlib.h>
// Define a character array to store text
char text[128];
int main(void) {
int i, j, k;
int result = 0;
char temp[8];
// Prompt user to input sentences with positive integers
printf("Input Sentences with positive integers:\n");
// Read user input into the 'text' array
scanf("%s", text);
i = 0;
while (text[i]) {
// Loop through characters until a digit is found
for (; (text[i] < '0' || '9' < text[i]) && text[i]; i++);
if ('0' <= text[i] && text[i] <= '9') {
// Extract and store the numerical value in 'temp'
for (j = 0; '0' <= text[i] && text[i] <= '9'; j++, i++) {
temp[j] = text[i];
temp[j] = '\0';
// Convert 'temp' to an integer and add it to 'result'
result += atoi(temp);
// Print the sum of all numerical values embedded in the sentence
printf("\nSum of all numerical values embedded in a sentence:\n");

printf("%d\n", result);
return 0;
Copy
Sample Output:
Input Sentences with positive integers:
5littleJackand2mouse.
Sum of all numerical values embedded in a sentence:

7
146. Write a C program to extract words of 3 to 6 characters

length from a given sentence not more than 1024 characters.
Input:
English sentences consisting of delimiters and alphanumeric
characters are given on one line.
Sample Output:
characters on one line:
w3resource.com
Extract words of 3 to 6 characters length from the said sentence:

com
Internet search engine giant, such as Google accepts web pages

around the world and classify them, creating a huge database.
The search engines also analyze the search keywords entered by
the user and create inquiries for database search. In both cases,
complicated processing is carried out in order to realize efficient
retrieval, but basics are all cutting out words from sentences.
Input:
characters are given on one line.
Sample Solution:
C Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
int main() {
// Define an array to store input text
char input_text[1536];
// Initialize a counter variable
int ctr = 0;
// Define a pointer variable 'temp'
char * temp;
printf("English sentences consisting of delimiters and alphanumeric

characters on one line:\n");
// Read a line of text from the user
fgets(input_text, sizeof(input_text), stdin);
// Print message indicating the purpose of the operation

printf("\nExtract words of 3 to 6 characters length from the said
sentence:\n");
// Tokenize the input text using delimiters (space, period, comma,

newline)
for (temp = strtok(input_text, " .,\n"); temp != NULL; temp =

strtok(NULL, " .,\n")) {
const int len = strlen(temp);
// Check if the length of the word is between 3 and 6 characters
if (3 <= len && len <= 6) {
// If not the first word, print a space before the word
if (ctr++) putchar(' ');
// Print the word
fputs(temp, stdout);
// Print a newline character after the extracted words
puts("");
return (0);
Copy
Sample Output:
characters on one line:
w3resource.com
Extract words of 3 to 6 characters length from the said sentence:

com
147. Write a C program to find the number of combinations that

satisfy p + q + r + s = n where n is a given number <= 4000 and p,
q, r, s are between 0 and 1000.
Sample Output:
25
Number of combinations of p,q,r,s:

3276
C Code:
#include <stdio.h>
#include <stdlib.h>
// Define a macro to ensure non-negative numbers
#define check_num(x) (x>0?x:0)
// Define global variables
int n, result, x;
int main(void) {
printf("Input a positive integer:\n");

// Read the input
scanf("%d", &n);
// Initialize result variable
result = 0;
// Loop through possible values of x within the specified range
for (x = check_num(n - 2000); x <= 2000 && n >= x; x++) {
// Calculate the result based on the given formula
result += (1001 - abs(1000 - (n - x))) * (1001 - abs(1000

- x));
// Print the number of combinations
printf("\nNumber of combinations of p,q,r,s:\n");
printf("%d\n", result);
// Return 0 to indicate successful execution
return 0;
Sample Output:
25
Number of combinations of p,q,r,s:

3276
148. Write a C program, which adds up columns and rows of
given table as shown in the following figure.
Input:
n (the size of row and column of the given table)
1st row of the table
2nd row of the table
:
:
n th row of the table
The input ends with a line consisting of a single 0.
Sample Output:
Input number of rows/columns:
4
Input the cell value
Row 0 input cell values

25
69
51
26

68
35
29
54

54
57
45
63

61
68
47
59
Result:
25 69 51 26 171
68 35 29 54 186
54 57 45 63 219
61 68 47 59 235
208 229 172 202 811
Input:
n (the size of row and column of the given table)
1st row of the table
2nd row of the table
:
:
n th row of the table
The input ends with a line consisting of a single 0.
Output:
For each dataset, print the table with sum of rows and columns.
Sample Solution:
C Code:
#include <stdio.h>
int main() {
// Declare a 2D array to store cell data
int cell_data[11][11];
int i, j, n, sum_val;
printf("Input number of rows/columns:\n");
scanf("%d", &n);
// Prompt user for cell values
printf("Input the cell value\n");

// Check if n is a positive value
if (n > 0) {
// Loop through rows
for(i = 0; i < n; i++) {
printf("\nRow %d input cell values\n", i);
// Loop through columns
for(j = 0; j < n; j++) {
// Read cell value and store it in the array
scanf("%d", &cell_data[i][j]);
// Calculate row sums and update array
printf("\nResult:\n");
for(i = 0; i < n; i++) {
sum_val = 0;
for(j = 0; j < n; j++) {
sum_val += cell_data[j][i];
cell_data[n][i] = sum_val;
// Calculate column sums and update array

for(i = 0; i < n; i++) {
sum_val = 0;
for(j = 0; j < n; j++) {
sum_val += cell_data[i][j];
cell_data[i][n] = sum_val;
// Calculate total sum and update array
sum_val = 0;
for(i = 0; i < n; i++) {
sum_val += cell_data[n][i];
cell_data[n][n] = sum_val;
// Print the updated array
for(i = 0; i < n + 1; i++) {
for(j = 0; j < n + 1; j++) {
printf("%5d", cell_data[i][j]);
printf("\n");
// Return 0 to indicate successful execution

return 0;
Copy
Sample Output:
Input number of rows/columns:
4
Input the cell value

25
69
51
26

68
35
29
54

54
57
45
63

61
68
47
59
Result:
25 69 51 26 171
68 35 29 54 186
54 57 45 63 219
61 68 47 59 235
208 229 172 202 811
149. Write a C program that reads a list of pairs of a word and a

page number, and prints the word and a list of the corresponding
page numbers.
Input:
word page_number
Output:
word
a_list_of_the_page_number
word
a_list_of_the_Page_number.
Sample Output:
Input pairs of a word and a page_no number:
Twinkle
65
Twinkle
55
Little
25
Star
35
^Z
Word and page_no number in alphabetical order:

Little
25
Star
35
Twinkle
55 65
The number of pairs of a word and a page number is less than or
equal to 1000. A word never appears in a page more than once.
The words should be printed in alphabetical order and the page
numbers should be printed in ascending order.
Input:
word page_number
Output:
word
a_list_of_the_page_number
word
a_list_of_the_Page_number
Sample Solution:
C Code:
#include<stdio.h>
#include<string.h>
// Define a structure to hold a word and its corresponding page number
typedef struct{
int page_no;
char word[50];
} STR;
main(){
STR temp, str[10000]; // Declare variables of type STR
int i=0,j,k;
int count=0;
printf("Input pairs of a word and a page_no number:\n");
// Read word and page_no pairs until end of file (EOF)
while(scanf("%s %d",str[i].word,&str[i].page_no)!=EOF){
i++;
// Sorting algorithm to sort words alphabetically and by page number

if words are the same
for(j=0;j<i;j++){
for(k=i-1;0<k;k--){
if(strcmp(str[k].word,str[k-1].word)<0){
temp=str[k];
str[k]=str[k-1];
str[k-1]=temp;
else if(strcmp(str[k].word,str[k-1].word)==0){
if(str[k].page_no<str[k-1].page_no){
temp=str[k];
str[k]=str[k-1];
str[k-1]=temp;
// Print sorted word and page number pairs
printf("\nWord and page_no number in alphabetical order:\n");
for(j=0;j<i;j++){
if(j!=0){
if(strcmp(str[j].word,str[j-1].word)==0){
printf(" %d",str[j].page_no);
else{
printf("\n%s\n%d",str[j].word,str[j].page_no);
else{
printf("%s\n%d",str[j].word,str[j].page_no);
printf("\n");
return 0;
Copy
Sample Output:
Input pairs of a word and a page_no number:
Twinkle
65
Twinkle
55
Little
25
Star
35
^Z
Word and page_no number in alphabetical order:

Little
25
Star
35
Twinkle
55 65
150. Write a C program that reads an expression and evaluates

it.
Input:
4
10-2*3=
8*(8+2-5)=
Sample Output:
Input an expression using +, -, *, / operators:
1+6*8-4/2
47
Sample Output:
25/5-6*7+2
-35
Sample Output:
9+6+(5*2)-5
20
Terms and conditions:

The expression consists of numerical values, operators and
parentheses, and the ends with '='.
The operators includes +, -, *, / where, represents, addition,
subtraction, multiplication and division.
When two operators have the same precedence, they are applied
to left to right.
You may assume that there is no division by zero.
All calculation is performed as integers, and after the decimal
point should be truncated
Length of the expression will not exceed 100.
-1 × 10 9 <= intermediate results of computation <= 10 9
Sample Input:
4
10-2*3=
8*(8+2-5)=
Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
// Function declarations
int addsub();
int muldiv();
int term();
char input[101]; // Declare character array to store user input
int pos = 0; // Initialize a global variable to keep track of the

position in the input string
// Function to parse and evaluate a term (number or expression inside

parentheses)
int term(){
int n = 0;
// Check if the current character is an opening parenthesis
if(input[pos] == '('){
pos++; // Move to the next character
n = addsub(); // Evaluate the expression inside the parentheses
// Check if the next character is a closing parenthesis
if(input[pos] == ')'){
pos++; // Move to the next character (closing parenthesis)
return n; // Return the evaluated result

}
}else{
// If the current character is a digit, parse the number
while('0' <= input[pos] && input[pos] <= '9'){
n = n*10 + (input[pos] - '0'); // Convert characters to integer

and build the number
pos++; // Move to the next character
return n; // Return the parsed number
// Function to handle multiplication and division operations
int muldiv(){
int first,second;
first = term(); // Evaluate the first term
for(;;){
if(input[pos] == '*'){
pos++; // Move to the next character (operator)
second = term(); // Evaluate the second term
first *= second; // Perform multiplication
}else if(input[pos] == '/'){

second = term(); // Evaluate the second term
first /= second; // Perform division
}else{
return first; // If no more operators, return the result
// Function to handle addition and subtraction operations
int addsub(){
int first,second;
first = muldiv(); // Evaluate the first term
for(;;){
if(input[pos] == '+'){
second = muldiv(); // Evaluate the second term
first += second; // Perform addition
}else if(input[pos] == '-'){
second = muldiv(); // Evaluate the second term
first -= second; // Perform subtraction
}else{
return first; // If no more operators, return the result

}
int main(){
int n,i,j;
printf("Input an expression using +, -, *, / operators:\n");
scanf("%s",input); // Read the user input as a string
printf("%d\n",addsub()); // Evaluate the expression and print the

result
return 0; // Indicate successful execution and return 0 to the

operating system
Copy
Sample Output:
1+6*8-4/2
47
Sample Output:
25/5-6*7+2
-35
Sample Output:
9+6+(5*2)-5
20

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1) How do you construct an increment statement or

2) What is the difference between Call by Value and Call by

3) Some coders debug their programs by placing comment

4) What is the equivalent code of the following statement

printf ("%d\n", a * a);

printf ("%d\n", a * a);

6) What is a sequential access file?

7) What is variable initialization and why is it important?

8 What is spaghetti programming?

9) Differentiate Source Codes from Object Codes

10) In C programming, how do you insert quote characters

11) What is the use of a ‘\0’ character?

12) What is the difference between the = symbol and ==

14) What is a nested loop?

15) Which of the following operators is incorrect and why?

16) Compare and contrast compilers from interpreters.

17) How do you declare a variable that will hold string

18) Can the curly brackets { } be used to enclose a single

20) What is syntax error?

21) What are variables and it what way is it different from

22) How do you access the values within an array?

24) Can two or more operators such as \n and \t be

26) When is the “void” keyword used in a function?

27) What are compound statements?

28) What is the significance of an algorithm to C

29) What is the advantage of an array over individual

30) Write a loop statement that will show the following

for (b=1; b<=a; b++)

32) How do you generate random numbers in C?

33) What could possibly be the problem if a valid function

34) What are comments and how do you insert it in a C

35) What is debugging?

36) What does the && operator do in a program code?

37) In C programming, what command or code can be used

40) What are the different types of control structures in

41) What is || operator and how does it function in a

42) Can the “if” function be used in comparing strings?

43) What are preprocessor directives?

45) Describe the order of precedence with regards to

46) What is wrong with this statement? myName =

47) How do you determine the length of a string value that

48) Is it possible to initialize a variable at the time it was

49) Why is C language being considered a middle level

50) What are the different file extensions involved when

51) What are reserved words?

53) What is FIFO?

54) What are binary trees?

55) Not all reserved words are written in lowercase. TRUE

56) What is the difference between the expression “++a”

58) In C language, the variables NAME, name, and Name

59) What is an endless loop?

60) What is a program flowchart and how does it help in

61) What is wrong with this program statement? void = 10;

62) Is this program statement valid? INT = 10.50;

63) What are actual arguments?

64) What is a newline escape sequence?

65) What is output redirection?

66) What are run-time errors?

68) What are formal parameters?

69) What are control structures?