Unit 3 Dielectrics EE Stream
Unit 3 Dielectrics EE Stream
Unit 3 Dielectrics EE Stream
Objectives
At the end of lesson we shall understand about,
Static dielectric constant.
Types of Polarizations.
Internal or local fields in solids and liquids.
Lorentz field in cubic materials.
Clausius Mossotti equation.
Introduction
electrical insulation between two media (conductors) which are at different potentials.
Eg - Glass, Wax paper, Ceramics, Mica, Porcelain. When a dielectric medium interacts
with an applied electric field, charges are redistributed within its atoms or molecules.
This redistribution alters the shape of an applied electrical field both inside the
dielectric medium and in the region nearby. When two electric charges move through a
dielectric medium, the interaction energies and forces between them are reduced.
Dielectric Constant
Faraday discovered that the capacitance of the condenser increases when the region
between the plates is filled with dielectric. If C 0 is the capacitance of the capacitor
without dielectric and C is the capacitance of the capacitor with dielectric then the
ratio C/C0 gives εr called as relative permittivity or Dielectric constant. Also for a given
isotropic material, the electric flux density is related to the applied field strength by
the equation D = εE, where ε is absolute permittivity. In SI system of units, the relative
space. ε = ε0εr, where ε0 is permittivity of the free space and εr is the relative
Dipole: A dipole is an entity consisting equal number of positive and negative charges
separated by a small distance. A dipole moment is a vector directed from positive field.
-q q
under the action of applied field leading to the development of dipole moment is called
as polarization.
Electrical polarization
already existing dipoles by the application of an electric field on the dielectric material.
The ratio of induced dipole moment to the effective applied electric field is called as
polarizibility.
In dielectrics there are no free electrons, the center of positive charges are centered or
concentrated at the center of the atom and center of negative charges are concentrated
in the electron cloud. When the center of gravity of positive charges coincides with
center gravity of negative charges, then it neutralizes each other; hence their dipole
moment is zero. Such dielectrics are called non-polar dielectrics.
In some other dielectrics like water, center of gravity of positive charges never
coincides with the center of gravity of negative charges even in the presence of applied
field. In such dielectrics, each molecule behaves as if it contains a pair of positive and
negative charges separated by a distance. Hence they have a permanent dipole
moment. They are known as polar dielectrics.
Consider a dielectric material placed between two plates of a parallel plate capacitor as
shown in figure 2.
Let a dc potential be applied between the plates; the atomic dipoles in the material will
align in the electric field. The mean position of electrons will align towards the positive
plate of the capacitor and mean position of positively charged nucleus will align
towards negative plate of capacitor. Inside the material the dipoles formed will align in
such a way that the positively charged particles are attracted towards the negatively
charged particles. In fact, at the surface of dielectric layer, negative charge is formed
near positively charged plate of capacitor; a layer of positive charge is formed adjacent
to the negatively charged plate of capacitor and these charges on the surface of
+
Conducting plate (Metal)
- - - - - - - - -
+ + + + + + + + +
E0
- - - - - - - -
+ + + + + + + +
1. Electronic polarization
2. Ionic polarization
Electronic Polarization
This is the most common type of polarization, which occurs in most of the dielectrics.
electronic because of the dipole moment resulting due to the shift of the electron cloud
relative to the nucleus as shown in Fig 3. This type of polarization is due to the
induced dipole moments. The electrons have very high natural frequencies of the order
e is proportional to E.
Hence, e = αeE
Therefore,
NαeE = o ( r 1) E
αe = o ( r 1) /N
Ionic Polarization
The ionic polarization occurs only in ionic materials like NaCl etc. In this type of
materials, under equilibrium conditions, the cations and anions remain at their mean
equilibrium conditions. When the field is applied, the cations and the anions get
displaced from their mean positions in opposite directions and give rise to a net dipole
moment as shown in Fig 4. As the dipole moment occurs only under an applied
electric field, the ionic polarization is due to the induced dipoles; and also the ions are
heavier than electrons. This type of polarization is a slow process and ionic
The orientation polarization occurs in polar dielectrics in which there are molecules
with a permanent dipole moment. The orientation of these molecules are random due
to their thermal agitation, because of the randomness in orientation, the material has
net zero dipole moment in the absence of electric field. When an electric field is
applied, each dipole undergoes a rotation so as to orient along the direction of the
field, which exerts a torque in them and thus the material itself develop the dielectric
not exist, however the dipole alignment is balanced by thermal agitation and this type
- + - - +
- - +
+
+ + -
+ -
+ - - + - +
+ + -
- qu
+ ote
- + - +
+ - + - from
+ the
Aligned dipoles in electric docu
Fig 5: Randomly oriented permanent dipoles field men
The orientation polarizibility is given by, α0 = µ2/3kT t or
the
The orientation polarization P o is given by, Po = Nµ2E/3kT sum
mary
4 Space Charge Polarization of an
inter
The space charge polarization occurs in multiphase
+ dielectric substances in which estin
g
there is a change of resistivity between different phases when an electric field is
poin
applied at a high temperature. The electric charges get accumulated at the interface t.
You
due to the sudden change in conductivity. This accumulation of charges with opposite
can
posit
ion
the
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polarities at opposite parts in low resistivity phase leads to the development of dipole
+ - + - + -
_ +
+ - + - + -
+ - + - + -
The space charge polarization is not an important factor in most common dielectrics.
The total polarization α of a material is thus given by the sum of electronic, ionic and
orientation polarizations,
Internal Field
When the electric field is applied to a dielectric material either liquid or solid, each
atom in the material develops dipole moment and acts like an electric dipole, since the
atoms either in liquids or solids are surrounded on all sides by polarized atoms, the
internal field at given point inside the material is equal to the electric field created by
the neighboring atoms and the applied field.
“The internal field is defined as the electric field that acts at the site of any given atom
of a solid or liquid. Dielectric field subjected to an external field and is resultant of the
applied field and the field due to all the effects of the surrounding atoms.”
Consider a dielectric material solid or liquid under the action of an electric field of
intensity ‘E’. In a dielectric, imagine an infinite string of similar equidistant atomic
dipoles parallel to the external applied field,
Fig 7: Internal field
The components of the electric field at ‘P’ due to an atomic dipole in polar form
are given by,
μ cosθ μ sin θ
Er Eθ
2π 0 r 3 4π 0 r 3
(1)
Dipole at A1:
i.e., r = d and = 0
μ
Er Eθ 0 (2)
2π 0 d 3
μ
Field at X due to A1: Er+ Eθ =
2π 0 d 3
Dipole at A2:
Since it is situated symmetrically on the other side of X, its field at X will also
be μ
2π 0 d 3
Field at X due to A2: μ (3)
2π 0 d 3
Therefore field at X due to both dipoles A1 and A2
μ
Field at X due to B1 & B2, located at a distance of 2d: E 2
π 0 (2d) 3
E' E1 E2 E3 ....
μ μ μ
....
π 0 (d) 3
π 0 (2d) 3
π 0 (3d) 3
μ 1 1
[1 3 3 ....]
π 0 d 3
2 3
μ 1
π 0 d 3
n
n 1
3
where n = 1, 2, 3,….∞
1
But we know that, the summation of infinite series 3
=1.2
n 1 n
μ
E' = 1.2 (5)
π 0 d 3
The total field at X which is the internal field Ei is the sum of the applied field E and
Ei = E + E' (6)
µ = αeEi (7)
1.2 e Ei
Ei = E +
0 d 3
By rearranging the terms in the above equation we have,
E
Ei =
1 1.2 e
π ε 0d 3 (8)
This is the expression for internal field in case of one–dimensional array of atoms in a
In the 3D if it is a cubic lattice then, γ =1/3 and the internal field is named as Lorentz
Field given by
E Lorentz = E + P/3ε0
The above equation is known as Lorentz relation. One of the important results that
CLAUSIUS-MOSSOTTI RELATION
Consider an element solid dielectric of a dielectric constant εr. If N is the
number of atoms/unit volume of the material, is the atomic dipole moment,
then we have,
Dipole moment,
e = αeEi ………………….. (1)
Polarization of the medium is given by,
P = NαeEi …………………… (2)
Therefore,
Ei = P/Nαe …………………….. (3)
In a 3D dielectric material,
P P P ……………….. (7)
N 0 ( r 1) 0
1 1 1 1
N 0 ( r 1) 3
0 r 2
N 3( r 1)
Rearranging we get,
r 1 N
r 2 3 0 (8)
Dielectric losses:
It is the loss of energy in the form of heat by a dielectric medium due to the internal
friction that is developed as consequences of switching action of molecular dipoles
under certain ac conditions.
Dipolar Relaxation:
Relaxation time is the time required for the dipole to reach the equilibrium orientation
from the disturbed position in alternating field conditions.
Summary:
1. Dielectrics are insulators and posses high electrical resistivity. Dielectric constant
4. The total polarization of materials is sum of the electronic, ionic and orientation
polarizations.
1. Insulating Materials
a. The electrically insulating material should have high resistivity to reduce the
leakage current and high dielectric strength to enable to withstand higher
voltage without being breaking down.
d. Polypropylene films and tissue paper impregnating with dielectrol-II are used
in power capacitor applications.
c. In electrical transformers, mineral oils are used as a liquid dielectric and they
assist in the cooling process. Castor oil is used in high-voltage applications.
Solved examples:
Solution:
Ε =500 V/m
P=?
P = ε0(εr -1)E
2. A parallel plate capacitor of area 650 mm2 and a plate separation of 4mm have a
charge of 2 * 10-10 C on it. What should be the resultant voltage across the capacitor
when a material of dielectric constant 3.5 is introduced between the plates?
Solution:
Given
We know that,
C = ε0εrA/d
Also, C = Q/V
Q/V = = ε0εrA/d
Or V= Qd/ε0 εr A
= 39.73V
3. The dielectric constant of sulphur is 3.4. Assuming a cubic lattice for its
structure calculate the electronic polarizability of sulphur.
Solution:
Since the crystal structure of sulphur is cubic we can apply Clausius –Mossotti
equation, r 1 N
2 3
r 0
1 3 0
Hence αe = r
r 2 N
Now, N the number of atoms/unit volume can be written as,
N A * 10 3 * D
N
atomicnumb er
6.025 * 10 26 * 2.07 * 10 3
N
32.07
N = 3.89*1028 /m3
1 3 0
Hence αe = r
r 2 N
12
αe = 3.4 1 3 * 8.854 * 10
3.4 2 3.89 * 10
28
Solution:
αe = 7* 10-40 Fm2
No of atoms/m3 =3*1028
Since the internal field is Lorentz field, we can apply Clausius –Mossotti
equation,
r 1 N
r 2 3 0
r 1 3 * 10 28 * 7 * 10 40
12
r 2 3 * 8.854 * 10
= 0.7906
r -1 = 0.7906 r + 1.5812
r (1-0.7906) = 2.5812
r =2.5812/0.2094
r = 12.33