Allen Test Class 11 4

PAPER CODE 2 0 0 1 C J A1 0 1 6 2 1 0 0 4
CLASSROOM CONTACT PROGRAMME

(ACADEMIC SESSION 2020-2021)
ADVANCE NURTURE COURSE : PHASE-I REVIEW TEST # 01 (Pattern : JEE-Advanced)

TARGET : JEE (Main + Advanced) 2023 Date : 01- 03- 2021
Time : 3 Hours Maximum Marks : 186
Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.
INSTRUCTIONS
A. General :
1. The booklet is your Question Paper. Do not break the seal of this booklet before being instructed to do
so by the invigilator.
DO NOT BREAK THE SEALS WITHOUT BEING INSTRUCTED TO DO SO BY THE INVIGILATOR

2. The question paper CODE is printed on the bottom page corner of this sheet.
3. Blank spaces and blank pages are provided in the question paper for your rough work. No additional sheets
will be provided for rough work.
4. Blank papers, clipboards, log tables, slide rules, calculators, cameras, cellular phones, pagers and electronic
gadgets are NOT allowed inside the examination hall.
5. Write your name and Form number in the space provided on the back cover of this booklet.
6. The answer sheet, a machine-readable Optical Response Sheet (ORS), is provided separately.
7. DO NOT TAMPER WITH/MUTILATE THE ORS OR THE BOOKLET.
8. On breaking the seal of the booklet check that it contains 20 pages and all the 18 questions in each subject
and corresponding answer choices are legible. Read carefully the instructions printed at the beginning of
each section.
B. Filling the ORS :
9. A candidate has to write his / her answers in the ORS sheet by darkening the appropriate bubble with the
help of Black ball point pen as the correct answer(s) of the question attempted.
10. Write all information and sign in the box provied on part of the ORS (Page No. 1).
C. Question Paper Formate :
The question paper consists of 3 parts (Physics, Chemistry and Mathematics).
11. Section- I :
(i) Contains 5 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of
which ONLY ONE is correct.
(ii) Contains 8 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of
which ONE or MORE are correct.
12. Section-II contains 5 questions The answer to which is a Numerical Value. For each question, enter
the correct numerical value to answer two decimal place, If the numerical value has more than two decimal
places, truncate/round-off the value to TWO decimal places.
Please read the last page of this booklet for rest of the instructions
CDG/2001CJA101621004
Target : JEE (Main + Advanced) 2022/01-03-2021
SOME USEFUL CONSTANTS

A to m ic No . H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16, Cl = 17,
Br = 35, Xe = 54, Ce = 58,
At o m ic m a sse s : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,
Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,
Xe = 131, Ba=137, Ce = 140,
Boltzmann constant k = 1.38 × 10–23 JK–1

1
Coulomb's law constant = 9 ×10 9
4 0
Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2

Speed of light in vacuum c = 3 × 108 ms–1
Stefan–Boltzmann constant = 5.67 × 10–8 Wm–2–K–4
Wien's displacement law constant b = 2.89 × 10–3 m–K
Permeability of vacuum µ0 = 4 × 10–7 NA–2
1
Permittivity of vacuum = 2
0c
0
Planck constant h = 6.63 × 10–34 J–s
2/20 CDG/2001CJA101621004
Advance Nurture Course/Phase-I/01-03-2021
HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS
PHYSICS
BEWARE OF NEGATIVE MARKING
PART-I : PHYSICS
SECTION–I(i) : (Maximum Marks : 15)
This section contains FIVE questions.
Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is correct.
For each question, darken the bubble corresponding to the correct option in the ORS.
For each question, marks will be awarded in one of the following categories :
Full Marks : +3 If only the bubble corresponding to the correct option is darkened.
Zero Marks : 0 If none of the bubbles is darkened.
Negative Marks : –1 In all other cases.
2
1. Velocity v = 3t2 – then acceleration is :-
t
2 2 2
(A) 6t + 2 (B) 6t – 2 (C) 6t + (D) None of these
t t t
Ft 3
I
Displacements S = G 3 JK
4t m, here ‘t’ is time in seconds, let motion starts from t=0, calculate
2.
H
displacement when velocity is zero
16 8
(A) 0 (B) – m. (C) 8 m (D) – m.
3 3
Space for Rough Work
CDG/2001CJA101621004 3/20
3. cos(7x 3)dx
PHYSICS
1
(A) –7 sin(7x – 3) + C (B) + sin(7x – 3) + C
3
1 1
(C) – sin(7x – 3) + C (D) sin(7x – 3) + C
7 7
4. If P 2iˆ 7ˆj 10kˆ and Q ˆi 2 ˆj 3kˆ then choose a vector R such that when it is added to resultant
of P and Q , it gives net resultant of an unit vector along x-axis :-
(A) 2iˆ 9ˆj 7kˆ (B) 2iˆ 9ˆj 7kˆ (C) 2iˆ 9ˆj 7kˆ (D) 2iˆ 7ˆj 9kˆ
5. If a vector 2iˆ 3ˆj 8kˆ is perpendicular to the vector 4ˆj 4iˆ kˆ . Then the value of is :-
1 1
(A) – 1 (B) (C) – (D) 1
2 2
CDG/2001CJA101621004
4/20
SECTION-I (ii) : (Maximum Marks: 32)
PHYSICS
This section contains EIGHT questions.
Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of these
four option(s) is (are) correct option(s).
For each question, choose the correct option(s) to answer the question.
Answer to each question will be evaluated according to the following marking scheme:
Full Marks : +4 If only (all) the correct option(s) is (are) chosen.
Partial Marks : +3 If all the four options are correct but ONLY three options are chosen.
Partial Marks : +2 If three or more options are correct but ONLY two options are chosen,
both of which are correct options.
Partial Marks : +1 If two or more options are correct but ONLY one option is chosen
and it is a correct option.
Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).
For Example : If first, third and fourth are the ONLY three correct options for a question with second
option being an incorrect option; selecting only all the three correct options will result in +4 marks.
Selecting only two of the three correct options (e.g. the first and fourth options), without selecting
any incorrect option (second option in this case), will result in +2 marks. Selecting only one of the
three correct options (either first or third or fourth option), without selecting any incorrect option (second
option in this case), will result in +1 marks. Selecting any incorrect option(s) (second option in this
case), with or without selection of any correct option(s) will result in –1 marks.
7. If y = 2x3 – 12x2 + 36 then for minimum value of y :-
(A) x = 0 (B) x = 4 (C) x = 1 (D) None
8. Consider A 2iˆ 3jˆ 4kˆ and B iˆ ˆj kˆ . Choose CORRECT options.
(A) A B 3iˆ 2ˆj 5kˆ (B) A·B 3 (C) A·B 9 (D) B 3

CDG/2001CJA101621004 5/20
t2
PHYSICS
9. Area under the graph of velocity-time gives displacement in time interval as S Vdt . Choose COR-
t1
RECT options for given velocity-time graph.

velocity
10m/s
8 time
4 (in sec)
–10
8 4
(A) V dt is 20 (B) V dt is 10 m
.0 .0
4 8
(C) V dt is 20 m (D) V dt is 0
.0 .0
10. A particle position is given as x = 6t2 – 12t. Choose CORRECT options. Where t is in seconds and x
is in meter.
(A) Particle stop at t = 2s. (B) Particle stop at t = 1s.
(C) Acceleration of particle is 12t (D) Acceleration of particle is 12 m/s2
CDG/2001CJA101621004
6/20
11. The angle between two vectors a & b is and the magnitude of b is half of magnitude of a . If
PHYSICS
c a b & | a | a then choose the CORRECT statements
a 5 a 3
(A) if c = then will be 90° (B) if c = then will be 60°
2 2
a 3a
(C) if c = then will be 45° (D) if c = then will be 180°
2 2
12. A particle is moving along x-axis. Position of particle is given by x = 2t2. Here x is measured in meters
and time t is measured is seconds.
(A) Acceleration of particle is 4 m/s2 (B) Acceleration of particle is 2 m/s2
(C) Initial velocity of particle is Zero (D) Initial velocity of particle is 2 m/s2
4
13. For a straight line y x 4 . Choose CORRECT alternative(s)
3
dy 4 dy 3
(A) (B)
dx 3 dx 4
(C) when y = 0, x= 3 (D) when y = 0, x = 4

14. For the function y 4x x 2 4, which of the following is true :
(A) It has a minima at x = 2 (B) It has a maxima at x = 2
(C) Minimum value of y is 3 (D) Maximum value of y is 8
CDG/2001CJA101621004 7/20
SECTION – II : (Maximum Marks : 15)
PHYSICS
This section contains FIVE(05) questions. The answer to each question is a NUMERICAL VALUE.
For each question, enter the correct numerical value of the answer using the mouse and the on-screen
virtual numeric keypad in the place designated to enter the answer. If the numerical value has more
than two decimal places, truncate/round-off the value to Two decimal places.
Full Marks : +3 If ONLY the correct numerical value is entered.
Zero Marks : 0 In all other cases.
1. If displacement s = (t3–3t) then velocity at t = 2s is :-
2
2. The value of x 3 dx is :-
1
3. The farm house shown in figure has rectangular shape and has sides parallel to the chosen x and y axes.
The position vector of corner A is 125 m at 53° and corner C is 100 m at 37° from x axis. The length
of the fencing required in meter is
y
A B
D C
53°
37° x
4. If â bˆ 3 then angle between â & b̂ is , find Z.

Z
5. The position vectors of an object at two different times are given by r1 3iˆ 5 ˆj m and r2 7iˆ 8 ˆj m.
Find the magnitude of displacement (in m).

CDG/2001CJA101621004
8/20
CHEMISTRY
PART-II : CHEMISTRY
1. If 100ml of H2O2 solution gives 1135 mL of O2 at STP, what is molarity of this H2O2 solution ?
(A) 0.5M (B) 1M (C) 1.5M (D) 0.1M
2. 250 cm3 of solution is made by dissolving 0.63g of oxalic acid (H2C2O4.2H2O) into water. The molarity
(M) of solution is :
(A) 0.02 M (B) 0.01M (C) 0.2M (D) 0.1M
3. 80gm of SOx gas occupies 14 litre at 2atm & 273K. The value of x is :
(Use R = 0.0821L-atm/K-Mole)
(A) 3 (B) 2 (C) 1 (D) None
4. A given initial mass of KClO3 on 50% decomposition produces 67.2 litre oxygen at 0ºC and 1 atm.
The other product of decomposition is KCl. The initial mass of KClO3 (in gm) taken is.
[Atomic weight of K = 39, Cl = 35.5]
(A) 245 (B) 122.5 (C) 490 (D) 735
5. A 120g of oleum sample contains 60g free SO3. What is % labelling of this sample ?
(A 106% (B) 111.25% (C) 104% (D) 109.5 %
CDG/2001CJA101621004 9/20
CHEMISTRY

Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of these four
option(s) is (are) correct option(s).
6. In the reaction, 2Al(s) + 6HCl(aq) 2Al3+(aq) + 6Cl¯(aq) + 3H2(g).
(1) 6L HCl(aq) is consumed for every 3L H2(g) produced
(2) 33.6 L H2(g) is produced regardless of temperature and pressure for every mole Al that reacts
(3) 67.2 L H2(g) at 0ºC and 1 atm is produced for every mole Al that reacts
(4) 11.2 L H2(g) at 0ºC and 1 atm is produced for every mole HCl(aq) consumed
7. X+Y X3Y4
Above reaction is carried out by taking 6 moles each of X and Y respectively then :
(A) X is the limiting reagent (B) 1.5 moles of X3Y4 is formed
(C) 1.5 moles of excess reagent is left behind (D) 75% of excess reagent reacted
CDG/2001CJA101621004
10/20
8. In 2.6 kg of FeSO4 . 6H2O [At. wt. of Fe = 56, S = 32, atomic no of S = 16]
CHEMISTRY
(A) Number of atoms of O are 100 × NA (B) Moles of H-atoms are 120 × NA
2–
(C) Number of Molecules of water are 60 × NA(D) Moles of e– present in SO4 are 500
9. 400 ml 0.1 M BaCl2 is mixed with 600 ml 0.1 M H2SO4 to form product according to following reaction
BaCl2(aq.) + H2SO4(aq.) BaSO4(s) + 2HCl(aq.)
Select the correct option(s) after reaction is completed :
(A) Molarity of Ba+2 ions in final solution is 0.04 M
(B) Molarity of SO42– ions in final solution is 0.02 M
(C) Molarity of H+ ions do not change on mixing
(D) Final molarity of H+ ion in solution is 0.12 M
10. Which of the following concentration terms are dependent on temperature
(A) molarity (B) Molality (C) % mass by volume (D) Mole fraction
CDG/2001CJA101621004 11/20
11. 1.4 g of a hydrocarbon gave 4.4g of CO2 and 1.8g of H2O on complete combustion. Molecular
CHEMISTRY
mass of this compound is 28. Select the correct statement(s) about this :
(A) Its empirical formula mass is 14. (B) Its molecular formula contains total 5 atoms
(C) Its molecular formula is C2H4 (D) Its empirical formula is CH4
12. A sample of MgSO4 is found to contain 8 × 1020 atoms of O.
(A) Mass of S present in the sample is 1.06 × 10–2 g
(B) Number of Mg atoms in the sample is 8 × 1020
(C) Total number of atoms in the sample is 1.2 × 1021
(D) Mass of Mg present in the sample is 1.06 × 10–6 g
13. Molarity of solute A (mol.wt. = 60) in an aqueous solution is 2M.
(Density of aqueous solution is 1.2 gm/m .)
(A) Molality of A in the solution is 1.85m (B) Molality of A in the solution is 1m
(C) Mole fraction of A in the solution is 1 (D) wt % of A in the solution is 10 %
CDG/2001CJA101621004
12/20
CHEMISTRY
This section contains FIVE (05) questions. The answer to each question is a NUMERICAL VALUE.
1. 340 gm mixture of N2 and H2 is taken in stoichiometric ratio and gives ammonia . The produced mass
of ammonia (in kg) is :
2. 27 gm of Al react with excess of oxygen to give 4.59 gm of Al2O3. Calculate percentage yield of reaction.
[Atomic weight of Al = 27, O = 16]
CDG/2001CJA101621004 13/20
3. Calculate moles of electron in 1900 mg of PO43– ion.

CHEMISTRY
[Atomic number of P = 15], [Atomic weight of P = 31, O = 16]

4. 5 mole of C and 4 moles of O2 are reacted completely to form CO and CO2 total moles of CO2 and
CO is
5. Mass of 10 moles of CaCO3 is 6.022× 10x amu
CDG/2001CJA101621004
14/20
MATHEMATICS
PART-III : MATHEMATICS
(x 2 1)2 (x 2 5x 6)(x 4) 2
1. The complete set of values of ‘x’ for which 0
(x 7)3 (x 1)
(A) (3, 7) (B) (–1, 5) (C) (–1, 0) (D) (–1, 2) (3, 7)
2 9 3
2. The value of sin 120 cos2 180 sin 2 tan is
4 4
3 5 1 1
(A) (B) (C) (D)
4 4 4 4
3. The value of cos 3 x tan 8 x cos ec x

, wherever exist is equal to
3
sin 8 x sec x
2
(A) sinx (B) cosx (C) 1 (D) –1

4. The value of sin 2 1 sin 2 2 sin 2 3 .................... sin 2 90 is equal to
89 91
(A) 45 (B) 88 (C) (D)
2 2
5. If (1 tan1 )(1 tan 2 )(1 tan 3 )...........(1 tan 44 )(1 tan 45 ) 2k then k is equal to
(A) 22 (B) 23 (C) 44 (D) 45
CDG/2001CJA101621004 15/20
MATHEMATICS

Each question has FOUR options for correct answer(s). ONE OR MORE THAN ONE of these
four option(s) is (are) correct option(s).
3
6. If cosA = , where A lies in the 4th quadrant then which of the following is true?
5
A 1 A 1 24 7
(A) sin = (B) tan = (C) tan2A = (D) cos2A =
2 5 2 2 7 25
sin 2x sin 4x sin 6x

7. The value of at x , is greater than
cos 2x cos 4x cos6x 16
3
(A) –1 (B) 0 (C) 1 (D)
2
CDG/2001CJA101621004
16/20
MATHEMATICS
sin 2 48 cos 2 12 a
8. The value of expression (a, b N & co-prime), then
cos12 cos 48 sin18 b
(A) a = 2 (B) b = 1 (C) a = 1 (D) b = 2

9. If tan 1º tan 2º .............. tan 89º = x2 – 8, then the value of x can be
(A) –1 (B) 1 (C) –3 (D) 3
(x 2 – 3x 2) x – 5
10. Values of x satisfying the inequality > 0 can be
(3x–1 –1)
(A) (6, ) (B) (8, ) (C) [8, ) (D) (– , 1)
11. The number of different integral value(s) of x , satisfying 3 2 x 2 is
(A) 0 (B) 1 (C) 2 (D) 3

12. The value of x which satisfy the equation |x–1| = 2 is/are
(A) 3 (B) –1 (C) 2 (D) –3
13. Which of the following is INCORRECT ?
1 13 1 15
(A) sin765° = – (B) cosec(–1410°) = 2 (C) tan = (D) cot =–1
2 3 3 4
CDG/2001CJA101621004 17/20
MATHEMATICS

This section contains FIVE (05) questions. The answer to each question is a NUMERICAL VALUE.
1. The value of 1024[(cos5 ·cos55 ·cos 65 )2 (sin 5 ·sin 55 ·sin 65 )2 ]2 is
2. The value of tan 200º (cot 10º – tan 10º ) is
4 3
3. The expression, 3 sin sin 4 (3 ) – 2 sin 6 sin 6 (5 ) is equal to
2 2
4. The number of real roots of the equation, (x 1)2 + (x 2)2 + (x 3)2 = 0 is :
2 135 45 45
5. The value of 4 sin sin 2 cos is
4 4 2
CDG/2001CJA101621004
18/20
CDG/2001CJA101621004 19/20
D. Marking scheme :
13. For each question in Section-I (i), you will be awarded 3 marks if you darken the bubble corresponding to the correct
answer and zero mark if no bubbles are darkened.In all other cases minus one (–1) mark will be awarded.
14. For each question in Section-I (ii), you will be awarded 4 marks if you darken the bubble corresponding to the correct
answer and zero mark if no bubbles are darkened.In all other cases minus one (–1) mark will be awarded.
Partial Marks : +1 For darkening a bubble corresponding to each correct option, Provided NO incorrect option
is darkened.
For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three will result in
+4 marks; darkening only (A) and (D) will result in +2 marks; and darkening (A) and (B) will result in –1 marks,
as a wrong option is also darkened.
15. For each question in Section-II, you will be awarded 3 marks if you darken all the bubble(s) corresponding to only
the correct answer(s) and zero mark if no bubbles are darkened. No negative marks will be awarded for incorrect
answers in this section.
16. Take g = 10 m/s2 unless otherwise stated.
Appropriate w ay of darkening the bubble for your answ er to be evaluated

a The one and the only acceptable
a Part darkening
a a Darkening the rim
a Cancelling after darkening
a Erasing after darkening

Figure-1 : Cor rect w ay of bubbling for valid answ er and a few examplex of invalid answ ers
Any other form of partial marking such as ticking or crossing the bubble will be invalid
1 4 2 0 0 0 2 2
0 0 0 0 0
1 1 1 1 1 1 1
2 2 2 2 2
3 3 3 3 3 3 3 3
4 4 4 4 4 4 4
5 5 5 5 5 5 5 5
6 6 6 6 6 6 6 6
7 7 7 7 7 7 7 7
8 8 8 8 8 8 8 8
9 9 9 9 9 9 9 9
Figure-2 : Correct Way of Bubbling your Form Number on the ORS. (Example Form Numebr : 14200022)
Name of the Candidate Form Number
I have read all the instructions and shall abide by them. I have verified all the information filled in by the Candidate.
Signature of the Candidate Signature of the Invigilator
Corporate Office : CAREER INSTITUTE, “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005
+91-744-2436001 +91-744-2435003 info@allen.ac.in
20/20 Your Hard Work Leads to Strong Foundation CDG/2001CJA101621004

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PAPER CODE 2 0 0 1 C J A1 0 1 6 2 1 0 0 4

CLASSROOM CONTACT PROGRAMME

ADVANCE NURTURE COURSE : PHASE-I REVIEW TEST # 01 (Pattern : JEE-Advanced)

Time : 3 Hours Maximum Marks : 186

DO NOT BREAK THE SEALS WITHOUT BEING INSTRUCTED TO DO SO BY THE INVIGILATOR

7. DO NOT TAMPER WITH/MUTILATE THE ORS OR THE BOOKLET.

B. Filling the ORS :

C. Question Paper Formate :

The question paper consists of 3 parts (Physics, Chemistry and Mathematics).

SOME USEFUL CONSTANTS

Boltzmann constant k = 1.38 × 10–23 JK–1

Universal gravitational constant G = 6.67259 × 10–11 N–m2 kg–2

Planck constant h = 6.63 × 10–34 J–s

(A) A B 3iˆ 2ˆj 5kˆ (B) A·B 3 (C) A·B 9 (D) B 3

RECT options for given velocity-time graph.

(C) when y = 0, x= 3 (D) when y = 0, x = 4

4. If â bˆ 3 then angle between â & b̂ is , find Z.

Find the magnitude of displacement (in m).

This section contains EIGHT questions.

3. Calculate moles of electron in 1900 mg of PO43– ion.

[Atomic number of P = 15], [Atomic weight of P = 31, O = 16]

Space for Rough Work

3. The value of cos 3 x tan 8 x cos ec x

(A) sinx (B) cosx (C) 1 (D) –1

Space for Rough Work

SECTION-I (ii) : (Maximum Marks: 32)

sin 2x sin 4x sin 6x

(A) a = 2 (B) b = 1 (C) a = 1 (D) b = 2

(A) (6, ) (B) (8, ) (C) [8, ) (D) (– , 1)

11. The number of different integral value(s) of x , satisfying 3 2 x 2 is

(A) 0 (B) 1 (C) 2 (D) 3

SECTION – II : (Maximum Marks : 15)

4. The number of real roots of the equation, (x 1)2 + (x 2)2 + (x 3)2 = 0 is :

16. Take g = 10 m/s2 unless otherwise stated.

Appropriate w ay of darkening the bubble for your answ er to be evaluated

a a Darkening the rim

a Cancelling after darkening

a Erasing after darkening

Name of the Candidate Form Number

Signature of the Candidate Signature of the Invigilator

20/20 Your Hard Work Leads to Strong Foundation CDG/2001CJA101621004

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