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4 Stats Assignment

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Presented By:

Alishba Imtaiz ( 006 )

Awais Sohail (008)

Raja Nadeem Asghar Kayani ( 032 )

Presented To:
Mam Sara Siddique

Subject:
Statistics

Class:
BBA 3 A
SBE 13th Ed ( Anderson ), Chapter 6, Case Problem: Specialty Toys:

Sol:
1. Let X = the demand for the toy.

X follows normal distribution with mean μ = 20000 and standard deviation σ.

P (10000 < X < 30000) = 0.95

P ((10000-20000)/σ < (X-20000)/σ < (30000-20000)/σ) = 0.95

From tables of areas under the standard normal curve (30000-20000)/σ = 1.96

σ = (30000-20000)/1.96 =10000/1.96 = 5102


2. Probability of stock out with an order of K units is P(X > K) = P (Z > (K-20000)/5102),

where Z is distributed as standard normal and z will be greater than K must be 1.000 –

cumulative probability.

Order (K) (K-20000)/5102 P(X > K): 1- cumulative


probability

15,000 -0.98001 0.836458876

18,000 -0.392 0.652472052

24,000 0.784006 0.216518215

28,000 1.568013 0.058439102

3. 15,000 units at a cost of $16/unit = $240,000 invested.


a. Worst case #sold: 10000 x 24 + 5000 x 5 = $265,000
Profit: $25,000
b. Most likely #sold: 15000 x 24 = $360,000 income
Profit: $120,000
c. Best case #sold: 15000 x 24 = $360,000 income
Profit: $120,000
18,000 units at a cost of $16/unit = $288,000 invested
a. Worst case #sold: 10000 x 24 + 5000 x 5 = $265,000 income

Loss of -$23,000

b. Most likely #sold: 18000 x 24 = $432,000 income

Profit: $144,000

c. Best case #sold: 18000 x 24 = $432,000 income


Profit: $144,000
24,000 units at a cost of $16/unit = $384,000 invested
a. Worst case #sold: 10000 x 24 + 5000 x 5 = $265,000 income

Loss of $119,000

b. Most likely #sold: 20000 x 24 + 4000 x 5 = $500,000 income

Profit: $116,000

c. Best case #sold: 24000 x 24 = $576,000 income

Profit: $192,000

Order Scenario 10000 Scenario 20000 Scenario 30000

15000 8*10000-11*5000 8*15000=120000 8*15000 =


=25000 120000
18000 8*10000-11*8000 8*18000 = 144000 8*18000 =
= -8000 144000
24000 8*10000-11*14000 8*20000-11*4000 8*24000 =
= -74000 =116000 192000
28000 8*10000-11*18000 8*2000-11*8000 8*28000 =
= -118000 =72000 224000

Cost of sales per unit $24 - Cost of goods sold $16 = profit per unit 8

Cost of sales per unit $24 – Cost of surplus inventory $5 – profit per $8 = coverage $11

4. The order quantity to meet 70% demand is found by solving

P(X < K) =0.70

P (Z < (K-20000)/5102) = 0.70

(K-20000)/5102 = 0.5244

K = 20000 + 5102 * 0.5244 = 20000 + 2675 = 22,675 units to be ordered.


5. The best case in which sales equals 30,000 units.

Expected sales price = 22,675 * 24 = $544,200

The suggested order quantities is 22,675, so the cost price is

22,675*16 = $362,800

Sales is expected to be 30,000 so there is no stock out and

The projected profit = sales price – cost price

544,200 – 362,800 = $181,400

The most likely case in which sales equal 20,000 units

Expected sale price = 544,200

Cost is 22,675 * 16 = 362,800

There is no stock out

Projected profit = 544,200 – 362,800 = $181,400

Worst case in which sales equal 10,000 units

Sell for $24 based on cost of $16 per unit

Expected sales = 10,000 * 24 = $240,000

Cost price is 22,675 * 16 = $362,800

Stock out is 22, 675 – 10,000 = 12,675 units.

These will be sold at $5 per unit = 12,675 *5 = $63,375

Total sale price = 240,000 + 63,375 = $303,375

Projected profit = 362,800 – 303,375 = $59,425

The best recommendation would be to order between 15,000 to 18,000 because even in the worst
scenario, if the order quantity is 15,000 there will be profit of about $89,137.50 which puts you
at the mid-range mark.

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