Lipschitz Continuity and Semiconc
Lipschitz Continuity and Semiconc
Lipschitz Continuity and Semiconc
17 (2010), 715–728
c 2010 Springer Basel AG
1021-9722/10/060715-14
published online June 5, 2010 Nonlinear Differential Equations
DOI 10.1007/s00030-010-0078-x and Applications NoDEA
1. Introduction
We consider the following partial differential equation
⎧
⎨−vt + H(t, x, v, − ∂v , − ∂ 22 v ) = 0, (t, x) ∈ [0, T ) × Rn ,
∂x ∂ x
(1.1)
⎩v(T, x) = h(x), x ∈ Rn ,
where
H(t, x, u, p, A)
1
= sup tr(Aσ(t, x, u)σ T (t, x, u)) + p, b(t, x, u) − f (t, x, u) (1.2)
u∈U 2
for any (t, x, p, A) ∈ [0, T ] × Rn × Rn × L(Rn , Rn ). It is well-known that,
under continuity and boundedness assumptions on b, σ, f and h, equation (1.1)
has a unique continuous viscosity solution of at most polynomial growth v :
[0, T ] × Rn → R (see, for instance, [2]). The main goal of the present article is
to prove the local Lipschitz continuity and semiconcavity of the solution. We
recall the following:
716 R. Buckdahn et al. NoDEA
Remark 2.1. In fact, (2.3) is well-posed even when functions b, σ and f have
linear growth with respect to x—instead of being bounded as assumed in (S2).
The results of our paper remain valid under linear growth conditions but, for
simplicity, here we prefer to restrict the analysis to the bounded case.
3. Lipschitz continuity
The fact that, under assumption (S1) and (S2), the solution to (1.1) ought
to be jointly Lipschitz continuous in (t, x) is somewhat expected in the litera-
ture, see, e.g., [4,6]. On the other hand, some care is needed to give a precise
Lipschitz regularity result for V , as our next example shows.
Example 3.1. We consider the following one dimensional example m = n = 1
without control where b = 0, σ = 1, f = 0 are constant √ and h(x) = |x|, for
any x ∈ R. Then it can be easily checked that V (s, 0) = T − s and so V fails
to be Lipschitz with respect to s at s = T .
The theorem below completes the analysis of the Lipschitz regularity
of V .
Theorem 3.2. Under assumptions (S1) and (S2) the value function V is
Lipschitz continuous in [0, T − δ) × Rn , ∀δ > 0.
We give a complete proof of the above theorem using a technique that is
similar—yet simpler—to the one that will be needed later for semiconcavity.
Proof. We remark that K, during the proof, denotes a generic constant, that
may differ at different places.
Let us fix δ > 0, and let (s1 , y1 ) and (s0 , y0 ) ∈ [0, T ) × Rn be such that
min{T − s1 , T − s0 } > δ. (3.6)
We have to show that
V (s1 , y1 ) − V (s0 , y0 ) ≤ C(|s1 − s0 | + |y1 − y0 |) (3.7)
for some constant C ≥ 0. For any > 0, there exists u0 (·) ∈ U w [s0 , T ] such
that J(s0 , y0 ; u0 ) < V (s0 , y0 ) + . Let x0 (·) be the solution of
dx0 (t) = b(t, x0 (t), u0 (t))dt + σ(t, x0 (t), u0 (t))dW (t), t ∈ [s0 , T ],
(3.8)
x0 (s0 ) = y0 .
Now, let us consider the change of time
T (s0 − s1 ) + (T − s0 )t
τ : [s1 , T ] → [s0 , T ], τ (t) = (3.9)
T − s1
Observe that τ̇ (t) is constant, more precisely
T − s0
τ̇ (t) = . (3.10)
T − s1
Vol. 17 (2010) Lipschitz continuity and semiconcavity properties 719
By the change of variable r = τ (t) in the first integral above we obtain, setting
x̃1 (r) = x1 (τ −1 (r)),
V (s1 , y1 ) − V (s0 , y0 ) −
T
1
≤E f (τ −1 (r), x̃1 (r), u0 (r)) − f (r, x0 (r), u0 (r)) dr
s0 τ̇
+ E{h(x1 (T )) − h(x0 (T ))}
Recalling that f (t, x, u) and h(x) are bounded and Lipschitz, we have
V (s1 , y1 ) − V (s0 , y0 ) −
T
1
≤E f (τ −1 (r), x̃1 (r), u0 (r)) − f (τ −1 (r), x̃1 (r), u0 (r)) dr
s0 τ̇
T
+E f (τ −1 (r), x̃1 (r), u0 (r)) − f (r, x0 (r), u0 (r)) dr
s0
+ K E{|x1 (T ) − x0 (T )|}
So, the conclusion (3.7) will follow from the estimates
1 − 1 ≤ K|s1 − s0 | (3.12)
τ̇
|τ −1 (r) − r|dr ≤ K|s1 − s0 | (3.13)
T
E |x̃1 (r) − x0 (r)|dr ≤ K(|y1 − y0 | + |s1 − s0 |) (3.14)
s0
720 R. Buckdahn et al. NoDEA
and
E{|x1 (T ) − x0 (T )|} ≤ K(|y1 − y0 | + |s1 − s0 |). (3.15)
4. Semiconcavity
Theorem 4.1. In addition to (S1) and (S2), assume:
(S3)(i) h is semiconcave in Rn and f (·, ·, u) is semiconcave in [0, T ] × Rn
uniformly in u ∈ U ;
(S3)(ii) b and σ are continuously differentiable in (t, x) with derivatives bt,x
and σt,x satisfying, for some constant ≥ 0,
|bt,x (t, x, u) − bt,x (s, y, u)| + |σt,x (t, x, u) − σt,x (s, y, u)|
≤ (|x − y| + |t − s|) (4.17)
n
for all t, s ∈ [0, T ], all x, y ∈ R , and all u ∈ U .
Then the value function V is semiconcave in [0, T − δ) × Rn for every δ > 0
Proof. Once again K will denote a generic constant, that may differ from line
to line. Let δ > 0 be fixed and let (s1 , y1 ), (s0 , y0 ) ∈ [0, T ) × Rn be such that
min{T − s1 , T − s0 } > δ.
We only have to show that, for some constant C ≥ 0 and all λ ∈ [0, 1],
λV (s1 , y1 ) + (1 − λ)V (s0 , y0 ) − V (sλ , yλ )
≤ Cλ(1 − λ) |s1 − s0 |2 + |y1 − y0 |2 (4.18)
.
where (sλ , yλ ) = λ(s1 , y1 ) + (1 − λ)(s0 , y0 ). Let λ ∈ [0, 1] be fixed.
For any > 0, there exists a control uλ, (·) = uλ (·) ∈ U w [s0 , T ] such that
J(sλ , yλ , uλ ) < V (sλ , yλ ) + .
Let xλ (·) be the solution of the Cauchy problem
dxλ (t) = b(t, xλ (t), uλ (t))dt + σ(t, xλ (t), uλ (t))dW (t), t ∈ [sλ , T ],
(4.19)
xλ (sλ ) = yλ .
Now, for i = 0, 1 consider the time changes
T (sλ − si ) + (T − sλ )t
τi : [si , T ] → [sλ , T ], τi (t) = (4.20)
T − si
and note that τ˙i (t) is constant, with τ˙i (t) = (T − sλ )/(T − si ), t ∈ [si , T ].
Finally, define ui (t) = uλ (τi (t)) and let xi (t) be the solution of the problem
dxi (t) = b(t, xi (t), ui (t))dt + σ(t, xi (t), ui (t))dWi (t), t ∈ [si , T ],
(4.21)
xi (si ) = yi ,
where Wi (t) = 1/τ˙i W (τi (t)).
722 R. Buckdahn et al. NoDEA
In the first two integrals above let us apply the change of variables r = τi (t),
.
defined by (4.20). Then, for x̃i (r) = xi (τi−1 (r)) (i = 0, 1), we have
− f (t̃(r), x̃λ (r), uλ (r)) dr
T
+E f (t̃(r), x̃λ (r), uλ (r)) − f (r, xλ (r), uλ (r)) dr
sλ
+ E λh(x1 (T )) + (1 − λ)h(x0 (T )) − h(X̃λ (T )) + h(X̃λ (T )) − h(xλ (T ))
T
≤ K λ̃0 λ̃1 E |τ1−1 (r) − τ0−1 (r)|2 + |x̃1 (r) − x̃0 (r)|2 dr
sλ
Vol. 17 (2010) Lipschitz continuity and semiconcavity properties 723
T
+K E (|t̃(r) − r| + |x̃λ (r) − xλ (r)|)dr
sλ
Now, the technical lemmas below will provide all the estimates that are needed
to complete the proof.
and
Proof of Lemma 4.2. We first observe that directly from the definitions of τi
and λ̃i it follows that
(s1 − s0 )(T − r)
|τ1−1 (r) − τ0−1 (r)| = ≤ |s1 − s0 |
(4.29)
T − sλ
and
λ(1 − λ)
λ̃0 λ̃1 = ≤ λ(1 − λ). (4.30)
τ̇1 τ̇0
That proves (4.23).
Inequality (4.25) can be checked by a straightforward computation that
we omit.
Proof of Lemma 4.3. Recalling the definition of x̃λ , λ̃1 and λ̃0 we have
x̃λ (r) − xλ (r) = λ̃1 x̃1 (r) + λ̃0 x̃0 (r) − xλ (r)
r
= λ̃1 y1 + λ̃0 y0 − yλ + λτ̇1−2 b(τ1−1 (ρ), x̃1 (ρ), uλ (ρ))
sλ
−2 −1
+ (1 − λ)τ̇0 b(τ0 (ρ), x̃0 (ρ), uλ (ρ)) − b(ρ, xλ (ρ), uλ (ρ)) dρ
r
−3/2
+ λτ̇1 σ(τ1−1 (ρ), x̃1 (ρ), uλ (ρ))
sλ
−3/2
+ (1 − λ)τ̇0 σ(τ0−1 (ρ), x̃0 (ρ), uλ (ρ)) − σ(ρ, xλ (ρ), uλ (ρ)) dW (ρ)
Taking the expectation of the square and using the Hölder as well as the
Burkholder inequality we obtain
E{|x̃λ (r) − xλ (r)|2 } ≤ K{|λ̃1 y1 + λ̃0 y0 − yλ |2
r
−2 −1
+E λτ̇ b(τ (ρ), x̃1 (ρ), uλ (ρ)) + (1 − λ)τ̇ −2 b(τ −1 (ρ), x̃0 (ρ), uλ (ρ))
1 1 0 0
sλ
r
2 −3/2
− b(ρ, xλ (ρ), uλ (ρ))| dρ + E λτ̇1 σ(τ1−1 (ρ), x̃1 (ρ), uλ (ρ))
sλ
2
σ(τ0−1 (ρ), x̃0 (ρ), uλ (ρ)) − σ(ρ, xλ (ρ), uλ (ρ)) dρ
−3/2
+ (1 − λ)τ̇0 (4.33)
In our next computations we will obtain suitable bounds for the terms in the
right-hand side of the above inequality. This will be achieved by the following
three estimates:
|λ̃1 y1 + λ̃0 y0 − yλ | ≤ Kλ(1 − λ)|s1 − s0 ||y1 − y0 | (4.34)
E λτ̇1−2 b(τ1−1 (ρ), x̃1 (ρ), uλ (ρ)) + (1 − λ)τ̇0−2 b(τ0−1 (ρ), x̃0 (ρ), uλ (ρ))
1/2
2
− b(ρ, xλ (ρ), uλ (ρ))|
≤ (E{|x̃λ (r) − xλ (r)|2 })1/2 + Kλ(1 − λ) |s1 − s0 |2 + |y1 − y0 |2 (4.35)
−3/2
E λτ̇1 σ(τ1−1 (ρ), x̃1 (ρ), uλ (ρ))
2 1/2
−3/2
+ (1 − λ)τ̇0 σ(τ0−1 (ρ), x̃0 (ρ), uλ (ρ)) − σ(ρ, xλ (ρ), uλ (ρ))
≤ (E{|x̃λ (r) − xλ (r)|2 })1/2 + Kλ(1 − λ) |s1 − s0 |2 + |y1 − y0 |2 (4.36)
Proof of (4.35). Hereafter, to simplify the notation, we will omit the depen-
dence of functions on the independent variable: we will write, for instance, xλ
726 R. Buckdahn et al. NoDEA
x̂λ = λ̂1 x̃1 + λ̂0 x̃0 , t̂(ρ) = λ̂1 τ1−1 (ρ) + λ̂0 τ0−1 (ρ).
Then, by assumption (S3) we have, recalling (4.29) and (4.25),
−2 −1
λτ̇ b(τ , x̃1 , uλ ) + (1 − λ)τ̇ −2 b(τ −1 , x̃0 , uλ ) − b(ρ, xλ , uλ )
1 1 0 0
= Λλ̂1 b(τ1−1 , x̃1 , uλ ) + Λλ̂0 b(τ0−1 , x̂0 , uλ ) − b(ρ, xλ , uλ )
≤ Λλ̂1 b(τ1−1 , x̃1 , uλ ) + Λλ̂0 b(τ0−1 , x̂0 , uλ ) − Λb(t̂, x̂λ , uλ )
+ |(Λ − 1)b(t̂, x̂λ , uλ )| + |b(t̂, x̂λ , uλ ) − b(t̃, x̃λ , uλ )|
+ |b(t̃, x̃λ , uλ ) − b(ρ, xλ , uλ )|
≤ KΛλ̂1 λ̂0 |τ1−1 − τ0−1 |2 + |x̃1 − x̃0 |2 + K|(Λ − 1)b(t̂, x̂λ , uλ )|
+ |b(t̂, x̂λ , uλ ) − b(t̃, x̃λ , uλ )| + K |t̃ − ρ| + |x̃λ − xλ |)
Thus, from
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R. Buckdahn, M. Quincampoix
Laboratoire de Mathématiques, UMR6205,
Université de Bretagne Occidentale,
6 Avenue Le Gorgeu, 29200 Brest, France
e-mail: Marc.Quincampoix@univ-brest.fr
R. Buckdahn
e-mail: Rainer.Buckdahn@univ-brest.fr
P. Cannarsa
Dipartimento di Matematica,
Università di Roma Tor Vergata,
Via della Ricerca Scientifica 1,
00133 Roma, Italy
e-mail: cannarsa@mat.uniroma2.it