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Q4 Math4 Week2

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SDO TABACO CITY

Mathematics 4
Quarter 4 – Week 2

LAS 2.1 – Solving Routine and Non- routine Problems Involving


Squares, Rectangles, Triangles, Parallelograms, and
Trapezoids (M4ME-IVc-60)

Development Team

Writer
Sheina V. Bueno, Teacher II, Bogñabong ES

Editors/Reviewers
Emelda D. Bien, Teacher II, San Lorenzo ES
Jayson B. Baria, Teacher I, Magapo ES
Efren B. Bonsa, PSDS
Dioleta B. Borais, EPS 1, Mathematics
Republic of the Philippines
Department of Education
Region V-Bicol
SCHOOLS DIVISION OF TABACO CITY

Name: _____________________________ Sec: __________ Date: __________


Learning Area-Grade: Mathematics 4_______ Teacher: _____________________

LEARNING ACTIVITY SHEETS NO. 2.1


Solving Routine and Non- Routine Problems
Objective
Solves routine and non- routine problems involving squares, rectangles,
triangles, parallelograms, and trapezoids.

Learning Activity
Problem solving is a mathematical process, in which it is regarded both as a
method of teaching mathematics and the goal of learning mathematics. Problems in
mathematics can be categorized into routine and non- routine. Routine problem
solving concerns solving problems that are useful for daily living. They are mostly in
the form of exercises. It can be solved using at least any of the four arithmetic
operations.
Non-Routine problems are word problems that we do not usually encounter.
These are problems that have multiple solutions but do not have automatic solution
on how to go about it. Solving non-routine problems would require us to think
analytically based on the problem and to use our cognitive by using the critical and
creative thinking skills.
There are different ways in solving Non-Routine problems, such as guess and
check, acting-it-out, make a systematic list, identifying a pattern, draw a diagram/
picture, make a table or chart, write an equation, working backwards, etc.

In solving problems, we use the 4- Step Plan:


1. Understand the problem- know what is asked and the given facts in the
problem. Identify also the words and phrases that will help you solve the problem.
2. Plan- determine the operation/ formula/ appropriate strategy to be used.
3. Solve- execute the operation/ formula/ strategy.
4. Check and look back- check whether your answer make sense and write your
final and complete answer.
Example:
A residential lot has the shape of a parallelogram. Its base measures 20 meters.
The distance between the 2 parallel sides is 8 meters. What is the area of the lot?

Step Answer
1. Understand
• the area of the lot
a. What is asked?
• Parallelogram- shaped lot,
b. What are the given facts? base – 20 m, height- 8 m
2. Plan
a. What formula will you use? • A=bxh
b. What is the number sentence?
• A = 20 m x 8 m
• 20 m x 8 m = 160 m2
3. Solve
a. Execute the formula

4. Check and look back • The area of the lot with a


a. Check whether your answer is correct and shape of a parallelogram is
write your final and complete answer 160 m2.

Practice Exercises
A. Choose and encircle the letter of the correct answer.
Krizten has a flower garden. The garden is triangular in shape. The
length of the base is 8 meters, and the height is 6 meters. What is the area of
the garden?
1. What is asked in the problem?
A. the shape of the garden C. the perimeter of the garden
B. the area of the garden D. the length of the garden
2. What are the given facts?
A. triangular- shaped garden, base = 6 m, height =8 m
B. rectangular- shaped garden, base = 8 m, height = 6 m
C. parallelogram- shaped garden, base = 8 m, height = m
D. triangular- shaped garden, base = 8 m, height = 6 m
3. What formula will you use?
1
A. A = b x h B. A = 2 (b x h) C. A = l x w D. A = l x w x h
4. What is the number sentence?
1
A. A = 8 m x 6 m C. A = 2 (8 m x 6 m)
B. A = 8 m + 6m D. A = 8 x 6 x 8
5. What is the final answer?
A. The area of the garden is 24 m2.
B. The perimeter of the garden is 24 m.
C. The area of the garden is 48 cm2.
D. The perimeter of the garden is 48 m.

B. Solve the problem using the steps. Write your answers on the space
provided.
Mrs. Bueno bought a residential lot. It has a trapezoidal lawn with an
upper base of 16 meters and a lower base of 30 meters. The distance between
the parallel bases is 10 meters. What is the area of the lawn?

1. What is asked in the problem?

2. What are the given facts?


3. What formula will you use?

4. What is the number sentence?

5. What is the final answer?

C. Study the problem below, then solve.


The length of a rectangle is 6 cm, and the width is 4 cm. If the length is
greater by 2 cm, what should the width be so that the new rectangle has the
same area as the first one?

Final answer: ________________________________


Evaluation
Read and understand each problem. Solve and encircle the letter of your
answer.
1. A triangular pond has a base of 10 meters and a height of 6 meters. What is
the area of the pond?
A. 30 cm2 B. 30 m2 C. 60 cm2 D. 60 m2
2. A lawn is to be planted with bermuda grass. How many square meters of
grass will cover the lawn if it is 5 meters long and 4 meters wide?
A. 20 m2 B. 20 cm2 C. 10 m2 D. 10 cm2
3. Mr. Balderama bought a parallelogram- shaped lot. Its base is 36 meters and
its height is 20 meters. What is the area of the lot?
A. 360 cm2 B. 360 m2 C. 720 cm2 D. 720 m2
4. A rice field in the shape of a parallelogram is 300 meters long. The
perpendicular distance between the base and its opposite side is 80 meters.
What is its area?
A. 12 000 m2 B. 12 000 cm2 C. 24 000 m2 D. 24 000 cm2
5. Maebelle bought a lot measuring 15 m long and 12 m wide. What is the area
of the lot?
A. 180 m2 B. 180 cm2 C. 90 m2 D. 90 cm2

Answer Key
Practice Exercises
A. 1. B 2. D 3. B 4. C 5. A
B. 1. The area of the trapezoidal lawn
2. trapezoidal lawn, upper base – 16 m, lower base – 30 m, height – 10 m
(𝑏 +𝑏 )ℎ
3. A = 1 2
2
(16 𝑚+30 𝑚)10 𝑚
4. A =
2
5. The area of the trapezoidal lawn is 230 m2.
C. The width of the new rectangle should be 3 cm.

References
Mathematics 4, Learner’s Material pages 215- 218
Mathematics 4, Teacher’s Guide pages 285- 290

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