Botany - Section A: AIIMS Level Test (05-Jun) Full Syllabus
Botany - Section A: AIIMS Level Test (05-Jun) Full Syllabus
Botany - Section A: AIIMS Level Test (05-Jun) Full Syllabus
Page: 1
AIIMS Level Test (05-Jun) Full Syllabus
Contact Number: 9667591930 / 8527521718
14. The pressure flow or mass flow hypothesis: 21. A dominant gametophyte will be seen in the life cycle
1. is the best-supported theory to explain the movement of of:
sap through the phloem 1. Marchantia
2. explains the movement of water in xylem 2. Sequoia
3. is no longer accepted as a hypothesis to explain the 3. Adiantum
movement of sap through the phloem 4. Eucalyptus
4. is the accepted mechanism of transport of water in the
roots till the endodermis 22. Fucus is:
1. a brown alga having oogamous sexual reproduction and
15. Which relationship given in column I is not correctly haplo-diplontic life cycle
matched with the partner apparently not deriving any 2. a red alga having anisogamous sexual reproduction and
benefit out of the relationship [Column II]? diplontic life cycle
COLUMN I COLUMN II 3. a brown alga having oogamous sexual reproduction and
diplontic life cycle
1. Orchid growing on a mango branch Mango
4. a red alga having isogamous sexual reproduction and
2. Barnacles growing on back of a whale Whale diplontic life cycle
3. Sea anemone and clown fish Sea anemone
4. Lichen Algal partner 23. Which of the following organisms is not matched with
the correct nature of the cell wall present in their
cell/cells?
16. Morels and truffles: Organism Nature of cell wall
1. are pathogenic fungi causing rust and smut 1. True bacterium Polysaccharide + Amino acid
2. do not reproduce sexually 2. Fungus With chitin
3. do not produce asexual spores
3. Euglenoids Cellulosic
4. are delicacies belonging to Ascomycetes
4. Diatoms Embedded with silica
17. In an ecosystem, during decomposition, water soluble
inorganic nutrients go down into the soil horizon and get
precipitated as unavailable salts by the process of: 24. In the mitochondrial electron transport system:
1. Fragmentation 1. Electrons from NADH are oxidized by Complex II
2. Leaching 2. Ubiquinone is located on the outer surface of the inner
3. Catabolism membrane
4. Humification 3. Complex IV refers to cytochrome c oxidase containing
cytochromes a and a3, and two copper centres
18. In a sample of water polluted with sewage discharge, 4. Cytochrome c is an electron carrier located within not
if you measure BOD [Biochemical Oxygen Demand] and with the inner membrane
DO [Dissolved Oxygen], you expect to find that:
1. The levels of both BOD and DO are high 25. Trichoderma polysporum is a fungal species:
2. The levels of both BOD and DO are low 1. extensively used in biocontrol of nematode pests
3. The levels of BOD will be high and the levels of DO 2. and a source of an immunosuppressive agent
will be low 3. used for commercial production of citric acid
4. The levels of BOD will be low and the levels of DO 4. that causes ringworm in humans
will be high
26. Even if a plant is infected with a virus:
19. What is not correct regarding apomixis? I. the apical meristem is free of virus
1. It is production of seeds without fertilization II. the axillary meristem is free of virus
2. It is a form of asexual reproduction III. meristem can be grown in-vitro to obtain virus free
3. It is fruit production without fertilization plants
4. Nucellar cells developing into embryos is an example 1. Only I and III are correct
2. Only II and III are correct
20. As a method of cellular defence, the RNA interference 3. Only I and II are correct
takes place in all: 4. I, II and III are correct
1. nematodes
2. bacteria and archaea
3. eukaryotic cells
4. plant cells
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AIIMS Level Test (05-Jun) Full Syllabus
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27. A hierarchy is an arrangement of items that are 33. Select the option where the given characters are
represented as being "above", "below", or "at the same correct match for members of Rhodophyceae:
level as" one another. Select the correct ascending order of Major Stored
taxonomic hierarchy? Cell wall Flagella
pigments food
1. Species → Genus → Family → Order → Class →
Chlorophyll a, Cellulose, pectin, 2-8,
Division → Kingdom Mannitol.
1. d; polysulphate equal,
2. Species → Genus → Family → Class → Order → Laminarin
phycoerythrin esters apical
Division → Kingdom
3. Species → Genus → Order → Family → Class → Chlorophyll a, Cellulose, pectin,
Floridean
Division → Kingdom 2. d; polysulphate Absent
starch
4. Genus → Species → Family → Order → Class → phycoerythrin esters
Kingdom → Division 2,
Chlorophyll a, Mannitol. Cellulose and
3. unequal,
c; Fucoxanthin Laminarin algin
lateral
28. When we talk of ‘ozone hole’ we mean: 2-8,
1. an absence of ozone layer in troposphere Chlorophyll a,
4. Starch Cellulose equal,
2. an absence of ozone layer in stratosphere b;
apical
3. a thinned ozone layer in troposphere
4. a thinned ozone layer in stratosphere
29. In palmately compound leaves: 34. Identify the incorrect statement regarding
1. Leaf lamina is entire photosynthesis in higher plants:
2. Leaf lamina is incised but the incisions do not touch the 1. Chlorophyll a is the chief pigment associated with
mid rib. photosynthesis.
3. Leaf lamina is incised, lamina reach up to the midrib 2. Splitting of water is associated with PS II
and leaflets are present on a common axis 3. Cyclic flow of electrons results only in the synthesis of
4. Leaf lamina is incised, lamina reach up to the midrib NADH
and leaflets are attached at a common point 4. Biosynthetic phase is dependent on the products of the
light reaction
30. In the Citric acid cycle the reduction of NAD+ to
NADH + H+ takes place at all the following steps except: 35. A higher plant requires the nutrient element
1. Conversion of Citric acid to α-ketoglutaric acid magnesium for:
2. Conversion of α-ketoglutaric acid to Succinyl CoA 1. opening and closing of stomata
3. Conversion of Malic acid to Oxaloacetic acid 2. maintaining the ribosome structure
4. Conversion of Succinic acid to Fumaric acid 3. nitrogen metabolism
4. splitting of water
31. In a diploid organism:
1. there are two copies of each gene
2. there are two genes for each character Botany - Section B
3. there are two sets of homozygous chromosomes 36. Looking at the size of the ears in hares shown in the
4. one allele is always completely dominant over the other diagram given, which hare is most likely to be found in
allele of the same gene arctic region?
1. A
2. B
3. C
4. D
Page: 3
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37. RNA interference involves silencing of a specific 43. When the water content in a seed is reduced to about
mRNA which essentially means: 10-15 % moisture by mass:
1. the transcription of mRNA is stopped by inactivating 1. the seed will never be able to germinate even with the
the promoter return of favourable conditions
2. the hnRNA is not allowed to undergo post- 2. the seed will immediately germinate to avoid
transcriptional modification unfavourable conditions
3. the mRNA cannot cross the nuclear pore complex 3. the general metabolic activity of the embryo slows
4. translation of the mRNA molecule is prevented down
4. the seed dies
38. Name the scientist:
I. He studied the tobacco mosaic virus. 44. Liliaceae:
II. He succeeded in extracting the virus in the form of pure 1. is a family of dicotyledonous plants
crystals in 1935. 2. is distributed in a highly restricted rand of specific
III. He was able to show that the tobacco mosaic virus is temperate climates
composed of protein and RNA. 3. is characterized by floral characters such as tepal, six
1. D. J. Ivanowsky [3+3]; stamen, six [3+3], epitepalous
2. W. M. Stanley 4. includes economically important plants such as
3. M. W. Beijerenik sunhemp, lupin and indigofera
4. Louis Pasteur
45. Regarding pteridophytes:
39. A lot of carbon is fixed annually in the biosphere I. They are the first terrestrial plants to possess true
through photosynthesis. It is estimated that this amount is vascular tissue
close to: II. Main plant is sporophyte
1. 4 X 1013 kg III. Water is required for transfer of antherozoids
1. Only II is incorrect
2. 4 X 1031 kg
2. Only I is correct
3. 4 X 1021 kg 3. I and II are incorrect
4. 4 X 103 kg 4. I, II and III are correct
41. Which of the following pteridophytes does not belong 47. Identify the incorrect statement:
to the same class as the other three? 1. Noise was included as a pollutant in the Air [Prevention
1. Dryopteris and Control of Pollution] Act in 1981
2. Pteris 2. Montreal Protocol was signed in 1987
3. Adiantum 3. The ‘Earth Summit’ was held in Rio de Janeiro in 1992
4. Equisetum 4. The world Summit on Sustainable Development was
held in 2002 in Johannesburg
42. In both lactate fermentation and alcohol fermentation:
1. glucose is completely oxidized under aerobic conditions 48. Identify the incorrectly matched row:
2. carbon dioxide is produced Extinct animal Category Country/Continent
3. about 70 percent of energy trapped in glucose is
released 1. Dodo Bird Mauritius
4. NADH + H+ is reoxidized to NAD+ Subspecies of
2. Quagga India
Zebra
3. Thylacine Marsupial Australia
Stellar’s sea
4. Mammal Russia
cow
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49. Regarding the formation and activity of cambial ring 54. Identify the incorrect statement regarding allergy:
during secondary growth in a dicot stem: 1. It is an exaggerated response of the immune system
I. The cells of medullary rays, adjoining intrafascicular 2. Antibodies produced in response to allergens are of
cambium become meristematic. IgA type
II. It is generally more active on the inner side than on the 3. It can be caused by release of chemicals like
outer. histamine by mast cells
1. Only I is correct 4. Steroids can quickly reduce the symptoms of allergy
2. Only II is correct
3. Both I and II are correct
4. Both I and II are incorrect 55. Both AIDS and Hepatitis B infections in humans:
1. are acute fatal infections
50. Select the statements that will be true for C4 plants: 2. are easily cured if detected early
I. Calvin cycle takes place in Bundle sheath cells 3. can be transmitted by a mosquito vector
II. Number of carbon atoms in the primary carbon dioxide 4. can be transmitted through sexual contact or infected
acceptor is 5 blood
III. Initial carboxylation reaction occurs in mesophyll cells
IV. Primary carbon dioxide fixation product is oxaloacetic
acid 56. Regarding the human kidney:
1. Only I, II and III 1. glomerulus is a tuft of capillaries formed by the
2. Only I, III and IV efferent arteriole
3. Only II, III and IV 2. vasa recta is highly reduced in juxtamedullary
4. I, II, III and IV nephrons
3. DCTs of many nephrons open into a straight tube
called collecting duct
Zoology - Section A 4. columns of Bertini are extensions of medulla into the
51. Which of the following animals belongs to the cortex
subphylum Vertebrata?
1. Doliolum
2. Branchistoma 57. Which of the following is not a lipid?
3. Petromyzon 1. Palmitic acid
4. Salpa 2. Glutamic acid
3. Cholesterol
4. Lecithin
52. Osteoporosis, commonly seen in post menopausal
women, is commonly caused by:
1. low levels of calcium ions in blood 58. During oogenesis:
2. decreased levels of oestrogens 1. meiosis I is completed before birth
3. autoimmune destruction of joints and cartilages 2 meiosis I, when completed results in equal sized
4. accumulation of uric acid crystals daughter cells
3. meiosis II results in the unequal sized cells
4. meiosis II is completed just before ovulation
53. Intercalated discs are:
1. flattened interconnected smooth ER in muscle fibre
2. communication junctions between cardiac muscle 59. Identify the hormone that is not correctly matched
cells with its function:
3. cell junctions that hold smooth muscle cells together 1. Parathyroid Increases calcium levels in the
in a unit hormone blood
4. dorsoventrally flattened mitochondria in a skeletal 2. Aldosterone Stimulates reabsorption of sodium
muscle cell at the renal tubules
3. Insulin Enhances cellular glucose uptake
and utilization
4. Cortisol Enhances cellular amino acids
uptake and utilization
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60. Identify the incorrectly matched pair: 67. What is not correct regarding malpighian tubules in
1. Golgi Formation of glycoproteins and cockroaches?
apparatus glycolipids 1. They are present at the junction of midgut and
2. Rough ER Synthesis of steroidal hormones in hindgut
animal cells 2. They are lined by glandular and ciliated cells
3. Lysosomes Carry acid hydrolases 3. They are 100-150 in number and arranged in a ring-
4. Nucelolus Site for active rRNA synthesis like manner
4. Though they are excretory structures, they do not
have osmoregulatory functions
61. Which of the following will not be seen in any
Cnidarian?
1. Metagenesis 68. Which of the following drugs is a very effective
2. Cnodicytes sedative and painkiller, acts on its receptors in CNS and
3. Bilateral symmetry in larva GIT and is also a CNS suppressant?
4. Tentacles 1. Morphine
2. Marijuana
3. Cocaine
62. The partial pressure of oxygen is expected to be least 4. Atropine
in:
1. Atmospheric air
2. Alveoli 69. Identify the incorrect statement:
3. Oxygenated blood 1. Notochord is derived from embryonic mesoderm
4. Tissues 2. Stomochord in hemochordate is actually notochord
3. Chordates have a post-anal tail
4. Pharynx is perforated by gill slits in chordates
63. A motor neuron, at the neuromuscular junction,
releases a neurotransmitter that is:
1. Epinephrine 70. Thermus aquaticus is the source bacterium of:
2. Acetylcholine 1. a heat-resistant enzyme used in PCR
3. Dopamine 2. an acid-resistant enzyme used in biological detergents
4. Serotonin 3. a reporter enzyme used in recombinant procedures
4. a key enzyme involved in ELISA
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73. Which of the following hormones does not generate 79. Match blood cells given in Column I with their most
second messenger in their target cells? important function in Column II and select the correct
1. Insulin match from the codes given:
2. Parathyroid hormone COLUMN I COLUMN II
3. Triiodothyronine A Neutrophils P Phagocytosis
4. Adrenaline B Basophils Q Inflammatory reactions
C Lymphocytes R Immune responses
D Thrombocytes S Coagulation of blood
74. Amyloplasts, Leucoplasts and Aleuroplasts are:
1. Chromoplasts containing accessory photosynthetic Codes:
pigments A B C D
2. Pro-plastids capable of developing into any types of
1. P Q R S
plastids
2. Q P S R
3. Plastids found in green algae, photosynthesizing
bacteria and protists 3. R S P Q
4. Types of leucoplasts that store nutrients 4. S R Q P
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84. A person with HIV infection starts suffering from 90. In Eukaryotes, during transcription, the introns:
infections, that could have been otherwise overcome, 1. represent the coding sequence of eukaryotic split gene
when the virus significantly destroys: 2. are loosely defined as regulatory genes
1. Macrophages 3. do not appear in mature or processed RNA
2. Helper T cells 4. provide site of attachment for RNA polymerase
3. Cytotoxic T cells
4. B cells 91. Predators play very important roles in an ecosystem
that include:
I. They act as conduit of energy
85. The lineage Synapsids → Pelycosaurs → Therapsids II. They keep prey population under check
evolved into: III. They maintain species diversity in a community
1. Crocodiles 1. Only I and II
2. Turtles 2. Only I and III
3. Birds 3. Only II and III
4. Mammals 4. I, II and III
98. Which of the following steps would be most important 105. The correct relation for Van der Waals constants 'a'
to check the population growth rate of our country? and 'b' for N and N H will be
2 3
1. Zero
by a ribozyme that is a part of the:
2. -1
1. 50S (23S component) ribosome subunit
3. +1
2. 30S (28S component) ribosome subunit
4. -3
3. 60S (28S component) ribosome subunit
4. 40S (23S component) ribosome subunit
107. When excess of AgN O and KI are added in a 3
102. When aluminium is made to react with an excess of 109. For the reaction, 2O ⇌ 3O , 3 2
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111. The packing efficiency in case of simple cubic unit 118. In the reaction:
cell is-
1. 2π
2. π
3
,
the compound 'B' is
3. π
4. π
1.
112. In the upper zone of blast furnace, the reducing agent
in the metallurgy of iron from haematite is
1. C
2. CO
3. Both (1) and (2)
4. H 2
2.
113. 100 ml of H Cl (pH=1) is mixed with 150 ml of
H Cl (pH =2). The pH of the resulting solution will be
1. 1.35
2. 1.5
3. 1.8
4. 1.9
solution is electrolysed, the ion discharged at the anode is 120. When magnesium is burnt in the air, the product
1. SO 2− formed is
4
2. OH − 1. M gO
3. H SO − 2. M g N
3 2
4
3. M gO + M g N
4. Cl − 3 2
Page: 10
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122. In which of the following cases, value of the Van't 128. The correct graph representing the frequency of
Hoff factor (i) is the highest? incident radiation (ν) and the kinetic energy of the ejected
1. N aCl (dissociation = 90%) electron (K.E.) will be
2. CaF (dissociation = 80%)
2
5
will be
1. Square pyramidal
2. Square planar
3. Trigonal bipyramidal 3.
4. Octahedral
m
√
h
2π
2. 1
2m
√
h
3. 1
m
√
h
4. 1
2m
√
2π
h
Page: 11
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131. Which one of the following elements has the highest 137. Which compound is the most reactive towards
3rd ionization potential? aromatic nucleophilic substitution reaction?
1. Na
2. Mg
3. Al
4. Si
2+ 2+
Zn|Zn ||Cu |Cu
3.
(0.01M )(2M )
3.
2+ 2+
Zn|Zn ||Cu |Cu
4. (0.2M )(1M )
3. sp 3
4. sp as well as sp
2 3
Chemistry - Section B
136. When BCl is hydrolyzed then an acid of boron is
3
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138. Which of the following compounds gets 139. Given the following reaction
decarboxylated most readily?
1.
O
||
CH3 − C − CH − COOH
The compound 'A' in the above reaction is
|
Cl
2.
O
1.
||
CH3 − C − CH − COOH
N H2
2.
3.
O
||
CH3 − C − CH − COOH
| 3.
N O2
4.
O
||
4.
CH3 − C − CH − COOH
140. Victor Meyer Test is used to distinguish primary (1°),
| secondary (2°) and Tertiary (3°) ......
CH3 1. Alcohols
2. Alkyl halides
3. Nitro alkanes
4. All of the above
1. u
=
d
4H
1. Para-formaldehyde 3.
u
2
=
H
2
2. Meta-formaldehyde g
2
2d
2
4.
u H
3. Formalin g
=
4d
1. dsp and 34
2 Δl2
equals
2. dsp and 36
2
3. sp and 34
3
4. sp and 36
3
2. [Zn(N H ) Cl ] 3 2 2
2. 2
3. [P t(N H ) Cl] 3 3 3. √2
Page: 14
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153. Sinusoidal sound waves of the same frequency 155. A mango falling from a height H from a tree is
travelling in air along the x-axis and the y-axis arrive in observed from a car moving with a uniform velocity u,
phase with each other at the origin. Their amplitudes are along a road, that passes underneath. The mango hits the
equal to A (each). The amplitude of the vibration at the car. Assume the size of the car to be negligible, and the
origin is acceleration due to gravity to be g.
1. u + √2gH
1. A
2. u − √2gH
2. √2A
3. √u
2
+ 2gH
3. 2A
4. √u
2
− 2gH
4. (2 + √2)A
1. 1
1. m
g+2a 2. 1
2
g+a
g+a 3. 2
2. m
g
3
g+a 4. 3
3. m
a
2
g+2a
4. m
g
158. An ideal gas forms the working substance of a Carnot
engine, and is taken around the Carnot cycle. We form the
dQ
integral: I = ∫ ,
T
1. zero
2. negative
3. positive
4. non-negative(positive or zero)
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159. The 1 kg–block strikes the 2 kg–block, and the first 162. A 20 V-cell delivers the same power to a 2 Ω resistor
block is brought to rest immediately after impact. The as it does to an 8 Ω resistor. The internal resistance of the
coefficient of restitution is cell is
1. 2 Ω
2. 4 Ω
3. 6 Ω
4. 1.6 Ω
4. 1
6 μ0 L r i
1.
V
μ0 L r i
the two bubbles can flow through the tube. Then, air will 3. 2V
flow μ0 L r i
4.
4π V
1.
μ0 i
2.
μ0 i
+
μ0 i
earth equals
4r 2πr
μ0 i μ0 i
3. 4r
+
4πr 1. BH
1
2 2
2.
BH
4.
μ0 i μ0 i 2
[( ) + ( ) ]
√2
4r 4πr
3. BH √2
4. 2BH
Page: 16
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166. Blackbody radiation emerging from a body at an 169. The bob (mass : m) of a simple pendulum is
absolute temperate T is allowed to fall on an ideal gas suspended from a long wire of length L. When this bob is
enclosed in a transparent vessel until its temperature submerged in a fluid of density ρ, it is observed by means
reaches a steady state value of T . Then,
1 of a careful measurement that the extension in the wire is
halved. The volume of bob is
1. T = T
1
2. T > T
1
3. T < T
1
2ρ
2
TA explanation of (A).
√5
2. TAB = TA
2 171. A ball is thrown up with a speed u at an angle of 60°
3. TAB =
1
2
TA with the horizontal; the thrower of the ball runs with a
4. TAB =
2
TA
uniform speed v and stops suddenly when he reaches a
3
certain point. He observes that the ball is at its maximum
height, and then waits until it reaches him. Then
168. The equivalent capacitance of the circuit between the
points A and B is equal to
1. v = 4u
2. v = 2u
3. v = u
4. v < u
2. 3C
2
1. 1.6 m
3. 3C
2. 1.4 m
4. 5C 3. 1.8 m
2
4. √(1.6)
2
+ (0.2)
2
m
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173. A horizontal force F is applied to a uniform solid 176. A non-conducting circular plate is uniformly charged
sphere at rest, so that its line of action passes through the and the potential at its center is V . If all the charge is
0
mid-point (P ) of the vertical radius OA; O being the collected and kept at its edge, then the potential will be
centre of the sphere (mass : m). The acceleration of the
uppermost point A is 1. 2V0
2.
V0
3.
V0
3
V0
4.
√2
m
.
3. less than . F
2.
2F0
1.
1 2 k
mv
2 4F0
2. mv
2 3. k
4.
F0
3.
1 2
mv
4 2k
4. 3
4
mv
2
1. 1 A
2. 0.5 A
3. 2.5 A
4. 3 A
1. √
kh
2
k(√2−1)h
2. √
m
3.
kh
(√2 + 1)√
m
4. (√2 − 1)√
kh
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179. The two blocks A, B have identical masses and are 181. A particle of mass m is placed at the mid-point of the
placed on a smooth horizontal plane. The pulley P is radius of a thin uniform spherical shell of mass M , as
light, and is rigidly connected to the block A by means of shown in the figure. Consider the plane that slices the
a horizontal light rod. The string connecting block B is shell into two parts: the plane is perpendicular to the
also horizontal. A force F is acting vertically on the radius and passes through m. The upper part of the shell
string, and the two blocks move horizontally. The force on has a mass and the lower part
M
. Let the
3M
A due to rod is
4 4
1. F
2. 2F
3. √2F
1. 3 F
4. F
2. 2 F
√2
3. 4 F
plane of the rails. The wire to the previous dipole. If the electric fields due to both
dipoles p, p , at the mid-point of the dipole p, are equal,
′
′
p
then p
equals
1. 3√3
3√3
2. 2
3. √3
√3
4. 2
1. falls with uniform velocity. by 1% in an adiabatic process. The temperature of the gas
2. accelerates down with acceleration less than g.
3. accelerates down with acceleration equal to g. 1. increases by 1.5%
4. moves down and eventually comes to rest. 2. decreases by 1.5%
3. increases by %
1
4. increases by 2
3
%
1. −mg
2. −mg sinθ
3. −mg cosθ
4. −mg cotθ
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185. Air flows past a windmill at a constant speed v, the 188. The input signals at A and B are as follows:
area swept by the blades being A. Assume that the At A : 0011010
windmill extracts a constant fraction of the energy of the At B : 1001101
air that flows past it. The power generated by the windmill
varies with v as
1. v
−1
2. v
1
3. v
2
4. v
3
The output at Y is
1.
3
2
is absorbed and the remaining reflected. The force exerted
2. 2 on the surface is
3.
3
√
2
4. √2
2. P
√3P
1. Only A 4. 2c
2. Only B
3. Only A & B
4. A, B, C Page: 20
AIIMS Level Test (05-Jun) Full Syllabus
Contact Number: 9667591930 / 8527521718
191. An equilateral triangular prism of glass (μ = 1.5) is 194. Under what conditions will diode D conduct?
1
1. VA > VB + V0
2. VA < VB + V0
3. VA > VB − V0
4. VA < VB − V0
1. normally from the surface BC. 195. An inductor of 0.1 H is connected with a 10 Ω
2. normally from the surface AC. resistance in series with it, as shown in the figure. A dc-
3. either from the surface BC or AC, normally. source of emf 20 V and an ac-source of emf 20 V(rms) are
4. either from the surface BC or AC, at an angle of separately connected across AB. The ac-frequency is
emergence greater than 60 but less than 90 .
∘ ∘
Hz. 50
1. h
e
Let the dc-energy stored in the inductor be U (after a long
2. h
2πe
1. zero
193. Moseley's law for characteristic X-rays states: 2. 1
√ν = a(Z − b). 3. 1
4. 1
Kα , Kβ , Lα , Lβ . . .
196. In a Young's double-slit experiment with identical
(B) a is independent of material of cathode.
slits (of slit separation-d, slit to screen distance D), the
(C) b depends on Z.
phase difference between the waves arriving at a point just
opposite to one of the slits is . The source is placed
π
2. Only A, B are true symmetrically with respect to the slits. The wavelength of
3. Only B, C are true light is
4. Only B is true 2
1. 2d
D
2
2.
d
2D
2
3. d
D
2
4.
D
Page: 21
AIIMS Level Test (05-Jun) Full Syllabus
Contact Number: 9667591930 / 8527521718
197. A radioactive sample contains two different isotopes 199. Assertion (A): The output power from a transistor
of an element X, both of them are radioactive but they amplifier is much greater than the input power.
have very different half-lives. X has a half-life T and
1 1 Reason (R): This occurs because the power is generated
X has half-life T , T >> T . The activity of the mixture
2 2 1 2 by the electrons moving from the input to the output
is shown in the figure. within the transistor.
1. ln2
T1
π
2. ln2
T2
3. 1
ln2
(T1 +T2 )
2
4.
1 1
ln2( + )
T1 T2
198. Assume that the corner of O of the room is the Let the dc-current be i (after a long time) and the peak ac-
origin, and the axes x, y, z are along the edges. The three current be i . The ratio equals
i
3. 1
√2
4. 1
1.
2.
^ ^ ^
i − 2j − k
^ ^ ^
i + k − 2j
CLICK HERE to get
3. ^ ^ ^
− i + 2j + k FREE ACCESS for 3
4. ^ ^ ^
course
Page: 22