Ejemplo 2 Plantilla
Ejemplo 2 Plantilla
Ejemplo 2 Plantilla
Constantes
Formula Nombre A B C
𝑯_𝟐 𝑶 𝑨𝒈𝒖𝒂 8.05573 1723.6425 233.08
55
50
45
40
35
30
25
20
15
10
5
0
0 5 10 15 20 25 30 35 40 45 50 55 60
t °C
Datos
𝒕_(𝑳_𝟏 ) 20 °𝑪
𝒕_(𝑳_𝟐 ) 50 °𝑪
𝒕_(𝑮_𝟏 ) 18 °𝑪
𝝋 30 %
𝑮′ 2500 𝒌𝒈∕ 〖𝒎 ^𝟐∙𝒉 〗
𝑳′ 1000 𝒌𝒈∕ 〖𝒎 ^𝟐∙𝒉 〗
𝑲_𝒀 𝒂 1200 𝒌𝒈∕ 〖𝒎 ^𝟑∙𝒉 〗
𝝆_agua 1000 𝒌𝒈∕𝒎^𝟑
𝑪_𝑳 4.18 𝒌𝑱∕ 〖𝑲𝒈∙ °𝑪 〗
𝑪_𝑳 1 𝒌𝒄𝒂𝒍∕ 〖𝑲𝒈∙ °𝑪 〗
M_agua 18 𝒌𝒈∕𝒌𝒎𝒐𝒍
M_aire 29 𝒌𝒈∕𝒌𝒎𝒐𝒍
𝝆_𝒂𝒊𝒓𝒆 1.2 𝒌𝒈∕𝒎^𝟑
Datos
𝑳' 1000 𝒌𝒈∕ 〖𝒎 ^𝟐∙𝒉 〗
𝒄_𝑳 1 𝒌𝒄𝒂𝒍∕ 〖𝒌𝒈∙ °𝑪 〗 𝒊_𝑮=(𝟎.𝟐𝟒+𝟎.𝟒𝟔 𝒀)𝒕+𝟓𝟗
𝑲_𝒀 𝒂 1200 𝒌𝒈∕ 〖𝒎 ^𝟑∙𝒉 〗
𝒕_(𝑳_𝟏 ) 20 °𝑪 𝒀_𝟏
𝒕_(𝑳_𝟐 ) 50 °𝑪 𝒊_𝟏
𝒊_𝟏 9.95655 𝒌𝒄𝒂𝒍∕𝒌𝒈
𝝆_𝒂𝒊𝒓𝒆 1.29 𝒌𝒈∕𝒎^𝟑
𝝋 30 %
𝑮' 2500 𝒎^𝟑∕ 〖𝒎 ^𝟐∙𝒉 〗
𝒕_(𝑮_𝟏 ) 18 °𝑪
𝑮 3225 𝒌𝒈∕𝒉
𝑨 1 𝒎^𝟐
55
50
45
40
35
30
i kcal/kg
25
20
15
10
0
0 5 10 15 20 25
t °C
𝒊_𝑮=(𝟎.𝟐𝟒+𝟎.𝟒𝟔 𝒀)𝒕+𝟓𝟗𝟕.𝟐 𝒀
65
60
55
50
45
40
i kcal/kg
35
30
25
20
15
10
0
15 20 25 30 35 40 45 50 55 0 5 10 15 20 25
t °C t
Línea de operación
𝒕_𝑳 𝒊
20 6.560276
50 15.86260158
0.310077519
#VALUE!
𝒕_𝑳𝟏
n 𝒕_𝑳𝟏
0 20
1 25
2 30
3 35
4 40
5 45
6 50
Constantes
Formula Nombre A B C
𝑯_𝟐 𝑶 𝑨𝒈𝒖𝒂 8.05573 1723.6425 233.08
𝒀=𝑴_𝒗/𝑴_𝒈 ∙𝒑_𝒔𝒂𝒕/(𝑷−𝒑_𝒔𝒂𝒕 )
𝒊_𝑮=(𝟎.𝟐𝟒+𝟎.𝟒𝟔 𝒀)𝒕+𝟓𝟗𝟕.𝟐 𝒀
𝑵_𝒐𝒊=𝒉/𝟑 [𝒇(𝒂)+𝒇(𝒃)+𝟒
5 10 15 20 25 30 35 40 45 50 55
t °C
Línea de operación
𝒕_𝑳 𝒊
20 6.560276
50 15.86260158
𝒉=(𝒃−𝒂)/𝒏
h 1.550387597
𝒊 𝒕_𝑳𝟐 𝒊^∗ 𝟏/(𝒊^∗−𝒊) 0
6.560276 20 13.71358785 0.13979538725 20 6.560276
8.110663597 25 18.22678381 0.098852127 20 13.71358785
9.661051194 30 23.82190533 0.07061720927
11.21143879 35 30.82541912 0.05098404215 2
12.76182639 40 39.66974325 0.03716378362 30 9.661051194
14.31221398 45 50.9391392 0.0273023191 30 23.82190533
15.86260158 50 65.44336402 0.020169113
4
ENTALPIA DE LA INTERFASE 40 12.76182639
𝒕 °𝑪 𝒑_𝒗 𝒎𝒎𝑯𝒈 𝒀 𝒊_𝒊 40 39.66974325
20 17.58196308 0.014699188 13.7135878484
25 23.82407433 0.020086716 18.2267838092 6
30 31.91164359 0.027204428 23.8219053298 50 15.86260158
35 42.28121052 0.036565171 30.8254191247 50 65.44336402
40 55.4460788 0.048846237 39.6697432499
45 72.00469675 0.064960575 50.9391392007
50 92.64920559 0.086171177 65.4433640172
𝑹𝒆𝒔𝒖𝒍𝒕𝒂𝒅𝒐𝒔
𝑵_𝒐𝒊 0.560248289
𝑯_𝒐𝒊 2.6875 m
a) 𝒛 1.505667276 m
𝑵_𝒐𝒊=𝒉/𝟑 [𝒇(𝒂)+𝒇(𝒃)+𝟒∑▒𝒊𝒎𝒑𝒂𝒓𝒆𝒔+𝟐∑▒𝒑𝒂𝒓𝒆𝒔]
𝑯_𝒐𝒊=𝑮/(𝑲_𝒀 𝒂)
1
25 8.110663597
25 18.22678381
3
35 11.21143879
35 30.82541912
5
45 14.31221398
45 50.9391392
Datos
𝒕_(𝑳_𝟏 20 °𝑪
)
𝒕_(𝑳_𝟐 ) 50 °𝑪
𝒕_(𝑮_𝟏 ) 18 °𝑪
𝝋 30 %
𝑮′ 2500 𝒌𝒈∕ 〖𝒎 ^𝟐∙𝒉 〗
𝑳′ 1000 𝒌𝒈∕ 〖𝒎 ^𝟐∙𝒉 〗
𝑲_𝒀 𝒂 1200 𝒌𝒈∕ 〖𝒎 ^𝟑∙𝒉 〗
𝝆_agua 1000 𝒌𝒈∕𝒎^𝟑
𝑪_𝑳 4.18 𝒌𝑱∕ 〖𝑲𝒈∙ °𝑪 〗
𝑪_𝑳 1 𝒌𝒄𝒂𝒍∕ 〖𝑲𝒈∙ °𝑪 〗
M_agua 18 𝒌𝒈∕𝒌𝒎𝒐𝒍
M_aire 29 𝒌𝒈∕𝒌𝒎𝒐𝒍
𝝆_𝒂𝒊𝒓𝒆 1.2 𝒌𝒈∕𝒎^𝟑
Constantes
Formula Nombre A B C
𝑯_𝟐 𝑶 𝑨𝒈𝒖𝒂 8.05573 1723.6425 233.08
De la carta psicometrica obtenemos:
Y 0.0036 Kg de agua/ Kg de aire seco
Calculamos i_G1 con
iG= (0.24+0.46 Y)t + 597.2 Y
75
70
65
60
55
50
45
i kcal/kg
40
35
30
25
20
15
10
0
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70
t °C
Linea de operación
tL i_G
20 6.499728
50 18.499728
0.4
iG2 18.499728
80
75
70
65
60
55
50
45
i kcal/kg
40
35
30
25
20
15
10
0
50 55 60 65 70 0 5 10 15 20 25 30 35 40 45 50 55 60 65 70
t °C
Simpson 1/3
h 2
n t1 i t2 i*
0 20 6.499728 20 13.7135878
1 25 8.499728 25 18.2267838
2 30 10.499728 30 23.8219053
3 35 12.499728 35 30.8254191
4 40 14.499728 40 39.6697432
5 45 16.499728 45 50.9391392
6 50 18.499728 50 65.443364
Entalpia de la interfase
t P Y i
20 17.5819631 0.01469919 13.7135878
25 23.8240743 0.02008672 18.2267838
30 31.9116436 0.02720443 23.8219053
35 42.2812105 0.03656517 30.8254191
40 55.4460788 0.04884624 39.6697432
45 72.0046967 0.06496057 50.9391392
50 92.6492056 0.08617118 65.443364
Noi 0.75676824
Hoy 2.08333333 m
Z 1.57660049 m
45 50 55 60 65 70
0
t_L i
20 6.499728
20 13.7135878
f(x)
0.13862204 1
0.10280603 25 8.499728
0.07506281 25 18.2267838
0.0545682
0.03972981 2
0.0290365 30 10.499728
0.02130214 30 23.8219053
3
35 12.499728
35 30.8254191
4
40 14.499728
40 39.6697432
5
45 16.499728
45 50.9391392
6
50 18.499728
50 65.443364