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6.3 Lecture Notes

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§6.

3 Volume by Slicing, Page 1

We have seen that integration is used to compute the area of two-dimensional regions bounded by
curves. Integrals are also used to find the volume of three-dimensional regions (or solids). Once
again, the slice-and-sum method is key to solving these problems.

General Slicing Method


Suppose a solid object extends from x = a to x = b, and the
cross section of the solid perpendicular to the x-axis has an
area given by the function A that is integrable on [a, b].
Z b
The volume of the solid is V = A(x)dx.
a

x
1. Consider the solid S with a triangular base formed by y = , y = 0, and x = 4, for which
2
parallel cross-sections perpendicular to the base and x-axis are squares. Calculate the volume
of S.

2. Consider the solid S whose base is bounded by x = y 2 and x = 1, for which parallel
cross-sections perpendicular to the base and x-axis are equilateral triangles. Calculate the
volume of S.
§6.3 Volume by Slicing, Page 2

Solids of Revolution - Disk Method about the x-axis


Suppose you are given a region R in the xy-plane and you rotate R about one of the axes. This
results in a 3-dimensional solid, S. We can use the following approach to calculate the volume of S.
(1) “Fill up” the region R with rectangles, each with width ∆x and height f (x).
(2) Rotate each rectangle around the x-axis to form a collection of circular disks.
(3) Calculate the volume of each circular disk.
(4) Sum up the volumes of each disk to approximate the total volume of the solid S.

Let f be continuous with f (x) ≥ 0 on the interval [a, b]. If


the region R bounded by the graph of f , the x-axis, and the
lines x = a and x = b is revolved about the x-axis, the volume
Z b
of the resulting solid of revolution is V = π(f (x))2 dx,
a
where f (x) describes the disk radius.


3. Consider the region bounded by y = x, the x-axis, and the line x = 1.
Calculate the volume of the solid generated by a rotation about the x-axis.
§6.3 Volume by Slicing, Page 3

Solids of Revolution - Washer Method about the x-Axis


A slight variation on the disk method enables us to compute the volume of more exotic solids of
revolutions. Let f and g be continuous functions with f (x) ≥ g(x) ≥ 0 on the interval [a, b].
Let R be the region bounded by y = f (x), y = g(x), and the
lines x = a and x = b. When R is revolved about the x-axis, the
volume of the resulting solid of revolution is
Z b
V = π(f (x)2 − g(x)2 )dx,
a
where f (x) describes the outer radius and g(x) describes the inner
radius.

4. Consider the region bounded by y = x2 + 2, y = 21 x + 1, x = 0, and x = 1.


Calculate the volume of the solid generated by a rotation about the x-axis.
§6.3 Volume by Slicing, Page 4

Solids of Revolution about the y-Axis


5. Consider the region bounded by y = x3 , y = 1, y = 8, and x = 0. Calculate the volume of the
solid generated by a rotation about the y-axis.

Solids of Revolution about Other Lines


6. Consider the region bounded by y = 0, x = 0, and y = 1 − x. Calculate the volume of the
solid generated by a rotation about the line x = 2.
§6.3 Volume by Slicing, Page 5

Additional Practice Problems


7. Find the volume of the torus (doughnut) formed when the circle of radius 2 centered at (3, 0)
is revolved about the y-axis. Use symmetry and geometry to evaluate this integral.

8. Use calculus to find the volume of a right circular cone with height h and base radius r.

9. A 6 inch tall plastic cup is shaped like a surface obtained by rotating a line segment in the
first quadrant about the x-axis. Given that the radius of the base of the cup is 1 inch, the
radius of the top of the cup is 2 inches, and the cup is filled to the brim with water, use
integration to approximate the volume of water in the cup.

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