15 - PDFsam - 01 رياضيات 1-ب
15 - PDFsam - 01 رياضيات 1-ب
15 - PDFsam - 01 رياضيات 1-ب
Solution
(i) We know that derivative of mx is m. Thus, we make the substitution
mx = t so that mdx = dt.
1 1 1
Therefore, ∫ sin mx dx = m ∫ sin t dt = – m cos t + C = – m cos mx + C
INTEGRALS 301