10th Cbse Science Pyq
10th Cbse Science Pyq
10th Cbse Science Pyq
online
CHAPTER 2
Acid Bases and Salts
23. What is meant by term pH of solution? The pH of 33. Write a balanced chemical equation for the reaction
rain water collected from two cities A’ and ‘B’ were between sodium carbonate and hydrochloric acid
found to be 6.0 and 5.0 respectively. The water of indicating the physical state of reactants and the
which city will be more acidic? products.
Ans : [CBSE 2011] Ans : [CBSE 2010]
pH of solution is defined as negative logarithm of H+ Na 2 CO 3 (s) + 2HCl (dill) $ 2NaCl (aq) + CO 2 (g) + H 2 O (l)
ion concentration. It determines the strength of acid
and base. Rainwater with pH = 5 is more acidic. 34. Name the acid and base that have constituted the salt
ammonium nitrate.
24. A few drops of sulphuric acid are added to water Ans : [CBSE 2010]
before electrolysis, why?
Acid: HNO3,
Ans : [CBSE 2011] Base: NH4OH (i.e., Nitric acid, Ammonium hydroxide).
Water is not a good conductor of electricity. Few
drops of sulphuric acid makes it better conductor of 35. Suggest one way to reduce alkaline nature of the soil.
electricity. Ans : [CBSE 2010]
Add ammonium nitrate (Acidic salt) to neutralise
25. Write the names of two salts belonging to sodium
alkaline nature of soil.
36. Oxides of metals are basic while those of non-metals 46. How does the pH change when solution of a base is
are acidic. Explain. diluted?
Ans : [CBSE 2010] Ans : [CBSE 2008]
Metal oxides dissolve in water to form base basic in When solution of a base is diluted, its pH decreases.
nature. On the other hand non-metals dissolve in
water to form acids, acidic in nature. 47. Arrange the following in an increasing order of their
pH values: NaOH solution, Blood, Lemon juice.
37. What is the difference between slaked lime and lime Ans : [CBSE 2008]
water?
Lemon juice < Blood < NaOH solution.
Ans : [CBSE 2010]
The solid Ca(OH)2 is slaked lime whereas clear 48. At what pH in the mouth is tooth decay faster and
solution of Ca(OH)2 in water is lime water. why?
Ans : [CBSE 2008]
38. Write a balanced chemical equation for the
At pH lower than 5.5, tooth decay becomes faster
neutralisation reaction, mentioning the physical state
because calcium phosphate (enamel) reacts with acid
of reactants and products.
and gets corroded.
Ans : [CBSE 2010]
NaOH(aq) + HCl(aq) $ NaCl(aq) + H2O(l)
TWO MARKS QUESTIONS
39. During summer season, a milkman usually adds a very
small amount of baking soda to fresh milk. Give one
reason. 49. A white chemical compound becomes hard on mixing
proper quantity of water. It is also used to maintain
Ans : [CBSE Sample Paper 2009]
joints in fixed position. Name the chemical compound
Baking soda is basic in nature, it will not allow milk and write its chemical formula. Write the chemical
to turn sour due to the formation of lactic acid. equation to show what happens when water is added
to this compound in proper quantity.
40. Curd is not kept in copper and brass utensils, why?
Ans : [CBSE Sample Paper 2018, CBSE 2016]
Ans : [CBSE 2009C]
CaSO4. 12 H2O is the formula of the compound. The
Curd contains lactic acid which can make poisonous name of compound is ‘Plaster of Paris’ (Calcium
compounds with brass and copper vessels. sulphate hemihydrate).
41. Fresh milk has pH = 6. When it changes to curd will
CaSO 4 $ 12 H 2 O + 32 H 2 O $ CaSO 4 $ 2H 2 O
(Plaster of Paris) (Gypsum)
its pH value increase or decrease? 50. Two solutions ‘A’ and ‘B’ have pH value 3.0 and 10.5
Ans : [CBSE 2009] respectively. Which of these will turn
pH value will decrease when milk changes to curd. a. Blue litmus solution to red,
b. Phenolphthalein from colourless to pink? Justify
42. What would be the colour of litmus in a solution of your answer in each case.
sodium carbonate? Ans : [CBSE 2016]
Ans : [CBSE 2009] a. ‘A’ with pH = 3, will turn blue litmus red because
The red litmus will turn blue in Na2CO3 solution. it is acidic in nature.
b. “B’ with pH = 10.5, will turn phenolphthalein
43. What is the colour of litmus in a solution of ammonium colourless to pink because ‘B’ is basic in nature.
hydroxide?
Ans : [CBSE 2009] 51. The pH of soil ‘A’ is 7.5, while that of soil “B is 4.5.
Which of the two soils A or B should be treated with
Red litmus will turn blue green colour in a solution of
powdered chalk to adjust the pH and why?
ammonium hydroxide.
Ans : [CBSE 2016]
44. On adding dilute hydrochloric acid to copper oxide Soil ‘B’ is acidic, therefore it needs to be treated with
powder, the solution formed is blue green. Predict the powdered chalk to adjust its pH because chalk is basic,
new compound formed which imparts a blue green which will make soil neutral.
colour to the solution.
Ans : [CBSE 2008] 52. Write the chemical equation to describe how baking
soda is produced on a large scale. Also write the
Copper chloride imparts blue green colour to the
chemical name of the products formed in the reaction.
solution.
Ans : [CBSE 2016]
45. How does flow of acid rain water into river makes the NH 3 + H 2 O + CO 2 + NaCl $ NaHCO 3 + NH 4 Cl
survival of aquatic life in the river difficult? (Sodium hydrogen (Ammonium
carbonate) chloride)
Ans : [CBSE 2008]
Acidic water makes aquatic species uncomfortable. 53. What is chlor-alkali process? Write a balanced
Aquatic species are more comfortable in the pH 7 to chemical equation for the reaction involved in this
7.8.
process, to justify your answer. Ans : [CBSE 2016]
Ans : [CBSE 2016] a. Green precipitate of Fe(OH)2 will be formed:
When brine solution is electrolysed we get alkali FeSO 4 (aq) + 2NaOH (aq) $ Fe (OH) 2 . Na 2 SO 4 (aq)
(Green ppt)
(NaOH) and chlorine (Cl2) gas, this process is called
chlor-alkali process. b. White precipitate of Al(OH)3 will be formed:
2NaCl (aq) + 2H 2 O (l) $ 2NaOH (aq) + H 2 (g) + Cl 2 (g) AlCl (aq) + 3NaOH $ Al (OH) 3 (s) + 3NaCl (aq)
(White ppt)
54. What is meant by the term water of crystallisation? 60. 15 mL of water and 10 mL of sulphuric acid are to be
How would you show that copper sulphate crystals mixed in a beaker
contains water of crystallisation? a. State the method that should be followed with
Ans : [CBSE 2016] reason.
b. What is this process called?
The molecules of water associated with a crystalline
Ans : [CBSE 2015]
substance are called water of crystallisation.
When hydrated copper sulphate is heated its colour a. Acid should be added to the water slowly with
changes from blue to dirty white and water droplets constant cooling because the reaction is highly
are formed. exothermic.
CuSO4.5H2O
Heat
CuSO4 + 5H2O b. This process is called dilution.
If we add little water to anhydrous CuSO4, we get blue
colour again. It is the presence of molecules of water of
crystallisation which was lost on heating.
CuSO4 + 5H2O $ CuSO4.5H2O
(Anhydrous)
Test: Bring a burning splinter near the gas. If it burns 95. a. Define a universal indicator. Mention its one use.
with ‘pop’ sound, the gas liberated is hydrogen. b. Solution ‘A’ gives pink colour when a drop of
Zn + H2SO4(dil) $ ZnSO4(aq) + H2 phenolphthalein indicator is added to it. Solution
Hydrogen gas will be evolved by reaction of the same ‘B’ gives a red colour when a drop of methyl
metal with dilute H2SO4, strong acid. orange is added to it. What type of solutions are
‘A’ and ‘B’ and which of these will have higher
91. The pH of a salt which is used to make tasty and pH?
crispy pakoras is 14. Identify the salt and write a c. Name one salt whose solution has pH greater than
7 and one salt with pH less than 7.
CuSO 4 (s) + 5H 2 O (l) $ CuSO 4 $ 5H 2 O
Ans : [CBSE 2016] Blue
a. Universal indicator is mixture of indicators used b. Na2CO3.10H2O, washing soda (Sodium carbonate
to find pH of solution. It is used to measure levels decahydrate) has 10 molecules of water of
of H+ ion concentration. crystallisation. CaSO4.2H2O, gypsum, chemically
b. ‘A’ is basic in nature, ‘B’ is acidic in nature. ‘A’ calcium sulphate dihydrate has 2 molecules of
will have higher pH than ‘B’. It should be greater water of crystallisation.
than 7.
100. You are provided with magnesium ribbon and sulphur
c. Na2CO3 is the salt whose pH is more than, CuSO4
powder. Explain with the help of activity that metal
is the salt whose pH is less than 7.
oxides are basic and oxides of non-metals are acidic
96. a. Define pH scale. Draw a figure showing variation in nature.
of pH with change in concentration of H+(aq) and Ans : [CBSE 2014]
OH-(aq) ions. Bum magnesium ribbon with the help of tongs to
b. Mention the pH of acidic, basic and neutral form white ash. Dissolve the ash in hot water. Add
solutions respectively. red litmus which turns blue, showing that MgO is a
Ans : [CBSE 2016] basic oxide.
a. pH scale is a scale which is used for measuring 2Mg(s) + O2(g) $ 2MgO(s)
hydrogen ion concentration in a solution. MgO(s) + H2O(Hot) $ Mg(OH)2(aq)
Heat sulphur taken in a iron spatula and pass the gas
through water. Add blue litmus into it. It will turn red
showing SO2 is an acidic oxide.
S + O2 $ SO2
SO2 + H2O $ H2SO3 (Sulphurous acid)
b. pH < 7 is for acidic solution, pH > 7 basic solution, 101. List two differences between acids and bases on the
pH = 7 for neutral solution. basis of chemical properties.
97. a. Define olfactory indicators. Name two substances Ans : [CBSE 2013]
which can be used as olfactoiy indicators.
b. Choose strong acids from the following: Acids Bases
CH3COOH, H2SO4, H2CO3, HNO3 1. Acids turn blue litmus Bases turn red litmus
Ans : [CBSE 2015] red. blue.
a. Olfactory indicators: They give different smell in 2. Acids liberate CO2 Bases do not react
acidic and basic medium e.g., onion, clove, vanilla. with metal carbonates with metal carbonates
b. HNO3 and H2SO4 are strong acids among the given and hydrogen and hydrogen
acids. carbonates. carbonates.
98. Explain the action of dilute hydrochloric acid on the
following with suitable chemical equations: 102. A substance ‘X’ is used as antacid reacts with
a. Magnesium ribbon, hydrochloric acid to produce a gas W which is used in
b. Sodium hydroxide, fire extinguishers:
c. Crushed egg shells. a. Name the substance X and ‘Y’.
b. Write a balanced equation of the reaction between
Ans : [CBSE 20151
X and hydrochloric acid.
a. Mg(s) + 2HCl(dil) $ MgCl2(aq) + H2(g) Ans : [CBSE 2013]
b. NaOH(aq) + HCl(dil) $ NaCl(aq) + H2O(l)
c. CaCO 3 ^ s h + 2HCl ^dilh $ CaCl 2 ^gh + CO 2 ^gh + H 2 O ^ l h a. ‘X’ is NaHCO3 (Sodium hydrogen carbonate). ‘Y’
is CO2 gas, which is used in fire extinguishers.
99. a. The blue colour of crystals of a substance on b. NaHCO 3 (s) + HCl (aq) $ NaCl (aq) + H 2 O (l) + CO 2 (g)
heating in a closed test tube gets changed but the
colour was regained after sometime on cooling. 103. “Sodium hydrogen carbonate is a basic salt.” Justify
Name that substance and write its chemical the statement. How is it converted into washing soda?
formula. Explain the phenomenon involved. Explain.
b. Write name and chemical formulae of two such Ans : [CBSE 2012]
compounds whose one unit is associated with 10 NaHCO3 is a salt of NaOH which is a strong base and
and 2 water molecules respectively. H2CO3 (Carbonic acid) which is a weak acid, therefore
Ans : [CBSE 2015] it is a basic salt. It can be converted into washing soda
a. Hydrated copper sulphate, CuSO4.5H2O is the by heating followed by crystallisation:
Heat
name and chemical formula of that substance. 2NaHCO 3 (s) Na 2 CO 3 (s) + CO 2 (g) + H 2 O (l)
It loses water of crystallisation on heating and Na2 CO3 + 10H2 O $ Na 2 CO 3 $ 10H 2 O
(washing soda)
regains these molecules of water on exposure to
the atmosphere: 104. Describe an activity with diagram to illustrate that
CuSO 4 $ 5H 2 O
Heat
CuSO 4 + 5H 2 O the reaction of metal carbonates or metal bicarbonates
Blue (Dirty while)
with acid produces carbon dioxide. Write the relevant b. D is strongly alkaline,
equations of all the reactions that take place. Name c. ‘C’ is strongly acidic,
any two forms in which calcium carbonate is found in d. A is weakly acidic,
nature. e. ‘E’ is weakly basic. D<E<B<A<C is the
Ans : [CBSE 2012] increasing order of H+ ion concentration.
Activity: To show reaction of metal carbonates and 107. You have been provided with three test tubes. One
metal hydrogen carbonates with dilute acids. of them contains distilled water and the other two
1. Take marble chips in Woulfe bottle. contains an acidic solution and a basic solution
2. Set the apparatus as shown in the diagram. respectively. If you are given only red litmus, how will
3. Add dilute HCl with the help of thistle funnel. you identify the contents 5 of each test tube?
4. Collect the gas and pass through lime water and Ans : [CBSE 2011 ]
bring a burning matchstick near the gas.
5. Observe what happens. Add red litmus to each of them. The test tube in
Observation: Lime water turns milky. The burning which it turns blue contains the base.
matchstick gets extinguished. Add blue litmus to the remaining two test tubes.
Conclusion: Metal carbonates react with dilute acids The one in which it turns red contains the acid. The
to liberate carbon dioxide. other one in which blue litmus and red litmus do not
Repeat the experiment with NaHCO3 taken in change contains distilled water,
Woulfe bottle.
Observation: 108. While constructing a house, a builder selects marble
CO2 gas will be evolved which turns lime water milky. flooring and marble table top for the kitchen where
Conclusion: Metal hydrogen carbonates give CO2 with vinegar and lemon juice, tamarind etc., and more
dilute acids. often used for cooking are to be kept. Will you agree
to this selection and why?
Ans : [CBSE 2010]
No, he has taken wrong decision. Marble will react
with vinegar and other acids and get corroded.
CaCO 3 + 2CH 3 COOH $ (CH 2 COO) 2 Ca + H 2 O + CO 2
105. What is neutralisation reaction? Give two examples. FIVE MARKS QUESTIONS
Ans : [CBSE 2011]
The reaction in which acid reacts with base to form
110. a.Define indicator. Name two indicators obtained
salt and water is called neutralisation reaction e.g.,
from plants.
NaOH + HCl $ NaCl + H2O
b. Write a balanced chemical equation for the
2KOH + H2SO4 $ K2SO4 + 2H2O
reaction taking place when sodium oxide reacts
CaCO3 (Marble), CaCO3(Chalk) are the two forms in
with water. How will this solution behave towards
which calcium is found in nature.
phenolphthalein and red litmus paper?
106. Five solutions A, B, C, D, and E showed pH as 4, 7, c. State what happens when sodium hydroxide
1, 11 and 9 respectively when tested with universal solution reacts with hydrochloric acid.
indicator. Which solution is Ans : [CBSE 2016]
a. Neutral, a. Indicator is a substance which give different
b. Strongly alkaline, colour or odour in acid and base e.g., litmus and
c. Strongly acidic, turmeric are indicators obtained from plants.
d. Weakly acidic, b. Na2O(s) + H2O(l) $ 2NaOH(aq)
e. Weakly alkaline. Solution will turn phenolphthalein pink and red
Arrange the pH in increasing order of H+ ion litmus paper blue.
concentration. c. Sodium chloride and water are formed:
Ans : [CBSE 2011] NaOH(aq) + HCl(aq) $ NaCl(aq) + H2O(l)
a. ‘B’ is neutral,
111. State the reason for the following statements: and H2CO3 is added in test tube ‘B’ in equal amounts:
a. Tap water conducts electricity whereas distilled a. Identify the test tube showing vigorous reaction.
water does not. b. Give reason to support your answer.
b. Dry hydrogen chloride gas does not turn blue c. Name the gas liberated in both the test tubes.
litmus red whereas dilute hydrochloric acid does. How will you prove its liberation?
c. During summer season, a milkman usually adds a d. Write chemical equations for both the reactions.
very small amount of baking soda to fresh milk. e. Out of two acids taken above, which one will have
d. For dilution of an acid, acid is added to water and lower pH value and lower H+ ion concentration
not water to acid. respectively?
e. Ammonia is a base but it does not contain Ans : [CBSE 2014]
hydroxyl group.
a. ‘A’ will show vigorous reaction.
Ans : [CBSE 2015] b. H2SO4 is a strong acid, it reacts faster than H2CO3,
a. Tap water contains ions which makes it a good a weak acid.
conductor whereas distilled water does not contain c. H2 gas. If we bring a burning splinter near the gas,
any ions. it will burn with ‘pop’ sound.
b. Dry HCl gas does not dissociate into ions, so it d. Mg + H2SO4 $ MgSO4 + H2
has no effect on the litmus. Hydrochloric acid Mg + H2CO3 $ MgCO3 + H2
form ions, so it turns blue litmus red. e. H2SO4 will have lower pH. H2CO3 will have lower
c. Baking soda prevents the formation of lactic acid H+ ion concentration,
when milk turns sour.
d. Acid is added to water slowly because the reaction 115. Write chemical equations when zinc granules react
is highly exothermic. If water is added to acid, with
then glass container may break due to lot of heat a. Sulphuric acid,
evolved. b. Hydrochloric acid,
e. NH3 dissolves in H2O forming NH4OH, therefore c. Aluminium chloride,
it acts as base: d. Sodium hydroxide,
NH3 + H2O $ NH4OH $ NH4 + OH- e. Nitric acid
Ans : [CBSE 2014]
112. a.State the chemical properties on which the
a. Zn(s) + H2SO4(dil.) $ ZnSO4(aq) + H2(g)
following uses of baking soda are based:
b. Zn(s) + 2HCl(dil) $ ZnC(aq) + H2(g)
(i) as an antacid,
c. Zn(s) + AlCl3(aq) $ No reaction
(ii) as a soda acid fire extinguisher,
d. Zn(s) + 2NaOH(aq) $ Na2ZnO2(aq) + H2(g)
(iii) to make bread and cake soft and spongy.
e. 3Zn (s) + 8HNO 3 (dil) $ 3Zn (NO 3) 2 (aq) + 2NO (g) + 4H 2 O (l)
b. How is washing soda obtained from baking soda?
Write the relevant balanced chemical equation. 116. The metal salt ‘A’ is blue in colour. When salt ‘A’ is
Ans : [CBSE 2015] heated strongly over a burner, then a substance ‘B’
a. (i) It is basic in nature. present in it is eliminated and a white powder ‘C’ is
(ii) It liberates CO2 with acid which extinguishes left behind. When a few drops of a liquid ‘D’ is added
fire. to powder ‘C’, it becomes blue again.
(iii) It releases CO2 gas on heating which makes a. Identify A, B, C and D.
bread and cake soft and spongy. b. Write the chemical equations involved.
b. Washing soda is obtained by heating baking soda c. Give an example of the salt which also shows the
followed by crystallisation: above property.
2NaHCO3(s) $ Na2CO3 + CO2 + H2O Ans : [CBSE 2014]
Na 2 CO 3 + 10H 2 O $ Na 2 CO 3 $ 10H 2 O a. ‘A’ is CuSO4.5H2O, ‘B’ is H2O, ‘C’ is CuSO4
(Washing
(Washing soda)
soda)
(ahydrous).
Heat
113. Write balanced chemical equations for the following: b. CuSO 4 $ 5H 2 O (s) CuSO 4 (s) + H 2 O (l)
(Blue)
a. Bleaching powder is kept open in air. (White) B
b. Blue crystals of copper sulphate are heated. c. FeSO4.7H2O is a salt which also shows this
c. Chlorine gas is passed through dry slaked lime. property.
d. Carbon dioxide gas is passed through lime water.
e. NaOH solution is heated with zinc granules. 117. a.Write the chemical name and chemical formula of
Ans : [CBSE 2014] washing soda.
b. How is chlorine obtained from sodium chloride?
a. CaOCl2 + CO2 $ CaCO3 + Cl2
Heat Give equations for the reactions involved.
b. CuSO4.5H2O CuSO4 + 5H2O c. Give an example of the salt which also shows the
c. Ca(OH)2 + Cl2 $ CaOCl2 + H2O above property.
d. Ca(OH)2 + CO2 $ CaCO3 + H2O
Ans : [CBSE 2014]
e. Zn + 2NaOH $ Na2ZnO2 + H2
a. Na 2 CO 3 $ 10H 2 O , Sodium carbonate decahydrate.
114. Equal length of magnesium ribbon are taken in two b. NaCl + H 2 O + NH 3 + CO 2 $ NaHCO 3 + NH 4 Cl
test tubes A and B. H2SO4 is added to test tube ‘A’ Heat
2NaHCO 3 Na 2 CO 3 + H 2 O + CO 2
Na 2 CO 3 + 10H 2 O $ Na 2 CO 3 $ 10H 2 O relevant chemical equation.
CO2 gas is passed through ammonical brine to get (b) While diluting an acid, why is it recommended
back NaHCO3. NaHCO3 on heating again gives that the acid should be added to water and not
Na2CO3 which on crystallisation gives washing water to the acid?
soda. Ans : [CBSE 2012]
c. Na2CO3 is salt of NaOH (Strong base) and
a. ‘X’ is NaOH. It is a base which is hygroscopic
H2CO3(Weak acid), therefore it is a basic salt. It
i.e., absorbs moisture from the atmosphere and
is used for softening hard water.
turns sticky. It is also formed by the electrolysis of
118. a.Identify the acid and the base whose combination aqueous solution of brine by chlor alkali process:
Heat
forms the common salt that you use in your food. 2NaCl (aq) + 2H 2 O (l) 2NaOH (aq) + H 2 (g
Write its chemical formula and chemical name of Neutralisation reaction will take place between
the salt. NaOH and HCl:
b. What is rock salt? Mention its colour and the NaOH + HCl $ NaCl + H2O
reason due to which it has this colour. b. It is because the process is highly exothermic. If
c. What happens when electricity is passed through we add H2O to acid, the glass container may break
brine? Write chemical equation for it. due to excess heat evolved.
Ans : [CBSE 2013] 121. a.Explain the following chemical properties of acids
a. NaOH (Sodium hydroxide) and HCl (Hydrochloric with the help of balanced chemical equations only:
acid) form common salt. NaCl is common salt, (1) when an acid reacts with a metal carbonate,
sodium chloride. (2) when an acid reacts with a metal bicarbonate,
b. Rock salt is sodium chloride found in the form of (3) when an acid reacts with a metal oxide.
rocks. It is yellowish in colour due to the presence b. You are given three solutions A, B and C with pH
of impurities. values, 2,10 and 13 respectively. Which solution
c. Sodium hydroxide, H2 gas and chlorine gas will has the highest hydrogen ion concentration among
be formed: the three and state the nature ‘acidic or basic’ of
2NaCl (aq) + 2H 2 O (l) $ 2NaOH (aq) + H 2 (g) + Cl 2 (g) each solution.
Ans : [CBSE 2012]
119. a.Explain why is hydrochloric acid a strong acid and
acetic acid, a weak acid. How can it be verified? a. (1)Na2CO3 + H2SO4(dil) $ Na2SO4 + H2O + CO2
b. Explain why aqueous solution of an acid conducts (2) 2NaHCO3 + H2SO4(dil) $ Na2SO4+ H2O + CO2
electricity. (3) MgO + H2SO4 $ MgSO4 + H2O
c. You have four solutions A, B, C and D. The pH of b. ‘A’ has more H+ ion concentration among the
solution A is 6, B is 9, C is 12 and D is 7. three.
(1) Identify the most acidic and most basic A’ is acidic.
solutions respectively. ‘B’ is basic.
(2) Arrange the above four solutions in the ‘C’ is strongly basic.
increasing order of H+ ion concentration.
122. a.A metal compound ‘X’ reacts with dilute H2SO4
(3) State the change in colour of pH paper on
to produce effervescence. The gas evolved
dipping in solution C and D.
extinguishes a burning candle. If one of the
Ans : [CBSE 2012] compound formed is calcium sulphate, then what
a. Hydrochloric acid is a strong acid because it is is ‘X’ and the gas evolved? Also write a balanced
completely ionised in its aqueous solution. Acetic chemical equation for the reaction which has
acid is only partially ionised. HCl reacts with occurred.
Mg vigorously whereas acetic acid reacts less b. (i) Name one antacid. How does it help to relieve
vigorously. indigestion in stomach?
b. Aqueous solution of acid contain ions which carry (ii) A farmer treats the soil with quicklime or
current, it conducts electricity. calcium carbonate. What is the nature of the
c. (1) With pH = 6 ‘A’ is most acidic, soil? Why does the farmer treat the soil with
With pH = 12, ‘C’ is most basic. quicklime?
(2) C < B < D < A is the increasing order of H+ Ans : [CBSE 2012]
ion concentration.
This is is calcium carbonate
(3) pH paper will turn blue in ‘C’ with pH = 12,
CaCO 3 (s) + H 2 SO 4 (dill) $ CaSO 4 (aq) + H 2 O (l) + CO 2 (g)
basic pH paper will turn green in D with pH
The gas evolved is carbon dioxide (CO2).
= 7, neutral.
b. (i) NaHCO3(baking soda) is an antacid. If
120. (a) Dry pellets of a base ‘X’ when kept in open neutralises excess of HCl in stomach and
absorbs moisture and turns sticky. The compound gives relief.
is also formed by chlor-alkali process. Write the (ii) The nature of soil is acidic. The farmer treats
chemical name and formula of X. Describe chlor- the soil with quicklime (basic in nature) to
alkali process with balanced chemical equations. neutralise the acidity of soil and make it fit
Name the type of reaction occurs when X is for crops.
treated with dilute hydrochloric acid. Write the
123. a. Tooth enamel is one of the hardest substance in
our body. Explain the changes in pH of mouth
which indicates tooth decay. How does tooth
paste help in preventing it?
b. What is the nature of salt if pH of its aqueous
solution is greater than 7? Name the acid and
base that would be used to prepare the following
salts:
(i) Potassium sulphate, (ii) Ammonium chloride
Ans : [CBSE 2012]
a. Tooth enamel is made up of Ca3(PO4)2 calcium
phosphate. pH = 5.5 causes tooth decay because
Ca3(PO4)2 reacts with acid. Tooth paste are basic,
neutralises the acid in mouth and prevents tooth
decay.
b. The salt is basic if pH > 7.
(i) KOH and H2SO4 are needed to prepare K2SO4.
(ii) NH4OH and HCl are needed to prepare
NH4Cl.
125. What are strong acids and weak acids? In the following
list of acids, separate strong acids from weak acids:
hydrochloric acid, citric acid, acetic acid, nitric acid,
formic acid, sulphuric acid.
Ans : [CBSE 2012]
Strong acids are those acids which are completely
ionised in aqueous solution e.g.-,
HCl(aq) $ H+(aq) + Cl- (aq)
Weak acids do not ionise completely in aqueous
solution:
CH3COOH(aq) CH 3 OO- (aq) + H+ (aq)
Strong acids: Hydrochloric acid, Nitric acid, Sulphuric
acid.
Weak acids: Citric acid, Acetic acid, Formic acid.
Chap 1 : Chemical Reactions and Equations www.cbse.online
CHAPTER 1
Chemical Reactions and Equations
Ans : [CBSE 2011] 26. Complete and balance the following equation:
Fermentation of fruit juice is a chemical change. Fe2O3 + Al $
Ans : [CBSE 2010]
17. Is burning of a candle wax a physical or a chemical
change? Fe2O3 + 2Al $ 2Fe + Al2O3
Ans : [CBSE 2011] 27. Balance the following chemical equation:
Burning of a candle wax is a chemical change. Pb(NO3)2 $ PbO + NO2 + O2
Ans : [CBSE 2009]
18. Write a balanced equation for the chemical reaction
that can be characterised as precipitation reaction. 2Pb(NO3)2 Heat 2PbO + 4NO2 + O2
Ans : [CBSE 2011] 28. Identity the type of reaction in the following example:
AgNO3(aq) + NaCl(aq) $ AgCl(s) + NaNO3(aq) Na2SO4(aq) + BaCl2(aq) $ BaSO4(s) + 2NaCl(ag)
It is a precipitation reaction. Ans : [CBSE 2008(C)]
19. State the main difference between endothermic Double displacement reaction.
reaction and an exothermic reaction.
29. Identify the type of reaction in the following example:
Ans : [CBSE 2011] Fe(s) + CuSO4(aq) $ FeSO4(aq) + Cu(s)
In endothermic reaction, heat is absorbed. In Ans : [CBSE 2008(C)]
exothermic reaction, heat is evolved.
Displacement reaction.
20. What happens chemically when quick lime is added to
30. Identify the type of reaction in the following example:
water filled in a bucket?
2H2(g) + O2(g) $ 2H2O(l)
Ans : [CBSE 2010, 2008]
Ans : [CBSE 2008(C)]
Calcium hydroxide (Slaked lime) is formed with
Combination reaction.
evolution of heat and hissing sound.
CaO(s) + H2O(l) $ Ca(OH)2(aq) 31. Balance the given chemical equation:
Al(s) + CuCl2(aq) $ AlCl3(aq) + Cu(s)
21. Define oxidation and reduction.
Ans : [CBSE 2008(C)]
Ans : [CBSE 2011, 2010]
2Al(s) + 3CuCl2(aq) $ 2AlCl3(aq) + 3Cu(s)
Oxidation is a process in which oxygen is added or
loss of electrons take place. Reduction is a process in 32. Balance the given chemical equation:
which hydrogen is added or gain of electrons takes FeSO4(s)
Heat
Fe2O3(s) + SO2(g) + SO3(g)
place.
Ans : [CBSE 2008]
22. Give an example of double displacement reaction 2FeSO4(s)
Heat
Fe2O3(s) + SO2(g) + SO3(g)
(only with complete balanced equation).
Ans : [CBSE 2011, 2010] 33. Balance the following chemical equation:
Fe(s) + H2O(g) $ Fe3O4(s) + H2(g)
BaCl2(aq) + H2SO4(dil.) $ BaSO4(s) + 2HCl(aq)
It is a double displacement reaction. Ans :
3Fe(s) + 4H2O(g) $ Fe3O4(s) + 4H2(g)
23. On what basis is a chemical reaction balanced?
Ans : [CBSE 2010, 2008] 34. On adding dilute hydrochloric acid to copper oxide
powder, the solution formed is blue green. Predict the
Chemical equation is balanced on the basis of law of
new compound formed which imparts a blue green
conservation of mass.
colour to the solution.
24. What change in colour is observed when white silver Ans : [CBSE 2008]
chloride is left exposed to sun¬light? State the type of CuO + 2HCl $ CuCl2 + 2H2O
chemical reaction in this change. Copper chloride solution imparts blue green colour to
Ans : [CBSE 2010, 2009] the solution.
Grey coloured silver metal is formed and pungent
35. Why is respiration considered as exothermic process?
smelling chlorine gas is evolved.
sunlight Ans : [CBSE 2008]
2AgCl(s) 2Ag(s) + Cl2(g)
Respiration is an exothermic process because energy is collected by the method as shown in figure.
is given out in respiration.
(Blue) (Pale Green) (Reddish brown) (b) The reaction is an example of double displacement
40. Name the reducing agent in the following reaction: (precipitation) reaction.
3MnO2 + 4A1 $ 3Mn + Al2O3
State which is more reactive, Mn or Al and Why? 45. (a) Write a balanced chemical equation for the process
of photosynthesis.
Ans : [CBSE 2016, 2015]
(b) When do desert plant take up carbon dioxide and
Al is the reducing agent. Al is more reactive than Mn. perform photosynthesis.
Reason: It is because Al is displacing Mn from MnO2. Ans : [CBSE 2015]
sunlight
41. “We need to balance a skeleton chemical equation”. a. 6CO2(g) + 6H2O(l) chlorophyll C6H12O6(aq) + 6O2(g)
Give reason to justify the statement. b. Desert plant take up carbon dioxide and perform
Ans : [CBSE 2015] photosynthesis at night.
We must balance a skeletal equation so as to ensure 46. Two reactions are given below:
that the reaction follows ‘Law of conservation of mass’. a. 2KI + Cl2 $ 2KCl + I2
The total mass of reactants must be equal to the total b. 2K + Cl2 $ 2KCl
mass of products, that is why all reactions should he Identify the type of reaction, giving justification in
balanced. each case.
42. A metal is treated with dilute H2SO4. The gas evolved Ans : [CBSE 2015]
a. Displacement reaction because Cl2 is displacing I2 answer the questions which follow:
Heat
from KI solution. (i) CuO + H2 Cu + H2O
b. Combination reaction because K reacts with Cl2 (ii) ZnO + C
Heat
Zn + CO
to form potassium chloride. a. Name the substances that are oxidised and
reduced respectively in each case,
47. On heating copper powder in air, the surface of copper
b. Identify the reducing agent in each case.
powder becomes coated with black CuO. How can this
black coating be converted into brown copper? Write Ans : [CBSE 2013]
chemical equation for the reaction that occurs during a. H2 is getting oxidised to H2O, CuO getting reduced
the colour change. to Cu.
Ans : [CBSE 2015] b. H2 is reducing agent in (i) reaction whereas C is
Heat reducing agent in second reaction.
2Cu + O2 2CuO
(Black)
54. What is a redox reaction? Identify the substances
Copper oxide on heating with H2 will change back to
oxidised and the substance reduced in the following
reddish brown copper metal.
Heat reactions:
CuO(s) + H2(g) Cu(s) + H2O(g) a. MnO2+ 4HCl $ MnCl2 + Cl2 + H2O
48. What is observed when a solution of potassium iodide b. CuO + H2 $ Cu + H2O
is added to a solution of lead nitrate? Name the type Ans : [CBSE 2012]
of reaction. Write a balanced chemical equation to Redox reaction is a reaction in which oxidation and
represent the above chemical reaction. reduction takes place simultaneously.
Ans : [CBSE 2014, 2013] c. HCl is the substance oxidised, MnO2 is the
Yellow precipitate is formed due to formation of lead substance getting reduced.
iodide. d. H2 is getting oxidised, CuO is getting reduced.
It is a precipitation as well as double displacement 55. Write balanced chemical equations for the following
reaction. reactions:
Pb (NO 3) (aq) + 2KI (ag) $ PbI 2 (s) + 2KNO 3 (aq) a. Silver bromide on exposure to sunlight decomposes
Yellow ppt
49. Write a balanced chemical equation for the process of into silver and bromine.
photosynthesis and the conditions of reaction giving b. Sodium metal reacts with water to form sodium
physical state of all substances. hydroxide and hydrogen gas.
Ans : [CBSE 2014) Ans : [CBSE 2012]
sunlight
6CO 2 (g) + 6H 2 O (l)
sunlight
C 6 H 12 O 6 (aq) + 6O 2 (g) a. 2AgBr(s) 2Ag(s)+ Br2(g)
chlorophy II
b. 2Na(s) + 2H2O(l) $ 2NaOH(l) + H2(g)
50. Give one example of each:
a. Chemical reaction showing evolution of a gas. 56. Identify the type of reaction from the following
b. Change in colour of a substance during chemical equations:
reaction. a. CH4 + 2O2 $ CO2 + 2H2O
b. Pb(NO3)2 + 2KI $ PbI2 + 2KNO3
Ans : [CBSE 2013]
c. CaO + H2O $ Ca(OH)2
a. 2K(s) + 2H2O(l) $ 2KOH(aq) + H2(g) d. CuSO4 + Zn $ ZnSO4 + Cu
Heat
b. FeSO4.7H2O(aq) FeSO4(s) + 7H2O(l) Ans : [CBSE 2012]
(Pale green) (Dirty white)
a. Oxidation reaction
51. Translate the following statement into chemical b. Double displacement reaction
equation and then balance it. “A metal in the form of c. Combination reaction
ribbon burns with a dazzling white flame and changes d. Displacement reaction
into white powder.”
Ans : [CBSE 2013] 57. Write balanced equation for the reaction between Mg
Burning
and hydrochloric acid. Name the product obtained,
2Mg(s) + O2(g) 2MgO(s) + Light + Heat identify the type of reaction.
52. It has been found that marble of Taj is getting corroded Ans : [CBSE 20i2]
due to development of industrial areas around it. Mg(s) + 2HCl(dil) $ MgCl2(aq) + H2(g)
Explain this fact giving a chemical equation. Magnesium chloride and hydrogen gas are formed in
Ans : [CBSE 2013] this reaction. It is a displacement reaction.
Taj is made up of CaCO3 which reacts with acid 58. a. What is colour of ferrous sulphate crystals? How
formed by pollution of SO2(g) and NO2 from Mathura does this colour change after heating?
refinery and other industries. b. Name the products formed on strongly heating
CaCO3 + 2H2SO4 $ CaSO4 + CO2 + 2H2O ferrous sulphate crystals. What type of chemical
CaCO3 + 2HNO3 $ Ca(NO3)2 + H2O + CO2 reaction occurs in this change?
53. Consider the chemical equations given below and Ans : [CBSE 2012.2009]
a. FeSO 4 $ 7H 2 O crystals are pale green in colour.
They become dirty white on heating. 64. Translate the following statements into chemical
b. Ferric oxide, sulphur dioxide and sulphur trioxide equations and then balance them:
are formed: a. Hydrogen gas combines with nitrogen to form
Heat
2FeSO4(s) Fe2O3(s) + SO2(g) + SO3(g) ammonia.
It is a decomposition reaction. b. Hydrogen sulphide gas burns in air to give water
and sulphur dioxide.
59. Reaction of compound X with aluminium is used to c. Barium chloride reacts with aluminium sulphate
join railway tracks or cracked machine parts. to give aluminium chloride and a precipitate of
a. Identify the compound. barium sulphate. State the two types in which
b. Name the reaction. this reaction can be classified.
c. Write a balanced chemical equation for the d. Potassium reacts with water to give potassium
reaction. hydroxide and hydrogen gas.
Ans : [CBSE 2012] Ans : [CBSE 2012]
a. The compound X is Fe2O3 (Ferric oxide) or Iron a. 3H2(g) + N2(g) $ 2NH3(g)
(III) oxide. b. 2H2S(g) + 3O2(g) $ 2H2O(l) + 2SO2(g)
b. It is called Thermite Reaction. c. 3BaCl 2 (aq) + Al 2 (SO 4) 3 (aq) $ 3BaSO 4 (s) + 2AlCl 3 (aq)
Heat
c. 2Al(s) + Fe2O3(s) Al2O3(s) + 2Fe(l) This reaction can be classified as a double
displacement reaction as the two reacting species
60. Using balanced chemical equation explain the (BaSO4, Al2SO4)3 undergoes mutual exchange
difference between a displacement reaction and a of ions. It can also be classified as precipitation
double displacement reaction. reaction, since a white ppt. of BaSO4 is obtained.
Ans : [CBSE 2012, 2011] d. 2K(s) + 2H2O(l) $ 2KOH(aq) + H2(g)
Displacement reaction: A reaction in which a more
65. When a metal X is added to salt solution of metal Y,
reactive element displaces a less reactive element from
the following chemical reaction takes place:
its salt solution e.g.,
2KBr(aq) + Cl2(g) $ 2KCl(aq) + Br2(aq) Metal X + Salt solution of Y $
Double displacement reaction: A reaction in which Salt solution of X + Metal Y
two compounds exchange their ions to form two new Mention the inference you draw regarding the
compounds e.g., reactivity of metal X and Y and also the type of
KOH + HNO3 $ KNO3 + H2O reaction. State the reason of your conclusions.
61. Give an example each for thermal decomposition Ans : [CBSE 2012]
and photochemical decomposition reactions. Write X is more reactive than Y because , X displaces Y from
balanced chemical equation also. its salt solution. Hence, this reaction is an example of
Ans : [CBSE 2012] displacement reaction.
Thermal decomposition: 66. Identify the type of each of the following reactions:
Heat
ZnCO3(s) ZnO(s) + CO2(g) a. A reaction in which a single product is formed
Photochemical decomposition: from two or more reactants.
sunlight
2AgI(s) 2Ag(s) + I2(g) b. The reaction mixture becomes warm.
c. An insoluble substance is formed.
62. Why are decomposition reactions called the opposite d. External surface of the container in which reaction
of combination reactions? Give chemical equations for takes place becomes cold.
these reactions. Ans : [CBSE 2012]
Ans : [CBSE 2012]
a. Combination reaction
In decomposition reactions, a compound is broken b. Exothermic reaction
down into one or more elements or compounds e.g., c. Precipitation reaction (Double displacement
Heat
CaCO3(s) CaO(s) + CO2(g) reaction)
In combination reactions, two or more elements d. Endothermic reaction
or compounds combine to form a new compound.
Therefore, decomposition reactions are opposite to 67. A solution of potassium chloride when mixed with
combination reactions e.g., silver nitrate solution, an insoluble white substance is
3Mg(s) + N2(g)
Burns
Mg3N2(s) formed. Write the chemical reaction involved and also
mention the type of reaction.
63. Why does the colour of copper sulphate solution Ans : [CBSE 2012, 2011, 2010]
changes when an iron pin is dipped in it?
AgNO3(aq) + KCl(aq) $ AgCl(s)+KNO3(aq)
Ans : [CBSE 2012] (White ppt.)
CHAPTER 7
Control and Coordination
6. State the function of: 13. Which gland secretes growth hormone in human
a. gustatory receptors beings?
b. olfactory receptors Ans : [CBSE 2013]
Ans : [CBSE 2014] Pituitary gland.
a. To detect taste.
14. Which mechanism control timing and amount of
b. To detect smell.
hormone released?
7. Which part of the nervous system controls reflex arcs? Ans : [CBSE 2013]
Ans : [CBSE 2014] Feedback mechanism.
Spinal cord.
15. Define‘Chemotropism’.
8. What type of movement is shown by mimosa plant Ans : [CBSE 2013]
leaves when touched with a finger? Chemotropism is a nastic response towards the
Ans : [CBSE 20141 chemicals like the germination of pollen tube when
Nastic movement. pollen grain lands on stigma.
56. Name the hormone synthesised at the shoot tips. How 58. Give the function(s) of the following plant hormones:
does it help the plant to respond to light? a. Auxins
b. Gibberellins
Ans : [CBSE 2010]
c. Cytokinins
Auxin is synthesised at the shoot tips when growing d. Abscisic acid
plant detects light and helps the cells to grow longer. e. Ethylene
When light is coming from one side of the plant, Ans : [CBSE 2015]
auxin diffuses towards the shady side of the shoot. a. Auxins promote cell elongation, root formation,
This concentration of auxin stimulates the cells to cell division, etc. It also promote fruit growth.
grow longer on the side of the shoot which is away b. Gibberellins stimulate stem elongation, seed
from light. Thus, the plant appears to bend towards germination and flowering.
light. c. Cytokinins help in breaking the dormancy of
seeds and buds. They delay ageing in leaves. They
also promote the opening of stomata.
d. Abscisic acid promotes falling of leaves and fruits.
e. Ethylene promotes ripening of fruits.
CHAPTER 4
Carbon and Its Compounds
5. Write the formula of first two members of homologous 10. Write the next homologue of each of the following:
series whose functional group is —CHO. a. C2H4
Ans : [CBSE 2017] b. C4H6
Ans : [CBSE 2016]
1. Methanal (1) C3H6, CH2=CH—CH3
(2) C5H8, HC=C—CH2—CH2—CH3
16. Which element exhibits the property of catenation to 26. Carbon has four electrons in its valence shell. How
maximum extent and why? does carbon attain stable electronic configuration?
Ans : [CBSE 2016] Ans : [CBSE 2015]
Carbon because it can form strong covalent bond with Carbon can share four electrons to acquire stable
other carbon atoms due to smaller size. electronic configuration.
17. Write the name and formula of fourth member of 27. Write the name and formula of 2nd member of
alkane series. homologous series having general formula CnH2n.
Ans : [CBSE 2016] Ans : [CBSE 2015]
18. What is a homologous series of carbon compounds? 28. Write the name and formula of 2nd member of
homologous series having general formulaC n H 2n + 2 .
Ans : [CBSE 2016]
Ans : [CBSE 2015]
Homologous series is series of organic compounds
which have same functional group and similar chemical CH3—CH3, Ethane
properties and each successive member has more — 29. Write the name and formula of 2nd member of
CH2 unit than the previous one. homologous series having general formula C n H 2n - 2 .
19. A colourless gas X has a formula C3H6. It decolourises Ans : [CBSE 2015]
bromine water. Write the chemical formula of ‘X’. HC / C—CH3, Propyne
Ans : [CBSE 2016]
30. Write the number of covalent bonds in the molecule
CH2=CH—CH3, Propene of propane, C3H6.
20. Draw the structural formula of methanoic acid. Ans : [CBSE 2015]
Ans : [CBSE 2016]
has 10 covalent bonds
Methanoic acid
31. Write the number of covalent bonds in the molecular
21. A molecule of ammonia has the formula NH3. Predict formula of butane, C4H10.
the total number of bonds present around nitrogen
Ans : [CBSE 2015]
atom.
Ans : [CBSE 2016]
has 13 covalent bonds
, it has three covalent bonds
Methanoic acid
56. Write the name and formula of the 2nd member of the
series of carbon compounds whose general formula is 64. Butanone has four carbon per molecule of a compound.
CnH2n+1—OH. Name the functional group present in it.
Ans : [CBSE 2012] Ans : [CBSE 2011]
57. Write the name and formula of 2nd member of the 65. Name the following compound:
series of carbon compounds whose general formula is
CnH2n.
Ans : [CBSE 2012]
CH2=CH—CH3, Propene
Ans : [CBSE 2011]
58. State the difference between oils and fats.
Ans : [CBSE Sample Paper 2012] 1-Hexyne
69. Name the compound formed when ethanol is warmed b. Sodium ethoxide and hydrogen gas is formed.
with ethanoic acid in the presence of few drops of 2C2H5OH + 2Na $ 2C2H5ONa + H2
cone. H2SO4.
Ans : [CBSE 2009 (C)] 76. State reasons to explain why covalent compounds:
a. are bad conductors of electricity?
Ethyl ethanoate
Con. H 2 SO 4 b. have low melting and boiling points?
CH3COOH + CH3CH2OH T
Ans : [CBSE 2016]
CH3COOC2H5 + H2O a. Covalent compounds do not form ions, hence they
70. What is the difference in the molecular formula of
are bad conductor of electricity.
any two consecutive members of homologous series of b. Covalent compounds have weak intermolecular
organic compounds? forces of attraction, therefore, have low melting
and boiling points.
Ans : [CBSE 2008 (C)]
The difference between successive members of 77. What is homologous series? Write the name and draw
homologous series is of —CH2 unit. the structure of the second member of alkene series.
Ans : [CBSE 2016]
TWO MARKS QUESTIONS a. The series of organic compounds having same
functional group and similar chemical properties
is called homologous series.
71. Draw the structural formulae of the possible isomers b.
for the compound with molecular formula C3H6O.
Ans : [CBSE Sample Paper 2017]
72. Explain why cannot we have isomers of first three 78. List two characteristics of covalent compounds.
members of alkane family. Ans : [CBSE 2015]
Ans : [CBSE Sample Paper 2017, CBSE 2015] (i) They have low melting and boiling point.
It is because branching is not possible with carbon (ii) They do not conduct electricity.
atoms, that is why, there are no isomers till propane.
79. Name an element, other than carbon, which exhibits
73. Write balanced equations for the burning of (a) property of catenation up to seven or eight atoms. Are
methane (b) ethane in air. these compounds stable?
Ans : [CBSE 2017] Ans : [CBSE 2015]
(a) CH4(g) + 2O2(g) $ CO2(g) + 2H2O(l) Si and Sulphur (S8).
(b) 2C2H6(g) + 7O2(g) $ 4CO2(g) + 6H2O(l) No, these compounds are not stable, rather they are
reactive.
74. Compare the structures of benzene and cyclohexane
by drawing them. 80. Select alkenes and alkynes from the following:
C2H4, C3H4, C2H2, C4H8
Ans : [CBSE 2017]
Ans : [CBSE 2015,2014]
Alkenes C2H4, C4H3 Alkynes C3H4, C2H2 88. Give the electron dot structure of chloro-methane. Also
write the formula and the name of next homologue of
81. Why are detergents preferred over soaps for washing it.
clothes in hard water? Explain.
Ans : [CBSE 2015]
Ans : [CBSE 2015,2014]
Detergents work well even with hard water because
their calcium and magnesium salts are soluble in
water. They do not form scum.
T
CH3COOC2H5 + H2O
89. The structural formula of an ester is
87. What are soaps? Why do they form scum with hard 92. Explain the action of soap in removing an oily spot
water? from a piece of cloth.
Ans : [CBSE 2013] Ans : [CBSE 2011]
Soaps are sodium or potassium salts of fatty acids e.g. Cleansing action of soap: Soap has ionic end which
sodium stearate. They react with Ca2+ and Mg2+ ions is hydrophilic, interacts with water while carbon
in hard water to form calcium and magnesium salt chain is hydrophobic interacts with oil, grease. The
of fatty acids which are insoluble in water and called soap molecules orient themselves in a cluster in which
scum. hydrophobic tails are inside the cluster and ionic ends
face outside. called homologous series.
These cluster are called micelles. These attract oil C2H6O(C2H5OH) and CH4O(CH3OH) belong to same
which is washed away by water. homologous series.
93. Draw electron dot structures of (i) C2H4 (ii) C2H5OH. 98. With the help of a suitable example explain in brief the
process of hydrogenation mentioning the conditions of
Ans : [CBSE 2011]
the reaction and also state any one physical property
of substances changes due to hydrogenation.
Ans : [CBSE 2010]
i.
443 K
c. CH3COOH + NaHCO3 $
CH3COONa + H2O + CO2
Con. H 2 SO 4
+ H2O C2H5OH + CH3COOH
CH3COOC2H5 + H2O
105. Complete the following reactions: Ester
CH3COOC2H5 + H2O
Activity:
To carry out esterification reaction.
• Take 2 mL of ethanol (100% alcohol) in a test
tube.
• Add 2 mL of glacial acetic acid.
• Add few drops of conc. H2SO4.
• Set the apparatus as shown in diagram. Covalent compounds Ionic compounds
• Heat the mixture in test tube in water bath for 5
to 10 minutes observe what happens. 1. They are bad con- They are good conduc-
• Observation: Pleasant fruity smell is observed. ductor of electricity. tor of electricity.
• Conclusion: Ester is formed. 2. They have low They have high melting
melting and boiling and boiling points.
points.
443K
functional group and similar chemical properties
128. The structural formula of an ester is is called homologous series.
b. C5H10 has higher molecular mass, more surface
area, more van der Waal’s forces of attraction,
hence higher boiling point than C4H8.
c. C3H6 < C4H8 < C5H10
Write the structural formula of the acid and the
132. The general formula of three compounds A, B and C
alcohol from which it might be prepared. Name the
is C n (H 2n . ‘B’ has highest boiling point and ‘C’ has
process of formation of an ester.
lowest boiling point.
Ans : [CBSE 2016] a. Mention the type of compounds A, B, C.
b. Which of these have minimum number of carbon
atoms?
c. Name the homologous series to which A, B and
C belong. this reaction is referred to as substitution reaction.
Ans : [CBSE 2016] Ans : [CBSE 2015]
a. A, B, C are unsaturated compounds.
b. C has minimum number of carbon atoms..
c. They belong to alkene homologous series.
b. , , C2H4
c. , , C2H2
137. Convert CH4 into CC14 by substituting hydrogen
atom with chlorine atom in successive reactions. Why
141. Why is homologous series of carbon compounds so
X
called? Write the chemical formula of two consecutive KMnO 4 /KOH
members of any two homologous series and state the CH3CH2OH + 2[O] CH3COOK
part of these compounds that determines their (a) H+
CH3COOH + K+
physical and (b) chemical properties.
X is CH3COOC2H5, ethyl ethanoate.
Ans : [CBSE 2015]
Homologous means members of same family that 145. What is meant by homologous series of carbon
is why series of carbon compounds having same compounds? Write the general formula of (i) alkenes,
functional group and similar properties is called and (ii) alkynes. Draw the structures of the first
homologous series. member of each series to show the bonding between
Homologous series of alcohol. the two carbon atoms.
CH3OH Methanol Ans : [CBSE 2014]
C2H5OH Ethanol The series of organic compounds having same
CH3— and C2H5— groups determine physical functional group and similar chemical properties is
properties and —OH group determines chemical called homologous series.
properties. Homologous series of aldehyde. i. Alkenes CnH2n
CH3OH Ethanol
C2H5OH Propanal
Here, CH3—and C2H5— groups determine physical
properties while —CHO group determines chemical
properties.
ii. Alkynes CnH2n–2
142. What are esters? How are they prepared? List two
uses of esters.
Ans : [CBSE 2014]
Esters are pleasant fruity smelling compounds with 146. Write the chemical equations to show what happens
general formula R—COOR’. They are prepared by when
reaction of carboxylic acid and alcohol in presence a. an ester reacts with a base?
of cone. H2SO4. b. methane is treated with chlorine in the presence
Conc. H SO
CH3COOH + C2H5OH
2 4
of sunlight?
CH3COOC2H5 + H2O c. ethanol reacts with ethanoic acid in the presence
Uses of sulphuric acid?
i. They are used in cold drinks and ice creams as Ans : [CBSE 2014]
synthetic flavours.
ii. They are used in perfumes. a. CH3COOC2H5 + NaOH
CH3COONa + C2H5OH
143. State the meaning of functional group in an organic Sunlight
b. CH4 + Cl2 CH3Cl + HCl
compound. Write the formula of the functional group
present in alcohols, aldehydes, ketones and carboxylic c. CH3COOH + C2H5OH
Conc. H 2 SO 4
a. CH3CH2OH
Conc. H 2 SO 4
CH2=CH2 + H2O a. It is due to tetravalency of carbon and property of
443 K
catenation shown by carbon to maximum extent.
b. 2CH3COOH + Na2CO3 $ b. Air holes must be kept open fully so that complete
2CH3COONa + H2O + CO2 combustion of fuel takes place producing blue
flame.
150. What is meant by isomers? “We cannot have isomers c. Some of detergents are not bio¬degradable, they
of first three members of alkane series.” Give reason create water pollution.
to justify this statement. Draw the structures of two
isomers of pentane, C5H12. 154. a.Why are covalent compounds generally poor
Ans : [CBSE 2013] conductors of electricity?
b. Name the following compound:
Isomers are those compounds which have same
molecular formula but different structural formula.
CH3– CH2– CH2– CH2– CH3
Pentane
i.
152. a.What is meant by a functional group in an organic
compound? Name the functional group present in
(1) CH3CH2OH
(2) CH3COOH
b. State one point of difference between soap and
synthetic detergent. ii.
Ans : [CBSE2009]
a. Functional group is an atom or group of atoms
which determine chemical properties of organic
iii.
Alkene CnH2n
formed when the ester CH3COOC2H5 undergoes A is CH3COOH, ‘B’ is CH3COOCH2CH3, *C’ is
saponification. CH3COONa, ‘D’ is CO2, ‘E’ is Na (Sodium metal).
Ans : [CBSE 2014, 2013]
166. An organic compound “X’ on heating with cone.
a. Vinegar is 5-8% solution of acetic acid (Ethanoic H2SO4 forms a compound ‘Y’ which on addition of
acid) in water. It can be made by fermentation of one molecule of hydrogen in the presence of nickel
ethanol in presence of oxygen. forms a compound ‘Z’. One molecule of compound
b. Glacial acetic is pure (100%) acetic acid. Its ‘Z’ on combustion forms two molecules of CO2 and
melting point is 290 K. three molecules of H2O. Identify giving reasons the
c. They do not ionise completely in aqueous solution. compounds X’, ‘Y’ and ‘Z’. Write the chemical
d. CH3COOC2H5 + NaOH equations for all the chemical reactions involved.
CH3COONa + C2H5OH Ans : [CBSE 2013]
Sodium ethanoate Ethanol Conc. H 2 SO 4
CH3CH2OH heat
CH2 = CH2 + H2O
‘X’ ‘Y’
164. a. How will you bring out following reactions? Write Ni
CH2 = CH2 + H2 CH3 – CH3
‘Y’ ‘Z’
C2H6 + (7/2)O2 2CO2 + 3H2O Ethanol Ethanoic acid
‘Z’ on combustion gives 2CO2 and 3H2O so hydrocarbon
(a) Physical taste: It is It is solid below 290
‘Z’ must be ethane. “Y’ on addition of H2 gives ethane
liquid. K
so ‘Y’ must be ethene. “X’ in presence of cone. H2SO4
dehydrates to ethene i.e., ‘X’ is ethanol.
(b) Taste: It has It has sour taste.
167. List in tabular form three physical and two chemical burning taste.
properties on the basis of which ethanol and ethanoic
acid can be differentiated. (c) NaHCO3 test It does It liberates CO2 gas.
not react.
Ans : [CBSE 2012]
(d) Ester test: It reacts It reacts with alcohol
Ethanol Ethanoic acid with carboxylic acid to form pleasant to
to form easter form fruity smelling
Physical Properties esters.
1. It has Specific smell It has vinegar (ii)
like smell. CH3CH2OH +
Conc. H 2 SO 4
CH2=CH2 + H2O
443 K
2. It has burnnrg It has sour taste
taste 170. Give reasons for the following:
a. Element carbon forms compound mainly by
covalent bonding.
3. Pure ethanol is liquid Pure acetic b. Diamond has high melting point.
of room temprature. acid is solid c. Graphite is good conductor of electricity.
below 290 K. d. Acetylene bums with sooty flame.
Chemical Properties e. Kerosene does not decolourise bromine water
whereas cooking oil does.
4. It does not It turn-s blue
change colour litmus red. Ans : [CBSE 2011]
of litmus a. It is because carbon can neither lose 4 electrons
nor gain 4 electrons. It can share four electrons to
5. It does not react with It liberstes
form covalent bonds.
NaHCO3 CO2 with
b. Diamond has strong C—C bonds and compact 3-D
NaHC03.
structure in which one carbon atom is covalently
bonded to other four carbon atoms therefore, has
168. What are detergents chemically? List two merits and
high melting point.
two demerits of using detergents for cleansing. State c. In graphite, one carbon atom is bonded to other
the reason for the suitability of detergents for washing three carbon atoms. Remaining one electron on
even in case of water having calcium and magnesium each carbon is free to move due to which graphite
ions. conducts electricity.
Ans : [CBSE 2012] d. Acetylene has high carbon content, therefore,
Detergents are sodium or potassium salts of sulphonic partial oxidation causes it to bum with sooty or
acids of benzene or sulphates of unsaturated smoky flame.
hydrocarbons like alkenes with —SO3Na or —SO4Na e. Kerosene is a saturated compound, therefore,
group. does not decolourise bromine water.
Merits:
They are more effective than soaps.
They work well even with hard water.
Demerits:
a. They are expensive.
b. Some of them create water pollution.
CHAPTER 12
Electricity
17. What is the lowest resistance that can be obtained 23. Why is tungsten metal selected for making filaments
by combining four coils of resistances 4 W , 8 W , 12 W of incandescent lamps?
and 24 W ? Ans : [CBSE 2005]
Ans : [CBSE 2010] Tungsten has high resistance and high melting point.
If the resistances are combined in parallel then we
24. A wire of resistance 5 W is bent in the form of a closed
shall get the lowest resistance. In parallel combination:
circle. What is the resistance between two points at
1 = 1 + 1 + 1 + 1 the ends of any diameter of the circle?
R R1 R2 R3 R 4
Ans : [CBSE 2005]
= 1+1+ 1 + 1
4 8 12 24 R = 5W
It can be assumed as two semi circular elements are
= 6 + 3 + 2 + 1 = 12 = 1 connected across diameter AB .
24 24 2
Total resistances of couple wire 5 W . Resistance of two
R = 2W
semicircular elements = 5 W
2
18. Nichrome is used to make the element of electric
Both the elements are connected in parallel.
heater. Why?
Ans : [CBSE 2010] 1 = 1 + 1 =2+2= 4
Rl R1 R2 5 5 5
Nichrome is used to make element of electric heater
because nichrome is an alloy which has high melting or Rl = 5 W
4
point and high resistances.
25. Why is much less, heat generated in long electric
cables than in filaments of electric bulbs? R = 20 ohm
Ans : [CBSE 2005]
R =rl
A
2
As heat produced = I Rt
Electric cables are made of thick good conductor or r = R A = 20 # 2 W cm
l 10
where as filaments are made of thin tungsten wire
whose resistances is high. The resistance of electric r = 4 W - cm
cables is very less. So heat produced in cable is much
lesser than filaments. TWO MARKS QUESTIONS
26. State which has a higher resistance a 50 W or a 25 W
lamp bulb and how many times?
29. The amount of charge passing through a cell in four
Ans : [CBSE 2005] second is 12 C. Find the current supplied by cell.
We have P1 = 50 W Ans : [CBSE 2016]
P2 = 25 W Given: t =4s
Let their resistances are R1 and R2 respectively.
Q = 12 C
2 2
P = V or R = V Q
R P I = = 12 A = 3 A
t 4
2 2
R1 = V W and R2 = V W
50 25 30. Calculate the number of electrons that would flow per
R1 = 25 = 1 second through the cross- section of a wire when 1 A
R2 50 2 current flows in it.
Ans : [CBSE 2016]
or R1 = 1 R2
2
Given: I = 1 A, t = 1 s
1
i.e. 50 W bulbs has resistance than 25 W bulb.
2 Q
I = & Q = I#t
t
27. Define resistivity of a material.
Ans : [CBSE 2004] Q = 1A#1s (Q = 1 coulomb)
But Q = ne
We have R =rl Q
A n = = 1C
e 1.6 # 10-19
Resistivity, r = RA
l = 6.25 # 1018 electrons
If
A = 1, l = 1 then r = R i.e. resistivity of a material 31. Name the device/instrument used to measure potential
is the resistance of a conductor of this material whose difference. How is it connected in an electric circuit?
length and area of cross- section both are unity.
Ans : [CBSE 2016]
or
Resistivity of a material is the resistance of a conductor The device which is used to measure potential
of this material whose volume is unity. difference is voltmeter. Voltmeter is connected in
parallel in an electric circuit.
I = 220 = 1 A
1100 5
28. A cylinder of a material is 10 cm long and has a cross- When heater is connected with the same source then
section of 2 cm2. If its resistance along the length be
20 ohm, what will be its resistivity in number and I = V = 220 = 2.2 A
R 100
units?
Ans : [CBSE 2004] 33. (a) What are the values of mA and mA ?
(b) Draw the symbols of battery and rheostat.
l = 10 cm, A = 2 cm2 Ans : [All India 2015]
1 mA = 1 milli ampere = 10-3 A A — Bulb (load)
1 mA = 1 micro ampere = 10-6 A B — Rheostat
C — Cell
D — Ammeter (being in series)
We have, P = 100 W
V = 250 Volt
2 2
P = V or R = V
R P Ans : [CBSE 2011]
^250h2
1W, 3W, 2W resistances are connected in series.
R = = 250 # 250 = 625 W
100 100
R = R1 + R2 + R3
45. Why do the wires connecting an electric heater to the = 1+3+2 = 6W
mains not glow while its heating element does?
I =V = 3 = 1A
Ans : [CBSE 2011] R 6 2
Connecting wire has low resistivity or good Current in each resistance is same, i.e. 1 A .
2
conductivity, i.e. resistance of these wires is negligible
Voltage across B & C = 1 # 3 = 3 Volt.
hence no heat is produced while heating element 2 2
is of an alloy whose resistivity is high, due to high
resistance heat is produced in the element. VBC = 3 Volt.
2
46. In the circuit diagram shown, the two resistance wires
A and B are of same area of cross-section and same
material, but A is longer than B. Which ammeter A1
or A2 will indicate higher reading for current? Give
reason.
Sample A B C
Resistivity 1.6 # 10 Wm 5.2 # 10 Wm 100 # 10-4 Wm
-5 -5
and R2 = r l2 = r 2l1
A2 A2
Ans : [CBSE2010]
R2 = 2 A1 = 2 2 = 4
R1 #A
2
# a. The other two bulbs will glow even if B1 gets
fused. There is no change in glow of B2 and B3.
R2 = 4R1
Here V = 4.5 V
53. (a) What material is used in making the filament of and I = 3A
an electric bulb?
(b) Name the characteristics which make it suitable RP = V = 4.5
I 3
for this.
R P = 1. 5 W
Ans : [CBSE 2010]
For parallel combination
1 = 1 + 1 + 1 Q
RP R1 R2 R3 I = or Q = I # t
t
1 = 1+1+1 Q = 0.2A # 1 hr = 0.2 # 60 # 60 A - s
1.5 R R R
= 720 C
1 = 3 & R = 4. 5 W
1.5 R 61. An electric iron draws a current of 0.5 A when the
For B 2 , 4.5 = I # 4.5 voltage is 200 volt. Calculate the amount of electric
charge flowing through it in one hour.
1A = I
Ans : [CBSE 2004]
For B 3 , 4.5 = I # 4.5 1A = I
Current in Ammeter, ^Ah = 1A + 1A = 2A We have I = 0.5 A
V = 200 volt
t = 1 hr = 3600 s
Q = I # t = 0.5 # 3600 A - s = 1800 C
Q = It
58. (a) Draw a circuit diagram to show how two resistors Given, I = 0.4 A
are connected in series.
V = 200 Volt
(b) In a circuit, if the two resistors of 5 ohm and 10
ohm are connected in series, how does the current t = 1 hr = 3600 s
passing through the two resistors compare? ` Q = 0.4 # 3600 C
Ans : [C8SE 2006) Q = 1440 C
Q =? ` Rs = 9 + 9 = 18 W
Rs and R3 are in parallel so, resistance of A is more and its length also.
1 = 1 + 1
Req. Rs R3
1 = 1 +1 = 1+2 = 3
Req. 18 9 18 18
and Req. = 6 W
I1 = P1 = 100 A = 5 = 0.45 A R =V
V 220 11 I
a. When a low current is passed for a short duration,
Current in second bulb. through a conductor, heat produced is almost
negligible and hence no appreciable change in its
I2 = P2 = 60 A = 3 A = 0.27 A
V 220 11 resistance.
b. When heavy current is passed through the
64. (a) List the factors on which the resistance of a conductor for 30 s. Conductor may be get heated
conductor in the shape of a wire depends. and its resistance and resistivity change.
(b) Why are metals good conductors of electricity
whereas glass is a bad conductor of electricity? 67. Name and define the SI unit of current. Calculate the
Give reason. number of electrons that flow through a conductor in
(c) Why are alloys commonly used in electrical 1 second to constitute a current of 1 ampere. (Charge
heating devices? Give reason. on an electron = 1.6 # 10-19 coulomb)
Ans : [CBSE 2017] Ans : [CBSE 2016]
a. Factors on which resistance of a wire depends: SI unit of current is Ampere (A)
i. Resistance is directly proportional to length. q
ii. Resistance is inversely proportional to area of I =
t
cross-section. If q = 1 C, t = 1 s
then I = 1A
R ? l, R ? 1 If 1 C charge flows in 1 s in a conductor then magnitude
A
of current is said to be 1A.
R ? l or R = r l
A A q = ne
b. Metal are good conductor due to having large q
n = = I#t
number of free electrons and their low resistivity. e e
Glass is a bad conductor because it has no free
electrons and its resistivity is higher. = 1A # 1-s19 = 100 # 1018
1.6 # 10 16
c. Alloys are commonly used in electrical heating
devices due to their high resistivity and high = 6.25 # 1018
melting point which produces more heat.
68. Electric current flows through three lamps when
65. V-I graphs for two wires A and B are shown in the arranged in (a) a series (b) a parallel. If the filament
figure. If both the wires are made of the same material of one lamp breaks. Explain what happens to the
and are of equal thickness, which of the two is of more other two lamps in both the cases.
length? Give justification for your answer. Ans : [CBSE 2015]
Ans : [CBSE 2016] a. In series combination if the filament of one lamp
We know for identical wire more length more resistance breaks then the circuit will be broken and hence
and vice versa slope of wire A is more than B. Hence other lamps stops glowing.
work is done.
Ans : [All India 2015]
Given: V = 20 Volt
W = 40 J
W = P#t
= V#I#t
b. In parallel combination of lamps if the element of Q
= V# #t
one lamp breaks then other two will continue to t
glow. or W = V#Q
40 = 20 # Q
or Q = 2C
ne = Q
Q 2
n = =
e 1.6 # 10-19
= 1.25 # 1019
R1 = r L
A1
R2 = r 2L & R2 = 2 # A1
A2 R1 A2 Ans :
R2 = 2 2 = 4
R1 #
In the given circuit 2 W, 2 W resistances are in parallel.
R2 = 4R1 Rp = 1 W
New resistance becomes four times.
R = r l = 10 W = 220 A = 10 A
A 22
b. Current in series combination
or l = 10
A r RS = 22 + 22 = 44 W
For new wire,
IS = 220 = 5 A
L2 = 3l 44
c. Current in parallel combination
A2 = 4A
1 = 1 + 1 = 2 W
R2 = r 3l = 3 r l RP 22 22 22
4A 4 A
& RP = 11 W
R2 = 3 R = 3 # 10 = 15 W
4 4 2
IP = 220 = 20 A so first bulb will consume more energy.
11
81. Draw the nature of V–I graph for a nichrome wire. (V
78. An electric kettle of 2 kW works for 2 h daily. Calculate -Potential difference, I -Current)
the (a) energy consumed in SI and commercial units A metallic wire of 625 mm length offers a 4 W
(b) cost of running it in the month of June at the rate resistance. If the resistivity of the metal is 4.8 # 10-7
of ` 3.00 per unit. ohm-metre, then calculate the area of cross-section of
Ans : [CBSE 2014] the wire.
Ans : [CBSE 2013]
(a) Given: P = 2 kW = 2000 W
V–I graph for nichrome wire
t = 2h
Electric energy, E = P # t = 2 # 2 = 4 kWh
(b) Total energy consumed in month of June (having
30 days)
Electric kettle = ^4 # 30h kWh = 120 kWh
= 120 units.
Cost of running electric kettle:
= `120 # 3 = `360
79. Two lamps, one is rated 100 W at 220 V, and the Given: l = 625 mm = 0.625 m
other 60 W at 220 V, are connected in parallel to a
R =4W
220 V supply. Find the current drawn from the supply
line. r = 4.8 # 10-7 Ohm-m
Ans : [CBSE 2014] A =?
Given: Lamp one 100 W, 220 V, Lamp 2 60 W, 220 V. R = r l or A = r l
Let their resistances are R1 and R2 A R
2 A = 4.8 # 10-7 # 0.625
R =V 4
P
= 0.75 # 10-7 m2
R1 = 220 # 220 W = 484 W
100
82. Derive the relation R = R1 + R2 + R3 when three
= 220 # 220 W = 2420 W resistors R1, R2 and R3 are connected in series in an
60 3 electric circuit.
In circuit R1 and R2 are connected in parallel. Ans : [CBSE 2012]
1 = 1 + 3 Three resistors R1, R2 and R3 are connected in series.
R 484 2420 Therefore current in each resistor is same. Let current
in the circuit is I.
R = 605 W
2
I = V = 220 # 2 A = 0.727 A
R 605
= 4+3+1 = 8 = 2 V = 5 Volt.
12 12 3
94. State the formula co-relating the electric current
R = 3 W = 1.5 W flowing in a conductor and the voltage applied across
2
it. Also, show this relationship by drawing a graph.
91. (a) State Ohm’s law. Express it mathematically. What would be the resistance of a conductor, if
(b) Write symbols used in electric circuits to represent: the current flowing through it is 0.35 ampere when the
(i) variable resistance. potential difference across it is 1.4 volt?
(ii) voltmeter. Ans : [CBSE 2004]
(c) An electric bulb is rated 220 V and 100 W. When
it is operated on 110 V, what will be the power V = IR
consumed?
i.e., V ?I
Ans : [CBSE 2010] If we plot a graph b/w V and I , it is straight line.
a. Ohm’s Law states that if the physical conditions of Graph b/w V and I :
a conductor are kept constant then current passing
through a conductor is directly proportional to
the potential difference across its ends.
V ? I or V = RI
b. A variable resistor
c. Given rating of bulb 220 V – 100 W
R=?
Power consumed = ? when V = 110 Volt Given: I = 0.35 A
2 V = 1.4 Volt.
R = V = 220 # 220 = 484 W
P 100
R = V = 1.4 Ohm
Power at 110 volt I 0.35
2
P = V = 110 # 110 R =4W
R 484
FIVE MARKS QUESTIONS
R1 = 240 # 240 W
40
R1 = 25 or R1 = 5
R2 40 R2 8
R1 < R2 i.e., Resistance of 25 W bulb is more than 40
W bulb.
96. Draw a labelled circuit diagram showing three resistors 98. a. What is meant by saying that the potential
R1, R2 and R3 connected in series with a battery difference between two points is 1 volt?
(E), a rheostat (Rh), a plug key (K) and an ammeter b. Why does the connecting cord of an electrical
(A) using standard circuit symbols. Use this circuit to heater not glow while the heating element does?
show that the same current flows through every part c. Electrical resistivity of some substance at 20°C
of the circuit. List two precautions you would observe are given below:
while performing the experiment.
Silver 1.60 # 10-8 Wm
Ans : [CBSE 2016]
By changing the position of ammeter, measure the
Copper 1.62 # 10-8 Wm
current in it. Every time the magnitude of current is Tungsten 5.2 # 10-8 Wm
found same i.e., in series combination the current in
every part of the circuit, remains same.
Iron 10.0 # 10-8 Wm
Mercury 94.0 # 10-8 Wm
Nichrome 100 # 10-6 Wm
Answer the following questions in relation to them:
i. Among silver and copper which one is better
conductor? Why?
ii. Which material would you advise to use in
electrical heating device? Why?
Ans : [CBSE 2016]
Precaution: a. If the amount of work done in bringing a unit
a. Connect the ammeter in series with battery. positive charge from one point to another is 1 J in
b. All connection must be tight. an electric field then potential difference b/w the
c. Current must not be greater than the two points is said to be 1 volt.
range of ammeter.
1V = 1J
1C
97. (a) Derive the formula for the calculation of work b. Connected cord of an electrical heater does not
done when current flows through a resistor. glow because this is of copper metal, which has
(b) One electric bulb is rated 40 W and 240 V and low resistivity and good conductivity. Heating
other 25 W and 240 V. Which bulb has higher element glows due to its high resistivity or poor
resistance and how many times? conductivity.
Ans : [CBSE 2016] c. (i) The resistivity of silver is lesser than copper so
a. Let R is the resistance of the resistor in which I it is a good conductor.
current is passed for a time t by applying a p.d. ( (ii) The resistivity of nichrome is maximum in the
V ) across the resistor. given table so nichrome will be advised to use
in electrical heating device. of charge and work. Draw the circuit symbols for
(i) variable resistor, (ii) a plug key which is closed
99. (a) Name an instrument that measures electric one.
current in a circuit. Define unit of electric current. (b) Two electric circuits I and II are shown below “
(b) What are the following symbols mean in an
electric circuit?
(i) (ii)
(c) Draw a closed circuit diagram consisting of 0.5 m
long nichrome wire XY, an , ammeter, a voltmeter,
four cells of 1.5 V and a plug key.
Ans : [CBSE 2015]
a. Ammeter. (i) Which of the two circuits has more resistance?
If IC charge flows in an electric circuit is 1 s then (ii) Through which circuit more current passes?
the current is said to be 1 A. (iii) In which circuit, the potential difference
b. (i) Rheostat (ii) Closed key across each resistor is equal?
(iv) If R1 > R2 > R3 in which circuit more heat
will be produced in R1 as compared to other
two resistors?
Ans : [CBSE 2014]
c.
a. Voltmeter
The amount of work done in bringing a unit
positive charge from one point to another in an
electric field is said to be potential difference
Ans :
a. Potential difference b/w the two terminals of a
cell is produced due to chemical reaction in the
cell. This potential difference maintains a current
Since V ? I
in the circuit.
Hence graph between V and I is a straight line
b. (i) The resistance b/w XZY and XTY are in
for a conductor. Which passes through the origin
parallel combination. Their equivalent resistance.
O of the graph.
1 =1+1
Rxy 2 6
104. Draw a schematic diagram of an electric circuit (in the
“on” position) consisting of a battery of five cells of 2 Rxy = 3 = 1.5 W
2
V each, a 5 W resistor, a 8 W resistor, a 12 W resistor
and a plug key, all connected in series. An ammeter (ii) Net resistance of the circuit
is put in the circuit to measure the electric current R = 1.5 + 1.5 = 3.0 W
through the resistors and a voltmeter is connected so
as to measure the potential difference across the 12 Hence, I =V = 6
R 3
W resistor.
Calculate the reading shown by the: (a) ammeter (b) I = 2.0 A
voltmeter in the below electric circuit. (iii) P.D. across X, Y points
Ans : [CBSE 2014] V = IRxy = 2 # 1.5 = 3.0 V
Resistors of 5 W , 8 W , 12 W all the connected in series. I in 2 W resistor = 3.0 = 1.5 A
Hence, 2
108. (a) Name and state the law that gives relationship
between the current through a conductor and the
potential difference across its two terminals. Also,
express this law mathematically.
(b) Draw the V-I graph for this law. Justify your
answer.
(c) Write the name and use of the circuit components
whose symbols are given below.
(i) (ii)
(b) How many 176 W resistors in parallel are required
Ans : [CBSE 2013] to carry 5 A on a 220 V line?
a. The law is Ohm’s law. (c) Define electric power, Derive relation between
If the physical conditions of a conductor is kept power, potential difference and resistance.
constant then current through it is directly Ans : [CBSE 2012]
proportional to the potential difference applied
across it. a. R = TV = 2 - 0 W
TI 0.1 - 0
V ? I or V = RI
b. Since V ? I so a graph b/w V and I is a straight R = 20 W
line.
1 = 1 + 1 + 1
R R1 R2 R3
b. To prevent oxidising the filament due to high
temperature.
c. The current in the fuse wire must not exceed 5 A
otherwise it will melt.
P = I2 R But I = V
R
2 2
P = V 2 R or P = V Ans : [CBSE 2012]
R R
a. (i) The resistance of two times long wire also
111. (a) Three resistors R1, R2 and R3 are connected in becomes two times so current decreases in the
parallel and the combination is connected to circuit.
battery, ammeter, voltmeter and key. Draw (ii) If area of the nichrome wire is doubled then
suitable circuit diagram. Obtain an expression its resistance decreases and hence current
for the effective resistance of the combination of increases in the circuit.
resistors in parallel. b. Potential difference b/w A and B is 1 volt means
(b) Why are electric bulbs filled with chemically that 1 J of work is to be done in moving a unit
inactive nitrogen or argon? positive charge (+ 1C) from point A to B.
(c) What is meant by the statement that the rating of
a fuse in a circuit is 5 A? 113. Draw a circuit diagram for a circuit consisting of a
Ans : [CBSE 2012] battery of five cells of 2 volts each, a 5 W resistor, a
10 W resistor and a 15 W resistor, an ammeter and
a. Let equivalent (effective) resistance is R
a plug key; all connected in series. Also, connect a
then I =V voltmeter to record the potential difference across the
R
15 W resistor and calculate:
a. the electric current passing through the above
circuit and
b. potential difference across 5 W resistor when the
key is closed.
Ans : [CBSE 2012]
Similarly, I1 = V
R1
c. (i)
(i) (ii)
4 =rl
A
R2 = r l2 ...(2)
A2
l
R2 = r 2
2A
Rp = R
16
Now R12 and R34 are in series R14 = 1 + 1 = 2 W and
R56 and R78 are in series 143. A wire is 1.0 m long, 0.2 mm in diameter and has
a resistance of 10 W . Calculate the resistivity of its
R56 = 1 + 1 = 2 W
material.
Ans : [CBSE 2011]
L = 1.0 m
D = 0.2 mm
r = D = 0.2 = 0.1 mm
2 2
= 10
30
Rp = 3 W b. Total resistance of the circuit
b. (i) Voltage across each appliance remains = ^4 + 4h W = 8 W
(ii) If any appliance fails to work other appliances Current in 4 W resistor
continue to work.
I = 8 = 1A
8
146. Three 2 W resistors, A, B and C, are connected as c. Potential difference across 4 W resistor
shown in figure. Each of them dissipates energy and V = IR = 1 # 4 = 4 Volt.
can withstand a maximum power of 18 W without d. Power dissipated in 4 W resistor
melting. Find the maximum current that can flow
P = I2 R = ^1 h2 # 4 W
through the three resistors.
P =4W
e. Both the ammeters are in series in the circuit so
current will be same in both ammeters. Hence no
difference in the reading of two ammeter.
from P = I R or I = P
2 2 V = 220 Volt.
R
I2 = 18 = 9 Resistance of bulb = V = 220 = 22 W
2 I 10
V = 200 V
P = 100 W
2
(a) P =V
R
^200h2
R = W = 40000 = 400 W
100 100
(b) Energy consumed in 4 hrs. by one bulb.
Chap 9 : Herededit and Evolution www.cbse.online
CHAPTER 9
Herededit and Evolution
It is a functional piece of DNA that is responsible for 25. What are the basic events in evolution?
expression of a trait in the organisms. Ans : [CBSE 2013.14]
15. What is heredity? The changes in DNA during reproduction are the
Ans : [All India 2014] basic events in evolution.
Transmission of characters and traits from one 26. What is genetic drift?
generation to the next. Ans : [CBSE 2012,13]
16. Mendel observed a contrasting trait in relation to The change in the frequency of certain genes in a
position of flowers. Mention the trait. population over generations.
Ans : [All India 2014-15] 27. What are fossils?
Axial flower position (dominant), terminal flower Ans : [CBSE 2012, 13]
position (recessive).
Preserved traces of living organisms.
17. Name the term used for the traits that are exhibited
28. What are analogous organs?
externally.
Ans : [CBSE 2011, 12, 13]
Ans : [CBSE 2014]
The organs which have similar functions but different
Phenotype.
structures are called analogous organs.
18. Give the respective scientific terms used for studying:
29. The human hand, cat paw and the horse foot, when
a. the mechanism by which variations are created
studied in detail show the same structure of bones and
and inherited, and
point towards a common origin.
b. the development of new type of organisms from
a. What do you conclude from this?
the existing ones.
b. What is the term given to such structures?
Ans : [CBSE 2014]
Ans : [Sample Paper 2010]
a. Heredity
a. They have common origin/ancestory.
b. Species
b. Homologous organs.
19. Write the sex of the baby that inherits Y-chromosomes
30. When a tall and dwarf pea plant were crossed, Fx
from the father.
showed only tall plants but in F2 generation, some
Ans : [CBSE 2014] plants were dwarf. What does it mean?
Male. Ans : [CBSE 2008]
20. What is the phenotypic ratio of a dihybrid cross in F2 It means reappearance of the dwarf character, a
generation? recessive trait in B’2 generation shows that the dwarf
Ans : [CBSE 2014] trait/ character was present in individuals of F* but
it did not express (due to the present of tallness, a
9 : 3 : 3 : 1. dominant trait / character)
21. Give an example where sex determination is regulated 31. How is the age of fossil determined?
by environmental factors.
Ans : [Panchkula 2008]
Ans : [CBSE 2014]
The age of fossil fuels is determined through carbon-
In snail, sex is determined by environmental factors dating or time dating method.
(temperature).
32. What is evolution?
22. Define speciation.
Ans : [Panchkula 2008, CBSE 2013,14]
Ans : [CBSE 2013,14]
Gradual unfolding of organisms from pre-existing
Speciation means origin of new species from the organisms through change is called evolution.
existing one.
23. What is the effect of DNA copying which is not TWO MARKS QUESTIONS
perfectly accurate on the reproduction process?
Ans : [CBSE 2013,14]
33. What are fossils? What is their significance in the
It will result in less variations which may further lead study of evolution?
to less adaptation to changing environment, thus,
Ans : [Sample Paper 2016-17]
giving less chances of survival.
Fossils are impressions of the body/ body parts or
the remains of organisms living in the past, which got or second generation.
preserved in sediments of earth.
a. Study of fossils helps in working out evolutionary 40. “The chromosome number of the sexually producing
relationships. parents and their offspring is the same”. Justify this
b. Fossils provide one of the most acceptable statement.
evidences in support of evolution, because we can Ans : [CBSE 2015]
study the evolutionary past of individuals in the In sexual reproduction, both the gametes (male and
form of their fossils. female) contain half the number of chromosomes
c. Age of fossils can also be found by time dating (haploid or n) and by the fusion of these gametes,
using isotopes of carbon! carbon dating. the zygote have full set (diploid 2n) chromosomes.
d. By studying fossils occurring in different strata of
rocks, geologists are able to reconstruct the time 41. If YYRR is round yellow, what do the following
course of evolutionary events. represent?
yyrr yyRR
34. (a) On what rules inheritance is based?
Ans : [CBSE 2015]
(b) Is each trait influenced by both paternal and
maternal DNA? yyrr - Wrinkled, green seeds
Ans : [CBSE 2016] yyRR — Round, green seeds
a. The rules of inheritance is based on the fact that 42. How did Mendel explain that it is possible that a trait
the traits in the progeny are carried out by DNA’s is inherited but not expressed in an organism?
of both the parents (mother and father). These Ans : [All India 2017]
rules are known s ‘Mendel’s Laws of Inheritance’.
The rules are: Yes, it is possible.
(i) Law of dominance, Example - When pure tall pea plants are crossed
(ii) Law of segregation, and with pure dwarf pea plants, only tall pea plants are
(iii) Law of independent assortment. obtained in F1 generation.
b. Yes, it is true that each trait is influenced by both On selfing tall plants of F1 both tall and dwarf
paternal and maternal DNA. plants are obtained in F2 generation in the ratio 3:1.
35. a. What is the genetic constitution of human sperm? Reappearance of the dwarf character, a recessive
b. Mention the chromosomes pair present in zygote trait in F2 generation shows that the dwarf trait/
determining the sex of a male child. character was present in individuals of F1 but it did
not express (due to the present of tallness, a dominant
Ans : [CBSE 2016]
trait / character)
a. 22 + Y or 22 + X
b. (22 + Y + 22 + X) 43. What is a dominant trait with respect to height in pea
plant. Give any two examples.
36. a. How many gene sets should a germ cell have? Ans : [All India 2014]
b. Mention two factors causing evolution.
Characters/Traits like ‘T’ are called dominant trait
Ans : [CBSE 2016]
(because it express itself) ‘t’ are recessive trait
a. One gene set. (because it remains supressed).
b. (i) Reproduction isolation (ii) Natural selection
Character Dominant Trait Recessive Trait
37. What is micro evolution? Does it explain speciation? Seed shape Round Wrinkled
Ans : [CBSE 2016] Pod shape Inflated Constricted
a. In micro evolution, the changes are small which
Pod colour Green Yellow
occurs in lower categories and change the common
characteristics of a particular species. Height of plant Tall Dwarf
b. It does not properly explain speciation.
65. How do Mendel’s experiments show that the Acquired Trait Inherited Trait
a. traits may be dominant or recessive,
1 Experiences of an Genetically inherited
b. traits are inherited independently?
individual during its
Ans : [All India 2017] lifetime.
a. When Mendel cross pollinated pure tall pea plants
Acquired Trait Inherited Trait b. Mendel studied that genes segregate during the
formation of gametes (sperms in males and ova in
2. It cannot be passed on They can be passed on females) and they again combine in the offspring
from one generation to from one generation to (one from each parent) and appear as dominant or
the next. the next. recessive trait. This can be worked out by making
3. Example: power to lift Example: Eye colour a test cross.
weights and reading or height c. Mendel proposed three laws, namely:
French (i) Law of segregation: Each inherited trait is
defined by a pair of gene. Parental genes are
68. What is evolution? How does it occur? randomly separated to the germ-cells so that
Ans : [All India 2016] germ contain only one pair of gene.
(ii) Law of independent assortment: Genes of
Organic Evolution: Gradual unfolding of organisms
different traits are sorted separately from one
from pre-existing organisms through change is called
another so that the inheritance of one trait is
evolution.
not dependent on the inheritance of another.
a. Evolution occurs in the form of genetic drift and
(iii) Law of dominance: An organism with alternate
natural selection combined with geographical
forms of a gene will express the form that is
separation.
document.
b. Speciation - evolution of a new species from pre-
existing species-occurs. 71. a. What function is performed by human arms,
c. Fossils are impressions of the body/body parts or forelimbs of dog and forelimbs of whales?
the remains of organisms living in the past, which b. Which type of organs are these?
got preserved in sediments of earth. c. Why do we call them so?
d. Study of not living species but also fossils helps in
Ans : [CBSE 2016]
working out evolutionary relationships.
e. Fossils provide one of the most acceptable a. Human arm : holding things Forelimbs of dog :
evidences in support of evolution, because we can running Forelimbs of whales : paddles
study the evolutionary past of individuals in the b. Homologous,
form of their fossils. c. Same origin, different functions.
69. “Two areas of study namely evolution and classification 72. If a population of red beetles, living on green bushes,
are interlinked”. Justify this statement. is being eaten by crows. During sexual reproduction,
Ans : [All India 2016,2017] a green beetle is found in progeny:
a. What is the future of new trait?
All living things are identified and categorised on the b. Will it survive in the new habitat?
basis of their body design in form and function. After a
Ans : [CBSE 2016]
certain body design comes into existence, it will shape
the effects of all other subsequent design changes a. Among progeny, when green beetle is found, it
simply because it already exists. So, characteristics escaped attack of crows as it merged with green
which came into existence earlier are likely to be colour. Green beetles increased, red decreased.
more basic than characteristics which have come into b. New trait will survive.
existence later.
73. An angiosperm plant having red coloured flowers
This means that the classification of life forms will when crossed with the other having the same colour
be closely related to their evolution. On connecting produced 40 progenies, out of which 30 plants were
this idea of evolution to classification, it is seen with red coloured flowers, 10 plants were with white
that some groups of organisms with ancient body coloured flowers. Find out:
designs have not changed very much. However, other a. What is the possible genotype of parent plants?
groups of organisms have acquired their particular b. Which trait is dominant and recessive?
body designs relatively recently. Because there is a c. What is this cross called as and what is its
possibility that complexity in design will increase over phenotypic ratio?
evolutionary time, it may not be wrong to say that Ans : [CBSE 2016]
older organisms are simpler, while younger organisms
are more complex. a. Rr and Rr.
b. Red colour of flowers is the dominant trait while
70. Explain Mendel’s concept of heredity, by giving three white colour is the recessive trait.
points. c. Monohybrid cross, phenotypic ratio is 3 : 1.
Ans : [CBSE 2016]
74. What is DNA copying? State its importance.
a. Mendel worked on pea plant {Pisum sativum) and Ans : [Delhi 2015]
discovered the fundamental laws of inheritance. He
found that traits (characteristics) are controlled A process where a DNA molecule produces two similar
by factors (which are now called genes) and each copies of itself in a reproducing cell.
factor (gene) come in pairs. These factors (genes) Importance -
are inherited as distinct units, one from each a. It makes possible the transmission of characters
parent. from parents to the next generation.
b. It causes variation in the population.
75. “We cannot pass on to our progeny the experiences denoted by ww.
and qualifications earned during our lifetime”. Justify a. What is the expected colour of the flowers in their
the statement giving reason and examples. F1 progeny?
Ans : [Delhi 2015] b. What will be the percentage of plants bearing
white flower in F2 generation, when the flowers of
Acquiring knowledge / skill in one’s lifetime such as
F1 plants were selfed?
learning dance, music, physical fitness or any other
c. State the expected ratio of the genotypes BB and
suitable example.
Bw in the F2 progeny.
Reason:
a. Such characters / experiences acquired during Ans : [CBSE 2015]
one’s lifetime do not bring any change in the DNA a. F1 generation — blue.
of the reproducing c$ll/germ cell. b. 25%
b. Only germ cells are responsible for passing on the c. BB : Bw = 1 : 2.
characters from the parents to the progeny.
80. Give reasons for the following:
76. a. Insects, octopus and vertebrates all have eyes. a. Traits acquired during lifetime of an individual
Can we group eyes of these animals together to are not inherited.
establish a common evolutionary origin? Justify b. All the human beings belong to a single species.
your answer. c. Variations keep on accumulating during
b. “Birds have evolved from reptiles”. State evidence reproduction and do not disappear in next
to prove the statement. generation.
Ans : [Delhi 2015] Ans : [CBBE 2015]
a. No, the structure of the eye in each of the a. These are acquired traits that do not make any
organisms is different. change to the DNA of an organism.
b. Fossils of certain dinosaurs/reptiles show imprints b. Homo sapiens originated in Africa and spread
of feathers along with their bones but they across the globe in stages. The humans with
could not fly presumably using the feathers for different colours in different regions have come
insulation. into being as an accident of evolution, so that
Later they developed / evolved and adapted they could live their lives the best they could. So
feathers for flight, thus becoming the ancestors of all belong to the same species.
present day birds. c. Inheritance from the previous generation provides
(OR any other suitable evidence/example) both a common basic body design, and subtle
changes in it, for the next generation. So the
77. What are chromosomes ? Explain how in sexually changes keep on accumulating generations after
reproducing organisms the number of chromosomes in generations.
the progeny is maintained.
Ans : [Outside Delhi 2015] 81. In a pea plant, find the contrasting trait if:
a. the position of flower is terminal.
Chromosomes - Thread like structures made up of
b. the flower is white in colour.
DNA found in the nucleus. The original number of
c. shape of pod is constricted.
chromosomes becomes half during gamete formation.
Hence, when the gametes combine, the original Ans : [CBSE 2015]
number of chromosomes gets restored in the progeny. a. Axial position of flower.
(or same thing explained in the form of a flow chart). b. Purple colour of flower.
c. Inflated shape.
78. Explain with an example for each, how the following
provides evidences in favour of evolution in organisms: 82. a. “Chromosomes are heredity carriers.” Why do we
a. Homologous organs say so?
b. Analogous organs b. Which vital function is not controlled by
c. Fossils autosomes?
Ans : [All India 2015, 2016, 2011, Delhi 2017] Ans : [CBSE 2015]
a. Homologous organs - study of homologous organs a. Chromosomes are made-up of DNA. Genes are
suggests that the organs having same structure located on the chromosomes. It is the DNA copy
but performing different functions have evolved which transfers from both the parents to their
from a common ancestor. Example: forelimbs of a offspring. Therefore, chromosomes made-up of
frog, lizard, bird and man. DNA and containing genes are said to be the
b. Analogous organs - show adoption of organs for heredity carriers.
common use. Example: wings of butterfly and b. Sex of the child is not controlled by autosomes.
wings of bat.
c. Fossils - provide the missing links between two 83. a. During evolution some changes may have occurred
species. Example: - Archeopteryx / fossils of some for a reason but proved to be useful for some other
dinosaurs with feathers. purpose. Cite one such example.
b. Has the evolutionary changes took place all of
79. A pea plant with blue colour flower denoted by BB sudden. Elaborate.
is cross-breed with a pea plant with white flower Ans : [All India 2014]
a. Evolutions of feathers: Functional Advantage: A c. Birds developed feathers for insulation.
change that is useful for one property to start
with can become useful later for quite a different 86. With the help of suitable examples, explain why certain
function. Feathers, for example, can start out as traits cannot be passed on to the next generation.
providing insulation in cold weather. But later, What are such traits called?
they might become useful for flight. In fact, some Ans : [CBSE 2014]
dinosaurs had feathers, although they could not Example: Acquiring knowledge by reading/change
fly using the feathers. Birds seem to have later in body weight. Reason: Because such changes do
adapted the feathers to flight. This, means that not bring any change in the DNA of the germ cells/
birds are very closely related to reptiles, since such changes take place only in the non-reproductive
dinosaurs were reptiles. Birds have evolved from tissues.
reptile. Traits: Acquired traits.
b. Evolution changes has not took place all of
sudden. Evolution takes place in stages, i.e., bit 87. List three main factors responsible for the speciation
by bit over generations. Even an intermediate and briefly describe each one of them.
stage, such as a rudimentary eye, can be useful Ans : [CBSE 2014]
to some extent. This might be enough to give a
fitness advantage. In fact, the eye seems to be a Genetic Drift: Random change in the frequency of
very popular adaptation. genes.
Insects have them, so does an octopus, and Natural Selection: Nature selects the fittest individual
so do vertebrates. And the structure of the eye in in a population. Reproductive Isolation: When two
each of these organisms is different - enough for individuals are geographically isolated and natural
them to have separate evolutionary origins. selection operates upon them differently leading to
inability of the individuals to interbreed.
84. Variation is useful for the useful over long time. But
the variants have unequal chances of survival. Explain
this statement. [All India 2014-15]
or
Define variation in a species. How does it increases the
survival chances of a species?
a. Identify the organism shown in the above figure.
b. Name one incipient feature selected by the nature.
c. Mention any other primitive feature of birds.
Ans : [All India 2014-15]
Variation are minor differences among members
of a population. They are useful for the process of
evolution which take place over long time. But some of
the variants find it more advantageous in the present
environmental conditions to survive than others
88. (a) Which type of organs are shown in the figure
variants by virtue of the variation possessed by them
below?
hence they have unequal chances of survival. Thus
some get selected and others get eliminated. Those
which survive pass their genes to next generation
therefore frequency of genes possessed by them
increase in frequency in the population. Example - in
a population of beetles, a new variation (green colour)
get survival benefit/advantage to green beetles
whereas other (red) perishes.
85. (a) Identify the organism shown in the above figure. (b) Which type of origin and structure do these
organs have?
Ans : [CBSE 2014]
a. These are organs which help in flying (wings of
insects and wings of birds).
b. The structure and components of these wings are
different. They look similar because they have a
common use for flying, but their origins are not
common, i.e., they are analogous.
(b) Name one incipient feature selected by the nature.
(c) Mention any other primitive feature of birds. 89. (a) “Each organism has its own identity”. Explain.
Ans : [All India 2014-15] (b) What is speciation?
Ans : [CBSE 2014]
a. Planaria.
b. Eyes which were there only for detecting light. a. (i) The DNA of each organism is different from
others. makeup and phenotype.
(ii) The DNA of each organism is specific within
the same species with specific number of 94. Rekha is very dark in colour. She stays very quiet at
chromosomes/genes. home and in her class also. She is always seeing for
b. Emergence of new species from pre-existing forms the beauty products which can help her to become
through natural selection/artificial selection/ fair. Her friend Lila talks to her about excessive use
genetic drift/evolution, etc. * of beauty products and tells her that they are very
harmful and colour comes by birth and she is not
90. An organ like a wing in birds are an advantage to an responsible for her dark colour.
organism. Did they appear in different stages or were a. What might have caused Rekha’s colour to be
formed due to a single sudden change in them. dark?
Ans : [CBSE 2014] b. Is it possible that all the family members of
Rekha’s family were dark?
Feathers in dinosaur were long and they could not
c. What value do you learn?
fly using feathers. It gave them protection from cold
weather and warmth. Birds seem to have later adapted Ans : [All India 2013]
the feathers to flight. a. Her dark colour may be due to the genetic
inheritance.
91. How are fossils formed? Describe, in brief, two methods b. All may not be dark, depending upon the genes
of determining the age of fossils. inherited and the environmental conditions that
Ans : [All India 2013] each one of them living in.
Fossils are formed when dead organisms are not c. Awareness, logical thinking, scientific
completely decomposed. The organisms may get temperament.
trapped in resins of tree, lava of volcanoes or hot mud
95. A cross was carried out between a pure bred tall pea
which when hardens, retains the animal’s parts thus,
plant and a pure bred dwarf pea plant and F1 progeny
forming fossils.
was obtained. Later, the F1 progeny was selfed to
Two methods of determining the age of fossils:
obtain F2 progeny. Answer the following questions:
a. Relative method: By estimating the age of the
a. What is the phenotype of the F1 progeny and
layer of earth’s crust where the fossil is found.
why?
Fossils near the surface are recent and those in the
b. Give the phenotypic ratio of the F2 progeny.
deeper layers are more ancient.
c. Why is the F2 progeny different from the F1
b. Radio-carbon dating method: By detecting the
progeny?”
ratios of different isotopes of carbon in the fossils.
Ans : [CBSE2013,14]
Fossils help in determining the connecting links
between various groups and their origin from their a. Tall, because genes responsible for tallness are
primitive ones, e.g., Archaeoptyrx. dominant over dwarf trait.
b.
92. Explain the term homologous organ with an example.
Ans : [All India 2013]
The organs which have similar basic structure and c. Because in F2 generation, recessive genes got
mode of origin but perform different functions in expressed in homozygous condition.
different animals are called homologous organs. E.g.,
Forelimbs of amphibians, reptiles, birds and mammals. 96. a. State any two factors that could lead to the rise of
Homologous organs give an evidence of common a new species.
ancestory and evolutionary relationship between b. How do analogous organs provide evidence in
apparently different species. favour of evolution?
Ans : [CBSE 2013]
93. How green beetles had colour advantage over red
beetles? Explain. a. Natural Selection, Genetic drift, Mutations,
Variations.
Ans : [All India 2013] b. The organs which are similar in function but are
Green beetle merge with green background of structurally different suggest that although these
vegetation which give survival advantage to a species two organs may look alike superficially giving
from elimination. an idea of common ancestory but the different
a. in the population of beetles, the new variation in structure and origin suggests that organisms
(green colour) get survival benefit / advantage to having these organs have a distant ancestor but
green beetles whereas other (red) perishes. such organs have developed during the course of
b. It is because of Natural selection — some variations evolution as an adaptation to similar mode of life.
are advantageous for an organism to adapt better
in the prevailing conditions of habitat. It makes it 97. a. Why traits such as intelligence and knowledge
easy to obtain food and mating partner by them. cannot be passed on to the next generation?
In this manner they are able to propagate more, b. How can we say that birds are closely related to
transmitting their genes to next generation and reptiles and have evolved from them?
producing more individuals with similar genetic Ans : [CBSE 2013]
a. Traits such as intelligence and knowledge are observation regarding their ancestry?
not heritable traits, which do not bring upon Ans : [Delhi 2012]
any changes in the DNA of the germ cells and,
The organs which have similar basic structure and
therefore, cannot be passed on to the progeny.
mode of origin but perform different functions in
b. This can be said because traits such as feathers
different animals are called homologous organs, e.g.,
were first seen in reptiles like Dinosaurs, which
forelimbs of amphibians, reptiles, birds and mammals.
performed the function of providing insulation
Homologous organs give an evidence of common
to them in cold weather although they could not
ancestory and evolutionary relationship between
fly using the feathers but later birds adapted
apparently different species.
the feathers for flight. This means that birds are
very closely related to reptiles, as dinosaurs were Analogous organ are the organs in different
reptiles. organisms which have different basic structure but
have similarity in shape and function, e.g., wings of
98. (a) Differentiate between: bat and bird. These organs do not provide an evidence
1. Homologous organs and Analogous organs. in support with common ancestory.
2. Pollination and Fertilization
(b) What do fossils tell us about the process of
evolution? THREE MARKS QUESTIONS
Ans : [CBSE 2013]
a. (i) Organs in different organisms with same origin 102. A group of grasshoppers — some green and some
with different function/ different origin, same brown lived in a grassland having dry bushes and dry
function. grass.
(ii) Transfer of pollen from the stamen to the a. Which one would normally be picked up by
pistil of the flower/fusion of male and female predatory birds and why?
gametes. b. Population of which grasshopper will increase?
b. Help in establishing links and act as evidence of c. Name this phenomenon.
evolution. Ans : [Sample Paper 2010]
99. (a) Explain giving examples how artificial selection a. Green grass hopper, because they stand out,
has helped in the formation of newer varieties of against brown background of dry bushes.
cauliflower. b. Brown
(b) List the steps involved in the formation of new c. Natural selection.
species.
103. (a) Explain why the wing of a bat and the wing of
(c) How different races of human beings belong to the
bird are considered to be analogous organs.
same species?
(b) List two factors that lead to the formation of a
Ans : [CBSE 2013] new species.
a. Formation of newer varieties, e.g., Broccoli, Ans : [CBSE 2012]
cauliflower, red cabbage, etc. by man.
a. Design, structure and components are different.
b. Migration, gene flow, natural selection, new
Origins are not common.
species.
b. Genetic drift and natural selection.
c. Capable of interbreeding among themselves.
104. a.Name the scientist who gave the idea of evolution
100. What is speciation? Discuss any two factors that lead
of species by natural selection.
to speciation.
b. What conclusion did Mendel draw from his
Ans : [Delhi 2012] experiments about traits?
Speciation means creation of new species from pre c. Arrange the following according to evolution.
exiting ones. Cockroach, Mango tree, Gorilla, Fish
The two main factors which could lead to the Ans :
formation of a new species are natural selection leading a. Darwin
to accumulation of adaptation in geographically b. Traits are inherited independently.
separated populations of a species and development of c. Mango tree — Cockroach - Fish — Gorilla.
reproductive barrier among them.
105. a.What are fossils?
Complete separation of sub-populations of a
b. Explain the importance of fossils in evolutionary
spices (Genetic drift) and difference in way of Natural
relationship.
selection in them for many generations results in
speciation i.e. formation of new species that cannot Ans :
interbreed under natural conditions. a. Impressions of the body parts of the organisms
and preserved traces of the living organisms are
101. Fore limbs of amphibians, reptiles, birds and mammals
called fossils.
show similarity in their bones but Wings of bat and b. The presence of fossilized remains of the organism
bird don’t. What conclusion can be drawn from such is the evidence of existence of organisms million
years ago which have now become extinct. Fossils
also help in determining the connecting links If a sperm with “X’ fuses with the ovum, female
between various groups and their origin from child is born and if a sperm with ‘Y’ chromosome fuses
their primitive ones. with the ovum, male child is born as shown below in
the cross.
106. What are fossils? What do they tell about the process
of evolution?
Ans : [Outside Delhi 2008, CBSE 2008 C]
The fossils can be defined as remains or impressions
of the hard parts of the past individuals in the strata
of the earth. Fossils helps in working out evolutionary
relationships. Fossils provide one of the most
acceptable evidences in support of evolution, because
we can study the evolutionary past of individuals in
Hence, we find that the sex of the child is actually
the form of their fossils. By studying fossils occurring
determined by the type of sperm that fuses with ovum
in different strata of rocks, geologists are able to
at the time of fertilization.
reconstruct the time course of evolutionary events.
Age of fossils can also be found by time dating using In this manner we can justify that the sex of the
isotopes of carbon (carbon dating). children is determined by what they inherit from their
father and not their mother.
107. “Only variations that confer an advantage of an
individual organism will survive in a population”.
Comment. FIVE MARKS QUESTIONS
Ans : [Delhi 2008 C]
According to Theory of Natural Selection, some 109. How do Mendel’s experiment show that traits are
variations are advantageous for an organism to inherited independently?
adapt better in the prevailing conditions of habitat. Ans : [All India 2016]
It makes it easy to obtain food and mating partner
Mendel carried out dihybrid crosses by crossing
by them. In this manner they are able to propagate
two pea plants differing in contrasting traits of two
more, transmitting their genes to next generation
characters. For example, he crossed a pea plant
and producing more individuals with similar genetic
having yellow colour and round seed characters with
makeup and phenotype.
another pea plant bearing green colour and wrinkled
Though according to Genetic Drift Theory, even seed characters. In the F2 generation, he obtained
those not having a variation that confers an advantage pea plants with two parental and two recombinant
also get to 5 survive but only in a small population. If phenotypes as yellow round and green wrinkled
due to an accident most of the individual with other (parental) and yellow wrinkled and green round
variation get removed, the organisms with leftover (recombinant). This indicated that traits separated
variation get to propagate and survive under such from their original parental combinations and got
circumstances. inherited independently.
Hence it is wrong to say that only variations that
confer an advantage of an individual organism will
survive in a population.
CHAPTER 11
Human Eye and The Colorful World
1. ONE MARK QUESTIONS For a human eye, there is a near point, 25 cm. If the
distance of the object is lesser than this distance, eye
cannot see object clearly.
1. Name the essential parts of human eye,
11. When you enter from a bright sunshine into a dark
Ans : [CBSE 2016] room, you are not able to see clearly for sometime,
(a) Retina (6) Eye lens (c) Cornea (d) Pupil (e) Iris why?
Ans : [Delhi 2015]
2. Which liquid fills the space behind the cornea?
In bright light, pupil had become small.
Ans : [Delhi 2016]
Aqueous humour is filled in the space behind the 12. On what factor the colour of the scattered light
cornea. depends?
Ans : [CBSE 2015]
3. Which part of the eye controls the amount of light
entering the eye? The colour of the scattered light depends on the size
of scattered particles.
Ans : [CBSE 2016]
Pupil controls the amount of light entering the eye. 13. What is Presbyopia ?
Ans : [CBSE 2014]
4. What is eye lens made of ?
Presbyopia is a kind of eye defect in old persons due
Ans : [CBSE 2016]
to ageing. It happens due to decrease in flexibility of
Eye lens is made of transparent and flexible jelly like eye lens and weakening of ciliary muscles.
material.
14. What is twinkling of stars due to?
5. How is the sense of vision carried from the eye to the Ans :
brain?
Twinkling of star is due to atmosphere refraction.
Ans : [CBSE 2016]
Through optical nerve, sense of vision is carried from 15. Define dispersion of white light.
eye to the brain. Ans : [CBSE 2014]
6. Which liquid fills the space between eye lens and The splitting of white light into its constituents seven
retina? colours is called dispersion of light.
Ans : [All India 2015] 16. What kind of lens is used in the spectacles of a person
Vitreous humour. suffering from myopia (near sightedness)?
Ans : [CBSE 2014]
7. Why is blind spot so called?
A diverging lens/concave lens is used for a person
Ans : [CBSE 2015]
suffering from near sightedness/ myopia.
An image formed at this point is not sent to brain.
17. Name the part of the human eye that helps in changing
8. What is the number of receptors contained in the the focal length of the eye lens.
retina? Ans : [All India 2013]
Ans : [CBSE 2015]
Ciliary muscles help in changing the focal length of
Retina contains more than 125 millions receptors the eye lens.
which are of two types, rods and cones.
18. Write the value of near point of distinct vision for
9. What is meant by far point? normal eye.
Ans : [CBSE 2015] Ans : [CBSE 2013]
The farthest point upto which an normal human eye For a normal human eye the value of near point of
can see objects clearly is known as far point. distinct vision is 25 cm.
10. Why can you not see an object clearly if it is placed 19. What is the role of pupil in a human eye?
very close to your eye? Ans : [CBSE 2013]
Ans : [All India 2015]
Pupil regulates and controls the amount of light depends. Why does the sky appear dark in space?
entering in the eyes. Ans : [CBSE 2016]
20. What is the range of vision for a normal human eye? Scattering of light depends on the presence of
Ans : [CBSE 2013] atmosphere which contains water droplets, molecules
of air, smoke and dust particles.
Range of vision is 25 cm to infinity.
In the space, there is no atmosphere to scatter
21. Name the two phenomena involved in the formation light.
of rainbow.
30. How can change of size of eyeball be one of the reason
Ans : [CBSE 2012]
for: (a) Myopic (b) Hypermetropic
The phenomena involved in formation of rainbow are
Compare the size of eyeball with that of a normal
dispersion and total internal reflection and refraction.
eye in each case. How does this change of size affect
22. Name the component of white light that deviates the the position of image in each case?
least and the most while passing through a prism. Ans : [All India 2016]
Ans : [CBSE 2012] (a) The eye suffering from myopia, has long eye ball
Red colour deviates the least and violet colour deviates than that of normal eye due to which the retina
the most. is at a larger distance from the eye lens. This
results in the formation of the image in front of
23. A person is advised to wear spectacles with concave the retina.
lenses. What type of defect of the vision is he suffering (b) The eye suffering from hypermetropia has short
from? eye ball than that of normal eye due to which the
Ans : [CBSE 2012] retina is smaller distance from the eye lens. This
results in the formation of the image behind the
Myopia. retina.
24. Name the part responsible for the power of 31. Sushil went to an eye specialist for check up. He
accommodation of the eye. prescribed him to use spectacle lens of + 0.5D power.
Ans : [CBSE 2012] a. Name the defect of vision he is suffering from.
Ciliary muscles help for the power accommodation of b. Find the focal length of spectacle lens.
the eye. Ans : [CBSE 2015]
25. Name the condition resulting due to the eye lens a. Hypermetropia.
becoming cloudy. b. Power of spectacle P = + 0.5D
Ans : [CBSE 2012] f = 1 =+ 1 m
P 0.5
Cataract.
or f =+ 2 m positive sign means it is a convex
26. Why sky appears dark to the passengers flying at high lens.
altitudes?
32. State the function of pupil and ciliary muscles.
Ans : [CBSE 2012]
Ans : [CBSE 2015]
There is no atmosphere at high altitudes. Hence no
scattered light can reach to the eye. a. Pupil controls the amount of light entering the
eye.
27. A person suffering from an eye defect uses lenses of b. Ciliary muscles help in accommodation of power
power – 1D. Name the defect he is suffering from and of eye lens.
the nature of lens used.
33. A child sitting in a classroom is not able to read
Ans : [CBSE 2012]
clearly the writing on the blackboard.
He uses a concave lens (negative power) because he is a. Name the type of defect from which his eye is
suffering from myopia. suffering.
b. With the help of a ray diagram show how this
28. Which colour of white light suffers (i) least deviation
defect can be remedied.
and (ii) maximum deviation when a beam of white
Ans : [Delhi 2015]
light passes through a glass prism?
Ans : [CBSE 2011] a. Myopia
b. Myopia can be remedied by using concave lens.
Longer wavelength light (red) suffers least deviation
and shorter wavelength (violet) suffers maximum
deviation when white light is passed through a prism.
59. Study the diagram and answer the questions the 62. With the help of scattering of light, explain the reason
follows : for the difference in colours of the Sun as it appears
Ans : during sunrise/sunset and noon.
Ans : [CBSE 2015]
At the time of sunrise or sunset it appears red where
as at noon it appear white when it is overhead
because at sunrise or sunset blue colour and other
shorter wavelength light get scattered away while
passing through the atmosphere. Scattering of longer
a. Identify the defect of vision represented by this wavelength is least which reach to the earth. Due to
diagram. this sun appears red during morning and evening time.
b. List the two possible causes of this defect. When sun is overhead at noon, sun rays travels
c. With the help of ray diagram explain how this smaller distance, due to little scattering of blue and
defect can be corrected. violet colour wavelength almost all wavelengths reach
Ans : [Delhi 2016] to earth and due to this sun appears white.
a. The defect of vision is hypermetropia. 63. State the cause of dispersion, when white light enters
b. (i) increase in focal length of eye lens a glass prism. Explain with a diagram.
(ii) shortening of eye ball.
Ans : [All India 2014]
c. Hypermetropia can be corrected by using convex
lens. When white light passes through a prism it splits into
its constituent colours, because each coloured light has
different speed in prism. Prism has different refractive
index for these light rays and so deviates through
different angles when emerge out from the prism.
Deviation for violet colour (shortest wavelength) is
most and for red colour (largest wavelength) deviation
is least.
65. State one function each of iris, pupil, and cornea. It can be corrected with the help of a convex lens
Ans : [CBSE 2014] as shown.
a. Iris: It controls the amount of light entering the
eye by changing the size of pupil.
b. Pupil: Pupil is a part of the eye through which
light enters in the eye.
c. Cornea: It is a thin membrane which covers the
eye ball. Light enters the eye through cornea 69. A person is unable to read a book clearly when kept
where it is refracted most. at a distance of 25 cm from his eye. Name the defect.
How can it be corrected? Draw ray diagrams for (i)
66. (a) Explain the phenomenon of scattering of light.
defective eye (ii) corrected eye and explain them.
State the factor on which colour of scattered light
depends. Ans : [CBSE 2013]
(b) List any two natural phenomenon based on The person cannot read a book at a distance of 25 cm
scattering of light. from his eyes. So he is suffering from long sightedness/
Ans : [CBSE 2014] hypermetropia. It can be corrected by using convex
lens of suitable focal length.
(a) Scattering of light is the phenomenon due to which
light gets deflected by the atoms or molecules
of different atmospheric gases and suspended
particles present in atmosphere. Scattering
depends upon size of the particles of the medium
through which light passes.
(b) Two natural phenomenon based on scattering
are (i) Reddish colour of sky during sunrise and
sunset, (ii) Blue colour of sky.
(a) (i) P1 = - 6D as f1 = 1 =- 1 m
P1 6
f1 = - 100 cm = - 16.66 cm
6
(ii) P2 = + 2D as f2 = 1 =+ 1 m
P2 2
(b) B f2 = 50 cm
(b) (i) Due to continuous changes in the densities of
the atmospheric layers the apparent position
FIVE MARKS QUESTIONS of the star also changes; which make the
light coming from the distant point sized
star brighter and dimmer. The light coming
72. (a) A student is unable to see clearly the words
from the stars therefore gives a shaking
written on the black board placed at a distance of
appearances, which gives the impression of
approximately 3 m from him. Name the defect of
twinkling of a star.
vision the boy is suffering from. State the possible
(ii) Since the planets are closer to us. Due to this
causes of this defect and explain the method of
they appear a combination of large point-sizes
correcting it.
source of light, and change in the path of light
(b) Why do stars twinkle? Explain.
coming from the planets is not significant. So
Ans : [CBSE 2017] planets do not appear twinkling.
(a) He is suffering from myopia. (iii) Due to atmospheric refraction, a star appears
Causes of myopia: to be slightly higher than its actual position
(i) elongation of eye ball. in sky.
(ii) excessive curvature of cornea.
Concave lens of suitable power is used to correct 75. (a) State the reasons which lead to hypermetropia.
myopia. With the help of suitable diagram, explain this
(b) Light coming from stars when enter in the Earth’s defect of vision and its correction.
atmosphere suffers refraction from the atmospheric (b) Draw diagram of an experimental arrangement for
layers. Since the densities of atmospheric gases observing scattering of light in colloidal solution.
changes frequently. Since the stars are point sized Name the two chemicals used in this activity.
and at a far distance so sometimes star appear Ans : [All India 2015]
brighter and sometimes dimmer which gives the a. In hypermetropia a person cannot see near by
impression as the stars twinkling. objects clearly. Its is due to shortening of the eye
ball or due to increase in focal length of eye lens.
73. Account for the following:
To correct hypermetropia, a convex lens of suitable
a. Part of the human eye that helps in changing the
focal length is needed.
focal length of the eye lens.
b.
b. The condition resulting due to the eye lens
becoming cloudy.
c. The factors on which colour of the scattered white
light depends.
d. The range of vision of a normal eye.
e. The sky appears dark to the astronauts in the
space.
Ans : [CBSE 2016]
a. Ciliary muscles. 76. What is meant by scattering of light? Mention the
b. Cataract. factor on which it depends. Explain why the colour of
c. Size of the suspended particles in the medium the clear sky is blue? An Astronaut in space finds sky
through which white, light passes. to be dark. Explain reason for this observation.
d. 25 cm to infinity is the range of vision of normal Ans : [CBSE2015]
eye. (a) Scattering of light is the phenomenon due to
which light gets deflected by the atoms, molecules prism. Collect these coloured lights on a screen or
or particles of the medium when light falls on white sheet of paper. This prove that white light
them. These are known as scatterer particles. is made up of seven colours.
(b) Factors on which scattering depends are the size (b) Violet colour deviates most whereas red colour
of the atoms, molecules of the scatterer. deviates least because they have different speeds
(c) When sunlight falls on the atoms or molecules of in prism they have different refractive indices and
the gases shorter wavelengths J like of blue colour hence have different angle of deviation.
get scattered more due to which sky appears blue.
In space there is no atmosphere, so there is 80. (a) Explain why colour of clear sky appears blue
no scattering hence the sky appears dark/black. during the day with the help of diagram.
(b) Explain why Sun looks reddish at the time of
77. (a) How does refraction take place in the atmosphere? sunrise and sunset.
Why do stars twinkle but not the planets? Ans : [CBSE 2014]
(b) State any two effects of atmospheric refraction on
(a) Due to scattering of blue colours by the dust
the sun as observed from the earth.
particles present in the atmosphere.
Ans : [C8SE2015] (b) During the Sunrise or Sunset, Sun is at the
(a) Due to change in the density of atmospheric layers horizon, and sunlight travels a longer distance
when light travel through them gets refracted. It in the atmosphere. Due to this all colours get
is known as atmospheric refraction. Due to this scattered except red which reaches to the eye of
atmospheric refraction intensity of light, coming the observer to whom sun appears reddish in the
from a point sized star same times becomes more morning or evening.
and sometimes less, which gives the appearance of
twinkling of the star.
(b) (i) Sun can be seen two minute prior it rises and
two minute before it sets.
(ii) Twinkling of star.
CHAPTER 6
Life Process
45. Name the respiratory pigment in human beings? What Alveoli in the Nephrons in the
is its role? [All India 2013] Lungs Kidneys
Ans : 1. Thin walled, sac Thin walled,
Respiratory pigment, haemoglobin is present in red like structure, tubular structure,
blood cells. Haemoglobin has affinity for O2 thus surrounded surrounded
helping in its transport. with network of with network of
capillaries. capillaries.
46. What are enzyme? Do they play some role in our
2. Helps in exchange of Helps in filtration of
digestive system too?
gases between blood wastes like urea and
Ans : [CBSE 2013 C] and outside air, that uric acid from blood
They are chemically proteinaceous biocatalyst, which is, removal of CO2
increase or decrease the rate of a biochemical reaction. and taking in of 09.
The enzyme present in our digestive system 3. Waste produced is Waste produced is
help to breakdown of complex molecules of food into C02 and water vapor urine-salts, urea, uric
simpler ones. (gaseous waste) acid etc. dissolved in
water liquid waste
47. What is the role of large intestine? [All India 2013]
Ans : 53. What the components of transport system are in
highly organize plants? [All India 2017]
Water re-absorption occurs through villi, undigested
or
food is stored in rectum and thrown out through anus.
Exit is regulated by anal sphincter. 54. What is the difference between Xylem and Phloem?
(A)
Air being exhaled into lime water
92. In order to prepare a temporary mount of a leaf peel 97. A student set up apparatus as shown in figure. After 8
to observe stomata, which chemicals used for staining hours what is he likely to observe. Explain the reasons.
and mounting? [Delhi 2017]
Ans :
The chemicals used for staining and mounting
respectively are safranin and glycerine.
Ans :
a. Water would have risen in the tube as the oxygen
present in the airtight flask would have been used
up by germinating seeds for their respiration and
CO2 gas which is being produced them must
have been absorbed by KOH. As a result partial
Ans : vacuum created will make water from beaker
move up.
Nothing will happen to the level of water/ KOH as
b. Water will rise initially while seeds are germinating
vacuum will not be created in the flask.
but fall later.
94. Name the gap formed between the kidney shaped cells c. Water.
in the given figure. What role do they play? What are
Chap 10 : Light Reflaction and Refraction www.cbse.online
CHAPTER 10
Light Reflaction and Refraction
1. ONE MARK QUESTIONS convex mirror for seeing traffic at the rear?
Ans : [CBSE 2015]
Advantage of Convex Mirror: It provide wider view of
1. Write down four important characteristics of image the rear traffic.
formed by a plane mirror. Disadvantage: It does not give the correct distance of
Ans : [CBSE 2014] the vehicle at the rear.
Image is virtual, erect, laterally inverted and of same
5. What are the units of power of a lens?
size as object.
Ans : [CBSE 2015]
2. Describe a spherical mirror. If the focal length is measured in metre then the unit
Ans : [CBSE 2014] of power of a lens is dioptre.
Spherical mirror is a part of a sphere. If reflection
takes place from inside, it is said to be concave mirror,
and if the reflection takes place from outside surface
it is a convex mirror.
3. Define the following terms in relation to concave 6. Give two uses of a convex lens.
spherical mirror:
Ans : [All India 2016]
a. Pole
b. Centre of curvature Convex lens are used in (i) spectacles, (ii) telescopes,
c. Radius of curvature (iii) microscopes, (iv) camera.
d. Principal axis
e. Principal focus 7. Give one use of a concave lens.
f. Aperture Ans :
g. Focal length (each one mark) Concave lenses are used in (i) shaving mirror, (ii) flash
Ans : [CBSE2013, 2014, 2015] lights,
a. The mid point of mirror is known as pole. 8. What is a prism?
b. The centre of curvature of a spherical mirror is
Ans : [CBSE 2015,2016]
the centre of that sphere of which mirror is a part,
c. The distance between pole and centre of curvature A prism is an optical device with two triangular
is called radius of curvature of the mirror. bases along with three rectangular lateral surfaces
d. The straight line joining the pole and centre of commonly inclined at an angle of 60°.
curvature is called principal axis.
e. The point on the principal axis through which 9. Define the term reflection.
parallel rays to the principal axis passes or appear Ans : [CBSE 2016]
to pass after reflection. The bouncing back of a ray of light in the same
f. The diameter of the mirror or size of the mirror is medium after striking on a surface of an object.
called aperture.
g. The distance between focus and pole of a mirror 10. Define the terms:
is the focal length of the mirror. a. Angle of incidence
b. Angle of reflection
4. What are the advantages and disadvantages of using a c. Plane of incidence
Ans : [CBSE 2016] TWO MARKS QUESTIONS
a. The angle between incident ray and normal at the
point of incidence is called angle of incidence +i .
19. If the image formed by a convex lens is of the same
b. The angle between the reflected ray and normal at
the point of incidence is called angle of reflection size as that of the object. What is the position and
+r . nature of the image with respect to the lens?
c. A plane containing, incident ray, normal, and Ans : [CBSE 2012, 2013]
reflected ray is known as plane of incidence. The image will be real, inverted and will be formed at
centre of curvature of the lens.
11. State the laws of reflection.
Ans : [All India 2010] 20. How can you identify the three types of mirrors
Laws of Reflection without touching them?
a. The incident ray, the reflected ray and the normal Ans : [CBSE 2011]
at the point of incidence are always in the same a. If the image formed is erect, of same size, and at
plane. equal distance behind the mirror as object and is
b. +i = +r in front of the mirror, then mirror is plane.
b. If the image is of larger size and erect and changes
12. Explain why we see the sign front of to inverted and smaller size by changing the
the some vehicles. position of mirror from the object it is concave
Ans : [CBSE 2015] mirror.
Because the image of laterally inverted written letter c. If the image is smaller and erect for all positions
will once again laterally inverted in the rear view mirror of mirror from the object, it is a convex mirror.
of the vehicle going ahead and image so produced will
21. (a) What happens to a ray of fight when it travels
be erect image of the word AMBULANCE.
from one medium to another having equal
13. What is the radius of curvature of a plane mirror? refractive indices?
Ans : [CBSE 2015] (b) State the cause of refraction of fight.
Ans : [CBSE 2011]
The radius of curvature of a plane mirror is infinite.
(a) If a ray travels from one medium to another
14. How many images are formed by two parallel mirrors? medium of same refractive indices then it will not
Ans : [CBSE 2015] bend and travels in a straight line.
(b) Change in speed of light is the cause of
The images formed by two parallel plane mirrors will
refraction. -
be infinite.
22. (a) What should be the position of the object, when a
15. Name a mirror that can give an erect and enlarged
concave mirror is to be used:
image of an object.
(i) as a shaving mirror, and
Ans : [CBSE 2011, 2012, 2013] (ii) in torches producing parallel beam of fight?
Concave mirror (b) A man standing in front of a mirror finds his
image having a very small head and legs of normal
16. The radius of curvature of a spherical mirror is 20 cm. size. What type of mirror are used in designing
What is its focal length? such a mirror?
Ans : [CBSE 2011] Ans : [CBSE 2011]
Focal length f = R = 20 = 10 cm (a) (i) Face must be placed in between the pole and
2 2
focus of the mirror so that enlarged, erect
17. Light enters from air to glass having refractive index image of face can be formed.
1.50. What is the speed of light in glass? Speed of light (ii) At focus, because rays coming from the focus
in air is 3 # 108 m/s. after reflection will become parallel.
(b) It is a combination of convex mirror (small head)
Ans : [CBSE 2011]
and plane mirror (legs of normal size).
Speed of light in glass
8 23. Name the type of lens that can be used . as magnifying
v = c = 3 # 10 = 2 # 108 m/s
n 1.5 glass. Give reason(s) and draw a ray diagram to
support your answer.
18. The refractive index of diamond is 2.42. What is the Ans : [CBSE 2011]
meaning of this statement?
A convex lens of smaller focal length can be used as
Ans : [CBSE 2011]
magnifying glass. When an object is placed in between
The meaning of refractive index of diamond is 2.42 the pole and focus of the convex lens then enlarged,
is that speed of light in diamond is 1/2.42 times the erected and same side of object image is formed.
speed of light in air/vacuum D,
i.e. speed of light in diamond
8
v = c = 3 # 10 = 1.24 # 108 m/s
n 2.42
27. (a) Name the spherical mirror used as:
1. Shavingmirror,
2. Rearview mirror in vehicles,
3. Reflector in search – fights.
(b) Write any three differences between a real and
virtual image.
Ans : [CBSE 2012]
(a) 1. Concave mirror,
24. An object is placed at the following distances from a 2. Convex mirror,
concave mirror of focal length 15 cm. 3. Concave parabolic
(a) 10 cm (b) Differences between a real and virtual image :
(b) 20 cm
Real Image Virtual Image
(c) 30 cm
(d) 40 cm It can be taken on a It can not be taken on
Which position of the object will produce: screen a screen
(i) Virtual image It is always inverted It is always erected
(ii) A diminished real image
(iii) An enlarged real image When reflected or When reflected or
(iv) An image of same size. refracted rays actually refracted rays appear
Ans : [CBSE 2011] meet at a point, then to meet at a point
real image is formed. then virtual image is
Given, concave mirror of f= 15 cm. formed
a. When object is placed at a distance 10 cm from
mirror (between P and f) image is virtual, enlarged 28. What is meant by power of a lens? Give its SI unit.
and erected. When two or more lenses are placed in contact, what
b. For object in between 2F and 3 i.e. 40 cm image will their combined power?
is inverted, diminished and real.
c. For object in between F and C (20 cm), image is Ans : [CBSE 2012]
inverted, enlarged and real beyond 2F(C). Power of a lens is the ability of the lens to converge or
d. For object at 2F (30 cm), the image is of same diverge a ray of light incident on it. It is the reciprocal
size. of the focal length of the lens, i.e. P = 1f . The SI unit
of power is D(dioptre) if f is measured in metre.
25. (a) What is meant by refraction of fight?
(b) If on applying Cartesian sign convention for 29. For the same angle of incidence in media P, Q and
spherical lenses, the image distance obtained is R, the angles of refraction are 45°, 35° and 15°
negative, state the significance of the negative respectively. In which medium will the velocity of
sign. light be minimum? Give reason.
Ans : [CBSE 2011] Ans : [CBSE 2012]
(a) When a ray of light passes from one medium to
As n = c = sin i & v = c sin r
another it bends from its path. The phenomenon v sin r sin i
of bending a ray of light when it passes from one for same incident angle, v will be minimum for
medium to another is called refraction of light. minimum value of angle r i.e. medium R.
(b) In a lens if the image distance is negative then its
meaning is that image formed is at the same side 30. Define absolute refractive index. Absolute refractive
of object, virtual and erect. The lens is concave indices of medium A and medium B are na and nb
lens. respectively, what is the refractive index of medium
B with respect to medium A? How does the velocity
26. What is minimum number of rays required for locating of light vary with change in the optical density of the
the image formed by a concave mirror for an object? media?
Draw a ray diagram to show the formation of a virtual Ans : [CBSE 2012]
image by a concave mirror.
Absolute refractive index of a given medium, w.r.t.
Ans : [CBSE 2011]
air/vacuum is known as absolute refractive index of
We require minimum two rays for locating the image the medium
formed by a concave Speed of light in vacuum or air
n =
Speed of light in medium
n = c as c > v
v
n >1
b n = Velocity of light in B = vb = na
a
Velocity of light in A va nb
Higher the optical density, lesser is the velocity of
light in the medium
31. As the velocity of light increases, the refractive index Ans : [CBSE 2014]
of the medium decreases. Light enters from air to water When a ray passes from optically rarer to denser
having refractive index 4/3. Find the speed of light in medium it bends towards the normal.
water. The speed of light in vacuum is 3 # 108 m/s.
na = 1.36 alcohol
Ans : [CBSE 2012]
8
vw = 3 # 10 # 3
4
= 2.25 # 108 ms-1
f = 1 m = 1 m = + 10 m
P + 1.5 15
=+ 2 m
3
f =+ 66.7 cm 40. An object is placed at the focus of a convex lens. Draw
+ f means the lens is convex (converging) lens. a ray diagram to locate the position of the image
formed, if any. State its position and nature.
36. With the help of a ray diagram, show that the
Ans :
formation of the image of an object by a concave
mirror when it is placed at the centre of curvature. Image is formed at 3, image will be real, inverted
Ans : [CBSE 2012] and enlarged.
gn
= 2.42 = 1.61
d 1.50
52. A 4.5 cm needle is placed 12 cm away from a convex
mirror of focal length 15 cm. Give the location of
image and magnification. Describe what happens to
the image as the needle is moved farther from the
mirror.
Ans : [All India 2014]
Given: u = - 12 cm
f = + 15 cm
h1 = 4.5 cm
50. (a) A ray of light falls normally on a face of a glass
slab. What are the values of angle of incidence v = ?, m = ?
and angle of refraction of this ray? Mirror formula,
(b) Light enters from air to a medium X. Its speed 1+1 = 1
in medium X becomes 1.5 # 108 ms-1 . Find the v u f
refractive index of medium X.
1 =1-1 = 1 - 1 = 1 + 1
Ans : [All India 2012] v f u 15 - 12 15 12
a. When a ray of light falls normally on a glass slab v = + 6.6 cm
then i = 0 , and r = 0
b. vm = 1.5 # 108 m/s m = - v =- 6.6 = 0.55
u - 12
c = 3 # 108 m/s Size of image is smaller than size of object.
We know Refractive index
53. (a) State Snell’s law of refraction.
n = c (b) When a ray of light travelling in air enters
vm
obliquely into a glass slab, it is observed that the
8
or n = 3 # 10 8 = 2 light ray emerges parallel to the incident ray but
1.5 # 10 it is shifted sideways slightly. Draw a ray diagram
n =2 to illustrate it.
Ans : [All India 2014]
51. (a) Water has refractive index 1.33 and alcohol has
refractive index 1.36. Which of the two medium (a) Snell’s law = sin i = constant
is optically denser? Give reason for your answer. sin r
Draw a ray diagram to show the path of a ray of (Refractive index of the medium)
(b)
a concave mirror then its image moves from focus to
infinity.
v = - 20 cm = - 6.66 cm
3
Image formed is virtual, erect
m = hl = v
h u
hl = h # v = 5 # b- 20 # 1 l cm
u 3 - 20
= 5 # 1 cm = 5 cm = 1.66 cm
55. Discuss the position and nature of the image formed 3 3
by a concave mirror when the object is moved from
infinity towards the pole of the mirror. 59. If the image formed by a mirror for all positions of
Ans : [All India 2015] the object placed in front of it is always erect and
diminished, what type of mirror is it? Draw a ray
When an object is moved from 3 toward the pole of
diagram to justify your answer. Where and why do we if image formed is real. Express it in terms of
generally use this type of mirror? relation between v and u
Ans : [All India 2015] Ans : [All India 2016]
Only in convex mirror, for all positions of the object Given f = + 10 cm, u = ?
placed in front of it is always virtual, erected and For virtual image
diminished. Hence this mirror is convex mirror.
m =+ 2
As m = v or v = 2
u u
v = 2u ...(1)
1-1 = 1 ...(2)
v u f
Substituting (1) in (2)
1 -1 = 1
2u u 10
- 1 = 1
2u 10
u = - 5 cm
For real image, f = 10 cm, m =- 2
v = - 2 , v =- 2u
Convex mirrors are used in automobiles as a rear view u
mirror because of wider field of view and formation of 1-1 = 1
erect image. v u f
1 -1 = 1
60. The nature, size and position of image of an object - 2u u 10
produced by a lens or mirror are as shown below.
Identify the lens/ mirror (X) used in each case and - 3 = 1 or u =- 15 cm
2u 10
draw the corresponding complete ray diagram, (size
of the object about half of the image). 62. One half of a convex lens is covered with a black paper.
a. Show the formation of image of an object placed
at 2Fp of such covered lens with the help of ray
diagram. Mention the position and nature of
image.
b. Draw the fay diagram for same object at same
position in front of the same lens, but now
Ans : [CBSE 2016] uncovered. Will there be any difference in the
image obtained in the two cases? Give reason for
a. Convex lens when object is in between F and C your answer.
(2F).
Ans : [Delhi 2016]
a. If the lower half of the lens is covered even then it
will form a complete real, inverted image of same
size at C2(2F2) with reduced intensity of image.
b.
c. f = - 20 cm, v = - 15 cm, u = ?
c. When lens is cut along the principal axis its focal Lens formula
length remains same but intensity is reduced.
1-1 = 1
69. (a) Define principal focus of a spherical mirror.
v u f
(b) For what position of the object does a concave 1 -1 = 1
mirror form a real, inverted and diminished image - 15 u - 20
of the object? Draw the ray diagram.
(c) An object 4 cm high is placed at a distance of 6 - 1 = -1 + 1 = -3 + 4 = 1
u 20 15 60 60
cm in front of a concave mirror of focal length 12
u = - 60 cm
cm. Find the position of the image formed.
Ans : [All India 2011] 71. (a) Under what condition, a concave mirror produces
a. The point on the principal axis at which the light a virtual and magnified image? Draw a labelled
rays parallel to principal axis after reflection from ray diagram to show the formation of image in
a concave mirror actually meet or appear to come the above case. Also, state the position of object
from in convex mirror on the principal axis is to produce magnified and real image.
called principal focus. (b) A ray of light moving along principal axis is falling
b. In case of a concave mirror, when the object is on a concave mirror. Draw the path of reflected
placed beyond 2F(C) then image formed is real, ray. Also, state the values of angle of incidence
inverted and diminished. and reflection in this case.
Ans : [All India 2011]
a. A concave mirror will produce a virtual and a glass slab, it is observed that a ray of light
magnified image of the object if placed in between undergoing refraction emerges parallel to the
F and pole of the mirror. direction of incident ray. Why does it happen so?
Explain with the help of a diagram.
Ans : [All India 2011]
a. By holding concave mirror, focus the reflected
light incident on the mirror on a sheet of paper.
The distance between paper sheet and mirror
will give the approximate value of focal length of
concave mirror.
Real and magnified image will be formed if the b. Size of image reduces
object is placed in between 2F ^C h and F in front
of a concave mirror.
b. Ray of light moving along the principal axis will
retraces it path because incident angle +i =
reflected angle +r = 0 .
b.
iv.
i.
b. m =- 1
m = v =- 1
u
v =- u
(i) Size of image = Size of object
(ii) Minus sign mean that the image is real and
inverted. A concave mirror can produce it
ii. when object is kept at 2F ^C h .
f = 100 cm = 1 m
3 3
(a) (i) P1 = + 2D
f1 = 1 = 1 m
P1 2
f1 = 50 cm
Lens is convex lens.
(ii) P2 = - 4D
f2 = 1 = 1 m
P2 -4
f2 = - 25 cm
Lens is concave lens.
b. For the lens of power P = - 4D , we have
f = - 25 cm, u =- 100 cm
90. An object is placed 15 cm from a convex mirror of Lens formula, 1-1 = 1
v u f
radius of curvature 60 cm. Find the position of image
and its magnification. 1- 1 = 1
v ^- 100h - 25
Ans : [All India 2016]
1 =- 1 - 1 = -5
Here, u = - 15 cm v 25 100 100
R = + 60 cm v = - 20 cm
f = R =+ 30 cm 93. A 4.5 cm needle is placed 12 cm away from a convex
2
mirror of focal length 15 cm. Give the location of the
v =? image and its magnification.
m =? Ans : [All India 2016]
Mirror formula, 1 =1+1
f v u h1 = 4.5 cm, u =- 12 cm
1 =1- 1 f = + 15 cm, v = ?
30 v 15 1+1 = 1
Mirror formula,
1 = 1 + 1 = 1+2 = 3 v u f
v 30 15 30 30
1+ 1 = 1
v - 12 15 The position of screen must be 37.5 cm from the
mirror.
1 = 9
v 60 m = h2 =- v
h1 u
v = 60 = 6.7 cm
9 h2 = ^- 37.5h
4.0 ^- 25h
m = h2 =- v
h1 u
h2 = - 37.5 # 4 =- 6 cm
25
h 2 = - 6. 7
4.5 ^- 12h Image is enlarged, inverted, real and same side of
object.
h 2 = + 6. 7 # 4. 5
12
96. The power of a lens is 2.5 dioptre. What is the focal
=+ 2.5 cm length and the type of lens?
Size of image is +2.5, virtual, erect and smaller behind Ans : [Delhi 2015]
the mirror.
P = + 2.5 D
94. A convex mirror used on an automobile has 3 m
radius of curvature. If a bus is located at 5 m from f = 1 = 100 cm
P 2.5
this mirror, find the position, nature and size of the
image. f = 40 cm
Focal length is positive hence it is a convex lens.
Ans : [All India 2016]
97. A10 cm tall object is placed perpendicular to the
We have R = + 3 m
principal axis of a convex lens of focal length 30 cm.
f = R = 1.5 m The distance of the object from the lens is 20 cm. Find
2
the (i) position, (ii) nature and (iii) size of the image
u =- 5 m formed.
Mirror formula, Ans : [All India 2014]
I +1 =1 We have h1 = 10 cm
v u f
u = - 20 cm
I + 1 = 1
v ^- 5h 1.5 f = + 30 cm
I = 1 + 1 = 1 + .3 = 1.3 v =?
v 1.5 5 1.5 1.5 1-1 = 1
Lens formula,
v u f
v = 15 = 1.15 m
13 1- 1 = 1
v - 20 30
m = h2 =- v =- 1.15 = 0.23
h1 u ^- 5h 1 = 1 - 1 = 2 - 3 = -1
i.e. image is virtual, erected and smaller in size behind v 30 20 60 60
the mirror. v = - 60 cm
95. An object, 4.0 cm in size, is placed 25.0 cm in front m = h2 = v
of a concave mirror of focal length 15.0 cm. At what h1 u
distance from the mirror should a screen be placed in h2 = - 60 = 3
order to obtain a sharp image? Find the nature and 10 - 20
the size of the image.
h2 = + 30 cm
Ans : [All India 2016] Virtual, erect, enlarged image.
We have h1 = 4.0 cm 98. Find the position, nature and size of the image of an
u = - 25 cm object 3 cm high placed at a distance of 9 cm from a
f = - 15.0 cm concave mirror of focal length 18 cm.
Ans : [All India 2004]
v =?
h2 = ? h1 = 3 cm
u = - 9 cm
From mirror formula, 1 + 1 = 1
v u f
f = - 18 cm
1+ 1 = 1
v ^- 25h - 15 v =?
Mirror formula, 1+1 = 1
1 =- 1 + 1 = - 5 + 3 = - 2 v u f
v 15 25 75 75
1+ 1 = 1
v =- 75 =- 37.5 cm v -9 - 18
2
1 = 1 +1 = 1 v = - 30 cm
v 18 9 18
^- 30h
m = h2 = - v & h2 =-
v = 18 cm h1 u 1 ^- 15h
m = h2 =- v h2 = - 2 cm
h1 u Image is real, inverted and 2 times larger.
h2 =- 18
3 ^- 9h 101. A 2.0 cm tall object is placed perpendicular to the
principal axis of a convex lens of 1 focal length 10 cm.
h2 = 6 cm
The distance of the object from the lens is 15 cm. Find
Image is formed at a distance of 18 cm behind the
the position, nature and size of the image forms.
mirror which is erected, virtual and magnified image.
Ans : [All India 2013]
99. (a) A concave mirror produces three times enlarged
In convex lens, h1 = 2.0 cm
image of an object placed at 10 cm in front of it.
Calculate the focal length of the mirror. f = 10 cm
(b) Show the formation of the image with the help of u = - 15 cm
a ray diagram when object is placed 6 cm away
v =?
from the pole of a convex mirror.
Ans : [All India 2012] Lens formula, 1-1 = 1
v u f
(a) u =- 10 cm 1- 1 = 1
Let a real image is formed in concave mirror i.e., v ^- 15h 10
m =- v =- 3 1 = 1 - 1 = 1
u v 10 15 30
v = 3u v = 30 cm
v = 3 # 10 cm = 30 cm = h2 = v
1 =1+1 h1 u
Mirror formula,
f v u h2 = 30
1 = 1 + 1 2.0 - 15
f - 30 - 10 h2 = - 4 cm
1 =- 1 - 1 = -4
f 30 10 30 Image is real, inverted and four times enlarged.
f = - 30 = - 7.5 cm
4
(b) When u =- 6 cm from pole of a convex mirror.
For convex mirror, the image will be virtual,
erected and smaller.
CHAPTER 13
Magnetice Effect of Electric Current
In our house we get AC of voltage 220 V and frequency 18. What constitutes the field of a magnet?
50 Hz. Ans : [CBSE 2006]
11. Name the type of current: (a) used in household The magnetic field is created by the magnet or when
supply (b) given by a cell. a charge particle is moving with some velocity in both
Ans : [CBSE 2014] cases they produce a magnetic field around them. The
magnetic field is due to current or magnetic material.
a. We use alternating current in our houses which
changes to direction and magnitude with time. 19. What is the advantage of the third wire of earth
b. A cell supply direct current (DC) or unidirectional connection in domestic appliances?
current which flows only in one direction only. Ans : [CBSE 2006]
12. State the rule which you use to find the direction of In case of any electric fault in domestic appliances,
induced current or state Fleming’s right hand rule. current may comes in appliance body. The third wire
Ans : [CBSE 2015] called earth wire transfer this current to the earth and
user remains safe from any such electric shock.
Fleming’s right hand rule gives the direction of current
produced in a conductor. According to Fleming’s right 20. How can you show that the magnetic field produced
hand rule, if we stretch right hand thumb, forefinger by a given electric current in the wire decreases as the
and middle finger perpendicular to each other in distance from the wire decreases?
such a way that thumb points the direction of force Ans : [CBSE 2006]
on a conductor and forefinger points the direction
If we bring a magnetic compass from a distance to
of magnetic field then middle finger will point the
near a current carrying conductor its deflection goes
direction of current produced in the conductor.
on increasing and when magnetic compass is brought
13. How can it be shown that a magnetic field exists away from the current carrying wire its deflection goes
around a wire through which a direct current is on decreasing which shows that magnetic field near
passing. current carrying wire is maximum and decreasing on
Ans : [Delhi 2014] increasing the separation.
When we put a small magnetic compass near a current 21. When is the force experienced by a current carrying
carrying conductor it gets deflected, which shows that conductor placed in a magnetic field the maximum?
a magnetic field is produced near a current carrying Ans : [CBSE 2009]
conductor.
A current carrying conductor experience maximum
14. How is the strength of the magnetic field at a point force in a magnetic field when the direction of current
near a wire related to the strength of the electric is perpendicular to the magnetic field.
current flowing in the wire?
22. How is the induced current in a secondary coil related
Ans : [CBSE 2009] to current in a primary coil?
The magnetic field strength at a point near a wire is Ans : [CBSE 2009]
directly proportional to the current strength in the
Induced current in a secondary coil may be more or
conductor.
lesser than the current in primary coil depending upon
15. An alternating electric current has a frequency of 50 the number of turns in secondary.
Hz. How many times does it change its direction in
23. What is the pattern of field fines inside a solenoid?
one second?
What do they indicate?
Ans : [CBSE 2011]
Ans : [CBSE 2010]
50 Hz ac changes its direction 100 times in 1 sec.
The magnetic field inside a solenoid is uniform in the
form of parallel lines. A coil of many circular turns of insulated wire wrapped
closely in the form of a cylinder is called a solenoid.
24. How is the magnetic field produced in a solenoid used? In a current carrying solenoid magnetic field is same
Ans : [CBSE 2010] at all points inside it, i.e. field is uniform inside the
Magnetic field produced in a solenoid can be used in solenoid. The magnetic field inside a coil vary.
making a soft iron piece electromagnet.
33. An alpha particle (+ve charged particle) enters a
25. What does the direction of thumb indicate in the magnetic field at right angle to it as shown in figure.
right-hand thumb rule? Explain with the help of a relevant rule, the direction
of force acting on the alpha particle.
Ans : [CBSE 2010]
Thumb points the direction of current in the conductor
holding a straight conductor in right hand.
a. Magnetic field lines of a current carrying circular 44. What is meant by the term “magnetic field lines”?
loop.
List two properties of magnetic field lines. whether we require it or not.
Ans : [CBSE 2006] d. In series combination total potential difference
is divided among all appliances in proportion
Magnetic field lines are the path traced by a
to their resistance. So all appliance will not get
hypothetical north pole in the magnetic field of
required voltage to operate efficiently.
another magnet or current carrying conductor if it is
allowed to do so. 47. Explain what is short-circuiting and overloading in an
Properties: electric supply.
a. No two field lines are found to cross each other. Ans : [CBSE 2001]
b. Outside the magnet magnetic field lines travel
from N-pole to S-pole and inside the magnet from When live wire and neutral wire come in contact with
S-pole to N-pole. each other short circuit takes place. This may be due
to fault in electric circuit or when insulation of wire is
45. With the help of a neat diagram, describe how you damaged. During the short circuiting current increases
can generate induced current in a circuit. abruptly due to decrease in resistance in the circuit.
Ans : [CBSE 2006] This short circuiting leads the spark and house may
catch fire.
Take a coil of large number of turns and connect the
two ends of the coil with a galvanometer. Galvanometer Over loading means to draw the current by all
is a device used to detect the presence of current. electric appliances in the circuit more than maximum
permitted value of the current, overloading also leads
Now bring N pole of a strong magnet towards
the heating of wires which may damage the insulation
the coil. There is a momentary deflection in the
of wires.
galvanometer. Now bring the N pole away from
the coil, again there is a deflection in the opposite
direction in the galvanometer deflection in the
galvanometer shows that a current is induced in the
coil. The induced current can be produced by keeping
magnet stationary and giving movement to the coil,
or when both have a relative motion w.r.t. each other.
62. Why does a current carrying Conductor experiences Ans : [CBSE 2011]
a force when it is placed in a magnetic field? State
As per Fleming’s left hand rule the electron
Fleming’s left hand rule.
will experience a force upward. So it will move
Ans : [CBSE 2011] perpendicularly outward.
When a current carrying conductor is placed in
a magnetic field it experiences a force due to
interaction between the two magnetic fields due to
current carrying , conductor and given magnetic field
of a magnet. If we hold our thumb, forefinger, and
middle finger perpendicular to each other in such a
way that forefinger points the direction of magnetic
field, middle finger points the direction of charge q
(direction of current in conductor), then thumb will
point the direction force acting upon the conductor.
Fleming’s left hand rule -stretch the forefinger,
63. A student performs an experiment to study the
the middle finger and the thumb of the left hand
magnetic effect of current around a current carrying
mutually perpendicular to each other in such a way
straight conductor with the help of a magnetic
that forefinger points the direction of magnetic field,
compass. He reports that:
middle finger points the direction of current (opposite
a. the degree of deflection of the magnetic compass
to the flow of electrons) then the thumb will point the
increases when the compass is moved away from
direction of force on the conductor (charge).
the conductor.
b. the degree of deflection of the magnetic compass 66. (a) What is the direction of magnetic field lines inside
increases when the current through the conductor a bar magnet and outside of it?
is increased. (b) What does the degree of closeness of the field lines
Which of the above observations of the student represent?
appears to be wrong and why?
Ans : [CBSE 2011]
Ans : [CBSE 2011]
The direction of magnet lines of force inside a bar
The first statement is wrong because the strength of magnet is from S-pole to N-pole. Outside the bar
magnetic field decreases when we move away from magnet these emerge out from N-pole and go to the
a current carrying conductor. So deflection in the
compass, instead of increasing must decrease. 67. A magnetic compass shows a deflection when placed
near a current carrying wire. How will the deflection
64. A student while studying the force experienced by a of the compass get affected, if the current in the wire
current carrying conductor in a magnetic field records is increased? Support your answer with a reason.
the following observations:
Ans : [CBSE 2011]
a. The force experienced by the conductor increases
as the current is increased. If the strength of current is increased then deflection
b. The force experienced by the conductor decreases of compass also increase because magnetic field is
as the strength of the magnetic field is increased. directly proportional to the current in the conductor.
More magnetic field more deflection in the compass. a. \ r1 , i.e. magnetic field decreases with increase in
radius.
68. Draw magnetic field lines produced around a b. \ n , i.e. magnetic field increases with increase in
current carrying straight conductor passing through number of turns.
cardboard. How will the strength of the magnetic field
change, when the point where magnetic field is to be 71. Name and state the rule to determine the direction
determined, is moved away from the straight wire of a force experienced by a current carrying straight
carrying constant current? Justify your answer. conductor placed in a magnetic field which is
Ans : [CBSE 2012] perpendicular to it. Name a device that uses current
carrying conductor and magnetic field.
The strength of the magnetic field decreases when
the point where magnetic field is to be determined is Ans : [CBSE 2012]
moved away from the wire. Fleming’s left hand rule gives the direction of force
experienced by a current carrying straight conductor
placed in a magnetic field which is perpendicular to
it. According to Fleming’s left hand rule if we stretch
our left hand thumb, forefinger and middle finger
in such a way that forefinger points the direction of
magnetic field, middle finger points the direction of
current then thumb will give the direction of force on
the conductor.
I = Total Power = nP
V V
= 2 # 1.1 kW
220 V
= 2 # 1.1 # 1000 W = 10 A
220 V
74. A uniform magnetic field is directed vertically So a fuse wire of rating must be greater than 10 A.
upwards. In which direction in this field should an
a-particle (which are positively charged particles) be 77. Can a freely suspended current carrying solenoid
projected so that it is deflected south ward? Name stay in any direction? Justify your answer. What will
and state the rule you have used to find the direction happen when the direction of current in the solenoid
in this case. is reversed? Explain.
Ans : [CBSE 2016] Ans : [CBSE 2015]
Forefinger - direction of magnetic field (upwards). No, current carrying solenoid behaves like a bar
Thumb - direction of force (southwards) Middle finger magnet and will stay only geographical N and S
gives direction of current or direction of positively direction. If the direction of current is reversed then
charged particle (East) i.e. from west to east a particles the polarity of the magnet will change and hence will
must be projected. rotate through an angle of 180°.
78. What is meant by electromagnetic induction? State carrying circular coil changes, if we increase the:
the rule which helps in determining direction of a. value of current flowing through it?
induced current. b. distance of point P from the coil?
Ans : [CBSE 2015] c. number of turns of the coil?
Electromagnetic induction is the phenomenon of Ans : [CBSE 2011, 2014]
production of emf (potential difference) or current a. Magnetic field is directly proportional to current
in a coil due to change in magnetic field around it. so magnetic field increases when current increases.
Fleming right hand rule: If we stretch our right hand b. If we increase the distance of point P, magnetic
thumb, forefinger and middle finger perpendicular to field decreases.
each other in such a way that forefinger points the
direction of magnetic field, and thumb points the
direction of force acting on the conductor (motion
of the conductor), then the middle finger points the
direction of induced current in the conductor.
The direction of magnetic field due to current at A 82. What happens to the deflection of the compass needle
is from north to south and at B from south to north. placed at a point near current carrying straight
Therefore, at A earth’s magnetic field and field due to conductor:
current are in opposite direction and at B earth’s a. if the current is increased?
magnetic field and magnetic field due to current are b. if the direction of current in the conductor is
in same direction. changed (reversed)?
c. if compass is moved away from the conductor?
Ans : [CBSE 2011, 2014]
a. If the current increases deflection of compass
increases.
b. If the direction of current is reversed the deflection
in the compass needle is also reversed.
c. Deflection of the compass needle decreases when
compass is moved away from the conductor.
96. (a) Mention the colour code used for live, neutral and
earth wire.
(b) You want to connect a 2 kW electric oven in the
electric circuit. In which power line would you
connect it and why? What may happen if you
connect it wrongly in the other power line?
Ans : [CBSE 2013]
(a) Live wire – Red
92. A coil made of insulated copper wire is connected to
a galvanometer. What will happen to the deflection Neutral wire – Black
of the galvanometer if this coil is moved towards a Earth wire – Green
stationary bar magnet and then moved away from it? (b) 2 kW electric iron draws large current. If it is
Give reason for your answer and name the phenomenon connected to a socket of 5Athen fuse will be
involved. blown. So it is connected in power socket of 15 A.
Ans : [CBSE 2011]
In both the case there is a change in magnetic field FIVE MARKS QUESTIONS
associated with the coil, an induced current is produced
in the coil, but in opposite direction. This phenomenon
is called electromagnetic induction (EMI). 97. (a) State Fleming’s left hand rule.
(b) Write the principle of working of an electric motor.
93. What is meant by overloading of an electrical circuit?
(c) Explain the function of the following parts of an
Explain two possible causes due to which overloading electric motor.
may occur in household circuit. Explain one precaution
that should be taken to avoid the overloading of (i) Armature (ii) Brushes (iii) Split ring
domestic electric circuit. Ans : [CBSE 2017]
Ans : [CBSE 2012] (a) Fleming’s left hand rule state that if the thumb,
Connecting large number of electric appliances in forefinger and middle finger are stretched
one socket whose load is more than the maximum perpendicular to each other in such a way that
permitted limit. The two possible cause are forefinger indicates the direction of magnetic field,
a. all of a sudden supply of high voltage and middle finger indicate the direction of current
b. too many devices connected in a single socket. in the conductor then thumb will indicate the
direction of force on the conductor.
Precautions:
(b) The principle of electric motor is that when a
a. use of voltage regulator,
current carrying coil is placed in a magnetic field
b. load of a socket must be greater than its permitted
it experiences a torque and if the coil is allowed it
rating.
rotates in the magnetic field.
94. Write one difference between direct current and (c) Function of the parts of an electric motor :
alternating current. Which one of the two is mostly (1) Armature: Armature is a large number
produced at power stations in our country? Name one of turns of the coil on soft iron core which
device which provides alternating current. State one rotates in magnetic field.
important advantage of using alternating current. (2) Brushes: They allow current to pass from
external source to armature.
Ans : [CBSE 2012]
(3) Split rings: Split rings are of copper, splits into
Direct current has constant magnitude and two halves and make a connection between
unidirectional current. Alternating current changes its armature and brushes.
magnitude and direction alternatively.
a. Alternating current is produced in power stations 98. (a) Explain what is the difference between direct
in India. current and alternating current? Write one
important advantage of using alternating current. (ii) In bar magnet, magnetism is permanent but
(b) An air conditioner of 2 kW is used in an electric in solenoid it exists only till there is a current
circuit having a fuse of 10 A rating. If the potential in solenoid.
difference of the supply is 220 V, will the fuse
be able to withstand, when the air conditioner is
switched on? Justify your answer.
Ans : [CBSE 2016]
(a) Direct current is a unidirectional current with
constant magnitude. Alternating current is a
current which change its magnitude and direction
after a fixed period. AC voltage can be increased
or decreased. Where is dc voltage cannot be
increased or decreased. AC can be transmitted to
long distances with lesser power loss.
(b) Given P = 2 kW and V = 200 volt,
Power, P = VI & I = VP
I = 2000
220 = 9.09 A
The rating of the fuse wire is 10 A which is greater
than current drawn by air conditioner so when air
conditioner is switched on, fuse will not blow off.
Ans : [CBSE2016]
(a) Fix a cardboard and pass a straight wire through a
hole in cardboard and connect the two ends of the
(b) A current carrying solenoid behaves as a bar
wire with a cell through a rheostat and key with
magnet one end of the solenoid behaves like a N
a cell. Sprinkle iron filings uniformly on the card
pole and another end as S pole like two poles in
board. Pass the current in the wire and gently tap
bar magnet, so the field lines of a solenoid and bar
the card board. You would find that iron filings
magnet appear same in many ways:
align themselves in concentric circles around the
(i) Magnetic lines of force inside the body is
copper wire which represents the magnetic field
strong and uniform.
around the current carrying conductor. The
(ii) In both the cases stronger field exists at the
direction of magnetic field changes on reversing
poles compared to the middle part.
the direction of current.
Dissimilarities
(b) According to Fleming’s left hand rule the force on
(i) In bar magnet, the poles are not exactly at
the oc-particle will be inwards perpendicular to
the ends of the magnet, in solenoid poles can
the plane of paper, so \-particle will move in the
be considered to be lying at the edges.
direction of force.
In both the cases of a current carrying solenoid and
bar magnet the magnetic lines of forces inside the
body is strong and uniform. In both the cases there
exists stronger magnetic field at the poles compared
to the middle parts.
Dissimilarities:
(i) The poles in a bar magnet do not exist at the
extreme ends of the magnet whereas in solenoid
the poles can be considered to be lying at the
edge.
121. (a) The given figure shows a domestic electric circuit. A solenoid is a large number of turns of insulated
Study this circuit carefully. List any two errors in copper wires having shape of a cylinder or helix.
Magnetic field are given in following figures.
(a) Fix a white paper sheet on a drawing board with
the help of copper pins. Keep a bar magnet in the
centre of the paper and sprinkle some iron filings
uniformly around the bar magnet. Tap the board
gently. Iron filings arrange themselves in a pattern
as shown in figure. These iron filings near the bar
magnet align themselves along the magnetic field
lines.
CHAPTER 3
Metals and Non-Metals
22. How are ionic compounds formed? 31. Why do we use copper and aluminium wire for
Ans : [CBSE 2012] transmission of electric current?
Ans : [CBSE 2011]
Gallium has a melting point 303 K, it melts on palm.
Copper and aluminium are ductile and good
23. It nature, aluminium is found in combined state conductors of electricity, therefore they are used in
whereas silver/gold are found in free state. Give transmission wires.
reason.
Ans : [CBSE 2012, 2010, 2011] 32. Why do we use copper and aluminium wire for the
transmission of electric current?
Aluminium is reactive metal, therefore it is found in
Ans : [CBSE 2011]
combined state whereas silver/gold are less reactive
(noble) metals and so are found in free state. It is has 4 to 8 valence electrons, it is a non-metal.
Exception is hydrogen which has 1 valence electron
24. Why do ionic compounds conduct electricity in molten and He which has 2 valence electrons, but these are
state and not in solid state? non- metals.
Ans : [CBSE 2010,2012]
33. Name two metals which are found in nature in free
Ionic compounds do not conduct electricity in solid state.
state because ions are not free to move. In molten
Ans : [CBSE 2011]
state, ions are free to move.
Gold and silver are found in free state.
25. Write a balanced chemical equation for the reaction:
Aluminium when heated in air. Write the name of the 34. Why do we apply paint on iron grills?
product formed. Ans : [CBSE 2011]
Ans : [CBSE 2012] Iron grills are painted to prevent them from rusting.
35. Why does stainless steel not get rusted easily? c. Which is used to galvanise iron articles?
Ans : [CBSE 2010] d. Whose articles when exposed to air forms a black
coating?
Stainless steel is an alloy of Fe, C, Cr and Ni, therefore
it does not get rusted. Ans : [CBSE 2016]
a. Carbon makes it hard and strong. Tungsten also
36. Why do we use gold and platinum metals in jewellery? makes it hard and strong.
Ans : [CBSE 2010] b. Mercury is alloyed with metals to form amalgam.
Gold and Platinum are lustrous metals and do hot c. Zinc metal is used for coating over iron metal to
react with substances present in the atmosphere, galvanise iron.
therefore remain lustrous for a long time. d. Silver articles acquire black coating when left
exposed to the atmosphere.
37. Which property makes solder alloy suitable for welding
electric wires? 45. Which of the following listed metals can displace zinc
from its salt solution? Give reason for your answer
Ans : [CBSE 2010]
with a chemical equation:
Its melting point is low which makes solder suitable Copper, Lead, Magnesium, Silver
for welding. Ans : [CBSE 2016]
38. What is the valency of silicon with atomic number 14? Magnesium can displace zinc from zinc salt solution
Ans : [CBSE 2010] because Mg is more reactive than zinc:
Mg(s) + ZnSO4(aq) $ MgSO4(aq) + Zn(s)
Si (2,8,4): Its valency is 4 because it can share four
electrons to become stable. 46. The reaction of metal X with Fe2O3 is highly exothermic
and is used to join railway tracks. Identify metal X.
39. What is the valency of phosphorus with atomic
Write the chemical equation for the reaction.
number 15?
Ans : [CBSE 2016]
Ans : [CBSE 2010]
X is Al.
P (2, 8, 5): Its valency is 3 because it can gain three 2Al + Fe2O3 $ Al2O3 + 2Fe
electrons to become stable.
47. (a) In electrolytic refining of impure copper metal,
40. What is the valency of an element with atomic number
what are used as cathode and anode?
35? (b) Show the formation of HgCl2 from magnesium
Ans : [CBSE 2010] and chlorine atoms.
Br(35) (2, 8, 18, 7): Its valency is equal to 1 because Ans : [CBSE 2016]
it can gain one electron to become stable. (a) Pure copper is used as the cathode, impure copper
41. Arrange the following metals in decreasing order of is used as the anode.
reactivity are Na, K, Cu, Ag
(b)
Ans : [CBSE 2009]
K > Na > Cu > Ag is the decreasing order of reactivity. 48. Write one example of each of
a. a metal which is so soft, that it can be cut with a
42. Which of the following two metals will melt at body
knife and a non-metal which is the hardest known
temperature (37°C): Gallium, Magnesium, Caesium,
substance.
Aluminium?
b. a metal and a non-metal which exist as liquid at
Ans : [CBSE 2008(C)] room temperature.
Gallium and Caesium will melt at the body Ans : [CBSE 2015]
temperature.
a. Sodium is so soft that it can be easily cut with a
43. Show the electronic transfer in formation of MgCl2 knife.
from its elements. b. Diamond is the allotrope of carbon, which is the
Ans : [CBSE 2008] hardest known substance and a non-metal.
c. Mercury is a metal and Bromine is a non-
metal which are found in liquid state at room
temperature.
52. A copper plate was dipped into a solution of silver 57. Define alloy. How an is alloy prepared?
nitrate. After sometime a black layer was observed on Ans : [CBSE 2014]
the surface of copper plate. State the reason for it and
Alloy is an homogeneous mixture of two or more
write chemical equation for the reaction involved.
metals. One of them can be a non-metal also. Alloys
Ans : [CBSE 2015] are made by melting two metals together and then
Copper is more reactive than Ag, therefore it can cooling it.
displace Ag from AgNO3 solution:
Cu(s) + 2AgNO3(aq) $ Cu(NO3)2(aq) + 2Ag(s) 58. In one of the methods of rust prevention, iron is not
coated with anything. Name that method and define
53. Give reason: it.
a. Carbonate and sulphide ores are usually converted Ans : [CBSE 2014]
into oxides during the process of extraction of
The method is alloy formation, by adding a suitable
metals.
metal or a non-metal.
b. Ionic compounds generally have high melting
point. Alloy is. a homogeneous mixture of two or more
c. Hydrogen is not a metal but has been assigned a metals. One of them can be a non- metal also. This
place in the reactivity services of metals. process is called alloying.
d. The galvanised iron article is protected against
rusting even if the zinc layer is broken. 59. Give reasons for the following:
a. Platinum, gold and silver are used for making
Ans : [CBSE 2015]
jewellery.
a. It is easier to reduce an oxide than sulphide and b. Sodium, potassium and lithium are stored under
carbonate ores. kerosene oil.
b. It is due to strong forces of attraction between c. Aluminium is highly reactive metal but still used
positive and negative ions. for making cooking utensils.
c. Hydrogen form H+ ions like metals, therefore it is d. Carbonate and sulphide ores are usually converted
included in the activity series. into oxides during the process of extraction.
d. Zinc is more reactive than iron, therefore it will Ans : [CBSE 2013, 2014]
get easily oxidised in preference to Fe and hence
protect iron from rusting even if zinc coating is a. It is because they are lustrous metals.
broken. b. These are highly reactive metals.
c. It forms an oxide layer on its surface which makes
54. A compound Z is formed by transfer of electrons from it passive.
the metal X to a non-metal Y, Identify the type of d. It is easier to reduce a metal oxide than sulphides
bond formed in the compound. List three properties and carbonates.
of compound formed by such type of bonds.
60. What happens to potassium and sodium if they are
Ans : [CBSE 2014]
kept in open? Why are they 3 immersed in kerosene
The bond formed is ionic bond: oil?
a. The compound will have high melting and boiling Ans : [CBSE 2013]
point.
b. It will be soluble in water. Potassium and Sodium if kept in open, can catch the
c. It will conduct electricity in molten state as well presence of moisture.
as in aqueous solution. They are immersed in kerosene so that they do
not react with air and H2O present in the atmosphere.
55. Give reason for the following:
a. School bells are made up of metals. 61. Why hydrogen gas is not evolved when a metal reacts
with nitric acid? Molecular weight of NaOH = 40 g mol-1. Y is NaOH
Ans : [CBSE 2013] and Z is H2 gas which easily catches fire.
Nitric acid is an oxidising agent, therefore H2(g) is not 68. Name the following:
evolved on reaction with metal. Dilute HNO3 mostly a. A metal which is preserved in kerosene.
gets reduced to NO in this process. b. A lustrous coloured non-metal.
c. A metal which melts when kept on palm.
62. Why is iron galvanised with zinc? Can it be galvanised
d. A metal which is a poor conductor of heat.
with copper? If not, why?
Ans : [CBSE 2013, 2012]
Ans : [CBSE 2013]
a. Sodium or Potassium
Iron is galvanised by zinc because zinc is more reactive
b. Iodine
than Fe. Iron cannot be galvanised by copper because
c. Gallium
copper is less reactive than iron and therefore iron
d. Lead
itself gets corroded when coated with copper.
69. Define the term alloy. Write the constituents of
63. Differentiate between roasting and calcination giving
Bronze.
examples.
Ans : [CBSE 2013]
Ans : [CBSE 2013]
Alloy is a homogeneous mixture of two or more metals.
Roasting Calcination One of them can be a non- metal also.
1. It is done in the It is done in the Alloys are made by melting two metals together
presence of oxygen. absence of oxygen. and then cooling it.
2. It is done with It is done with 70. Why do silver articles turn black and copper items
sulphide ores eg. carbonate ores e.g. turn green after sometime?
2ZnS + 3O 2 $ 2ZnO + 2SO 2 FeCO 3 Heat
FeO (s) + CO 2 (g) Ans : [CBSE 2013]
Silver turns black due to the formation of Ag2S, (Silver
sulphide). Copper turns green due to formation of
64. Name the ore of mercury. How mercury is extracted basic copper carbonate.
from its ore?
Ans : [CBSE 2013] 71. Give reasons for the following:
a. Iron grills are frequently painted.
Cinnabar (HgS) is the ore of mercury.
b. Gold ornaments retain their lustre even after
Roasting:
several years of use.
HgS(s) + O2(g) $ 2Hg(l) + SO2(g)
Cinnabar, on roasting gives Mercury and sulphur Ans : [CBSE 2013]
dioxide. Mercury can be purified by distillation a. It is done to prevent them from rusting.
process. b. Gold is least reactive, therefore it remains lustrous
even after several years.
65. How is copper obtained from Cu2S? Give reactions.
Ans : [CBSE 2013] 72. Give reasons for the following:
a. Aluminium oxide is considered has amphoteric
a. Roasting:
oxide.
Cu2S(s) + 3O2(g) $ 2Cu2O(s) + SO2(g)
b. Ionic compounds conduct electricity in molten
b. Self-Reduction:
Heat state.
Cu2S(s) + 2Cu2O(s) 6Cu(s) + SO2(g)
Ans : [CBSE 2012]
66. Explain, why calcium metal after reacting with water a. Al2O3 reacts with acids as well as bases, therefore
starts floating on its surface. Write the chemical it is regarded as amphoteric oxide.
equation for the reaction. b. In molten state, ions are free to move, therefore it
Ans : [CBSE 2013, 2012] conducts electricity.
Calcium reacts with water to form Ca(OH)2 and H2
73. How do properties of iron change when
gas.
a. a small quantity of carbon is mixed in it?
Ca(s) + 2H2O(l) $ Ca(OH)2(aq) + H2(g)
b. nickel and chromium are mixed in it?
The bubbles of hydrogen gas sticks to the surface of
calcium and therefore it floats over water. Ans : [CBSE 2012]
a. It becomes hard and does not get rusted.
67. When a metal X is reacted with cold water, it gives b. It becomes lustrous and malleable and so it does
a basic compound Y with molecular formula XOH not get rusted.
(Molecular mass 40) and liberates a gas Z which easily
catches fire. Identify X, Y, Z. 74. You must have seen tarnished copper vessels being
Ans : [CBSE 2013, 2012] cleaned with lemon or tamarind juice. Explain why
these sour substances are effective in cleaning the
X is Na (Sodium).
vessels.
2Na(s) + 2H2O(l) $ 2NaOH(aq) + H2(s)
(Cold) Ans : [CBSE 2012]
Copper vessel coated with a green layer of CuCO3. and then cooling the mould of two metals being mixed
Cu(OH)2 which reacts with acid present in lemon or that forms the alloy.
tamarind juice and get removed it. Some substances Solder is an alloy of lead and tin. It has low melting
contain acids which react with basic substances to point, therefore it is used for welding purposes.
form soluble salt which can be easily removed.
82. Using the electronic configuration, explain how
75. Name two metals which can be used to reduce metal
magnesium atom combines with oxygen atom to form
oxides to metals. magnesium oxide by transfer of electrons.
Ans : [CBSE 2012] Ans : [CBSE 2011]
Aluminium and Magnesium
2Al + Fe2O3 $ Al2O3 + 2Fe
3Mg + Fe2O3 $ 3MgO + 2Fe
92. Give reason for the following: At cathode: Zn2+ + 2e- $ Zn(s)
(Pure)
a. Metals can be given different shapes according to
b. Copper sulphite is concentrated by froth floation
our needs.
process.
b. Hydrogen is not evolved when a metal reacts with
i. 2Cu2S + 3O2 $ 2Cu2O + 2SO2
nitric acid.
ii. Reduction: Cu2S + 2Cu2O $ 6Cu + SO2
Ans : [CBSE 2008(C)] iii. Electrolytic refining:
a. Metals are malleable, therefore they can be given At cathode: Cu2+ + 2e- $ Cu
(pure)
different shapes.
At anode: Cu $ Cu2+ + 2e-
b. It is because HNO3(dil.) is a good oxidising agent. (Impure)
129. Observe the two test tubes A and B as shown in b. It is an ionic compound.
the diagram given below and answer the following 1. It is soluble in water.
questions : 2. It conducts electricity in molten state and in
aqueous solution.
3. It is a hard solid.
135. A metal (E) is stored under kerosene oil. When a small This reaction need heat to start but it is highly
piece of it is left open in air, it catches fire. When exothermic.
the product formed is dissolved in water, it turns red This reaction belongs to the category of:
litmus blue. (1) Displacement reaction,
a. Name the metal (E). (2) Redox reaction.
b. Write the chemical equation for the reaction 137. Four metals A, B, C and D are added to the following
when it is exposed to air and when the product is aqueous solutions one by one. The observations made
dissolved in water. are tabulated below:
c. Explain the process by which metal is obtained
from its molten chloride. Iron (II) Copper (II) Zinc Silver nitrate
Ans : [CBSE 2012,2011] sulphate sulphate sulphate
A No Reaction Reddish Brown .......... ..........
a. E is sodium metal. Deposit
b. 2Na + 2H2O $ 2NaOH + H2
B Grey Deposit .......... No Reaction ..........
H2 gas will catch fire.
NaOH turns red litmus blue. C No Reaction No Reaction No Reaction White Shining
4Na(s) + O2(s) $ 2Na2O(s) Deposit
Na2O + H2O(aq) $ 2NaOH(aq) D No Reaction No Reaction No Reaction No Reaction
c. It is obtained by electrolytic reduction e.g., ‘Na’
metal is obtained by electrolysis of molten NaCl: Answer the following questions based on the above
NaCl
Electrolysis
N+ + Cl- observations:
Molten a. Which is the most active metal and why?
At cathode: Na+ + e- $ Na b. What would be observed if B is added to copper
At anode: Cl- $ Cl + e- (II) sulphate solution and why?
Cl + Cl $ Cl2 c. Arrange the metals A, B, C and D in order of
increasing reactivity.
136. a.Write two differences between calcination and d. Container of which metal can be used to store
roasting. [CBSE 2012] both zinc sulphate solution as well as silver nitrate
b. ‘No reaction takes place when granules of a solid solution?
‘A’ is mixed with a powder of solid ‘B’. However e. Which of the above solutions can be easily stored
when the mixture is heated, a reaction starts with in a container made up of any of these metals?
the evolution of much heat. Product ‘C’ of the
Ans : [CBSE Sample Paper 2009]
reaction settles down as a liquid metal and a solid
product ‘D’ keeps on floating over the liquid ‘C’. a. B is the most reactive because it displaces Fe. It
This reaction is sometimes used for making metals will displaces Fe. It will displace Cu as well as Ag
for ready use in odd places. also.
a. Based on this information, make assumptions b. B will displace copper from CuSO4 solution
about metals ‘A’ and ‘B’ and corresponding because it is more reactive than Cu.
deductions about ‘C’ and ‘D’ and write a balanced c. D is least reactive and D<C<A<B is the
chemical equation for the reaction. Include in increasing order of reactivity.
the chemical equation about the physical states d. Container of metal D can be used to store both
of the reactants and products, need for heating ZnSO4 and AgNO3.
for starting the reaction and the reaction being e. Zinc sulphate solution can be stored in container
exothermic. made up any of the metals A, B, C, D because none
b. Name two types of chemical reactions to which of them could displace zinc from zinc sulphate as
this reaction can belong to. these are less reactive than zinc.
Ans : [CBSE 2012]
a. Differences between calcination and roasting.
Roasting Calcination
1. It is done in the It is done in the
presence of oxygen. absence of oxygen.
2. It is done with It is done with
sulphide ores eg. carbonate ores e.g.
Heat
2ZnS + 3O2 FeCO3
$ FeO(s) +
2ZnO + CO2(g)
2SO2
b. A is Al, B is Fe2O3, C is molten Iron, D is Al2O3
(Molten)
Chap 5 : Periodic Classification of Elements www.cbse.online
CHAPTER 5
Periodic Classification of Elements
131. Based on the group valency of elements state the 135. Two elements X and Y have atomic 12 and 17
formula for the following giving justification for each: respectively.
a. Oxides of 1st group elements, a. Write the electronic configuration of both these
b. Halides of the elements of group 13, and elements.
c. Compounds formed when an element of group 2 b. Which type of bond will they form?
combines with an element of group 16. c. Write the formula of the compound formed by
their combination (in terms of X and Y).
Ans : [CBSE 2014]
Ans : [CBSE 2014]
a. M2O
b. MCl3 a. X: 2, 8, 2; Y: 2, 8,7
c. CaO b. They will form ionic bond.
155. In the following table, are given eight elements A, 158. The position of three elements A, B and C in the
B, C, D, E, F, G and H (here letters are not the Periodic Table is shown below:
usual symbols of the elements) of the Modem Periodic
Table with the atomic numbers of the elements in Group 16 Group 17
parenthesis. - -
Period Group 1 Group 2 - A
2 A(3) E(4) - -
3 B(11) F(12) B C
4 C(19) G(20) Giving reasons, explain the following:
a. Element ‘A’ is a non-metal.
5 D(37) H(38) b. Element ‘B’ has a larger atomic size than element
a. What is the electronic configuration of‘F? ‘C’.
b. What is number of valence electrons in ‘F’ ? c. Element ‘C’ has a valency of 1.
c. What is number of shells in *F’ ? Ans : [CBSE 2008C]
d. Arrange E, F, G, H in decreasing order of atomic
a. A is a non-metal because it has 7 valence electrons,
size.
it can gain one electron to form anion.
e. State whether F is a metal or a non¬metal.
b. B has less electrons and protons, less forces of
f. Out of three elements B, E and F, which one has
attraction between the nucleus and valence
biggest atomic size.
electrons, therefore it is bigger in size.
Ans : [CBSE 2010] c. C can gain 1 electron to become stable, therefore
its valency is equal to 1. group of the periodic table. Their atomic numbers are
4, 12, 20 respectively
159. The position of three elements A, B and C in the a. Write the electronic configuration of these
Periodic Table is shown below: elements.
b. Write the valency exhibited by them,
Group " 1 2 13 14 15 16 17
c. Which three elements will be the most reactive?
Period
. Ans : [CBSE 2013]
a.
1 B
2 A Shell K L M N
3 C Be(4) : 2 2
H He
Li Be B C N O F Ne
a. Pick out the two elements which are known as
Na Mg Al Si P S Cl Ar alkali metals.
Using this table, explain why b. Pick out the two elements which have valency of
a. Li and Na are considered as active metals. 4.
b. Atomic size of Mg is less than that of Na. c. Pick out two elements which belong to group 16
c. Fluorine is more reactive than chlorine. of the periodic table.
Ans : [CBSE 2009] Ans : [CBSE 2013]
a. Li and Na have largest atomic size in respective a. Na, K are alkali metals.
period, therefore they can lose an electron easily, b. C, Si have valency equal to 4
hence they are active metals. c. O and S belongs to group 16.
b. Mg has 12 protons and 12 electrons which has
164. Examine elements of the third period: Na, Mg, Al, Si,
more forces of attraction, therefore, it is smaller
P, S, Cl and Ar Answer the following:
in size than Na which is having 11 protons and 11
a. Choose (i) Metals, (ii) Non-metals out of these
electrons.
elements.
c. F is smaller in size, it can gain electrons easily,
b. On which side of periodic table we find (i) metals
therefore, it is more reactive than Cl.
(ii) non-metals.
162. The element Be, Mg and Ca are placed in the second c. Name metalloids out of the elements given above.
Where are they located in the periodic table? Ans : [CBSE 2015]
Ans : [CBSE 2011] a. Group 18
a. (i) Na, Mg, A1 are metals. b. They will form anions.
(ii) P, S, Cl, Ar are non-metals. c. F will have similar properties to ‘C’.
b. (i) Metals are placed on the left hand side and d. A has only one shell.
middle part of the periodic table. e. A and D both are inert elements.
(ii) Non-metals are placed on the right hand side f. C is the most abundant element in the Earth
of periodic table. crust.
c. Silicon is a metalloid. They are located between
metals and non-metals at the border line in a zig- FIVE MARKS QUESTIONS
zag manner.
CHAPTER 8
How Do Organisms Reproduce
3. Name the method by which Plasmodium reproduce 12. Give the respective scientific terms used for studying:
under favourable conditions. Is this method sexual or a. The mechanism by which variations are created
asexual? and inherited and
Ans : [Delhi 2017] b. The development of new type of organisms from
the existing ones.
Multiple Fission. Asexual
Ans : [CBSE 2015]
4. When a cell reproduces, what happens to its DNA? a. Heredity
Ans : [All India 2017] b. Fission.
Its DNA first doubles up followed by its equal and
accurate division between two daughter cells.
19. How does the embryo gets nourishment from the Cutting and grafting.
mother?
29. What is reproduction?
Ans : [All India 2013]
Ans : [All India 2009 C]
Through placenta.
Reproduction is the process of producing individuals
20. Why does the lining of uterus become thick and of its own kind.
spongy every month?
30. What is the effect of DNA copying which is not
Ans : [CBSE 2013] perfectly accurate on the reproduction process?
To receive and nurture the growing embryo, lining of Ans : [All India 2008]
uterus become thick and spongy.
Leads to variation/ evolution.
21. Regeneration is not possible in all types of animals.
Why? TWO MARKS QUESTIONS
Ans : [CBSE 2012]
Regeneration is carried by specialised cells. The
31. State the changes that take place in the uterus when
organisms which have those cells only can show
a. implantation of embryo has occurred
regeneration.
b. female gamete/egg is not fertilized
22. What is the advantage of reproducing through spores? Ans : [Delhi 2017]
Ans : [CBSE 2012] a. Uterus wall becomes thicker due to development
In the form of cyst, spore with a cell wall can survive of blood vessels and glands in it and placenta
in adverse conditions. develops from the side of foetus so that it can
derive nutrition from mother and pass the waste
They can be easily dispersed through wind as to mother’s blood.
they are more in number and light in weight. b. Uterus lining gets peeled and shed off along with
23. What happens if egg is not fertilized? mucus, blood, dead ovum during menstruation.
Ans : [CBSE 2012] 32. Give reasons as to why the following processes are
If fertilization does not occur then menstruation different from each other:
occurs, i.e., blood and mucus comes out through the a. Fission in Amoeba and Plasmodium .
vagina. b. Binary fission and Fragmentation.
Ans : [CBSE 2016]
24. Differentiate between pollen grain and ovule.
a. In Amoeba during binary fission the cell divides
Ans : [CBSE 2011]
into two daughter cells while in Plasmodium
Pollen grains contain male gametes and ovules multiple fission occurs, where the cell divides into
contains female gametes in plants. many daughter cells.
b. In binary fission, a cell divides into two daughter
25. Differentiate between germination and fertilization, cells while in fragmentation, the body of a
Ans : [CBSE 2011 ] multicellular organisms divides into two or more
parts which grow further. a. Each piece grows into a complete organism.
b. Develops into new plants.
33. a. What is the location of the following: c. Changes occurs in the appearance at the time of
(i) DNA in a cell (ii) Gene puberty.
b. Expand DNA.
Ans : [CBSE 2016] 38. What does the diagram given below correctly
illustrate? Give reason in support of your answer.
a. (i) Nucleus. (ii) Located on the chromosomes.
b. Deoxyribo Nucleic Acid.
a. Reproduction seen in organisms by formation of a. DNA copying is essential for formation of addition
spores. cellular apparatus, so that when DNA copies
b. Organisms are cut into any number of pieces and separate, each cell gets its own cellular apparatus.
each piece grows into a complete organism. b. The process of DNA copying results in variation
c. Unicellular organisms divide into many daughter each time. As a result, the DNA copies generated
cells simultaneously. will be similar, but may not be identical to the
original.
37. What happens when the following situations are
initiated: 42. “The consistency of DNA copying during reproduction
a. A Planaria is cut into three different pieces. is important for the maintenance of body design
b. Leaf of the Bryophyllum with notches falls on the features.” Support this statement with two arguments.
soil. Ans : [CBSE 2014]
c. Testosterone is released in the male reproductive
system. 43. Why is vegetative propagation practised for growing
Ans : [CBSE 2015]
some types of plants? [Delhi 2012] a. Formation of sperms takes place in testes.
or b. Prostate gland contributes fluid to the semen.
Why is vegetative propagation practiced for growing
some types of plant? List two plants which are grown 50. Why do we need to adopt contraceptive measures?
by this method. Ans : [CBSE 2012, 13]
Ans : [All India 2013] a. Contraceptive measures are needed to be adopted
Advantages of vegetative propagation: to prevent unwanted pregnancies.
a. The plants bear flowers and fruits earlier than b. To prevent sexually transmitted diseases.
those propagated sexually. c. Spacing between children.
b. Plants have lost capacity to form seeds hence d. For sound health of a mother.
they are propagated vegetatively. Such plants are
51. Give two differences between a male and a female
genetically similar to parent plants and have all
gamete.
their characters.
Ans : [CBSE 2012]
44. Define variation in relation to a species. Why is a. Male gamete is smaller in size or compared to the
variation beneficial to the species? female gamete.
Ans : [CBSE 2013] b. Male gamete is motile whereas female gamete is
Variation means certain changes which occur in non-motile.
sexually reproducing organisms because of errors in
52. What kind of contraceptive methods prevents STDs
DNA copying. Variations are beneficial for species
and how?
because they given survival advantage even in the
adverse environmental conditions. Ans : [CBSE 2012]
Barrier method prevent STDs.
45. State the importance of chromosomal difference By this method there is no direct contact of genital
between sperms and eggs of humans. organs of male and female and thus it prevents
Ans : [CBSE 2013] transmission of any infection.
Eggs always contain same type of sex chromosomes
53. List any two reasons why the Government has banned
(both X). Sperms contain X or Y sex chromosomes.
prenatal sex determination by law.
Thus, sperm containing X chromosome when combines
with X chromosome of egg results in a female child. Ans : [CBSE 2012]
Whereas sperm containing Y chromosome when a. People may get female foetus aborted.
combines with X chromosome of egg results in a male b. Reckless female foeticide has disturbed male-
child. female ratio in society.
46. a. List any two methods of asexual reproduction. 54. Mention any four ways of asexual reproduction.
b. Explain how Spirogyra reproduces. Ans : [CBSE 2012]
Ans : [CBSE 2013]
a. Fission
a. (i) Budding in Hydra and Yeast. b. Budding
(ii) Spore formation in Fungi. c. Spore formation
b. Spirogyra breaks up into smaller pieces upon d. Fragmentation
maturation. These fragments grow into new e. Regenerations
individuals
55. Mention the functions of (a) placenta (b) fallopian
47. How can pregnancy be prevented surgically? tube in the human female , reproductive system.
Ans : Ans : [CBSE 2012]
Pregnancy can be prevented surgically by adopting: a. Placenta:
a. Vasectomy: When vas deferens in males are blocked (i) Helps in transporting glucose and oxygen
surgically, sperm transfer will be prevented. from the mother to the embryo.
b. Tubectomy: When fallopian tubes are blocked, (ii) Waste generated by the embryo is removed by
eggs will not be able to reach the uterus. transferring it to the mother’s blood.
b. Fallopian tube:
48. ‘Regeneration is not reproduction’. Justify this (i) Helps in carrying the egg from the ovary to
statement with reason. the uterus.
Ans : [CBSE 2013,14] (ii) Fertilization occurs here.
When a piece is cut from an organism, it grows into
56. List any four modes of asexual reproduction.
complete organisms. Regeneration is carried out by
specialized cells. It is not reproduction since most Ans : [All India 2011]
organisms would not be able to grow through pieces. a. Four modes of asexual reproduction:
b. Fission
49. State one function each performed by the following c. Budding
organs in human beings: (a) Testes (b) Prostate gland d. Spore formation
Ans : [CBSE 2013] e. Fragmentation
f. Regenerations c. ovule
d. sepals and petals
57. Give one example each of a unisexual and bisexual
Ans : [CBSE 2011]
flower. [All India 2011]
or a. forms zygote
Differentiate between unisexual and bisexual flower. b. forms fruit
or c. forms seed
Distinguish between unisexual and bisexual flowers d. shrinks and fall off
giving one example of each.
62. What is the function of copper-T used by some
Ans : [All India 2014-15] women? What is its effect?
Unisexual flower have only one type of sex organ, Ans : [CBSE 2011 ]
either carpels or stamen, hence they are either male
Copper-T prevents pregnancy as it prevents
or female flower. For example: Cucurbit and maize.
implantation in the uterus. It can cause side effect
Bisexual flower have both carpels and stamens. For
due to irritation of the uterus.
example: Marigold and rose.
63. Leaves of Bryophyllum fallen on the ground produce
58. List any two differences between pollination and
new plants. Why?
fertilization.
Ans : [CBSE 2011]
Ans : [CBSE 2011]
Leaves of Bryophyllum bears adventi¬tious buds/
Pollination Fertilization plantlets in the notches along the leaf margin. When
1. It is the transfer of It is the fusion of male the buds fall on the soil they develop into new plant
pollen grain from gamete with female under favourable condi-tions.
the anther to the gamete (egg).
64. Differentiate between self-pollination and cross-
stigma of flower.
pollination.
2. It is achieved by It is achieved by the Ans : [CBSE 2011]
agents like wind, growth of pollen tube
water or animals. so that the male Self-pollination Cross-pollination
gamete reaches the
1. Self-pollination is Cross-pollination is
female germ cells.
the transfer of pollen the transfer of pollen
3. It leads to It leads to formation of grains from anther grains from anther
fertilization. seeds to stigma within the to stigma in another
4. It is an external It is an internal same flower. flower.
process process. 2. It occurs either in It occurs between
the same flower or two flowers which are
59. Differentiate between plumule and radicle. another flower of the on different plants
Ans : [CBSE 2011] same plant. but are of the same
species.
Plumule Radicle
3. It occurs in the It occurs between
1. The part of growing The part of growing flowers which are flowers which are
embryo which later embryo which later form genetically same. genetically different.
forms the shoot of the root of young plant.
young plant. 65. Label any four parts.
2. It is positively It is positively
phototrophic geotrophic and
and negatively negatively phototrophic.
geotrophic.
71. What is vegetative propagation? List two advantages 74. Mention the total number of chromosome along
and two disadvantages of vegetative propagation. with sex chromosome. Explain how in a sexually
reproducing organism chromosome number of parents
Ans : [All India 2017]
and their offsprings is the same.
Method of producing new plants from vegetative Ans : [Delhi 2017]
parts like roots, stem and leaves is called vegetative
propagation. Total number chromosomes is 23 pairs. The last pair
Advantages are: is called sex chromosome. If they are similar, they are
a. The plants bear flowers and fruits earlier than termed as XX chromosome. They are present in the
those propagated sexually. females. If they are dissimilar, they are called XY.
b. Plants have lost capacity to form seeds hence they They are present in the males. DNA doubling is always
are propagated vegetatively. followed by cell division. But multicellular organisms
Disadvantages are: have special linkages of cells in specialised organs
a. Such plants are genetically similar to parent plants which have only half the number of chromosomes and
and are vulnerable to infections and diseases. half the amount of DNA. Thus, when these germ-
b. They do not have variations therefore do not cells from two individuals combine during sexual
adapt well to changing environment, the plant reproduction to form a new individual, it results in
species does not evolve. re-establishment of number of chromosome and DNA
content.
72. List three techniques to prevent pregnancy. Which of
them is not meant for males? How does the use of such 75. State the basic requirement for sexual reproduction.
techniques have an impact on health and prosperity of Write the importance of such reproduction in nature.
a family? [All India 2017] Ans : [Delhi 2017]
or Sexual reproduction takes place in multicellular
List any four methods of contraception used by organisms with complex body design. There are
humans. How does their use have a direct effect on specialized (sex) organs in which through a special
the health and prosperity of a family? type of cell division, number of chromosome is reduced
Ans : [Delhi 2015, All India 2014] to half and male and female germ cells/gametes form.
Three techniques to prevent pregnancy: These gamete fuse to form zygote on fertilization,
a. Mechanical barrier — male or female. thus the characteristic number of chromosome and the
b. Taking oral pills/i-pill/saheli - changing the normal DNA content for a cell is regained.
hormonal balance of the body so that eggs are Sexual reproduction gives rise to more variations
not released. which are essential for evolution as well as survival
c. Use of the loop or the Copper-T. of species under unfavorable conditions. Species
d. Surgical method - tubectomy / vasectomy reproducing sexually have better chances of survival.
Use of hormonal preparations is not meant for
males. 76. What happens when:
Effect on Health and Prosperity: a. Accidentally Planaria is cut into three different
a. Health of women is maintained pieces.
b. Parents can give more attention to children b. Bryophyllum leaf fall on the wet soil.
c. More resources can be made available. c. On maturation sporangia of Rhizopus burst.
Ans : [Delhi 2017]
73. Reproduction is one of the most important
characteristics of the living beings. Give three reasons a. Three new Planaria will form due to regeneration.
in support of your answer. [All India 2017] b. New plantlets will form from these buds helping
or the plant to propagate vegetatively.
c. Spores are released which upon finding suitable flower by agents like wind, water or animals.
substratum germinates to form new individual. c. Style is the middle elongated part of the carpel.
It acts as a passage for pollen to reach ovary for
77. List four steps in sexual reproduction. Write two of the fertilization. Filaments is the elongated part
its advantages. of stamen.
Ans : [Delhi 2017]
81. a. Trace the path of sperms from where they are
a. Four steps in sexual reproduction :
produced in human body to the exterior.
b. Formation of gametes in the sex organs.
b. Write the functions of secretions of prostate gland
c. Transfer of male gamete to female gamete which
and seminal vesicles in humans.
involves release of both types of gametes in the
medium outside. Ans : [CBSE 2016]
d. Fusion of gametes, either inside or outside the a. The formation of sperms takes place in testes and
female parents body. delivered through the vas deferens which unites
e. Development of zygote to embryo and then with a tube coming from urinary bladder to form
complete individual. urethra from where they are excreted out of the
Advantages: body.
a. Variations are produced among the progeny. b. Prostate gland and seminal vesicles add their
b. Such populations are able to adapt well to secretions to make the sperms motile in a fluid
changing environment and thus evolves faster. which makes their transport easier and provides
nutrition.
78. Write one main difference between asexual and sexual
mode of reproduction. Which species is likely to 82. Give two examples each of the following:
have comparatively better chances of survival - the a. Plants having unisexual flowers
one reproducing asexually or the one reproducing b. Agents of pollination
sexually? Give reason to justify your answer. c. Physical changes on puberty that are common to
Ans : [CBSE 2017] both boys and girls.
Ans : [CBSE 2016]
Sexual reproduction Asexual reproduction
a. Papaya, watermelon
1. It involves two parents It involves only one b. Insects, air, water, etc.
and causes genetic parent and does c. (i) Appearance of pubic hair.
variation. not causes genetic (ii) Skin becomes oily and may develop pimples.
variation.
83. Why are the testes located outside the abdominal
2. Fertilization/zygote No fertilization/zygote
cavity? Mention the endocrine and exocrine function
formation is observed. formation is observed.
of testes.
The species having sexual mode of reproduction Ans : [CBSE 2016]
have better chances of survival because sexual
reproduction leads to variations which give better Sperm formation requires a lower temperature than
survival advantage to the species over time. the normal body temperature. This temperature is
1-3°C lower than the temperature of the body. Testes
79. Explain the term “Regeneration” as used in relation are thus located outside so that scrotum provides an
to reproduction of organisms. Describe briefly how optimal temperature for the formation of the sperms.
regeneration is carried out in multicellular organisms Endocrine function:
like Hydra. Production of male hormone (testosterone).
Ans : [All India 2016] Exocrine function:
Production of male gametes (sperms).
The ability to give rise to new individuals from
the body parts of the parent individual is called 84. List six specific characteristics of sexual reproduction.
regeneration, e.g., Hydra and Planaria, if their bodies Ans : [All India 2015, CBSE 2016]
get broken into many pieces, each piece is capable of
re-growing into a complete individual. Characteristics of sexual reproduction:
a. Two parents are involved.
80. Compare the following: b. Two dissimilar gametes are formed by meiosis.
a. Unisexual and bisexual flower. c. Variations are produced.
b. Self-pollination and cross pollination. d. Occurs in all the higher and some of the lower
c. Style and filament. organisms.
Ans : [All India 2016-17] e. Fertilization / fusion of gametes leading to zygote
formation.
a. Unisexual flowers have either stamens or carpels,
e.g., Papaya and Watermelon. Bisexual Flowers 85. List four points of significance of reproductive health in
have both stamens and carpels, e.g., Mustard and a society. Name any two areas related to reproductive
Hibiscus. health which have improved over the past 50 years in
b. Self-Pollination is transfer of pollen grains from our country.
the stamen to the stigma of same flower. Cross Ans : [All India 2015, CBSE 2016]
Pollination is transfer of pollen grains to another
Significance: a. Barrier method (Condoms)
a. Prevent STDs. b. Surgical method (Vasectomy in males and
b. Advantage of small family. Tubectomy in females)
c. Less mortality among new-borns. c. Withdrawal method
d. Reduces the cases of maternal mortality. d. Calendar method
Areas which have improved: e. Hormonal method
a. Family Planning. f. IUCD/Copper-T/Loop (any four)
b. Decrease in STD cases. Two advantages:
a. Helps in maintaining health of women.
86. What is placenta? Explain its function in human b. Helps in preventing STDs especially AIDS.
female. [Foreign 2015, All India 2014] c. Helps in birth control.
or
State the role of placenta in the development of
embryo. [All India 2013]
or
What is placenta? Describe its structure. State its
functions in case of a pregnant human female.
Ans : [All India 2016]
Placenta is a specialized tissue embedded in the
uterine wall. It contains villi on the embryo’s side and
blood spaces on the mother’s side.
Function:
a. Helps in passing of nutrients from mother to
foetus.
b. Exchange of oxygen and carbon dioxide gases.
c. Passing of waste materials from embryo to the
mother. 90. List any two modes of asexual reproduction. Under
which mode of reproduction is vegetative propagation
87. Write one main difference between asexual and sexual placed and why? List two advantages of vegetative
mode of reproduction. Which species is likely to propagation.
have comparatively better chances of survival- the Ans : [All India 2014]
one reproducing sexually or the one reproducing
asexually? Justify your answer. Two modes of asexual reproduction are fission
[Foreign 2015, All India 2018] Regeneration
or Vegetative propagation is placed under asexual
How is sexual reproduction better than asexual reproduction as reproduction happens from any part
reproduction? of a plant. It may be either leaf, shoot or root.
Ans : [All India 2013] Advantages are:
a. Asexual reproduction does not involve genetic a. The plants bear flowers and fruits earlier than
fusion while sexual reproduction involves fusion of those propagated sexually.
male and female gametes to form a zygote. b. Plants have lost capacity to form seeds hence they
b. Species reproducing sexually have better chances are propagated vegetatively.
of survival. 91. “Regeneration is not same as reproduction”.
Reason : a. Justify the statement.
Sexual reproduction gives rise to more variations b. What is meant by regeneration?
which are essential for evolution as well as survival c. How is this process different from
of species under unfavorable conditions. fragmentation?
88. What are chromosomes? Explain how in sexually Ans : [All India 2015]
reproducing organisms, the number of chromosomes a. Regeneration is not the same as reproduction,
in the progeny is maintained? since most organisms would not normally depend
Ans : [CBSE 2015] on being cut up to be able to reproduce.
Chromosomes are thread like structures made-up of b. The ability to give rise to new individuals from
DNA found in the nucleus. The original number of the body parts of the parent individual is called
chromosomes becomes half during gamete formation. regeneration.
Hence, when the gametes combine, the original c. In fragmentation, the body of a simple multicellular
number of chromosome gets restored in the progeny. organism breaks down onto many ‘fragments’. All
cells undergo division and the organism develops
89. List four categories of contraceptive methods. State from each fragment. Regeneration occurs only
in brief two advantages of adopting such preventive through some specialised cells.
methods.
92. Explain the process of regeneration in Planaria. How
Ans : [CBSE 2015] is this process different from reproduction?
Four categories of contraceptive methods are: Ans : [All India 2014, CBSE 2008]
Regeneration is the ability to give rise to new a. Binary fission.
individuals from the body parts of the parent b. Amoeba.
individual e.g., Hydra and Planaria, if their bodies c. Binary fission occurs in unicellular organisms
get broken into many pieces, each piece is capable of only. In fragmentation the body of a simple
re-growing into a complete individual. multicellular organism breaks down into many
‘fragments’. All cells undergo division and the
organism develops from each fragment.
a. Identify the process. 97. Give the functions of the following in the process of
b. Which organism uses the above method of reproduction:
reproduction? a. Pollen tube.
c. How is the above method different from the b. ovary,
process of fragmentation? [All India 2014-15] c. Stigma.
or Ans : [All India 2015]
In context of reproduction of species, state the main
difference between fission and fragmentation. Also a. Pollen tube carries male gamete from stigma to
give one example of each. ovule.
b. Ovary has ovule and forms fruit to protect and
Ans : [All India 2016]
dispersal of seeds.
c. Stigma receives pollen during pollination. formation of zygote is known as fertilization.
The growth of embryo (present in the seed)
98. Justify the following statements: into seedling under appropriate conditions is
a. Variation is beneficial for the species over a period known as germination.
of time.
b. New offsprings produced are similar to their 102. A part of the male reproductive system is shown
parents but not identical. below. Study the diagram and answer the questions
c. Binary fission is different in Amoeba and that follow.
Leishmania.
Ans : [All India 2014-15]
a. Variations help a population in the process of
natural selection and accumulation of adaptations
in a population. It leads to evolution of a species.
b. Offspring, especially when produced sexually, have
minor differences or variations among themselves
hence they may not look identical. By virtue of
them being from same species they look similar.
c. Binary fission in Amoeba is in any plane but in
Leishmania it is in a fixed plane.
flower.
Ans : [All India 2010, 2015]
a.
(i) Ovary
(ii) Oviduct or fallopian tube
(iii) Uterus or uterus wall
b. (i) It becomes thicker due to development of
blood vessels and glands in it.
(ii) It gets peeled and shed off along with mucus,
blood, dead ovum during menstruation