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Group - 17

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FIITJEE CPP - Group – 17

Single Options Correct:-

1. The iodine is violet because


(A) it absorbs violet color of the visible region and electron excites from highest filled molecular orbital to the lowest
unoccupied molecular orbital
(B) it absorbs yellow & green color of the visible region and electron excites from highest filled molecular orbital to
the lowest unoccupied molecular orbital
(C) it is due to crystal defect of solid iodine.
(D) it is due to poor bonding in iodine molecule

2. On addition of Cl2 in KI(aq) solution gives a violet colour but excess of Cl2 turns it colourless due to the formation of
(A) HI & HCl (B) HIO & HCl (C) HIO3 & HCl (D) HIO4 + HCl

3. Which of the following is CORRECT


(A) 2NaCl + 2H2SO 4 → Na2SO 4 + SO2 + 2H2O + Cl2
( conc.)
(B) 2NaBr + H2SO4 → Na2SO4 + 2HBr
( conc.)
(C) I2 + 2KCl → 2KI + Cl2
(D) Cl2O6 + 2NaOH → NaClO4 + NaClO3 + H2O

4. Liquid iodine (I2) conducts very slightly due to the formation of ions ‘A’ & ‘B’. The hybridization of the central atom of
A & B are
3 3 3 3 3 3
(A) sp & sp d (B) sp d & sp d (C) sp & sp (D) no hybridization
.
5. F2 is called super halogen because it differs from other halogens in many properties. Which of the following is same
for all halogens (X2)
(A) X2 + 2H2O → 4HX + O2 (B) 2X2 + 2NaOH → OX2 + 2NaX + H2 O
(C) X2 + 3H2O → 6HX + O3 (D) all X2 are coloured

6. Which of the following statement is INCORRECT about oxides of halogens?


(A) in vapour state ClO3 is paramagnetic but in liquid state it is diamagnetic
(B) in Cl2O7 all Cl – O bond lengths are equal
(C) structures of ClO2 & H2O are same
(D) OF2 is a powerful oxidizing agent

7. Which of the following statement is TRUE


(A) the order of stability of hypohalites is LiOCl > NaOCl > KOCl
(B) order of acidic strength HOCl < HOBr < HOI
-
(C) XO are stable in basic solution
(D) 4KClO3 →
at low temperature
3KClO4 + KCl

8. In which case the oxidation number of chlorine in product is +5


(A) Na2 O2 + ClO2 →

(B) NaClO2  →
(C) Ba ( ClO2 )2 + H2SO4 →
(D) CaOCl2 + CO2 + H2O →

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FIITJEE
9. Which of the following statement is WRONG for interhalogen compounds/ions?
(A) The thermal stability of IF, BrF & ClF is IF > BrF > ClF
(B) On hydrolysis of IF7, BrF5 and IF7 the products formed are
IF5 + 3H2O → 5HF + HIO3
BrF5 + 3H2O → 5HF + HBrO3
IF7 + 6H2 O → 7HF + H5IO6
(C) KClO3 + I2 → KIO3 + ICl
(D) ICl−4 has distorted tetrahedral shape.

10. Which of the following set has halogenoids only


(A) ( CN)2 , Cl2 , HCN (B) ( CN)2 , ( SCN)2 , HN3
(C) ( CN)2 , ( SCN)2 , ( SeCN)2 , ( SCSN3 )2 , ( OCN)2 (D) CN, OCN, SCN, N3−

One Or More Than One Options Correct:-

11. The halogen acids that can’t be prepared by using simple displacement reaction of sodium halide and concentrated
sulfuric acid
(A) HF (B) HCl (C) HBr (D) HI

12. For the formation of nitrogen trihalide excess of halogens are used with liquid or gaseous state of ammonia. The
liquid phase of ammonia is not essential for
(A) Cl2 (B) I2 (C) Br2 (D) F2

13. For the hydrolysis of ICl the possible products is/are


(A) Cl− (B) OCl− (C) IO3− (D) OI−

14. Which interhalogen compound does not exist?


(A) IF2Cl (B) ICl7 (C) IF (D) ClBr3

15. Which of the following is (are) ionic


(A) I4O9 (B) KI3 (C) ClO3 (D) OF2

16. Among the tetrahalide which is (are) not exist(s).


(A) SnI4 (B) PbI4 (C) PbCl4 (D) GeF4

17. The salt formed by the action of NaOH (concentrated) on Cl2O6 is/are
(A) NaOCl (B) NaOCl2 (C) NaOCl3 (D) NaOCl4

18. The statement regarding oxy acids of halogen is/are true


(A) the stability of oxy acid anions are due to dπ - pπ bond between halogen and oxygen
(B) HOCl, HOBr and HClO2 only exists in aqueous solution
(C) HClO3 and HIO3 exists in solid state
(D) The order of oxidizing power HClO4 > HClO3 > HClO2 > HOCl

Matrix Match Type:-

19. Match the following:

Column – I Column – II
Na2 SO3 + H2 O + Cl2 → One element of the product has two different
(A) (p)
oxidation number in products
(B) MnO2 + HBr → (q) One product is halogen
(C) CuSO4 + KI → (r) One product is halogen acid
(D) HgO + Br2 → (s) Reaction is disproportionation

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FIITJEE
20. Match the following:

Column – I Column – II
(A) F2 (p) Oxidizes by O3 as well as HNO3
(B) Cl2 (q) Physical state is liquid
In moist state it has strongest & fastest bleaching
(C) Br2 (r)
action among halogens.
(D) I2 (s) Strongest oxidizing power

21. Match the following:

Column – I Column – II
(A) HF (p) Strongest reducing agent
Its presence can be confirmed by chloroform layer
(B) HCl (q)
test
(C) HBr (r) Lowest melting point
(D) HI (s) Gives white precipitate with calcium chloride

22. Match the following:

Column – I Column – II
(A) AgClO3 + Cl2 → products (p) One product is Cl2O7
(B) K 2 Cr2 O7 + HCl → products (q) One product is ClO2
(C) HClO4 + P2O5 → products (r) One product is CrO2Cl2
(D) BaCl2 + K 2Cr2O7 + H2SO4 → products (s) One product is CrCl3

Integer Type:-

23. NaBr + NaBrO3 + H2SO4 →


The half of the sum of the stoichiometry coefficients of all the reactants and products in balanced reaction is ……..

24. How many of the following interhalogen compounds are less reactive than BrF3;
ClF3, IF, IF7, IF5, IF3

25. CuSO 4 + KCN  →


o
60 C

The number of different products formed in the above reaction.

26. In molten state ICl3 shows electrical conductivity due to the presence of ions. The sum of the oxidation number of
iodine atoms having different oxidation number in ions is …..

27. The n-factor of Cl2 on reaction with dil and cold NaOH is …

28. On reaction of iodine (I2) with conc. HNO3, O3 (aq), Cl2 (aq), KClO3, KBrO3, Na2S2O3 separately. The number of
different products having +5 oxidation number of the iodine is (are) …

29. On reaction of AgNO3 & Pb(NO3)2, with HCl & HI separately, the number of coloured metal halides formed is (are)
....

30. On long standing bleaching powder undergoes auto-oxidation. The sum of the oxidation numbers of chlorine atoms
in the products is …..

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FIITJEE
Chemistry
Group – 17

1. B 2. C 3. D 4. A 5. D 6. B 7. A

8. B 9. D 10. C 11. CD 12. ACD 13. ACD 14. BD

15. AB 16. B 17. CD 18. AB

19. A – r; B – p,q; C – p,q; D – p,s 20. A – s; B – r; C – q; D – p

21. A – s; B – r; C – q; D – p,q 22. A – q; B – s; C – p; D – r

23. 9 24 3 25. 3 26. 4 27. 1 28. 2 29. 2

30. 4

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FIITJEE Hint & Solution

Chemistry

1. Iodine absorbs yellow and green radiations and the color of iodine due to transmitted light is violet

2. Cl2 is stronger oxidizing agent than I2


Cl2 + KI ( aq) → 2KCl + I2
( violet color )
& if excess of Cl2 is passed through solution then Cl2 oxidizes the I2 evolved
5Cl2 + I2 + 6H2 O → 10HCl+ 2HIO3
( excess) colourless
( iodic acid)
colourless

3. Cl2O6 + 2NaOH → NaClO4 + NaClO3 + H2O


While (A) is wrong because the HCl can’t reduce H2SO4 into SO2 & (B) is wrong because the product HBr
reduces the conc.H2SO4 into SO2 & (C) is wrong because Cl2 is more reactive than Br2

4. Self-ionization of iodine
3I2 ⇌ I3+ + I3−
( sp ) ( sp d)
3 3

5. all halogens are colored


F2 → pale yellow
Cl2 → greenish yellow
Br2 → reddish brown
I2 → violet

6. (A) ClO3 has one dimerises in liquid state and becomes diamagnetic
(B) Structure of Cl2O7
o
1.72 A
O
o O O
1.42 A
O Cl Cl
O
O O

(D) OF2 is a powerful oxidizing agent

7. (A) NaOCl is less stable than LiOCl while KOCl is known only in solution
(B) order of acidic strength HOCl > HOBr > HOI
(C) 3XO− → XO3− + 2X − (in basic medium)
(D) 6KClO3 →
at low temperature
2KCl + 3O2
4KClO3 
at high temperature
→ 3KClO4 + KCl

8. (A) Na2 O2 + 2ClO2 → 2NaClO2 + O2



(B) 3NaClO2  → 2NaClO3 + NaCl
(C) Ba ( ClO2 )2 + H2 SO4 → BaSO4 + 2HClO2
(D) CaOCl2 + CO2 + H2 O → CaCO3 + H2O + Cl2

9. (A) is correct because the thermal stability of AB type halogen compounds decreases with the decrease in
electronegativity difference of A & B.
(B) all reactions are correct because binary interhalogen compounds on reaction with water give halogen acid &
oxy halogen acid of larger halogen atom.
(C) KClO3 + I2 → KIO3 + ICl
(D) in ICl−4 , I is sp d hybridized and square planar.
3 2

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FIITJEE
10. ( CN)2 cyanogen
( SCN)2 thiocyanogen
( SeCN)2 selenocyanogen
( SCSN3 )2 Azido carbon disulphide
( OCN)2 oxycyanogen
All are pseudohalogens (halogenoids)

11. Due to reducing nature of HBr and HI and oxidizing property of concentrated H2SO4.

12. As NI3 is extremely explosive in nature.

13. oxyhalides are formed from the larger halogens

14. (B) ICl7 due to large size of chlorine it does not exist
(D) ClBr3 chlorine is more electronegative than bromine so can’t be central atom.

15. (A) I4O9 ≡ I(IO3)3


(B) KI3
4+ - 2+
16. Pb oxidizes the large size I ion and itself reduces into Pb .

17. Cl2O6 + 2NaOH → NaClO3 + NaClO4 + H2O

18. (A) is true as fluorine has no vacant d-orbital so oxy acid of fluorine is not possible
(C) HClO3 exists only in aq. while HIO3 in solid state
(D) wrong

19. (A) Na2 SO3 + H2 O + Cl2 → Na2 SO4 + 2HCl


(B) MnO2 + 4HBr → MnBr2 + Br2 + 2H2 O
(C) 2CuSO4 + 4KI → Cu2I2 + I2 + 2K 2 SO4
(D) HgO + 2Br2 → Br2 O + HgBr2

20. (A) F2 is the strongest oxidizing agent.


(B) F2 & I2 has no bleaching action while moist bromine shows a slow bleaching action.
(C) F2, Cl2 are gases,
Br2 liquid,
I2 solid.

21. (A) 2HF + CaCl2 → CaF2 + 2HCl


( white ppt )

HF HCl HBr HI
(B)
m.p. −83 C −111 C −86 C 50.8 o C
o o o

- -
(C) Cl2 displaces the Br & I from the solution & makes the non-polar solvent layer brown and violet
respectively.

22. (A) 2AgClO3 + Cl2 → 2AgCl + 2ClO2 + O2


(B) K 2 Cr2 O 7 + 14HCl → 2KCl + 2CrCl3 + 7H2O + 3Cl2
(C) 2HClO4 + P2 O5 → Cl2O7 + 2HPO3
(D) 2BaCl2 + K 2 Cr2 O7 + 3H2SO4 → K 2SO 4 + 2CrO2Cl2 + 2BaSO4 + 3H2O

23. 5NaBr + NaBrO3 + 3H2 SO4 → 5HBr + HBrO3 + 3Na2 SO4

24. order of reactivity ClF3 > IF7 > BrF3 > IF5 > IF3 > IF

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FIITJEE
25. CuSO 4 + 4KCN → 2CuCN + ( CN)2 + K 2SO 4
  
three different products

26. 2ICl3 ⇌ ICl2+ + ICl4−

27. Cl2 + 2NaOH ( cold & dil ) → NaCl + NaOCl + H2O

28. I2 + 10HNO3 → 2HIO3 + 10NO2 + 4H2O


I2 + 5O3 + H2O → 2HIO3 + 5O2
I2 + 5Cl2 + 6H2O → 2HIO3 + 10HCl
2KClO3 + I2 → 2KIO3 + Cl2
2KBrO3 + I2 → 2KIO3 + Br2
2Na2S2O3 + I2 → 2NaI + Na2 S4 O6
HIO3 and KIO3 have +5 oxidation number of iodine

29. AgNO3 + HCl → AgCl+ HNO3


( white )
Pb (NO3 )2 + 2HCl → PbCl2 + 2HNO3
( white )
AgNO3 + HI → AgI + CH3 COOH
(Pale yellow )
Pb (NO3 )2 + HI → PbI2 + 2CH3 COOH
( yellow )

30. 6CaOCl2 → 5CaCl2 + Ca ( ClO3 )2

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