API 570 Exam Questions Dated 5/7/2018

1. Temporary piping repairs may remain for an indefinite period of time if they are
approved and documented by the:
A) Authorized Piping Inspector
B) Manager of Maintenance
C) Operations Manager
D) Piping Engineer

Answer: D … API 570, Para. 8.1.4.1, last sentence in Paragraph, API 570 Pg 52!

2. Which of the following is NOT a required marking on an ASME B16.5 flange or

flanged fitting?

A) Temperature range B) Pressure class rating

C) Material specification D) Manufacturer’s name or marking

Answer: A … ASME B16.5, Para. 4.2.1, 4.2.2.a/b/c, 4.2.3, and 4.2.5 = Not Req’d

3. When the MAWP is recalculated for the continued use of a piping system, the
wall thickness to be used is the:

A) Actual thickness
B) Actual thickness minus the estimated corrosion loss before the next inspection
C) Actual thickness minus the discovered corrosion loss since the previous inspection
D) Actual thickness minus 2 times the estimated corrosion loss before a next inspection

Answer: D … API 570, Para. 7.2 … MAWP calculation rules for t  See Table 4

4. TML readings on a piping system indicate that a corrosion rate has increased.
The Inspector’s most appropriate response is to:

A) Recalculate the inspection interval of the system

B) Recalculate the piping circuit average corrosion rate
C) Schedule the next inspection within six months (very soon)
D) Report this change in condition to the Maintenance Supervisor
Answer: A … API 570, Para. 7.1.1, Last Para. LT & ST corrosion rates should be
compared to see which results in shortest RL as part of the data
assessment!‫واﺣده‬ ‫ﺻﯾﻐﮫ اﻟﺳؤال ﻣﺧﺗﻠﻔﮫ ﻟﻛن اﻻﺟﺎﺑﮫ‬
5. When prioritizing piping systems for PMI testing, which of these is the most
important?

A) Likelihood of material mix-up during construction

B) Cost of the PMI testing program
C) Accessibility of piping segments
D) Process unit downtime schedule

Answer: A … API 578, Sect. 4.3.3, Item a … a/b/c/d  Highlight API 578 section

‫ﺻﯾﻐﮫ اﻟﺳؤال ﻣﺧﺗﻠﻔﮫ ﻟﻛن اﻻﺟﺎﺑﮫ واﺣده‬

6. A piping system installed in January 1993 (initial thickness 0.320 in.)
In January 2004, a thickness of 0.200 in. was recorded just prior to a change of servicein
the piping system as reported to the Corrosion Specialist by the Inspector, who was told
to expect a significant decrease in the corrosion rate. The next thickness in January 2009
measured 0.180 inches. What corrosion rate shall be used for this line and, given this
information, the Retirement thickness of 0.150 inches will be reached on:
A) Corrosion rate almost 9 MPY & retirement thickness will be reached by Jan 2012
B) Corrosion rate almost 9 MPY & retirement thickness will be reached by Jan 2013
C) Corrosion rate of 4 MPY & retirement thickness will be reached by July 2015
D) Corrosion rate of 4 MPY & retirement thickness will be reached by July 2016
Answer: D … API 570, Para. 7.1.1.1 (Last Para) &Corr Rate (ST & LT) & RL Calcs
Solution: The authorized inspector, in consultation with a corrosion specialist, shall select the
corrosion rate that best reflects the current process (last paragraph of Section 7.1.1) … In this
case, the ST corrosion rate should be selected which = 4 mils per year (7.5 years of RL exist)

LT = .32 - .18 = .14 lost in 16 yrs, so .14 (140 mils) ÷ 16 = .00875 (8.75 mils/year)
ST = .20 - .18 = .02 lost in 5 yrs, so .02 (20 mils) ÷ 5 = .004 (4.0 mils/year)
RL = .18 - .15 = .03 (30 mils remaining life) ÷ .004 (4.0 mils/year) = 7.5 years
January 2009 + 7.5 years = July 2016 = Answer D
7. To which of the following fluid services does API 570 specifically apply?
A) Category D fluid services as defined in ASME B31.3
B) Raw, intermediate, and finished petroleum products
C) Hydrocarbons and utility streams
D) Steam and steam condensate
Answer: B … API 570, Para. 1.2.1 & 1.2.1.a

8. An imperfection exceeding the acceptable criteria is known as a/an:

A) Flaw B) Defect
C) Discontinuity D) Indication

Answer: B … API 570, Para. 3.1.17  Definition of Defect

‫ﺻﯾﻐﮫ اﻟﺳؤال ﻣﺧﺗﻠﻔﮫ ﻟﻛن اﻻﺟﺎﺑﮫ واﺣده‬

9. Which of the following best describes the term undercut?

A) An incomplete bonding between the parent metal and filler metal under the weld
B) A lack of fusion under the cap that appears as a “cut” on a radiographic image
C) A groove melted into the base metal adjacent to weld toe or weld root
D) Incomplete filling of the weld root

Answer: C … API 577, Definition of Undercut (QW-480 ASME IX Definitions also)

10. Under which of these circumstances must a welder requalify?

A) When a welder’s foreman discovers the welder is not making acceptable welds
B) When a welder has not welded with same P-No in the previous three months
C) When a welder has not worked as a welder for the previous two months
D) When a welder has not requalified within the past twelve months

Answer: D … API 577, Par. 8.2 (KNOW MAJOR RULES)& ASME IX, QW-322.1.a …
In this case, SIX-MONTH RULE APPLIES … A is arguably also correct because of
the REASON TO QUESTION HIS ABILITY RULE … But the reason MAY NOT be
his ability … It may be equipment or a variety of other reasons  D = Best answer
11. Measurements from inspection of Class 3 pipe reveal actual metal thickness
of 0.350 inches. Calculated minimum thickness is 0.250 inches. If the corrosion
rate is 0.0025 inches/year, the NEXT thickness measurement inspection is due in:

A) 3 years B) 5 years C) 10 years D) None of these

Answer: C … API 570, Para. 6.3.3 & Table 2 (Should state NO RBI … old
question)Solution: Use the Lesser of ½ RL or Table 2 Value for UT Class 3 (which
is 10 yrs) .350 - .250 = .100 mils RL ÷ 0.0025 loss/yr = 40 yrs RL = ½ RL = 20 years
Use 10

12. Insert flush patch repairs are:

A) Allowed for Class 1 & 2 piping systems if welds receive 100% RT or suitable UT
B) Allowed for Class 1 & 2 piping systems if welds receive MT or PT exams
C) Not allowed for Class 1 & 2 piping systems
D) Not allowed for Class 1 piping systems

Ans: A … API 570, Para. 8.1.4.2.b (KNOW 3 RULES or a/b/c on FLUSH PATCHES)

13. The PMI testing program within a warehouse:

A) Requires dismantling of valves to test individual parts
B) Requires testing a part of every alloy component received
C) Is a cost-effective alternative to PMI testing of fabricated piping systems
D) Should not be regarded as an alternative to PMI testing of fabricated piping systems

Answer: D … API 570, Para. 5.9  API 578, Sect. 4.4.2 (last sentence in 2 nd Para)
and you should know warehouse PMI on piping components ONLY supplements
Fabrication welding PMI on completed welds when welding composition = critical

14. When performing liquid penetrant examination of stainless-steel weld joints,

which of the following is correct when verifying acceptable penetrant materials?

A) Verify certifications of penetrant and developer materials for chlorine/fluorine content

B) Verify certifications of penetrant and developer materials for lead and contaminants
C) Check (verify) the material containers for proper identification and batch numbers
D) Check (verify) the material containers for an indication of the VOC content

Answer: A … API 570, Para. 5.7.2.b  ASME V, Art. 6, T-641 & rules in Mandatory
Appendix II in Part II-610/642/690 covering the rules for PT material certifications
15. Vertical supports constructed of pipe components should be checked to
determine if they are filled with water, because water inside a support may cause:

A) Internal corrosion of the support B) Internal corrosion of the process pipe

C) External corrosion of the support D) Additional stress to be placed on a support

Answer: A … API 570, Para. 5.5.4 (2nd Paragraph)  External Inspection Question

16. The recommended MAXIMUM inspection interval at an injection point for

thickness measurement for an injection point circuit is:

A) 3 years or ½ remaining life, whichever is less

B) 5 years or ½ remaining life, whichever is less
C) 10 years or ½ remaining life, whichever is less
D) None of these are correct because it is determined by piping classification

Answer: A … API 570, Section 6, Table 2  3 years rule

17. Which inspection method is most appropriate for detecting chloride stress
corrosion cracking in austenitic stainless-steel piping systems?

A) Longitudinal wave ultrasonics

B) Dry magnetic particle method
C) Liquid Penetrant
D) Radiography

Answer: C … API 571, Para. 4.5.1.7.b

18. If the corrosion rate for a piping system cannot be determined by similar
service, initial thickness measurements should be taken within:

A) 3 months B) 6 months
C) 9 months D) 1 year

Answer: A … API 570, Para 7.3.c  3-month rule to determine corrosion rate

19. On what basis are image quality indicators selected?

A) The strength of the radiation source

B) The film type used by the radiographer
C) The alloy content of the material being radiographed
D) The thickness of base material plus weld reinforcement

Answer: D … ASME V, Art T-276 (a) & (b) … IQI reinforcement rule (Table T-276)

20. Inspection of small-bore piping (SBP) that is part of a Class 2 secondary

process system is:

A) Optional
B) Outside the scope of API 570
C) Performed at the same intervals as for Class 2 primary process piping
D) Performed at the same intervals as for Class 3 primary process piping

Answer: C … API 570,

21. Evaluation of the record of the previous inspection reveals that thickness
readings and the resulting calculation were inaccurate. The corrosion rate to be
used for the next inspection period shall:

A) Be the short-term corrosion rate from the record

B) Be changed to agree with the actual corrosion rate found
C) Not be changed to actual rate found until rate is confirmed at the next inspection
D) Be the average of the short-term and long-term corrosion rates from the record

Answer: B … API 570 Section 7.4, 2nd Para

22. Which of these MAWP values is correct for a piping system NPS 10, ASTM
A106 Gr. B Seamless pipe, designed at 300°F, latest UT = 0.30 inches, observed
corrosion rate = 0.020 inches per year, and the next inspection is to be in 5 years?

A) 372 psig B) 744 psig

C) 396 psig D) None of these is correct

Answer: A … API 570, Table 4 = MAWP = 2SEt ÷ D, S = 20 KSI (B31.3 A-1 Tables),
E = 1.0 Seamless Pipe (A-1B Tables), D = 10.750 … Step # 1 … Solve t … .300 in.
minus twice the Estimated Corrosion Loss (ECL = .100) = .300 - .200 = .100 inches
Formula: 2 x 20,000 x .100 ÷ 10.75 = 40,000 x .100 ÷ 10.75 = 4,000 ÷ 10.75 = 372 psi
23. Threaded carbon steel piping in an NPS 1.5 piping system is being replaced.
What is the minimum pipe schedule to be used?

A) Schedule 20 B) Schedule 40

C) Schedule 80 D) Schedule 160

Answer: C … ASME B31.3, Table 314.2.1  Normal Fluid Service CS (Note 3*)

24. A piping system made of mixed grades of piping, including A-53 CS with
silicon killed elbows and fittings, has recently been rerated from 400°F (204°C) to
500°F (260°C). The process fluid contains 0.52% weight sulfur. Inspector should:
A) Continue monitoring the system using existing CMLS if they have never shown more
than .002 inch (.05 mm) per year corrosion rates

B) Not be concerned with the 100°F (55°C) change

C) Increase the number of CMLs on the system

D) Relocate the CMLs to the fittings

Ans: C … API 570 5.6.3 (More CMLs Note c) & 574, Par. 7.4.6.2.j /special note
Localized specific corrosion 450°F API 571, Para. 4.4.2.3.c (McConomy Curves
/Crit. Factors Sulfidation) Note: best is to increase the number of CMLs & focus
on non-silicon-killed (low silicon) piping because the silicon-killed fittings will last
longer than the non-silicone killed pipe!

‫ﺻﯾﻐﮫ اﻟﺳؤال ﻣﺧﺗﻠﻔﮫ ﻟﻛن اﻻﺟﺎﺑﮫ واﺣده‬

25. A buried piping system for 100 psig service is hydrostatically tested at 125
psig for 8 hours. After 4 hours, the pressure dropped 5 psig, and the system was
repressurized back to 125 psig. During the remaining 4 hours, the pressure drop
was noted again to be by 5 psig. According to API 570, the inspector should:
A) Accept the test as successful

B) Visually inspect the piping and find the leak

C) Repeat the test and conduct further inspection

D) Excavate the piping and conduct an external visual inspection

Answer: A … API 570, Par. 9.3.7 IF MORE THAN 5% DROP, D is then correct
26. The most extensively used NDE method for welds is:
A) Penetrant Testing B) Visual testing

C) Radiographic testing D) Magnetic Particle Testing

Answer: B … API 577, Par. 9.3.1, 1 st Sentence … easy … All welds must have VT

27. When cracking is suspected and an internal visual inspection reveals no

indications of cracks, which of these testing methods is NOT recommended by
API 574 as a spot check?
A) Penetrant Testing B) Visual testing

C) Radiographic testing D) Magnetic Particle Testing

Answer: C … API 574, Par. 10.3.2.2 … RT is unreliable for environmental cracking

‫ﺻﯾﻐﮫ اﻟﺳؤال ﻣﺧﺗﻠﻔﮫ ﻟﻛن اﻻﺟﺎﺑﮫ واﺣده‬

28. An inspection reveals that a repaired NPS 4 seamless pipe, A-53 Gr. B, has a
thickness of 0.180 inches. If the service is 1000 psig at 500°F, what is the actual
remaining corrosion allowance considering only internal pressure?
A) 0.043 inches B) 0.064 inches C) 0.070 inches D) 0.116 inches

Answer: B … Barlow calc, ASME B31.3 Table A-1 (S=19 ksi), Table A-1B (E = 1.0),
PD = 1,000 x 4.500 = 4,500 ÷ 38,000 (2SE=2x19000x1)=.118 … .180 - .118 = 0.062 in.

‫ﻣﮭﻣﺔ‬
29. For piping systems where service conditions have been changed, if data for
the same or similar service is not available, a corrosion rate is estimated from the
experience of the owner/operator or from:
A) Published data on piping systems in comparable service

B) The highest known corrosion rate in the unit

C) A default corrosion rate of 10 mils per year

D) Worst case industry data

Answer: A … API 570, Para. 7.1.2.b …

30. An NPS 12 carbon steel standard pipe in Class 2 service, designed to operate
at 450 psig and 500°F (260°C) with an allowable stress of 20 ksi, has a thickness
at inspection of 0.280 inches (7.1 mm). What is the maximum interval for the next
thickness measurement inspection (assume no RBI, E=1.0, Corr. rate = 25 MPY)?

A) 2.7 years B) 5 years

C) 5.5 years D) 10 years

Ans: A … 570 Par. 6.3.3  UT Thickness meas interval = Lesser of 10 yrs or ½ RL

t required = PD ÷ 2SE: 450 x 12.75 ÷ 2 (20,000) (1) = 5,738 ÷ 40,000 = 0.143 inches

RL = 0.280 in. (t actual) – 0.143 inches = 0.137 inches ÷ 0.025 (25 MPY) = 5.48 yrs

Use lesser of ½ RL (½ RL = 2.74 yrs) or Table 2 value 10 years (Class 2) = 2.7 yrs

31. short term corrosion rate and long term corrosion rate which one selected
‫اﻟﺳؤال ﺑﻧﻔس اﻟﺻﯾﻐﺔ ﺗﻘرﯾﺑﺎ واﻹﺟﺎﺑﺔ ﻓﻲ‬
API 570 Para. 7.1.2 last three lines.

32. Arc Blow causes by Magnetic forces,

33. WPS & PQR ask about No of Specimen for bend test & ACC or Rej as per
result.
34. The range of pressure gauge for sensitive leak test.
35. Question say that Welder use filler metal not listed in ASME List what is the
action.
What is the action 1-never 2- the inspector make waiver of wps
36.alloy 1.5Cr what is brinell hardness.
37. Question about preheat.
38. welding inspector duities befor,during & after.
39. CUI ‫ﻣﺣﺗﺎج ﻣذاﻛرة ﻛوﯾس و ﺗرﻛﯾز ﺗﻘرﯾﺑﺎ ﺳت أﺳﺋﻠﺔ‬
40. Question about Hot spot API 574 para 10.3.8.
41. Acceptance criteria of L.O.F.
42. Non metallic material API 570 apply on it ( FRP fiberglass reinforced plastic).
43. cosed exam nearly 8 questions about
Corrosion Rate & Trequired & MAWP & Remaining Life
44. Materials used in repairing or altering piping systems must be:

1. the original construction materials.

2. compatible with 7018 weld electrodes.
3. approved by the maintenance manager.
4. of known weldable quality.
45.