EMD II UNIT 3 Design of Single Phase Induction Motor
EMD II UNIT 3 Design of Single Phase Induction Motor
EMD II UNIT 3 Design of Single Phase Induction Motor
MOTORS
Introduction
The motors which work on single phase ac
supply are called single phase
induction motors.
Advantages
High starting torque
Very compact design if high running speeds are
used.
Disadvantage
Requires maintenance
and short life problems caused by the
commutator.
MOTORS 5
Series-connected
Rotor and Stator are
connected in series
Operates on either
ac or dc
MOTORS 6
ECE 441 7
The Commutator Bar and Brushes are a
switch that reverses the current in the
armature coil as it rotates
ECE 441 9
Flux
“Bunchin
g”
Force on conductor B
is upwards, rotation
is counter-clockwise
(CCW)
+Positive ECE 441 1
0
Flux
“Bunchin
g”
Force on Conductor B
is upwards, rotation
is counter-clockwise
-Negative Half-
Cycle- (CCW)
ECE 441 1
1
REPULSION
MOTORS
Repulsion motors are classified under
single phase motors. In magnetic
repulsion motors the stator windings are
connected directly to the ac power
supply and the rotor is connected to
commutator and brush assembly, very
similar to that of DC armature.
Repulsion Motor
REPULSION MOTORS
The direction of
alternating current is such
that it creates a north pole
at the top and a south pole
at the bottom. The
direction of induced emf is
given by Lenz's law,
according to which the
direction of induced emf
opposes the cause
producing it. The induced
emf induces current in the
Application of Repulsion
motors :
• high speed
lift
• fans &
pumps
Application of Repulsion
motors :
• Hoists
• Mining
Equipment
• Air
Compressors
Applications of Single Phase
IM
The main specifications for a single phase induction motor for design
purposes are:-
2. Rated Voltage V
3. Rated current A
5. Frequency HZ
6. Poles, P
8. Starting torque Nm
10.Power-factor %
I. One capacitor
t h e i n d u c t i o n m o t o r t o t h e m a c h i n e ’ s m a i n d e t e rm i n i n g
Kw=Winding Factor
f=Frequency
V=Rated voltage
P=Number of poles
D=stator bore diameter, m
τP=Pole Pitch
magnetic loading
V=4.44 K W f Tph
=Bav L ( D/p)
f= ns P/2
D π
2
KVA =4.44 KW ( ns P/2) (Bav L) ( )*10-3
h. × 0.746
=
X. . X .
2
Xö逷 7 − 9; ö XX ½ Xö逷 = ö × 90 = 0.2225
14
4
Xö逷 6 − 10; ö XX ½ Xö逷 = ö × 90 = 0.4339
14
6
Xö逷 (5 − 11); ö XX ½ Xö逷 = ö × 90 = 0.6235
14
8
Xö逷 (4 − 12); ö XX ½ Xö逷 = ö × 90 = 0.7818
14
10
Xö逷 (3 − 13); ö XX ½ Xö逷 = ö × 90 = 0.9009
14
12
Xö逷 (2 − 14); ö XX ½ Xö逷 = ö × 90 = 0.9749
14
14
Xö逷 (1 − 15); ö XX ½ Xö逷 = ö × 90 = 0.5000
14
= 4.4375
Percentage of turns in coil 7-9
0.2225
× 100 = 5.014
4.4375
Percentage of turns in coil 6-10
0.4339
× 100 = 9.778
4.4375
Percentage of turns in coil 5-11
0.6235
× 100 = 14.051
4.4375
Percentage of turns in coil 4-12
0.7818
× 100 = 17.618
4.4375
Percentage of turns in coil 3-13
0.9009
× 100 = 20.302
4.4375
Percentage of turns in coil 2-14
0.9749
× 100 = 21.9696
4.4375
0.500
× 100 = 11.2676
4.4375
The turns in each coil will be
Xö逷 7 − 9 = (0.05014 × 48)
= 2.406 ≈2
Xö逷 6 − 10 = (0.09778 × 48)
= 4.693 ≈5
Xö逷 5 − 11 = (0.1405 × 48)
= 6.744 ≈7
Xö逷4 − 12 = (0.17618 × 48)
= 8.456 ≈8
Xö逷 3 − 13 = (0.20302 × 48)
= 9.745 ≈ 10
Xö逷 2 − 14 = (0.219696 × 48)
= 10.545 ≈ 11
Xö逷 1 − 15 = (0.112676 × 48)
= 5.40 ≈5
Total 48
Amended value of = 2 × 48 = 96
The winding factor is calculated as;
= 0.3695 ≈ 0.4
(1) Running Winding ( Main Winding)
=
4.44 X∅
(2) Conductor size
δ
Am=
(4) Number of Stator Slots
fm
B ts 6
( S s / p ) ´W ts ´ Li
(7) Stator Core
8.4 ( + )
= × 逷X r +2
DESIGN OF
ROTOR
(1)Number of Rotor Slots
The number of rotor slots is so chosen that there is
no noise producing combinations. The number of
rotor slots are divisible by number of poles. The
number of rotor slots S r differ from S s by 20 % or
more .Die cast aluminum rotor construction is used.
For
Copper
A ,
r
6 0 . 5 to 0 . 8
Am
For Aluminum,
A r
6 1 to 1 . 6
A m
(3) Area of End Rings
Ie = (Sr*Ib)/πp
Area of each end ring Ae = Ie /δe
mm2
Area of the rotor bars can be
calculated as
Ab = Ib /δb mm2
I S rIb S r a bd
a e 6 e
6 6 b
d e ppde ppde
0 . 32 A d
6 r
´ b
p d e
Ib= current in each bard
=b a b
ring p
(4) Rotor Resistance
It should be as low as possible to keep the rotor
copper loss minimum and to maintain high
efficiency ,high full load speed and minimum
temperature rise. In single phase motors ,rotor
resistance effects the maximum torque for a given
flux and a high value of pull out torque is obtained
with rotor resistance.
For split phase motors = 0.45 to 0.55
For capacitor start motors = 0.45 to 0.8
(5)Flux density
Rotor Teeth in the stator teeth =
fm
B tr 6
( S s / p ) ´W tr ´ Li
(6) Rotor Core
Flux density in the stator core
f
B 6 m
2 ´ d ´ L
c r
cr i
r L mtm T m
(4) Main winding Resistance
6
rsm am
(5) Stator Resistance
L mts ´ T s
rs 6 r
as
(6) Rotor Resistance
L mtr ´ Tr
rr 6 r
ar
The value of rotor resistance referred to running
winding ;
é Lb 2 Ds ù
rrm 6 8Tm K wm .
2
rê K ring ú
ëS r a b p p a e
2
û
Design of Starting Winding for Split
phase Motors
The starting winding is designed for maximum
torque per ampere of starting current .In order that
starting winding can produce a revolving field the
flux set up by it must be out of phase with flux set
up by the main winding. With resistance split phase
motors the required resistance is obtained by using
a small section wire i.e. about 25 % of main winding.
The phase angle between starting winding current
and the line voltage should be about 0.4 of main
winding.