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Short Quiz 1

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Sumaya, Miguel P.

MEE12 10/14/2022

APPLIED ENGINEERING MATHEMATICS

Solve for x (all possible values of x)


1. 𝟑𝒙𝟐 − 𝟒𝒙 − 𝟑𝟐 = 𝟎
(3𝑥 + 8)(𝑥 − 4) = 0
3𝑥 + 8 = 0
𝑥−4=0
−𝟖
𝒙= 𝒐𝒓 𝒙 = 𝟒
𝟑

2. 𝟐𝒙 − 𝟒𝒚 + 𝟑𝒛 = 𝟑𝟓
2𝑥 − 4𝑦 + 4𝑦 + 3𝑧 = 35 + 4𝑦
2𝑥 + 3𝑧 − 3𝑧 = 35 + 4𝑦 − 3𝑧
2𝑥 = 35 + 4𝑦 − 3𝑧
2𝑥 4𝑦 − 3𝑧 + 35
=
2 2
𝟒𝒚 − 𝟑𝒛 + 𝟑𝟓
𝒙=
𝟐

−𝟑𝒙 − 𝟐𝒚 + 𝟒𝒛 = 𝟓
−3𝑥 − 2𝑦 + 2𝑦 + 4𝑧 = 5 + 2𝑦
−3𝑥 + 4𝑧 − 4𝑧 = 5 + 2𝑦 − 4𝑧
−3𝑥 = 5 + 2𝑦 − 4𝑧
−3𝑥 5 + 2𝑦 − 4𝑧
=
−3 −3
𝟐𝒚 − 𝟒𝒛 + 𝟓
𝒙=
−𝟑

−𝒙 − 𝟓𝒚 + 𝟕𝒛 = 𝟑𝟔
−𝑥 − 5𝑦 + 5𝑦 + 7𝑧 = 36 + 5𝑦
−𝑥 + 7𝑧 − 7𝑧 = 36 + 5𝑦 − 7𝑧
−𝑥 = 36 + 5𝑦 − 7𝑧
−𝑥 5𝑦 − 7𝑧 + 36
=
−1 −1
𝟓𝒚 − 𝟕𝒛 + 𝟑𝟔
𝒙=
−𝟏
3. 𝟒𝒙+𝟏 = 𝟖𝟑𝒙−𝟓
(𝑥+1) (3𝑥−5)
22 = 23
22𝑥+2 = 29𝑥−15
2𝑥 + 2 = 9𝑥 − 15
15 + 2 = 9𝑥 − 2
17 = 7𝑥
17 7𝑥
=
7 7
𝟏𝟕
=𝒙
𝟕

4. 𝒍𝒐𝒈𝟑𝒙 + 𝟐𝒍𝒐𝒈𝒙 + 𝐥𝐨𝐠(𝟐) = 𝟏𝟎𝟐


3𝑙𝑜𝑔𝑥 + 2𝑙𝑜𝑔𝑥 + 0.30103 = 100
30103
5𝑙𝑜𝑔𝑥 + = 100
100000
100000(5𝑙𝑜𝑔𝑥) + 30103
= 100
100000
500000𝑙𝑜𝑔𝑥 + 30103 = 100000(100)
500000𝑙𝑜𝑔𝑥 + 30103 − 30103 = 10000000 − 30103
500000𝑙𝑜𝑔𝑥 = 9969897
500000𝑙𝑜𝑔𝑥 9969897
=
500000𝑙𝑜𝑔 500000𝑙𝑜𝑔
𝟗𝟗𝟔𝟗𝟖𝟗𝟕
𝒙=
𝟓𝟎𝟎𝟎𝟎𝟎𝒍𝒐𝒈

SIMPLIFY
−1
(𝑎 −4 𝑏−6 )3 (𝑎2 𝑏5 ) (𝑎𝑏6 )2
5.
(𝑎 3 𝑏−2 )(𝑎4 𝑏−3 )
2 17
𝑎 𝑏
=
𝑎21 𝑏 23
𝟏
= 𝟏𝟗 𝟔
𝒂 𝒃
6. 𝐴𝐵𝐶𝐷 + 𝐴𝐶𝐷 + 𝐴𝐷 = 2022

D.) 3𝐷 = 2, 12, 22
2 22
𝐷 = , 4,
3 3
𝑫=𝟒

C.) 1 + 3𝐶 = 2, 12, 22
1 − 1 + 3𝐶 = 2 − 1, 12 − 1, 22 − 1
3𝐶 = 1, 11, 21
1 11
𝐶= , ,7
3 3
𝑪=𝟕

B.) 2 + 𝐵 + 𝐴 = 10,20

2 − 2 + 𝐵 + 𝐴 = 10 − 2, 20 − 2
𝐵 + 𝐴 = 8, 18
𝑩=𝟕
𝐴𝑠𝑠𝑢𝑚𝑒 𝐵 + 𝐴 = 8, 18 𝐴𝑠𝑠𝑢𝑚𝑒 𝐵 + 𝐴 = 18
𝐵+𝐴=8 𝐵 + 𝐴 = 18
1+𝐴=2 𝐵=9
𝐴=1 𝐴=9
𝐵=7

A.) 𝐴 = 1

A=1, B=7, C=7, D=4

1774+174+74=2022

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