Coding & Decoding

Prof. Shashant Jaykar

Prof. Shashant Jaykar

Contents:
 Coding Concepts

 Type 1 Numericals

 Type 2 Numericals

 Type 3 Numericals

 Type 4 Numericals
Prof. Shashant Jaykar

Coding Concepts:
1 2 3 4 5 6 7 8 9 10 11 12 13
A B C D E F G H I J K L M
Z Y X W V U T S R Q P O N
26 25 24 23 22 21 20 19 18 17 16 15 14

E J O T Y
5 10 15 20 25

G7
Prof. Shashant Jaykar

Type 1 Numericals:
Q_1: If in a coding, Table is known as Chair, Chair as Cupboard, Cupboard as Chalk, Chalk as Book, Book as Duster and Duster
as Table. Main Code
1. What will be used to sit? a) Chair, b) Book, c) Table, d) Cupboard Table Chair
Sol: Cupboard Chair Cupboard
2. What will be used for reading? a) Chalk, b) Book, c) Duster, d) Cupboard Cupboard Chalk
Sol: Duster Chalk Book
3. The board will be cleaned by? a) Table, b) Chalk, c) Duster, d) Cupboard Book Duster

Sol: Table Duster Table

Q_2: If in a coding, Red is known as White, White as Black, Black as Yellow, Yellow as Green, Green as Sky and Sky as Pink.
1. What will be the colour of Sunflower? a) Yellow, b) Red, c) Green, d) Pink Main Code
Red White
Sol: Green
White Black
2. What will be the colour of Sky? a) Yellow, b) Red, c) Green, d) Pink
Black Yellow
Sol: Pink
Yellow Green
3. What will be the colour of Teeth? a) Yellow, b) White, c) Black, d) Pink Green Sky
Sol: Black Sky Pink
Prof. Shashant Jaykar

Type 2 Numericals:
Q_3: In any coding, if A = 1, B = 2, C = 3 - - - - Z = 26 then,
What will be the sum of the letter of word “APPLE”? a) 49, b) 50, c) 51, d) 48
Sol:
A P P L E

1 16 16 12 5
Sum = 1 + 16 + 16 + 12 + 5 = 50

Q_4: In any coding, if A = 1, B = 2, C = 3 - - - - Z = 26 then,

What will be the sum of the letter of word “EDUCATION”? a) 91, b) 92, c) 90, d) 102
Sol: E D U C A T I O N

5 4 21 3 1 20 9 15 14

Sum = 5 + 4 + 21 + 3 + 1 + 20 + 9 + 15 + 14 = 92
Prof. Shashant Jaykar

Type 2 Numericals:
Q_5: In any coding, if A = 2, B = 4, C = 6 - - - - Z = 52 then,
What will be the sum of the letter of word “COOL”? a) 90, b) 50, c) 45, d) 48
Sol:
C O O L

3 15 15 12
Sum = 2 × (3 + 15 + 15 + 12) = 90

Q_6: In any coding, if A = 2, B = 4, C = 6 - - - - Z = 52 then,

What will be the sum of the letter of word “POPULATION”? a) 264, b) 279, c) 220, d) 278
Sol: P O P U L A T I O N

16 15 16 21 12 1 20 9 15 14

Sum = 2 × (16 + 15 + 16 + 21 + 12 + 1 + 20 + 9 + 15 + 14) = 278

Prof. Shashant Jaykar

Type 2 Numericals:
Q_7: In any coding, if A = 26, B = 25, C = 24 - - - - Z = 1 then,
What will be the sum of the letter of word “GROUND”? a) 90, b) 82, c) 83, d) 74
Sol:
G R O U N D

7 18 15 21 14 4
Sum = (27 – 7) + (27 – 18) + (27 – 15) + (27 – 21) + (27 – 14) + (27 – 4) = 83

Q_8: In any coding, if A = 26, B = 25, C = 24 - - - - Z = 1 then,

What will be the sum of the letter of word “KASHI”? a) 88, b) 89, c) 78, d) 87
Sol: K A S H I

11 1 19 8 9

Sum = (27 – 11) + (27 – 1) + (27 – 19) + (27 – 8) + (27 – 9) = 87

Prof. Shashant Jaykar

Type 3 Numericals: Shifting Coding

Q_9: If “VOICE” is written as “OVIEC” in a coding, then what will be the code of “NOISE”? a) ONISE, b) OENIS, c) ONEIS, d)
ONIES 1 2 3 4 5 1 2 3 4 5
Sol: N O I S E
V O I C E

O V I E C O N I E S
2 1 3 5 4 2 1 3 5 4

Q_10: If “ELECTRONICS” is written as “LETCEINORSC” in a coding, then what will be the code of “MANUFACTURE”? a)
AMFUNOTARER, b) AMFUNUCAERE, c) AMFUNUTCAER, d) AMFUNUCTAER
Sol:
1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11

E L E C T R O N I C S M A N U F A C T U R E

L E T C E I N O R S C A M F U N U T C A E R
2 1 5 4 3 9 8 7 6 11 10 2 1 5 4 3 9 8 7 6 11 10
Prof. Shashant Jaykar

Type 3 Numericals: Shifting Coding

Q_11: If “RECEIVER” is written as “ECERVIRE” in a coding, then what will be the code of “COMPUTER”? a) PMOCUTRE, b)
PMOCTUER, c) PMOCTURE, d) PMOCRETU
Sol: 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8

R E C E I V E R C O M P U T E R

E C E R V I R E P M O C T U R E
4 3 2 1 6 5 8 7 4 3 2 1 6 5 8 7

Q_12: If “PROPORTION” is written as “OPORPNOITR” in a coding, then what will be the code of “POPULATION”? a)
LUPOPONITA, b) LUPOPNOITA, c) LUPOPINOTA, d) LUPOPTAION
Sol: 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10

P R O P O R T I O N P O P U L A T I O N

O P O R P N O I T R L U P O P N O I T A
5 4 3 2 1 10 9 8 7 6 5 4 3 2 1 10 9 8 7 6
Prof. Shashant Jaykar

Type 4 Numericals: Shifting With Change

Q_13: If “LOVE” is written as “MNWD” in a coding, then what will be the code of “PLAY”? a) QMBX, b) QKBX, c) QKBZ, d)
QKCX 12 15 22 5
Sol:
L O V E P L A Y
+ - + - + - + -
1 1 1 1 1 1 1 1

M N W D Q K B X
13 14 23 4

Q_14: If “NAMES” is written as “TFNBO” in a coding, then what will be the code of “CRANE”? a) FOBSD, b) FOSBD, c)
FOBDS, d) FODBS 14 1 13 5 19
Sol:
N A M E S C R A N E
+ +
1 1

T F N B O F O B S D
20 6 14 2 15
Prof. Shashant Jaykar

Type 4 Numericals: Shifting With Change

Q_15: If “GROUP” is written as “OTNQF” in a coding, then what will be the code of “THEIR”? a) QHSDG, b) QHSGD, c)
QHGDS, d) QHDGS 7 18 15 21 16

Sol: G R O U P T H E I R
- -
1 1

O T N Q F Q H D G S
15 20 14 17 6

Q_16: If “DESIGN” is written as “FCUGIL” in a coding, then what will be the code of “REPORT”? a) TCRMRT, b) TCRKTR, c)
TCRNTR, d) TCRMTR 4 5 19 9 7 14

Sol: D E S I G N R E P O R T
+ - + - + - - -
+ + - +
2 2 2 2 2 2 2 2
2 2 2 2

F C U G I L T C R M T R
6 3 21 7 9 12
Prof. Shashant Jaykar

Type 5 Numericals: China Coding

Q_17: If in coding language “481” is written as “Sky Is Blue” and “246” as “Is Sea Deep” and “698” as “Sea Blue Book”, then
1. What will be the code for 4? a) Blue, b) Sea, c) Book, d) Is
Sol: Is 4 8 1 Sky Is Blue
2. What will be the code for Blue? a) 2, b) 4, c) 6, d) 8
Sol: 8 2 4 6 Is Sea Deep

3. What will be the code for “Sky Is Green”? a) 246, b) 148, c) 419, d) CND
6 9 8 Sea Blue Book
Sol: CND
Prof. Shashant Jaykar

Type 5 Numericals: China Coding

Q_18: If in coding language “Driving Is Not Easy” is written as “Jo Ro Ho Go” and “Rough And Tough Driving” as “No Sa Jo
Da” and “Looks Easy But Dangerous” as “Ai Ro To Po” and “Is Rough Tough Dangerous Driving” as “Ho Jo No Ai Da”, then

1. What will be the code for Driving? Driving Is Not Easy Jo Ro Ho Go

a) Jo, b) Ai, c) Ho, d) Po
Sol: Jo Rough And Tough Driving No Sa Jo Da

2. What will be the code for “Is Not Easy”?

Looks Easy But Dangerous Ai Ro To Po
a) Jo Ro Ho, b) Ai Ho Ro, c) Go Ro Ho, d) Po To Po
Sol: Ho Go Ro => Go Ro Ho
Is Rough Tough Dangerous Driving Ho Jo No Ai Da
3. What will be the code for “Rough But Nice”?
a) Jo Go Ro, b) Ai Ro Jo, c) Ho No To, d) Po Bi No
Sol: No/Da To/Po Extra => No Po Bi => Po Bi No
4. What will be the code for “Looks”?
a) CND, b) Ai, c) To/Po, d) To and Po
Sol: To/Po
Prof. Shashant Jaykar

Type 5 Numericals: China Coding

Q_19: Main contents and its china coding is given in table:

1. What will be the code for “Innocent”?

a) %8t, b) $9i, c) $8t, d) @19t Teacher Is More Important %4e $9t $2s &7r
Sol: $8t
2. What will be the code for “Joker”? Students Are Very Good @4d @8s #3e β4y

a) @15r, b) μ15j, c) μ15r, d) μ5r

Exam Is Coming $2s ε6g £4m
Sol: μ5r
3. What will be the code for “Water”?
Jobs Are At Stake #2t @5e #3e μ4s
a) β5r, b) $5w, c) @25r, d) γ5r
Sol: (New_code)5r => γ5r

Teacher = &7r
Symbol-Number-Alphabet
Is = $2s
More = %4e Starting of Spelling Count Last Alphabet
word with of word
Important = $9t same alphabet
Prof. Shashant Jaykar

Practice Questions:
Q_20: If in a coding, Kampala is known as Vienna, Vienna as Brasilia, Brasilia as Rome, Rome as Buenos Aires, Beunos Aires as
Madrid and Madrid as Berlin. Main Code
1. What is the capital of Spain? a) Brasilia, b) Madrid, c) Rome, d) Berlin Kampala Vienna
Sol: Berlin Vienna Brasilia
2. What is the capital of Argentina? a) Brasilia, b) Madrid, c) Rome, d) Berlin Brasilia Rome
Sol: Madrid Rome Buenos Aires
3. What is the capital of Uganda? a) Kampala, b) Vienna, c) Rome, d) Berlin Buenos Aires Madrid
Sol: Vienna Madrid Berlin

Q_21: In any coding, if A = 1, B = 2, C = 3 - - - - Z = 26 then,

What will be the sum of the letter of word “DICTIONARY”? a) 118, b) 128, c) 98, d) 148
Sol: D I C T I O N A R Y

4 9 3 20 9 15 14 1 18 25

Sum = 4 + 9 + 3 + 20 + 9 + 15 + 14 + 1 + 18 + 25 = 118
Prof. Shashant Jaykar

Practice Questions:
Q_22: In any coding, if A = 2, B = 4, C = 6 - - - - Z = 52 then,
What will be the sum of the letter of word “QUESTION”? a) 440, b) 240, c) 120, d) 245
Sol: Q U E S T I O N

17 21 5 19 20 9 15 14

Sum = 2 × (17 + 21 + 5 + 19 + 20 + 9 + 15 + 14) = 240

Q_23: In any coding, if A = 26, B = 25, C = 24 - - - - Z = 1 then,

What will be the sum of the letter of word “SILVER”? a) 67, b) 74, c) 97, d) 77
Sol:
S I L V E R

19 9 12 22 5 18
Sum = (27 – 19) + (27 – 9) + (27 – 12) + (27 – 22) + (27 – 5) + (27 – 18) = 77
Prof. Shashant Jaykar

Practice Questions:
Q_24: If “TEACHING” is written as “CHEATING” in a coding, then what will be the code of “GRADIENT”? a) DIRAGENT, b)
DIAGRENT, c) DIERATING, d) RATIGEND
Sol: 1 2 3 4 5 6 7 8 1 2 3 4 5 6 7 8

T E A C H I N G G R A D I E N T

C H E A T I N G D I R A G E N T
4 5 2 3 1 6 7 8 4 5 2 3 1 6 7 8

Q_25: If “LOCK” is written as “MPBJ” in a coding, then what will be the code of “WINE”? a) XMDJ, b) XJMD, c) XJDM, d)
XJND 12 15 3 11
Sol:
L O C K W I N E
+ + - - + + - -
1 1 1 1 1 1 1 1

M P B J X J M D
13 16 2 10
Prof. Shashant Jaykar

Practice Questions:
Q_26: If in any coding CAR = 19 and GATE = 29, then
1. What will be the code of “ORIGINAL”? a) 77, b) 84, c) 85, d) 95
7 1 20 5
Sol: 3 1 18
G A T E Total = 33
C A R Total = 22

Original = Total – Number of Alphabets

Original = Total – Number of Alphabets
29 = 33 - 4
19 = 22 - 3
15 18 9 7 9 14 1 12

O R I G I N A L Total = 85

Original = Total – Number of Alphabets

= 85 – 8 = 77
2. What will be the code of “LAPTOP”? a) 90, b) 80, c) 74, d) 64 12 1 16 20 15 16
Sol:
L A P T O P Total = 80

Original = Total – Number of Alphabets

= 80 – 6 = 74