Comparing Quantities Q - 1 TO 50

Answer 1) =5% of rs 300 =5/100 *300 =rs 15 now subtract the discounted amount from the price pr
bedsheet =300-15 =285 thus the
Answer 2) No. of bulbs =200, Cost of each bulb =10
Total C.P=200×10=2000
5 of them were discarded so only (200−5)=195 were sold, at a rate

of 12 per each bulb.
Total S.P=195×12=2340
Profit or loss =S.P–C.P=2340–2000=+340 (Profit)
Percent profit =C.PProfit×100=2000340×100buying price of bedsheet is rs

285
=17
∴ Profit is Rs.340 or 17%.

Answer 3) Let the C.P. = Rs. x.
Then First loss % =x(x−400)×100=x100x−40000%

Second loss % =x(x−380)×100=x100x−38000%
Given, x(100x−38000)−x(100x−40000)=4
⇒100x−38000−100x+40000=4x
⇒2000=4x
⇒x=500
Answer 4) We have,
A=P(1+100R)n
Here, P=Rs.12600,R=10,n=2
Therefore,
A=12600(1+10010)2=12600(1011)2
=12600×1011×1011=Rs.15246
CI=A−P=Rs.15246−Rs.12600=Rs.2646
Answer 5) We have,
A=P(1+100R)n
Here, P=Rs.12600,R=10,n=2
Therefore,
A=12600(1+10010)2=12600(1011)2
=12600×1011×1011=Rs.15246
Answer 7) 5% of x=600
⇒1005×x=600
⇒x=600×5100
⇒x=12000.
CI=A−P=Rs.15246−Rs.12600=Rs.264
Answer 8) We have, 30% × x = 600
or, 30100 × x = 600
Multiplying both sides by 100 and dividing both sides by 30,

we have x = 600 × 10030
x = 2000
answer 9) Let neeta have Rs. x in the beginning.
She spent 75% of the money that means she has only 25% left with her.
∴ she is left with 25% of Rs. x which is equal to Rs. 600.
∴10025×x=600
∴x=25600×100=2400
So, neeta had Rs. 2400 in the beginning
Answer 10) 70% of 30 students are good in mathematics Then ×30 students are good in maths =>
2100/100 => 21 students
Answer 11 ) Discount
Answer 12 ) Initial worth =10000, Depreciation =5%
Value after 1 year = Initial worth – Depreciation =10000–5% of 10000
Value =10000−(1005)×10000=9500
the machinery will be worth Rs.9500 after a year.
Answer 13) Initial Population, Po=20000

Rate of increase =5%
Let say population after 3 years at the end of the year 2000=P
P=Po(1+100R)T
P=200000(1+1005)3
P=20×400200000×21×441
P=231525
Thus, the population after 3 years in 2000 will be 231525.
Answer 14 ) The ratio of apples is to oranges = Number of apples : Number of oranges = 20 : 13
Answer 15 ) 50%
Answer 16 ) By unitary method:Out of 25 fruits, number of oranges are 5.So out of 100 fruits,
number of oranges 5 = ×100 = 20.
Answer 17 ) The ratio of the speed of a car 60 km/hr to the speed of a scooter 30 km/hr is 2:1
Answer 18 ) 5 m to 10 kmRatio = (5 𝑚 )/ (10 𝑘𝑚) = (5 𝑚)/ (10 × 1000 𝑚) = 1/2000 = 1 : 2000 (1 km

= 1000 m)
Answer 19)
(4/5) ×100 80%
Answer 21 ) 76% of 50 students are good in English. So, =76/100*50 =3800/100 =38 students are
good in English. Number of students not good in English are: =50-38 =12 students are not good in
English.
Answer 22 ∴ Total cost = Rs 560 + Rs 40 (Overhead expenses) = Rs 600 ∴ Profit = 5% of Rs 600 = = Rs

5 6 = Rs 30 Now, SP = CP + Profit = Rs 600 + Rs 30
Answer 25 ) Find selling price (SP) if a profit of 5% is made on a fan bought for Rs 560 and expenses
of Rs 40 made on its repairs. ∴ Total cost = Rs 560 + Rs 40 (Overhead expenses) = Rs 600 ∴ Profit =
5% of Rs 600 = = Rs 5 6 = Rs 30 Now, SP = CP + Profit = Rs 600 + Rs 30
Answer 26 ) Discount % = Discount/M.P × 100 Discount = M.P - S.P = 800 - 640 = 160 Discount = Rs.
160. Put, M.P and discount in discount% formula, Therefore, Discount percent is 20%.
Answer 29 ) 66.66% and can also be said as 66%
answer 30 ) C.P. of toy = Rs. 75

S.P. = Rs. 100
∴ Total gain = Rs. 100 - 75 = Rs. 25
gain%=25×100C.P=25×10075=1003=3313%
answer 31 ) Selling Price = Rs 100

Profit = Rs 20
Cost Price = SP - Profit = 100−20=80
Thus, Profit % = CPProfit×100=8020×100=25 %
answer 32 ) Let the cost price =Rs.100
Gain =33%=33% of 100=Rs.33
SP=CP+Gain=100+33=Rs.133
Now, Marked Price =SP+Discount
MP=133+5% of MP
MP−1005MP=133
MP=5133×100=Rs.140
Hence as per the given condition, the artile must be marked at 40% above its C
Answer 34 ) Let the original price be x.
VAT =8% of original price
Now, Cost price = VAT + Original price
It is given that, CP of hair dryer after added VAT =Rs. 5400
⇒x+8 of x=5400
⇒x+8x100=5400
⇒108x100=5400
⇒x=5400×100108
⇒x=300×1006
⇒x=50×100
⇒x=5000
So the price of the hair dryer was Rs. 5000 before including vat
Answer 36 ) For 1st year
Principal(P) =Rs. 10000, Rate(R) =8%
Time(T) =1 year
∴ Interest = 10000×8×1100=100×8=Rs.800
For 2nd year
P= Rs. 10000 +Rs. 800=Rs. 10800
Rate(R) =8% Time(T)=1 year
∴ Interest= 10800×8×1100=108×8=Rs.864
For 3rd year
∴ P= Rs. 10800 +Rs. 864 =Rs. 11664, R=8%, T=1 year
∴ Interest= 11664×8×1100=11664×225
=Rs. 933.12
∴ Amount =Rs. 11664 +933.12 =Rs. 12597.12
Hence required amount =Rs. 12597.12
∴ Compound interest =Rs. 12597.12 -10000=Rs. 2597.12
Answer 37) Rs 4500
Answer 38 ) We have,
p=20,000
R=5%
T=3 year,
A=20,000(1+1005)3
=20,000×(100105)3
=23,52.5
Answer 40) Given
Principal (P) = Rs 15000
Rate (R) = 10% p.a.
Period (n) = 2 years
Hence,
Amount (A) = P {1 + (R / 100)}n
= Rs 15000 {1 + (10 / 100)}2
On further calculation, we get,
= Rs 15000 × (11 / 10) × (11 / 10)
We get,
= Rs 18150
Therefore,
Compound interest = Amount – Principal
= Rs 18150 – 15000
We get,
= Rs 3150
Answer 41 ) 1:1000
Answer 42 ) Step - 1: Converting rupees to paise
We know that, 1 Rupee = 100 paise

∴ 5 Rupees = 15 × 100 paise
⇒ 5 Rupees = 500 paise .........eqn(i)
Step - 2: Substitute above result and get required ratio
Ratio of 50 paise to 5 Rupees = 5 Rupees50 paise
= 500 paise50 paise

Comparing Quantities Q - 1 TO 50

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Answer 1) =5% of rs 300 =5/100 *300 =rs 15 now subtract the discounted amount from the price pr

bedsheet =300-15 =285 thus the

Answer 2) No. of bulbs =200, Cost of each bulb =10

5 of them were discarded so only (200−5)=195 were sold, at a rate

Profit or loss =S.P–C.P=2340–2000=+340 (Profit)

Percent profit =C.PProfit×100=2000340×100buying price of bedsheet is rs

∴ Profit is Rs.340 or 17%.

Then First loss % =x(x−400)×100=x100x−40000%

Answer 8) We have, 30% × x = 600

or, 30100 × x = 600

Multiplying both sides by 100 and dividing both sides by 30,

answer 9) Let neeta have Rs. x in the beginning.

∴ she is left with 25% of Rs. x which is equal to Rs. 600.

So, neeta had Rs. 2400 in the beginning

Answer 12 ) Initial worth =10000, Depreciation =5%

Value after 1 year = Initial worth – Depreciation =10000–5% of 10000

the machinery will be worth Rs.9500 after a year.

Answer 13) Initial Population, Po=20000

Thus, the population after 3 years in 2000 will be 231525.

Answer 14 ) The ratio of apples is to oranges = Number of apples : Number of oranges = 20 : 13

Answer 18 ) 5 m to 10 kmRatio = (5 𝑚 )/ (10 𝑘𝑚) = (5 𝑚)/ (10 × 1000 𝑚) = 1/2000 = 1 : 2000 (1 km

(4/5) ×100 80%

Answer 22 ∴ Total cost = Rs 560 + Rs 40 (Overhead expenses) = Rs 600 ∴ Profit = 5% of Rs 600 = = Rs

Answer 29 ) 66.66% and can also be said as 66%

answer 30 ) C.P. of toy = Rs. 75

answer 31 ) Selling Price = Rs 100

Answer 37) Rs 4500

Answer 42 ) Step - 1: Converting rupees to paise

We know that, 1 Rupee = 100 paise

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