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    Conservation of Energy

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    Shaine Inovero
    The document discusses the conservation of energy. It defines energy and the different types of mechanical energy - kinetic energy and potential energy. Kinetic energy is the energy of motion, while potential energy is the energy due to an object's position. The principle of conservation of energy states that the total energy in an isolated system remains constant, though the type of energy may change. An example is given of a falling ball, where the kinetic energy increases as the potential energy decreases, keeping the total mechanical energy constant.

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    Conservation of Energy

    Uploaded by

    Shaine Inovero
    36 views2 pages
    The document discusses the conservation of energy. It defines energy and the different types of mechanical energy - kinetic energy and potential energy. Kinetic energy is the energy of motion, while potential energy is the energy due to an object's position. The principle of conservation of energy states that the total energy in an isolated system remains constant, though the type of energy may change. An example is given of a falling ball, where the kinetic energy increases as the potential energy decreases, keeping the total mechanical energy constant.

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    CONSERVATION OF ENERGY

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    The document discusses the conservation of energy. It defines energy and the different types of mechanical energy - kinetic energy and potential energy. Kinetic energy is the energy of motion, while potential energy is the energy due to an object's position. The principle of conservation of energy states that the total energy in an isolated system remains constant, though the type of energy may change. An example is given of a falling ball, where the kinetic energy increases as the potential energy decreases, keeping the total mechanical energy constant.

    Copyright:

    © All Rights Reserved
    Download as DOCX, PDF, TXT or read online from Scribd
    Download as docx, pdf, or txt
    36 views2 pages

    Conservation of Energy

    Uploaded by

    Shaine Inovero
    The document discusses the conservation of energy. It defines energy and the different types of mechanical energy - kinetic energy and potential energy. Kinetic energy is the energy of motion, while potential energy is the energy due to an object's position. The principle of conservation of energy states that the total energy in an isolated system remains constant, though the type of energy may change. An example is given of a falling ball, where the kinetic energy increases as the potential energy decreases, keeping the total mechanical energy constant.

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    CONSERVATION OF ENERGY

    ENERGY – is that property whose possession enables something to perform work. Work and Energy have
    the same units. Both are scalar quantities.

    Types of Mechanical Energy


    1. Kinetic energy – energy possessed by a body due to its motion.
    K = ½ mv 2
    where: m = mass in kg, gm, slug
    v = speed in m/s, cm/s, ft/s
    K = kinetic energy
    Units of energy
    1 N-m = 1 Joule (J)
    1 dyne-cm = 1 erg
    Ft-lb

    2. Potential Energy (U) – energy possessed by a body due to its position.


    U = mgh
    g = gravitational acceleration
    h = distance of the body from the reference line or point
    U = potential energy

    Conservation of Energy – the total amount of energy in a system isolated from the rest of the universe
    always remains constant, although energy transformation from one form to another may
    occur within the system.

    A falling ball provides a simple example of conservation of energy.

    m = 1 kg U K U + K (mechanical energy)
    50 m 490 J 0 490 J

    40 m v 392 J 98 J 490 J

    30 m 294 J 196 J 490 J

    20 m 196 j 294 j 490 J

    10 m 98 J 392 J 490 J

    0m 0 490 J 490 J

    K1 + U1 = K2 + U2 = U3 + K3 (friction and air resistance were neglected)


    At 50 m U = mgh = (1 kg)(9.8 m/s 2)(50 m) = 490 J K = 1/2mv 2 = 0

    At 40 m U = (1 kg)(9.8 m/s2)(40 m) = 392 J v 22 = v12 – 2gy


    v 22 = 0 – 2(9.8)(-10 m) = 196 m2/s2
    K = ½ (1 kg)(196) = 98 J

    At 30 m U = (1 kg)(9.8 m/s2)(30 m) = 294 J K = ½(1 kg)(392) = 196 J

    V22 = -2(9.8)(-20 m) = 392 m2/s2

    Experiment 7
    x = vo cos0t o = 00
    x = v ot
    vo = x/t

    y = vo sinot – 1/2gt2
    -y = - 1/2gt2
    t = 2y/g

    Given: x = _____, y = _____, vo = ?

    x = v0 cosot

    vo = x/t

    y = vo sin o t – 1/2gt2
    -y = -1/2gt2
    t = 2y/g
    K1 + U1 = K2 + U2

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