Nothing Special   »   [go: up one dir, main page]
Scribd Logo
Upload

Welcome to Scribd!

  • 58 views

    RCC14 Crack Width

    Uploaded by

    Kha Phuc
    The document contains calculations to determine crack width in concrete flexure according to BS 8110 and BS 8007 standards. It provides input parameters such as material strengths, reinforcement details, and applied load. It then shows the calculations to determine stress in reinforcement and concrete, strain values, and ultimately the calculated crack width of 0.39 mm.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd

    RCC14 Crack Width

    Uploaded by

    Kha Phuc
    58 views1 page
    The document contains calculations to determine crack width in concrete flexure according to BS 8110 and BS 8007 standards. It provides input parameters such as material strengths, reinforcement details, and applied load. It then shows the calculations to determine stress in reinforcement and concrete, strain values, and ultimately the calculated crack width of 0.39 mm.

    Original Description:

    CRACK WIDTH THEORY AND PRACTICE

    Copyright

    © © All Rights Reserved

    Available Formats

    PDF, TXT or read online from Scribd

    Did you find this document useful?

    Is this content inappropriate?

    The document contains calculations to determine crack width in concrete flexure according to BS 8110 and BS 8007 standards. It provides input parameters such as material strengths, reinforcement details, and applied load. It then shows the calculations to determine stress in reinforcement and concrete, strain values, and ultimately the calculated crack width of 0.39 mm.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd
    Download as pdf or txt
    58 views1 page

    RCC14 Crack Width

    Uploaded by

    Kha Phuc
    The document contains calculations to determine crack width in concrete flexure according to BS 8110 and BS 8007 standards. It provides input parameters such as material strengths, reinforcement details, and applied load. It then shows the calculations to determine stress in reinforcement and concrete, strain values, and ultimately the calculated crack width of 0.39 mm.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd
    Download as pdf or txt
    of 1

    Project

    Spreadsheets to BS 8110etc The Concrete Centre


    Client
    Advisory Group Made by Date Page
    Location
    Grid line 1 RC 16-May-2023 34
    Crack Width Calculations to BS8110: 2005/ BS8007:1987 Checked Revision Job No
    Originated from RCC14.xls v 4.0on CD © 2006 TCC chg - R68

    CRACK WIDTH CALCULATIONS - FLEXURE -

    INPUT
    fcu= 45 N/mm 2
    fy= 500 N/mm 2
    Area of reinforcement " As " = 1005 mm 2
    b= 1000 mm
    h= 325 mm
    d= 285 mm
    Minimum cover to tension reinforcement " CO " = 30 mm
    Maxmum bar spacing " S " = 200 mm
    Bar dia " DIA " = 20 mm
    " acr " =(((S/2)^2+(CO+DIA/2)^2)^(1/2)-DIA/2) as default or enter other value = 97.70 mm
    "acr " is distance from the point considered to the surface of the nearest longitudinal bar
    Applied service moment " Ms "= 112.0 KNm

    CALCULATIONS
    moduli of elasticity of concrete " Ec" = (1/2)*(20+0.2*fcu) = 14.5 KN/mm 2
    moduli of elasticity of steel " Es " = 200.0 KN/mm 2
    Modular ratio " a " = (Es/Ec) = 13.79
    " r " = As/bd = 0.004
    depth to neutral axis, "x" = (-a.r +((a.r)2 + 2.a.r)0.5.d = 76 mm

    " Z " = d-(x/3) = 260


    Reinforcement stress " fs " = Ms/(As*Z) = 429 N/mm 2
    Concrete stress " fc " = (fs*As)/(0.5*b*x) = 11.34 N/mm 2
    Strain at soffit of concrete beam/slab " e1 " = (fs/Es)*(h-x)/(d-x) = 0.002557
    Strain due to stiffening effect of concrete between cracks " e2 " =
    e2 = b.(h-x)2/(3.Es.As.(d-x)) for crack widths of 0.2 mm Used
    e2 = 1.5.b.(h-x)2/(3.Es.As.(d-x)) for crack widths of 0.1 mm n/a
    e2 = 0.000492
    Average strain for calculation of crack width " em "= e1-e2 = 0.002065

    Calculated crack width, " w " = 3.acr.em/(1+2.(acr-c)/(h-x))


    CALCULATED CRACK WIDTH, 'w' = 0.39 mm

    You might also like