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11th Atkins Physical Chemistry Student Solutions Manual-1

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1

1 The properties of gases

1A The perfect gas


E1A.1(a) 810 Torr 0.962 atm
E1A.2(a) no 24.4 atm
E1A.3(a) 3.42 bar 3.38 atm
E1A.4(a) 30 lb in−2 .
E1A.5(a) 0.0427 bar 4.27 × 105 Pa
E1A.6(a) S8 .
E1A.7(a) 6.2 kg
E1A.8(a) x O2 = 0.240 x N2 = 0.760 p O2 = 0.237 bar p N2 = 0.750 bar x N2 = 0.780
x O2 = 0.210 p N2 = 0.770 bar p O2 = 0.207 bar
E1A.9(a) 0.169 kg mol−1
E1A.10(a) θ = −273 ○ C
E1A.11(a) x H2 = 23 x N2 = 13 p H2 = 2.0×105 Pa p N2 = 1.0×105 Pa p tot = 3.0×105 Pa
P1A.1 1.15 × 105 Pa 8.315 J K−1 mol−1
P1A.3 0.082062 atm dm3 mol−1 K−1
P1A.5 p = ρRT/M 45.94 g mol−1
P1A.7 24.5 Pa 9.14 kPa 24.5 Pa
P1A.9 between 0.27 km3 and 0.41 km3
P1A.11 −2 Pa 0.25 atm
P1A.13 c CCl3 F = 1.1 × 10−11 mol dm−3 c CCl2 F2 = 2.2 × 10−11 mol dm−3 c CCl3 F = 8.0 ×
10−13 mol dm−3 c CCl2 F2 = 1.6 × 10−12 mol dm−3

1B The kinetic model


E1B.1(a) 9.975
E1B.2(a) υ rms,H2 = 1.90 km s−1 υ rms,O2 = 478 m s−1
E1B.3(a) 6.87 × 10−3
E1B.4(a) 1832 m s−1
E1B.5(a) υ mp = 333 m s−1 υ mean = 376 m s−1 υ rel = 531 m s−1
E1B.6(a) 1.7 × 1010 s−1
E1B.7(a) 475 m s−1 82.9 nm 8.10 × 109 s−1
E1B.8(a) 0.20 Pa
E1B.9(a) 1.4 × 10−6 m = 1.4 µm
P1B.3 υmean, new ≈ 0.493 υmean
P1B.5 3.02 × 10−3 for n = 3 4.89 × 10−6 for n = 4
P1B.7 1.12 × 104 m s−1 5.04 × 103 m s−1
2

P1B.9 0.0722 at 300 K 0.0134 at 1000 K


P1B.11 9.7 × 1010 s−1

1C Real gases
E1C.1(a) 0.99 atm 1.8 × 103 atm
E1C.2(a) a = 0.0761 kg m5 s−2 mol−2 b = 2.26 × 10−5 m3 mol−1
E1C.3(a) 0.88 1.2 dm3 mol−1
E1C.4(a) 140 atm
E1C.5(a) 50.7 atm 35.2 atm 0.695
E1C.6(a) 1.78 atm dm6 mol−2 0.0362 dm3 mol−1 153 pm
E1C.7(a) 1.41 × 103 K 175 pm
E1C.8(a) 8.7 atm 3.6 × 103 K 4.5 atm 2.6 × 103 K 0.18 atm 47 K
E1C.9(a) 4.6 × 10−5 m3 mol−1 0.66
P1C.1 1.62 atm
P1C.3 0.929 0.208 dm3 mol−1
P1C.5 501.0 K
P1C.7 0.1353 dm3 mol−1 0.6957 0.5914
P1C.9 0.0594 dm3 mol−1 5.849 atm dm6 mol−2 . 20.48 atm
P1C.11 0.03464 dm3 mol−1 1.262 atm dm6 mol−2
P1C.13 Vm = 3C/B T = B 2 /3CR p = B 3 /27C 2
P1C.15 B = 0.0868 atm
′ −1
B = 2.12 dm mol−1
3
bp
P1C.19 1 + 1.11
RT
P1C.21 −0.01324 dm3 mol−1 1.063 × 10−3 dm6 mol−2
P1C.23 Vm = 13.6 dm3 mol−1 2%
2RT 1/2
I1.1 υ = ( )
M
3
I1.3 0.071 dm mol−1

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