Operations Management Lecture
Operations Management Lecture
Operations Management Lecture
◼ Contract Agreement:
Cost estimate = Rs. 100,000
◼ All allowable costs will be reimbursed
Target Fee = Rs. 10,000
Minimum Fee = Rs. 5,000
Maximum Fee = Rs. 15,000
Target Price = 110,000
Gain Sharing Ratio = 70/30
X Y
1 4
X Z
C (20) D (20)
3
Time 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46
A
B
C
D
Time 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46
A
B
C
D
1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 5 5 5 5 5 6 6 6 6
Time 2 4 6 8
0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6
A
B
C
D
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CCPM – Example – Continued
Cut 25-33% of original time estimates
1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 5 5 5 5 5 6 6 6 6
Time 2 4 6 8
0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6 8 0 2 4 6
A
B
C
D
◼ Basic questions
◼ What type of capacity is needed?
◼ How much is needed?
◼ When is it needed?
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Examples of Capacity Types and
Measures
◼ Types
◼ Design Capacity/Best operating level
◼ System capacity/Effective capacity
◼ Actual output
◼ Measure
◼ Throughput
◼ Utilization
◼ Efficiency
◼ Economies of scale
◼ Diseconomies of scale
◼ Economics of scope
◼ Learning curve
◼ Focused factories
◼ Plant within a plant (PWP)
◼ Subcontractor networks
◼ Capacity cushions
◼ Method 1:
◼ Current demand = Capacity used = 50
◼ Capacity available = 50 ×1.1 = 55
◼ Future demand = capacity required = 50 × 2 = 100
◼ Future capacity proposed = 100 × 1.2 = 120
◼ Capacity addition planned = 120 – 55 = 65
◼ Method 2:
◼ Current demand = Capacity used = 50
◼ Capacity available = 50 /0.9 = 55.56
◼ Future demand = capacity required = 50 × 2 = 100
◼ Future capacity proposed = 100 / 0.8 = 125
◼ Capacity addition planned = 125 – 55.56 = 69.44
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Use of Input Measure – Formulation
◼ Capacity requirements = M
= [D. p + (D/Q). S]/[N. {1 – (C/100)}]
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Use of Input Measure – Example
3500
◼ BM time required = (3500 × 0.5 + × 0.4) = 1765.56
90
◼ BM time with capacity cushion = 2077.12
2800
◼ HRM time required = (2800 × 0.7 + × 0.35)
95
=1970.32
◼ HRM time with capacity cushion = 2318.02
◼ If the machine can be used for both BM and HRM material
◼ Then total time = 4395.14
◼ One machine input capacity = 250 × 8 = 2000 hrs.
◼ If demand must be met and cushion must be > 15%
◼ No of machine required = 4395.14/ 2000 = 2.2 ≈ 3
◼ What was the assumption about Capacity Cushion?
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Evaluating Capacity Requirements –
Example
◼ Current situation
◼ 3 flexible machines for Type X with
◼ 150,000/year for each machine
◼ Requires 2 operators/Machine – No extra operator
◼ 5 flexible machines for Type Y with
◼ 250,000/year for each machine
◼ Requires 3 operators/Machine – 5 extra operator
◼ Demand Forecast (In Thousands)
Product Type Year 1 Year 2 Year 3 Year 4 Year 5
Type X 60 100 150 200 250
Product A
Type Y 100 200 300 400 500
Type X 75 85 95 105 120
Product B
Type Y 200 400 600 700 900
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Mix Capacity – Solution