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CONFIDENTIAL OCT2021/PSY223

SEMESTER/ YEAR : 2 

PROGRAMMES : DIPLOMA IN OFFSHORE ENGINEERING 

SUBJECT NAME : PHYSICS II 

MODULE CODE : PSY 223 

ASSESSMENT : TEST 2 

DURATION : 8 PM - 12 AM (4 HOUR) 

DATE : 19 JANUARY 2022 

......................................................................................................................................................
...................... 

Name  

ID Number

Program/Group

Lecturer’s Name  NURUL AZWA BINTI OTHMAN

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Section  Question  Learning  Marks

Outcome    

  
Section Q1  CLO 2  /16

PHYSICS II Page 1 of 4 

Q2(a) – CLO 2  /22 CONFIDENTIAL


Q2(b)  OCT2021/PSY223 

QUESTION 1 
Q3(a) – CLO 2  /12
Q3(b)  1. State the
Archimedes’
Total  /50 Principle. Then
briefly explain
application of  Archimedes’ Principle in ship and submarine. 

= While constructing ships, Archimedes’ principle is followed, a large portion


of the ships are kept hollow from inside that maintains their density less than
the water density, hence the weight of the ship becomes less than the weight of
the water displaced by it, and the buoyant force of magnitude equal to the
displaced water exerts on the ship, and the ship floats on the surface of the
water.

(8 marks) 

2. The cylindrical piston of a hydraulic jack has a cross-sectional area


of 0.06m and the plunger has a cross-sectional area of 0.002m . 
2 2

Figure 1 

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a) What is the function of oil for the hydraulic jack? 

= jack oils are the fluid used in hydraulic jacks to easily lift any heavy object
with a small applied force. You can find hydraulic jack applications in material
handling equipment, earthmoving equipment, and everywhere in the automobile
workshops.
(2 marks) 

b) Calculate the downward force on the plunger required to lift


this load (3 marks)
= F1/A1 = F2/A2
= 0.002 m2 x 9000 N / 0.06 m2
F1 = 300 N
c) If the distance moved by the plunger is 75 cm, what is
the distance  moved by the larger piston. 

= A1d1 = A2d2

0.002 (75) = 0.06 d2

D2 = 2.5 cm

(3 marks)

PHYSICS II Page 3 of 6 

CONFIDENTIAL OCT2021/PSY223 

QUESTION 2 

1. Find Give the definition for: 


a) Heat 

= heat is energy in transfer to or from a thermodynamic system, by


mechanisms other than thermodynamic work or transfer of matter.

b) Temperature  

= Temperature is a physical quantity that expresses hot and cold. It is the


manifestation of thermal energy, present in all matter, which is the source of
the occurrence of heat, a flow of energy, when a body is in contact with
another that is colder or hotter.

c) Energy Transfer 

= Energy transfer is the process by which energy is relocated from one


system to another, for example, through the transfer of heat, work or mass
transfer. In chemistry, the affect of atomic or molecular composition on energy
transfer is studied, examples of which include energy transfer through molecular
collisions or through fluorescence resonance energy transfer.

d) Specific heat capacity 

= specific heat capacity of a substance is the heat capacity of a sample of the


substance divided by the mass of the sample. Specific heat is also sometimes
referred to as massic heat capacity. Informally, it is the amount of heat that
must be added to one unit of mass of the substance in order to cause an
increase of one unit in temperature.

e) Molar heat capacity 

= The molar heat capacity of a chemical substance is the amount of energy


that must be added, in the form of heat, to one mole of the substance in order
to cause an increase of one unit in its temperature. Alternatively, it is the
heat capacity of a sample of the substance divided by the amount of
substance of the sample; or also the specific heat capacity of the substance
times its molar mass. The SI unit of specific heat is joule per kelvin per
mole, J⋅K−1⋅mol−1.

(10 marks) 

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2. Calculate the energy needed to heat: 

a) 80ml of water form 17°C to 50°C. 

= Q = (80) (4.18) (50 – 17)


= 11035.2 J

(4 marks) 

b) 2.3 litres of water from 34°C to 100°C. 

= Q = (2.3) (4.18)(100 – 34)

= 634.534 J

(4 marks) 

d) 200g of cooking oil from 23°C to 100°C. 

= Q = (200)(2.2)(100 – 23)

= 33880 J

(4 marks) 

(Note: 1 ml = 1 g) 

Given that: Cg for water is 4.18 J /g/°C and Cg for oil is 2.2J /g/°C

PHYSICS II Page 5 of 6 

CONFIDENTIAL OCT2021/PSY223 

QUESTION 3 

1. Describe and illustrate electromagnetism. 


= Electromagnetism is the physical interaction among electric charges, magnetic
moments, and the electromagnetic field. The electromagnetic field can be static,
slowly changing, or form waves. Electromagnetic waves are generally known as
light and obey the laws of optics.

(6 marks) 

2. Define current carrying conductor. 

= Now the direction of the current through this conductor depends on the conductor
in which orientation the conductor is placed between two poles of the magnet. So
the current carrying conductor always faces a force in the vicinity of a permanent
magnet or any electro-magnet. Based on this phenomenon DC motor rotates.

(2 Marks) 

3. A transformer primary winding connected across a 415 V supply


has 750 turns.  Determine how many turns must be wound on the
secondary side if an output  of 1.66 kV is required. 

= Vs / Vp = Ns / Np

= 1.66 x 1000

= 1660 v

= 1660 / 415 x 750

Ns = 3000 turns

(4 Marks) 

- END OF QUESTION PAPER -

PHYSICS II Page 6 of 6

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