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Lecture 4 - Fluid Dynamics - Linear Momentum Conservation

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13/07/1443

2 -Conservation of momentum (vector) (Momentum equation)

a- Conservation of linear momentum

the time rate of change of the linear momentum of the


system is equal to the sum of external forces acting on
the system
𝑑
(M𝑉)= 𝐹
𝑑𝑡

Using reynolds transport theorem

𝑑𝑋 𝜕
= 𝑥𝜌𝑑𝑉 + 𝑥𝜌𝑉. 𝑑𝐴 & 𝑋 = 𝑀𝑉 𝑎𝑛𝑑 𝑥 = 𝑉
𝑑𝑡 𝜕𝑡 𝐶𝑉 𝐶𝑆

𝜕 𝑑𝑀𝑉
𝜕𝑡 𝐶𝑉
𝑉𝜌𝑑𝑉 + 𝐶𝑆
𝑉𝜌𝑉 . 𝑑𝐴 = 𝑑𝑡

𝜕
𝜕𝑡 𝐶𝑉
𝑉𝜌𝑑𝑉 + 𝐶𝑆
𝑉𝜌𝑉 . 𝑑𝐴 = 𝐹
𝜕
When the flow is steady
𝜕𝑡 𝐶𝑉
𝑉𝜌𝑑𝑉 =0
let 𝑉= 𝑉𝑥 𝑖+ 𝑉𝑦 𝑗+ 𝑉𝑧 𝑘
then 𝑉𝜌𝑉 . 𝑑𝐴 = 𝐹
𝐶𝑆 𝐹 = 𝐹𝑥 𝑖+ 𝐹𝑦 𝑗+ 𝐹𝑧 𝑘
Momentum equation in x-direction

𝑉 𝜌 𝑉. 𝑑𝐴 = 𝐹𝑥 𝑚° 𝑉𝑥 − 𝑚° 𝑉𝑥 = 𝐹𝑥
𝐶𝑆 𝑥
𝑜𝑢𝑡 𝑖𝑛
Momentum equation in y-direction
𝑉 𝜌𝑉. 𝑑𝐴 = 𝐹𝑦 𝑚° 𝑉𝑦 − 𝑚° 𝑉𝑦 = 𝐹𝑦
𝐶𝑆 𝑦
𝑜𝑢𝑡 𝑖𝑛
Momentum equation in Z-direction
𝑉 𝜌𝑉. 𝑑𝐴 = 𝐹𝑧 𝑚° 𝑉𝑧 − 𝑚° 𝑉𝑧 = 𝐹𝑧
𝐶𝑆 𝑧
𝑜𝑢𝑡 𝑖𝑛

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Body forces Surface forces


(Gravity, Electrical, ….) (Normal, p, Tangential, 𝜏)

Assume steady, one dimensional flow in a


channel, determine the total wall forces
exerted on the fluid flow neglecting body
forces.
𝑚° 𝑉𝑥 − 𝑚° 𝑉𝑥 = 𝐹𝑥
𝑜𝑢𝑡 𝑖𝑛
𝑚° 𝑉𝑜𝑢𝑡 − 𝑚° 𝑉𝑖𝑛 = 𝐹𝑏𝑥 + 𝑃𝑖𝑛 𝐴𝑖𝑛 − 𝑃𝑜𝑢𝑡 𝐴𝑜𝑢𝑡
𝐹𝑏𝑥 = [𝑚° 𝑉𝑜𝑢𝑡 + 𝑃𝑔𝑜𝑢𝑡 𝐴𝑜𝑢𝑡 ] − [𝑚° 𝑉𝑖𝑛 +𝑃𝑔𝑖𝑛 𝐴𝑖𝑛 ]

The inlet and outlet pressures are gauge pressure to take the
effect of control volume

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