Guide For Fire Protection and Detection System
Guide For Fire Protection and Detection System
Guide For Fire Protection and Detection System
FOAM SYSTEM
Hydraulic Calculations :
Q = k x (P)^(1/2)
K = Q/(P)^1/2
K = 13/(30)^(1/2) = 2.3
Therefore ;
P = (Q /k)^2
P = (16/3)^2
P = 28.44 < Min. Operating Pressure ( Refused)
10 = 0.4085 x 16.4/d^2
d = 0.8 inch say 1 Inch.
10 = 0.4085 x 32.4/d^2
d = 1.15 inch say 1.5 Inch.
10 = 0.4085 x 65.6/d^2
d = 1.63 inch say 2 Inch.
10 = 0.4085 x 98.4/d^2
d = 2.004 inch say 2 inch
32.6 GPM
16.4 GPM 16.4 GPM
65.6 GPM
16.4 GPM 16.4 GPM
1 inch 1 inch
1.5 inch
1 inch 1 inch
2 inch
1 inch 1 inch
2 inch
DV 2 inch
1
2
5 4
DV
6
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Pressure Loss Calculation Sheet
Example :
Assume the system consists of 100 feet of 2-in. black schedule 40
pipe and that the fluid is a 3 percent AFFF foam concentrate with
the following properties: 100 equivalent feet of 2-in. schedule 40
black steel pipe Q = 30 gpm d = 2.067 inches μ = 1.1 cP 63 lb/ft3 T
= 68°F
Now that the Reynolds Number and the relative roughness have
been calculated, the friction factor can be determined by
referring back to the Moody diagram.
P = 1.2
v psi
1. Installation Identification
2. Hazard Classification and Description
3. Liquid Identification
4. Type of Protection
5. Surface Area of Liquid to be protected
6. Foam agent Selected
7. Description, Number & Placement of Foam
application devices
8. Foam solution application Rate
9. Foam Concentrate Supply Rate
10. Water Supply Rate
11. Duration of Discharge
12. Total Quantity of Water required
13. Pipe Size Determination
14. Valve Selection and Location
15. Foam Proportioner Selection
16. Pump Consideration
17. Hydraulic Calculation
17.1 – The starting point
17.2 – Determination of Supply Riser Size
17.3 – Determination of Friction losses.
17.4 - Summary
Example Project
= ∏/4 (d)^2
= 11310 SF
Q=AxV
V = 0.4085 x Q (gpm) / d^2(inches)
10 = 0.4085 x 566/d^2
FL = 0.0420 psi/ft
Q=AxV
10 = 0.4085 x 1132/d^2
Foam Propotioner
5 1132 GPM @ 94.26 psi
psi
SUBJECT : Fixed foam System for flammable liquid atmospheric storage tank
HAZARD : 120-ft-diameter outdoor cone roof flammable liquid storage tank
Flammable or combustible liquid identification: Gasoline—SG 0.72
Foam agent selected: Fluoroprotein—3%
Duration of discharge: 55 min
Foam
Make Added Total Pipe & Eq. Propotioner Required
Pipe size Friction Static Psi
type and GPM GPM fitting Length Psi Press, GPM
location
Psi/ft Total Psi
Ref: NFPA 13, FL =
Table 4.52*Q^1.85/C^1.85*
23.4.3.1.1 d^4.87
1 566 566 50
Pump Capacity = Required Pressure(Considering Frictional,elevation Losses)- Available Pressure from city supply(if any)
Step - 01: Classify the Aircraft hangar into the correct group from
Group 1 through 4 ( NFPA 409, 2019; Chapter 4)
There are (3) types of primary foam systems available for aircraft
hangars.
• PRIMARY FOAM-WATER SPRINKLER SYSTEMS (May require
supplemental oscillating foam monitors)
• LOW-LEVELVEL FOAM SYSTEMS (Monitors or Grate
Nozzles)
• HIGH EXPANSION FOAM SYSTEMS
• Supplemental Requirements for all above systems FOAM-
WATER HAND HOSE LINE SYSTEMS
All Low-Expansion foam systems are sized on a (GPM / FT²) application density of
solution flow philosophy
All Medium and High-Expansion foam systems are sized on a (CFM) volumetric rate
of discharge philosophy
OPTION 1
OPTION 2
OPTION 3
OPTION 1
OPTION 2
OPTION 3
OPTION 4
All hangars housing fueled aircraft shall have a foam water hose
system
Exemption: Group 4 hangars with a fire area less than 12,000 SF do not require
foam hose line
• Two hand hose line flowing minimum for agent and water
calculations
1. Area of Hangar:
= 69300 CFM
• #NFPA 409. 6.2.5.4.3 The discharge rate of the system shall be based on the
application rate multiplied by the entire aircraft storage and servicing floor
area. The application total discharge rate shall include the sprinkler breakdown
factor in accordance with NFPA 11.
=SxQ
Where ;
Rs = 10 x 2550
Rs= 25500 CFM
= 130824 CFM
= 130824 /14491
= 9 Nos.
4. Agent Calculation:
Total Flow from the all Generators = flow of one generator x no.
of generators
= 119 x 9
= 1074 GPM
Required Solution in Gallons = Total flow x duration x % foam
concentrate
5. Sprinkler Demand:
= 2 x 60 x 20 x 0.03
= 72 GPM