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LESSON PLAN

I. OBJECTIVES
At the end of the lesson, 70% of the students should be able to:
 define interest and its variables,
 solve problems that involve interests.

II. SUBJECT MATTER: BUSINESS MATH XI
A. Topic: Simple Interests
B. References:
 http://teachersites.schoolworld.com/webpages/tahrens/files/Simple%20and
%20Compound%20Interest.pdf
C. Materials: visual aids, board work for exercises

III. LESSON PROPER


A. Preparation:
 Prayer, greeting and observe classroom arrangement.
B. Drill:
Change the following percent to decimals and vice versa
1. 15% = 0.15 6. 0.05= 5%
2. 2%= 0.02 7. 23% = 0.23
3. 0.8 = 80% 8. 50% = 0.5
4. 30% = .3 9. 0.078= 7.8 %
5. 120% = 1.2 10. 0.156 = 15.6 %
C. Motivation: PICTOWORD
Guess the hidden word by looking at the picture.
1.
= INTEREST

2.

=PRINCIPAL

3.

= PERCENTAGE

D. Presentation
1. Ask the students “what is interest?”
 INTEREST- the amount of money that you pay to borrow money or the amount of
money that you earn on a deposit.
Ways to get interest:
 Payment to the borrowed money (debtor)
Ex. Loans, pawnshops, and lending
 Earned on a deposit (creditors)
Ex. Bank deposits
2. Define and discuss the variables in computing simple interest.
 Simple Interest (I) — amount of money paid or earned for the use of money
 Principal (p) — the amount of money borrowed or invested
 Rate (r) — the annual interest rate written as a decimal
 Time (t) — the amount of time in years (If time is given in months, it must be
written as a fraction. For example, 6 months would be 6/12 years or 0.5 years.)
3. Present the formula for simple interest and show examples.

I=prt
Ex. A. Joe deposits P20,000 in an account at his bank. The interest rate is 6%. How much
interest will he earn in three (3) years?
I = prt
I = (20,000)(.06)(3)
I = P3,600.00.
Joe will earn P3600 in interest.

B. Joe borrows P94,500 to fix his car and paid P9,922.5 after 1 year and 6 months. How
many percent of interest does he paid to the bank?
I
r= Pt
9,922.5
r= (94,500)(1.5)
9,922.5
r= 141,750
r= 0.07
Joe paid 7% interest rate

C. Jill deposits P365000 on a bank with an interest rate of 5.5%. How long does Jill have to
wait if she wants her money to earn P15,000?
I
t=
Pr
15,000
t=
(365,000)(0.055)
15,000
t=
(20,075)
t=0.7471 or 0.75 ( round of to two decimal value)
t=0.75 x 12 months
t=9 months (Jill has to wait for 9 months)

IV. COMPARISON AND ABSTRACTION:


Solve for the following problems
1. Jane owes the bank some money at 4% per year. After half a year, she paid P45, 000 as
interest. How much money does she owe the bank?
I
P=
rt
45000
P=
( 0.04)(0.50)
45000
P=
0.02
P=P 2,250,000
2. John wants to have an interest income of P34, 500 a year. How much must he invest for
one year at 8%?
I
P=
rt
34500
P=
(0.08)(1)
45000
P=
0.08
P=P 43,250

V. GENERALIZATION:
 What is Interest? is the amount of money to pay a borrowed money or the amount
earned in a deposit.
 What are the variables to compute interest? Principal, rate and time
 Do you think learning how to compute interest will help you? In what way?
yes, by knowing how much interest will you pay for a specific duration when loaning
in a bank or in doing any transactions involving borrowing and depositing.
VI. APPLICATION:
QUIZ
Compute for the missing term
1. Principal: P25,000 2. Principal: P280,000
Interest: P3,000 Rate: 2.3%
Time: 10 months Interest: P46,000
Answer
I I
1. r = Pt 2. t= Pr
3000
r= 46,000
10 t=
( 25,000 ) ( ) (280,000)(0.023)
12
3000 46,000
r= t=
( 25,000 ) ( 0.83) 6440
3000
r= t=7.14 years .
20,750
r=0.14%

3. Dianna deposits P725,000 into a savings account that pays 2.3% simple annual
interest. How much interest will Dianna earn after 18 months?
I = prt
I =(725,000)(0.023)(1.5)
I =P 25,012.50

VII. ASSIGNMENT:
Find the meaning of the following word
 compound interest
 annual rate
 formula for compound interest
Prepared by:
Chriza N. Dollete

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