Midterm - Engg 404 2022
Midterm - Engg 404 2022
Midterm - Engg 404 2022
GENERAL DIRECTIONS:
1. Answer all problem-solving type problems in a clean paper, preferably white.
2. Avoid rounding off during computations but only on final answers, up to four (4) decimal places.
3. Upload your .pdf file with complete solution at the end of the Google Form on or before March 28, 2022, 11:59 P.M. It
must be named as <Section-Last Name, F.N.-Midterms>. Example: 2201-de Guzman, M.-Midterms.pdf
I. Concept Check. Select the best answer for each item. If NONE of the choices is the correct answer, choose E.
2.This method is based on he concept of equivalent worth of all cash flows relative to some base or beginning point
in time.
A. Future worth B. Annual worth C. Present worth D. Perpetuity
3.One special variation of the PW method involves determining the PW of all revenues or expenses over an infinite
length of time. What is this method called? E.
A. Bond Value B. IRR C. Annual worth D. B-C ratio
5.Which among these pairs would provide a good market feasibility judgment on a given project?
A. B/C ratio and breakeven point
B. ERR and IRR
C. B/C ratio and payback period
D. MARR and PW method
6.If someone computes for the MARR using AW Method and AW becomes positive at a certain fixed interest ≥0
and same ≠ 0 periods, then
A. PW is always larger than FW and AW
B. PW is always larger than FW
C. AW is always smaller than PW and FW
D. AW is always larger than PW
7.Which of the following DOES NOT agree with the definition/description of B/C ratio?
A. B/C ratio can have a value less than 0, but the project is not economically feasible.
B. A B/C ratio less than 1 means that the benefits are inferior of the costs.
C. If conventional B/C ratio is less than 1, so does the modified B/C ratio.
D. If the annual costs = annual benefits, the conventional and modified B/C ratios are equal to 0.
8.A project with a smaller payback period is better than projects with higher payback period.
A. Always True
B. Always False
C. Sometimes True
D. Insufficient Data
Republic of the Philippines
BATANGAS STATE UNIVERSITY
BatStateU Alangilan
Alangilan, Batangas City
College of Engineering, Architecture and Fine Arts
https://batstate-u.edu.ph/, Tel. No. (043) 425-0139 loc. 118/2121
9.If the inflation rate is higher than the interest rate, then
A. it is no longer possible to earn any amount from an initial capital.
B. only if the inflation is within the same period where interest is less, the investor will not earn.
C. the amount invested at present time will be equal to the future amount.
D. any annual worth computed at any period n (of N total years) will not be equal to the annual worth at + 1
period.
10. You need to determine whether a project is profitable or not in a long run. Based on the data given, which of
these projects will be profitable according to engineering economy methods? E
A. n= 3 yrs., Net Value: 0
B. Accumulated (without interest) net values of the revenues, expenses and investments after 5 years is +300.
C. Accumulated (without interest) net values of the revenues, expenses and investments after 4 years is +100.
D. n = 6 yrs., Net Value: +400
II. Problem Solving (Part I). (5 pts. each). Solve each problem completely. Show you solution
1. A sales engineer claims that his pump is economically justifiable. He says that for a cost of P250,000.00, it will
have a market value of P30,000 at the end of 10 years. If the increased productivity attributable to this project
would beP38,804 per year, is he lying? Take MARR = 10%
SOLUTION
P=F(P/F,i,n)
P=30000(1+0.10)-10
P=11,566.298682885900
P = A(P/A, i, n)
P= 38804 ((1+0.1)10-1)
0.1(1+0.1)10
P=238,433.78196976500
Since PW(i=MARR) ≥0, the pump is economically justifiable, therefore the engineer was not lying
Republic of the Philippines
BATANGAS STATE UNIVERSITY
BatStateU Alangilan
Alangilan, Batangas City
College of Engineering, Architecture and Fine Arts
https://batstate-u.edu.ph/, Tel. No. (043) 425-0139 loc. 118/2121
2.An IOU agreement was made between two persons. For a face value of P100,000, it was agreed that the borrower
will make 8 annual payments at a 10.50% interest rate. The first payment will be due at the end of the year. It
wasalso agreed that 90% of the face value will be paid for redemption. What is the bond value if it yields at a
rate of 12%?
SOLUTION
Z= 100,000
n=8
r=10.50% = 0.1050
C=0.90 x 100000 = 90000
i=12%=0.12
Vn=Php 88,509.7081
3.Calculate the capitalized cost of an equipment maintained at a rate of 6% every year for P10,000, replaced every 3
years for P25,000 at the same rate, and bought for P110,500.
SOLUTION
Cc= Cf + A + S
i (1+i)k-1
Cc = 408,045.7553
4.A new project is being planned for a study period of 8 years. It will require P250,000 for the start-up and after the
end of the first year, P13,500 shall be paid for its innovation. The board then requires to add another modified
technology which will cost P25,000 by the end of the second year. After the end of third year, the project will
startto earn P57,500 annually. Calculate the annual effective interest rate using ERR method if the interest rate
externalto this project (ε) is 13.75%.
SOLUTION
Calculate Expense
Calculate Revenue
R=629,390.4879
5.Calculate the B/C ratio (modified) of a building that houses students during their classroom discussion. The
accommodation equates to P525,000 annually. However, the annual maintenance is P135,000. Its construction
costs for about 2.3 M. If sold 20 years from its first operating year, it will amount to P250,000. Take MARR = 15%
(3pts.)
SOLUTION
=(525,000)(1-(1+0.15)-20) + (135,000)(1-(1+0.15)-20)
0.15 0.15
2,300,000 -( 250,000(1+0.15)-20))
III. Problem Solving (Part II). (50 pts). Solve each problem completely. Show you solution
Plant Design is a major requirement for you to be able to graduate BS ChE in Batangas State University. Suppose
you are a panelist, and you must evaluate if the design is feasible or not. You look at the breakdown of expenses,
possible revenues, etc. Here are some important chapters and discussions taken from a certain plant design.
Chapter 4: Products
Our company produces ear dropper solution which can be sold for PHP. 125.00 per bottle. Annually, the
company can produce 1000 pallets of the product. Each pallet is stacked with 14 layers and each layer
consists of 8 boxes. A box contains 12 bottles of ear dropper for wholesale purposes. In addition, the
company also ventures for retail services.
By-products are also produced by the company including excess chemicals that can be sold for P1,200 per
15 grams. IIVSDROP produces a total of 7,820 kg of these excess chemicals per year.
Assume a high demand for the product and by-products that all produced goods are sold each year within the study
period. Calculate the following:
1.Payback period (tabular)
2.Payback period formula
Republic of the Philippines
BATANGAS STATE UNIVERSITY
BatStateU Alangilan
Alangilan, Batangas City
College of Engineering, Architecture and Fine Arts
https://batstate-u.edu.ph/, Tel. No. (043) 425-0139 loc. 118/2121
3.B/C ratio (conventional)
4.AW if i= MARR
5.Internal Rate of Return
Based on the computed values, decide whether the project is economically justifiable or not.
CALCULATION OF REVENUE/BENEFIT
CALCULATION OF EXPENSE
CALCULATION OF INVESTMENT
INVESTMENT
Construction Cost 550,320,000
Documents and Permits 27,000,000
TOTAL 577,320,000
Republic of the Philippines
BATANGAS STATE UNIVERSITY
BatStateU Alangilan
Alangilan, Batangas City
College of Engineering, Architecture and Fine Arts
https://batstate-u.edu.ph/, Tel. No. (043) 425-0139 loc. 118/2121
PP= ₱577,320,000
₱808,600,000 - ₱24,380,800
D. AW if I=MARR
AW = E - R - CR
=₱808,600,000 -(₱24,380,800 + ₱ 1,080,593.3393075( 0.20 ))- (₱577,320,000 ( 0.20 ) )
1-(1+0.2)-30 1-(1+0.2)-30
AW=₱ 668,049,691.7000
AW = E - R - CR
Republic of the Philippines
BATANGAS STATE UNIVERSITY
BatStateU Alangilan
Alangilan, Batangas City
College of Engineering, Architecture and Fine Arts
https://batstate-u.edu.ph/, Tel. No. (043) 425-0139 loc. 118/2121
Through Calculation
i= 1.355840933
i=135.5840933 %
IRR = 135.5841%
CONCLUSION
Conventional B-C ratio = 5.7531 ≥ 0;
AW (i =MARR) = ₱ 668,049,691.7000 ≥ 0;
IRR = 135.5841% ≥ 20 %
Since conventional B-C ration is greater than 1, the annual worth if i=MARR is greater than zero, and internal
rate of return is greater than MARR, the project is economically justifiable
Prepared by:
Noted by:
Approved by: