M.SC Chemistry Inorganic Chemistry Semester-II
M.SC Chemistry Inorganic Chemistry Semester-II
M.SC Chemistry Inorganic Chemistry Semester-II
Sc Chemistry
Inorganic Chemistry
Semester-II
REFERENCE BOOKS:
1. Electronic Spectra of Transition Metal Complexes by D. Sutton
2. Introduction to Ligand Field Theory: Figgis
3. Concise Inorganic Chemistry by J. D. Lee
Tanabe Sugano Diagram
Though it is possible to add low-spin states to an Orgel Diagram, Tanabe Sugano
diagrams are commonly used instead for interpretation of spectra including both weak
and strong fields.
Tanabe Sugano diagrams are similar to Orgel diagrams in that they show how energy
levels change with Δo, but they differ in several ways:
• Ground State is taken as the abscissa and provides a constant reference point. The
other energy states are plotted relative to this.
1.
• Low spin terms i.e. states where the spin multiplicity is lower than ground state are
included.
2.
• In order to make the diagrams general for different metal ions with same electronic
configuration and to allow for different ligands energy/B is plotted against Δo/B
3.
Difference between Orgel and Tanabe-Sugano
Diagrams
d2 configuration:
3F, 3P, 1D, 1G, 1S
dxy1 dz21
T2g (F)
dyz1 dx2-y21
dzx1 dx2-y21
dxy1 dx2-y21
T1g (P)
dyz1 dz21
dzx1 dz21
1E 1T
1S g 2g (G)
1T
E/B 1g 3T1g (P) 3T2g (F)
υ2
1G 1A1g (G)
38.6
υ1 υ2
3F
Δo/B 27.5
3T1g (F)
υ2= E[3T1g(P) 3T1g(F)] υ1= E[3T2g(F) 3T1g(F)]
Ratio
υ2 =
25200 = 1.47 For First Transition:
υ1 17100 E/B=25.8
For second transition:
E/B=38.6
υ2/υ1 E[3T2g(F)]= 25.8 x B
= 25.8 x 860
2
= 22188 cm-1
1
These values of υ1 and υ2 are higher as B we are using for free V3+
Now to see how much υ1 and υ2 are
varying
First Band= Ecalculated/ E Observed
= 22188/17100
= 1.3
Second Band= 33200/25200
=1.3
We have accounted for 1.3 times higher B.
B’= B/1.3 =860/3= 662 cm-1
Δo/B’= 27.5
Δo = 27.5 x B’
=27.5 x 662 = 18192 cm-1
β = B’/ B = 662/860 = 0.77
d3 configuration
υ = 17400 cm-1, υ = 24600 cm-1, υ = 37800 cm-1
1 2 3
Find Δo, B’ and β (B for Cr3+ = 918 cm-1)
•Ratio of energies of the first two excited states 4t2g(F) and 4T1g(F)
above the gr0und state 4A2g(F) is plotted against Δo/B
υ (cm-1) ε Assignment
A 17,400 13.3 4T 4A
2g(F) 2g(F)
C 37, 800 4 4T 4A
1g(P) 2g(F)
The ratio of two energy bands A and B is 1.42. This ratio fits with Δo/B=25.0.
From figure, this corresponds to:
E (4T2g(F))= 25.0 B’…………………….(1)
E (4T1g(F))= 35.5 B’…………………….(2)
E (4T1g(P))= 55.5 B’…………………….(3)
E (4T2g(F))= 25.0 x 918
= 22950 cm-1
Δo/B’ = 25.0
E(4T1g(F))= 35.5 x 918 Δo = 25.0 x 706
=32589 cm-1 = 17653 cm-1
υ1= Ecalculated/Eobserved
= 22950/ 17400
= 1.3189
υ2= Ecalculated/Eobserved
β= B’/B
= 32589/24600 = 706/918
= 1.3247 = 0.7690
B’=B/1.3
=918/1.3
= 706 cm-1
υ1= 16500 cm-1
υ2= 24950 cm-1
υ1= 13000 cm-1
Strong Field
Weak Field
d6 configuration
5D: Ground state
1I, 1F……: Excited states
5D 5T , 5E
2g g
1I 1A , 1T , 1T , 1E , 1A
1g 1g 2g g 2g
1F 1A , 1T , 1T
2g 2g 1g
The state of highest
multiplicity for d6 is 5D and for
weak field, there is only 1 spin
allowed transition:
5T 5E
2g g
Strong Field
Weak Field S=0
(same as d1) Singly degenerate
Here G.S term is A1g