CH 6-2 Solution
CH 6-2 Solution
CH 6-2 Solution
𝑇𝑏
Prandtl numbers ranging from about 0.6 to 100 and with moderate temperature differences
More recent information by Gnielinski [45] suggests that better results for
turbulent flow in smooth tubes may be obtained from the following:
𝑇𝑏
𝑇𝑏
A power function for each of these parameters is a simple
type of relation to use, so we assume
𝑇𝑏
𝑇𝑏 𝑇𝑤
𝑇𝑏
where L is the length of the tube and d is the tube diameter. The
properties in Equation (6-6) are evaluated at the mean bulk
temperature.
Petukhov [42] has developed a more accurate, although more complicated,
expression for fully developed turbulent flow in smooth tubes:
𝑇ഥ𝑓 𝑇𝑏
𝑇𝑤
where n=0.11 for T >T , n=0.25 for T <T , and n=0 for constant heat flux or
w b w b
for gases. All properties are evaluated at T =(T +T )/2 except for μ and μ .
f w b b w
The friction factor may be obtained either from Figure 6-4 or from the
following for smooth tubes:
Hausen [4] presents the following empirical relation for fully developed
laminar flow in tubes at constant wall temperature:
𝑇𝑏
𝑇𝑏
𝑇𝑤
where the constants C and n are tabulated in Table 6-2. Properties for use with Equation (6-17) are evaluated at the film
temperature as indicated by the subscript f .
Fand [21] has shown that the heat-transfer coefficients from liquids to cylinders in
cross flow may be better represented by the relation
This relation is valid for 10−1 <Ref <105 provided excessive free-stream turbulence is
not encountered.
following relations for heat transfer from tubes in cross flow, based on the
extensive study of References 33 and 39:
For gases the Prandtl number ratio may be dropped, and fluid properties are evaluated
at the film temperature. For liquids the ratio is retained, and fluid properties are
evaluated at the free-stream temperature.
Still a more comprehensive relation is given by Churchill and
Bernstein [37] that is
applicable over the complete range of available data:
This relation underpredicts the data somewhat in the midrange of
Reynolds numbers between 20,000 and 400,000, and it is suggested
that the following be employed for this range
for 40<Re<10 , 0.65<Pr <300, and 0.25<μ /μ <5.2. All properties are valuated
5 ∞ w
Tb
Tb
Tb
Tw
Tb
Tb
∆ Tb = large Tb
Tw
6-1
Engine oil enters a 5.0-mm-diameter tube at 120◦C. The tube wall is maintained at
50◦C, and the inlet Reynolds number is 1000.
• Calculate the heat transfer, average heat-transfer coefficient, and exit oil temperature for tube
lengths of 10, 20, and 50 cm.
120◦C
d=5.0-mm
Reynolds number is 1000.
Water at an average bulk temperature of 80◦F flows inside a horizontal smooth tube with wall temperature
maintained at 180◦F. The tube length is 2 m, and diameter is 3 mm. The flow velocity is 0.04 m/s.
d=3-mm
180◦F
80◦F
Water 50◦C
0.04 m/s.
L= 2 m.
6-3
• Calculate the flow rate necessary to produce a Reynolds number of 15,000 for the flow of air at 1 atm and 300 K
in a 2.5-cm-diameter tube.
20◦C.
Water 5×10mm
60◦C
𝒌 𝒒
𝒉= . 𝑵uT = 𝑵uT . P. dT
𝑫𝑯 𝑳
6-6
Water at the rate of 3 kg/s is heated from 5 to 15◦C by passing it through a 5-cm-ID copper
tube. The tube wall temperature is maintained at 90◦C.
3 kg/s
Water 90◦C
L= ????? .
6-7
Water at the rate of 0.8 kg/s is heated from 35 to 40◦C in a 2.5-cm-diameter tube whose surface
is at 90◦C.
• How long must the tube be to accomplish this heating?
2.5-cm ID
35◦C
0.8 kg/s
90 ◦C 40◦C
Water
L= ?????
𝑅𝑒 = 𝑥. 𝑈/𝜇
𝑚ሶ
=𝑈
𝐴
6-8
Water flows through a 2.5-cm-ID pipe 1.5 m long at a rate of 1.0 kg/s. The pressure drop is 7 kPa
through the 1.5-m length. The pipe wall temperature is maintained at aconstant temperature of 50◦C by
a condensing vapor, and the inlet water temperature is 20◦C.
20◦C
2.5-cm ID
1 kg/s
50 ◦C ??◦C
7 kPa
L= 1.5 m
𝐾𝑔 2 𝑚 𝐾𝑔
= 𝑚 . . 3
𝑠 𝑠 𝑚
6-9
Water at the rate of 1.3 kg/s is to be heated from 60◦F to 100◦F in a 2.5-cm-diameter tube. The tube wall
is maintained at a constant temperature of 40◦C.
• Calculate the length of tube required for the heating process.
60◦F
2.5-cm ID
1.3 kg/s
40 ◦C 100◦F
L= ?????
𝑅𝑒 = 𝑥. 𝑈/𝜇
𝑚ሶ
=𝑈
𝐴
6-10
Water at the rate of 1 kg/s is forced through a tube with a 2.5-cm ID. The inlet water temperature is
15◦C, and the outlet water temperature is 50◦C. The tube Wall temperature is 14◦C higher than the
water temperature all along the length of the tube.
• What is the length of the tube?
Cp 15◦C
2.5-cm ID
1 kg/s
Water 14+ Tw ◦C 50◦C
L= ?????
𝑅𝑒 = 𝑥. 𝑈/𝜇
𝑚ሶ
=𝑈
𝐴
6-11
Engine oil enters a 1.25-cm-diameter tube 3 m long at a temperature of 38◦C. The tube wall temperature
is maintained at 65◦C, and the flow velocity is 30 cm/s.
• Estimate the total heat transfer to the oil and the exit temperature of the oil.
38◦C
1.25-cm
30 cm/s
Engine oil 65◦C
L= 3 m
6-12
Air at 1 atm and 15◦C flows through a long rectangular duct 7.5 cm by 15 cm. A 1.8-m section of the
duct is maintained at 120◦C, and the average air temperature at exit from this section is 65◦C.
• Calculate the airflow rate and the total heat transfer.
120◦C 7.5 cm
Air 65◦C
1.8-m
6-13
Water at the rate of 0.5 kg/s is forced through a smooth 2.5-cm-ID tube 15 m long. The inlet water
temperature is 10◦C, and the tube wall temperature is 15◦C higher than the water temperature all along
the length of the tube.
• What is the exit water temperature?
10◦C
2.5-cm
0.5 kg/s
Water 15+ Tw ◦C
L= 15 m
6-14
Water at an average temperature of 300 K flows at 0.7 kg/s in a 2.5-cm-diameter tube 6 m long. The pressure
drop is measured as 2 kPa. A constant heat flux is imposed, and the average wall temperature is 55◦C.
• Estimate the exit temperature of the water.
2 kPa
2.5-cm Tav=300 K
0.7 kg/s
Water 55 ◦C
6-15
An oil with Pr =1960, ρ=860 kg/m3, ν=1.6×10−4 m2/s, and k =0.14W/m· ◦C enters a 2.5-mm-diameter
tube 60 cm long. The oil entrance temperature is 20◦C, the mean flow velocity is 30 cm/s, and the tube wall
temperature is 120◦C.
• Calculate the heat-transfer rate.
2.5-cm
30 cm/s
oil 120 ◦C
20◦C
60 cm
6-16
Liquid ammonia flows through a 2.5-cm-diameter smooth tube 2.5 m long at a rate of 0.4 kg/s. The
ammonia enters at 10◦C and leaves at 38◦C, and a constant heat flux is imposed on the tube wall.
• Calculate the average wall temperature necessary to effect the indicated heat transfer.
2.5-cm
30 cm/s
oil 120 ◦C
20◦C
60 cm
6-17
Liquid Freon 12 (CCl2F2) flows inside a 1.25-cm-diameter tube at a velocity of 3 m/s. the heat-
transfer coefficient for a bulk temperature of 10◦C.
• Calculate How does this compare with water at the same conditions?
1.25-cm
3 m/s
Freon 12 550 ◦K
10◦C
6-18
Water at an average temperature of 10◦C flows in a 2.5-cm-diameter tube 6 m long at a rate of 0.4 kg/s.
The pressure drop is measured as 3 kPa. A constant heat flux is imposed, and the average wall
temperature is 50◦C.
• Estimate the exit temperature of the water.
2.5-cm
0.4 kg/s
water 50 ◦C
3 kPa 6m
Tav= 10◦C
6-19
Water at the rate of 0.4 kg/s is to be cooled from 71 to 32◦C.
• Which would result in less pressure drop—to run the water through a 12.5-mm-diameter pipe
at a constant temperature of 4◦C or through a constant-temperature 25-mm-diameter pipe at
20◦C?
12.5-cm
0.4 kg/s
Water 4 ◦C
T=71◦C
T=32◦C
6-20
Air at 1400 kPa enters a duct 7.5 cm in diameter and 6 m long at a rate of 0.5 kg/s The duct wall is
maintained at an average temperature of 500 K. The average air temperature in the duct is 550 K.
• Estimate the decrease in temperature of the air as it passes through the duct.
7.5-cm
0.5 kg/s
Air 550 ◦K
1400 kPa 6m
Tav=500◦K
6-103
Glycerin at 10◦C flows in a rectangular duct 1 cm by 8 cm and 1 m long. The flow rate is such
that the Reynolds number is 250.
• Estimate the average heat transfer coefficient for an isothermal wall condition.
6-104
Air at 300 K blows normal to a 6-mm heated strip maintained at 600 K. The air velocity is such
that the Reynolds number is 15,000.
• Calculate the heat loss for a 50-cm-long strip.
6-105
Sn =Sd =9 mm
V=50,000 L=50 cm d=6 mm
Air
400 K
1 atm
300 K 400 tubes
6-108
• Repeat Problem 6-107 for a tube bank with a staggered arrangement, the same
dimensions, and the same free-stream inlet velocity to the tube bank. ?
6-109
Compare the Nusselt number results for heating air in a smooth tube at 300 K and Reynolds numbers
of 50,000 and 100,000, as calculated from Equation (6-4a), (6-4b), and (6-4c).
• What do you conclude from these results?
6-110