Determining Optimal Level of Product Availability: Uday Venkatadri January 11, 2018
Determining Optimal Level of Product Availability: Uday Venkatadri January 11, 2018
Determining Optimal Level of Product Availability: Uday Venkatadri January 11, 2018
Availability
Uday Venkatadri
Then:
Cost of Understocking, Cu = r−c
Cost of Overstocking, Co = c−s
pCo = (1 − p)Cu
Cu
⇒p =
Co + Cu
IENG 4579: Supply Chain Management 4
Newsboy Example
SparesRUs, an auto parts retailer, must decided on the order size of
a model of brakes. The demand is expected to have a mean of 350
and a standard deviation of 100. The retail price of the brakes is
$250. Each brake costs $100. Unsold brakes are disposed of for $80.
How many brakes should be ordered?
Cu = $150
Co
= $20
150
⇒p = , i.e., 0.88
150 + 20
⇒ O∗ = F −1 (0.88, 350, 100), i.e., 468
Therefore:
HQ
CSL = 1 − P (X ≥ r) = 1 − DCu
For this formula to be valid, HQ should be less than equal to DCu .
Generally speaking, Q < D, and H < Cu and therefore,
HQ < DCu .
IENG 4579: Supply Chain Management 9
Postponement Example
United Colors of Benetton can either dye and knit (Option 1) or
postpone dyeing until after a garment is knitted (Option 2). The
retail price of each garment is $50. The manufacturing costs for the
two options are $20 and $22 respectively. The salvage value of each
garment is $10. Knitting takes 20 weeks. Garments are sold in four
colours, each with a mean (independent) demand of 1,000 and a
standard deviation of 500. With Option 1, Benetton makes the
buying decision for each colour 20 weeks in advance and holds
separate inventories for each colour. With Option 2, Benetton
forecasts only the aggregate uncoloured thread to purchase 20
weeks in advance. The held inventory is based on the aggregate
demand across all four colours. The quantity for individual colours
is made after the demand is known.
Benetton Example
Refer to the tab “Benetton” in the Excel file Availability.xls.
Option 1
Clearly, Cu = 30 and Co = 10.
30
Therefore, CSL = 30+10 = 0.75
The optimal ordersize is given by:
O∗ = F −1 (0.75, 1000, 500) = 1337
Expected profits are: $94,578
Option 2
28
Since Cu = 28 and Co = 12, CSL = 28+12 = 0.70
Over all colours, the mean demand is 4000 and standard deviation
p
is 1000 (= 500 ∗ (4)).
The optimal ordersize is given by:
O∗ = F −1 (0.70, 4000, 1000) = 4524
Expected profits are: $98,092