CH 12 Review Solutions PDF
CH 12 Review Solutions PDF
CH 12 Review Solutions PDF
PERIOD:
CHAPTER 12
REVIEW PROBLEMS
2A + B -> products
-
.03
.03
::
_ ~ t''l
\ - ",-,'
I -v )'1 ( '2',""1
::
,0"
---
,Ob
-----
-1( (.
~( (,!
d
')VI(
I
, .'
•
J
3)~"1
d-=-JV)
() z: /
(b) Calculate the value of the rate constant.
KA~
--k .: W
-Ol
3.0 y. {O
..:..-:----
e- I
,--"--'l
.1 - I '
I 30 s
\' -\
1..----
OVER
2. Given the following data for 15.0oC, derive the rate law expression and calculate the rate constant for the
reaction:
A + B + 3C --> products
=
. II
G .Old
- -
• oO~
.00(0
=
C1 0 I
«ATE ~ J, [A J [ 13 ] [c J
- t[cJ 1
.Ol~
:;
.0010 [RATE ~ ...k [II
o II
z:
(I. d)J(.J)
.).
:\0.38
L
mtA 01 s
-- ... -.--~
3. The following data were obtained for the reaction
'" )....
a. 7 J. '" to -1./ *(.003) (.OOI~ _
i. 3<0 ¥- (0
-l(
~< (. 0 0 IS)"' (. 00 I s) M
di')::'d.
() z: I
-~
-
I,
d.7d.'j.IO
-
1.3~ )(/0
-'-I
)L(.OO\S)Y)
*- (. OC>\ S)'"
(.0003)""
C. 00 IS) "'"
~1lE I. 3~
~<.:: -:: L·S
[0(1-) [I-) C. COIS ~s ~ )
z: \100.4 1.s 1
(c) Calculate the rate when [OCI"] = 0.0020 mol/L and [1-] = 0.0050 mol/L.
d. Determine the rate when [BF3] = 0.100 molfL and [NH3) = 0.500 mol/L.
M~ z X. [L'>t; J [~nfJJ
M.~)'
-C (,SOD ~)
t:'
( 3. l( r M~ . S ) ( .100
"'~
-- O,llO<.{
L'S
.:
lno n<\~
l' S 1'j
aA ---> bB
At a particular temperature and [A]o = 2.00 x 10-2 M, concentration vs. time data were collected for this reaction,
and a plot ofln[A] versus time resulted in a straight line with a slope value of -2.97 x 10-2 min-I.
a. Determine the rate law, the integrated rate law, and the value of the rate constant for this reaction.
RATE ~ ~ l'-'J
= - ~t + & [A J 1)
.: - k
-;J
c:: a1Afl ;> d. q 7 X 10 J'YIifl-/
= n -c;l • -/
~. "1 ") 'I. 10 1I((lt
c. How much time is required for the concentration of A to decrease to 2.50 x 10-3 M?
OVER
6. The reaction
A--+B+C
is known to be zero order in A and to have a rate constant of 5.0 x 10-2 mol/L s at 25.0aC. An experiment was run at
25.0aC where [A], = 1.0 x 10-3 M.
(_ S.OO 'j. /0
-~ ~ M)
L.s
~T-I ( /.0 YIO
-3 M.~)
L
t.L2- .:
-LA] 0
~.A(
.00/
z:
(do. )C.OS)
~ \0.01 s)
c. Calculate the concentration ofB after 5.0 x 10-3 s has elapsed. Mv-f
-"
lA 1 .s: - C.O 5') (.00 S) 4 . (90 1=-7. So 'f.. {O L
- I{ v-i
•••• "tJ
S ~tA. 7. So Y. 10
- 'I ~~
L o/;
R .
/l£.N>'\.{X,(;'lW
'.J-
-u ~
d.
'
-SoY (0 L V"o
~' J(J1 ~ I ~ '2 A Ai ~ 1~u-4 (/6rS_1o
l[~J .~J fJ
~"i~"
7, The first order rate constant for the radioactive decay of radium-223 is 0,0606 day". What is the half-life of
radium-223?
-[1-d.. .~q3
-- -.A<.
= '~C\~
. 0(,0 ~
= J:.t +
[~
1 :: (I.0)( 80.0 ) .,. -'-
•I
I .
~
b. 3~umm
I
.-!-
-- z:
Jd~ + [t\] 0
[t:>.J
.r, ~
= (I. b ) (30.0) of- .I
[AJ 1 VY\~
.i.. L-
z: CJ.O';}S
~ ~O \ [AJ
[~]
(a) 1f3.00 mol ofN02 is initially present in a sealed 2.00 L container at 25.00C, what is the half-life of the reaction?
J-
t .L-
2...
•••
-
At. [AJo
9
s: '-/. 7 fo X ID .3 IS 18'
(b) What concentration ofN02 remains after 115 years?
I --L-
[A) =- j(.t -t (AJo
OVER
t. 17 <f 3lf~ J& 7
CEE:-[~r-)J-:::-{)-,-~-S.)-~-~-;-.'
10. For the reaction
a. Disregarding the absence of information regarding the rate law, is the proposed mechanism consistent with
the equation for the overall reaction?
'If.5
11. The decomposition of nitrous oxide, N20, is believed to occur by a two-step mechanism:
What can you say about the relative rates of the two steps of the proposed mechanism?
S~ Ju ~ i: .i: Jh
+' ~)
~(J{A¥V' hn~~ ~ ~
13. The gas phase reaction between methane and diatomic sulfur is given by the equation:
At 550°C the rate constant for this reaction is 1.1 Llmol s and at 625°C the rate constant is 6.4 Llmol s. Using these
values, calculate E. for this reaction.
~ (~) = 5;-( I
T,
~(~) I. I
:;
OVER
14. The activation energy for the reaction
is 167 kJ/mo!. The rate constant at 302°C is 2.45 x 10-4 Limo!. What is the rate constant for this reaction at 205°C?
~(~I): ~~(~I
.i:
(
t; (:~:~1O-4) = S1.5.
.A'- ~ q
) ::
~ ( .;1., l( S'IIO-
.J( ), _'7.0~&S3J.3(,
= e ------
r L.
-7
d.O</XIO
were measured at five different temperatures. A plot of In(k) versus IIT produced a straight line with a slope of -
2.09 x 104 K. and a y-intercept of -0.45.
I. 7 l{ Y. fO.s Zvl = I 1 7 L{
'--
~.~
'''t'-i
---.J
j-
(b) Determine the value of the frequency factor for this reaction.
~ A.:- - 0.4.5
-0.4.5
ft.:- e
(c) Calculate the value of the rate constant at 537°C.
A c£kt~t .11
o ~
I~ L
.:AJ7lL Aafi.[ ~-D
J, I I
/JL().cX~«rtV -'0
~
LvU\QN
I •
au,;t.£I!lv.v(J
)tv. Cld~vrJ;.;',\.
~ '" Jcj ~"';'(J e. t-r-s ~.
17. What is the difference between a homogeneous and a heterogeneous catalyst?
4 hv"»ta-r't~
/tJ~vt A.J-IJA
OVER