Pre-Medical: All India Major Test Series Phase-I & II

Form No.
Student Name:
PRE-MEDICAL
MAJOR TEST-15 / 9
ALL INDIA MAJOR TEST DATE : 08-04-2020
TEST SERIES TARGET NEET (UG)-2020
Phase-I & II MEDIUM –ENGLISH &HINDI
IMPORTANT INSTRUCTIONS
Do not open this Test Booklet until you are asked to do so
SYLLABUS
Physics : Full Syllabus
Chemistry : Full Syllabus
Biology : Full Syllabus
SPACE FOR ROUGH WORK

NEET_PHYSICS All India Major Test Series(Phase-I & II)_Major Test-15/9 (08-04-2020)
PHYSICS
Q.1 If force F, velocity V and time T are taken as Q.1 ;fn cy F, osx V ,oa le; T dks ewyHkwr ek=d ekus
fundamental units then dimension of force in rks nkc esa cy dh foek;sa gksx h %
the pressure is:
(1) 3 (2) 5 (3) 6 (4) 1 (1) 3 (2) 5 (3) 6 (4) 1
Q.2 An object moves at a constant speed along a Q.2 ,d oLrq ,d fu;r pky ls {kSfrt ry XY esa] o`Ùkh;
circular path in horizontal XY plane with centre xfr dj jgh gS ] ftldk dsUnz ewy fcUnq ij gSA tc
at origin. When the object is at x = – 2m, its
oLrq x = – 2m ij gS bldk osx –(4m/s) ĵ gSA bl
velocity is –(4m/s) ĵ . What is object's
oLrq dk y = 2m ij Roj.k D;k gksxk \
acceleration when it is at y = 2m ?
(1) – (8 m/s2) ĵ (2) – (8 m/s2) î (1) – (8 m/s2) ĵ (2) – (8 m/s2) î
(3) – (4 m/s2) ĵ (4) (4 m/s2) î (3) – (4 m/s2) ĵ (4) (4 m/s2) î
Q.3 If the radius of a coil is halved and the number Q.3 ;fn fdlh dq.Myh dh f=T;k vk/kh dj nh tk;s rFkk
of turns doubled, then the magnetic field at the Qsjksa dh la[;k nksxquh dj nh tk;s] rks leku /kkjk ds
centre of the coil, for the same current will : fy;s dq.Myh ds dsUnz ij pqEcdh; {ks=%
(1) get doubled (2) get halved (1) nksxquk gks tk;sxk (2) vk/kk gks tk;sxk
(3) become 4 times (4)remains unchanged (3) pkj xquk gks tk;sxk (4) vifjofrZ r jgsxk
Q.4 In Young double slit interference experiment, the Q.4 ;ax ds f}&f>jhZ O;frdj.k ç;ksx esa ] nks L=ksrksa ds
distance between two sources is 0.1 mm. The
e/; nwjh 0.1 mm gSA L=ksrksa ls insZ dh nw jh 20 cm
distance of the screen from the sources is 20
gSA ç;ksx fd;s x;s çdk'k dh rjax&nS/;Z 5460 Å gSA
cm. Wavelength of light used is 5460 Å. Then
rc çFke vnhIr fÝUt dh dks.kh; fLFkfr gS%
the angular position of the first dark fringe is:
(1) 0.08º (2) 0.16º (3) 0.20º (4) 0.32º (1) 0.08º (2) 0.16º (3) 0.20º (4) 0.32º
Q.5 A particle is moving along a straight line with Q.5 ,d d.k c<+rh pky ls ljy js[kk ds vuqfn'k
increasing speed. Its angular momentum xfr'khy gSA bl js[kk ij fLFkr fuf'pr fcUnq ds
about a fixed point on this line:
lkis{k bldk dks.kh; laosx %
(1) Goes on increasing
(1) c<+rk jgsxk
(2) Goes on decreasing
(3) May be increasing or decreasing (2) ?kVrk jgsxk
depending on direction of motion (3) c<+uk vFkok ?kVuk xfr dh fn'kk ij fuHkZj djsxk
(4) Remains zero (4) 'kwU; jgsxk
Add. : 638, CAD Circle, Kota, Raj., India 1

Q.6 The circular scale of a micrometer has 200 Q.6 ekbØksehVj ds o`Ùkh; iSekus esa 200 Hkkx gS rFkk 2
divisions and pitch of 2 mm. Find the measure mm dk fip gSA iryh 'khV dh eksVkbZ dk ekik x;k
value of thickness of a thin sheet. eku Kkr dhft;sA
10 50 10 0 1 2 3 50
0 0 1 2 3 0
0 40 0 40
(1) 3.41 mm (2) 6.41 mm (1) 3.41 mm (2) 6.41 mm

(3) 3.46 mm (4) 3.51 mm (3) 3.46 mm (4) 3.51 mm
Q.7 Two charged particles of masses m and 2m Q.7 m rFkk 2m nzO;eku ds nks vkos f'kr d.kksa ij vkos 'k
have charges +2q and +q respectively. They Øe'k% +2q rFkk +q gS aA bUgsa ,d leku oS|qr {ks= esa
are kept in uniform electric field and allowed to j[kdj Lora= :i ls dqN le; ds fy;s xfr djus
move for some time. The ratio of their kinetic ds fy, eq Dr Nks M+ fn;k tkrk gSA budh xfrt
energies will be: ÅtkZvksa dk vuqi kr gksx k %
(1) 1 : 1 (2) 4 : 1 (3) 1 : 4 (4) 8 : 1 (1) 1 : 1 (2) 4 : 1 (3) 1 : 4 (4) 8 : 1
Q.8 A short bar magnet of magnetic moment 0.4 Q.8 pqEcdh; vk?kw. kZ 0.4 JT–1 dk ,d NksVk NM+ pqEcd
JT–1 is placed in a uniform magnetic field of 0.16 T ds ,dleku pqEcdh; {ks= esa j[kk tkrk gSA
0.16 T. The magnet is in stable equilibrium pqEcd LFkk;h lkE;koLFkk esa gksrk gS tc fLFkfrt
when the potential energy is: ÅtkZ gksrh gS%
(1) 0.064 J (1) 0.064 J
(2) – 0.064 J (2) – 0.064 J
(3) zero (3) 'kwU;
(4) – 0.082 J (4) – 0.082 J
Q.9 A satellite is moving around the earth with Q.9 ,d mixzg i`Foh ds pkjksa vksj V pky ls r f=T;k ds
speed V in circular orbit of radius r. If the o`Ùkh; d{k esa ?kwe jgk gSA ;fn d{kh; f=T;k dks 2%
orbital radius is decreased by 2%, the speed ls de dj fn;k tk, rks mixz g dh pky esa %
of the satellite will: (1) 1% dh o`f) gksxh
(1) Increase by 1%
(2) 0.5% dh o`f) gksxh
(2) Increase by 0.5%
(3) 1% dh deh gksx h
(3) Decrease by 1%
(4) 0.5% dh deh gksxh
(4) Decrease by 0.5%

Q.10 The pressure of water in a water pipe when Q.10 tc fdlh ikbi ls tqM+s gq, uy dks [kksyk rFkk can
tap is opened and closed is respectively fd;k tkrk gS rks ikbi esa Hkjs gq, ty dk nkc Øe'k%
3 × 105 N/m2 and 3.5 × 105 N/m2 .With open 3 × 105 N/m2 rFkk 3.5 × 105 N/m2 çkIr gksrk gSA uy
tap the velocity of water flowing is: dks [kksyus ij çokfgr gksus okys ty dk osx gS%
(1) 10 m/s (2) 5 m/s (1) 10 m/s (2) 5 m/s
(3) 20 m/s (4) 15 m/s (3) 20 m/s (4) 15 m/s
Q.11 A bo dy falling freely under gravity passes Q.11 Lora= :i ls fxjus okyh dksbZ oLrq] ,d nwljs ls 30
two points 30 m apart in 1s. From what m dh nwjh ij fLFkr nks fcUnqvksa dks 1s esa ikj dj ysrh
point above the upper point it began to gSA crkb;s fd Åijh fcUnq ls fdruh Åij dh Å¡pkbZ
fall? (Take g = 10 ms –2 ) ls ;g oLrq fxjuk çkjEHk djrh gS\ (g = 10 ms–2 yso)sa
(1) 31.25 m (2) 16.0 m (1) 31.25 m (2) 16.0 m
(3) 8.6 m (4) 4.0 m (3) 8.6 m (4) 4.0 m

Q.12 How much electric flux will come out through a Q.12 E  2iˆ  4ˆj  7kˆ oS|qr LFkSfrd {ks= esa j[ks i`"B
surface S = 10 ĵ kept in an electrostatic field S = 10 ĵ ls fdruk oS|qr ¶yDl ckgj vkrk gS%

E  2iˆ  4ˆj  7kˆ :
(1) 20 ek=d (2) 40 ek=d
(1) 20 units (2) 40 units
(3) 70 units (4) nearly 80 units (3) 70 ek=d (4) yxHkx 80 ek=d
Q.13 In which of the following circuit is the current Q.13 fuEu esa ls fdl ifjiFk esa] fLop S dks can djus ds
maximum just after the switch S is closed: rqjUr ckn /kkjk vf/kdre gS%
R R R R
E E E
L R L L E R L
S S S S
(i) (ii) (i) (ii)
R R
E E
R L R L
S S
(iii) (iii)
(1) (i) (2) (ii) (1) (i) (2) (ii)
(3) (iii) (4) both (ii) and (iii) (3) (iii) (4) (ii) ,oa (iii) nksuksa

Q.14 The binding energy per nucleon for a deuteron Q.14 M~;wVªksu rFkk -d.k ds fy;s çfr U;wfDyvkWu ca/ ku
and an -particle are x1 and x2 respectively.
ÅtkZ Øe'k% x1 rFkk x2 gSA vfHkfØ;k
The energy (Q) released in the reaction
2
H 12 H 24 He  Q esa eqDr gqbZ ÅtkZ (Q) gksx h %
2
1 H 12 H 24 He  Q is : 1
(1) 2(x2 – x1) (2) 2(x1 + x2) (1) 2(x2 – x1) (2) 2(x1 + x2)
(3) 4(x1 + x2) (4) 4(x2 – x1) (3) 4(x1 + x2) (4) 4(x2 – x1)
Q.15 An aeroplane of mass 3 × 104 kg and total Q.15 3 × 104 kg nzO;eku dk ok;q;ku ftuds ia[kksa dk dqy
wing area of 120 m2 is in a level flight at some {ks=Qy 120 m2 gS] dqN Å¡pkbZ ij ,d {kS frt ry esa mM+
height. The difference in pressure between the
jgk gSA mlds ia[kksa ds Åijh o fupyh lrg ds e/;
upper and lower surface of its wing in
kilopascals is (g = 10 m/s 2)
nkckUrj dk eku fdyks ikLdy esa gksxk (g = 10 m/s2)
(1) 2.5 (2) 5.0 (1) 2.5 (2) 5.0
(3) 10.0 (4) 12.5 (3) 10.0 (4) 12.5
Q.16 Rain is falling vertically with a speed of Q.16 o"kkZ dk ikuh 30 ms–1 dh pky ls Å/okZ/kj uhps dh
30 ms –1 . A wo man rides a bicycle with a vksj fxj jgk gSA ,d efgyk iwoZ ls if'pe fn'kk esa
–1
speed of 12 ms in east to west
12 ms–1 dh pky ls lkbfdy pyk jgh gSA mls
direction. She should hold her umbre lla:
viuk Nkrk j[kuk pkfg,%
 –1  2
(1) At an angle of tan   with the vertical
5 2
(1) Å/okZ/kj ls tan–1   ds dks.k ij iw oZ dh vksj
towards the east 5
2 2
(2) At an angle of tan–1   with the vertical (2) Å/okZ/kj ls tan–1   ds dks.k ij if'pe dh vksj
5 5
towards the west
5
5
(3) At an angle of tan–1   with the vertical (3) Å/okZ/kj ls tan–1   ds dks.k ij iw oZ dh vksj
2 2
towards the east 5

(4) Å/okZ/kj ls tan–1   ds dks.k ij if'pe dh vksj
5 2
(4) At an angle of tan–1   with the vertical
2
towards the west

Q.17 Two identical pendulum A and B are Q.17 ,d gh fcUnq ls nks ,d leku yksyd yVdk;s x;s
suspended from the same point. The bobs are gSA yksydksa dks bl çdkj /kukos f'kr fd;k x;k gS fd
given positive charges, with A having more A esa B ls vf/kd vkos'k gSA os nksu ksa ,d&nwljs ls nwj
charge than B. They diverge and reach at gVdj lkE;koLFkk esa bl çdkj vk tkrs gS fd
equilibrium, with A and B making angles 1 yksyd A rFkk B Å/okZ/kj ls Øe'k% 1 rFkk 2 dks.k
and 2 with the vertical respectively. Then cukrs gSA rc
(1) 1 = 2 (1) 1 = 2
(2) 1 > 2 (2) 1 > 2
(3)  1 < 2 (3)  1 < 2
(4) Tension in A is smaller than in B (4) A esa ruko B ls de gS
Q.18 An LCR series circuit with R = 100 is Q.18 R = 100 ds lkFk ,d LCR Js.kh ifjiFk dks 200
connected to a 200 V, 50 Hz a.c. source. V, 50 Hz ds çR;korhZ+ /kkjk L=ksr ls tksM+k x;k gSA
When only the capacitance is removed, the tc dsoy la/kkfj= dks gVk;k tkrk gS] rc /kkjk]
current lags the voltage by 60º. When only the foHko ls 60º i'pxkeh gks rh gSA tc dsoy çsjdRo
inductance is removed, the current leads the dks gVk;k tkrk gS rc /kkjk] foHko ls 60º vxzxkeh
voltage by 60º. The current in the circuit is: gksrh gSA ifjiFk esa /kkjk gS%
(1) 2A (2) 1A (1) 2A (2) 1A
3 2 3 2
(3) A (4) A (3) A (4) A
2 3 2 3
Q.19 When light of wavelength 300 nm falls on a Q.19 tc 300 nm rjaxnS/;Z dk çdk'k] çdk'k mRltZd ij
photoelectric emitter, photoelectrons are just fxjrk gS ] rks çdk'k bys DVªkWu dsoy ek= mRlftZr
liberated. For another emitter, light of gksrs gSA vU; çdk'k mRltZd ds fy;s 600 nm
wavelength 600 nm is just sufficient for rjaxnS/;Z dk çdk'k] çdk'k bys DVªksuks a dks mRlftZr
liberating photoelectrons. The ratio of the work djus ds fy;s i;kZ Ir gSA nks uksa mRltZdks ds dk;Z
function of the two emitters is: Qyuksa dk vuqikr gksxk %
(1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4 (1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4
Q.20 The gap between any two rails, each of length Q.20 jsy iFk ij fcNk;h x;h  yEckbZ dh nks iVfj;ksa ds
 laid on a railway track equal x at 27ºC. When chp 27ºC ij vUrjky x gSA tc rki 40ºC rd c<+
the temperature rises to 40ºC, the gap close tkrk gS ] rks vUrjky Hkj tkrk gSA iVjh ds inkFkZ dk
up. The coefficient of linear expansion of the
js[kh; çlkj xq.kkad gSA 27ºC ij iVjh dh yEckbZ
material of the rail is . The length  of a rail at
 dk eku gS %
27ºC will be
x x 2x 2x x x 2x 2x
(1) (2) (3) (4) (1) (2) (3) (4)
26 13 13 14 26 13 13 14

Q.21 A person in an elevator accelerating upwards Q.21 ,d O;fDr 2 ms–2 ds Roj.k ls Åij dh vksj tkrh
with an acceleration of 2 ms –2, tosses a coin gqbZ fy¶V esa cSBk gq vk gSA og Åij dh vksj 20 ms–
vertically upwards with a speed of 20 ms –1. 1
dh pky ls ,d flDds dks mNkyrk gSA flDdk
After how much time will the coin fall back into fdrus le; ds i'pkr~ mlds gkFk esa okil fxjsx k\
his hand? (g = 10 ms –2) (g = 10 ms–2)
5 3 10 3 5 3 10 3
(1) s (2) s (3) s (4) s (1) s (2) s (3) s (4) s
3 10 3 5 3 10 3 5
Q.22 In the circuit, shown in the figure, the effective Q.22 fp= esa fn[kk;s x;s ifjiFk esa A rFkk B ds chp çHkkoh
capacitance between A and B is: /kkfjrk gS%
4F 4F
A A
4F 2F 2F 4F 2F 2F
4F B 4F B
(1) 3 F (2) 2 F (3) 4 F (4) 8 F (1) 3 F (2) 2 F (3) 4 F (4) 8 F

Q.23 A fully charged capacitor C with initial charge q0 Q.23 çkjfEHkd vkos'k q0 okyk ,d lEiw.kZ vkosf'kr la/kkfj=
is connected to a coil of self inductances L at t = C dks t = 0 ij ,d Lo&çsj.k L okyh dq.Myh ls
0. The time at which the energy is stored equally tksM+k tkrk gSA og le;] ftl ij fo|qr ,oa
between the electric and the magnetic fields is : pqEcdh; {ks=ksa esa lafpr ÅtkZ ,d leku gS %
 
(1)  LC (2) LC (1)  LC (2) LC
4 4
(3) 2 LC (4) LC (3) 2 LC (4) LC
Q.24 Half life of substance is 20 min. Time between Q.24 inkFkZ dh v)Zvk;q 20 min gSA 33% {k; o 67% {k;
33% decay and 67% decay will be: ds e/; le;&vUrjky gks xk %
(1) 20 min (2) 40 min (3) 50 min (4) 10 min (1) 20 min (2) 40 min (3) 50 min (4) 10 min
Q.25 A uniform metallic rod rotates about its Q.25 ,d le:i /kkfRod NM+ vius yEc v)Zd ds ifjr%
perpendicular bisector with constant angular fu;r dks.kh; pky ls ?kwerh gSA bldk rki FkksM +k
speed. If it is heated uniformly to raise its c<+kus ds fy;s bldks ,d leku :i ls xeZ fd;k
temperature slightly: tkrk gS] rks %
(1) Its speed of rotation increases (1) bldh ?kw.kZu dh pky c<+ tkrh gSA
(2) Its speed of rotation decreases (2) bldh ?kw.kZu dh pky ?kV tkrh gSA
(3) Its speed of rotation remains same (3) bldh ?kw.kZu dh pky ogh jgrh gSA
(4) Its speed of rotation increases because its (4) bldh ?kw.kZu pky c<+ tkrh gS D;ksa fd bldk
moment of inertia increases tM+Ro vk?kw. kZ c<+ tkrk gS

Q.26 A constant force acting on a body of mass of 5 Q.26 5 kg nzO;eku ds fi.M ij fØ;k'khy fu;r cy 10
kg changes its speed from 5 ms –1 to 10 ms–1 lsd.M esa mldh pky dks 5 ms–1 ls 10 ms–1 dj
in 10 s without changing the direction of nsrk gSA xfr dh fn'kk vifjofrZr jgs rks fi.M ij
motion. The force acting on the body is dk;Zjr cy gksxk
(1) 1.5 N (2) 2 N (1) 1.5 N (2) 2 N
(3) 2.5 N (4) 5 N (3) 2.5 N (4) 5 N
Q.27 Voltmeter reads potential difference across Q.27 ,d iqjkuh cSVjh ds VfeZuyksa ds e/; ,d oksYVehVj
the terminals of an old battery as 1.2 volt, }kjk ekik x;k foHkokUrj 1.2 oksYV gS] tcfd
while a potentiometer reads 1.4 volt. The foHkoekih }kjk ekik x;k foHkokUrj 1.4 oksYV gSA
internal resistance of battery is 40 , then ;fn cSVjh dk vkUrfjd çfrjks/k 40 gS rks
voltmeter resistance is: oksYVehVj dk çfrjks/k gS %
(1) 120   (2) 240  (1) 120   (2) 240 
(3) 360   (4) 480  (3) 360   (4) 480 
Q.28 A fish looking up through the water sees the Q.28 ikuh ds Hkhrj dksbZ eNyh Åij dh vksj ckgjh nq fu;k
outside world, constant in a circular horizon. If dks o`rh; ijkl esa lek,sa ns[krh gSA ;fn ty dk
4
the refractive index of water is 3 and the fish viorZukad 4
gS] rFkk eNyh] ty ds i`"B ls 12 cm
3
is 12 cm below the water surface, the radius of
this circle in cm is: uhps gS ] rks o`Ùk dh lsUVhehVj esa f=T;k gS %
36 36
(1) 36 7 (2) (1) 36 7 (2)
7 7
(3) 36 5 (4) 4 5 (3) 36 5 (4) 4 5
Q.29 Two ideal diode are connected to a battery as Q.29 nks vkn'kZ Mk;ksM+ ksa dks ifjiFk esa n'kkZ;s x;s vuqlkj
shown in the circuit. The current supplied by ,d cSVjh ls tksM+k x;k gSA cS Vjh }kjk lIykbZ dh
the battery is: xbZ fo|qr /kkjk gksxh %
D1 10 D1 10
D2 20 D2 20
5V 5V
(1) 0.75 A (2) Zero (1) 0.75 A (2) 'kwU;

(3) 0.24 A (4) 0.5 A (3) 0.24 A (4) 0.5 A

Q.30 One mole of a gas mixture is heated under Q.30 ,d eksy xSl feJ.k dks fu;r nkc ij xeZ fd;k
constant pressure, and heat supplied Q is tkrk gS rFkk çnku dh x;h Å"ek Q rFkk mRiUu
plotted against temperature difference acquired. rkikUrj ds e/; vkjs[k çnf'kZ r gSA feJ.k ds fy, 
Find the approximate value of  for mixture: dk eku ¼yxHkx½ Kkr dhft,%
Q Q
2500J 2500J
100K T 100K T
4 3 7 5 4 3 7 5
(1) (2) (3) (4) (1) (2) (3) (4)
3 2 5 3 3 2 5 3
Q.31 For the given uniform square lamina ABCD Q.31 fn;s x;s ,d leku oxkZdkj pknj ABCD ds fy;s
whose centre is O, pick incorrect statement :- ftldk dsUnz O gS] vlR; dFku pqus %
F F
B C B C
E G E G
O O
A D A D
H H
(1) If part OCD is removed, COM will shift (1) ;fn Hkkx OCD dks gVk fn;k tk;s] rks nzO;eku
towards E, on line OE dsUnz OE js[kk ij E dh vksj f[kld tk;sxkA
(2) If part FHDC is removed, COM will shift (2) ;fn Hkkx FHDC dks gVk fn;k tk;s] rks nzO;eku
towards E, on line OE dsUnz OE js[kk ij E dh vksj f[kld tk;sxkA
(3) If part HOG is removed, COM will shift (3) ;fn Hkkx HOG dks gVk fn;k tk;s] rks nzO;eku
towards B, on line OB dsUnz OB js[kk ij B dh vksj f[kld tk;sxkA
(4) If part EGDA is removed, COM will shift (4) ;fn Hkkx EGDA dks gVk fn;k tk;s] rks nzO;eku
towards B, on line OB dsUnz OB js[kk ij B dh vksj f[kld tk;sxkA
Q.32 In the given circuit diagram, find the current Q.32 fn;s x;s ifjiFk fp= esa] rkj CD esa izo kfgr /kkjk
passing through wire CD (in ampere) : (,sEih;j esa) Kkr djksa :
1 2 1 2
C C
3 D 4 3 D 4
50 V 50 V
(1) 1 (2) 2 (3) 3 (4) 4 (1) 1 (2) 2 (3) 3 (4) 4

Q.33 A convex mirror of focal length 10 cm is Q.33 10 lseh Qksdl nwjh ds ,d mRry niZ.k ds eq[; v{k
shown in figure. A linear object AB = 5 cm is ds vuq fn'k ,d js[khd oLrq AB = 5 lseh dh
placed along the optical axis. Point B is at mifLFkr gSA fcUnq B niZ.k ds /kzqo ls 20 cm nwjh ij
distance 20 cm from the pole of mirror. Then
gSA AB ds izfrfcEc dh yEckbZ gksx h :
size of image of AB will be:
A B
A B C
C 20 cm
20 cm
5 10
5 10 (1) cm (2) cm
(1) cm (2) cm 14 21
14 21
10
10 (3) cm (4) 2.5 cm
(3) cm (4) 2.5 cm 14
14
Q.34 The combination of 'NAND' gates shown here Q.34 fp= esa fn[kk;s x;s 'NAND' xsVks a dk la;kst u fdl
under (figure) are equivalent to : xsV ds lerqY; gSA
A C A C
B B
C A C
A B
B
(1) An OR gate and an AND gate respectively (1) Øe'k% ,d OR xsV ,oa ,d AND xsV
(2) An AND gate and an NOT gate respectively (2) Øe'k% ,d AND xsV ,oa ,d NOT xsV
(3) An AND gate and an OR gate respectively (3) Øe'k% ,d AND xsV ,oa ,d OR xsV
(4) An OR gate and a NOT gate respectively (4) Øe'k% ,d OR xsV ,oa ,d NOT xsV
Q.35 The value of Cp – Cv = 1.00 R for a gas in state A Q.35 ;fn fdlh xSl dh voLFkk A ds fy, Cp – Cv =
and Cp – Cv = 1.06 R in another state B. If PA 1.00 R rFkk ,d vU; voLFkk B ds fy, Cp – Cv
and PB denote the pressure and TA and TB = 1.06 R gSA PA ,oa PB rFkk TA ,oa TB nks u ks a
denotes the temperature in the two states, then : voLFkkvksa ds fy, nkc ,oa rki dks n'kkZ rs gS rks %
(1) PA = PB : TA > TB (2) PA > PB : TA = TB (1) PA = PB : TA > TB (2) PA > PB : TA = TB
(3) PA < PB : TA > TB (4) PA = PB : TA < TB (3) PA < PB : TA > TB (4) PA = PB : TA < TB

Q.36 A nucleus at rest splits into two nuclear parts Q.36 ,d ukfHkd] tks fd fojke esa gS ] nks Hkkxksa esa foHkkftr
having same density and the radii in the ratio 1 gks tkrk gS ] ftuds ?kuRo leku gS rFkk f=T;kvksa dk
: 2. Their velocities are in ratio_____ vuqikr 1 : 2 gSA buds os xksa dk vuqi kr gksx k _____
(1) 2 : 1 (2) 4 : 1 (1) 2 : 1 (2) 4 : 1
(3) 6 : 1 (4) 8 : 1 (3) 6 : 1 (4) 8 : 1
Q.37 In the circuit shown, current through R2 is zero. If Q.37 n'kkZ;s x;s ifjiFk esa R2 ls izokfgr /kkjk 'kwU; gSA
R4 = 2 and R3 = 4, current through R3 will be : ;fn R4 = 2 ,oa R3 = 4gks] rks R3 ls izokfgr
10V R1 5V /kkjk gksxh :
10V R1 5V
R2
R2
15V R3 R4 15V R3 R4
(1) 1.5 A (2) 5A (1) 1.5 A (2) 5A

(3) 3.15 A (4) 3.5 A (3) 3.15 A (4) 3.5 A
Q.38 Birds is flying at 12 m height above the water Q.38 ,d iaN h ikuh dh lrg ls 12 m dh Å¡pkbZ ij
surface and fish is swimming 16 m below the mM+ rk gS rFkk eNyh ikuh dh lrg ls 16 m uhps
water surface (water = 4/3). Find distance of rS j jgh gSA (ikuh = 4/3)A iaN h dh eNyh ds
bird with respect to fish: lkis{ k nw jh gS %
(1) 28 (2) 32 (1) 28 (2) 32
(3) 26 (4) 12 (3) 26 (4) 12
1
Q.39 The amplitude of a wave represented by Q.39 foLFkkiu rjax lehdj.k y = 1 sin t ±
a b
1 1
displacement equation y = sin t ±
a b cost dk vk;ke gksxk%
cost will be ab a b
(1) (2)
ab a b ab ab
(1) (2)
ab ab
a b a b
a b a b (3) (4)
(3) (4) ab ab
ab ab

Q.40 Two bodies performing SHM have same Q.40 nks oLrq ,sa leku vk;ke o vko`fŸk ls ljy vkorZ xfr
amplitude and frequency. Their phases at a djrh gSA ,d fuf'pr {k.k ij mudh dyk
certain instant are as shown in the figure. The fp=kuqlkj gSA muds e/; dykUrj gS %
phase difference between them is  2 3 
 2 3   2 A
 
 A
 2  (–x) (+x)
(–x) (+x)
(–x) (+x)
(–x) (+x)  2 3 
 2 3   2  A
 
 2  A
 
2
2 (1)
(1) 3
3
(2) 
(2) 

 (3)
(3) 3
3
(4) buesa ls dksbZ ugha
(4) None of these
Q.41 A body falling from a height of 10 m rebounds Q.41 ,d oLrq 10 m dh Å¡pkbZ ls fxjrh gS vkSj ,d
from hard floor. It is loses 20% energy on the dBksj lrg ij Vdjkdj ykS Vrh gSA ;fn VDdj esa
impact, then coefficient of restitution is ;g 20% ÅtkZ [kks nsrh gS] rks izR;koLFkku xq.kkad dk
eku gS&
(1) 0.89 (2) 0.56
(1) 0.89 (2) 0.56
(3) 0.23 (4) 0.18
(3) 0.23 (4) 0.18
Q.42 Electron move at right angle to a magnetic Q.42 bysDVªkWu] 1.5 × 10–2 T ds pqEcdh; {ks= ds yEcor~
field of 1.5 × 10–2 T with speed of 6 × 107 m/s. 6 × 107 m/s osx ls pyrk gSA ;fn bys DVªkWu dk
If the specific charge of the electron is 1.7 × fof'k"V vkos'k 1.7 × 1011 C/kg gks ] rks o`Ÿkkdkj ekxZ
1011 C/kg. the radius of circular path will be:- dh f=T;k gksxh %
(1) 3.31 cm (1) 3.31 cm
(2) 4.31 cm (2) 4.31 cm
(3) 1.31 cm (3) 1.31 cm
(4) 2.35 cm (4) 2.35 cm

Q.43 The angular resolution of 10 cm diameter Q.43 10 cm O;kl okys ,d nwjn'khZ dh 5000Å rjaxnS/;Z
telescope at a wavelength of 5000Å is of the ds izdk'k ds fy;s dks. kh; foHksnu {kerk dh dks Vh
order of: gksxh%
(1) 10–4 rad (1) 10–4 rad
(2) 10–5 rad (2) 10–5 rad
(3) 106 rad (3) 106 rad
(4) 10–2 rad (4) 10–2 rad
Q.44 When a tuning fork of frequency 341 Hz is Q.44 ,d Lofj=] ftldh vko`fŸk 341 Hz gS ] ,d nwljs
sounded with another tuning fork, six beats per Lofj= ds lkFk N% foLian iz fr lSd.M mRiUu djrk
second are heard. When the second tuning gSA ;fn nwljs Lofj= ij FkksM+ k&lk ekse yxk fn;k
fork is loaded with wax and sounded with the tk, o iqu% igys ds lkFk dfEir fd;k tk,] rks nks
first tuning fork, the number of beats is two per
foLian iz fr lSd.M+ mRiUu gks rs gSA nwljs Lofj= dh
second. The natural frequency of the second
ewy vko` fŸk gksx h%&
tuning fork is:
(1) 334 (2) 339
(1) 334 (2) 339
(3) 343 (4) 347
(3) 343 (4) 347
Q.45 Two pendulums differ in lengths by 22 cm. Q.45 nks yksydks dh yEckbZ;ksa esa 22 cm dk vUrj gSA
They oscillate at the same place such that one nksuksa leku LFkku ij nksyu djrs gS ,oa leku le;
of them makes 15 oscillations and the other esa ,d 15 nksyu djrk gS rks nwljk 18 nksyu djrk
makes 18 oscillations during the same time. gSA yksydks dh yEckbZ;k¡ (cm esa) gS %&
The length (in cm) of the pendulums are:
(1) 72 rFkk 50
(1) 72 and 50
(2) 60 rFkk 38
(2) 60 and 38
(3) 50 rFkk 28
(3) 50 and 28
(4) 80 rFkk 58
(4) 80 and 58

NEET_BIOLOGY All India Major Test Series(Phase-I & II)_Major Test-15 / 9 (08-04-2020)
BIOLOGY
Q.46 Read the following statements and select the Q.46
fuEu dFkuks dks if<;s ,oa lgh fodYi pqfu;sA
correct option.
BIOLOGY ofxZdh dqath lkekU;rk % iz—fr esa fo”ys’k.kkRed
(a)
(a) Taxonomic keys are generally analytical gksrh gSA
in nature.
(b) jk’Vh; ouLifr vuqla/kku laLFkku us lanHkZ ds
(b) National Botanical research institute
fy, ikS/kks dks lajf{kr fd;kA
preserved plants for reference.
(c) ikS/ks dks lajf{kr djus ds fy, oxhZdj.k ds ,d
(c) Herbarium sheets are arranged according
lkoZHkkS fed :i ls Lohd`r iz. kkyh ds vuqlkj
to a universally accepted system of
classification to conserve plants. gjxsfj;e “khV dh O;oLFkk dh tkrh gSA
(d) Diptera, Insecta and Primata are orders of (d) fMIVsjk] bUlsDVk ,oa izkbesVk txr ,s fuesfy;k
kingdom animalia. ds x.k gSA

(1) a, b and c (2) d only (1) a, b ,oa c (2) dsoy d
(3) a only (4) a, c and d (3) dsoy a only (4) a, c ,ao d
Q.47 Identify true or false statement by selecting Q.47 lgh fodYi dk p;u djrs gq, lR; vFkok vlR;
the correct option. dks igpkfu;sA
(a) M.W. Beijerinek showed that viruses (a) M.W. cSatsfjusd us iz nf”kZr fd;k dh ok;jl
could be crystallised and crystal consist of fØLVyhd` r gks ldrs gS ,oa fØLVy esa vf/kd
largely proteins.
ek=k esa izksVhu gksrs gS A
(b) In general, viruses that infect plants have
(b) lkekU; rkSj ij ok;jl tks ikS/kks dks loafer
double stranded RNA.
djes gS mues Mcy LVªS.MsM RNA gksrs gS A
(c) Potato spindle tuber disease causing
(c) vkyq rdZq dUn jksx ds dkj.k okbjkWbM esa de
viroids have DNA of low molecular weight
vkf.od Hkkj dk DNA gksra gS A
(d) Symbiotic association of phycobiont and
(d) “kSokyka” k ,oa dodka ”k dk lgthoh lkgp;Z cgqr
mycobiont are very good pollution
indicators.
vPNs ladsrd gS A
(a) (b) (c) (d)
(a) (b) (c) (d)
(1) T F T T
(1) T F T T
(2) T F F T
(2) T F F T
(3) T F F T
(3) T F F T
(4) T F T F
(4) T F T F
Q.48 "The sex organs are absent but plasmogamy Q.48 "tuu vax vuq ifLFkr gksrs gS ] ysfdu IykTeksxSeh dks
is brought about by fusion of two somatic fofHkUu thuksVkbi ds nks dkf;d dksf”kdkvks ds
cells of different genotypes". It is characteric lay;u }kjk yk;k tkrk gS" ;g fdldh fo”ks’krk
feature of gS%&
(1) Ustilago (2) Truffles
(1) vfLVySxks (2) Vª¶yl
(3) Trichoderma (4) Neurospora
(3) VªkbdksMekZ (4) U;wjksLiksj k

Q.49 Trypanosoma is the member of :– Q.49 fVªis ukslksek fdldk lnL; gS :–
(1) Sporozoans (1) Liksjkstks vu
(2) Ciliated protozoans (2) i{EkkHkh iz ksVkst ksvu
(3) Flagellated protozoans (3) d”kkfHkd izksV kstks vu
(4) Amoeboid protozoans (4) vehch; izksV kstks vu
Q.50 Which are reproduce asexually and sexually Q.50 fuEu essa ls dkS ulk dks f”kdk lay;u ,oa tkbxksV fuekZ.k
by cell fusion and zygote formation ? }kjk vyS fxd ,oa ySfxd :Ik ls iztuu djrk gS \
(1) Diatoms (2) Gonyaulax (1) Mk,VEl (2) xkWfu;ksysDl
(3) Desmids (4) All of these (3) MsfLeM (4) mijksDr lHkh
Q.51 Natural classification system is based on all Q.51 fdlds vfrfjDr lHkh izkd`frd oxhZd j.k ra = ij
except. vk/kkfjr gS&
(1) Embryology & Anatomy
(1) HkzkS.khdh ,oa “kkfjjhdh
(2) Phytochemistry
(2) ikni jlk;u
(3) Ultrastructure and morphology
(3) ijklajpuk ,oa vkdkfjdh
(4) Internal structure and phylogeny
(4) vkUrfjd lajpuk ,ao tkfro`r
Q.52 Fusion between one large non-motile female Q.52 ,d cMk vpy eknk ;qXed ,oa ,d NksVs py uj
gamete and a smaller, motile male gamete is ;qXed ds chp lay;u fdles ik;k tkrk gS&
found in :
(1) Lik;ajksxk;jk ,oa ;qy ksfFkzDl
(1) Spirogyra and Ulothrix
(2) okyokWDl ,oa ;wMks jfu;k
(2) Volvox and Eudorina
(3) ¶;qdl ,oa okyokWDl
(3) Fucus and Volvox
(4) ;qMksjfu;k ,ao dkjk
(4) Eudorina and Chara
Q.53 Carrageen is used commercially as Q.53 dsjkthu dk mi;ksx gkbMªksdkWy ksbM ds :Ik esa
hydrocolloids, and belongs to algae having O;olkf;d :Ik ls fd;k tkrk gS] ,a o “kSo kyks ds
reserve food as : vUrZxr lajf{kr@lafpr Hkkstu fdlds lEcfU/kr gS&
(1) Laminarin (1) ySfeusfju
(2) Mannitol (2) esfUuVksy
(3) Floredean starch (3) ¶yksfjfM;u LVkpZ
(4) Both (1) and (2) (4) nksuks (1) ,oa (2)
Q.54 Select the odd one w.r.t. life cycle pattern. Q.54 thou pØ iz k:Ik ds lUnHkZ esa ,d fo’ke@cSesy dks
pqfu;sA
(1) Cedrus and Pinus – Diplontic
(1) flMªal ,oa ikbul – f}xqf.krd
(2) Funaria and Selaginella – Haplontic (2) ¶;wusfj;k ,oa flySftusyk – vxqf.krd
(3) Spirogyra and Polysiphonia – Haplontic (3) Lik;jksxk;jk ,oa ik¡y hlkbQksfu;k – vxqf.krd
(4) Fucus and Ficus – Diplontic (4) ¶;wdl ,oa Qkbdl – f}xq f.krd

Q.55 Hisardale is result of cross breeding between Q.55 fglkjMsy fuEu ds ladj.k dk urhtk gS
(1) Male Bikaneri ewes and female merino rams (1) uj chdkusjh ,oht vkSj eknk esfjuks jSEl
(2) Female Bikaneri ewes and male merino rams (2) eknk chdkusjh ,oht vkSj uj esfjuksa jSEl
(3) Female Jamunapari and Male merino rams
(3) eknk tequkikjh ,oht vkSj uj esfjuks jSEl
(4) Female kashmiri pashmina and female
(4) eknk d'kehjh i'kehuk vkSj uj es fjuksa jSEl
merino rams
Q.56 Read the following steps of inspiration. Q.56 fu'olu (inspiration) ds fuEu pj.kksa dks if<+;s .
(a) Increases thoracic volume (a) o{kh; xqgk dk vk;ru c<+ uk
(b) Air move into lungs (b) ok;q dk QsQMs esa tkuk
(c) Contraction in diaphragm and EICM (c) Mk;Ýke rFkk EICM esa ladqpu
(d) Increases pulmonary volume (d) Qq¶Qqlh; vk;ru dk c<+u k
(e) Lungs expand (e) QsQM+ks dk Qwyuk
(f) Decreases the intra pulmonary pressure (IPP) (f) vkUrjkQq¶Qlh; nkc (IPP) dk ?kVuk
Find out the correct sequence of these steps : bu pj.kksa dk lgh Øe NkafV;s :
(1) a, b, c, d, e, f (2) c, d, a, e, f, b (1) a, b, c, d, e, f (2) c, d, a, e, f, b
(3) c, a, e, d, f, b (4) c, e, d, a, f, b (3) c, a, e, d, f, b (4) c, e, d, a, f, b
Q.57 Volume of air inspired or expired in relaxed Q.57 foJke voLFkk esa vUr%'oflr ;k fu%'oflr ok;q dk
position is : vk;ru gks rk gSA
(1) 500 mL (2) 300 mL (1) 500 mL (2) 300 mL
(3) 150 mL (4) 115 mL (3) 150 mL (4) 115 mL
Q.58 Goblet glands are : Q.58 dy”k xza fFk;ka gksrh gSa &
(1) Unicellular exocrine glands of intestine (1) vkar fd ,ddks f”kdh; ckº; L=koh xza fFk
(2) Unicellular endocrine glands of intestine (2) vkar fd ,d dksf”kdh; va r% L=koh xza fFk
(3) Multicellul`ar exocrine glands of intestine (3) vkar fd cgqd ksf”kdh; ckº; L=koh xzafFk
(4) Multicellular endocrine glands of intestine (4) vkar fd cgqd ksf”kdh; var% L=koh xzafFk
Q.59 Exoskeleton of cockroach and other insects Q.59 dkWd jksp o vU; dhVksa dk ckº; dad ky cuk
is formed of : gks rk gS A
(1) Keratin (1) fdjsfVu
(2) Amino acids (2) ,ehuks vEy
(3) Chitinous cuticle (3) dkbVhuh miRopk
(4) Non-chitinous cuticle (4) dkbVhuhfoghu miRopk
Q.60 Autecology is the Q.60 LoikfjfLFkfrdh gSa &
(1) relation of a population to its environment
(1) tula[;k dk vius i;kZoj.k ls lEcU/k
(2) relation of an individual to its environment
(2) O;fDrxr dk vius i;kZoj.k ls lEcU/k
(3) relation of a community to its environment
(4) relation of a biome to its environment (3) leqnk; dk vius i;kZoj.k ls lEcU/k
Q.61 In 2005, for each of the 14 million people (4) thokse dk vius i;kZoj.k ls lEcU/k

present in a country, 0.028 were born and Q.61 2005 esa ns'k esa mifLFkr izR;sd 14 yk[k yksxks esa 0-
0.008 died during the year. Using 028 iSnk gq, ,oa 0-008 blh o"kZ esa ej x,A ?kkrkadh
exponential equation, the number of people lehdj.k }kjk 2015 esa mifLFkr yksxksa dh la[;k
present in 2015 is predicted as gksxh \
(1) 25 millions
(1) 25 fefy;u
(2) 17 millions
(2) 17 fefy;u
(3) 20 millions
(3) 20 fefy;u
(4) 18 millions
(4) 18 fefy;u
Q.62 If a population of 50 Paramecium present in Q.62 ;fn ,d dq.M esa 50 iSjkehf'k;e dh iztkfr ,d
a pool increases to 150 after an hour, what ?k.Vs ckn c<+dj 150 gks tkrh gSa ] rks tula[;k dh
would be the growth rate of population ? o`f) nj D;k gksxh \
(1) 50 per hour (1) 50@?k.Vk
(2) 200 per hour (2) 200@?k.Vk
(3) 5 per hour (3) 5@?k.Vk
(4) 100 per hour (4) 100@?k.Vk
Q.63 The process of accumulation of a dark Q.63 lw{ethoh; fØ;kvksa ds iz fr mPp iz frjks/ kh xgjs
coloured …A… substance called …B… that
ja x ds …A… inkFkZ ] …B… ds Loka x hdj.k ,oa
is highly is highly resistant to microbial action
vR;Ur /kheh xfr ls vi?kfVr gks us okys izØe dks
and undergoes decomposition at an
....C... dgrs gSa A
extremely slow rate is called .........C........ .
Choose the correct option for A, B, C and C. A, B, C ,oa C gsrq lgh fodYi pqfu,A
(1) A –amorphous, B – humus, C – (1) A – vukdkj, B – ãwel, C – ãelhHkou
humification
(2) A – Bksl, B – [kfut, C – [kfuthHkou
(2) A – solid, B – minerals, C – mineralisation
(3) A – ty esa foys;, B–vdkcZfud iks"kd rRo,
(3) A – water soluble, B–inorganic nutrients,
C–fu{kkyu
C – leaching
(4) A – ,Utkbeh, B – vijn~, C – vip;
(4) A – enzymatic, B – detritus, C-catabolism
Q.64 The mass of living material at a tropic level at Q.64 ,d fof'k"V le; esa] ,d iks"kd Lrj ij mifLFkr
a particular time is called thfor inkFkksZa dk Hkkj dgykrk gSa &
(1) Gross primary productivity (1) ldy izkFkfed mRikndrk
(2) Standing state (2) [kM+h voLFkk
(3) Net primary productivity (3) dqy izkFkfed mRikndrk
(4) Standing crop (4) [kM+h Qly

Q.65 Given below is a simplified model of Q.65 ,d LFkyh; ikfjfLFkfrdh rU= esa QkWLQksjl pØ dk
phosphorus cycling in a terrestrial ecosystem ljyhÑr ekWMy uhps fn;k x;k gSa] ftlesa pkj
with four blanks (A – D). Identify the blanks. fjDr LFkku (A – D) gSaA bUgsa igpkfu,A
Consumers C miHkksDrk C
D D
A A
Uptake mn~okg
Soil solution e`nk foy;u
B Run-off B izokg ¼ju vkWQ½
A B C D
A B C D
(djdV)
(1) Rock minerls Detritus Litter fall Producer (1) pV~Vkuh [kfut vijn~ mRiknd
(litter fall)
(2) Litter fall Producers Rock minerals Detritus (2) djdV mRiknd pV~V kuh [kfut vijn~
(3) Detritus Rock minerals Producer Litter fall (3) vijn~ pV~Vkuh [kfut mRiknd djdV
(4) Producers Litter fall Rock minerals Detritus (4) mRiknd djdV pV~V kuh [kfut vijn~
Q.66 Which of the following hypothesis suggests, Q.66 fuEu esa ls dkSu&lh vo/kkj.kk crkrh gSa fd
that the ecosystems are like aeroplane where ikfjrU= ok;q;ku dh Hkka fr gksrs gSa] tgka mM+ku
the flight (ecosystem functioning) may or may (ikfjrU= dh dk;kZRedrk) u"V gq , Hkkx ;k yqIr gqbZ
not be compromised depending upon which
tkfr ds vk/kkj ij izH kkfor gksxh ;k ugha gksxha \
species are being lost.
(1) xSvk vo/kkj.kk
(1) Gaia hypothesis
(2) xkWl&viotZu vo/kkj.kk
(2) Gause-exclusion hypothesis
(3) dqMqe dh vo/kkj.kk
(3) Qudum's hypothesis
(4) Rivet popper hypothesis (4) fjosV iksij vo/kkj.kk
Q.67 In which one of the following, both the pairs Q.67 fuEu esa ls dkS u&lk ;qXe lgh gSa \
have correct combination. (1) Lo LFkkus laj{k.k @ jk"Vªh; m|ku]
(1) In situ conservation / National park
cgh LFkkus laj{k.k @ okuLifrd m}kku
Ex situ conservation / Botanical garden
(2) Lo LFkkus laj{k.k @ nqzr'khyru]
(2) In situ conservation / Cryopreservation
cgh LFkkus laj{k.k @ oU;tho vH;kj.k
Ex situ conservation / Wildlife sanctuary
(3) Lo LFkkus laj{k.k @ cht cSad]
(3) In situ conservation / Seed bank
Ex situ conservation / National park cgh LFkkus laj{k.k @ jk"Vªh; m|ku
(4) In situ conservation / Tissue culture (4) Lo LFkkus laj{k.k @ Ård lao/kZu]
Ex situ conservation / Sacred groves cgh LFkkus laj{k.k @ ifo= miou

Q.68 Fill in the blanks. Q.68 fjDr LFkkuksa dh iwfrZ dhft,A
I. …A… in soil results from irrigation without I. ty ds fcuk leqfpr fudklh O;oLFkk ds flapkbZ
proper drainage of water. This affects the ds dkj.k e`nk esa …A… gksrk gSaA ;g ikniksa dks
plants and draws slats to the soil surface.
izHkkfor djrk gSa rFkk yo.kksa dks e` nk dh lrg
The salt is either deposited as a layer on
ij ys vkrk gSaA ;s yo.k ;k rks Hkwfe dh lrg
land surface or collects at …B… of plants.
II. A water logged soil has poor …C…. ij tek gks tkrk gSa ;k ikniksa dh …B… ij
III. Removal of forest areas to fulfil the need tek gks tkrk gSaA
of growing human population is called II. ty esa fueXu e` nk esa …C…[kjkc gks rk gSaA
…D…. III. c<+rh gqbZ ekuo tula[;k dh vko';drkvksa dh
IV. …E… of India has recommended 33% iwfrZ gs rq ouksa {ks= ksa dks gVkuk …D…. dgykrk
forest cover for the plains and 67% for the
gSaA
hills.
IV. Hkkjr dh …E… ds vuqlkj eSn kuksa dk 33%
Here A-E refers to :
(1) A – Soil erosion, B-Stems, C – Structure,
,oa ioZrksa dk 67% Hkkx oukPNkfnr gks uk
D – Reforestation, E – The National pkfg,A
Forest Policy 1987 ;gk¡ A ls E n”kkZrs gS :
(2) A – Water logging, B – Roots, C – (1) A – e`nk vijnu, B-LrEHk, C – lajpuk,
Aeration, D – Deforestation, E – The D – iquZuohuhdj.k, E – jk"Vªh; ou uhfr 1987
National Forest Policy 1988 (2) A – ty ØkfUr, B – ewy, C – okrk;u, D –
(3) A – Soil succession, B – Leaves, C –
ouksUewyu, E – jk"Vªh; ou uhfr 1988
Nutrients, D – Afforestation, E – The
(3) A – e`nk vijnu, B – iRrh, C – iks"kd rRo, D
National Forest Policy 1989
(4) A – Desertification, B – Fruits, C – – ouhdj.k, E – jk"Vªh; ou uhfr 1989
Minerals, D – Deforestation, E – The (4) A – e:LFkyhdj.k, B – Qy, C – [kfut rRo,
National Forest Policy 1986 D – ouksUewyu, E – jk"Vªh; ou uhfr 1986
Q.69 Which statement is correct about the Q.69 o`Ddh; ufydk ds dk;Z ds ckjs esa lgh gSaA
function of the renal tubule.
(1) DCT esa HCO–3 ds p;ukred L=o.k dh {kerk
(1) DCT is capable selective secretion of
gksrh gSaA
HCO–3
(2) gsuys ds ywi esa iqu jko'kks"k.k fØ;k lokZf/kd
(2) Reabsorption in Henle's loop is maximum gksrh gSaA
(3) PCT also helps to maintain the pH & ionic (3) PCT Hkkx HCO–3 ds vo'kks"k.k }kjk 'kkfjjhd
balance of body fluids by absorption of
rjy dh pH rFkk vk;fud larqyu dks cuk;s
HCO–3 j[kus esa lgk;d gksrk gSaA
(4) DCT part allow passage of small amount (4) esMwyjh rjy dh ijklj.krk dks cukus ds fy;s
of urea into the medullary interstitium to DCT Hkkx ;wfj;k dh dqN ek=k dk ifjogu
maintain the osmolarity. esMwyjh vUrjkyh rjy esa djrk gSaA
Q.70 Which of the following are actively secreted Q.70 fuEu esa ls fdls usÝksu dh ufydh; dksf'kdkvksa }kjk
into filtrate by tubular cells of nephron. fQYVªsV esa lfØ; :i ls L=kfor fd;k tkrk gSaA
(1) Na+, K+, Uric acid (2) K+, NH+3, H+ (1) Na+, K+, Uric acid (2) K+, NH+3, H+
+ – + + +
(3) H , HCO , K
3 (4) H , NH , C6H12O6 (3) H+, HCO–3 , K+ (4) H+, NH+, C6H12O6

Q.71 Solid ball of cell produced by repeated cleavage Q.71 ckj&ckj fonyuks a ds QyLo:i dks f'kdkvksa dh Bksl
is called : xsanuqek lajpuk dgykrh gSaA
(1) Gastrula (1) xssLVwy k
(2) Blastula
(2) CykLVqyk
(3) Morula
(3) eks:yk
(4) Neurula
(4) U;w:yk
Q.72 At the time of implantation, cells attached to Q.72 vUrZjksi.k ds le;] xHkkZ'k; vUr% Lrj ls tqM+us
endometrium of uterus are : okyh dksf'kdk,sa gSa &
(1) Inner cell mass (1) varj dks f'kdk lewg
(2) Trophoblast
(2) iks"kdksjd
(3) Epiblast
(3) bihCykLV
(4) Hypoblast
(4) gkbiksCykLV
Q.73 Adventitious root get swollen to store food is Q.73 viLFkkfud tM+sa Hkkstu ds laxzg ds fy, Qwy tkrh
found in gSa] ;s ik;h tkrh gSa
(1) Carrot (2) Radish (1) xktj esa (2) ewyh esa
(3) Turnip (4) Sweet potato
(3) 'kyte esa (4) 'kdjdUn esa
Q.74 Which of the following is matched correctly? Q.74 lqesfyr ;qXe dk p;u dhft;sA
(1) Etaerio of achenes – Mango (1) ,dhuksa dk bVhfj;ks – vke
(2) Simple dry indehiscent fruit – Ficus (2) ljy 'kq"d vLQqVu'khy Qy – Qkbdl
(3) Composite fruit – Wheat (3) laxzfFkr Qy – xsgw¡
(4) Simple dry dehiscent fruit – Pea (4) ljy 'kq"d LQqVu'khy Qy – eVj
Q.75 Youngest layer of secondary xylem is Q.75 f}rh;d tkbye dh lcls r#.k (uohu) ijr
(1) Laid just inner to the cambium ring (1) ,èkk oy; ds Bhd Hkhrj fLFkr gksrh gS
(2) Involved in conduction of water and mineral (2) ty rFkk [kfut ds laogu esa Hkkx ysr h gS
(3) Light in colour and occupies in periphery (3) gYds jax dh gksrh gS rFkk ifjèkh esa fLFkr gksrh gS
(4) More than one option is correct
(4) ,d ls vfèkd fodYi lgh gSa
Q.76 Ground tissue system Q.76 Hkj.k Ård ra=

(1) Is composed of simple permanent tissues (1) ljy LFkk;h Årdksa ls feydj laxfBr gksr k gS
(2) Forms the outermost covering of the whole (2) lEiw.kZ ikni 'kjhj ds lcls ckgjh vkoj.k dk
plant body fuekZ.k djrk gS
(3) Include general cortex, endodermis, pericycle (3)f}chti=h ruksa esa blesa lkekU;r% oYdqV]
vUrLRopk] ifjjEHk lfEefyr gksrs gSa ] ijUrq
but not the medullary rays in dicot stems
eTtk jf'e;k¡ ugha
(4) More than one option is correct
(4) ,d ls vfèkd fodYi lgh gSa

Q.77 The transverse section of a typical young Q.77 ,d izk:ih r#.k f}chti=h rus dh vuqi zLFk dkV
dicot stem shows n'kkZ rh gS
(1) Few layered sclerenchymatous (1) ;kaf=d lkeF;Z iznku djus okyh dqN ijrksa
hypodermis providing mechanical strength
;qDr n` <+ksÙkdh; vèkLRopk
(2) Few layered parenchymatous pericycle
(2) ¶yks,e ds Åij v)Z&pUnzkdkj pdrksa ds :i esa
above the phloem in the form of semi-lunar
dqN ijrksa ;qDr e`nwÙkdh; ifjjEHk
patches
(3) vUr%vkfnnk:d tkbye ;qDr la;qDr] oèkhZ
(3) Conjoint, open vascular bundles with
endarch xylem laogu iwy
(4) Large number of elongated (4) vUrjk dksf'kdh; vodk'kksa ;qDr nh?khZÑ r LFkwy
collenchymatous cells with intercellular dks.kksÙkdh; dksf'kdkvksa dh cM+h la[;k] tks

spaces that constitute the central pith dsUnzh; eTtk la? kfVr djrh gS
Q.78 Odd sepal in fabaceae family is : Q.78 Qscslh dqy esa fo"ke ckg~;ny gksrk gS &
(1) Posterior (2) Anterior
(1) i'p (2) vxz
(3) Lateral (4) None
(3) ik'ohZ; (4) dksbZ ugha
Q.79 Which of the following secretion of alimentary Q.79 fuEu esa ls dkSulk vkgkj uky dk L=ko.k jDr esa
canal is present in blood? mifLFkr gksrk gS \
(1) Trysinogen (2) Pepsinogen (1) fVªfIlukstu (2) isfIlukstu
(3) Secretin (4) Steapsin
(3) lsØsVhu (4) LVhfILku
Q.80 Defaecation Q.80 eyR;kx&

(1) Involuntary process regulated by (1) Lok;Ur raf=dk ra = }kjk fofu;fer vuSPNhd
autonomic nervous system izfØ;k gSA

(2) Involuntary process and is carried out by (2) vuSPNhd izfØ;k gS ,a o lkewfgd Øekdqapu xfr
a mass peristaltic movement }kjk fd;k tkrk gSA

(3) Voluntary process regulated by neural (3) raf=dh; ,ao gkeks Zuy fu;a=.k }kjk fofu;fer
and hormonal control ,SfPNd iz fØ;k gSA
(4) Voluntary process and is carried out by a (4) ,SfPNd izfØ;k gS ,ao lkewfgd Øekdqapu xfr
mass peristaltic movement }kjk fd;k tkrk gSA
Q.81 Which of the following diseases are spread Q.81 fuEu esa ls dkSulk jksx nwf’kr Hkkstu ,ao ikuh ds
by intake of contaminated food and water? lsou ls QSyrk gS \
a. Ascariasis b. Amoebiasis a. ,sLdsfj;kfll b. vehfc,fll
c. Ringworm d. Polio
c. fjaxokeZ d. iksfy;ks
e. Typhoid f. Dengue
e. VkbQkWbM f. MSaxw
(1) a, b & e (2) a, b, d & e
(1) a, b & e (2) a, b, d & e
(3) a, c & f (4) d & e
(3) a, c & f (4) d & e

Q.82 The following drugs have hallucinogenic Q.82 fdlds vfrfjDr] fuEu vkS’kf/k;ksa esa foHkzked xq.k
properties, except gksrs gS \
(1) LSD (2) Datura (1) LSD (2) /krwjk
(3) Amphetamines (4) Hashish (3) ,EQhVsehu (4) gf”k’k
Q.83 The location where Plasmodium reproduces Q.83 og LFkku tgk¡ IykLeksfM;e ekuo “kjhj esa vySfxd
asexually in human body is :Ik ls iztuu djrk gSA
(1) RBC (2) Liver (1) RBC (2) ;d`r
(3) Skin (4) Both (1) and (2) (3) Ropk (4) nksuks (1) ,ao (2)
Q.84 Which of the following is correct about Golgi Q.84 xkWYthdk; ds fy, dkSu lk lgh gS \
body ? (1) xkWYthdk; lajpukRed o tSo jklk;fud :i
(1) GB is structurally and biochemically ls /kzqohd` r gksrk gSA
polarized (2) xkWYthdk; dk eq[; dk;Z inkFkkZs dh is fda x gS ] tks
(2) The main function of GB is packing of
varZdksf'kdh; mnns '; rd igqapkrs gS ;k ckgj
materials to be delivered to the
([kq jnjh varizZ nO;h tkfydk ;k fpduh va rizZnO;h
intracellular targets or secreted outside
(produced by RER or SER of both) tkfydk ;k nks uksa }kjk fufeZr) mRlftZ r dj ns rs gS A
(3) The products that travel through GB are (3) xkWYthdk; }kjk xfr'khy mRikn la'kks f/kr gks tkrs gS
usually modified as they move from one ;s ,d flLVuhZ ls vU; flLVuhZ rd xfr djrs gSA
cisternae to another cisternae (4) mijksDr lHkh
(4) All of these
Q.85 Q.85
Which one is correct ? dkSu lk dFku lgh gS \

A B C D A B C D
(1) Telocentric Acrocentric Submetacentric Metacentric (1) vardSUnzh vxzfcUnq mie/;dsUnzh e/;dsUnzh
chromosome Chromosome Chromosome chromosome
xq.klw= xq.klw= xq.klw= xq.klw=
(2) Acrocentric Telocentric Metacentric Submetacentric (2) vxzfcUnq vardSUnzh e/;dsUnzh mie/;dsUnzh
chromosome chromosome chromosome Chromosome
(3) Submetacentric Metacentric Telocentric Acrocentric (3) mie/;dsUnzh e/;dsUnzh vardSUnzh vxzfcUnq
Chromosome chromosome chromosome chromosome
(4) Metacentric Submetacentric Acrocentric Telocentric xq.klw= xq.klw= xq.klw= xq.klw=
chromosome Chromosome chromosome chromosome (4) e/;dsUnzh mie/;dsUnzh vxzfcUnq vardSUnzh
Q.86 Important site for formation of glycoproteins Q.86 Xykbdksiz ksVhu o Xykbdks fyfiM ds fuekZ.k ds fy,
and glycolipids is egRoiw.kZ LFky gS
(1) Iysosome (2) vacuole (1) ykblkslkse (2) fjfDrdk
(3) golgi apparatus (4) plastid
(3) xkWYth midj.k (4) yod

Q.87 A -pleated sheet organization in a Q.87 ,d ikWfyisIVkbM J`a[kyk esa -IyhVsM 'khV laxBu
polypeptide chain is an example of mnkgj.k gS
(1) 1° structure (2) 2° structure (1) 1° lajpuk dk (2) 2° lajpuk dk
(3) 3° structure (4) 4° structure
(3) 3° lajpuk dk (4) 4° lajpuk dk
Q.88 Label the structure indicated by lines (i), (ii), Q.88 js[kk (i), (ii), (iii) o (iv) }kjk iznf'kZr lajpuk dks
(iii) and (iv). ukekafdr dhft,A
(1) (i) Chromatid, (ii) Centriole, (1) (i) ØksesfVM, (ii) lsfUVªvksy,
(iii) Centromere, (iv) Chromosome (iii) lsUVªkseh;j, (iv) xq.klw=
(2) (i) Chromosome, (ii) Centriole, (2) (i) xq.klw=, (ii) lsfUVªvksy,
(iii) Centromere, (iv) Chromatid (iii) lsUVªkseh;j, (iv) ØksesfVM
(3) (i) Chromatid, (ii) Centromere (3) (i) ØksesfVM, (ii) lsUVªkseh;j
(iii) Centriole, (iv) Chromosome (iii) lsfUVªvksy, (iv) xq.klw=

(4) (i) xq.klw=, (ii) lsUVªkseh;j,
(4) (i) Chromosome, (ii) centromere,
(iii) lsfUVªvksy, (iv) ØksesfVM
(iii) Centriole, (iv) Chromatid
Q.89 The number of chromosomes is reduced to Q.89 xq.klw= dh la[;k fdlds nkSjku vk/kh gks tkrh gS \
half during (1) lelw=h o v)Zlw=h dh ,ukQst
(1) anaphase of mitosis and meiosis (2) v)Zlw=h II
(2) meiosis II (3) v)Zlw=h I
(3) meiosis I
(4) fu"kspu
(4) fertilization
Q.90 Select the correct sequence from the Q.90 fuEu dk lgh Øe pqfu,A
following.
(1) Gametogenesis  Syngamy  Zygote  (1) ;qXedtuu  lay;u  ;qXeut  Hkzw.ktuu
Embryogenesis
(2) Gametogenesis  Syngamy  (2) ;qXedtuu  lay;u  Hkzw.ktuu  ;qXeut
Embryogenesis  Zygote
(3) Zygote  Embryogenesis  (3) ;qXeut  Hkzw.ktuu  ;qXedtuu  lay;u
Gametogenesis
(4) Syngamy  Gametogenesis
(4) lay;u  ;qXedtuu;qXeut Hkzw.ktuu
ZygoteEmbryogenesis

Q.91 The number of chromosomes in radicle is 16. Q.91 ewykadqj esa x.klw=ksa dh la[;k 16 gSA uyh dsUnzd]
What will be the number of chromosomes in izfreq[kh dksf'kdk] fu;fer dsUnzd o Hkzw. kiks"k esa
tube nucleus, antipodal cells, definitive
x.klw=ksa dh la[;k] Øe'k% D;k gksx h \
nucleus and endosperm respectively ?
(1) 8, 8, 16, 24 (2) 8, 8, 16, 16
(1) 8, 8, 16, 24 (2) 8, 8, 16, 16
(3) 16, 16, 32, 48 (4) 8, 8, 24, 48 (3) 16, 16, 32, 48 (4) 8, 8, 24, 48
Q.92 In double fertilization, total number of male Q.92 f}fu"kspu esa uj dsUnzd o eknk dsUnzd dh dqy
nuclei and total number of female nuclei la[;k gS
involved are
(1) Øe'k%] 3, 2 (2) Øe'k%] 2, 3
(1) 3, 2 respectively (2) 2, 3 respectively
(3) 2, 2 respectively (4) 3, 1 respectively (3) Øe'k%] 2, 2 (4) Øe'k%] 3, 1
Q.93 The minimum length of cistron in base pair, Q.93 {kkj ;qXe esa flLVªkWu dh de ls de yEckbZ tks fd
which synthesis a polypeptide of 50 amino ,d 50 vfeuks vEyksa ds ikWyhisIVkbM dk la”ys’k.k
acids is : djrh gS] fdruh gksxh&
(1) 50 bp (2) 100 bp (1) 50 bp (2) 100 bp
(3) 150 bp (4) 200 bp (3) 150 bp (4) 200 bp
Q.94 Find the sequence of binding of the following Q.94 {kkj vuqØe 3'-TACATGGGTGGG-5' okys
aminoacyl tRNA complexes during DNA [k.M }kjk vuqysf[kr mRNA es vuqo knu
translation to a mRNA transcribed by a DNA ds nkSjku fuEu ,sehuks,fly tRNA ladqyks ds ca/ku
segment having the base sequence 3'-
dk vuqØe Kkr djsA o.kZekyk dk lgh vuqØe
TACATGGGTGGG-5'. Choose the answer
n”kkZ rs gq, mÙkj pqusA
showing the correct order of alphabets.
(1) 1, 2, 3, 4 (2) 2, 1, 3, 4 (1) 1, 2, 3, 4 (2) 2, 1, 3, 4

(3) 1, 2, 4, 3 (4) 2, 1, 4, 3 (3) 1, 2, 4, 3 (4) 2, 1, 4, 3
Q.95 A DNA molecule of Escherichia coli is heavy Q.95 bZ- dksykbZ dk ,d DNA vuq Hkkjh gS] (N15 ls iwjk
(full labeled with N15) and is allowed to yscYM) vkSj N14 okys ek/;e esa allowed fd;k
duplicated in a medium containing N14. After x;kA ,d ih<h ds ckn nks iq=h LVªS.M v.kq j[ks xk\
one generation, the two daughter strands
molecules have :
(1) leku MsfUljh] ys fdu vius iS=d DNA ls
(1) Same density, but do not resemble their
feyku ugha j[krk gks
parent DNA
(2) fHkUu&fHkUUk MsfUlVh] ysfdu budk Øe vius
(2) Different densities from parents but their
sequence resembles with parent DNA
iS=d DNA ls feyku j[krk gks
(3) fHkUu&fHkUu MsfUlVht] ,oa vius iS=d DNA ls
(3) Different densities and also do not
resemble the parent DNA feyku ugha j[krk gks
(4) Both the strands same in density, but do (4) nksuks LVª S.M~l MsfUlVh esa leku] ys fdu vius
not resemble to their parent DNA iS=d DNA ls feyku ugha j[krs gks

Q.96 Consider the following statements. Q.95 fuEufyf[kr dFkuksa dks if<, &
The genetic codes said to be degenerate and tsusfVd dksM degenerate ,oa universal dgykrk
universal, which means that :
gS] ftldk eryc gS] fd &
I. Amino acids may have more than one
I. vfeuks vEy ,d ls vf/kd dksM+ksu j[k ldrs gS
codon.
II. lHkh vfeuks ,flM~ l ,d ls vf/kd dks M ks u
II. All amino acids have more than one
codon. j[krs gS
III. Codons are common for higher and lower III. dksMksUl mPpre ,oa fuEure thoksa ds fy,
organism . lkekU; (common) gks rs gSA
IV. Codons are not found in bacteria. IV. thok.kq esa dksMksUl ugha ik;s tkrs gS
(1) I, II and III (2) I and II (1) I, II ,oa III (2) I ,oa II
(3) I, II and IV (4) I and III
(3) I, II ,ao IV (4) I ,ao III
Q.97 Match the following column. Q.97 fuEufyf[kr dkWyeksa dk feyku dhft,&
Column-I Column-II dkW ye -I dkW ye -II
A. Chargaff (1) Wilkins and Frankin A. pkjxkQ (1) fofYdUl ,oa ÝsfYdu
B. jsIyhdkWu (2) ysD Vkst dks ysuk
B. Replicon (2) Uptake of lactose
C. ijfe,t (3) hnRNA
C. Permase (3) hnRNA
D. fLIyV thu (4) jsIyhdkWu dh bdkbZ
D. Split gene (4) Unit of replication
X-ray diffraction X-ray fMQjsD 'ku
E. (5) (A + G) = (C + T) E. (5) (A + G) = (C + T)
studies LVM+ht
Codes : Codes :
A B C D E A B C D E
(1) 5 4 2 3 1 (1) 5 4 2 3 1
(2) 5 4 1 3 2 (2) 5 4 1 3 2
(3) 5 4 2 1 3 (3) 5 4 2 1 3
(4) 5 1 2 3 4 (4) 5 1 2 3 4
Q.98 In a cross between genotype Ab and ++, Q.98 ab/ab ,oa ++/++ thuksV kbi ds chp ØkWl esa 2000
1700 out of 2000 individuals were of parental esa ls 1700 O;fDr iS=d ds leku FksA A o B dh
type. The distance between A and B is : nwjh D;k gS&
(1) 35 map units (2) 45 map units (1) 35 map units (2) 45 map units
(3) 30 map units (4) 15 map units (3) 30 map units (4) 15 map units
Q.99 A monohybrid cross between two plants, one Q.99 nks ikS/kksa ds e/; ,d ,dladj.kh; ØkWl djkus ij]
having 24 cm long internodes, produces F1 ftuesa ,d 24 cm yEck b.VjukWM~l j[krk gS] F1
hybrids all having 18 cm long internodes. gkbfczM mRiUu gksrk gS] tks fd lHkh 18 cm yEck
This is a case of b.VjukWM~l j[krk gS ] ;g fdldk case gS&
(1) Recessive dominance (1) vizHkkoh izHkkfork
(2) Multiple allelism (2) eYVhiy ,yhftTe
(3)Complete dominance (3) iw.kZ izH kkfork
(4) Incomplete dominance (4) viw.kZ izHkkfork

Q.100 Parents with blood group O will have children Q.100 O jDr lewg okys iS =dksa ds cPpksa dk jDr lewg
with blood groups gksxk &

(1) A and O in ratio 1 : 4 (1) A o O, 1 : 4 vuqikr es
(2) dsoy O
(2) O only
(3) B ,oa O, 1 : 4 vuqikr esa
(3) B and O in the ratio of 1 : 4
(4) A o B leku vuqi kr esa
(4) A and B in equal ratio
Q.101 Given below is a pedigree chart of a family Q.101 uhps fn;k x;k ,d ik¡p cPpksa okyh ifjokj dk
with five children. It shows the inheritance of isfMxzh pkVZ gSA ;g eqDr earlobes ds foijhr
attached earlobes as opposed to the free la;qDr earlobs dh oa”kkxfr dks n”kkZ rk gSA
ones. The squares represent the male Squares uj O;fDr dks n”kkZ rk gS ,oa circles
individuals and circles the female individuals eknk O;fDr dks n”kkZrk gSA
Which one of the following conclusions fuEufyf[kr esa ls dkSu lk fu’d’kZ lgha gS\
drawn is correct? (1) iS=d le;qXeth vizH kkoh gSA
(1) The parent are homozygous recessive
(2) fo”kS’kdY–fyaDM
(2) The trait is Y–linked
(3) iS=d le;qXeth izHkkoh gks
(3)The parents are homozygous dominant
(4) iS=d fo’ke;qXeth gks
(4) The parent are heterozygous
Q.102 A man known to be the victim of hemophilia Q.102 ,d O;fDr tk fd gheksfQfy;k ls xzflr gS ] ,d
marries a normal woman whose father was lkekU; efgyk ls “kknh djrk gS] ftlds firk
known to be bleeder, then it may be bleeder (jDr) tkus tkrs Fks] rc ;g vis{ k dh tk
expected that
ldrh gS ] fd &
(1) all their children will be bleeders
(1) muds lHkh cPps bleeders gksaxs
(2) half of their sons will be bleeders
(2) muds vk/ks iq= bleeders gksxsa
(3) one fourth of their children will be
(3) muds 1/4th cPps bleeders gksxsa
bleeders
(4) lHkh lkekU; gksxsa
(4) all will be normal

Q.103 Match the column and select the correct Q.103 fuEu dk lgh feyku dj mfpr fodYi dks pqusa
option
Homo erects Neanderthal man Homo erects Neanderthal man

Maximum Cranial
1 Brain Size 600 cc (i) 1 efLr’d vkdkj 600 cc (i) vf/kdre dikyh; {kerk
Capacity
2 (ii) 2 Qykgkjh (ii) Ekalkgkjh

Fruit Eater Meat Eater
Fossils Recovered Fossils found in central 3 (iii)
e/; ,oa iwohZ ,f”k;k ls
3 (iii) Tkkok ls thok”e izkIr
from Java and eastern asia thok”e izkIr
izFke ckj m/oZ “kjhj
4 (iv) d`’ kh dks izkjEHk fd;k
4 Stood erect first (iv) Started agriculture fLFkrh
Q.104 Organs like wings of bats and flippers of

Q.104 vax tSls pexknM+ ds ia[k ,ao Ogsy ds f¶yilZ tks
Whale Which have same fundamental
,d leku vk/kkjHkwr lajpuk j[krs gS ] fdlds
structure, developed as a result of
QyLo:Ik fodflr gq, gSA
(1) Adaptive radiation (1) vuqdqyhfodhj.k
(2) Convergent evolution (2) vkfHklkjh mn~fodkl
(3) Divergent evolution (3) vilkjh mn~fodkl
(4) Adaption to same need. (4) leku vko”;drk ds vuqlkj vuqdy
q u
Q.105 Origin of first life on earth through Q.105 i`Foh ij vthokr thoksRiRrh }kjk iz Fke tho dh
abiogenesis was explained by mRiRrh dks fdlus foLrkj ls crk;k
(1) Louis Pasteur (1) yqbZl ik”pj
(2) Oparin and Haldane
(2) vksisfju ,oa gsYMkus
(3) Stanley Miller
(3) LVsuys feyj
(4) Special creation theory
(4) fof”k’V l`tuokn dk fl)kUr
Q.106 A specialised cardiac musculature called Q.106 ,d fo'ks"k izdkj dk ân is 'khU;kl] ___A___
___A___ which has the ability to generate dgykrk gS tks ____B____ fØ;k foHko iS nk djus
action potentials ____B____ . esa l{ke gks rs gSA
Choose the correct option to fill A & B :
lgh fodYi pqfu, %&
(1) A – Lymph node ; B – with external stimuli
(1) A –yfldk xk¡B ; B – ckg~; iz sj.kk ls
(2) A – Neural tissue ; B – without external
(2) A – raf=dh; mÙkd ; B – fcuk fdlh ckg~; izsj.kk
stimuli
ds
(3) A – Nodal tissue ; B – without internal
stimuli (3) A – uksMy mÙkd ; B – fcuk fdlh ckg~; izsj.kk
(4) A – Nodal tissue ; B – without internal ds

stimuli (4) A – uksMy mÙkd ; B – fcuk fdlh vkarfjd izsj.kk
ds

Q.107 Fill in the blanks :– Q.107 fjDr LFkkuksa dks Hkjks o lgh fodYi pqu ks :–
(I) The neural system is better organised in (I) ___A___ dk raf=dk ra= vf/kd O;ofLFkr gks rk
___A___, where a brain is present along with gS] ftlesa efLr"d vusd xqfPNdkvksa ,oa
a number of ganglia and neural tissues. raf=dh; Årdks ds lkFk fo/;eku gksrk gSA
(II) ___B___ esa raf=dh; laxBu cgqr gh ljy
(II) The neural organisation is very simple in
izdkj dk gks rk gS tks fd raf=dh; tky ds :i
___B___, which is composed of a network of
esa ik;k tkrk gS A
neurons.
(III) ___C___ esa vf/kd fodflr raf=dk ra= ik;k
(III) A more developed neural system is
tkrk gS tks dsfUnz; ra f=dk ra= rFkk ifj/kh;
found in ___C___, consists of CNS and PNS.
raf=dk ra= dk cuk gks rk gS
(1) A - Hydra B-Insects C-vertebrates (1) A -gkbMªk B-dhVksa C-d'ks:dh
(2) A- vertebrates B-Invertebrates C-Hydra (2) A- d'ks:dh B-vd'ks:dh C-gkbMª k
(3) A-Hydra B-Invertebrates C-vertebrates (3) A-gkbMª k B-vd'ks:dh C-d'ks:dh
(4) A-Insects B-Hydra C-vertebrates (4) A-dhVksa B-gkbMª k C-d'ks:dh
Q.108 Which of the following terms represent the Q.108 fuEufyf[kr esa ls dkSuls 'kCn lekurk n'kkZ rs gS ?
same or similar thing ?
(1) Leucocytes — Thrombocytes (1) Y;qdkslkbV~l — FkzksEckslkbV~l
(2) Pacemaker — Atrio ventricular node (2) islesdj — vfya n fuy; ioZ
(3) Tissue fluid — serum (3) Ård nzo — lhje
(4) Left atrio–ventricular valve – Mitral valve (4) cka;k vkfyan fuy; dikV– feVªy dikV
Q.109 Injury to medulla oblongata will not affect :- Q.109 esM~;wyk vkCWyksaxs Vk esa pksV yxus ij D;k izHkkfor
(1) Gastric secretions ugha gksx k :-

(1) TkBjh; lzko.k
(2) Respiratory rhythm
(2) 'olu y;
(3) Hormone secretions
(3) gkWeksZu lz ko.k
(4) Cardiac movements
(4) ân; xfr;k¡
Q.110 All protozoans are : Q.110 lHkh izksVkst ksvu gksrs gS&
(1) Saprophytes only (2) Parasites only (1) dsoy e`r ksithoh (2) dsoy ijthoh
(3) Predators only (4) Heterotrophs (3) dsoy ijHk{kh (4) fo’keiks’kh
Q.111 Which option is true for class amphibia : Q.111 dkSulk fodYi oxZ ,EQhfc;k ds fy, lR; gS\
(1) Sexes separate, fertilisation external, (1) uj ,oa eknk vyx&vyx] ckg~; fuospu]
oviparous and development is direct v.Mt ,oa ifjo?kZ u izR;{k gks rk gSA
(2) Sexes separate, fertilisation external, (2) uj ,oa eknk vyx&vyx] ckg~; fuospu]
oviparous and development is indirect. v.Mt ,oa ifjo?kZ u vizR;{k gksrk gSA
(3) Sexes separate, fertilisation internal, (3) uj ,oa eknk fu’kspu vkUrfjd] v.Mt ,oa
oviparous and development is indirect. ifjo/kZ u vizR;{k gksrk gSA
(4) Sexes not separate, fertilization external, (4) uj o eknk vyx&vyx ugh] fu’kspu ckg~;]
oviparous and development is indirect v.Mt ,oa ifjo/kZu vizR;{k gksrk gSA

Q.112 Non-epinephrine hormone is secreted from Q.112 fdllsukWj&,s fiusØhugkeksZu L=kforgksr kgS&
(1) Zonaglomerulosa (2) Zonafasciculata (1) tksukXykses:ykslk (2) tksukQsfldqysVk
(3) Zonareticularis (4) Medulla of Adrenal (3) tksukjsfVdq ysfjl (4) vf/ko`Dddk e/;k”k
Q.113 "Some absorb nutrients directly from host Q.113 "dqN iks’kd rRo lh/ks vius “kjhj dh lrg ds
intestine through their body surface". This ek/;e ls iks’kh vkar ls vo”kksf’kr djrs gS". ;g
statement is true for : dFku fdlds fy, lR; gSA
(1) All round worms (1) lHkh xksyd`fe
(2) All flat worms (2) lHkh piVsd`fe
(3) Flat worms & Round worms (3) piVsd`fe ,oa xksyd` fe
(4) Tapeworm (4) Qhrkd`fe
Q.114 Which one of the following characteristics is Q.114 fuEu esa ls dkSulk vfHky{k.k fuesVksMk ds fy, lgh
not correct for Nematoda ? ugh gS\
(1) Unsegmentedbody (1) v[kf.Mr “kjhj
(2) Complete digestive tract with muscular pharynx (2) iw.kZifpr iz.kkyh ds lkFk is”kh; xzluh
(3) Hermaphroditism (3) mHk;fyxark
(4) Pseudocoelomate (4) dwVnsgxqgh;
Q.115 Number of Islets of Langerhans in a normal Q.115 lkekU; ekuovXuk”k; esayS xjgSUl }hfidkvksa dh
Human pancreas ? la[;k gksrhgS&
(1) 1 to 2 lakhs (2) 1 to 2 millions
(1) 1 ls 2 yk[k (2) 1 ls 2 fefy;u
(3) 1 to 2 Billions (4) 1 to 2 Thousands
(3) 1 ls 2 fcfy;u (4) 1 ls 2 gtkj
Q.116 Identify the following figure correctly with its Q.116 fuEu fp=ksa dks muds y{k.k ,oa la?k ds lkFk lgh
characters& phylum :- :i esa esfyr fdft;sA
[A] [B] [A] [B]
[C] [D]
[C] [D]
Fig Animal Characters Phylum fp= tUrq y{k.k la?k

(1) A Sycon Nerve cells Porifera (1) A lk;du rf=dk dksf'kdk, iksfjQsjk
(2) B Aurelia Cnidocytes Ctenophora (2) B vksjsfy;k n'kadksf'kdk, VhuksQksjk
(3) C Pleurob rachia Bioluminis cence Ctenophora (3) C IywjksczSfd;k tSolnhfIr VhuksQksjk
(4) D Hirudinaria Acoelomate Platyhelminthes (4) D fg:fMusfj;k vxqgh; IyS fVgsyfeUFkht

Q.117 Most unique mammalian characteristic is the Q.117 lcls fof”k’V Lru/kkjh fo”ks ’ krk fdldh
presence of : mifLFkrh gS &
(1) Mammary gland (1) LruxzfUFk
(2) Presence of ear pinna (2) d.kZiYyo dh mifLFkfr
(3) 7 cervical vertebral (3) 7 xzhokd”ks:d
(4) Presence of muscular diaphragm (4) is”kh; Mk;kQke dh mifLFkfr
Q.118 Bttoxin protects cotton plants by killing target Q.118 Bt VkWfDlud ikl ds ikSa/kks dks y{; dhVksa }kjk
insects by – ekjdj cpkrk gSa&
(1) Formation of abnormal protein (1) vlkekU; izksVhu cukdj
(2) Midgut cell lysis and swelling (2) feMxV dh dksf'kdk dks rksM+d j vkSj lwtkdj
(3) Loss of coordination in different tissues of (3) dhV ds fofHkUu Årdksa esa leUo; dh gkfu
insects. djds
(4) All of the above (4) mijksDr lHkhA
Q.119 Indentify (A), (B) and (C) in the given table : Q.119 (A), (B) ,oa (C) dks igpkfu,A
Removal of oil rsy ds nkx dks
(A) Lipase (i) (A) ykbist (i)
staivo gVkuk
Immuno
(B) (B) (ii) izfrj{kk neudkjh
supperssive agent (B) (B) (ii)
(C) Strepto kinase (iii) (C) ,atsV
Lowering of (C) LVªiVksdkbust (iii) (C)
(D) (D) (iv)
blood cholestrol [kwu esa dksysLVsjksy
(D) (D) (iv)
dk de gksuk
(1) Cyclosponin A, clot buster, Renin (1) lkbDyksLiks fju A, FkDds ds rksMus okyk, jsfuu
(2) Statin, clot buster, cyclosponin A (2) LVsfVu, FkDds ds rksMus okyk, lkbDyks Liks fju A
(3) Cyclosponin A, clot buster, statin
(3) lkbDyksLiks fju A, FkDds ds rksMus okyk, LVsfVu
(4) Statin, cyclosponin A, clot buster
(4) LVsfVu, lkbDyksLiksfju A, FkDds ds rksMus okyk
Q.120 Golden nice has higher nutritional content of [A]. Q.120 [A]–xksYMu jkbl esa iks"kd rRo vf/kd gksr s gSa &
(1) Vitamin-A (2) Vitamin –D (1) foVkfeu-A (2) foVkfeu –D
(3) Vitamin -E (4) Vitamin -K (3) foVkfeu -E (4) foVkfeu -K
Q.121 Which of the following statements is true for Q.121 fuEu esa ls dkSulk dFku RNAi rduhd ds fy,
RNAi technology? lgh gS a \
(1) It is production of somaclonal variants in (1) Ård lao/kZu esa lks;kDyksuy ifjorZu dk
tissue culture cuukA
(2) Used for both prokaryotes and eukaryotes (2) vdSfUnzd vkSj dS fUnzd nksuksa esa dks f'kdk j{kkra=
as a cellular defence mechanism. ds :i esa dke esa fy;k tkrk gSaA
(3) When a piece of RNA that is (3) tc vuqØe esa iwjd RNA dk ,d VqdM+k ,d
complementary in sequence is used to fof'k"Vthu dh vfHkO;fDr dks jksdus ds fy,
stop expression of a specific gene. mi;ksx fd;k tkrk gSaA
(4) Both (2) and (3) (4) nksuksa (2) ,oa (3)

Q.122 The continued inbreeding : Q.122 fuajrj varxzZ g.k&
(i) Reduces productivity (i) mRiknu de djrk gSaA
(ii) Causes inbreeding depression (ii) buczhfMx volkn dk dkj.k curk gSaA
(iii) Reduces fertility (iii) moZjrk dks de djrk gSaA
(iv) Increaseshomozygosity (iv) le:irk c<+krk gSaA
(v) Decreases frequency of heterozygote's (v) fo"ke ;qXetrk dh vko`fr de djrk gSaA
(1) (i) (i), (ii) and (v) (1) (i) (i), (ii) ,oa (v)
(2) (ii) (i), (ii), (iii), (iv) and (v) (2) (ii) (i), (ii), (iii), (iv) ,oa (v)
(3) (ii), (iii) and (iv) (3) (ii), (iii) ,oa (iv)
(4) (ii) ,oa (iv)

(4) (ii) and (iv)
Q.123 Which of the following are the properties of Q.123 fuEu esa ls dkS uls VSd iksyhejst ds xq.k gSa&
enzyme taqpolymerase : (i) bl dks FkeZl ,Dos fVdl uked thok.q k ls

(i) Isolated from a bacterium known as fudkyk x;k gSaA
thermus aquaticus.
(ii) ;g ,d RNA vkfJr DNA iksyhejst
(ii) It is a RNA dependent DNA polymerase
FkeksZLVscy FkeksZQkby gSaA
thermostable thermophile.
(iii) bldks tsy oS/kqrd.k lapyu esa dke esa fy;k
(iii) It is used in the process of gel electro
tkrk gSaA
phoresis.
(iv) bls ,suhfya x esa dke fy;k tkrk gSaA
(iv) It is used in the step of annealing.
(1) (i), (ii) and (iv) (1) (i), (ii) ,oa (iv)
(2) (i), (ii) and (iii) (2) (i), (ii) ,oa (iii)
(3) (i), (ii), (iii) and (iv) (3) (i), (ii), (iii) ,oa (iv)
(4) (i) only (4) dsoy (i)
Q.124 Which of the following pairs is correctly Q.124 fuEu esa ls dkSulk ;qXe lgh :i esa essfyr gSa ?
matched ?
1. js'kse; laf/k — nks Jksf.kd v)Zk'kks ds chp
1. Fibrous joint — Between two pelvic half
Cartilagenous
2. — Skull bones 2. mikfLFke; laf/k+ — diky vfLFk;ksa ds chp
joint
3. Hinge joint — Between altas and axis 3. dCtk laf/k — ,Vyl ,oa ,fDll ds chp
Between zygopophysis
4. Gliding joint — process of the Øfed d'ks:dkvks ds
successive vertebral 4. folihZ laf/k — tk;xksiksQk;fll izo/kksZa ds
chp

Q.125 Read the following statements and select Q.125 fuEufyf[kr dFkuksa dks if<;s ,ao ml fodYi dks
option stating which ones are True (T) and pqfu;s tks lR; (T) ,oa vlR; (F) dks n”kkZrk gSa ?
which ones are False (F) . (i) V;wcsDVkseh (efgyk ulcan h) dk mÌs”; v.Ms ds
(i) Purpose of tubectomy to prevent egg
fueZ.k dks jksduk gS
formation.
(ii) tuuka eLlk nkn (âfiZl) ok;jl ds dkj.k ,d
(ii) Genital warts is a sexually transmitted
;kSu lapkfjr jksx gS
disease caused by herpes virus.
(iii) ,d vkn”kZ xHkZfujks/kd vklkuh ls miyC/k,
(iii) An ideal contraceptive should be user
friendly easily available, effective and izHkkoh ,ao iz frorhZ mi;ksxdrkZ ds vuqdw y gks uk
reversible. pkfg;s
(iv) IUDs decrease phogocytosis of sperms (iv) IUDs xHkkZ”k; esa “kqØk.kq ds Hk{kdk.kqfØ;k dks
with in uterus. de djrs gS
(i) (ii) (iii) (iv) (i) (ii) (iii) (iv)
(1) T F T F (1) T F T F
(2) F F T F (2) F F T F
(3) T T F T (3) T T F T
(4) F T T F (4) F T T F
Q.126 Reduction of NADP occurs in Q.126 fdles NADP dk vip;u gksr k gSA
(1) Oxidative photophosphorylation (1) vkWDlhdkjh izdk”k QkW LQksfjyhdj.k esa
(2) Cyclic photophosphorylation (2) pØh; izdk”k QkWLQksfjyhdj.k esa
(3) Non cyclic photophosphorylation (3) vpØh; izdk”k QkWLQksfjyhdj.k esa
(4) None (4) buesa ls dksbZ ughA
Q.127 Photorespiration involves oxidation of Q.127 izdk”k “olu esa fdldk vkWDlhdj.k lfEefyr gS&
(1) Glycolate (2) RuBP (1) XykbdksysV (2) RuBP
(3) Chlorophyll a (4) Both a and b (3) i.kZgfjr a (4) nksuks a ,oa b
Q.128 Photosynthesis can’t continue for long if Q.128 izdk”kla”ys’k.k yEcs le; rd tkjh ugh jg ldrk
duration light reaction, only cyclic gS ;fn vof/k izdk”k vfHkfØ;k gS ] dsoy pØh;
photophosphorylation takes place. This is
izdk”k QWkLQks fjyhdj.k gks rk gS ] bldk dkj.k gS &
because
(1) Only ATP is formed NADPH + H is not (1) dsoy ATP fufeZr gks rs gS NADPH + H ughA
formed (2) ;g O2 mRiUu ugh djrk gSA

(2) there is no evolution of O2 (3) ;g bys DVª kW u dh vfn”kkRed pØh; xfr gS A
(3) there is unidirectional cyclic movement
(4) izdk”k ra= 680nm ls vf/kd rjax nS/;Z ij
the electrons
(4) Photosystem stops getting excited at a mRrsftr gksuk cUn dj ns rk gSA
wavelength of light beyond 680nm

Q.129 Due to low atmospheric pressure, the rate of Q.129 fuEu ¼dkj½ ok;qe.Myh; nkc ds dkj.k] ok’iksRltZu
transpiration will dh nj &
(1) Increase (1) c<+ tk,sxh
(2) Decrease (2) ?kV tk,sxh
(5) Increase and Decrease (2) c<+ ,oa ?kV tk,sxh
(6) Remain unaffected
(3) vijforhZr jgsxhA
Q.130 When a plant is girdled (ringed) : Q.130 tc ,d ikni fxMZys M (ringed) gks rk gS rks & :
(1) The root and shoot die at the same time (1) leku le; ij tM ,ao izj ksg e`r gks tkrh gS
(2) the shoot dies first (2) igys izjks g e`r gksrh gSA
(3) the root dies first (3) igys tM+ e`r gksrh gSA
(7) neither root nor shoot will die (4) u rks tM+ ,oa u gh izjks g e` r gksxhA
Q.131 Water column in vessel/trancheids does not Q.131 fdlds dkj.k okfgdk/okfguhdh esa ty dkWye
rupture during the ascent of sap because of : jlkjks gj.k ds nkSjku ugh Vw Vrk gSA
(1) Cohesion and Adhesion (1) laltu ,ao vkaltu
(2) Lignified thick wall (2) fyfXru ;q Dr eksVh fHkfÙk
(3) Transpiration pull (3) ok’iksRltZu f[kpko
(4) weak gravitational pull (4) nqcZy xq:Roh; f[kpko
Q.132 Differentiation of shoot is controlled by: Q.132 izjksg dk foHkSnhdj.k fdlds }kjk fu;af=r gks rk gS&
(1) High auxin: cytokinnin ratio (1) mPp vkWfDlu ( lkbVksd kbfuu vuqi kr
(2) High cytokinnin : auxin ratio (2) mPp lkbVksdkbfuu : vkWDlhu vuqikr
(3) High gibberellins : auxin ratio
(3) mPp ftczSyhu ( vkWfDlu vuqi kr
(4) High gibberellins : cytokinnin ratio
(4) mPp ftczSyhu ( lkbVksdkbfuu vuqikr
Q.133 How many redox equivalents are transferred Q.133 fdrus fjMkW Dl rqY;kd LFkkukUrkfjr gksrs gS tc
when one PGAL forms 1, 3 Bis PGA in Xykbdksy kbfll esa ,d PGAL ,1, 3 Bis PGA
glycolysis? cukrk gSA
(1)Two (2) One (3) Four (4) Six
(1) nks (2) ,d (3) pkj (4) N%
Q.134 In anaerobic respiration, how many net ATP Q.134 vkok;oh; “olu esa] vkWDlhdkjh QWkLQks fjyhdj.k
are formed by oxidative phosphorylation? }kjk fdrus “kq) ATP fufeZr gksrs gS \
(1) 4 (2) 8 (3) 6 (4) 0 (1) pkj (2) vkB (3) N% (4) “kqU;
Q.135 Deficiency of mineral nutrients is not Q.135 fdlds fy, [kfut iks’kd rRoks dh U;wurk
responsible for
mÙkjnk;h ugh gS &
(1) shortening of internodes
(1) ioZ dh yEckbZ esa deh
(2) necrosis (2) usØksfll
(3) Chlorosis (3) gfjekghurk
(4) Etiolation (4) ik.Mqjrk

NEET_CHEMISTRY All India Major Test Series(Phase-I & II)_Major Test-15/9 (08-04-2020)
CHEMISTRY
Q.136 In all oxides, peroxides and superoxides, the Q.136 lHkh vkW DlkbM] ijkWDlkbM rFkk lqi jvkWDlkbM esa
oxidation state of alkali metals is : {kkj /kkrq vksa dh vkWDlhdj.k voLFkk D;k gksrh gS
(1) + 1 and – 1 (2) + 1 and + 2 (1) + 1 rFkk – 1 (2) + 1 rFkk + 2
(3) + 1 only (4) + 1, – 1 and + 2 (3) + 1 dsoy (4) + 1, – 1 rFkk + 2
Q.137 Which of the following chemical mixture is Q.137 gkWy-gsjksYV fof/k esa Al2O3 ds lkFk fuEufyf[kr esa ls
added to Al2O3 in hall herauolt process ? dkSulk jklk;fud feJ.k feyk;k tkrk gS \
(1) NaCl + CaF2 (1) NaCl + CaF2
(2) Na3AlF6 + CaCl2 (2) Na3AlF6 + CaCl2
(3) Na3AlF6 + CaF2 (3) Na3AlF6 + CaF2
(4) NaCl + CaCl2 (4) NaCl + CaCl2
Q.138 Which of the following relation is correct with Q.138 fuEufyf[kr esa ls dkS ulk laca/k lksfM;e rFkk
respect to first (I) and second (II) ionisation eSXusf”k;e ds izFke (I) rFkk f}rh; (II) vk;uu foHko
potentials of sodium and magnesium ? ds lkis{k lgh gS ?
(1) IMg = IINa (2) INa > IMg (1) IMg = IINa (2) INa > IMg
(3) IIMg > IINa (4) IINa > IIMg (3) IIMg > IINa (4) IINa > IIMg
Q.139 How many species are linear with sp Q.139 fdruh iztkfr sp ladj.k ds lkFk js[ kh; gS \
hybridization SO2, CO2, I3– , I3 , SiO2, XeF2 SO2, CO2, I3– , I3 , SiO2, XeF2
(1) 4 (2) 3 (3) 1 (4) 2 (1) 4 (2) 3 (3) 1 (4) 2
Q. 140 A metal ‘M’ forms chlorides in its + 2 and + 4 Q.140 ,d /kkrq ‘M’ bldh + 2 rFkk + 4 vkW Dlhdj.k voLFkk
oxidation states. Which of the following esa Dyks jkbMl cukrh gSA fuEu esa ls dkSulk dFku
statements about these chlorides is correct ? bu DyksjkbM~l ds fo’k; eas lgh gS ?
(1) MCl2 is more easily hydrolysed than MCl4 (1) MCl2 , MCl4 ls vf/kd ljyrk ls tyvi?kfVr
(2) MCl2 is more volatile than MCl4 gks rk gS

(3) MCl2 is more soluble in anhydrous ethanol (2) MCl2 , MCl4 ls vf/kd ok’Ik”khy gksrk gS
(3) MCl2, MCl4 ls futZyh—r ,FksukWy esa vf/kd
than MCl4
foys;”khy gksrk gS
(4) MCl2 is more ionic than MCl4
(4) MCl2 ,MCl4 ls vf/kd vk;fud gksrk gS

Q.141 Among the following, the paramagnetic Q.141 fuEufyf[kr esa ls vuqpqEcdh; ;kS fxd gS \
compound is ?
(1) Na2O2 (2) O3 (3) N2O (4) KO2
(1) Na2O2 (2) O3 (3) N2O (4) KO2
Q.142 Which among the following has smallest bond Q.142 fuEufy[kr esa ls dkS ulk lcls Nks V k ca/ k dks .k
angle ? j[krk gS ?
(1) H2S (2) NH3 (3) SO2 (4) H2O (1) H2S (2) NH3 (3) SO2 (4) H2O
Q.143 Which of the following is not true ? Q.143 fuEu esa ls dkS ulk lgh ugha gS ?
(1) Permanent hardness can be removed by (1) LFkk;h dBks jrk ty dks mckydj nwj dh tk
boiling the water ldrh gS
(2) The temporary hardness is due to the (2) vLFkk;h dBksjrk] Ca rFkk Mg ds ckbdkcksZus V~l
presence of Ca and Mg bicarbonates dh mifLFkrh ds dkj.k gksrh gS
(3) Permanent hardness is due to the presence (3) LFkk;h dBks jrk] Ca rFkk Mg ds lYQsVl]
of soluble Ca and Mg sulphates, chlorides DyksjkbMl dh mifLFkrh ds dkj.k gksrk gS
(4) Hardness of water depends on its behavior (4) ty dh dBks jrk bldh lkcqu ds izfr O;ogkj
towards soap ij fuHkZj djrh gSA
Q.144 Which is not correct ? Q.144 dkSulk lgh ugha gS ?
(1) GeCl2 is more stable than GeCl4 (1) GeCl2 , GeCl4 ls vf/kd LFkk;h gS
(2) Ge(OH)2 is amphoteric
(2) Ge(OH)2 mHk;/kehZ gS
(3) GeO2 is weakly acidic
(3) GeO2 nqCkZy vEyh; gS
(4) GeCl4 in HCl forms [GeCl6]2– ion
(4) GeCl4, HCl esa [GeCl6]2– vk;u cukrk gS
Q.145 The most stable allotropic form of sulphuris : Q.145 lY¶;wjl dk vf/kdre LFkk;h vij:Ik gS \
(1) rhombic (2) monoclinic (1) jksfEcd (2) ,durk{k
(3) plastic (4) milk of sulphur (3) IykfLVd (4) feYd vkWQ lYQj
Q.146 CIF on hydrolysis form Q.146 CIF ty vi?kVu ij cukrk gS

(1) HCl + HOF (1) HCl + HOF
(2) Cl2O + HF (2) Cl2O + HF
(3) HOCl + HF (3) HOCl + HF
(4) None of these (4) buesa ls dksbZ ugha

Q.147 What will be the charge on Fex+ if the Q.147 Fex+ ij vkos ” k D;k gks x k ;fn pqE cdh; vk?kw. kZ
magnetic moment is 24 ? 24 gS \
(1) + 2 (2) + 3 (3) Zero (4) + 4 (1) + 2 (2) + 3 (3) Zero (4) + 4
Q.148 Helium is added to oxygen used by deep sea Q.148 fgyh;e rFkk vkDlhtu dk feJ.k leqnzh xks rk[kksajksa
divers because : }kjk iz;qDr fd;k tkrk gS] D;ksa fd
(1) It is less soluble in blood than nitrogen (1) mPp nkc ij ;g jDr esa ukbVª kstu dh rq yuk esa
under high pressure de ?kqyu”khy gksrh gS
(2) It is lighter than nitrogen (2) ;g ukbVª kstu ls gYdh gksr h gS
(3) It is readily miscible with oxygen (3) ;g vkWDlhtu ds lkFk rhozrk ls ?kqyu”khy gksrh gS
(4) It is less poisonous than nitrogen (4) ;g ukbVª kstu ls de fo’kSyh gks rh gS
Q.149 Which of the following has highest molar Q.149 fuEu esa ls dkS ulk foy;u es a mPPkre eks yj
conductivity in solution ? pkydrk j[krk gS \
(1) [Pt(NH3)6]Cl4 (1) [Pt(NH3)6]Cl4
(2) [Pt(NH3)5Cl]Cl3 (2) [Pt(NH3)5Cl]Cl3
(3) [Pt(NH3)4Cl2]Cl2 (3) [Pt(NH3)4Cl2]Cl2
(4) [Pt(NH3)3Cl3]Cl (4) [Pt(NH3)3Cl3]Cl
Q.150 The value of ‘spin only’ magnetic moment for Q.150 fuEufyf[kr foU;kl esa ls ,d ds fy, dsoy pØ.k
one of the following configuration is 2.84 B.M. pqEcdh; vk?kw.kZ dk eku 2.84 gSA og gS :
The correct one is : (1) d4 (izcy {ks= fyxS.M esa )
(1) d4 (in strong field ligand)
(2) d2 (nqCkZy {ks= fyxS.M esa )
(2) d2 (in weak field ligand)
(3) d3 (nqcZy {ks= rFkk iz cy {ks= fyxS.M esa )
(3) d3 (in weak as well as in strong field ligand)
(4) d5 (izcy {ks= fyxS.M esa )
(4) d5 (in strong field ligand)
Q.151 Which of the following is correct ? Q.151 fuEu esa ls dkS ulk lgh gS ?
(1) g molecular mass = mol. mass in (1) g vkf.od nzO;eku = g esa vkf.od nzO;eku = NA
g = mass of NA molecules v.kqvksa dk nzO;eku

(2) 1 mole = N molecules = 6.023 × 1023 molecule (2) 1 eksy = N v.kq = 6.023 × 1023 v.kq
(3) mole = g molecules (3) eksy = g v.kq
(4) All of the above (4) mijksDr lHkh

Q.152 A and B are two identical vessels. A contains 15 g Q.152 A rFkk B nks leku ik= gSA 298 K rFkk 1 atm ij
of ethane at 298 K and 1 atm. The vessel B A esa 15 g ,sFksu mifLFkr gSA ik= B esas leku rki
contains 75 g gas X2 at the same temperature rFkk nkc ij 75 g xSl X2 mifLFkr gksrh gSA X2 dk
and pressure. The vapour density of X2 is : ok’i ?kuRo gksxk :
(1) 75 (2) 150 (1) 75 (2) 150
(3) 37.5 (4) 300 (3) 37.5 (4) 300
Q.153 Of the following transitions in hydrogen atom, Q.153 gkbMª kstu ijek.kq esa fuEu laØe.kksa esa dkSulk ,d
the one which gives an absorption line of U;wure vko` fÙk dh ,d vo”kks’k.k js[ kk nsrk gS :
lowest frequency is : (1) n = 1 ls n = 2
(1) n = 1 to n = 2
. (2) n = 3 ls n = 8
. (2) n = 3 to n = 8
(3) n = 2 ls n = 1
(3) n = 2 to n = 1
(4) n = 8 to n = 3 (4) n = 8 ls n = 3
Q.154 The first emission line of Balmer series for Q.154 H-Lis DVªe ds fy, ckej Js.kh dh iz Fke mRltZu js[kk
H-spectrum has the wave number equal fuEu esa ls fdlds cjkcj rjax la[;k .....…cm–1
–1
to.....…cm : j[krh gS :
9RH 7RH 9RH 7RH
(1) (2) (1) (2)
400 144 400 144
3RH 5RH 3RH 5RH
(3) (4) (3) (4)
4 36 4 36
,
Q.155 A piston filled with 0.04 mol of an ideal gas Q.155 ,d fiLVu 0.04 eksy ,d vkn”kZ xSl ls Hkjk gq vk gS
expands reversible from 50.0 mL to 375 mL at tks 37.0ºC ds fu;r rkieku ij 50.0 mL ls 375 ml
a constant temperature of 37.0ºC. As it does esa mRØe.kh; :Ik ls izlkfjr gksrk gS vksj bls gks us esa
so, it absorbs 208 J of heat. The values of q ;g 208 J Å’ek vo”kksf’kr djrk gSA izØe ds fy,
and w for the process will be : q rFkk w ds eku gksaxs :
(R = 8.314 J / mol K) (In 7.5 = 2.01) (R = 8.314 J / mol K) (In 7.5 = 2.01)
(1) q = – 208 J, w = – 208 J (1) q = – 208 J, w = – 208 J
(2) q = – 208 J, w = + 208 J (2) q = – 208 J, w = + 208 J
(3) q = + 208 J, w = + 208 J (3) q = + 208 J, w = + 208 J
(4) q = + 208 J, w = – 208 J (4) q = + 208 J, w = – 208 J

Q.156 Assuming that water vapour is an ideal gas, Q.156 ekuk dh tyok’Ik ,d vkn”kZ xSl gS] vkUrfjd ÅtkZ
the internal energy change (U) when 1 mole ifjorZ u (U) D;k gksxk tc 1 eksy ty 1 ckj nkc
of water is vaporised at 1 bar pressure and
rFkk 100ºC ij ok’ihd`r fd;k tkrk gSA (fn;k x;k
100ºC,(given : molar enthalpy of vaporization
–1
gS : 1 ckj rFkk 373 K rFkk R = 8.3 J mol–1 K–1 ij
of water 41 kJ mol at 1 bar and 373 K and
–1 –1 ty ds ok’ihdj.k dh eksyj ,UFkSYih 41 kJ mol–1 gS)
R = 8.3 J mol K ) will be :
(1) 4.100 kJ mol–1 (2) 3.7904 kJ mol–1 (1) 4.100 kJ mol–1 (2) 3.7904 kJ mol–1
(3) 37.904 kJ mol–1 (4) 41.00 kJ mol–1 (3) 37.904 kJ mol–1 (4) 41.00 kJ mol–1
Q.157 For the reaction, N2 + 3H2  2NH3 in a vessel, Q.157 ,d ik= es a N2 + 3H2  2NH3 vfHkfØ;k ds fy,
after the addition of equal number of mole of N2 rFkk H2 , ds eks y dh leku la[;k ds ;ks x ds
N2 and H2, equilibrium state is attained. Which ckn lkE; voLFkk LFkkfir gks rh gS A fuEu es a ls
of the following is correct ? dkSulk lgh gS ?
(1) [H2] = [N2] (2) [H2] < [N2] (1) [H2] = [N2] (2) [H2] < [N2]
(3) [H2] > [N2] (4) [H2] > [NH3] (3) [H2] > [N2] (4) [H2] > [NH3]
Q.158 pH of water is 7.0 at 25ºC. If water is heated to Q.158 25ºC ij ty dh pH = 7.0 gSA ;fn ty dks 70ºC
70ºC, then : rd xeZ fd;k tkrk gS, rks
(1) pH will decrease and solution becomes acidic (1) pH ?kVsxh rFkk foy;u vEyh; gks tkrk gS
(2) pH will increase and solution becomes basic (2) pH c<+sx h rFkk foy;u {kkjh; gks tkrk gS
(3) pH will remain constant as 7 (3) pH 7 dh rjg fLFkj jgsx k
(4) pH will decrease but solution will be neutral (4) pH ?kVsxh ijUrq foy;u mnklhu gksx k
, Q.159 A solution with pH 2.0 is more acidic than the Q.159 pH = 2.0 dk ,d foy;u pH = 6.0 ds ,d foy;u ls
one with pH 6.0 by a factor of : fdrus xq.kkad ls vf/kd vEyh; gksrk gSA
(1) 3 (2) 4 (1) 3 (2) 4
(3) 3,000 (4) 10,000 (3) 3,000 (4) 10,000
Q.160 Oxidation number of carbon in C3O2, Mg2C3 Q.160 C3O2, Mg2C3 eas dkcZu dh vkWDlhdj.k la[;k Øe”k%
are respectively : gS
4 4 4 4 4 4 4 4
(1) – ,  (2)  , – (1) – ,  (2)  , –
3 3 3 3 3 3 3 3
2 2 2 4 2 2 2 4
(3) – ,  (4) – ,  (3) – ,  (4) – , 
3 3 3 3 3 3 3 3

Q.161 A solid is formed and it has three types of Q.161 ,d Bksl fuehZr gksr k gS rFkk blesa rhu izdkj ds
atoms X, Y and Z, X forms a fcc lattice, Y ijek.kq X, Y rFkk Z gksrs gS, X ,d fcc tkyd cukrk
atoms occupying all tetrahedral voids and Z gS] Y ijek.kq lHkh prq’dQydh; fjDrh;ksa dks xzg.k
atoms occupying half of octahedral voids. The djrs gS rFkk Z ijek.kq vk/kh v’VQydh; fjDrh;ksa
formula of solid is : dks xzg.k djrs gSA Bksl dk lw= gksxk
(1) X4YZ2 (2) X4Y2Z (1) X4YZ2 (2) X4Y2Z
(3) XY2Z4 (4) X2Y4Z (3) XY2Z4 (4) X2Y4Z
Q.162 According to Freundlich adsorption isotherm, Q.162 ÝsaMyhp vf/k”kks’k.k lerkih ds vuql kj] fuEu esa ls
which of the following is correct ? dkSulk lgh gS \
x x
(1)  p1 (1)  p1
m m
x x
(2)  p1/n (2)  p1/n
m m
x x
(3)  p0 (3)  p0
m m
(4) All the above are correct for different (4) mijks Dr lHkh nkc dh fHkUu ijklksa ds fy,
ranges of pressure lgh gS
Q.163 The rate constant for the reaction ; Q.163 vfHkfØ;k 2N2O5 4NO2 + O2 ds fy, nj
2N2O5 4NO2 + O2 is 3.0 × 10–5 sec–1. If fLFkjkad 3.0 × 10–5 sec–1 gSA ;fn nj 2.40 × 10–5
–5 –1
the rate is 2.40 × 10 M sec , then the
concentration of N2O5 (in M) is : Msec–1 gS] rks (M esa) N2O5 dh lkUnz rk gksx h
(1) 1.4 (2) 1.2 (3) 0.04 (4) 0.8 (1) 1.4 (2) 1.2 (3) 0.04 (4) 0.8
Q.164 The amount of silver deposited on passing 2.0 Q.164 AgNO3 ds ,d tyh; foy;u ls 2.0 QsjkMs vkos”k
faraday of charge through an aqueous solution xqtkjus ij fu{ksfir flYoj dh ek=k gksx h
of AgNO3is :
(1) 54 g (2) 108 g (3) 216 g (4) 324 g (1) 54 g (2) 108 g (3) 216 g (4) 324 g
Q.165 18 g glucose (C6H12O6) is added to 178.2 g Q.165 18 g Xyqdksl (C6H12O6) dks 178.2 g ty esa
water. The vapour pressure of water for this feyk;k tkrk gSA 100°C ij bl tyh; foy;u ds
aqueous solution at 100ºC is : fy, ty dk ok’Ik nkc gksxk
(1) 759 torr (2) 7.60 torr (1) 759 torr (2) 7.60 torr
(3) 76.0 torr (4) 752.40 torr (3) 76.0 torr (4) 752.40 torr

Q.166 The total number of isomers for C4H8 is : Q.166 C4H8 ds leko;oh;ksa dh dqy la[;k gS :
(1) 5 (2) 6 (3) 7 (4) 8 (1) 5 (2) 6 (3) 7 (4) 8
Q.167 The IUPAC name of the compound : Q.167 fuEu ;kS fxd dk IUPAC uke gks xk :
CH2 – CH – COOH CH2 – CH – COOH
OH NH2 is: OH NH2
(1) 2-Amino-3-hydroxypropanoic acid (1) 2-,ehuks-3-gkbMªkWDlhiz ksisu kWbd vEYk
(2) 1-Hydroxy-2-aminopropan-3-oic acid (2) 1-gkbMªkWDlh-2-,ehuksiz ksisu-3-vkWbd vEy
(3) 1-Amino-2-hydroxypropanoic acid (3) 1-,ehuks-2-gkbMªkWDlhiz ksisu kWbd vEYk
(4) 3-Hydroxy-2-aminopropanoic acid (4) 3- gkbMªkWDlh-2-,ehuks izksis ukWbd vEy
Q.168 The most unlikely representation of resonace Q.168 p-ukbVªksfQukW DlkbM vk;u dh lokZ f/kd vlaHko
structures of p-nitrophenoxide ion is : vuquknh lajpuk gS :
– – – – – –
O + O O + O O + O O + O
N N N N
(1) (2) (1) (2)
O– O O– O
– –
O O O O O O O O
+ + + +
N N N N
(3) (4) (3) (4)

 
– –
O O O O
Q.169 In the reaction, Q.169 vfHkfØ;k esa,

 i X
CH3–CC–CH3 
ii H2O/ Zn CH3–C–C–CH3  i X
CH3–CC–CH3  CH3–C–C–CH3
ii H2O/ Zn
O O O O
X is : X gS :
(1) HNO3 (2) O2 (1) HNO3 (2) O2
(3) O3 (4) KMnO4 (3) O3 (4) KMnO4

Q.170 An SN2 reaction at an asymmetric carbon of a Q.170 ,d ;kSfxd ds vlfEer dkcZ u ij S N2 vfHkfØ;k
compound always gives : nsrh gS :
(1) an enantiomer of the substrate (1) fØ;kdkjd dk ,d iz frfcEc leko;oh
(2) a product with opposite optical rotation (2) foifjr izdkf'kd ?kw.kZ u dk ,d ;kSfxd
(3) a mixture of diastereomers (3) foofje leko;oh;ksa dk ,d feJ.k
(4) a single isomer (4) ,d vdsyk leko;oh
Q.171 The structure of the major product formed in Q.171 fuEu vfHkfØ;k esa fufeZr eq[; mRikn dh lajpuk
the following reaction is : gksxh :
Cl Cl
NaCN NaCN
DMF DMF
 
Cl Cl
CN CN
(1) (2) (1) (2)
NC NC
 
CN CN
Cl Cl
CN CN
(3) (4) (3) (4)
CN CN
 
Q.172 CH2OH on dehydration with conc. H2SO4 Q.172 CH2OH ,lkUnz H2SO4 ds lkFk futZ yhdj.k
predominantly forms : ij eq[; :i ls Ckukrk gS :
(1) CH2 (2) CH3 (1) CH2 (2) CH3
(3) CH3 (4) CH3 (3) CH3 (4) CH3

Q.173 In Kjeldahl’s method, nitrogen present is Q.173 tsYMksy fof/k esa] mifLFkr ukbVªkstu dk fdl :i esa
estimated as : eqY;kadu fd;k tkrk gS :
(1) N2 (2) NO (3) NH3 (4) NO2 (1) N2 (2) NO (3) NH3 (4) NO2
O O
SeO 2
SeO 2
Q.174 CH3–C–CH3  X + Se + H2O Q.174 CH3–C–CH3   X + Se + H2O
Here X is : ;gk¡ X gS :
O O O O O O
(1) CH3–C–C–H (2) CH3–C–OCH3 (1) CH3–C–C–H (2) CH3–C–OCH3
O O
(3) CH3–C–CH2OH (4) None of the above (3) CH3–C–CH2OH (4) mijksDr esa ls dksbZ ugha
Q.175 A compound which gives a red orange Q.175 dkSulk ;kSfxd 2, 4-MkbZukbVª ksQsfuy-gkbMªst hu dk
precipitate on adding to an alcoholic solution of ,d ,YdksgkWfyd foy;u feykus ij ,d yky ukjaxh
2, 4-dinitrophenyl-hydrazine but does not reduce vo{ksi nsrk gS ijUrq Qsgfyax foy;u rFkk
Fehling’s solution and ammonical silver nitrate
veksfu;ke; flYoj ukbVªsV foy;u dks vipf;r ugha
solution, is :
djrk gS :
(1) CH3CHOHCH3 (2) CH3COCH3 (1) CH3CHOHCH3 (2) CH3COCH3
(3) CH3CHO (4) CH3COOH (3) CH3CHO (4) CH3COOH
Q.176 An organic compound of molecular formula Q.176 v.kqlw= C4 H10O dk ,d dkcZfud ;kSfxd lksfM;e
C4H10O does not react with sodium. With ds lkFk fØ;k ugha djrk gSA H ds vkf/kD; ds lkFk
excess of H, it gives only one type of alkyl ;g dsoy ,d izdkj dk ,fYdy gsykbM ns rk gSA
halide. The compound is : ;kSfxd gksxk :
(1) Ethoxyethane (2) 2-Methoxypropane (1) ,FkkWDlh ,Fksu (2) 2-feFkkWDlh izksis u
(3) 1-Methoxypropane (4) 1-Butanol (3) 1-feFkkWDlh izksis u (4) 1-C;wVsukWy
Q.177 What is Z in the following sequence of Q.177 vfHkfØ;kvksa ds fuEu Øe esa Z D;k gksxk ?
reactions ?
fQukW y 
Zn
Dust
 X 
CH3Cl
futZy .AlCl3
Y 
{kkjh;
KMnO 4
Z
Phenol  Zn
Dust
 X 
CH3 Cl
Anhyd.AlCl3
 Y 
Alkaline
KMnO 4
Z
(1) csUthu (2) Vksywbu
(1) Benzene (2) Toluene
(3) Benzaldehyde (4) Benzoic acid (3) csUtsYMhgkbM (4) csUtksbd vEy

NO2 X NO2 X
Sn Sn
Q.178 
HCl
Q.178 
HCl
In the above reaction X stands for mijksDr vfHkfØ;k esa X vfHkO;Dr djrk gS
(1) SnCl2 (1) SnCl2
(2) NH3Cl (2) NH3Cl

(3) NH2 (3) NH2
(4) Cl (4) Cl
Q.179 Which base is present in RNA but not in DNA ? Q.179 RNA esa dkS ulk {kkj mifLFkr gks rk ijUrq DNA esa ugha ?
(1) Uracil (1) ;wjsfly
(2) Cytosine (2) lkbVkslhu
(3) Guanine (3) Xokuhu
(4) Thymine (4) Fkk;ehu
Q.180 Bakelite is : Q.180 csdsykbV gS :

(1) thermosetting polymer (1) rkin`< cgqyd
(2) copolymer (2) lgcgqyd
(3) crosslink polymer (3) fr;Zd cfU/kr cgqyd
(4) All (4) lHkh

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Physics : Full Syllabus

Chemistry : Full Syllabus

Biology : Full Syllabus

SPACE FOR ROUGH WORK

(3) – (4 m/s2) ĵ (4) (4 m/s2) î (3) – (4 m/s2) ĵ (4) (4 m/s2) î

Add. : 638, CAD Circle, Kota, Raj., India 1

(1) 3.41 mm (2) 6.41 mm (1) 3.41 mm (2) 6.41 mm

Add. : 638, CAD Circle, Kota, Raj., India 2

SPACE FOR ROUGH WORK

Add. : 638, CAD Circle, Kota, Raj., India 3

towards the east 5

Add. : 638, CAD Circle, Kota, Raj., India 4

SPACE FOR ROUGH WORK

Add. : 638, CAD Circle, Kota, Raj., India 5

4F 2F 2F 4F 2F 2F

(1) 3 F (2) 2 F (3) 4 F (4) 8 F (1) 3 F (2) 2 F (3) 4 F (4) 8 F

Add. : 638, CAD Circle, Kota, Raj., India 6

(3) 36 5 (4) 4 5 (3) 36 5 (4) 4 5

(1) 0.75 A (2) Zero (1) 0.75 A (2) 'kwU;

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(1) 1 (2) 2 (3) 3 (4) 4 (1) 1 (2) 2 (3) 3 (4) 4

SPACE FOR ROUGH WORK

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SPACE FOR ROUGH WORK

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(1) 1.5 A (2) 5A (1) 1.5 A (2) 5A

SPACE FOR ROUGH WORK

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SPACE FOR ROUGH WORK

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SPACE FOR ROUGH WORK

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kingdom animalia. ds x.k gSA

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B Run-off B izokg ¼ju vkWQ½

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Q.76 Ground tissue system Q.76 Hkj.k Ård ra=

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collenchymatous cells with intercellular dks.kksÙkdh; dksf'kdkvksa dh cM+h la[;k] tks

Q.80 Defaecation Q.80 eyR;kx&

autonomic nervous system izfØ;k gSA

a mass peristaltic movement }kjk fd;k tkrk gSA

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Which one is correct ? dkSu lk dFku lgh gS \

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(iii) Centromere, (iv) Chromosome (iii) lsUVªkseh;j, (iv) xq.klw=

(iii) Centromere, (iv) Chromatid (iii) lsUVªkseh;j, (iv) ØksesfVM

(iii) Centriole, (iv) Chromosome (iii) lsfUVªvksy, (iv) xq.klw=

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(1) 1, 2, 3, 4 (2) 2, 1, 3, 4 (1) 1, 2, 3, 4 (2) 2, 1, 3, 4

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(3)Complete dominance (3) iw.kZ izH kkfork

(4) Incomplete dominance (4) viw.kZ izHkkfork