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    Deberes 10mo

    Uploaded by

    Alexander
    The document defines a right triangle with sides of lengths 3 cm, 4 cm, and the hypotenuse of 5 cm. It then calculates the trigonometric ratios (sine, cosine, tangent, cosecant, secant, cotangent) of the angle θ in terms of the sides of the triangle. It further evaluates the trigonometric ratios numerically to find the measure of the angle θ, which is 36.87 degrees.

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    Deberes 10mo

    Uploaded by

    Alexander
    19 views4 pages
    The document defines a right triangle with sides of lengths 3 cm, 4 cm, and the hypotenuse of 5 cm. It then calculates the trigonometric ratios (sine, cosine, tangent, cosecant, secant, cotangent) of the angle θ in terms of the sides of the triangle. It further evaluates the trigonometric ratios numerically to find the measure of the angle θ, which is 36.87 degrees.

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    deberes 10mo

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    The document defines a right triangle with sides of lengths 3 cm, 4 cm, and the hypotenuse of 5 cm. It then calculates the trigonometric ratios (sine, cosine, tangent, cosecant, secant, cotangent) of the angle θ in terms of the sides of the triangle. It further evaluates the trigonometric ratios numerically to find the measure of the angle θ, which is 36.87 degrees.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd
    Download as pdf or txt
    19 views4 pages

    Deberes 10mo

    Uploaded by

    Alexander
    The document defines a right triangle with sides of lengths 3 cm, 4 cm, and the hypotenuse of 5 cm. It then calculates the trigonometric ratios (sine, cosine, tangent, cosecant, secant, cotangent) of the angle θ in terms of the sides of the triangle. It further evaluates the trigonometric ratios numerically to find the measure of the angle θ, which is 36.87 degrees.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd
    Download as pdf or txt
    of 4

    1.

    Determinar las razones trigonométricas del siguiente triángulo rectángulo, en función del
    ángulo θ.

    a = 3 cm β

    θ
    b = 4 cm

    𝑫𝒂𝒕𝒐𝒔:

    𝑎 = 3 𝑐𝑚

    𝑏 = 4 𝑐𝑚

    𝒄 = √𝒂𝟐 + 𝒃𝟐

    𝑐 = √(3)2 + (4)2

    𝑐 = √9 + 16

    𝑐 = √25

    𝒄= 𝟓

    𝑹𝑨𝒁𝑶𝑵𝑬𝑺 𝑻𝑹𝑰𝑮𝑶𝑵𝑶𝑴É𝑻𝑹𝑰𝑪𝑨𝑺

    𝑪𝒂𝒕𝒆𝒕𝒐 𝑶𝒑𝒖𝒆𝒔𝒕𝒂
    𝑺𝒆𝒏 𝜽 =
    𝒉𝒊𝒑𝒐𝒕𝒆𝒏𝒖𝒔𝒂
    𝑎
    𝑆𝑒𝑛 𝜃 =
    𝑐
    𝟑
    𝑺𝒆𝒏 𝜽 =
    𝟓

    𝑪𝒂𝒕𝒆𝒕𝒐 𝑨𝒅𝒚𝒂𝒄𝒆𝒏𝒕𝒆
    𝑪𝒐𝒔 𝜽 =
    𝒉𝒊𝒑𝒐𝒕𝒆𝒏𝒖𝒔𝒂

    𝑏
    𝐶𝑜𝑠 𝜃 =
    𝑐
    𝟒
    𝑪𝒐𝒔 𝜽 =
    𝟓
    𝑪𝒂𝒕𝒆𝒕𝒐 𝑶𝒑𝒖𝒆𝒔𝒕𝒐
    𝑻𝒈 𝜽 =
    𝑪𝒂𝒕𝒆𝒕𝒐 𝑨𝒅𝒚𝒂𝒄𝒆𝒏𝒕𝒆
    𝑎
    𝑇𝑔 𝜃 =
    𝑏
    𝟑
    𝑻𝒈 𝜽 =
    𝟒

    𝒉𝒊𝒑𝒐𝒕𝒆𝒏𝒖𝒔𝒂
    𝑪𝒔𝒄 𝜽 =
    𝑪𝒂𝒕𝒆𝒕𝒐 𝑶𝒑𝒖𝒆𝒔𝒕𝒐
    𝑐
    𝐶𝑠𝑐 𝜃 =
    𝑎
    𝟓
    𝑪𝒔𝒄 𝜽 =
    𝟑

    𝒉𝒊𝒑𝒐𝒕𝒆𝒏𝒖𝒔𝒂
    𝑺𝒆𝒄 𝜽 =
    𝑪𝒂𝒕𝒆𝒕𝒐 𝑨𝒅𝒚𝒂𝒄𝒆𝒏𝒕𝒆
    𝑐
    𝑆𝑒𝑐 𝜃 =
    𝑏
    𝟓
    𝑺𝒆𝒄 𝜽 =
    𝟒

    𝑪𝒂𝒕𝒆𝒕𝒐 𝑨𝒅𝒚𝒂𝒄𝒆𝒏𝒕𝒆
    𝑪𝒕𝒈 𝜽 =
    𝑪𝒂𝒕𝒆𝒕𝒐 𝑶𝒑𝒖𝒆𝒔𝒕𝒐

    𝑏
    𝐶𝑡𝑔 𝜃 =
    𝑎
    𝟒
    𝑪𝒕𝒈 𝜽 =
    𝟑

    1. Determinar las siguientes razones trigonométricas con el uso de la calculadora.

    𝟑
    𝑺𝒆𝒏 𝜽 =
    𝟓

    𝑆𝑒𝑛 𝜃 = 0.6

    𝜃 = 𝑆𝑒𝑛−1 (0.6)

    𝜃 = 36.87°
    𝟒
    𝑪𝒐𝒔 𝜽 =
    𝟓

    𝐶𝑜𝑠 𝜃 = 0.8

    𝜃 = 𝐶𝑜𝑠 −1 (0.8)

    𝜃 = 36.87°

    𝟑
    𝑻𝒈 𝜽 =
    𝟒

    𝑇𝑔 𝜃 = 0.75

    𝜃 = 𝑇𝑔−1 (0.75)

    𝜃 = 36.87°

    𝟓
    𝑪𝒔𝒄 𝜽 =
    𝟑

    𝐶𝑠𝑐 𝜃 = 1.6666

    𝜃 = 𝐶𝑠𝑐 −1 (1.6666)

    𝜃 = 36.87°

    𝟓
    𝑺𝒆𝒄 𝜽 =
    𝟒

    𝑆𝑒𝑐 𝜃 = 1.25

    𝜃 = 𝑆𝑒𝑐 −1 (1.25)

    𝜃 = 36.87°

    𝟒
    𝑪𝒕𝒈 𝜽 =
    𝟑

    𝐶𝑡𝑔 𝜃 = 1.3333

    𝜃 = 𝐶𝑡𝑔−1 (1.3333)

    𝜃 = 36.87°

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