The document describes formulas for calculating noise levels from pressure relief valves discharging gases, vapors, and steam. The key formulas calculate the sound level at 100 feet (L100) based on factors like the mass flow rate, temperature, and molecular weight. A second formula calculates the sound level (Lp) at any distance by adjusting the L100 based on the distance. An example calculation is shown for a natural gas relief valve, finding the noise level would be around 89.9 decibels at a distance of 500 feet.
The document describes formulas for calculating noise levels from pressure relief valves discharging gases, vapors, and steam. The key formulas calculate the sound level at 100 feet (L100) based on factors like the mass flow rate, temperature, and molecular weight. A second formula calculates the sound level (Lp) at any distance by adjusting the L100 based on the distance. An example calculation is shown for a natural gas relief valve, finding the noise level would be around 89.9 decibels at a distance of 500 feet.
The document describes formulas for calculating noise levels from pressure relief valves discharging gases, vapors, and steam. The key formulas calculate the sound level at 100 feet (L100) based on factors like the mass flow rate, temperature, and molecular weight. A second formula calculates the sound level (Lp) at any distance by adjusting the L100 based on the distance. An example calculation is shown for a natural gas relief valve, finding the noise level would be around 89.9 decibels at a distance of 500 feet.
The document describes formulas for calculating noise levels from pressure relief valves discharging gases, vapors, and steam. The key formulas calculate the sound level at 100 feet (L100) based on factors like the mass flow rate, temperature, and molecular weight. A second formula calculates the sound level (Lp) at any distance by adjusting the L100 based on the distance. An example calculation is shown for a natural gas relief valve, finding the noise level would be around 89.9 decibels at a distance of 500 feet.
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Noise Level Calculations
The following formulae are used for calculating noise level
of gases, vapors and steam as a result of the discharge of a pressure relief valve. The expressed formulae are derived from API Recommended Practice 521. Table T7-4 on page 7-11 lists relative noise levels. L100 = L + 10 LOG10 (0.29354 W k T/M) Where: L100 = Sound level at 100 feet from the point of discharge in decibels. L = Noise intensity measured as the sound pressure level at 100 feet from the discharge. Reference Figure F7-7 on page 7-11. W = Maximum relieving capacity, pounds per hour. k = Ratio of specific heats of the fluid. Reference Table T7-7 on page 7-26. (For steam, k = 1.3 if unknown.) T = Absolute temperature of the fluid at the valve inlet, degrees Rankine (°F + 460). M= Molecular weight of the gas or vapor obtained from standard tables or Table T7-7 on page 7-26. (For steam, M = 18) When the noise level is required at a distance of other than 100 feet, the following equation shall be used: Lp = L100 - 20 LOG10 (r/100) Where: Lp = Sound level at a distance, r, from the point of discharge in decibels. r = Distance from the point of discharge, feet. Example #1 Gas/Vapor Mass Flow (lb/hr) Fluid: Natural Gas Set Pressure: 210 psig Overpressure: 10% Back Pressure: 50 psig Inlet Relieving Temperature: 120F Molecular Weight: 19.0 (page 7-26) Compressibility: 1 Selected Area: 0.503 square inches Noise to be calculated at: 500 feet Although the required capacity has been given, the noise level of the valve should be calculated on the total flow through the selected valve at the specified overpressure. Therefore the rated flow must first be calculated. The following formula is a rearrangement of the area calculation formula for gas and vapor in mass flow units (lb/hr). Reference page 5-3. P1 = Absolute relieving pressure 210 + 21 + 14.7 = 245.7 psia Kb = 1.0 C = 344 from Table T7-7 on page 7-26. K = 0.975 W = A P1 C K Kb M / TZ W = (0.503)(245.7)(344)(0.975)(1)( 19)/ (580)(1) W = 7502 lb/hr T = 120F + 46F = 580R Pb = 50 psig Continuing with the noise level calculation: L100 = L + 10 LOG10 (0.29354 W k T/M) Where: PR = Absolute relieving pressure/absolute back pressure = P1 (Pb + 14.7) = 245.7/(50 + 14.7) = 3.8 L = 54.5 (Figure F7-7, page 7-11.) k = 1.27 (Table T7-7, page 7-26.) W = 7502 lb/hr M = 19 T = 120F + 460F = 580R L100=54.5+ 10 LOG10 [(0.29354)(7502)(1.27)(580)/(19)] L100=103.8 decibels At a distance of 500 feet: Lp = L100 - 20 LOG10 (r/100) Where: r = 500 feet Lp = 103.8 - 20 LOG10 (500/100) Lp = 89.9 decibels