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Concrete Column Design Based On ACI 318-19: Input Data & Design Summary

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PROJECT : PAGE :

CLIENT : DESIGN BY :
JOB NO. : DATE : REVIEW BY :
Concrete Column Design Based on ACI 318-19

INPUT DATA & DESIGN SUMMARY


CONCRETE STRENGTH fc' = 6 ksi, (41 MPa)
REBAR YIELD STRESS fy = 60 ksi, (414 MPa)
SECTION SIZE Cx = 40 in, (1016 mm)
Cy = 36 in, (914 mm)

FACTORED AXIAL LOAD Pu = 1440 kips, (6405 kN)


FACTORED MAGNIFIED MOMENT Mu,x = 2500 ft-kips, (3390 kN-m)
Mu,y = 500 ft-kips, (678 kN-m)
FACTORED SHEAR LOAD Vu,x = 130 kips, (578 kN) THE COLUMN DESIGN IS ADEQUATE.
Vu,y = 150 kips, (667 kN)
COLUMN VERT. REINFORCEMENT 8 # 8 at x dir.
(Total 22 # 8)
5 # 8 at y dir.
LATERAL REINF. OPTION (0=Spirals, 1=Ties) 1 Ties
LATERAL REINFORCEMENT 4 legs,# 4 @ 12 in. (305 mm), o.c., at x dir.
3 legs,# 4 @ 12 in. (305 mm), o.c., at y dir.

ANALYSIS
6000
e
5000

4000 e
3000
f Pn (k)
2000

1000 e
0
0 500 1000 1500 2000 2500 3000
-1000

-2000

f Mn (ft-k) Solid Black Line - Tension Controlled


Solid Red Line - Transition
Dash Line - Compression Controlled

Note:    e   e 2
1. Between compression & tension controlled is 
b e f C 2 
' c  c  , for 0 
   ec eo e s E s , for e s  e ty

Transition , which the f should be by linear fC    e o   e o   , fS
  f , for e s  e ty
interpolation. (ACI 318-19 Tab. 21.2.2 & Fig. R10.4.2.1)  y
 b e f C , for e c  e o
'
2. ACI 318-19 changed f (Fig.R21.2.2b) and keeps 
b e (22.2.2.4.1) and ecu (Fig. R21.2.2a) the same. 
2 b e f C'  f y e ty , for compression controlled

But AISC 360/341-16 has different f (0.9 only) and eo  , e ty  , et  
 0.003 , for tension controlled
Ec Es e ty

b e (1.0 or 0.7).
E c  57 f C , E s  29000ksi , b e  0.85 , e cu  0.003
'

CHECK FLEXURAL & AXIAL CAPACITY


f Pmax =F f [ 0.85 fc' (Ag - Ast) + fy Ast] = 4315 kips., (at max axial load, ACI 318-19 22.4)
where f = 0.65 , (ACI 318-19 Fig. R21.2.2b) > Pu [Satisfactory]
F = 0.8 , (ACI 318-19 Tab. 22.4.2.1) Ag = 1440 in2 Ast = 17.38 in
2

f Mn = 2812 ft-kips @ Pu = 1440 kips > Mu = 2550 ft-kips [Satisfactory]


rmax = 0.06 (ACI 318-19 18.7.4.1) rprovd = 0.012
rmin = 0.01 (ACI 318-19 18.7.4.1& 10.6.1.1) [Satisfactory]

CHECK SHEAR CAPACITY (ACI 318-19 10 & 22.5)

V u, x V u, x
  1.19 > 1.5 (ACI 318-19 22.5.1.11) [Satisfactory]
fV n, x f V n, x

f Vn = f (Vs + Vc) (ACI 318-19 22.5)

where f = 0.75 (ACI 318-19 21.2) fy = 60 ksi


d A0 Av Vc = 2 (fc')0.5A0 Vs = MIN (d fy Av / s , 4Vc) f Vn
x 37.5 1240 0.80 192.1 150.0 257
y 33.5 1240 0.60 192.1 100.5 219

smax = 16 (ACI 318-19 25.7) sprovd = 12 in


smin = 1 [Satisfactory]

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