Nothing Special   »   [go: up one dir, main page]
Scribd Logo
Upload

Welcome to Scribd!

  • 317 views

    10 5 13 Surveying Refresher Module 1

    Uploaded by

    Walter Catapang
    1. This document contains 12 survey problems involving leveling, distance and elevation calculations, triangulation, trilateration, and bearing corrections. 2. The problems cover topics such as standardizing tapes, reducing distances to sea level, calculating pace factors and distances, determining probable values from measurement data, performing two-peg tests on dump levels, solving for distances and elevations using angle of elevation measurements, and correcting for local magnetic attraction when determining bearings. 3. Solutions are provided in multiple choice format for each problem, testing understanding of fundamental surveying concepts and calculations.

    Copyright:

    © All Rights Reserved
    Download as DOC, PDF, TXT or read online from Scribd

    10 5 13 Surveying Refresher Module 1

    Uploaded by

    Walter Catapang
    317 views2 pages
    1. This document contains 12 survey problems involving leveling, distance and elevation calculations, triangulation, trilateration, and bearing corrections. 2. The problems cover topics such as standardizing tapes, reducing distances to sea level, calculating pace factors and distances, determining probable values from measurement data, performing two-peg tests on dump levels, solving for distances and elevations using angle of elevation measurements, and correcting for local magnetic attraction when determining bearings. 3. Solutions are provided in multiple choice format for each problem, testing understanding of fundamental surveying concepts and calculations.

    Original Description:

    Original Title

    pdfslide.net_10-5-13-surveying-refresher-module-1.doc

    Copyright

    © © All Rights Reserved

    Available Formats

    DOC, PDF, TXT or read online from Scribd

    Did you find this document useful?

    Is this content inappropriate?

    1. This document contains 12 survey problems involving leveling, distance and elevation calculations, triangulation, trilateration, and bearing corrections. 2. The problems cover topics such as standardizing tapes, reducing distances to sea level, calculating pace factors and distances, determining probable values from measurement data, performing two-peg tests on dump levels, solving for distances and elevations using angle of elevation measurements, and correcting for local magnetic attraction when determining bearings. 3. Solutions are provided in multiple choice format for each problem, testing understanding of fundamental surveying concepts and calculations.

    Copyright:

    © All Rights Reserved
    Download as DOC, PDF, TXT or read online from Scribd
    Download as doc, pdf, or txt
    317 views2 pages

    10 5 13 Surveying Refresher Module 1

    Uploaded by

    Walter Catapang
    1. This document contains 12 survey problems involving leveling, distance and elevation calculations, triangulation, trilateration, and bearing corrections. 2. The problems cover topics such as standardizing tapes, reducing distances to sea level, calculating pace factors and distances, determining probable values from measurement data, performing two-peg tests on dump levels, solving for distances and elevations using angle of elevation measurements, and correcting for local magnetic attraction when determining bearings. 3. Solutions are provided in multiple choice format for each problem, testing understanding of fundamental surveying concepts and calculations.

    Copyright:

    © All Rights Reserved
    Download as DOC, PDF, TXT or read online from Scribd
    Download as doc, pdf, or txt
    of 2

    Room 206 JPD Building 1955 CM Recto Avenue, Manila

    Telephone Number: (02) 516 7559 E-Mail: megareview_2008 @yahoo.com

    REFRESHER MODULE 1 - SURVEYING


    PROBLEM 6
    From the given data of a different leveling as shown in the tabulation:
    PROBLEM 1
    A 0.65kg, 50m tape was standardized and supported throughout its whole STA. B.S. F.S. ELEV.
    length and found to be 0.00205m longer at an observed temperature of 31.8°C 1 5.87 392.25
    and a pull of 10KN. This tape was used to measure a 4% grade line which was 2 7.03 6.29
    found to be 662.702m. During measurement, the temperature is 15°C and the 3 3.48 6.25
    tape is suspended under a pull of 20KN. E=200GPa, cross-sectional area of 4 7.25 7.08
    tape is 3mm2 and the coefficient of linear expansion is 0.0000116m/°C. 5 10.19 5.57
    1. Compute the standard temperature. 6 9.29 4.45
    a. 28.27°C b. 30.24°Cc. 26.27°C d. 32.24°C 7 4.94
    2. Compute the total correction per tape length.
    a. -0.2378 b. +0.2378 c. -0.2187 d. +0.2187 1. Find the diff. in elevation of station 7 and station 5.
    a. 10.09m b. 8.09m c. 12.09m d. 14.09m
    3. Compute the true horizontal distance. 2. Find the height of instrument at station 4.
    a. 659.46m b. 659.27m c. 659.20m d. 659.35m a. 400.26m b. 396.26m c. 392.26m d. 386.26m

    PROBLEM 2 PROBLEM 7
    A line measures 7800m at elevation 900m. The average radius of the curvature The table shows the values of backsight, foresight & intermediate foresight
    in the area is 6400km. reading taken from BM1 to BM2. Elevation of BM1 = 328.70m.
    1. Compute the sea level distance.
    a. 7768.90m b. 7778.90m c. 7788.90m d. 7798.90m STA. B.S. F.S. I.F.S. ELEVATION
    2. Compute the reduction factor. BM1 2.32 328.70
    a. 0.99886 b. 0.99986 c. 0.99686 d. 0.99786 1 1.7
    2 2.2
    PROBLEM 3 3 1.2
    A line 125 m. long was paced by a surveyor for four times with the following 4 0.9
    data 161,165, 159 and 158. Then another line was paced for five times with the TP1 2.77 3.43
    following results, 520, 525, 524, 522 and 518.
    5 2.2
    1. Determine the pace factor.
    6 3.7
    a. 0.7756 b. 0.7776 c. 0.7796 d. 0.7806
    2. Determine the number of paces for the new line. 7 1.6
    a. 521.8 b. 519.8 c. 523.8 d. 524.8 TP2 2.22 3.06
    3. Determine the distance of the new line. 8 2.8
    a. 405.75m b. 402.75m c. 407.75m d. 408.75m 9 3.6
    10 2.0
    PROBLEM 4 11 1.1
    From the measured values of distance AB, the following data were recorded. BM2 2.45
    DATA DISTANCE No. OF MEASUREMENTS
    1 120.68 1 1. Find the difference in elevation between stations 5 & 9.
    2 120.84 4 a. 2.64m b. 2.44m c. 2.24m d. 2.74m
    3 120.76 6 2. Find the elevation of TP2.
    4 120.64 8 a. 325.30m b. 327.30m c. 329.30m d. 323.30m

    1. Find the probable weight of data 2. PROBLEM 8


    a. 4 b. 6 c. 8 d. 1 In a two peg – test of a dumpy level, the following observations were taken.
    2. Find the probable error of the mean.
    a. +0.0106 b. +0.0126 c. +0.0146 d. +0.0166 Instrument at C Instrument at D
    3. Find the standard deviation. Rod reading on A 0.296 1.563
    a. +0.0856 b. +0.0836 c. +0.0816 d. +0.0796 Rod reading on B 0.910 2.140
    4. Find the standard error.
    a. +0.0187 b. +0.0167 c. +0.0147 d. +0.0137 Point C is equidistant from A and B. D is 2.5m from A and 72.5m from B.
    5. Find the probable distance of AB.
    a. 120.72 b. 120.92 c. 120.52 d. 120.32 1. What is the difference in elevation between A and B?
    a. 0.614 b. 0.624 c. 0.634 d. 0.644
    PROBLEM 5 2. Determine the error in the rod reading at B with the instrument at D.
    The following interior angles of a triangle traverse were measured with the a. 0.0393 b. 0.0383 c. 0.0373 d. 0.0363
    same precision. 3. What is the corresponding rod reading on A for a horizontal line of sight with
    ANGLE VALUE (DEGREES) No. OF MEASUREMENTS instrument still at D.
    A 39 5 a. 1.574 b. 1.564 c. 1.554 d. 1.544
    B 65 4
    C 75 3 PROBLEM 9
    Considering the effects of curvature and refraction, the difference in elevation of
    1. Determine the most probable value of angle A. points B & C is found out to be 111.356m. From point A, the angle of elevation
    a. 39° 15.32’ b. 39° 19.15’ c. 39° 25.53’ d. 39° 13.35’ of B is 18⁰30’ & that of C is 8⁰15’. A is between B & C.
    2. Determine the most probable value of angle B. 1. If C is 2000m from A, how far is B from C?
    a. 65° 13.35’ b. 65° 15.32’ c. 65° 19.15’ d. 65° 25.53’ a. 1.6km b. 1.4km c. 1.2km d. 1.0km
    3. Determine the most probable value of angle C. 2. Find the elevation of A if elevation of B is 450m.
    a. 75° 19.15’ b. 75° 13.35’ c. 75° 25.53’ d. 75° 19.15’ a. 48.79m b. 48.59m c. 48.19m d. 48.39m
    Room 206 JPD Building 1955 CM Recto Avenue, Manila
    Telephone Number: (02) 516 7559 E-Mail: megareview_2008 @yahoo.com
    PROBLEM 10
    Two hills A & C have elevations of 600m REFRESHER MODULE
    & 800m respectively. In between A& 1 - SURVEYING
    C, is hill B which has an elevation of 705m. B is located 12km from A & 10km
    from C. Determine the clearance or obstruction of the line of sight if an observer
    is @ A so that C will be visible from A. Ans. 3.95m
    a. 3.95m (obstruction)b. 3.95m (clearance)
    c. 3.75m (obstruction)d. 3.75m (clearance)

    PROBLEM 11
    A field is in the form of a regular pentagon. The directions of the bounding sides
    were surveyed with an assumed meridian 5⁰ to the right of the true north &
    south meridian. As surveyed, the bearing of one side AB is N 33⁰20’ W.
    1. Compute the true bearing of Line CD.
    a. S65⁰20’E b. S66⁰20’E c. S64⁰20’E d. S63⁰20’E
    2. Compute the true azimuth of Line BC.
    a. 220⁰40’ b. 221⁰40’ c. 222⁰40’ d. 223⁰40’

    PROBLEM 12
    The bearing of a line from A to B was measured as S16°30’W. It was found that
    there was a local attraction at both A & B and therefore a forward and a
    backward bearing were taken between A & a point C at which there was no
    local attraction. If the bearing of AC was S30°10’E & that of CA was N28°20’W,
    what is the corrected bearing of AB?
    a. S18°20’W b. S16°20’W c. S17°20’W d. S19°20’W

    PROBLEM 13
    From the given closed traversed shown.

    LINES BEARING DISTANCES


    A-B S. 35 30’ W 44.37 m.
    B-C N. 57 15’ W 137.84 m.
    C-D N. 1 45’ E 12.83 m.
    D-E ? 64.86 m.
    E-A ? 106.72
    1. Find the Bearing of line D-E.
    a. N 66.17°E b. N 68.17°E c. N 70.17°E d. N 72.17°E
    2. Find the Bearing of line E-A.
    a. S54.2°E b. S52.2°E c. S50.2°Ed. S48.2°E

    PROBLEM 14
    From the data below:
    LINE LATITUDE DEPARTURE
    AB -36.13 -25.77
    BC +74.56 -115.93
    CD +12.82 +0.39
    DE +19.90 +61.74
    EA -68.40 +69.57

    1. Solve for area by Transit Rule.


    a. 6753.29m2 b. 6726.62m2 c. 6726.29m2 d. 6753.62m2
    2. Solve for area by Compass Rule.
    a. 6753.29m2 b. 6726.62m2 c. 6726.29m2 d. 6753.62m2

    You might also like